How many faces are there?
A. 7
B. 10
C. 15
D. not enough information

How Many Faces Are There?A. 7B. 10C. 15D. Not Enough Information

Answers

Answer 1

The polyhedron has 7 faces.

To find the faces of the figure.

What is polyhedron?

A polyhedron is a 3D shape that has flat faces, straight edges, and sharp vertices (corners). The regular polyhedron are the tetrahedron, cube, octahedron, icosahedron, and dodecahedron. when many flat surfaces are joined together they form a polyhedron.

Given that:

The given figure,

By the use of  Euler's formula to find the faces.

F + V - E = 2

Where F = Faces, V = Vertices and E = Edges

Given, V = 10 and E = 15

F + 10 - 15 = 2

F - 5 = 2

F = 5 + 2 = 7

Therefore, the polyhedron has 7 faces.

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Related Questions

find the area of the triangle

Answers

Answer:

75.03

Step-by-step explanation:

14×11×sin(77)

= 75.02649499..

≈ 75.03 (rounded to nearest hundredth)

Answered by GAUTHMATH

The proportion of the variation in the dependent variable y that is explained by the estimated regression equation is measured by the _____. a. coefficient of determination b. correlation coefficient c. confidence interval estimate d. standard error of the estimate

Answers

Answer:

coefficient of determination

Step-by-step explanation:

The Coefficient of determination, R² which is the squared value of the correlation Coefficient is used to give Tha proportion of variation in the predicted / dependent variable that can be explained by the regression line. The coefficient of determination ranges from 0 to 1. Once the proportion of explained variation is obtained, the proportion of unexplained variation is ( 1 - proportion of explained variation).

log_c(A)=2
log_c(B)=5,
solve log_c(A^5B^3)

Answers

We know that [tex]\log_a(bc)=\log_a(b)+\log_a(c)[/tex].

Using this rule,

[tex]\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3)[/tex].

We also know that [tex]\log_c(a^b)=b\log_c(a)[/tex].

Using this rule,

[tex]\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)[/tex]

Now we know that [tex]\log_c(A)=2,\log_c(B)=5[/tex] so,

[tex]5\cdot2+3\cdot5=10+15=\boxed{25}[/tex].

Hope this helps :)

Suppose that a population begins at a size of 100 and grows continuously at a rate of 200% per year. Give the formula for calculating the size of that population after t years.
A) A = 100 + te^2
B) A = 100 + e^2t
C) A = 100e^2t
D) A = 100 + 2e^t

Answers

Answer:

D)

Step-by-step explanation: Im not so sure ok i sorry if Im wrong

I need help answering this ASAP

Answers

Answer:

"D"

if you multiply by Conjugate

the denominator would end up A^2 - b^2

the answer has 25 - 10x

that is D

Step-by-step explanation:

Write the expression as a single trigonometric function.
cos 5x cos 6x- sin 5x sin 6x

Answers

Answer:

[tex]\cos(11x)[/tex]

Step-by-step explanation:

Given

[tex]\cos 5x\ \cos 6x- \sin\ 5x \sin 6x[/tex]

Required

Express as a single function

In trigonometry, we have:

[tex]\cos(A + B) = \cos A\cos B - \sin A \sin B[/tex]

By comparison, we have

[tex]\cos(5x + 6x) = \cos 5x\cos 6x - \sin 5x \sin 6x[/tex]

[tex]\cos(11x) = \cos 5x\cos 6x - \sin 5x \sin 6x[/tex]

Write the point-slope form of an equation of the line through the points (-4, 7) and (5,-3).
0
A. Y+4= -1; (1 – 7)
B.Y-5 = = 10 (x+3)
OC. y +3 = = 10 (2+5)
D. y - 7= -5° (x+4)

Answers

Answer:

Step-by-step explanation:

There are two possible equations, but neither matches the the choices you listed. The choices seem to have several typographical errors.

Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 =(-10/9)(x + 4).

How to estimate the point-slope form of an equation of the line through the points (-4, 7) and (5,-3)?

Slope

[tex]$= \frac{y_{2} -y_{1}}{x_{2} -x_{1}}[/tex]

= (-3 - 7) / (5 - (-4))

= -10/9

The point-slope equation for the line of slope -(10/9) that passes through the point (5, -3).

y + 3 = (-10/9)(x - 5)

Point slope equation for the line of slope -(10/9) that passes through the point (-4, 7)

Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 = (-10/9)(x + 4).

Therefore, the correct answer is y - 7 = (-10/9)(x + 4).

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Which is the
Simplified form
r-7+s-12

Answers

Answer:

r + s - 19

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

r - 7 + s - 12

Step 2: Simplify

Combine like terms [constants]:                                                                          r + s - 19

Starting with a fresh bar of soap, you weigh the bar each day after you take a shower. Then you find the regression line for predicting weight from number of days elapsed. The slope of this line will be:__________.

Answers

Answer:

The slope will be negative

Step-by-step explanation:

The slope of the regression line tells us about the relationship or behavior of the dependent and independent variables. In the scenario above, where the weight is being compared with the number of days elapsed. What is expected of the weight and quantity of a bar soap each time it is used for a shower is that it will decrease in weight. Therefore, as the number of days increases, and hence, number of showers rise, the weight of soap will decrease. Hence, we'll obtain a negative slope, one in which the increase in a variable leads to decrease in the other.

!!!!PLEASE HELP!!!!
What is the following quotient?
2
√13+ /11
O 13-2./11
13+ 11
6
13+ V11
12
√13 - 1

Answers

(D)

Step-by-step explanation:

Multiply and divide the fraction by the conjugate:

[tex]\dfrac{2}{\sqrt{13}+\sqrt{11}}×\dfrac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}[/tex]

[tex]= \dfrac{2(\sqrt{13} - \sqrt{11})}{(\sqrt{13})^2 - (\sqrt{11})^2}[/tex]

[tex]=\dfrac{2(\sqrt{13} - \sqrt{11})}{2}[/tex]

[tex]=\sqrt{13} - \sqrt{11}[/tex]

3/4 pound of Colby cheese costs $1.69. Find the unit price per pound. (3/4 pound=12)

Answers

Answer:

2.25

Step-by-step explanation:

We can write a ratio to solve

1.69           x

------     = ---------------

3/4 lb              1 lb

Using cross products

1.69 * 1 = 3/4 *x

1.69 = 3/4 x

Multiply by 4/3

1.69 * 4/3  = x

x=2.25333

Rounding to the nearest cent

You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and the model (regression) sum of squares is 750. What is the adjusted R-squared value for this model

Answers

Answer:

Hence the adjusted R-squared value for this model is 0.7205.

Step-by-step explanation:

Given n= sample size=20  

Total Sum of square (SST) =1000  

Model sum of square(SSR) =750  

Residual Sum of Square (SSE)=250  

The value of R ^2 for this model is,  

R^2 = \frac{SSR}{SST}  

R^2 = 750/1000 =0.75  

Adjusted [tex]R^2[/tex] :

[tex]Adjusted R^2 =1- \frac{(1-R^2)\times(n-1)}{(n-k-1)}[/tex]

Where k= number of regressors in the model.

[tex]Adjusted R^2 =1-(19\times 0.25/((20-2-1)) = 0.7205[/tex]

I need to know the answer ASAP

Answers

Answer:

Step-by-step explanation:

Smart phone: Among 239 cell phone owners aged 18-24 surveyed, 103 said their phone was an Android phone. Part: 0 / 30 of 3 Parts Complete Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is .

Answers

Answer:

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

Step-by-step explanation:

The point estimate is the sample proportion.

Sample proportion:

103 out of 249, so:

[tex]p = \frac{103}{249} = 0.4137[/tex]

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

AB is tangent to the circle at B. M∠A = 27 and mBC=114 (The figure is not drawn to scale.)

Answers

9514 1404 393

Answer:

  a.  x = 60

  b.  y = 93

Step-by-step explanation:

The relevant relations are ...

external angle A is half the difference of intercepted arcs BC and BDinscribed angle y° is half the measure of intercepted arc CDthe sum of arcs of a circle is 360°

__

Using these relations, we have ...

  A = (BC -x°)/2

  x° = BC -2A = 114° -2(27°)

  x° = 60°

__

  y° = CD/2 = (360° -BC -BD)/2 = (360° -114° -60°)/2

  y° = 93°

Which of the following conversions is possible?
Meters to Liters
Feet to Miles
Pounds to Inches
Grams to Centimeters

Answers

Answer:

Feet to Miles

Step-by-step explanation:

Answer:

Feet to Miles

Step-by-step explanation:

Both units must measure the same quantity.

Please help me with this question

Answers

the answer above is correct!:))

Can someone help me? I don’t know how to solve the rest. I am struggling and I would be so happy if any of you helped me. Thank you for your help!

Answers

15.87%
2. 6 pounds and 8.8 pounds.
3. 2.28%
4. 50% of newborn babies weigh more than 7.4 pounds

I hope this helps.

do the two trapezoids in the figure appear to be similar? why or why not?

Answers

Answer:

The answer is D cuz two if the corresponding angles are congruent.

Oh Brian~
I need help again

Answers

Answer:

18c^3d^9

Step-by-step explanation:

2c^3 d^2 * 9d^7

We know that  we add the exponents when the base is the same

2*9  c^3 d^(2+7)

18c^3d^9

When a 0.42 tax was added to the price of a ticket, the total bill come to $7.03. Describe the above situation as a linear equation.

Answers

Answer:

P = 7.03 - 0.42T

Step-by-step explanation:

Let the price of a ticket be P.

Let the ticket be T.

A linear equation can be defined as an algebraic equation that's typically written for two (2) independent variables, in which each of them has an exponent of one (1) and they make a straight line when plotted on a graph.

Given the following data;

Tax = 0.42

Total bill = $7.03

Translating the word problem into an algebraic expression, we have;

0.42T + P = 7.03

P = 7.03 - 0.42T

HELP PLEASE AND BE CORRECT

Answers

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Each point moves to 3 times its original distance from P.

  A is 2 up and 1 left of P, so A' will be 6 up and 3 left of P.

  B is 1 down and 2 left of P, so B' will be 3 down and 6 left of P.

  C is 2 right of P, so C' will be 6 right of P.

An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from soil. Out of 155 seeds planted in soil containing 3% mushroom compost by weight, 74 germinated. Out of 155 seeds planted in soil containing 5% mushroom compost by weight, 86 germinated. Can you conclude that the proportion of seeds that germinate differs with the percent of mushroom compost in the soil

Answers

Solution :

Let [tex]p_1[/tex] and [tex]p_2[/tex]  represents the proportions of the seeds which germinate among the seeds planted in the soil containing [tex]3\%[/tex] and [tex]5\%[/tex] mushroom compost by weight respectively.

To test the null hypothesis [tex]H_0: p_1=p_2[/tex] against the alternate hypothesis  [tex]H_1:p_1 \neq p_2[/tex] .

Let [tex]\hat p_1, \hat p_2[/tex] denotes the respective sample proportions and the [tex]n_1, n_2[/tex] represents the sample size respectively.

[tex]$\hat p_1 = \frac{74}{155} = 0.477419[/tex]

[tex]n_1=155[/tex]

[tex]$p_2=\frac{86}{155}=0.554839[/tex]

[tex]n_2=155[/tex]

The test statistic can be written as :

[tex]$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}[/tex]

which under [tex]H_0[/tex]  follows the standard normal distribution.

We reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance, if the P-value [tex]<0.05[/tex] or if [tex]|z_{obs}|>Z_{0.025}[/tex]

Now, the value of the test statistics = -1.368928

The critical value = [tex]\pm 1.959964[/tex]

P-value = [tex]$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$[/tex]

                                     [tex]$=2 \times 0.085667$[/tex]

                                     = 0.171335

Since the p-value > 0.05 and [tex]$|z_{obs}| \ngtr z_{critical} = 1.959964$[/tex], so we fail to reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the [tex]\text{proportion}[/tex] of the seeds that [tex]\text{germinate differs}[/tex] with the percent of the [tex]\text{mushroom compost}[/tex] in the soil.

Another name for the standardized score from a normally distributed variable is the _____.
A. standard score
B. z-score
C. t-score
D. normal score

Answers

Answer:

the answer is b). z- score.

Answer:

b

Step-by-step explanation:

Find the equation of the line passing through the point (-1,2)
and the points of intersections of the line 2x - 3y + 11 = 0 and
5x + y + 3 = 0​

Answers

Answer:

[tex]y=-5x-3[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0).

To solve for the equation of the line, we would need to:

Find the point of intersection between the two given linesUse the point of intersection and the given point (-1,2) to solve for the slope of the lineUse a point and the slope in [tex]y=mx+b[/tex] to solve for the y-interceptPlug the slope and the y-intercept back into [tex]y=mx+b[/tex] to achieve the final equation

1) Find the point of intersection between the two given lines

[tex]2x - 3y + 11 = 0[/tex]

[tex]5x + y + 3 = 0[/tex]

Isolate y in the second equation:

[tex]y=-5x-3[/tex]

Plug y into the first equation:

[tex]2x - 3(-5x-3) + 11 = 0\\2x +15x+9 + 11 = 0\\17x+20 = 0\\17x =-20\\\\x=\displaystyle-\frac{20}{17}[/tex]

Plug x into the second equation to solve for y:

[tex]5x + y + 3 = 0\\\\5(\displaystyle-\frac{20}{17}) + y + 3 = 0\\\\\displaystyle-\frac{100}{17} + y + 3 = 0[/tex]

Isolate y:

[tex]y = -3+\displaystyle\frac{100}{17}\\y = \frac{49}{17}[/tex]

Therefore, the point of intersection between the two given lines is [tex](\displaystyle-\frac{20}{17},\frac{49}{17})[/tex].

2) Determine the slope (m)

[tex]m=\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug in the two points [tex](\displaystyle-\frac{20}{17},\frac{49}{17})[/tex] and (-1,2):

[tex]m=\displaystyle \frac{\displaystyle\frac{49}{17}-2}{\displaystyle-\frac{20}{17}-(-1)}\\\\\\m=\displaystyle \frac{\displaystyle\frac{15}{17} }{\displaystyle-\frac{20}{17}+1}\\\\\\m=\displaystyle \frac{\displaystyle\frac{15}{17} }{\displaystyle-\frac{3}{17} }\\\\\\m=-5[/tex]

Therefore, the slope of the line is -5. Plug this into [tex]y=mx+b[/tex]:

[tex]y=-5x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=-5x+b[/tex]

Plug in the point (-1,2) and solve for b:

[tex]2=-5(-1)+b\\2=5+b\\-3=b[/tex]

Therefore, the y-intercept is -3. Plug this back into [tex]y=-5x+b[/tex]:

[tex]y=-5x+(-3)\\y=-5x-3[/tex]

I hope this helps!

Suppose that the distribution of snake lengths in a certain park is not assumed to be symmetric. According to Chebyshev's Theorem, at least what percentage of snake lengths are within k =2.9 standard deviations of the mean?

Answers

According to Chebyshev,

P(|X - µ| ≤ 2.9σ) ≥ 1 - 1/2.9² ≈ 0.8811

Form a polynomial whose zeros and degree are given,
Zeros: - 2, 2,7; degree: 3
Type a polynomial with integer coefficients and a leaning coefficient of 1 in the box below.

F(x)=

Answers

Answer:

if the zeros are x = -2, x = 0, and x = 1

then (x + 2), x and (x - 1) are factors of the polynomial

multiply these factors together

p(x) = x(x + 2)(x - 1)

p(x) = x(x2 + x - 2)

p(x) = x3 + x2 - 2x

this is a polynomial of degree 3 with the given roots

A building 51 feet tall casts a shadow 48 feet long. Simultaneously, a nearby statue casts a shadow of 16 feet. How tall is the statue? Choose an answer

Answers

Answer: 17 feet

Step-by-step explanation:

51/48 = x/16

(51)(16)/48

The statute is 17 feet tall.

What are the similar triangles?

Similar triangles are the triangles that have the same shape, but different sizes. The corresponding angles are congruent and the sides are in proportion.

What is the ratio of any two corresponding sides of similar triangles?

The ratio of any corresponding sides in two equiangular triangles is always the same.

Let's visualize the situation according to the given question.

AB is the building ,whose height is 51f

BC is the shadow of the building AB, whose length is 48ft.

QR is the shadow of the tower statue, whose length is 16feet.

Let the height of the statue PR be h feet.

In triangle ACB and triangle PRQ

∠ACB = ∠PRQ = 90 degrees  

( the objects and shadows are perpendicular to each other)

∠BAC = ∠QPR

( sunray falls on the pole and tower at the same angle, at the same time )

ΔACB similar to ΔPRQ   ( AA criterion)

Therefore, the ratio of any two corresponding sides in equiangular triangles is always same.

⇒ AC/CB = PR/RQ

⇒[tex]\frac{51}{48} =\frac{h}{16}[/tex]

⇒ h = [tex]\frac{(51)(16)}{48}[/tex]

⇒ h = 17 feet.

Hence, the statute is 17 feet tall.    

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x^{2} +y^{2} =?
cho mình hỏi với

Answers

Answer:

[tex]{ \sf{ {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy }}[/tex]

Step-by-step explanation:

[tex]{ \tt{ {(x + y)}^{2} = (x + y)(x + y) }} \\ { \tt{ {(x + y)}^{2} = ( {x}^{2} + 2xy + {y}^{2}) }} \\ { \tt{( {x}^{2} + {y}^{2} ) = {(x + y)}^{2} - 2xy}}[/tex]

solve x^3-7x^2+7x+15​

Answers

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

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Test the claim by constructing an appropriate confidence interval.The 95% confidence interval is nothing(Round to three decimal places as needed.) What is the conclusion based on the confidence interval?Because the confidence interval limits includedo not include 0, there doesdoes not appear to be a significant difference between the two proportions. There is sufficientis not sufficient evidence to warrant rejection of the claim that men and women have equal success in challenging calls.c. Based on the results, does it appear that men and women may have equal success in challenging calls?A.The confidence interval suggests that there is a significant difference between the success of men and women in challenging calls. It is reasonable to speculate that women have more success.B.The confidence interval suggests that there is a significant difference between the success of men and women in challenging calls. It is reasonable to speculate that men have more success. C.The confidence interval suggests that there is no significant difference between the success of men and women in challenging calls.D.There is not enough information to reach a conclusion. Type the correct answer in the box. If necessary, use / for the fraction bar. Tora Co. plans to produce 1,020 units in July. Each unit requires two hours of direct labor. The direct labor rate is $20 per hour. Prepare a direct labor budget for July.\ Three wires are connected at a branch point. One wire carries a positive current of 18 A into the branch point, and a second wire carries a positive current of 7 A away from the branch point. Find the current carried by the third wire into the branch point. The GCF of 10 and 18 is 6.TRUEFALSE Sharla invests $275 in a simple interest bearing account for 16 years. The annual interest rate is 8%. Using the simpleinterest formula, / -Prt, how much interest will Sharla's initial investment earn over the 16 year period?$297$319$352$627 Insert seven rational numbers between 2 and 3. HELP MMEH PLEASE I REALLY NEED YOUR HELP 123456U-boats were used primarily togather information about enemy movements by tracking warshipsprotect the German coast from attack by Allied ships and submarines.resupply troops with guns ammunition and food via sea rather than land.target Allied shipments on passenger ships warships and merchant ships. What type of conic section is the following equation?5x^2-y=12 To solve the system of linear equations 3 x minus 2 y = 4 and 9 x minus 6 y = 12 by using the linear combination method, Henry decided that he should first multiply the first equation by 3 and then add the two equations together to eliminate the x-terms. When he did so, he also eliminated the y-terms and got the equation 0 = 0, so he thought that the system of equations must have an infinite number of solutions. To check his answer, he graphed the equations 3 x minus 2 y = 4 and 9 x minus 6 y = 12 with his graphing calculator, but he could only see one line. Why is this?i have a time limit someone answer fast plsss (taking this down at 4:20 pm) All of the following provide evidence for evolution except: What is the mean of the following list of extra credit points earned on a statistics test?10,8,18,17,7 when three times a certain number is subtracted from 5 the result is more than 9 find the range of the values of the number. Which phrase correctly completes the conversation?Oscar: Buenos das seor. Quiero trabajar. Tiene trabajo?Seor: Lo siento. ______ trabajo.Hace noNo haceNo hayHay no