Answer:
32. {-4, 1, 2, 12}
33. {2, 6, 9, 31, 65}
34. No
Step-by-step explanation:
32. The domain of a relation is the set that contains all the x-coordinates of all the ordered pairs of the relation.
domain = {-4, 1, 2, 12}
33. The range of a relation is the set that contains all the y-coordinates of all the ordered pairs of the relation.
range = {2, 6, 9, 31, 65}
34. No since the same number, 2, appears twice as an x-coordinate. In a function, no two ordered pairs can have the same x-coordinate.
Camp pine cone has 20 campers for every 6 counselors if there are 60 campers how many counselors are needed
Answer:
18
Step-by-step explanation:
20*3=60 so do 6*3 to get your answer
Evergreen Landscaping bought 4 tons of topsoil and 3 tons of mulch for $1460. The next week the
firm bought 5 tons of topsoil and 2 tons of mulch for $1391. Find the price per ton for each item.
Answer: The price per ton of topsoil is $179
and price per ton of mulch is $248.
Step-by-step explanation:
Let price of 1 ton of topsoil be x
and price 1 ton of mulch be y
According to question
4x + 3y = $1460 -(i)
and 5x + 2y = $1391 -(ii)
Now solving these linear equations
By multiply (i) equation with 5 and divide it by 4
we get 5x + [tex]\frac{15}{4}[/tex]y = $1825 -(iii)
Subtract equation (ii) from equation (iii)
5x +[tex]\frac{15}{4}[/tex] y - 5x - 2y = $1825-$1391
[tex]\frac{7}{4}[/tex]y=$434
y = $434х[tex]\frac{4}{7}[/tex] = $248
put value of y in equation (i)
4x + 3($248) = $1460
4x - $744 =$1460
4x = $716
x = $179
The price per ton of topsoil is $179
the price per ton of mulch is $248.
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Hello all! Please help me out with this.
I want to find a certain number which I will call Y. It is four times as great as another number which is two less than twenty. What is Y?
Answer:
Y=72
Step-by-step explanation:
First we set up the equation which is (20-2) times 4=Y
Then we solve, 20 minus 2 is risk since it is in the parentheses. 20 minus 2 is 18.
After that 18 times 4 is 72
Y=72
The graph shows the function f(x) = 2x.
What is the value of x when f(x) = 8?
[tex]\large\orange\implies \rm \large \:f(x) \: = \: 2x[/tex]
We have to find x when f(x) is 8
[tex]\large\orange\implies \rm \large \:8 = \: 2x[/tex]
[tex]\large\orange\implies \rm \large \: \cancel\frac{8}{2} \: = \: x \\ [/tex]
[tex]\large\orange\implies \rm \large \: \: 4 \: = \: x[/tex]
The value of x is 4 when f(x) is 8[tex]f(x) \: = \: 2x[/tex]
We have to find x when f(x) is 8
[tex]8 = \: 2x[/tex]
[tex]x = \frac{8}{2} \\ \\ x = 1.[/tex]
The value of x is 4 when f(x) is 8 .
A student has a test scores of 87, 89, 94 points. What must he score on the fourth exam to have an average of at least 92 points?
Answer: He must have atleast 98 points on the next exam in order to get an average of 92 points.
Step-by-step explanation: To calculate average, you need to add all the numbers given, and divide the sum by how many numbers there are. 87 + 89 + 94 + 98 (equals 368), and divide 368 by 4. You will get the average of 92 as its result.
Which values are part of the solution set? Check all that apply. x = 3 x = –5 x = negative one-half x = –4.5 x = –4
The values that are part of the solution are x = -5 and x = -4.5
Number linesNumber lines are lines that are used to represent the solution to inequalities.
From the given number line with he solution x > -4, this shows that all the solutions must be values that are greater than -4.
The values that are part of the solution are x = -5 and x = -4.5
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Base of a prism is a right triangle with legs 3 feet and 4 feet. The height is 13 feet , what is the volume?
Answer:
Triangular prisms
Remember the formula for calculating volume is: Volume = Area by height. V = A X h.
For a triangle the area is calculated using the formula: Area = half of base by altitude. A = 0.5 X b X a.
So to calculate the volume of a triangular prism, the formula is: V = 0.5 X b X a X h
Step-by-step explanation:
Can someone please solve
Answer: [tex]\sqrt{7}[/tex]
Step-by-step explanation:
Using the Pythagorean theorem,
[tex]3^2 + b^2 = 4^2\\\\9+b^2 = 16\\\\b^2 = 7\\\\b=\boxed{\sqrt{7}}[/tex]
Need some help ASAP and work shown. Ps; If you answer I’ll mark you brainliest.
Answer:
h ≈ 37 ft
Step-by-step explanation:
let x be the height of the tree from the viewers eye level
using the tangent ratio, then
tan24° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{x}{72}[/tex] ( multiply both sides by 72 )
72 × tan24° = x
then
height of tree = x + 5 = 72tan24° + 5 ≈ 37 ft ( to the nearest foot )
Answer:
37ft
Step-by-step explanation:
It can be considered as a right angle triangle. The height of the tree is equal to the product of tan(24°) and the distance between the man and tree+5 Therefore
⇒h=tan(24°)*72+5⇒h≈32ft+5⇒h≈37In conclusion
The height of the tree is 37ft
Rationalize the Denominator
2i/i-2
Answer:
2-4i/5
Step-by-step explanation:
[tex]\frac{2i}{i-2} *\frac{i+2}{i+2}\\=\frac{2i(i+2)}{i^2-4}\\= \frac{2i(i+2)}{-1-4}\\ =\frac{2i(i+2)}{-5} \\ = \frac{-2 + 4i}{-5}\\ =( 2 - 4i )/ 5[/tex]
Answer:
[tex]\frac{2i}{i-2}=\frac{2-4i}{5}[/tex]
Step-by-step explanation:
[tex]\frac{2i}{i-2}[/tex] (Given)[tex]=\frac{2i}{i-2}\times \frac{i+2}{i+2}[/tex] [Multiply numerator and denominator both by (i + 2)][tex]=\frac{2i(i+2)}{(i-2)(i+2)}[/tex][tex]=\frac{2i^2+4i)}{i^2-2^2}[/tex][tex]=\frac{2(-1)+4i)}{-1-4}[/tex][tex]=\frac{-2+4i)}{-5}[/tex][tex]=\frac{2-4i)}{5}[/tex][tex]\implies \frac{2i}{i-2}=\frac{2-4i}{5}[/tex]Determine the values of x and y.
Answer: x = 23, y = 40
Step-by-step explanation:
By the same-side interior angles theorem, y+30 and 110 are supplementary.
110 + y + 30 = 180 [supplementary angles add to 180 degrees]y + 140 = 180 [combine like terms]y = 40 [subtract 140 from both sides]We know that the 3x + 1 angle and y + 30 are also congruent, so:
3x + 1 = y + 30 [congruent angles have equal measure]3x + 1 = 40 + 30 [substitute y = 40]3x + 1 = 70 [combine like terms]3x = 69 [subtract 1 from both sides]x = 23 [divide both sides by 3]A pyramid has a square base with sides of length s. The height of the pyramid is equal to 1/2 of the length of a side on the base. Which formula
represents the volume of the pyramid?
A. V = 1/12 s ^3
B. V=1/6 s ^3
C. V=1/3s ^3
D. V=3s³
E. V=6s³
Answer:
V = (s^3)/6 (Answer B )
Step-by-step explanation:
If the length of a side of the base is s, then the height of the pyramid is half that, or s/2.
The volume of a pyramid with a square base and base side length S and height H is V = (1/3)(S^2)(H).
In this case, the formula is V = (1/3)(s^2)(s/2), or V = (s^3)/6 (Answer B)
Maximiza a: z=5x+2y
Sujeta a: x+2y≤12
x+y≥4
x,y ≥0
Answer:
hi
Step-by-step explanation:
no
if A={4,7,10,13,17} and B={3,5,7,9}, then which of the following statements is true
A U B= {7}
B c A
B c B
Answer:
good questing it is something
Step-by-step explanation:
1-1-2- --3--1234-3
3-4
Q-
-4
-24
-4
-
q 43-
43-
3 4-3
4-
4-4
- answer is 2def not cap i need 5 poinnts i gues
Factor the following expression. x² - 10x +9 2 Factor the following expression . x² - 10x +9 2
Answer:
x² - 10x + 9 = (x-9)(x-1)
the factored expression would be (x-9)(x-1)
What is the multiplicative rate of change between 10,50 and 250
Answer:D
Step-by-step explanation:
Which expression is equivalent to the given expression? 4lh x + lh 3 - lh x
Find the interval in which the function f(x) = |x + 4| is increasing.
[tex]f { }^{ - } (x) = \frac{2(x + 4)}{2 |x + 4| {}^{} } = \frac{x + 4}{ |x + 4| } [/tex]
[tex] |x + 4| \: is \: always \: positive[/tex]
[tex]solve \: x + 4 > 0[/tex]
[tex]x > - 4[/tex]
[tex]f(x) \: is \: incresing \: from \\[/tex]
]-4,∞[i need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Part B: Are there any outliers present for either data set? Justify your answer mathematically. (5 points)
Five number summary and IQR of both the data sets are different.
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Part A:
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set into four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
The interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =16-6.2\\ =9.5[/tex]
The interquartile range of the data is
[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =15.5-8\\ =7.5[/tex]
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.
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Considering only the values of β for which (1+cosβ)(1−cosβ)sinβ is defined, which of the following expressions is equivalent to (1+cosβ)(1−cosβ)sinβ?
Select the correct answer below:
sinβ
sin3β
secβ
1
sec2β
The following expressions (1+cosβ)(1−cosβ)sinβ is equivalent to sin³β
What are Trigonometric Ratios ?In a Right angled triangle , trigonometric ratios can be used to determine the value of angles and sides of the triangle.
The trigonometric expression given in the question is
(1+cosβ)(1−cosβ)sinβ
(a+b)(a-b) = a² - b²
( 1 - cos²β)sinβ
By the trigonometric Identity
1-cos²β = sin² β
sin² β x sin β
sin³β
Therefore Option B is the correct answer.
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Tioga Company manufactures sophisticated lenses and mirrors used in large optical telescopes. The
company is now preparing its annual profit plan. As part of its analysis of the profitability of individual
products, the controller estimates the amount of overhead that should be allocated to the individual product lines from the following information.
Lenses Mirrors
Units produced ................................................................................................................ 25 25
Material moves per product line ........................................................................................ 5 15
Direct-labor hours per unit ................................................................................................ 200 200
The total budgeted material-handling cost is $50,000.
Required:
1. Under a costing system that allocates overhead on the basis of direct-labor hours, the materialhandling costs allocated to one lens would be what amount?
2. Answer the same question as in requirement (1), but for mirrors.
3. Under activity-based costing (ABC), the material-handling costs allocated to one lens would be
what amount? The cost driver for the material-handling activity is the number of material moves.
4. Answer the same question as in requirement (3), but for mirrors.
Tioga Company manufactures sophisticated lenses and mirrors used in large optical telescopes, the values are mathematically given as
MH1=$1,000MH2=$1,000MH3=$1500MH4=$1500What is the material handling costs allocated?Generally, the equation for Material-handling cost for one lens mathematically given as
MH1=Total projected costs for material handling /{Total number of direct labor hours x Direct labor hours per unit)
MH1={$50,000/10.000)x 200
MH1=$1,000
2)
Material-handling cost for one mirror
MH2=Total budgeted material handling cost/ Total number of direct labor hours x direct labor hours per unit
MH2={$50,000/10.000)x 200
MH2=$1,000
3) Material-handling cost per lens
[tex]MH3=\frac{Total projected costs for material handling}{\frac{Number of material moves per lens + Number of material moves per mirror}{(Total number of lenses)}}* Material moves per lens[/tex]
[tex]MH3=\frac{50,000}{\frac{5+15}{25}}*5[/tex]
MH3=$1500
4)
[tex]MH4=\frac{Total projected costs for material handling}{\frac{Number of material moves per mirror + Number of material moves per lens}{(Total number of mirror)}}* Material moves per mirror[/tex]
[tex]MH4=\frac{50,000}{\frac{5+15}{25}}*5[/tex]
MH4=$1500
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Drag the tiles to the correct boxes to complete the pairs. Match each function to its domain and range.f(x)=5x-3
f(x) is a linear function, so both the domain and the range are the set of real numbers.
Patrisse and Makayla began arguing about who did better on their tests, but they couldn't decide who did better given that they took different tests. Patrisse took a test in English and earned a 81.4, and Makayla took a test in Art History and earned a 60.6. Use the fact that all the students' test grades in the English class had a mean of 72.8 and a standard deviation of 11.8, and all the students' test grades in Art History had a mean of 67 and a standard deviation of 8.6 to answer the following questions. a) Calculate the z-score for Patrisse's test grade. z = [Round your answer to two decimal places.] b) Calculate the z-score for Makayla's test grade. z = [Round your answer to two decimal places.] c) Which person did relatively better? Patrisse Makayla They did equally well.
a) Z-score for Patrisse test grade is 0.7288
b) z-score for Makayla test grade is -0.7441
c) Patrisse did better.
What is z- score?
A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.
Z-score for Patrisse test grade.
X= 81.4, [tex]\mu[/tex] = 72.8, [tex]\sigma[/tex] = 11.8
Z= x- [tex]\mu[/tex] / [tex]\sigma[/tex]
Z= 81.4 - 72.8/ 11.8
Z= 0.7288
Now, z-score for Makayla test grade.
X= 60.6, [tex]\mu[/tex] = 67, [tex]\sigma[/tex] = 8.6
Z= x- [tex]\mu[/tex] / [tex]\sigma[/tex]
Z= 60.6 - 67/ 8.6
Z= -0.7441
Hence, Patrisse did better as she had better z- score.
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I walked 280m of the road from the park to the station. This is equivalent to 9/10 of the total distance. How many meters is the total distance from the park to the station?
Answer:
311 1/9 or 311.11 mStep-by-step explanation:
Let the total distance be x.
We have:
9/10 of x is 280 m.Set this as equation and solve for x:
(9/10)x = 280x = 280 ÷ 9/10x = 280 × 10/9x = 2800/9 = 311 1/9 or 311.11 mTotal distance from the park to the station is approximately 311 m.
Let that be d
9/10 of d=2809/10d=280d=280(10/9)d=311.1m(7 + 7i)(2 − 2i)
(a) Write the trigonometric forms of the complex numbers. (Let
0 ≤ < 2.)
(7 + 7i) =
(2 − 2i) =
(b) Perform the indicated operation using the trigonometric forms. (Let
0 ≤ < 2.)
(c) Perform the indicated operation using the standard forms, and check your result with that of part (b).
The complex number -7i into trigonometric form is 7 (cos (90) + sin (90) i) and 3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)
What is a complex number?It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
We have a complex number shown in the picture:
-7i(3 + 3i)
= -7i
In trigonometric form:
z = 7 (cos (90) + sin (90) i)
= 3 + 3i
z = 4.2426 (cos (45) + sin (45) i)
[tex]\rm 7\:\left(cos\:\left(90\right)\:+\:sin\:\left(90\right)\:i\right)4.2426\:\left(cos\:\left(45\right)\:+\:sin\:\left(45\right)\:i\right)[/tex]
[tex]\rm =7\left(\cos \left(\dfrac{\pi }{2}\right)+\sin \left(\dfrac{\pi }{2}\right)i\right)\cdot \:4.2426\left(\cos \left(\dfrac{\pi }{4}\right)+\sin \left(\dfrac{\pi }{4}\right)i\right)[/tex]
[tex]\rm 7\cdot \dfrac{21213}{5000}e^{i\dfrac{\pi }{2}}e^{i\dfrac{\pi }{4}}[/tex]
[tex]\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}[/tex]
=21-21i
After converting into the exponential form:
[tex]\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}[/tex]
From part (b) and part (c) both results are the same.
Thus, the complex number -7i into trigonometric form is 7 (cos (90) + sin (90) i) and 3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)
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A scientist studying insects start with a population of 10. the population triples every hour. how many insects wil there be after 20 minutes
The question is asking you to understand that a population which is raised by a common ratio over a certain time period follows an exponential pattern. See:
After 1 hour, the population is 3*10
After 2 hours, the population is 3*3*10
After 3 hours, the population is 3*3*3*10
.....
This can be generalised as a function of t, the time in hours:
f(t) = (3^t) * 10
Since the function determines the population at a given time, it is more prudent to replace f(t) with P, the population after time t:
P = (3^t) * 10
Since 20 minutes is equal to (1/3) hours, t can be substituted for (1/3) in order to calculate the population size after 20 minutes:
P = (3^(1/3)) * 10 = 14.4224957031 ≈ 14
Therefore the population after 20 minutes is 14.
Find the inverse of the function.
y=x+9
Answer: [tex]y=x-9[/tex]
Step-by-step explanation:
To find the inverse of a function you must first swap the places of x and y
[tex]x=y+9[/tex]
Now solve for y
Step 1: Flip the equation.
[tex]y+9=x[/tex]
Step 2: Subtract 9 from both sides.
[tex]y+9-9=x-9\\y=x-9[/tex]
833.30/
1-(1+0.00833)^-360
Answer:
833.25 or 877.59
Step-by-step explanation:
I solved this in two different ways because I wasn't sure on how the question was meant to be read.
Attempt 1:
(833.3/1)-(1+0.00833)^-360
(1+0.00833)^-360 = 0.0505
so:
833.3 - 0.0505 = 833.25
Attempt 2:
833.3/(1-(1+0.00833)^-360)
1- 0.0505 = 0.9495
833.3/0.9495 = 877.59
PLEASEEEEEEE PLEASEEEEEE HELPPPPPP ASAPPPP
Find the measure of angle A in degrees.
Answer:
Angles are 45, 45 and 90 degrees because
AB and BC are congruent so that means the angles eating the sides are also congruent.
So to find the congruent angles:
180-90=90/2=45 degrees
To find AC:
a²+b²=c²
x²+x²=h²
√18=√c²
3√2=c
(I don't know why it says 3√3, but I think the q is wrong)
Hope it helps!
Answer:
45 degrees
Step-by-step explanation:
This is a special right triangle with these lengths. Which leads us to find the angles of 45, 45, 90 and B is 90 so A and C are 45 degrees.
A researcher believes that singing to plants causes them to grow an extra 0.5 inches on average per month. She tests this with 20 of her own plants by bringing 10 to work and leaving 10 at home. The ones at home she sings to each day, and she does not sing to the ones at her work.
The control variable that can be used in the research experiment is to ensure that the two set of plants will receive the same amount of water and light.
How to depict the control variable?According to the information, the researcher wants to seek whether singing to plants causes them to grow taller.
The explanatory variable is singing. Therefore, the researcher can control some of the variables to determine the explanatory variable on the growth of the plant.
Hence, the control variable that can be used in the research experiment is to ensure that the two set of plants will receive the same amount of water and light.
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