Part E
From the observations of the simulation, which strategy was most effective for quickly and efficiently producing ammonia? Why do you think this strategy is most effective?

Answer:

(a) 1s2 2s1

Explanation:

Electron configurations of atoms are in their ground state when the electrons completely fill each orbital before starting to fill the next orbital.

It's important to know how to read and interpret the notation.

For example, the first part of option (a) says "1s2"

It important to know which orbitals are in each shell:

So, it's also important to know how many electrons can be in each orbital in order to know if they are full or not.  The electrons should fill up these orbitals for each level, in this order:

For option (a):

This is in it's ground state.

For option (b):

Because the 3s orbital has an electron, but the lower 2p before it isn't full.  This is NOT in it's ground state.

For option (c):

Although the 2p orbital is full, since the 2s orbital before it was not yet full, this is NOT in it's ground state.

For option (d):

Again, despite that the final orbital (in this case, the 2s orbital), is full, since the 1s orbital before it was not yet full, this is NOT in it's ground state.

Element X is sodium.

If there is one more shell of electrons, then this means it is one period below.

Since there is one less valence electron, it is one group to the left.

Answer:

= 64584.7176 g

or

= 64.5847 kg

Explanation:

From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.

We know that from Avogadro's constant,

1 mole of a substance contains 6.02 x 10²³ ions/atoms/units

Thus,

1 mole => 6.02 x 10²³ atoms

x moles=> 6.075 × 10²⁶ atoms

We cross multiply;

x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)

= 1009.1362 moles

1 mole of SO2 = 64 g

1009.1362 moles = ?

=>

[tex] \frac{1009.1362 \times 64}{1} [/tex]

= 64584.7176 g

= 64.5847 kg

Answer:

8.33 atm

Explanation:

Xe is   5  out of (4+5)   or   5 / 9 ths of the gas present

  5/9  * 15 atm = 8.33 atm

The least massive particle is the electron. Hence, the option true is correct.

Sub-atomic particles are tiny particles of matter that together constitute an atom. There are three subatomic particles, which are namely electrons, protons and neutrons.

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron).

Hence, the option true is correct.

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Transient stage is also called the unstable stage and in this stage, there is a gradual decrease in deformation rate to a definite constant value.

A transient state is when a process variable or variables changes, but before the system reaches a steady state.

Transient time is the time it takes for a circuit to change from one steady state to the next.

Therefore, Transient stage is also called the unstable stage and in this stage, there is a gradual decrease in deformation rate to a definite constant value.

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Answer:

7.0k x 10^2k

Explanation:

Answer:

A

The H+ from acid and OH- from base forms water, the other parts form the salt.

The third principal level(n=3) of a given atom has 9 orbitals.

what are orbitals?

The 3rd electron shell has 3 subshells - 3s, 3p, 3d

therefore, the total number of orbitals in the third electron shell is:

1+3+5=9 orbitals

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The amount of ice converted into steam is 13.23 gram.

Heat of Vaporisation is the amount of heat required to convert 1 gm to liquid at its boiling point to vapour.

Let x gram of ice is there

At first x gm of ice will melt

The heat required is x * Heat of fusion = x * 79.9 = 79.9x

Then the heat required to rise the temperature of x gm of water from 0 degree to 100 degree Celsius .

= mc ΔT

= x * 1 * 100 = 100x

The heat required to convert x gm of liquid into x gm of steam

= x * 540 = 540x

The total heat supplied is 9522 cal

79.9x + 100x + 540x = 9522

719.9 x = 9522

x = 13.23 gm

The amount of ice converted into steam is 13.23 gram.

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Answer:

Work is the use of force to move an object. It is directly related to both the force applied to the object and the distance the object moves. Work can be calculated with this equation: Work = Force x Distance.

:)

Gamma rays are high-energy electromagnetic waves given off during nuclear decay; option A.

Electromagnetic waves are waves which are produced as a result of the interaction of the magnetic and electric fields.

Types of electromagnetic waves include gamma rays, radio waves, ultraviolet waves.

Gamma rays are high-energy electromagnetic waves given off during nuclear decay

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The buildup of sediment in which a river empties right into a slow-transferring or non transferring frame of water is referred to as a Delta.

Deltas are wetlands that shape as rivers empty their water and sediment into some other frame of water, together with an ocean, lake, or some other river.

A form of soil made nearly completely of windblown sediment is referred to as Loess.

The natural count number in soil comes from decaying flora and animals and their waste products.

Clay, that's made of tiny debris and drains water very poorly, is one of the essential additives of soil.

A form of soil referred to as peat is maximum probably to shape in a/an Coastal surroundings in Tropical placing.

Water enables withinside the improvement of soil with the aid of using carrying Mineral and vitamins from higher layers to decrease layers.

The Richness of nutrients from soil is not unusualplace in moist environments, like rain forests.

Quartz-wealthy determine cloth results in the improvement of Sandy soils.

The layers of soil composed specifically of natural count number are referred to as the O and A horizon.

A layer of soil wherein clay, iron, and different factors from the overlying soil accumulates is referred to as the B horizon, or subsoil.

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Answer:

Li2S is soluble in water

PbBr2 is soluble in hot water

KCI is soluble in water

ppm = mg/L = mg/kg

6.67 x 10⁻³ g = 6.67 mg

ppm = 6.67 mg : 0.6 L = 11.12

Answer:

less HCL acid is required to neutralize a weaker solution of base (sodium bicarbonate).

Explanation:

Answer:

pH=2.3

Explanation:

One H2SO4 molecule produce two H+ ions.

So conc. of H+ = 2(0.0025)

=0.005

Now, pH=-log (conc. of H+)

=-log(0.005)

=2.3

Answer: C(2)H(5)OH + 3O(2) —> 3H(2)O + 2CO(2)

Explanation:

*The number in parentheses or

( ) represents the subscript of the element

Carbon-2

Hydrogen-6

Oxygen-7

I hope this is helpful.

Answer:

8

Explanation:

im pretty sure it'll be 8 electrons

The moles of HCl are needed to react with 0.87 moles of Na are the A:0.87 mol HCl.

M = mol / L Calculate the molarity of an HCl answer which includes 18.23 g of HCl in 355. zero mL of answer. Calculate the wide variety of moles of HCl. Divide the wide variety of moles of HCl with the aid of using the overall quantity in liters.

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The atom present in Option (1) most likely to form cation with a charge of +1

A cation has more protons than electrons, consequently giving it a net positive charge.

For a cation to form, one or more electrons must be lost, typically pulled away by atoms with a stronger affinity for them.

The atoms present in Option 1 have one eletron in its outermost shell therefore, it is easy for the atom to lose one elecron than more electron  and to attain stable electronic confiuration.

Hence, The atom present in Option (1) most likely to form cation with a charge of +1

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The compound above is a cyclic (ring) compound.

Organic compounds are compounds which contains carbon and hydrogen.

Some classes of organic compounds include the following:

So therefore, the compound above is a cyclic (ring) compound.

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39.96 g product form when 16.7 g of calcium metal completely reacts.

Stoichiometry is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Equation:

[tex]Ca(s) + Cl_2(g)[/tex] → [tex]CaCl_2(s)[/tex]

In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:

[tex]m_{ca_C_l_2}[/tex]= 16.7 g Ca x [tex]\frac{1 mol \;of \;Ca}{40g Ca}[/tex] x [tex]\frac{1 mol \;of \;CaCl_2}{1 mol \;Ca}[/tex] x [tex]\frac{111g of \;CaCl_2}{1 mol \;CaCl_2}[/tex]

[tex]m_{ca_C_l_2}[/tex] = 39.96 g

Hence, 39.96 g product form when 16.7 g of calcium metal completely reacts.

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Answer:

The balanced chemical equation is P₄ (s) + 5O₂ (g) → P₄O₁₀ (s)

Explanation:

In order to balance the chemical equation, you first need to see what's out of balance.

In this case our Oxygen is not balanced, so in order to make the two the same, we need to see what coefficient we need to add to the compounds to balance the problem.

So, adding a coefficient of 5 to  the O₂ will result in an equal number of oxygen on both sides.

160 g of SO3 are needed to make 400 g of 49% H2SO4.

The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

[tex]SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]

1 mole of SO3 produces 1 mole of H2SO4

Molar mass of SO3 = 80 g/mol

Molar mass of H2SO4 = 98 g/mol

80 g of SO3 are required to produce 98 og 100%H2SO4

mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3

Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g

Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.

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Electrochemical cell is one in which energy is released by a chemical action.

An electrochemical cell is one in which energy is released by a chemical action.

Now we have the reaction;

Zn^2 (aq) + 2e- = Zn(s)

Pb²(aq) + 2e- → Pb(s)

and

Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O

H₂O2 + 2H+ + 2e- →2H₂O

In the first case, the Ecell is obtained from;

(-0.13 V) - (-0.76 V)

= 0.63 V

In the second case;

1.78 V - 1.33 V

= 0.45 V

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The nucleus of the atom is the heaviest part of the atom.

When the ratio of neutrons to protons is too high, the nucleus becomes unstable and Beta emission has to take place.

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Answer:

a.) increase

c.) collide more often with other reactant molecules

Explanation:

Generally, when you increase the quantity of reactants, the rate of the reaction increases (the forward reaction). When there are more reactants, there are more chances for them to interact with each other. More interactions means more reactions.

I predict that using a larger amount of calcium chloride powder will increase the reaction rate because the calcium chloride molecules will collide more often with other reactant molecules.

It becomes fair to assume that the reaction rate would increase when Jon increases the quantity of calcium chloride (CaCl2) powder utilised in the chemical reaction with sodium bicarbonate (NaHCO3).

This is due to the fact that adding more calcium chloride powder to the reaction mixture will add more CaCl2 molecules.

There will be more collisions between CaCl2 and NaHCO3 molecules due to the larger concentration of CaCl2 molecules. Successful collisions between reactant molecules are essential for the production of products in a chemical reaction.

Therefore, a greater reaction rate will result from more CaCl2 and NaHCO3 molecules colliding often. The additional molecules contribute to a higher number of energetic collisions, where the reactant particles possess sufficient energy to overcome the activation energy barrier and undergo the reaction.

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Answer:

B.) It states that the change in enthalpy is independent of the pathway
the reaction takes to get to the products.

Explanation:

Hess's Law states that the overall enthalpy change is the sum of the enthalpy changes of all preceding steps. It does not matter how many steps there are or the type, so long as the enthalpy change of each is combined at the end, the overall change can be determined. The sequence (aka pathway) is not important.