How many grams do 3.6 × 10^20 atoms of sodium weigh?
Answer in units of g.

Answers

Answer 1

Answer:

i

Explanation:


Related Questions

Which of the following types of radiation from the Sun has the longest wavelength?
A) gamma
B) infrared
C) ultraviolet
D) visible

Answers

Answer:

B) infrared im pretty sure

Answer:

Infrared

Explanation:

PLSSS HELP. And there’s also at the bottom of the picture another option if u didn’t see it

Answers

Answer:

B. Gradualism

Explanation:

Plz help
I don't know chem that well

Answers

Have a periodic table out! Group # are the ones on the top, # of protons is the atomic #, valence electrons corresponds with the ones digit on the group #, and oxidation # is the charge of the atom (positive on the left half, negative on the right half of the PT), then you just put the element and add the oxidation #!
To find these answers you can just pull up the picture of the periodic table. The # of protons can be found at the top of the element, AKA, the atomic number. The group number is which column the element is in, there are 18 groups, counting from left to right. The valence electrons and oxidation are found similarly by which column they are in, each column is different so I would advise looking it up for each element. And lastly, the Ion that will form is found by finding the ionic charge of each element. I hope this helps. :)

Radon-222 3.8 days

How many half lives have occurred if 12.5% of Rn-222 remains?

I need someone to explain how you do this to me?

Answers

3 half-lives have occured

Further explanation

Given

Half-life Radon-222 = 3.8 days

12.5% of Rn-222 remains

Required

Half-lives  occurred

Solution

General formulas used in decay:  

[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}[/tex]

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

12.5% of Rn-222 remains ⇒ Nt/No = 0.125

Input the value :

[tex]\tt 0.125=\dfrac{1}{2}^{t/3.8}\\\\\dfrac{1}{2}^3=\dfrac{1}{2}^{t/3.8}\\\\3=t/3.8\\\\t=11.4\rightarrow 3~half-lives[/tex]

A pan containing hot water is left on the counter and becomes cool mainly due to....
A. water molecules moving apart.
B. cold air penetrating the hot water.
C. heat from the water moving into the cooler air.
D. hot water reacting with the metal pan.

Answers

Answer:

C. heat from the water moving through the cooler air  

I think it's C because when something cools down, it has to reach a point of thermal equilibrium with the matter (in this case air) around it. So heat transfer happens through convection from the heat in the pan to the cooler surrounding air. The heated air becomes less dense and rises, while cooler air, sinks to the surface of the water, gets heated, and rises. This convection cycle keeps happening until the water in the pan is around the same temperature with the air around it.

How many moles of methanol must be burned to release 1454 KJ of energy

Answers

A lot of moles ya know but moles need sticks. Big sticks equals big moles and big moles equal for me 5 points

Aqueous copper(II) sulfate solution is placed in an iron container and left to stand for several days. Which statement describes what happens? A) Atmospheric oxygen reacts with the copper(II) sulfate to give black copper(II) oxide. B) Some fine iron particles are formed in the solution. C )The part of the container in contact with the solution is coated with copper. D) The solution turns from green to blue.

Answers

Answer:

C )The part of the container in contact with the solution is coated with copper.

Explanation:

To understand the answer to the question, we must have a good knowledge of the electrochemical series.

Remember that iron is above copper in the electrochemical series. This means that iron can replace copper in an aqueous solution of a copper salt.

The following reaction occurs in the container;

Fe(s) + CuSO4(aq) -----> FeSO4(aq) + Cu(s)

This is why the part of the solution in contact with the container becomes coated with copper.

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