How does the mass of an object affect its motion through the air?

Answers

Answer 1
Mass does not affect the speed of falling objects assuming there is only gravity acting on it. For example Both Bullets will strike the ground at the same time. The horizontal force applied does not affect the downward motion of the bullets — only gravity and friction (air resistance), which is the same for both bullets
(Sorry if u don’t get what I mean)
Answer 2

The motion of an object through the air does not affect by its mass. The rate of fall of objects does not depend upon the mass.

What are free fall and air resistance?

Free fall is a motion of a body in which gravity is the only force acting upon it. An object moving upwards might not be considered to be falling. But if the object is under the effect of the force of gravity, it is said to be in free fall.

Free fall is a type of motion in which the force acting upon an object is only gravity. Objects are not encountering a significant force of air resistance as they are only falling under the sole influence of gravity. All objects under such conditions will fall with the same rate of acceleration, regardless of their masses.

As an object falls through the air, have gone through some degree of air resistance. Air resistance is the collisions of the object's leading surface with molecules present in the air. The two most common factors that have a direct effect on the amount of air resistance are the cross-sectional area of the object and the speed of the object.

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Related Questions

4. I wonder if the amount of homework I complete has an effect on my science test scores. a. Question: b. Hypothesis + Prediction: c. Independent Variable (IV): d. Dependent Variable (DV): e. Controlling Variable (CV): f. Experiment:

Answers

Answer:

a. Question

Explanation:

The statement above is more of a question rather than a hypothesis or the other options. Consider, the statement has no direct initial assumption or hint of personally researching for answers.

In other words, the speaker could be asking another individual his opinion whether the amount of homework completed has an effect on science test scores.

A tennis ball is shot vertically upward inside a tower with an initial speed of
20.0 m/s. Neglect air resistance. Approximately how long does it take the tennis ball to reach its maximum height?
0.50 s
2.04 s
4.08 s
6.08 s
9.80 s

Determine the velocity of the ball 3.0 s after it is thrown
9.40 m/s, downward
9.40 m/s, upward
29.4 m/s, downward
38.8 m/s, upward
38.8 m/s, downward

Answers

The ball's height at time t is

y = (20.0 m/s) t - 1/2 g t²

where g is the acceleration due to gravity, with magnitude 9.80 m/s².

Also, recall that

v² - u² = 2 ay

where u is the initial velocity, v is the final velocity, a is the acceleration, and ∆y is the change in height. Let Y be the maximum height. At this height, v = 0, so

- (20.0 m/s)² = 2 (-g) Y

==>  Y ≈ 20.408 m

Plug this into the first equation and solve for t :

Y = (20.0 m/s) t - 1/2 (9.80 m/s²) t²

==>  t ≈ 2.04 s

The ball's velocity at time t is

v = 20.0 m/s - g t

After t = 3.0 s, its velocity will be

v = 20.0 m/s - (9.80 m/s²) (3.0 s)

v = -9.40 m/s

or 9.40 m/s in the downward direction.

calculate the rate of change (slope) of the graph shown.

Answers

Answer:5

Explanation:

You do change in y over change in X

A train 4.00 3 102 m long is moving on a straight track with a speed of 82.4 km/h. The engineer applies the brakes at a crossing, and later the last car passes the crossing with a speed of 16.4 km/h. Assuming constant acceleration, determine how long the train blocked the crossing. Disregard the width of the crossing.

Answers

Answer:

The  value  is  [tex]t  =29.2  \  s [/tex]

Explanation:

From the question we are told that

Generally the average velocity of the train is mathematically represented as

          [tex]v  =  \frac{u +  v}{2}[/tex]

substituting  82.4 km/h for  u and   16.4 km/h. for  v

       [tex]v  =  \frac{82.4 + 16.4}{2}[/tex]

          [tex]v  =  49.4 \  km/h[/tex]

Generally the time taken is mathematically represented as

     [tex]t  =  \frac{ L}{v}[/tex]

substituting   49.4 \  km/h for  v and  [tex]4.00 * 10^2 \  m  =  0.400 \  km[/tex]

         [tex]t  =  \frac{ 0.400}{49.4}[/tex]

          [tex]t  = 0.00809 \  h [/tex]

converting to seconds

         [tex]t  = 0.00809 * 3600  [/tex]

          [tex]t  =29.2  \  s [/tex]

     

A car passes point “A” and then 120 meters later. It’s velocity was measured 21 m/s. If it’s acceleration was constant at 0.853 m/s2. What was the car’s velocity at point “A”?

Answers

Recall that

[tex]{v_f}^2-{v_i}^2=2a\Delta x[/tex]

where [tex]v_i[/tex] and [tex]v_f[/tex] are the initial and final velocities, respecitvely; [tex]a[/tex] is the acceleration; and [tex]\Delta x[/tex] is the change in position.

So we have

[tex]\left(21\dfrac{\rm m}{\rm s}\right)^2-{v_i}^2=2\left(0.853\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)[/tex]

[tex]\implies v_i\approx\boxed{15.4\dfrac{\rm m}{\rm s}}[/tex]

(Normally, this equation has two solutions, but we omit the negative one because the car is moving in one direction.)

Which situation is most likely to lead to improving a scientific theory?
A. Analyzing the history of how a theory was developed
O B. Gathering scientists for a brainstorming session
c. Increasing public awareness of the need for scientific research
O D. Performing experiments that have never been done before
SUBMIT

Answers

Performing experiments that have never been done before is most likely to lead to improving a scientific theory. The correct option is D.

What is scientific theory?

A theory is a well-thought-out elaboration for natural-world observational data that has been built using the scientific process and incorporates many facts and hypotheses.

A theory not only helps to explain established information; it also allows scientists to predict what they will see if the hypothesis is correct.

Scientific theories can be tested. Emerging data should be consistent with an existing theory.

To improve a scientific theory, conduct novel experiments on it. This will provide greater clarity on the theory.

It may reveal the limitations of this theory, as well as aspects of the theory that can be improved.

Thus, the correct option is D.

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Which of the following best describes weight? The amount of space an object takes up The amount of matter in an object The force on an object due to its mass and gravity The force on an object due to its speed and location

Answers

Explanation:

The force on an object due to it's mass and gravity.

6. What IMFA holds the molecules of water together?
A. hydrogen bond
C. ionic bond
B. nonpolar covalent bond
D. polar covalent bond

Answers

The answer is Polar covalent. btw, this is chemistry work. not physics

Which is larger, the Sun's pull on Earth or Earth's pull on the Sun?
a. The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun.
b. They pull on each other equally.
c. The Sun's pull on Earth is larger.
d. Earth's pull on the Sun is larger.
e. There is no pull or force between Earth and the Sun.

Answers

B it’s the most logical answer

At the time when the sun pulls on earth should be large so it should be pulled on each other equally.

Gravitational force:

Here the gravitational force that lies between two masses should be proportional with respect to the product of mass that should be divided via the square of the distance that lies between them. The acceleration should be measured when the force should be divided by the mass. Here the two forces should be equal and opposite

Therefore, the option b is correct.

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What physical property of Earth gives rise to the seasons?

Answers

Answer:

Earth's tilted axis causes the seasons. Throughout the year, different parts of Earth receive the Sun's most direct rays. So, when the North Pole tilts toward the Sun, it's summer in the Northern Hemisphere. And when the South Pole tilts toward the Sun, it's winter in the Northern Hemisphere.

Explanation:

In a circus act, an acrobat rebounds upward from the surface of a trampoline at the exact moment that another acrobat, perched 9.0 m above him, releases a ball from rest. While still in flight, the acrobat catches the ball just as it reaches him.Required:If he left the trampoline with a speed of 5.6 m/s, how long is he in the air before he catches the ball?

Answers

Answer:

1.6 secs

Explanation:

In a circus act, an acrobat upwards from the surface of a trampoline

At that same moment another acrobat perched 9.0m above him

A ball is released from rest

While still in motion the acrobat catches the ball

He left the ball with a trampoline of 5.6m/s

Since the ball is falling downwards from a distance then acceleration will be negative

a= -9.8

s= d

s= 1/2at^2

= 1/2 × (-9.8)t^2

= 0.5× (-9.8)t^2

d = -4.9t^2

Therefore the time the acrobat stays in the air before catching the ball can be calculated as follows

9 - 4.9t^2= 5.6t + 1/2(-9.8)t^2

9 - 4.9t^2= 5.6t + (-4.9)t^2

9 - 4.9t^2= 5.6t - 4.9t^2

9= 5.6t

t= 9/5.6

t= 1.6 secs

Which formula is used to find an object's acceleration? ​

Answers

a=v-v0 divided by t equals delta(the triangle) V divided by delta t

Answer:

The answer is C.

Explanation:

A group of engineers is preparing a satellite to land by moving it 10% closer to
Earth in each rotation. Which statement is correct about the rotational inertia of
the satellite? (1 point)
O Rotational inertia does not change because it is conserved.
Rotational inertia increases proportional to the decrease in the
radius of rotation.
Rotational inertia first decreases and then increases as the
satellite is ready to land.
O
Rotational inertia decreases proportional to the decrease in the
radius of rotation.

Answers

Answer:

Rotational inertia decreases proportional to the decrease in the radius of rotation.

Explanation:

The rotational inertia decreases proportional to the decrease in the

radius of rotation.

Rotational inertia is directly proportional to the angular momentum of the object and inversely proportional to its angular velocity.

[tex]I = \frac{L}{\omega}[/tex]

where;

I is the rotational inertiaL is the angular momentumω is the angular speed

The angular momentum is given as;

[tex]L = mvr[/tex]

where;

m is the mass of the objectv is the velocity of the objectr is the radius of the object

The new rotational inertia equation becomes;

[tex]I = \frac{mvr}{\omega}[/tex]

From this equation, we can observe that the rotational inertia is directly proportional to the radius of the object.

A 10% closer to the Earth, means a decrease in the radius of the satellite by 10%.

Thus, a decrease in the rotational inertia as well.

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Which of the following BEST explains the energy transformation that takes place when a battery alarm clock goes off.

A. electrical energy --> chemical energy --> sound energy

B. electrical energy --> chemical energy --> mechanical energy --> sound energy

C. chemical energy --> electrical energy --> mechanical energy --> sound energy

D. it is impossible to tell without knowing what type of battery

Answers

I think it might be Either A or B im thinking B

Your office has a 0.025 m^3 cylindrical container of drinking water. The radius of the container is about 13 cm. Required:a. When the container is full, what is the pressure that the water exerts on the sides of the container at the bottom of the container above the atmospheric pressure? b. When the container is full, what is the pressure that the water exerts on the sides of the container halfway down from the top above the atmospheric pressure?

Answers

Answer:

a) 105935.7 Pa

b) 103630.35 Pa

Explanation:

The volume of the container = 0.025 m^3

The radius of the container = 13 cm = 0.13 m

We have to find the height of the tank

From the equation for finding the volume of the cylinder,

V = [tex]\pi r^2h[/tex]

where

V is the volume of the cylinder

h is the height of the cylinder

substituting values, we have

0.025 = 3.142 x [tex]0.13^2[/tex] x h

0.025 = 0.0531h

h = 0.025/0.0531 = 0.47 m

Pressure at the bottom of the tank P = ρgh

where

ρ is the density of water = 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

h is the depth of water which is equal to the height of the tank

substituting values, we have

P = 1000 x 9.81 x 0.47 = 4610.7 Pa

atmospheric pressure = 101325 Pa

therefore, the pressure in the tank bottom above atmospheric pressure = 101325 Pa + 4610.7 Pa = 105935.7 Pa

b) For half way down the container, depth of water will be = 0.47/2 = 0.235 m

pressure P = 1000 x 9.81 x 0.235 = 2305.35 Pa

This pressure above atmospheric pressure = 101325 Pa + 2305.35 Pa = 103630.35 Pa

(a) The pressure exerted by water on the sides of the container at the bottom is 4606 Pa.

(b) The pressure exerted by water on the sides of the container halfway down from the top is of 2303 Pa.

Given data:

The volume of cylindrical container is, [tex]V = 0.025 \;\rm m^{3}[/tex].

The radius of container is, r = 13 cm = 0.13 m.

(a)

When the container is full, the pressure that the water exerts on the sides of the container is given as,

[tex]P = \rho gh[/tex]

Here, [tex]\rho[/tex]  is the density of water, g is the gravitational acceleration and h is the height of container and its value is obtained as,

[tex]V = \pi r^{2}h\\\\0.025= \pi \times (0.13)^{2} \times h\\\\h = 0.47 \;\rm m[/tex]

Then pressure is,

[tex]P = 1000 \times 9.8 \times 0.47\\\\P=4606 \;\rm Pa[/tex]

Thus, the pressure exerted by water on the sides of the container at the bottom is 4606 Pa.

(b)

For the ides of the container halfway down from the top, the height is,

h' = h/2

h' = 0.47/2 = 0.235 m

Then the pressure is obtained as,

[tex]P' = \rho \times g \times h'\\\\P' = 1000 \times 9.8 \times 0.235\\\\P'=2303 \;\rm Pa[/tex]

Thus, the pressure exerted by water on the sides of the container halfway down from the top is of 2303 Pa.

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A two-liter bottle is one-fourth full of water and three-quarters full of air. The air in the bottle has a gage pressure of 340 kPa. The bottle is turned upsidedown and the cap is released so that the water is rapidly forced out of the bottle. If the air in the bottle undergoes an adiabatic pressure change, what is the pressure in the bottle when the bottle is five-sixths full of air

Answers

Answer:

The value is     [tex] P_G  =  2.925 *10^{5} \  Pa[/tex]

Explanation:

From the question we are told that

   The  volume of the bottle is  [tex]v  =  2 \  L  =  2 *  10^{-3} \  m^3[/tex]

   The gauge pressure of the air is [tex]P_g  =  340 \  kPa  =  340 *10 ^{3}  \  Pa[/tex]

   

Generally the volume of air before the bottle is turned upside down is  

      [tex]V_a  =  \frac{3}{4}  * V[/tex]

       [tex]V_a  =  \frac{3}{4}  *  2 *10^{-3}[/tex]

       [tex]V_a  =  0.0015 \  m^3 }[/tex]

Generally the volume air when the bottle is turned upside-down is

      [tex]V_u  =  \frac{5}{6}  *  2 *10^{-3}[/tex]

       [tex]V_u  =  0.00167 \  m^3 [/tex]

From the the mathematical relation of adiabatic process we have that

     [tex]P_g *  V_a^r  =  P_G *  V_u^r[/tex]

Here r is a constant with  a value  r =  1.4

So

      [tex] 340 *10 ^{3}  *  0.0015^{1.4}  =  P_G *  0.00167^{1.4}[/tex]

        [tex] P_G  =  2.925 *10^{5} \  Pa[/tex]

How does the lighter material of the bamboo affect the force created by the rider on the bike?

Answers

2223 but dry gc dresdyy tv hockey vocals

Newton's second law allows us to find the result for the effect of building a lower mass bike is:

An increase in the acceleration of the bicycle.

Newton's second law states that force is equal to the product of mass and acceleration of the body.

          ∑ F = m a

Where the bold letters indicate vectors, m is the mass and  a the acceleration.

They indicate that the bicycle is made of bamboo, so it has less mass, therefore the acceleration is:

          [tex]a = \frac{\sum F}{m}[/tex]

if the mass decreases, more acceleration is recorded, therefore from the kinematic reactions the bicycle reaches higher speeds.

         v = v₀ + a t

The bicycles parts of the rest.

          v = a t

In conclusion, using Newton's second law we can find the result for the effect of building a bicycle with alower mass is:

An increase in the acceleration of the bicycle.

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John is gliding along on his scooter at a speed of 2.8 m/s when
suddenly he collides with Sam who is walking around the corner. If
John is brought to rest in 0.15 s, what is his acceleration?

Answers

Answer: His acceleration is -18.66m/s^2

Explanation:

Ok, the initial speed is 2.8m/s. (we can define the initial direction as the positive direction).

And he wants to stop, so he must accelerate in the opposite direction as the initial movement, then we would have:

a(t) = -A.

So we have a constant, and negative acceleration.

Now, if we want to find the velocity we must integrate over time, and we will get:

v(t) = -A*t + V0

where V0 is the initial velocity, we know that it is 2.8m/s, and t is the time in seconds.

Then the velocity is:

v(t) = -A*t + 2.8m/s.

Now we know that John is brought to rest in 0.15 seconds after he starts slowing down, this means that at t = 0.15 seconds, his velocity is equal to zero.

v(0.15s) = 0m/s = -A*0.15s + 2.8m/s

2.8m/s = A*0.15s

2.8m/s/0.15s = 18.66m/s^2 = A.

So his acceleration is -A, then we have that:

His acceleration is -18.66m/s^2

what is the net force on a backpack with a mass of 12.0 kg and an acceleration of 0.5 m/s^2?

Answers

Answer:

The answer is

6.0 N

Explanation:

The net force acting on an object when given the mass and acceleration can be found by using the formula

Force = mass × acceleration

From the question

mass of backpack = 12 kg

acceleration = 0.5 m/s²

So the force is

Force = 12 × 0.5

We have the final answer as

6.0 N

Hope this helps you

Part A.)Six boxes held at rest against identical walls.

Rank the boxes on the basis of the magnitude of the normal force acting on them.

Rank from largest to smallest. To rank items as equivalent, overlap them.

1) 130N--->7kg

2) 150N--->1kg

3) 150N--->7kg

4) 120N--->3kg

5) 140N--->5kg

6) 140N--->3kg

(Since the boxes are at rest, Newton's 2nd law dictates that the horizontal forces on each box must add up to zero. You can use this information to determine the normal forces. If two boxes are both pushed against the wall by the same force, then they should experience the same normal force.)

Part B.) Rank the boxes on the basis of the frictional force acting on them.

Rank from largest to smallest. To rank items as equivalent, overlap them.

1) 130N--->7kg

2) 150N--->1kg

3) 150N--->7kg

4) 120N--->3kg

5) 140N--->5kg

6) 140N--->3kg

Answers

Answer:

Explanation:

When a body is held against a vertical wall , to keep them in balanced position , normal force is applied on their surface . this force creates normal reaction which acts against the normal force and it is equal to the normal force as per newton's third law . Ultimately friction force is created which is proportional to normal force and it acts in vertically upward direction . It prevents the body from falling down .

Hence normal force = reaction force .

From second law also net force is zero , so if  normal force is N and reaction force is R

R - N = mass x acceleration = mass x 0 = 0

R = N .

Ranking normal force from  highest  to smallest

150 N , 130 N , 120 N

B )

Frictional force is equal to the weight of the body because the body is held at rest .

Ranking of frictional force form largest to smallest

7 kg , 5 kg , 3 kg , 1 kg .

Here frictional force is irrespective of the normal force acting on the body  because frictional force adjusts itself so that it becomes equal to weight in all cases here because it always balances the weight of the body .

Based on the magnitude of normal force acting on them, the ranking from largest to smallest will be:

150N--->7kg =  150N--->1kg.140N--->5kg =  140N--->3kg.130N--->7kg. 120N--->3kg.

Based on the masses, the frictional force acting on the boxes will be such that the ranking from largest to smallest will be:

150N--->7kg = 130N--->7kg. 140N--->5kg 140N--->3kg = 120N--->3kg 150N--->1kg

Normal force magnitude

The normal forces acting on the box will depend on the force acting on the box. This means that the larger the force acting on the box, the larger the normal force.

This is why the box with a force of 150 N will be have the highest normal force acting on it.

Frictional force magnitude

The frictional force acting on the boxes will depend on the mass. Boxes will lager masses will have more frictional force acting on them.

The boxes of 7kg will therefore have the largest frictional forces acting on them.

Find out more on frictional forces at https://brainly.com/question/24386803.

A car traveling at 50 km/h hits a bridge abutment. A passenger in the car moves forward a distance of 61 cm (with respect to the road) while being brought to rest by an inflated air bag. What magnitude of force (assumed constant) acts on the passenger's upper torso, which has a mass of 44 kg?

Answers

Answer:

6957.04N

Explanation:

Using

vf2=vi2+2ad

But vf = 0 .

So convert 50km/hr to m/s, and you need to convert 61 cmto m

(50km/hr)*(1hr/3600s)*(1000m/km) = 13.9m/s

61cm * (1m/100cm) = .61m

So n

0 = (13.9m/s)^2 + 2a(.61m)

a = 158.11m/s^2

So

using F = ma

F = 44kg(158.11m/s^2) = 6957.04N

Answer:

6.95 kN

Explanation:

Given that

Speed of the car, u = 50 kmph

Distance moved by the passenger, s = 61 cm = 0.061 m

Mass of the passenger, m = 44 kg

Converting the initial velocity from km/h to m/s, we have

50 kmph = 50 * 1000/3600

50 kmph = 13.89 m/s

Using one of the equations of motion,

v² = u² + 2as, where v = 0,making a the subject of formula

a = -u²/2s

a = -(13.89²) / 2 * 0.61

a = -192.93 / 1.22

a = -158 m/s²

The force acting on the passenger's leg, F = m.a, so

-F = 44 * -158

F = 6952 N, or 6.95 kN

The centroid of the plane region shown is at c. use the method of composite area to determine the radius (R)? please someone help me i nedd your helps guys please!​

Answers

I don’t understand what are you trying to do ?


What is the difference between an observation and an inference?

Answers

Explanation:

observation is something what you could observe from your organs like eyes ears etc and also it is what you observed during an event for an experiment but inference is what you decide to do after observation or an event.

the act of inferring (to derive by reasoning). Observation = an act or instance of noticing or perceiving.

Thank u!

An owl is carrying a mouse to the chicks in its nest. It is 4.00 m west and 12.0 m above the center of the 30 cm diameter nest and is flying east at 2.50 m/s at an angle 32° below the horizontal when it accidentally drops the mouse. Will it fall into the nest? Find out by solving for the horizontal position of the mouse (measured from the point of release) when it has fallen the 12.0 m.

Answers

Answer:

4.61 m away

Explanation:

No, the owl will not fall into the nest.

The vertical component of the velocity, v of mouse after travelling vertical distance of 12 m is given by

v² - (4 * sin 32)² = 2 * 9.81 * 12

v² - (4 * 0.53)² = 235.44

v² - 4.494 = 235.44

v² = 235.44 + 4.494

v² = 239.934

v = 15.49 m/s

The time taken to travel the said 12 m downwards =

(15.49 - 4 * sin 32) / 9.81

(15.49 - 4 * 0.53) / 9.81

(15.49 - 2.12) / 9.81

13.37 / 9.81 = 1.36 s

Horizontal distance traveled in this time = 4 * (cos 32) * 1.36

= 4 * 0.848 * 1.36

= 4.61 m

Therefore, the horizontal position of the mouse is 4.61 m away from the point of release.

Part A
Suppose that you want to construct a line with slope m=3 that passes through the point (2,1). You would begin by setting up the equation
y=3x+b.
If you plug in the coordinates for any point on that line, the two sides of the equation will be equal. Once you've done this, you can solve for b. What is the value of b?
Express your answer as an integer.
Part B
Suppose that you want to find the equation for a line that passes through the two points (0,3) and (4,9). What is the slope of this line?
Express your answer numerically.

Answers

Answer:

a) b = -5

b) slope = 3/2

Explanation:

a) The equation of a line is given as y = mx + b, where m is the slope of the line and b is the intercept on the y axis.

Given that y = 3x + b and it passes through the point (2, 1). Hence when x = 2, y = 1. Therefore, substituting for x and y:

1 = 3(2) + b

1 = 6 + b

b = 1 - 6

b = -5

b) The equation of a line passing through two points ([tex]x_1,y_1[/tex]) and [tex]x_2,y_2[/tex] is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

The equation of the line passing through the two points (0,3) and (4,9) is:

[tex]y-3=\frac{9-3}{4-0}(x-0)\\ \\y-3=\frac{3}{2}x\\ \\y = \frac{3}{2}x+3[/tex]

Comparing y = (3/2)x + 3 with y = mx + b, the slope (m) is 3/2

Emily takes a trip, driving with a constant velocity of 85.5 km/h to the north except for a 22 min rest stop. If Emily's average velocity is 68.8 km/h to the north, how long does the trip take? Show your work

Answers

Answer:

1½ hours

Explanation:

Let the amount of time she drove at 85.5 km/hr be t, then

The distance that she rode would be 85.5 * t

This is means Emily has traveled the same distance at 68.8 km/hr without any stoppage whatsoever. Thus, we can create an equation as such

85.5 * t = 68.8 (t + 22/60), the 22/60 being, converting 22 minutes into hours. We proceed further as

85.5t = 68.8t + 1513.6/60, multiplying all sides by 60, we have

5130t = 4128t + 1513.6, now we collect like terms

5130t - 4128t = 1513.6

1002t = 1513.6

t = 1513.6/1002

t = 1.51 hrs, or in minutes, 1.51 * 60

t = 90.63 minutes. 1 hour and 36 minutes

So the total time the trip took, 22 minutes in addition, or say, 1 hour 58 minutes.

What elements on the periodic table are metalloids?

Answers

Answer:

The term 'mettaloid' is normally applied to a group of between six and nine elements ;

BoronSilicon GermaniumArsenicAntimonyTellurium, and possibly BismuthPolonium Astatine

are found near the center of the P-block or main block of the periodic table.

Explanation:

A point charge q is placed at the center of a spherical Gaussian surface. The electric fix through the surface will change if:
a. the shape or the surface to a changed to a cube with the same volume as the original sphere.
b. the point charge is moved off center (but still inside the sphere) the point charge is moved to allocation just outside the sphere.
c. if a second point charge is placed just outside the sphere.
d. the radius of the surface is doubled.

Answers

Answer:

. the point charge is moved off center (but still inside the sphere) the point charge is moved to allocation just outside the sphere.

Explanation:

Because

Gaussian surface is given as

ϕ= qclose/E0

​So Q enclosed charge will be same if w the charge inside the Gaussian surface is moved, so flux will not change.

measurement conversions [metric to metric] 568 cm = m​

Answers

Answer:

5.68 meters

Explanation:

hope this helps!

Answer:

5.68

Explanation:

to convert cm to m you  move the decimal point 2x to the left

4. What is the instantaneous acceleration at t= 10 s?

Answers

Answer:

I am fairly certain the answer is 2m/s^2

Explanation:

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