In the Millikan oil-drop experiment illustrated in the figure below, an atomizer (a sprayer with a fine nozzle) is used to introduce many tiny droplets of oil between two oppositely charged parallel metal plates. Some of the droplets pick up one or more excess electrons. The charge on the plates is adjusted so that the electric force on the excess electrons exactly balances the weight of the droplet. The idea is to look for a droplet that has the smallest electric force and assume it has only one excess electron. Suppose e are using an electric field of 6.45 104 NC. The charge on one electron is l 60 10-19 С. Calculate the radius of an oil dop , de sty 90aa ml for th h its weight could be balanced by the electric force of this field on one electron Oil droplets Pinhole Light Telesxcope with cale in eyepiece um
The radius of the oil droplet in this experiment is approximately 1.11 x 10^-7 meters.
The Millikan oil-drop experiment was designed to determine the fundamental unit of electrical charge, the charge on a single electron, by observing the behavior of charged oil droplets suspended in an electric field. To calculate the radius of an oil droplet given the electric field strength and the charge on one electron, we can use the following formula:
q = mg / E
where q is the charge on the droplet, m is the mass of the droplet, g is the acceleration due to gravity, and E is the electric field strength.
Assuming that the droplet has only one excess electron and that its weight is balanced by the electric force of the field on that electron, we can write:
q = e
where e is the charge on one electron.
Equating these two expressions for q, we can solve for the mass of the droplet:
mg / E = e
m = eE/g
Next, we can use the density of the oil droplet to calculate its volume and then its radius:
[tex]V = (4/3)πr^3 = m/ρ[/tex]
[tex]r = [(3m/4πρ)]^(1/3)[/tex]
where ρ is the density of the oil.
Substituting in the given values, we get:
[tex]m = eE/g = (1.60 x 10^-19 C)(6.45 x 10^4 N/C)/(9.81 m/s^2) = 1.04 x 10^-14 kg[/tex]
ρ = 0.90 g/cm^3 = 900 kg/m^3
[tex]r = [(3m/4πρ)]^(1/3) = [(3(1.04 x 10^-14)/(4π)(900))]^(1/3) = 1.11 x 10^-7 m[/tex]
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The experiment began by placing a white rat in front of the infant, who initially had no fear of the animal. watson then produced a loud sound by striking a steel bar with a hammer every time little albert was presented with the rat. after several pairings (the noise and the presentation of the white rat), the boy began to cry and exhibit signs of fear every time the rat appeared in the room. also afraid of similar objects, including other furry animals. watson also created similar conditioned reflexes with other common animals and objects (rabbits, santa beard, etc.) until albert feared them all.
The Little Albert experiment is controversial and ethically questionable by today's standards, as it involved intentionally inducing fear in a child and potentially causing lasting psychological harm
The experiment you are describing is known as the "Little Albert" experiment and was conducted by John B. Watson and his graduate student Rosalie Rayner in 1920. The purpose of the experiment was to demonstrate the principles of classical conditioning, which is a type of learning where an individual learns to associate a neutral stimulus with a meaningful stimulus and responds accordingly.
In the case of Little Albert, the white rat was initially a neutral stimulus that did not elicit any fear or emotional response from him. However, when Watson and Rayner paired the presentation of the rat with a loud, startling noise (the unconditioned stimulus), Little Albert began to associate the two stimuli and developed a fear response (the conditioned response) to the rat alone (the conditioned stimulus).
Watson and Rayner then went on to demonstrate that Little Albert's fear response had generalized to other similar stimuli, such as other furry animals and even a Santa Claus mask. This demonstrated the idea of stimulus generalization, where a conditioned response can be elicited by stimuli that are similar to the original conditioned stimulus.
The true identity of Little Albert was never definitively established, and it is not known what became of him after the experiment.
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An electric field of 6.50×105 V/m
is desired between two parallel plates, each of area 45.0 cm2
and separated by 2.45 mm
of air. What charge must be on each plate?
The charge on each plate is 2.608×10⁻⁸ C. Charge is a fundamental physical property of matter that describes the degree to which it interacts with electromagnetic fields.
Describe Charge?
It is an intrinsic property of subatomic particles, such as protons and electrons, that gives rise to electric and magnetic forces.
The basic unit of charge is the Coulomb (C), named after the French physicist Charles-Augustin de Coulomb, who first quantified the electric force between charged objects. A single proton or electron has a charge of approximately 1.6 x 10⁻¹⁹ Coulombs.
Electric charge is conserved, which means that the total amount of charge in a closed system remains constant over time. Charges can be positive, negative, or neutral, and like charges repel each other, while opposite charges attract each other.
The electric field between two parallel plates is given by:
E = V/d
where E is the electric field, V is the potential difference between the plates, and d is the distance between the plates.
In this case, the desired electric field is E = 6.50×10⁵ V/m, and the distance between the plates is d = 2.45 mm = 0.00245 m. So, we can solve for the potential difference between the plates as:
V = Ed = (6.50×10⁵ V/m)(0.00245 m) = 1592.5 V
Since the potential difference between the plates is the same as the potential difference across the capacitor, we can use the formula for the capacitance of a parallel plate capacitor to find the charge on each plate:
C = ε0A/d
where C is the capacitance, ε0 is the permittivity of free space, A is the area of each plate, and d is the distance between the plates.
Plugging in the given values, we get:
C = (8.85×10⁻¹² F/m)(0.00045 m²)/(0.00245 m) = 1.635×10⁻¹¹ F
Finally, we can find the charge on each plate using the formula:
Q = CV
where Q is the charge on each plate, C is the capacitance, and V is the potential difference between the plates. Plugging in the values we found, we get:
Q = (1.635×10⁻¹¹ F)(1592.5 V) = 2.608×10⁻⁸ C
Therefore, the charge on each plate is 2.608 ×10⁻⁸ C.
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Nan is upset because she has not lost enough weight to buy the new swimsuit that she had wanted, so she imagines herself on the beach having fun with her friends in her current swimsuit. Nan is using mental images to
Group of answer choices
When the accompanying stimuli are not present, we can alter and reactivate internal representations through mental imagery. This procedure results in the phenomenon known as "seeing with the mind's eye" when it comes to visual mental images. Thus, option B is correct.
What is the use of mental images?Mental imagery is mostly used to simulate potential future events and "relive" previous experiences. According to this viewpoint, imagery ought to be investigated in a variety of cognitive tasks as well as on its own.
Although it is widely used to enhance physical performance, mental imagery can also benefit tasks that need both cognitive and emotional functioning, such as managing emotions and stress or public speaking.
Therefore, change her feelings. Studies have demonstrated that imaging can promote relaxation in the body and mind. Manage depression, stress, and anxiety are other benefits. Help lessen the agony
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The given question is incomplete. The complete question is given below:
Nan is upset because she has not lost enough weight to buy the new swimsuit that she had wanted, so she imagines herself on the beach having fun with her friends in her current swimsuit. Nan is using mental images to
a.
Prepare for some action.
b.
Change her feelings.
c.
Make a decision.
d.
Aid memory.
Which is an accurate statement about two objects that have the same average kinetic energy?
Each object has the same amount of potential energy.
Each object has the same mass.
Both objects are made of the same material.
Both objects are at the same temperature.
Answer:
both objects are at the same temperature
Explanation:
kinetic energy is not affected or is independent of temperature
Why is it that, relative humidity does not tell us how much water is actually in the air, but tells us how close the air is to being saturated?
The reason why relative humidity does not tell us how much water is actually in the air is because the amount of water vapor that air can hold depends on its temperature and pressure.
What is Relative humidity?
Relative humidity is a measure of the amount of water vapor in the air compared to the maximum amount of water vapor that the air can hold at a given temperature and pressure. It is expressed as a percentage and provides information about how close the air is to being saturated with water vapor.
armer air can hold more water vapor than colder air, and air at higher pressure can hold more water vapor than air at lower pressure. Therefore, the same amount of water vapor in the air can result in different relative humilities depending on the temperature and pressure.
For example, on a humid day with a relative humidity of 90%, there may be more water vapor in the air than on a dry day with a relative humidity of 30%. However, the air on the dry day is still capable of holding more water vapor before it becomes saturated. This is because the amount of water vapor that air can hold increases with temperature, so if the dry day is hotter than the humid day, the air may be able to hold more water vapor even though the relative humidity is lower.
In summary, relative humidity is a useful measure of how close the air is to being saturated with water vapor, but it does not provide information about the actual amount of water vapor in the air, which depends on the temperature and pressure.
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A 12.5 m boom, AB, of a crane lifting a 3,000 kg load is shown below. The center of mass of the boom is at its geometric center, and the mass of the boom is 1,400 kg. For the position shown, calculate the following. tension T in the cable (in N) N the force at the axle A (Give the magnitude in newtons and the direction in degrees counterclockwise from the +x-axis. Assume that the +x-axis is to the right.) magnitude N direction
The force at the axle A is 35,903 N, in the direction 60 degrees counterclockwise from the +x-axis.
Describe Distance?Distance is a numerical measurement of how far apart two points are. It is a scalar quantity that represents the length of the path traveled between two points in space, regardless of the direction. Distance is typically measured in units such as meters, kilometers, miles, or feet. It is an important concept in physics, as it is used in many physical calculations, such as those involving speed, velocity, and acceleration. It is also a fundamental concept in everyday life, as it is used to describe the separation between two objects or locations.
To solve this problem, we need to use the principle of moments. The sum of moments about any point is equal to zero when the object is in static equilibrium.
First, let's find the distance from point A to the center of mass of the boom. We can use the fact that the boom is uniform and its center of mass is at the geometric center.
distance from A to center of mass = 12.5 m / 2 = 6.25 m
Let's take point A as the pivot point for calculating the moments. Then, the moment due to the tension T in the cable is:
moment due to T = T * 12.5 m
The moment due to the weight of the boom is:
moment due to boom =[tex]1400 kg * 9.81 m/s^2 * 6.25 m[/tex]
The moment due to the weight of the load is:
moment due to load = [tex]3000 kg * 9.81 m/s^2 * 12.5 m[/tex]
Since the system is in static equilibrium, the sum of these moments must be equal to zero:
[tex]T * 12.5 m - 1400 kg * 9.81 m/s^2 * 6.25 m - 3000 kg * 9.81 m/s^2 * 12.5 m = 0[/tex]
Solving for T, we get:
[tex]T = (1400 kg * 9.81 m/s^2 * 6.25 m + 3000 kg * 9.81 m/s^2 * 12.5 m) / 12.5 T = 41475 N[/tex]
So the tension in the cable is 41,475 N.
To find the force at the axle A, we can use the fact that the sum of forces in the x and y directions must be equal to zero, since the system is in static equilibrium. Let's take the +x axis to the right and the +y axis upward.
The forces in the x direction are:
[tex]T * cos(30°) - N = 0The forces in the y direction are:T * sin(30°) + 1400 kg * 9.81 m/s^2 + 3000 kg * 9.81 m/s^2 = 0Solving for N, we get:N = T * cos(30°) = 41475 N * cos(30°) = 35903 N[/tex]
So the force at the axle A is 35,903 N, in the direction 60 degrees counterclockwise from the +x-axis.
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A 20 kg box moving at an initial speed of 10 m/s slides 25 m to the right on a horizontal floor before it comes to a complete stop.
A concrete floor surface will produce a coefficient for traditional footwear that is high enough (between 0.55 and 70) to eliminate the foreseeable risk of slipping.
What best define about coefficient of friction of the floor?The ratio between the perpendicular force pushing the objects together and the frictional resistive force is known as the coefficient of friction.
The formula for the friction coefficient is = F N, where is the friction coefficient, is the frictional force, and is the normal force.
A numerical value known as the coefficient of friction (fr) is created by dividing the resistive force of friction (Fr), which pushes the objects together, by the normal or perpendicular force (N), which pushes them apart. It is represented by the formula below: fr = Fr/N.
X= 25 m
u = 10m/s
m = 20kg
F= uN
N= mg
[tex]a = \frac{uN}{m} = \frac{umg}{m}[/tex]
a= ug
[tex]v^{2} =u^{2} - 2ax[/tex]
[tex]o= (10)^2 - 2ug (25)[/tex]
[tex]50 ug = (10)^2 = 100[/tex]
[tex]u = \frac{2}{g} = \frac{2}{10} = 0.2[/tex]
Therefore, 0.2 is the coefficient of friction between the box and floor.
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(3 of 5)
Referring to the two questions above, the transit detection method relies on the difference
between the flux when the planet is transiting versus when it is off to the side. The larger
the difference, the better chance astronomers have of detecting the planet. For which of
the above is the transit detection method more likely to detect the planet?
O The configuration in question 1.
O The configuration in question 2
O Both are the same, so there is no dependence on planet size.
Answer: The configuration in question 2
Explanation:
Answer:
The configuration in question 1 (correct)
Explanation:
Which factors affect the gravitational force between two objects?
distance and velocity
O mass and distance
mass and weight
O acceleration and weight
Answer:
mass and distance
Explanation:
I could explain it but I don't know how to word it xd
Answer:
My best guess is:
B) mass and distance
This is because gravity is affected by the size of objects and the distance between objects.
Explanation:
Hope it helps! =D
Using the objects around you right now as your frame of
reference, you cannot tell that the Earth is moving.
What evidence would you need to collect in order to prove
that the Earth is in motion?
EXTRA HELP
Where should you position yourself in space in order to see
the Earth spinning?
What would you use as a frame of reference?
Scientists use the movement of pendulums to provide evidence that the Earth is rotating the moon's position in space in order to see the Earth spinning
What is the evidence of Earth's movement?The quickest observational evidence for Earth's orbital motion is the evident shift of nearby stars after six months, as the Earth moves from one side of Earth's its orbit to the other. Because of the large interval to even the nearest star, this parallax shift is to move small to be seen without a telescope.
Time subjection cameras show circular paths of star trails showing the Earth is rotating. The winds on the Earth curve evince the Earth is moving. proving the Earth is rotating.
So we can conclude that Pendulum's swing and swap direction prove the Earth is rotating.
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The mechanical energy of a bicycle at the top of a hill is 6000 j. The bicycle stops at the bottom of the hill by applying the brakes. If the gravitational potential energy of the bicycle-earth system is 2000 j at the bottom of the hill, how much mechanical energy was converted into thermal energy?.
Answer:
Explanation: POTENTIAL ENERGY is stored energy, energy ready to go. A race car at the starting line of a race, a bicycle on top of a hill, and students waiting to go home from school are all examples of potential energy.
A moving bicycle has mechanical energy. When you apply the brakes, the bicycle's mechanical energy is not destroyed. The mechanical energy is transformed into thermal energy. Friction between the brake pad of a car and the moving wheel transforms mechanical energy into thermal energy (heat).
During braking, 60% of the kinetic energy of the bicycle and rider is converted to thermal energy in the brake blocks.
A heart pacemaker fires exactly 71
times a minute. Each time it fires, a 33.0 nF
capacitor is charged by a battery in series with a resistor to 0.732
of its full voltage. What is the value of the resistance
?
The value of the resistance is approximately 0.047 kΩ.
What is Resistance?
Resistance is a measure of how much a material or device opposes the flow of electric current through it. Resistance is typically denoted by the letter R and is measured in Ohms (Ω) in the International System of Units (SI).
We can use the formula for the charging of a capacitor through a resistor:
V = V_0 * (1 - e^(-t/RC))
where V_0 is the initial voltage, V is the final voltage, t is the time, R is the resistance, and C is the capacitance.
In this case, the capacitor is charged 71 times per minute, so the time between charges is:
t = 60 s / 71
= 0.845 s
The capacitor is charged to 0.732 of its full voltage, so the fraction remaining is:
1 - 0.732 = 0.268
0.268 = e^(-0.845/RC)
Solving for RC, we get:
RC = -0.845 / ln(0.268) ≈ 1.42 s
Since we know the capacitance C is 33.0 nF, we can solve for the resistance R:
RC = R * C
= 1.42 s * 33.0 nF
= 0.0468 ≈ 0.047 kΩ
Therefore, the value of the resistance is approximately 0.047 kΩ.
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Which is matched correctly with its unit of measure?
luminous flux - lumens
illuminance - malus
illuminance - lumens
luminous flux - lux
Correctly matched with its unit of measure is : luminous flux - lumens
What is luminous flux?Luminous flux is also called luminous power. It is is the measure of perceived power of light and it differs from the measure of total power of light emitted, called 'radiant flux'.
In photometry, measure of the perceived power of light is known as luminous flux . It differs from radiant flux, measure of the total power of electromagnetic radiation, in that luminous flux is adjusted to reflect varying sensitivity of human eye to different wavelengths of light.
Lumen is the standard unit of luminous flux and luminous flux is the measure of perceived power of light by human eye and we measure luminous flux in lumens.
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Which object has the greatest momentum?* A. A sports car driving on the highway.
B. A baseball thrown by a professional pitcher.
C. An 18-wheeler tractor trailer at rest.
D. An average mass person walking.
The object has the greatest momentum is A sports car driving on the highway.
Option A is correct.
What is momentum?Momentum is described as the product of the mass and velocity of an object which is a vector quantity, possessing a magnitude and a direction.
The principle of conservation of momentum states that if two objects collide, then the total momentum before and after the collision will be the same if there is no external force acting on the colliding objects.
In conclusion, a sports car driving on the highway has the greatest momentum among the given options.
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14. A boy of mass m swings back and forth on the end of a rope 6 m long that is attached to a gymnasium ceiling. If he approaches to within 2 m of the ceiling during each cycle, what is his speed as he passes through the lowest point of the swing?
The boy's speed as he passes through the lowest point of the swing is 8.8 m/s.
How to find speed?To solve this problem, we can use the conservation of energy. At the lowest point of the swing, the boy has the maximum gravitational potential energy and no kinetic energy. At the highest point of the swing, he has the maximum kinetic energy and no gravitational potential energy.
Since the energy of the system is conserved, the sum of the gravitational potential energy and kinetic energy must remain constant throughout the swing. Let's call the speed of the boy as he passes through the lowest point of the swing "v".
At the lowest point, the gravitational potential energy is given by:
mgh = (1/2)mv²
where m is the mass of the boy, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height of the lowest point above the ground (6 m - 2 m = 4 m).
Solving for v:
v = √(2gh) = √(2 x 9.8 x 4) = √(77.76) = 8.8 m/s
So the boy's speed as he passes through the lowest point of the swing is approximately 8.8 m/s.
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According to the conservation of momentum, the momentum before a collision should be _______ the momentum after the collision.
A.greater than
B.less than
C.double
D.equal to
Answer:
D. equal to
Explanation:
The law of conservation of momentum states that momentum is conserved, so it would stay the same.
A spaceship in outer space has a doughnut shape with 900-m
outer radius. The inhabitants stand with their heads toward the center and their feet on an outside rim.
A.) Over what time interval would the spaceship have to complete one rotation on its axis to make a bathroom scale have the same reading for the person in space as when on Earth’s surface?
The formula for centripetal acceleration within the spacecraft is: ac =The outside radius of a spacecraft's doughnut-shaped body is 440 metres. The people are standing with thier feet on an outer rim and their heads .
What materials make up the Earth's surface?Earth's crust is made of igneous, metamorphic, or sedimentary rocks, which range in composition from mud or clay to diamonds or coal. Igneous rocks, which are created as magma cools, are the most prevalent types of rocks in the crust. Igneous rocks like granite and basalt are abundant in the crust of the Earth.
What precisely is a radius?The distance between any two places on a circle's circumference is in fact its radius. R or r are frequently used to denote it. Almost all calculations involving circles take this quantity into account. The radius of a circle can be used to determine a circle's circumference and surface area.
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You are asked to relocate a sunken boat to be used as an artificial reef. The boat's mass is 4,000Kg and the volume of its solid parts is 3m3. Assume the ocean water density is 1.02g/ml. Approximately, what is the minimal volume of an air bag (in liters) that should be attached to it so it can be lifted under water to be moved to its new location (the air bag weighs 10Kg)?
A 0.0272 kg arrow is fired with a velocity of 87.3 m/s from a 0.0245 kg bow. Determine the equivalent impulse value imparted on the arrow. (hint: you can also use newton's third law of motion)* A.2.37 Ns
B.3.11 Ns
C.113.5 Ns
D.214.2 Ns
The equivalent impulse value imparted on the arrow is 2.37 Ns,
option A
What is the impulse imparted?The equivalent impulse value imparted on the arrow can be determined using the equation for impulse, which is given by;
Impulse = force x time.
Since the arrow is moving with a constant velocity, the time during which the force is applied can be determined using the principle of conservation of momentum. The change in momentum of the arrow-bow system is equal to the impulse applied to the arrow, and the force applied to the arrow is equal to the recoil force experienced by the bow.
The initial momentum of the arrow-bow system is equal to the mass of the arrow times its velocity. The final momentum of the arrow-bow system is equal to the mass of the bow times its recoil velocity.
The change in momentum of the arrow-bow system is given by:
Δp = pf - pi = (m_bow * v_recoil) - (m_arrow * v_arrow)
The impulse applied to the arrow is equal to the change in momentum of the arrow-bow system:
impulse = Δp = (m_bow * v_recoil) - (m_arrow * v_arrow)
Using the given masses and velocities, we can calculate the impulse:
impulse = (0.0245 kg) * (87.3 m/s) - (0.0272 kg) * (87.3 m/s) = 2.37 Ns
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Which of the following is an effect of the varying input of solar radiation along the temperate
mid latitudes throughout the year?
Choose 1 answer:
B
Varying solar radiation causes seasonal changes in air temperature but not in
evaporation.
Varying solar radiation causes seasonal changes in evaporation but not air
temperature.
Varying solar radiation does not impact air temperature nor evaporation.
Varying solar radiation causes seasonal changes in air temperature and evaporation.
Varying solar radiation causes seasonal changes in air temperature and evaporation.
What is the effect of the varying input of solar radiation?The amount of solar radiation received by the Earth's surface changes throughout the year due to the tilt of the Earth's axis relative to the sun. In temperate mid-latitudes, this results in seasonal variations in the amount of solar radiation received, which in turn affects both air temperature and evaporation.
During the summer months, the sun is higher in the sky and the length of daylight is longer, resulting in increased solar radiation and higher air temperatures. This increased solar radiation also causes increased evaporation from bodies of water and from the soil, leading to higher levels of atmospheric moisture.
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NEEEEDD HELPP...........
a. The total energy is 10.75 J
b. The elastic potential energy at t= 1.25 s is 2.69 J
What is energy?Energy is the ability to do work.
What is elastic potential energy?Elastic potential energy is energy stored in a spring.
a. How to find the total energy of the system?The total energy of the system is the maximum elastic potential energy of the system. It is given by E' = 1/2kx'² where
k = spring constant and x = maximum displacementGiven that
k = 21.5 N/m andx' = 1.0 m (from the graph)Substituting the values of the variables into the equation, we have that
E = 1/2kx'²
= 1/2 × 21.5 N/m × (1.0 m)²
= 1/2 × 21.5 N/m × 1.0 m²
= 10.75 Nm
= 10.75 J
The total energy is 10.75 J
b. What is the potential energy stored in the system at t = 1.25 s?The potential energy stored in the system is given by
E = 1/2kx² where
k = spring constant and x = displacementAt t = 1.25 s from the graph, x = -0.5 m
Since k = 21.5 N/m, substituting the values of the variables into the equation, we have
E = 1/2kx²
E = 1/2 × 21.5 N/m × (-0.5 m)²
E = 1/2 × 21.5 N/m × 0.25 m²
E = 10.75 N/m × 0.25 m²
E = 2.6875 Nm
E = 2.6875 J
E ≅ 2.69 J
The potential energy is 2.69 J
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You are asked to figure out the size of an air bladder (a balloon that inflate and deflate to change the buoyancy of a profiling float) a profiling float should have to be able to profile from 1000m to the surface should be (at least). To figure it out, you look at profiles of density from the region where you will be deploying the float (see attached figure) and compute the maximum difference in density (=1000+sigma_theta) between 1000m and the surface.
Your float is a perfect cylinder with 20cm in diameter and 1.5m in length. Figure out its volume, Figure out the mass it should have, without inflating the bladder, to match the largest density observed at 1000m, so it can be neutrally buoyant at that depth (neither sinking or floating).
Finally, given the above, how big should the air bladder be (in minimum and in ml=cm^3) to that when inflated the float will be buoyant at the surface for all conditions observed at that region?
The minimum size of the air bladder [tex](in ml=cm^3)[/tex] should be[tex]2*σθ * 706.5 cm^3[/tex] to make sure that when inflated, the float will be buoyant at the surface for all conditions observed at that region.
What is air bladder?An air bladder is a sac-like organ that is filled with air and is found in certain aquatic animals, such as fish, amphibians, and certain invertebrates. It is used for buoyancy control, allowing the animal to adjust its position in the water column.
Volume of perfect cylinder =[tex]πr^2h[/tex]
[tex]= 3.14 * (10cm/2)^2 * 1.5m= 706.5 cm^3[/tex]
Mass of the float at 1000m = Density at 1000m * Volume of the float
[tex]= (1000+σθ)* 706.5 cm^3= (1000+σθ) * 706.5 g[/tex]
Air bladder size (minimum) = Mass of the float at 1000m - Mass of the float at surface
[tex]= (1000+σθ) * 706.5 g - (1000-σθ) * 706.5 g= 2*σθ * 706.5 g= 2*σθ * 706.5 cm^3[/tex]
Therefore, the minimum size of the air bladder (in ml=cm^3) should be [tex]2*σθ * 706.5 cm^3[/tex] to make sure that when inflated, the float will be buoyant at the surface for all conditions observed at that region.
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In the 2nd lab you were studying water squirting out from a hole in a cylinder filled with water into a tub. Just as a falling ball converts potential energy to kinetic energy, water pressure pushed water out of the hole by converting potential energy per unit volume (density x g x height) to kinetic energy per unit volume (density x velocity^2/2). Assume you have a 20 cm head of water above the hole and that the hole is 40 cm above ground.
How will the water reach by the time it touches the ground (in cm)?
What is the spring constant for a supermarket scale that stretches 0. 01 m when a force of 4 n is applied? n/m what is the displacement of a spring if it has a spring constant of 10 n/m, and a force of 2. 5 n is applied? m.
400 N/m is the spring constant for a supermarket scale that stretches 0. 01 m when a force of 4N is applied. 0.25 m is the displacement of a spring if it has a spring constant of 10 n/m, and a force of 2. 5N is applied.
Hooke's Law states that as a spring is extended, the force exerted is proportional to the increase in length from the equilibrium length. The spring constant may be computed as follows:
k = F/x,
where,
k is the spring constant.
F represents the force,
x represents the change in spring length.
Now,
k = F/x
F = k × x
4 N = k × 0.01 M
k = 400 N/M
The spring constant is the proportional constant k. It is a measure of the stiffness of the spring. When a spring is stretched or compressed by an amount x from its equilibrium length, it produces a force F = -kx in the direction of its equilibrium position.
Now,
F = -kx
x = -F/k
[tex]x = \frac{2.5\ N}{10\ N/m}[/tex]
x = 0.25 m
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You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 4.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.
A. What is the horizontal component of the hammer's velocity just as it leaves the roof?
B. What is the vertical component of the hammer's velocity just as it leaves the roof?
Answer:
A. The horizontal component of the hammer's velocity just as it leaves the roof can be calculated by multiplying the velocity of the hammer by the cosine of the angle of the roof with the horizontal:
Vhorizontal = V * cos(45) = 4.5 m/s * cos(45) = 3.16 m/s
B. The vertical component of the hammer's velocity just as it leaves the roof can be calculated by multiplying the velocity of the hammer by the sine of the angle of the roof with the horizontal:
Vvertical = V * sin(45) = 4.5 m/s * sin(45) = 3.16 m/s
Explanation:
A 100-g block of water ice is initially stored in a freezer at -10°C. It is removed
from the freezer and placed on a stove that provides 2000 Joules of heat per
second.
a. (3 pts) How long will it take for the ice to reach its melting point? (assume
4.18 J/g°C for the specific heat capacity of water)
b. (3 pts) The latent heat of fusion of water is 333 J/g. How long will it take
for the ice to completely melt?
c. (3 pts) After the ice has completely melted, how long will it take for the
water to reach the boiling point?
a. The time it takes the ice to reach melting point is: t = 4180 J / 2000 J/s = 2.09 s
b. The time it takes to fully melt is: t = 33300 J / 2000 J/s = 16.65 s
c. The time it takes to reach boiling point after melting is: t = 418000 J / 2000 J/s = 209 s.
Melting Point and Boiling Point Timea. To find the time it takes for the ice to reach its melting point (0°C), we need to calculate the amount of heat required to raise the temperature of the ice block from -10°C to 0°C. The heat required can be calculated using the equation:
Q = m * C * ΔT
where m is the mass of the ice block (100 g)
C is the specific heat capacity of water (4.18 J/g°C)
and ΔT is the change in temperature (0°C - (-10°C) = 10°C).
So, Q = 100 g * 4.18 J/g°C * 10°C = 4180 J
Now, we can use the heat supplied by the stove to calculate the time it takes to raise the temperature of the ice block to 0°C:
t = Q / P
where P is the power supplied by the stove (2000 J/s).
So, t = 4180 J / 2000 J/s = 2.09 s
b. To find the time it takes for the ice to completely melt, we need to calculate the amount of heat required to turn the ice block into liquid water. The heat required can be calculated using the equation:
Q = m * Lf
where m is the mass of the ice block (100 g) and Lf is the latent heat of fusion of water (333 J/g).
So, Q = 100 g * 333 J/g = 33300 J
Now, we can use the heat supplied by the stove to calculate the time it takes to melt the ice block:
t = Q / P
where P is the power supplied by the stove (2000 J/s).
So, t = 33300 J / 2000 J/s = 16.65 s
c. To find the time it takes for the water to reach the boiling point (100°C), we need to calculate the amount of heat required to raise the temperature of the water from 0°C to 100°C. The heat required can be calculated using the equation:
Q = m * C * ΔT
where m is the mass of the water (100 g), C is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature (100°C - 0°C = 100°C).
So, Q = 100 g * 4.18 J/g°C * 100°C = 418000 J
Now, we can use the heat supplied by the stove to calculate the time it takes to raise the temperature of the water to 100°C:
t = Q / P
where P is the power supplied by the stove (2000 J/s).
So, t = 418000 J / 2000 J/s = 209 s.
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The graph depicts the motion of two objects. Which statement BEST describes the acceleration of the two objects?
Responses
A Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.
B Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.
C Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.
D Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration.
Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration. The correct option is D.
What is acceleration?Acceleration of any object is defined as the variation in the speed of the object with the variation of time. Acceleration is a vector term and to define it we require both the magnitude and the direction. The unit of acceleration can be m / sec², miles / sec², etc.
In a velocity-time graph, the acceleration corresponds to the slope of the curve.
In fact, acceleration is defined as the ratio between the change in velocity and the time interval:
a = Δv / Δt
However, in a velocity-time graph, corresponds to the y-variable increment (), while corresponds to the x-variable increment (). (). As a result, acceleration can also be expressed as,
a = Δy / Δx
For object 1, the slope is constant: this means that the acceleration is constant.
For object 2, the slope varies: this means that the acceleration varies as well.
The missing graph is attached with the answer below.
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Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?
The magnitude of the charges must be 1.67 x 10⁻⁵ C in order for the force exerted by them to be comparable to the weight of a 50 kilogram individual.
The force of attraction between two point charges Q1 and Q2 separated by a distance r is given by Coulomb's law:
[tex]F = k * (Q1 * Q2) / r^2[/tex]
here,
k is Coulomb constant, value is [tex]9.0 * 10^9 Nm^2/C^2[/tex].
To find the magnitude of the charges such that the force between them equals the weight of a 50 kg person, we need to set the force equal to the weight of the person:
F = m * g
here,
m is mass of the person and
g is the acceleration gravity, value [tex]9.81 m/s^2[/tex].
Reserving values:-
[tex]m * g = k * (Q1 * Q2) / r^2[/tex]
We know that Q1 and Q2 are equal, so we can write Q1 = Q2 = Q. Reserving equation above:-
[tex]m * g = k * Q^2 / r^2[/tex]
Solving for Q:-
[tex]Q = \sqrt{[(m * g * r^2) / k]}[/tex]
Reserving values:-
[tex]Q = \sqrt{x} \sqrt{[(50 kg * 9.81 m/s^2 * (1.0 m)^2) / (9.0 x 10^9 Nm^2/C^2)]}[/tex]
Simplifying and evaluating:-
[tex]Q = 1.67 * 10^-^5 C[/tex]
Therefore, the magnitude of each of the charges should be approximately [tex]1.67 * 10^-^5 C[/tex].
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How much energy is transferred when the potential difference is 230v and the charge is 200c?.
Answer:
Explanation: E = QV, the energy transferred by the quantity of electric charge by a potential difference of V volts.
