What does the atomic mass of an atom tell us? (2 points)
O How much the atom weighs
O The number of electrons in the atom
O Which row the element is in on the periodic table
O The number of energy levels in the atom

Answer:

W = 29.06 KJ

Explanation:

The work done while stretching the leash can be calculated by the following formula:

[tex]W = \int\limits^b_a {F_{x}} \, dx \\[/tex]

whee,

W = Work Done = ?

Fₓ = Forcing Function = (-5.7 N/m)x - (78 N/m²)x²

a = starting point of x = 0 m

b = end point of x = 22 m

Therefore,

[tex]W = \int\limits^{22\ m}_{0\ m} {(-(5.7\ N/m)x - (7.8\ N/m^{2})x^{2}}) \, dx \\Integrating\ we\ get:\\W = -\frac{(5.7\ N/m)x^{2}}{2} - \frac{(7.8\ N/m^{2})x^{3}}{3}\\Applying\ limits:\\W = -\frac{(5.7\ N/m)(22\ m)^{2}}{2} - \frac{(7.8\ N/m^{2})(22\ m)^{3}}{3} - 0\\W = - 1379.4\ J - 27684.8\ J\\W = 29064.2\ J[/tex]

W = 29.06 KJ

Answer:

50N to the left

Explanation:

I'll explain if you ask

Answer:

50 newtons to the left

Explanation:

Answer:7.58 m

Explanation:

The required wavelength of a sound wave of frequency 660 Hz in steel is approximately 7.58 meters.

Wavelength is a fundamental property of waves, including electromagnetic waves like light and radio waves, as well as other types of waves, such as sound waves or water waves.

Here,
The wavelength (λ) of a sound wave is given by the formula,

λ = v/f

where v is the speed of sound in the medium and f is the frequency of the wave.

In this case, the speed of sound in steel is v = 5000 m/s, and the frequency of the sound wave is f = 660 Hz. Substituting these values into the formula, we get:

λ = 5000 m/s / 660 Hz

λ = 7.58 meters (rounded to two decimal places)

Therefore, the wavelength of a sound wave of frequency 660 Hz in steel is approximately 7.58 meters.

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Answer:

[tex]v=2.4*10^8m/s[/tex]

Explanation:

From the question we are told that

Wavelength of emission [tex]\lambda=122nm[/tex]

Observation distance [tex]d=366nm[/tex]

Generally the s equation is given as

[tex]f'=f\sqrt{\frac{(1-\frac{v}{c} )}{1+\frac{v}{c} }[/tex]

where

F is inversely proportional to T

[tex]d=\lambda\sqrt{\frac{(1-\frac{v}{c} )}{1+\frac{v}{c} }[/tex]

[tex]\frac{v}{c} =\frac{(1-\frac{\lambda}{d})}{(1+\frac{\lambda}{d}}[/tex]

[tex]\frac{v}{c}=\frac{1-(\frac{122}{366} )^2}{1+(\frac{122}{366})^2}[/tex]

[tex]\frac{v}{c}=\frac{0.8888888889}{1.11111111}[/tex]

[tex]\frac{v}{c}=0.80[/tex]

[tex]v=0.80*3*10^6[/tex]

[tex]v=2.4*10^8m/s[/tex]

Answer:

13.18m/s²

Explanation:

According to Newton's second law of motion

Force = Mass * acceleration

Given

Mass = 11kg

Force = 145N

Required

acceleration

From the formula

Acceleration = Force/Mass

Acceleration = 145/11

Acceleration = 13.18m/s²

Hence the initial acceleration of the object is 13.18m/s²

Answer:

[tex]V_2_X=33.16m/s[/tex]

Explanation:

From the question we are told that

Mass of car        [tex]M_1=1210kg \\Angle1=\theta _1 45\textdegree NE[/tex]

Velocity of car   [tex]v_1= 15m/s[/tex]

Mass of Truck  [tex]M_2= 1540kg \\Angle 2=\theta_2 0\textdegree E[/tex]

Final velocity    [tex]v_2= 23.3m/s[/tex]

Generally the the equation of the law of conservation of momentum is mathematically given by

Given the x direction

  [tex]m_1v_1cos\theta+m_2v_2=(m_1+m_2)v[/tex]

  [tex]1210*15.2cos45+1540*V_2=(1210+1540)*23.3[/tex]

  [tex]V_2=\frac{(1210+1540)*23.3}{210*15.2cos45+1540}[/tex]

  [tex]V_2=33.16m/s[/tex]

The x-component  of the second car's initial velocity is

[tex]V_2_X=33.16m/s[/tex]

Answer:

he combs are brought closer, each one has to move, therefore a force must be applied to each one, and the only force is electrostatic. force must have the same magnitude in each one and in the opposite direction; this description is equivalent to Newton's third law.

Explanation:

A very simple experiment that we can do is to rub a brush or plastic comb with a piece of paper, this creates some electrical charges in the comb, we hang the comb by a thread.

We take another comb and we form it with the same paper, when we bring the combs closer, we see that they repel each other, this is proof that the electrical charges created are of the same type.  

If now we rub the comb with another material, for example plastic, and bring it closer to the comb that is hanging, we see that they are approaching, therefore, it is proven that the load created from another type

With these two simple experiments it can be proved that electric charges are of two types, which are called positive and negative.  

4. In the previous experiment we see that when the combs are brought closer, each one has to move, therefore a force must be applied to each one, and the only force is electrostatic. If we observe carefully we see that the breaking of the combs is the same, therefore the force must have the same magnitude in each one and in the opposite direction; this description is equivalent to Newton's third law.

Answer:

Explanation:

given linear charge density λ = 290 x 10⁻³ C / m

Expression for electric field at distance d is given as follow .

E = λ / 2πε₀r

1 / 4πε₀ = 9 x 10⁹

1 / 2πε₀ = 18 x 10⁹

E = λ / 2πε₀r = 290 x 10⁻³ x 18 x 10⁹ / r

= 5220 x 10⁶ / r

For r = 10 x 10⁻² m = .1 m

E = 5220 x 10⁶ / .1

= 5.22 x 10¹⁰ N/m

For r = 100 x 10⁻² m = 1 m

E = 5220 x 10⁶ / 1

= 5.22 x 10⁹ N/m .

Given :

Weight of car is, W = 10000 N.

Acceleration due to gravity, g = 10 N/kg.

To Find :

The mass of car on Earth.

Solution :

We know, mass of an object is given by :

[tex]m = \dfrac{W}{g}\\\\m = \dfrac{10000}{10}\ kg\\\\m = 1000\ kg[/tex]

Therefore, mass of the car on Earth is 1000 kg.

Answer:

25%

Explanation:

500 J out of 2000 J is 25%

Answer:

B. positive; negative.

Explanation:

From the viewpoint of Principle of Energy Conservation and Work-Energy Theorem, we notice that gravity represents a conservative force, associated with gravitational potential energy, whereas air resistance is a non-conservative force, associated with dissipated work. Therefore, the work done by gravity is positive and work done by air resistance is negative. Therefore, the correct answer is B.

This question is incomplete, the complete question is;

The picture shows a triangular prism. The end of prism are equilateral triangles with x meters. the other dimension of the prism is L meters

a) Find the volume V in terms of x and L

b) Water is entering the prism at a rate of A m³/hr. The prism is empty at time 0. Express the depth d of the water in meters in terms of A, the length of time t the water has been entering the trough, and the length L of the prism.  

Answer:

a) the volume V in terms of x and L is  ((√3/4)x²L) m³

b) required expression is (2/(3)^(1/u))√(At/L)

Explanation:

Given that;

form the question and image below;

triangular prism ends are equilateral triangle

side length = x meter

Dimension of the prism = L meter

Area of the equilateral triangle = √3/4 (side)² = √3/4 (x)² meter

Volume of the triangular prism = Area × height

= √3/4 (x)² × L

V = ((√3/4)x²L) m³

Therefore, the volume V in terms of x and L is  ((√3/4)x²L) m³

b)

Rate of water entering = A m³/hr

Depth of water tank = d meter

Time = t

Length of prism = L

now Rate of water entering is A m³/hr

dv/d = A                             [  V = ((√3/4)x²L) m³ ]

and

dv/dt = √3/4 [2x dx/dt ] L                   { L is constant }

so

A = √3/4 [2x dx/dt ] L  

∫A dt = √3/2 [ Lx dx ]                   { Integrate both sides}

At = √3/2 × Lx × x²/2

x² = uAt / √3L                              { we find square root of both sides}

x = √( uAt / √3L )

x = (2/(3)^(1/u))√(At/L)

Therefore; required expression is (2/(3)^(1/u))√(At/L)

Answer:

T = 1733.16 s = 28.88 min

Explanation:

The orbital velocity of a satellite about Earth is given as follows:

[tex]v = \sqrt{\frac{GM}{R}}[/tex]

where,

v = orbital speed = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

M = Mass of Earth = 5.982 x 10²⁴ kg

R = Orbit Radius = 3.117 x 10⁶ m

Therefore,

[tex]v = \sqrt{\frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(5.982\ x\ 10^{24}\ kg)}{(3.117\ x\ 10^{6}\ m)}}\\\\v = 11.3\ x\ 10^{3}\ m/s[/tex]

but the velocity is given as:

[tex]v = \frac{distance}{time}[/tex]

for distance = circumference = 2πR

time = time period = T = ?

Therefore,

[tex]11.3\ x\ 10^{3}\ m/s = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{T}\\\\T = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{11.3\ x\ 10^{3}\ m/s}\\\\[/tex]

T = 1733.16 s = 28.88 min

Answer:

hydrogen and helium

Explanation:

the sun is so hot that the huge amount of hydrogen is undergoing a constant star wide nuclear reaction

Answer:

the correct answer is C and D

I took a test hope it helps

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

[tex]h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m[/tex]

The time to fall through the height is calculated as;

[tex]h =ut+ \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s[/tex]

Therefore, the time taken for the object to fall is 6 s.

Answer:576

Explanation:

Answer:

Rocks, coins, honey, vegetable oil, diamonds, etc.

Explanation:

Object that are more dense than water.

Answer:

the answer to your question is b

Answer:

The ball will get to the bottom of the cliff in 1.26 s, while the player will reach the bottom of the cliff  2 s later. Thus, it is not possible for the player to catch the ball.

Explanation:

Given;

vertical height of the cliff, h = 22 m

velocity of the ball, u = 18 m/s at an angle 39⁰

vertical component of the velocity, [tex]u_y = u \ sin \theta[/tex]

The time for the ball to get to the bottom of the cliff is calculated as;

h = ut + ¹/₂gt²

h = (u sinθ)t + ¹/₂ x 9.8 x t²

22 = (18 sin 39)t + 4.9t²

22 = 11.328t + 4.9t²

4.9t² + 11.328t  - 22 = 0

Solve the above equation with formula method;

a = 4.9, b = 11.328, c = -22

[tex]t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-11.328\ \ +/- \ \ \sqrt{(-11.328)^2 - 4(4.9\times -22)} }{2(4.9)}\\\\t = 1.26 \ s[/tex]

The time for the player to get to the bottom of the cliff;

Given maximum speed, Vx = 6.0 m/s and horizontal distance, X = 12 m;

[tex]t = \frac{X}{V_x} \\\\t = \frac{12}{6} \\\\t = 2 \ s[/tex]

The ball will get to the bottom of the cliff in 1.26 s, while the player will reach the bottom of the cliff 2 s later. Thus, it is not possible for the player to catch the ball.

Answer:

mg, g, kg,

Explanation:

Tip King Henry Died Unit Drinking Chocolate Milk

Mg is in the back so its smallest then unit which is g and finally King also known as Kilogram which is the biggest

A color.......................................................................yeah the color of your socks is a color :}

Answer:

The speed of the water bottle at impact with the street is 49 m/s

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not experience air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The water bottle dropped by Jamie takes t=5 seconds to impact the ground, thus its speed at that moment is:

vf= 9.8*5

vf =  49 m/s

The speed of the water bottle at impact with the street is 49 m/s

Answer:

IBL²

Explanation:

Given that

Current flowing in the wire, is I

Magnetic field towards the right, is B

Length of each side of the loop, is L

Number of windings on the loop, is N

Torque exerted on the wire, is T

The torque, T is usually given by the formula

Torque, T = NBIAsinθ,

and if N = 1 and sinθ = 1 also, then we have

Torque, T = BIA

And we know that Area A from this particular question will be given as = L². If we then substitute A for L², we then have

Torque, T = IBL²

Answer:

It will double.

Explanation:

Apparent weight is the weight of a physical body affected by a force of gravity different of that of the athmosphere.  Thus, the lower the gravity, that is, the lower the attraction of one body to another, the lower the apparent weight of the object on which the gravitational force is exerted; while the opposite occurs if the gravitational force is greater. In other words, the apparent weight of an object is determined by the gravitational force exerted on it: the greater the force, the greater the weight. Therefore, as the outer ring has twice the force of gravity than the inner ring, the apparent weight of the astronaut will double as well.

Answer:

Answer C It is stored as a series of ones and zeros because it was converted to binary data.

Explanation:

After the Analog to Digital Converter (ADC) the data is stored in a series of numbers encoded in binary mode (combinations of Zeros and Ones).

This agrees with answer labeled as C) in the list of options.

Answer: C

Explanation: Study Island correct

Answer:

Option A. 0.33 m/s

Explanation:

From the question given above, the following data were obtained:

Mass of A (mₐ) = 1000 kg

Velocity of A (uₐ) = 5 m/s

Mass of B (m₆) = 2000 kg

Velocity of B (u₆) = 2 m/s

Velocity (v) after collision =?

mₐuₐ – m₆u₆ = v (mₐ + m₆)

(1000 × 5) – (2000 × 2) = v (1000 + 2000)

5000 – 4000 = 3000v

1000 = 3000v

Divide both side by 3000

v = 1000 / 3000

v = 0.33 m/s

Thus, the speed of the cars after collision is 0.33 m/s

The speed of the cars after the collision is 0.33 m/s.

The right option is a. 0.33 m/s

To calculate the speed of the cars after the collision, we use the formula below.

Formula:

Where:

make V the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The speed of the cars after the collision is 0.33 m/s.

The right option is a. 0.33 m/s

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Answer: Choice A) 0.44 miles

=================================================

Work Shown:

1 hour = 60 minutes

1 minute = 60 seconds

1 hour = 60*60 = 3600 seconds

40 seconds = 40*(1/3600) = 40/3600 = 1/90 hours

The car travels 1/90 of an hour. Let t = 1/90.

The initial velocity is vi = 30 mph.

The final velocity is vf = 50 mph.

Apply one of the kinematics equations as given below.

x = distance traveled

x = 0.5*(vi+vf)*t

x = 0.5*(30+50)*(1/90)

x = 0.44444444444444 which is approximate

x = 0.44

The car traveled roughly 0.44 miles. This matches with choice A.

I'm assuming choice A is supposed to say 0.44 instead of 0.442; otherwise, I think your teacher made a typo by putting that 2 in there. Each of the other answer choices are accurate to 2 decimal places, so it would make sense that choice A is also accurate to 2 decimal places as well.

If 0.442 was intended by your teacher, and it's not a typo, then the answer would be E) None of the choices given.

Answer:

If it turns the paper blue it would have to be a base.

Explanation:

I hope that answers your question!

Answer:

If it turns the paper blue it would have to be a base.

Explanation:

I hope that answers your question!