I need help, please.

I Need Help, Please.

Answers

Answer 1

Answer:

sorry I don't know it

Explanation:


Related Questions

A student in a lab experiment jumps upward off a common bathroom scale as the lab partner records the scale reading. What does the lab partner observe during the instant the student pushes off?


The scale reading will remain unchanged during the entire time the student is in contact with the scale.

The scale reading will increase momentarily then will decrease as the student is moving upward from the scale.

The scale reading will increase during the entire time the student is in contact with the scale.

The scale reading will decrease momentarily then will increase as the student is moving upward from the scale.

Answers

Answer:

B: The scale reading will increase momentarily then will decrease as the student is moving upward from the scale

Explanation:

The way weighing scale works is that when you climb on it, it will take your weight reading but when you are moving off the top of it, the reading slowly approaches 0 until you are completely off it.

Thus, the lab partner will observe that the reading will increase for a while and then gradually decrease to zero as the student moves upwards off the scale.

The correct answer is (B)The scale reading will increase momentarily then will decrease as the student is moving upward from the scale.

According to the third law of motion, every action has an equal and opposite reaction. In order to jump, the student will apply force to the bathroom scale in downward direction and there will be an equal force exerted by the bathroom scale upwards on the student which helps him jump.

 So when the student applies downward force on the scale in order to jump, the scale reading will increase momentarily and then will decrease as the student moves upwards.

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without calculation explain why the vertical component of velocity v h changes from 3.5 m/s at A to 0 m/s at B​

Answers

Answer:

due to gravity.

Explanation:

.............

9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en el émbolo para reducir su volumen a 35 mL, a temperatura constante? Indica la ley que aplicas.

Answers

Answer:

2.61 atm

Ley de Boyle

Explanation:

[tex]P_1[/tex] = Presión inicial = 0.96 atm

[tex]P_2[/tex] = Presión final

[tex]V_1[/tex] = Volumen inicial = 95 mL

[tex]V_2[/tex] = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

[tex]\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}[/tex]

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

A 5.0 kg object suspended on a spring oscillates such that its position x as a function of time t is given by the equation x (t ) = A cos(ωt ), where A = 0.80 m and ω = 2.0 s-1 . What is the magnitude of the maximum net force on the object during the motion?

Answers

Answer:

The magnitude of the maximum net force on the object during the motion is 16 newtons.

Explanation:

The position of the mass, measured in meters, within the mass-spring system is:

[tex]x(t) = A\cdot \cos \left(\omega\cdot t \right)[/tex] (1)

Where:

[tex]A[/tex] - Amplitude, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

[tex]\omega[/tex] - Angular frequency, measured in radians per second.

The acceleration function ([tex]\ddot {x} (t)[/tex]), measured in meters per square second, is obtained by deriving twice (1) in time:

[tex]\dot {x} (t) = -\omega\cdot A\cdot \sin (\omega\cdot t)[/tex]

[tex]\ddot {x} (t) = -\omega^{2}\cdot A\cdot \cos (\omega\cdot t)[/tex] (2)

And the maximum acceleration ([tex]a_{max}[/tex]), measured in meters per square second, experimented by the mass is:

[tex]a_{max} = \omega^{2}\cdot A[/tex] (3)

And the maximum net force ([tex]F[/tex]), measured in newtons, is:

[tex]F = m\cdot a_{max}[/tex] (4)

If we know that [tex]\omega = 2\,\frac{rad}{s}[/tex], [tex]A = 0.80\,m[/tex] and [tex]m = 5\,kg[/tex], then the maximum net force on the object during the motion is:

[tex]a_{max} = \left(2\,\frac{rad}{s} \right)^{2}\cdot (0.80\,m)[/tex]

[tex]a_{max} = 3.2\,\frac{m}{s^{2}}[/tex]

[tex]F = (5\,kg)\cdot \left(3.2\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 16\,N[/tex]

The magnitude of the maximum net force on the object during the motion is 16 newtons.

The magnitude of the maximum net force on the object during the motion will be 16 newtons.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem is;

m is the mass of  5.0 of object kg

x (t ) = A cos(ωt ),

A is the amplitude=  0.80 m

ω is the frequency= 2.0 s-1 .

F is the  magnitude of the maximum net force=?

The position of the mass is given by the equation;

[tex]x(t)= A cos( \omega t)[/tex]]

[tex]\em \dot x= - \omega A sin(\omega t) \\\\ \dot \dot x = - \omega ^2 A cos (\omega t)[/tex]

The maximum acceleration is found as;

[tex]\rm a_{max} = \omega ^2 A \\\\ \rm a_{max} = (2) ^2 \times 0.80 \\\\ \rm a_{max} =3.2 \m/sec^2[/tex]

The value of net force is found as;

[tex]\rm F= m a_{max} \\\\ \rm F= 5 \times 3.2 \\\\\ \rm F=16\ N \\[/tex]

Hence the magnitude of the maximum net force on the object during the motion will be 16 newtons.

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Modern psychology traces its roots back

Answers

Answer:

Psychology traces its roots back through recorded history to India, China, the Middle East, and Europe. Buddha and Confucius focused on the powers and origin of ideas. ... The ideas of Bacon and Locke contributed to the development of modern empiricism.

Explanation:

A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.


Determine the magnitude of the distance the object traveled

Answers

Answer:

26 m southwards.

Explanation:

From a North, East, South, West coordinate plane, moving northwards implies positive distance. While moving southwards implies negative distance.

Thus;

It moves 16 meters northward; d = 16 m

It now moves 22 meters southward; d = -22 m

It moves 12 meters northward; d = 12 m

It moves 32 meters southward; d = -32 m

Thus, total magnitude = 16 - 22 + 12 - 32 = -26 m

Thus, the object travels 26 m southwards.

A 5 kg rock falls from an 8 m high cliff. What is the speed of the rock when it hits the ground?

Answers

Answer:

3k mph

Explanation:

don't take my answer it is wrong

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.65 m/s. The car is a distance d away.
The bear is 32.4 m behind the tourist and running at 5.68 m/s. The tourist reaches the car safely. What is the maximum possible
value for d?

Answers

Answer:

146.27 m

Explanation:

From the question given above, the following data were obtained:

Velocity of tourist (vₜ) = 4.65 m/s

Distance travelled by tourist (dₜ) = d

Velocity of bear (v₆) = 5.68 m/s

Distance travelled by bear (d₆) = 32.4 + d

Value of d =?

Next, we shall determine the time taken for tourist and the bear to get to the car.

For the tourist:

Velocity of tourist (vₜ) = 4.65 m/s

Distance travelled by tourist (dₜ) = d

Time (tₜ) =?

vₜ = dₜ / tₜ

4.65 = d/tₜ

Cross multiply

4.65 × tₜ = d

Divide both side by 4.65

tₜ = d / 4.65

For the bear:

Velocity of bear (v₆) = 5.68 m/s

Distance travelled by bear (d₆) = 32.4 + d

Time (t₆) =?

v₆ = d₆ / t₆

5.68 = (32.4 + d) / t₆

Cross multiply

5.68 × t₆ = (32.4 + d)

Divide both side by 5.68

t₆ = (32.4 + d) / 5.68

NOTE: Both the tourist and the bear have the same time. Thus, to obtain the value of d, we shall equate both the time taken for the tourist and the bear together. This is illustrated below:

Time taken by tourist (tₜ) = time taken by the bear (t₆)

tₜ = d / 4.65

t₆ = (32.4 + d) / 5.68

tₜ = t₆

d / 4.65 = (32.4 + d) / 5.68

Cross multiply

d × 5.68 = 4.65 (32.4 + d)

5.68d = 150.66 + 4.65d

Collect like terms

5.68d – 4.65d = 150.66

1.03d = 150.66

Divide both side by 1.03

d = 150.66 / 1.03

d = 146.27 m

Thus, the maximum value of d is 146.27 m

Two 10-cm-diameter charged rings face each other, 23.0 cm apart. Both rings are charged to 40.0 nC . What is the electric field strength You may want to review (Pages 641 - 643) . For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Charge on a Van De Graaff.

Answers

The strength of the electric field is 1.10×10^4 N/C.

The data is sent to us.

r = d/2 = 0.1/2 = 0.05 m, d = 10 cm = 0.1 m, and z = 17 cm = 0.17 m

Q = 40 nC = 40×10^-9 C

A) in the middle of the two circles

Since the electric fields created by the two rings are directed in opposite directions, there is no electric strength.

B) midway down the left ring

Electric strength is equal to the sum of the electric fields created by the left and right rings.

Electric strength is equal to E leftring + E rightring, which equals 0 plus kQz/(r2 + z2).

Electric strength = k×Q×z/(r^2 + z^2)^

Electric strength = 9×10^9×40×10^-9×0.17/(0.05^2 + 0.17^2)

Electric strength= 1.10×10^4 N/C

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QUESTION 1
A box, initially at rest, has 33.3 N of force exerted on it for 2.35 s. If the box has a mass of 7.33 kg, what was its velocity at this time?

Answers

Answer:

Velocity of the box: 10.67 m/s

Explanation:

Recall that impulse is defined as the force applied times the time the force is in action. Then we can obtained the value of the impulse given to the box as:

Impulse = F * time = 33.3 N * 2.35 s = 78.225 kg m/s

then we use the momentum of the box at that precise time to find its velocity recalling that :

Momentum = mass * velocity

Then

78.225 kg m/s = 7.33 kg * v

v = 78.225/7.33  m/s = 10.67 m/s

The ball of a ballpoint pen is 0.5 mm in diameter and has an ASTM grain size of 12. How many grainsare there in the ball

Answers

Answer:

the number of grains in the ball is 274,848

Explanation:

Given that;

diameter = 0.5 mm

so radius r = 0.25 mm

first we determine the volume of the ball using the following equation;

V = 4/3×πr³

we substitute

V = 4/3×π(0.25)³

V =  0.06544 mm³

Now form table 1.1 "Grain sizes" a metal with grain size number of 12 has about 4,200,000 grains/mm³

so;

Number of grains N = 0.06544 × 4,200,000

N = 274,848 grains

Therefore, the number of grains in the ball is 274,848

A ball rolls across a smooth surface at a steady 0.5 m/s. What is its acceleration? m/s^2?

Answers

Answer:

0m/s²

Explanation:

The acceleration of the given body whose motion has been described will be zero.

This is because the body moves with a constant velocity.

Acceleration is defined as the rate of change of velocity with time.

Since in this problem, the velocity is not changing per time, then the acceleration would be zero.

A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.

What are the characteristics of a nebulae? (Select all that apply.)
end-stage of a star’s life
contain hydrogen
clouds of gas and dust
location of gas planets
needed to create a star

Answers

Answer:

B. contain hydrogen

C. clouds of gas and dust

E. needed to create a star

Explanation:

A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.

Some of the examples of stars are; Vega, Sun (closest to planet Earth), Antares, Betelgeus, Canopus, etc.

Stars are typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He). The chronological order in which the formation of a star occur are;

1. Gravity pulls gas and dust together to form dense cores.

2. A protostar forms as mass increases.

3. Nuclear fusion begins under high pressure.

Scientists have been able to understand and discover that, gravity pulled materials (low-density cloud of interstellar gas and dust known as a nebula) together forming the planetary bodies in our solar system.

A dark nebula can be defined as an interstellar cloud that is so dense as a result of high concentration of gas and dust and as such it obscures the visible wavelengths of light from stars behind it, thus appearing completely opaque (dark patch) in front of a bright emission nebula or in regions having plenty stars.

The characteristics of a nebulae are;

I. It contain hydrogen.

II. Clouds of gas and dust

III. It is needed to create a star.

A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?

Answers

Answer:

Δp = 620 N.s

Explanation:

Newton's second law, was originally conceived  as follows:

       [tex]F = \frac{\Delta p}{\Delta t} (1)[/tex]

In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

       for m= constant, it reduces to F= m*a.

Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

       [tex]\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)[/tex]

An object accelerates 3.0 m/s2 when a force of 6.8 newtons is applied to it. What is the mass of the object?

Answers

F= ma so m= F/a m= 6.8/3 = 2.27 kg

Which option is an example of a good blackbody radiator?
A. A mirror that reflects the light that strikes it
B. A classroom full of students in a school
C. A stove burner that glows red when it is turned on
D. Water that bends the light that enters it

Answers

Answer: C. A stove burner that glows red when it is turned on

Explanation:

I did the quiz

A source of frequency f sends waves of wavelength λ traveling with speed v in some medium. If the frequency is changed from f to 2f, then the new wavelength and new speed are (respectively): Question 1 options:

Answers

Answer:

Explanation:

The speed will remain unchanged because speed does not depend upon frequency .

So new speed = v

wavelength x frequency = speed

For frequency = 2 f

wavelength = speed / frequency

= v / 2f

So new wavelength = v / 2f .

1. The new wavelength is equal to [tex]\frac{\lambda}{2}[/tex].

2. The new speed is equal to v.

Given the following data:

Wavelength = λSpeed = vInitial frequency = fFinal frequency = 2f

To determine the new wavelength and new speed are:

Mathematically, the speed of a waveform is calculated by using the formula;

[tex]v = \lambda f[/tex]

Where:

[tex]\lambda[/tex] is the wavelength of a wave.v is the speed of a wave.f is the frequency of a wave.

Ideally, the speed of a wave doesn't change when the frequency provided they are both in the same medium.

However, the wavelength would change when frequency changes.

Therefore, the new speed = v.

For new wavelength:

[tex]v = \lambda f=\frac{\lambda}{2} (2f)[/tex]

New wavelength = [tex]\frac{\lambda}{2}[/tex]

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If the mass of the moon is ...
a. ... increased by a factor of 2, then the F . is
by a factor of
b. ... increased by a factor of 3, then the F., is
by a factor of
C. ... decreased by a factor of 4, then the F... is
by a factor of
d. Discuss some evidence (data values) and reasoning in which you explain the
logic behind your answers to parts a-c.

Answers

C decreased the factor cuz the max is smaller

At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 300 N/C. At a distance r2 from the charge, the field has a magnitude of 160 N/C. Find the ratio r2/r1.

Answers

Answer:

the  ratio of r₂/r₁ is 1.37.

Explanation:

Given;

magnitude of electric field strength at a distance r₁, E₁ = 300 N/C

magnitude of electric field strength at a distance r₂, E₂ = 160 N/C

Electric field strength is given as;

[tex]E = \frac{kQ}{r^2} \\\\E_1r_1^2 = E_2r_2 ^2\\\\\frac{E_1}{E_2} = \frac{r_2^2}{r_1^2} \\\\\frac{E_1}{E_2} =( \frac{r_2}{r_1})^2\\\\\sqrt{\frac{E_1}{E_2} } = \frac{r_2}{r_1}\\\\\frac{r_2}{r_1} = \sqrt{\frac{300}{160} }\\\\\frac{r_2}{r_1} =1.37[/tex]

Therefore, the  ratio of r₂/r₁ is 1.37.

A flat, rigid object oscillates as a physical pendulum in simple harmonic motion with a frequency f. The mass of the pendulum is m, and the pivot point is a distance d from the center of mass. What is the moment of inertia of the pendulum about its pivot point

Answers

Answer:

I = mgd/4π²f²

Explanation:

The period of the physical pendulum T = 1/f where f = frequency,

T = 1/f = 2π√(I/mgd) where I = moment of inertia of the physical pendulum, m =mass of pendulum, g = acceleration due to gravity and d = distance of center of mass of pendulum from pivot point.

1/f = 2π√(I/mgd)

dividing both sides by 2π, we have

1/2πf = √(I/mgd)

squaring both sides, we have

(1/2πf) = [√(I/mgd)]²

1/4π²f² = I/mgd

multiplying both sides by mgd, we have

I = mgd/4π²f²

What needs to happen to make electrical current flow in a generator?

Answers

Electric current can be generated by moving a metal wire through a magnetic field. This applies both to alternating current (AC) and direct current (DC) electricity. This is a different method than where DC is created by a battery, which uses chemical reactions

Two marbles, one twice as massive as the other, are dropped from the same height. When they strike the ground, how does the kinetic energy of the more massive marble compare to that of the other marble

Answers

Answer: The more massive one will have larger kinetic energy.

Explanation:

We know that when we drop an object, the acceleration of the object will be equal to the gravitational acceleration.

a(t) = -9.8m/s^2

And to get the velocity, we need to integrate over time, to get:

v(t) = (-9.8m/s^)*t + v0

Where v0 is the initial speed of the object.

You can see that the mass of the object does not affect the velocity of it.

Then when we drop two marbles of different masses from the same height, we know that the final velocity of them will be equal.

Now, we also know that the kinetic energy can be written as:

K = (m/2)*v^2

where m is the mass, and v is the velocity.

Then the kinetic energy of the marble with less mass can be written as:

k = (m/2)*v^2

And the kinetic energy for the more massive one is:

K = (M/2)*v^2

And we know that both of them have the same velocity, and M is larger than m, then we can conclude that the marble with larger mass will have larger kinetic energy.

Find the electron and hole mobilities, and the resistivity of intrinsic silicon at 300K. Is intrinsic silicon a semiconductor

Answers

Answer:

Resistivity = 231.481 K Ohm

Yes, Intrinsic Silicon is the semiconductor.

Explanation:

Solution:

At 300K:

Let suppose mobility of electron in intrinsic semiconductor = [tex]M_{e}[/tex]

Mobility of electron in intrinsic semiconductor is:

[tex]M_{e}[/tex]  = 1300 [tex]cm^{2}[/tex]/volt.sec

Let suppose mobility of hole in intrinsic semiconductor = [tex]M_{h}[/tex]

[tex]M_{h}[/tex] = 500 [tex]cm^{2}[/tex]/volt.sec

We know that, intrinsic silicon semiconductor has equal number of holes and electrons. So,

At 300 K

Intrinsic Carrier Concentration = 1.5 x [tex]10^{10}[/tex]/[tex]cm^{3}[/tex] = C

And,

Conductivity of intrinsic Silicon is:

σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e

e = 1.6 x [tex]10^{-19}[/tex] C

So, plugging in the values, we get:

σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e

σ = 1.5 x [tex]10^{10}[/tex] x (500 + 1300) x 1.6 x [tex]10^{-19}[/tex]

σ = 4.32 x [tex]10^{-6}[/tex]

So, now we can find the resistivity.

Resistivity = 1/σ

Resistivity = 1/ 4.32 x [tex]10^{-6}[/tex]

Resistivity = 231.481 K Ohm

Yes, Intrinsic Silicon is the semiconductor.

(I am doing a lab called, Density of solids and I need help with this question) (I am in HS and I picked Physics because I thought it was short for Physical Science )


4. Locate the data and observations collected in your lab guide. What are the key results? How would you best summarize the data to relate your findings?

Answers

Answer: Location the data and observations collected in your lab guide

Explanation:

When scientists want to determine the actual age of a fossil, they use_____________

Answers

Answer:

Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages. Absolute dating is used to determine a precise age of a fossil by using radiometric dating to measure the decay of isotopes, either within the fossil or more often the rocks associated with it.

A force acts on a body of mass 13 kg initially at rest. The force
acts for 10 seconds, and once it quits, the body covers 60 min
the next 6 seconds. Find the force that acted on the body.

Answers

Answer:

Force that acted on the body was F = 13 N

Explanation:

If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s

When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:

[tex]v_f=v_i+a*t[/tex]

which in our case becomes;

[tex]10\,m/s=0+a*(10\,s)[/tex]

and we can solve for the acceleration as:

a = 10/10  m/s^2 = 1 m/s^2

Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:

F = 13 kg * 1 m/s^2 = 13 N

a machine has an efficiency of 70 percent, how much work does the machine do when 20000 j of work is done on it a. 14000 b. 20600 c. 1400000 or c. 2860000

Answers

Answer:

a. 14000

Explanation:

Given parameters:

Efficiency of the machine  = 70%

Work done on machine  = 20000J

Unknown:

Work done by machine = ?

Solution:

 Efficiency of a machine is determined by;

  Efficiency  = [tex]\frac{Work done by machine}{Work done on machine} x 100[/tex]  

   70  = [tex]\frac{Work done by machine}{20000}[/tex] x 100

   

   70  = [tex]\frac{work done by machine}{200}[/tex]  

 Work done by machine  = 70 x 200 = 14000J

which two types of potentional energies would be types of mechancial energies

Answers

Answer:

Gravitation Potential Energy and Elastic Potential Energy

Explanation:

PE=abbreviation for potential energy

PE is a mechanical energy like KE is. There are two types of PE in high school physics (do not talk about other PE's like chemical PE).

Elastic PE is like the stored energy for example in a pole vault competition, the Elastic PE is stored in the pole before the vaulter goes over the desired height. (Energy stored in ELASTIC object ONLY) (commonly on the 11th grade regents springs are used to represent elastic PE)

Gravitational PE can be calculated through the formula PE=mgh although some people substitute the PE with a U. (ENERGY STORED IN OBJECT'S HEIGHT)


An object moves along the x-axis. Its position is given by the equation y( X = 4t^2 - 41t+ 78 \). Find the position of the
object when it changes direction

Answers

The object changes direction when its velocity changes sign. You can get the velocity function by differentiating the position function with respect to time t :

x(t) = 4t ² - 41t + 78

→   v(t) = dx(t)/dt = 8t - 41

Solve v(t) = 0:

8t - 41 = 0

8t = 41

t = 41/8 = 5.125

Just to confirm that the velocity indeed changes sign:

• Pick any time before this one to check the sign of v :

v (0) = 8•0 - 41 = -41 < 0

• Pick any time after and check the sign again:

v (6) = 8•6 - 41 = 7 > 0

Now just find the position at this time:

x (5.125) = -433/16 = -27.0625

which means the object is 27.0625 units on the negative x-axis.

You can also do this without calculus by completing the square in the position function:

4t ² - 41t + 78 = 4 (t ² - 41/4 t ) + 78

… = 4 (t ² - 2• 41/8 t + (41/8)² - (41/8)²) + 78

… = 4 (t ² - 2• 41/8 t + (41/8)²) - 4•1681/64 + 78

… = 4 (t - 41/8)² - 433/16

which describes a parabola that opens upward. When t = 41/8 = 5.125, the quadratic term vanishes and the turning point of the parabola occurs at a position of -433/16 units.

1. How many atoms are needed to form a molecule?
Answer:

Answers

Answer: 20

Explanation: cause

Explanation:

When two or more atoms link up, they create a molecule. e.g, A molecule of water is made of two atoms of hydrogen (H) and one atom of oxygen (O).

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I need help quickly the I think the blank mean neither Write a story in which a ring, a key and a letter play an important part Central idea of "The Taming of the Shrew" Act 4 Question 9 of 10Immigrants often stayed in neighborhoods with other people from the samecountry. What were these neighborhoods called?A. Ethnic enclavesB. Ellis IslandC. TenementsD. SteerageSUBMITYes If the Cable Company offers cable for $110 a month but gives a 10%discount for new customers. Find the cost for the new customers. (SHOWALL WORK) At McMeck High School they decided to calculate the average GPA of all 950 students. Theaverage GPA was 2.38 with a standard deviation of 0.59, what is the margin of error? Roundyour answer to three decimal places. What does the atomic mass of an atom tell us? (2 points)O How much the atom weighsO The number of electrons in the atomO Which row the element is in on the periodic tableO The number of energy levels in the atom pollock's method became known as "action painting" because_______ A. it was used by the indians. B. it showed people in action. C. the artist moved around while doing it. 3. What does he mean by "wee must Consider that wee shall be as a City upon a Hill? Divide 8/9 by 1/4" Your answer What is the value of x? Which part is correct or wrong PLEASE HELP ASPPPP!!! 840x60=____________ Read the excerpt below from Araby by James Joyce and answer the question that follows.Every morning I lay on the floor in the front parlour watching her door. The blind was pulled down to within an inch of the sash so that I could not be seen. When she came out on the doorstep my heart leaped. I ran to the hall, seized my books and followed her. I kept her brown figure always in my eye and, when we came near the point at which our ways diverged, I quickened my pace and passed her. This happened morning after morning. I had never spoken to her, except for a few casual words, and yet her name was like a summons to all my foolish blood.Her image accompanied me even in places the most hostile to romance. On Saturday evenings when my aunt went marketing I had to go to carry some of the parcels. We walked through the flaring streets, jostled by drunken men and bargaining women, amid the curses of labourers, the shrill litanies of shop-boys who stood on guard by the barrels of pigs cheeks, the nasal chanting of street-singers, who sang a come-all-you about ODonovan Rossa, or a ballad about the troubles in our native land. These noises converged in a single sensation of life for me: I imagined that I bore my chalice safely through a throng of foes. Her name sprang to my lips at moments in strange prayers and praises which I myself did not understand. My eyes were often full of tears (I could not tell why) and at times a flood from my heart seemed to pour itself out into my bosom. I thought little of the future. I did not know whether I would ever speak to her or not or, if I spoke to her, how I could tell her of my confused adoration. But my body was like a harp and her words and gestures were like fingers running upon the wires.One evening I went into the back drawing-room in which the priest had died. It was a dark rainy evening and there was no sound in the house. Through one of the broken panes I heard the rain impinge upon the earth, the fine incessant needles of water playing in the sodden beds. Some distant lamp or lighted window gleamed below me. I was thankful that I could see so little. All my senses seemed to desire to veil themselves and, feeling that I was about to slip from them, I pressed the palms of my hands together until they trembled, murmuring: O love! O love! many times.At last she spoke to me. When she addressed the first words to me I was so confused that I did not know what to answer. She asked me was I going to Araby. I forgot whether I answered yes or no. It would be a splendid bazaar, she said she would love to go.And why cant you? I asked.While she spoke she turned a silver bracelet round and round her wrist. She could not go, she said, because there would be a retreat that week in her convent. Her brother and two other boys were fighting for their caps and I was alone at the railings. She held one of the spikes, bowing her head towards me. The light from the lamp opposite our door caught the white curve of her neck, lit up her hair that rested there and, falling, lit up the hand upon the railing. It fell over one side of her dress and caught the white border of a petticoat, just visible as she stood at ease.Its well for you, she said.If I go, I said, I will bring you something.What innumerable follies laid waste my waking and sleeping thoughts after that evening! I wished to annihilate the tedious intervening days. I chafed against the work of school. At night in my bedroom and by day in the classroom her image came between me and the page I strove to read. The syllables of the word Araby were called to me through the silence in which my soul luxuriated and cast an Eastern enchantment over me. I asked for leave to go to the bazaar on Saturday night. My aunt was surprised and hoped it was not some Freemason affair. I answered few questions in class. I watched my masters face pass from amiability to sternness; he hoped I was not beginning to idle. I could not call my wandering thoughts together. I had hardly any patience with the serious work of life which, now that it stood between me and my desire, seemed to me childs play, ugly monotonous childs play.What do the images in paragraph 3 seem to foreshadow?A.Distance will play a role in the resolution of the story.B.The bazaar will be rained out.C.The boys wishes will be unfulfilled.D.Love will overcome any obstacles put in the boys way.E.The drawing room will burn down. Jay made 3 out of 12 attempted baskets in the game. What percentage of the shots did he NOT make? Dis fo chem try n answer it ig. How is the author affected by the violin music?AShe feels less alone in the world, listening to a fellow Arab-American musician.BShe feels moved by the reminder of important parts of herculture.She feels saddened by the reminder that Arab-Americansare struggling right now.She is upset by the reminder of her past and the culturalexpression she is no longer allowed. I NEED HELPSlope-Intercept Formx=-4I don't know how to graph this, I basically just need help learning it, I barely understand Slope-Intercept Form. can someone help plzzzzzzzzzzzzzzzzz ill give extra brain lets