I NEED HELP PLEASE SOMEONE HELP ME

Answer:

the distance written as a decimal is 3.7

37/10 = 3,7

Achievements :)

Answer:

Step-by-step explanation:

The median female *less than*

The range of female*less than*

Which birth weight:*minimum*

Answer:

The median female birth weight is

✔ less than

the median male birth weight.

The range of female birth weight is

✔ less than

the range of male birth weight.

Which birth weight measure is the same for both genders?

✔ minimum

Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

[tex]E = P*I*t[/tex]

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

After t years, the total amount of money is:

[tex]T = E + P[/tex]

In this question:

Rate of 10%, so I = 0.1.

9 months, so [tex]t = \frac{9}{12} = 0.75[/tex]

How much should he pay for a note that will be worth $3,000 in 9 months?

We have to find P for which T = 3000. So

[tex]T = E + P[/tex]

[tex]3000 = E + P[/tex]

[tex]E = 3000 - P[/tex]

Then

[tex]E = P*I*t[/tex]

[tex]3000 - P = P*0.1*0.75[/tex]

[tex]1.075P = 3000[/tex]

[tex]P = \frac{3000}{1.075}[/tex]

[tex]P = 2790.7[/tex]

He should pay $2,790.7.

Answer:

The value of x^3 + 1/x^3 is 47/x + 1/x^3 - 1/x^5

Step-by-step explanation:

x^4 + 1/x^4 = 47

x^4 = 47 - 1/x^4

x^3 + 1/x^3 = 1/x(x^4 + 1/x^2)

x^4 = 47 - 1/x^4

x^3 + 1/x^3 = 1/x(47 - 1/x^4 + 1/x^2) = 47/x - 1/x^5 + 1/x^3 = 47/x + 1/x^3 - 1/x^5

Answer:

x^3-6x^2-4x-8

Step-by-step explanation:

First you would multiply (x-2) by itself (x-2) to get

x^2-2x-2x+4

then you would combine like terms

x^2-4x+4

Then you would multiply that by x-2

(x^2-4x+4)(x-2)

x^3-2x^2-4x^2-8x+4x-8

then you combine like terms

x^3-6x^2-4x-8

Answer:

Step-by-step explanation:

1) The given inequality is

[tex]|\sqrt{n} \frac{(\bar R_n-p)}{\sqrt{p(1-p)} } |<q_{\alpha /2}| \\\\ \to(\frac{(\sqrt{n} \bar R_n-p)}{\sqrt{p(1-p)} })<q^2_{\alpha /2}[/tex]

[tex]\to n( \bar R _n - p)^2<p(1-p)q^2_{\alpha /2}[/tex]

[tex]\to n\bar R +np^2-2nR_np<q^2_{\alpha /2 p- q^2_{\alpha /2}p^2[/tex]

Arranging the terms  with p² and p, we get

[tex]p^2(n+q^2_{\alpha /2)-p(2n \bar R _n+q^2_{\alpha / 2})+n \bar R ^2 _n <0[/tex]

Hence, the inequality is of the form

Ap² + Bp + c < 0

2. A quadratic equation of the form

Ap² + Bp + c < 0 with A > 0 looks like

Check the attached image

The region where the values are negative lies between p₁ and p₂ ...

The p₁ < p < p₂

Answer:

Due to the higher z-score, he did better on the SAT.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Determine which test the student did better on.

He did better on whichever test he had the higher z-score.

SAT:

Scored 1070, so [tex]X = 1070[/tex]

SAT scores have a mean of 950 and a standard deviation of 155. This means that [tex]\mu = 950, \sigma = 155[/tex].

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1070 - 950}{155}[/tex]

[tex]Z = 0.77[/tex]

ACT:

Scored 25, so [tex]X = 25[/tex]

ACT scores have a mean of 22 and a standard deviation of 4. This means that [tex]\mu = 22, \sigma = 4[/tex]

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{25 - 22}{4}[/tex]

[tex]Z = 0.75[/tex]

Due to the higher z-score, he did better on the SAT.

Answer:

[tex]-30[/tex]

Step-by-step explanation:

[tex]3\frac{3}{5} \times (-8 \frac{1}{3} )[/tex]

[tex]\frac{18}{5}\times \left(-\frac{25}{3}\right)[/tex]

[tex]\frac{18}{5}\times -\frac{25}{3}[/tex]

[tex]-\frac{18\times \:25}{5\times \:3}[/tex]

[tex]-\frac{450}{15}[/tex]

[tex]=-30[/tex]

Answer:-30

Step-by-step explanation:

3 3/5 x -8 1/3

18/5 x -25/3

-30

Answer:

80

Step-by-step explanation:

For every additional 10 hrs, you get 200 more dollars.

Answer:

D. G(x) = |x| + 7

Step-by-step explanation:

→For the function G(x) to shift upwards, there needs to be a number being added to the whole function.

→The answer isn't "A," because the 1 is being subtracted, making it shift downwards 1 unit, not upwards.

→The answer isn't "B," because adding the 2 there would cause the function to shift to the left for 2 units, not upwards.

→The answer isn't "C," because 10 is being multiplied, which would cause the function to narrow, and not shift upwards.

This means the correct answer is "D," because the 7 is being added, making the function shift upwards 7 units.

Answer:

# of pages   # of magazines

     1-20                    7

   21-40                    4

Step-by-step explanation:

Numbers 1 through 20:

10, 11, 14, 16, 17, 17, 20 (7 numbers)

Numbers 21 through 40:

21, 28, 29, 32 (4 numbers)

Answer:

A.

Step-by-step explanation:

So you would have f(3) = 3 + [tex]\frac{2}{2}[/tex]

f(3) = 3 + 1

f(3) = 4

Answer:

Step-by-step explanation: f(x)

3+ a square root of 3+1 / x-1

3+ a square root (4/2)

3+ square root of 2. That's the answer

Answer:

Step-by-step explanation:

a. The sample size for the poll would be at most 10% of the total readers of the tennessean.

b. Categorical data...data collected in groups or categories.

c. Yes it would make more sense to use percentages as this gives a better estimate for proportion.

d. The number of individual that provided this response is 67% of the sample size (which is at most 10% of the total population of readers of the online newspaper).

Answer:

-15

Step-by-step explanation:

The solution of expression for x = - 4 is,

⇒ - 15

We have to given that,

An expression is,

⇒ 2x - 7

Now, We can simplify the expression for x = - 4 as,

An expression is,

⇒ 2x - 7

Plug x = - 4;

⇒ 2 × - 4 - 7

⇒ - 8 - 7

⇒ - 15

Thus, The solution of expression for x = - 4 is,

⇒ - 15

Learn more about the equation visit:

brainly.com/question/28871326

#SPJ6

1 × 18/100 = 12/100(g+11), is the equation. The answer is 12/100 gallons

Answer:

2/7

Step-by-step explanation:

Since Rebecca is garunteed to pick a poodle, there are 7 puppies left. There are 2 retrievers so the probability is 2/7

Answer:2/7

Step-by-step explanation:

Answer:

a) The size of each of the two samples(equal), n = 518

b) Sample size, n = 439

Step-by-step explanation:

For clarity and easiness of expression, the complete solution to this question is handwritten and attached as files. Check the attached files below for the explanations.

Answer: radius and height

Step-by-step explanation:

Radius is the distance between the center of the circle to its boundary.

Height is the length of the figure from top to bottom.

Given statement : A cylinder with height of 42 millimeters and radius of 12 millimeters.

That clearly means that the cylinder is having radius of 12 millimeters i.e. 12 is representing the measure of the radius of the cylinder.

And Similarly, 42 is representing the measure of the height of the cylinder.

Hence, the 2 and 42 describe the radius and height respectively of the cylinder.

Answer:

radius and height

Step-by-step explanation:

i just took the test edge 2020. rate me 5 stars!

Answer:

x = 1.5

Step-by-step explanation:

Given

[tex]\frac{x}{2} \geq 0.75[/tex]

[tex]\frac{x}{2} < 2.5[/tex]

Required

Find the value of x.

First, the inequalities need to be rewritten and merged;

if [tex]\frac{x}{2} \geq 0.75[/tex], then

[tex]0.75 \leq \frac{x}{2}[/tex]

Multiply both sides by 2

[tex]2 * 0.75 \leq \frac{x}{2} * 2[/tex]

[tex]1.5 \leq x[/tex]

Similarly;

[tex]\frac{x}{2} < 2.5[/tex]

Multiply both sides by 2

[tex]2 * \frac{x}{2} < 2.5 * 2[/tex]

[tex]x < 5[/tex]

Merging these results together; to give

[tex]1.5 \leq x < 5[/tex]

This means that the range of values of x is from 1.5 to 4.9999....

From the question, x is the smallest rational number; from the range above ([tex]1.5 \leq x < 5[/tex]), the minimum value of x is 1.5 and 1.5 is a rational number;

Hence, x  = 1.5

Answer:

D Y is all real numbers

Step-by-step explanation:

When looking at the y axis, you can see that if the graph were to be bigger, the line would keep going. This means y will never stop.

Answer:

D

Step-by-step explanation:

Answer:

V ≈ 382 inches ³

Step-by-step explanation:

V = 4/3πr³

V = 4/3(3.14)(4.5)³

V = 1145.11/3

V = 381.7

V ≈ 382 inches ³

Pass = $21 , Souvenir = 2x/3 = $14 , Burger = x/6 =$3.5 .

Answer:

The 95% confidence interval for the true population proportion of adults with at least a high school education is (0.6819, 0.7381). This means that we are 95% sure that the true proportion of adults in the entire population surveyed with at least a high school education is (0.6819, 0.7381).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 1000, \pi = \frac{710}{1000} = 0.71[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 - 1.96\sqrt{\frac{0.71*0.29}{1000}} = 0.6819[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 + 1.96\sqrt{\frac{0.71*0.29}{1000}} = 0.7381[/tex]

The 95% confidence interval for the true population proportion of adults with at least a high school education is (0.6819, 0.7381). This means that we are 95% sure that the true proportion of adults in the entire population surveyed with at least a high school education is (0.6819, 0.7381).

Answer: B. although none are exactly 0.3 B is closest

Step-by-step explanation:

a. 35/999 = .0350

b. 31/99 = .3153

c. 105/7333 = .0143

d. 35/111 = .3135

Answer:

[tex]x + y = \frac{1000}{9}[/tex]

Step-by-step explanation:

Step 1: Identify the approach:

With this problem, the general solution is to try manipulate given data and transform data into a new form, in which, the desired value [tex](x + y)[/tex] is on the left side and all of other components which do not contain [tex]x[/tex] or [tex]y[/tex] are on the right side.

Step 2: Analyze:

[tex]9x + 2y^{2} - 3z^{2} = 132\\9y - 2y^{2} + 3z^{2} = 867[/tex]

Realize that in both equations, the [tex]2y^{2}[/tex] and [tex]3z^{2}[/tex] are in form of different signs. Then adding up corresponding sides of both equation can help eliminate these undesired components.

Step 3: Perform manipulation:

[tex]9x + 2y^{2} - 3z^{2} + 9y - 2y^{2} - 3z^{2} = 132 + 867[/tex]

Rearrange:

[tex](9x + 9y) + (2y^{2} - 2y^{2}) +(3z^{2} - 3z^{2}) = 132 + 867[/tex]

Simplify:

[tex]9(x + y) + 0 + 0 = 1000[/tex]

Simplify:

[tex]x + y = \frac{1000}{9}[/tex]

Hope this helps!

:)

Answer:

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]

Step-by-step explanation:

Given that:

A tank contains 180 liters of fluid in which 50 grams dissolved inside.

Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min

The salt pumped out[tex]= \dfrac{6 L}{180 L} = \dfrac{1}{30}[/tex] of initial amount added salt

At (t = 0) = 50

To determine the number A (t)

[tex]\dfrac{dA}{dt}=Rate_{in} - Rate _{out}[/tex]

[tex]A' = 6 - \dfrac{1}{30}A[/tex]

[tex]A' + \dfrac{1}{30}A = 6[/tex]

Integrating factor  [tex]y = e^{\int\limits pdt[/tex]

[tex]y = e^{\int\limits \dfrac{1}{30}dt}[/tex]

[tex]y = e^{\dfrac{t}{30}}[/tex]

[tex](e^{ \frac{t}{30}}A)' =4 e ^{\dfrac{t}{30}}+c[/tex]

Taking integral on the both sides;

[tex]Ae ^{\dfrac{t}{30}}= 6 * 30 e^{\dfrac{t}{30}} + c[/tex]

[tex]A = 180+ ce^ {-\dfrac{t}{30}}[/tex]

At  A(t = 0) = 50

50 = 180  + C            (assuming C = [tex]ce ^{-\dfrac{t}{30}}[/tex])

C = 50 - 180

C = 130

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]

Answer:

Step-by-step explanation:

Two sides and the angle between are marked as congruent. That immediately tells you that the Side-Angle-Side (SAS) theorem of congruence applies.

The angle is a right angle, which makes the adjacent sides be "legs" of the right triangle. Then the Leg-Leg (LL) theorem of congruence for a right triangle also applies.

Appropriate choices are ...

  SAS, LL

Answer:

X = 4 x

  over  5 ( x − 1 ) − 1 5 ( x − 1 )

Answer:

x = 4

Step-by-step explanation:

10(x-1) = 8x-2

Distribute

10x-10 = 8x-2

Subtract 8 from each side

10x-10-8x = 8x-2-8x

2x-10 = -2

Add 10  to each side

2x-10+10 = -2+10

2x = 8

Divide each side by 2

2x/2 = 8/2

x = 4