Identify bond types as either ionic, metallic or covalent
HCN
Fe
PbO
Si
​

Answer:

The answer for this problem would be "b. A 10 mL graduated cylinder".

Explanation:

The reason for this is because with a instrument that is closer to the value you're trying to measure, the more precise it will be.

For example using a teaspoon to measure something rather than a cup.

11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex]  gas measured at 1.3 atm pressure and 298 K

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

Moles = 0.3588 moles

Now,

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]0.3588 moles = \frac{mass}{32}[/tex]

Mass= 11.48 gram

Hence, 11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K

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Answer:

40 g= 6.022×10²³

x=1.4×10¹⁵

x=40g×6.022×10²³/1.4×10¹⁵

x=17.77×10⁸

Answer:

nitrogen compounds in the air

Explanation:

Answer:

The oxygen atom in water has a negative charge.

Polar molecule: A molecule in which the centroid of the positive charges is different from the centroid of the negative charges.

Oxygen: A colorless, odorless, gaseous element constituting about one-fifth of the volume of the atmosphere and present in a combined state in nature. It is the supporter of combustion in air and was the standard of atomic, combining, and molecular weights until 1961, when carbon 12 became the new standard. Symbol: O; atomic weight: 15.9994; atomic number: 8; density: 1.4290 g/l at 0°C and 760mm pressure.

Water: A transparent, odorless, tasteless liquid, a compound of hydrogen and oxygen, H2O, freezing at 32°F or 0°C and boiling at 212°F or 100°C. that in more or less impure state constitutes rain, oceans, lakes, rivers, etc.: it contains 11.188 percent hydrogen and 88.812 percent oxygen, by weight.

Hydrogen: A colorless, odorless, flammable gas that combines chemically with oxygen to form water: the lightest of the known element. Symbol: H; atomic weight: 1.00797; atomic number: 1; density: 0.0899 g/l at 0°C and 760 mm pressure.

Atom: Am atom is the smallest constituent particle of a chemical element which has the properties of that element. They re comprised of at least an electron and a portion, as is the case for Hydrogen. Atoms of all other elements however, contain at least one neutron.

Proton: A positively charged elementary particle that is a fundamental constituent of all atomic nuclei. It is the lightest and most stable baryon, having a charge equal in magnitude to that of the electron, a spin of 1/2, and a mass of 1.673 × 10-27kg. Symbol: P.

Electron: An elementary particle that is a fundamental constituent of matter, having a negative charge of 1.602 × 10-19 coulombs, ha mass of 9.108 × 10-31 kilograms, and spin of 1/23, and existing independently or as the component outside the nucleus of an atom.

Neutron: An elementary particle having no charge, mass slightly greater than that of a proton, and spin of 1/2: a constituent of the nuclei of all atoms except those of hydrogen. Symbol: n.

A object has a negative charge when it consists of more electrons than protons.

With a partial positive charge on 2 Hs and a partial negative charge on oxygen, water molecules are polar molecules.

Actually, two hydrogen atoms and the core oxygen atom of water are covalently connected. Due to its greater electronegative nature than hydrogen, oxygen pulls the bound electron pair in the middle of the atom toward it.

When illustrating higher electron densities over oxygen, partial negative charge is used, whereas partial positive charge is used to illustrate lower densities over hydrogen atoms.

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Answer:

T₂ = 39.4 °K

Explanation:

Because you are only dealing with volume and temperature, you can use Charles' Law to find the missing value. The formula looks like this:

V₁ / T₁ = V₂ / T₂

In this formula, "V₁" and T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You have been given values for all of the variables except for "T₂". Therefore, by plugging these values into the formula, you can simplify to find the answer.

V₁ = 350 mL                     T₁ = 45 °K

V₂ = 400 mL                     T₂ = ?

V₁ / T₁ = V₂ / T₂                                        <----- Charles' Law formula

(350 mL)(45 °K) = (400 mL)T₂                <----- Insert values into variables

15750 = (400 mL)T₂                                <----- Multiply left side

39.4 = T₂                                                 <----- Divide both sides by 400

So mass of sulphur

[tex]\\ \rm\Rrightarrow 0.02\times 757\times 10^{6}[/tex]

[tex]\\ \rm\Rrightarrow 1514\times 10^4[/tex]

Moles =64/32=2

So

So tons of sulphur dioxide

[tex]\\ \rm\Rrightarrow 2(1516)10^4[/tex]

[tex]\\ \rm\Rrightarrow 3032\times 10^4ton[/tex]

Explanation:

2% of 2million tons of sulphur=

2÷100×7.57E9

That is;

[tex] \frac{2}{100} \times 7.57 \times 10 {}^{6} = 0.02 \times 7.57 \times 10 {}^{6} \\ = 2 \times 10 {}^{ - 2} \times7.57 \times 10 {}^{6} = 2 \times 7.57(10 {}^{ - 2 + 6}) \\ = 15.14 \times 10 {}^{4} (for \: sulphur) \\ for \: sulphur \: dioxide = so2 \\ the \: molar \: mass \: of \: so2 = 64g.mol {}^{ -1} \\ if \: 32grams \: of \: sulphur \: weighs \: 15.14 \times 10 {}^{4} tones \\ 64grams \: will \: weigh \: \frac{64}{32} \times 15.14 \times 10 {}^{4} \\ = 2 \times 15.14 \times 10 {}^{4} \\ = 30.28 \times 10 {}^{4} \\ or = 3.028 \times 10 {}^{5} tones[/tex]

Answer:

Whts ur question??

..?

Explanation:

Was this by mistake or smthin

The type of crude oil that is considered to be the highest quality for gasoline is West Texas Intermediate (Option B).

Oil is a fossil fuel obtained from Earth's crust, which is fundamental nowadays to generate electricity.

West Texas Intermediate is a highly pure and high-type energy source of crude oil used in industry.

In conclusion, the type of crude oil that is considered to be the highest quality for gasoline is West Texas Intermediate.

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NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

[tex]2NO(g) +2H_2(g)[/tex] → [tex]N_2 +2H_2O[/tex]

Moles of nitrogen monoxide

Molecular weight: [tex]M_(_N_O_)[/tex]=30g/mol

[tex]n_(_N_O_) =\frac{mass}{molar \;mass}[/tex]

[tex]n_(_N_O_) =\frac{22.0}{30g/mol}[/tex]

[tex]n_(_N_O_) = 0.73 mol[/tex]

Moles of hydrogen

Molecular weight: [tex]M_(_H_2_)[/tex]=30g/mol

[tex]n_(_H_2_) =\frac{mass}{molar \;mass}[/tex]

[tex]n_(_H_2_) =\frac{5.80g}{2g/mol}[/tex]

[tex]n_(_H_2_) = 2.9 mol[/tex]

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

[tex]n_(_N_2_) =[/tex] (2.9 mol- 0.73 mol NO x [tex]\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}[/tex]) x [tex]\frac{2g \;of \;H_2}{mole \;of \;H_2}[/tex]

[tex]n_(_N_2_) =[/tex]4.34 g

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The Correct option is A. octahedral

because the molecule has 6 sigma bonds that results into sp³d² hybridization.

and octahedral structure is formed

Answer:

Octahedral

Explanation:

You have a atom connected to 6 others and each of the bonds are similar

Gneiss is a sedimentary rock and granite is a metamorphic rock. That is option A.

Rocks are geological hard materials that are made up of various types which include:

Therefore, Gneiss is a sedimentary rock and granite is a metamorphic rock.

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Answer:

C

Granite is formed due to the slow cooling of magma below Earth's surface and gneiss is formed due to metamorphosis.

Explanation:

I took the test!

Answer:

cysteine is HOOC-CH--CH₂-SH

reaction with Naoh

HOOC-CH--CH₂-SH + Naoh ---->oh-oNH2-oh + H2o

Answer:

Just under 1 tsp

Explanation:

This is a situation where dimensional analysis is helpful....

156 mg / (80 mg / 2.5 ml    *  5 ml / tsp ) =

156 mg / ( 160 mg/tsp)   = .975  tsp    ~~~  1 tsp

Answer:

you know that they will be a displacement reaction that will form a barium salt:

Ba(NO3)2+ 2NaCl--> BaCl2 + 2NaNO3

So now that we have that formula and the molecular weight we can determine how much salt will be made. So here we convert the grams to moles

(42.3g Ba(NO3)2)*(1 mole/261.34g) = 0.16185 mol

In the molecular formula we know that 1 mole of Barium nitrate will create 1 mole of Barium chloride, so in this case (in a perfect world) you should get 0.16185 mole of barium chloride (208.23 g/mol) that we then have to convert to grams.

(0.16185 mol BaCl2) * ( 208.23 g/mol) = 33.7037 g of Barium Chloride (rounded to 3 significant digits = 33.7g)

Answer:

V = 11 L

Explanation:

To find the missing value, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this formula,

 ----> P = pressure (atm)

 ----> V = volume (L)

 ----> n = number of moles

 ----> R = constant (0.0821 atm*L/mol*K)

 ----> T = temperature (K)

You have been given all of the values in the correct units. Therefore, you can plug these values into the equation and simplify to find volume. The answer should have 2 sig figs to match the given value with the lowest amount of sig figs.

PV = nRT

(9.4 atm)V = (4.5 moles)(0.0821 atm*L/mol*K)(286 K)

(9.4 atm)V = 105.6627

V = 11 L

Answer:

pH = 4.6  

Explanation:

pH is the negative of the log of the hydrogen ion concentration

- log { 2.52 x 10^-5)   = ~ 4.6

Answer:

4.2  g  

Explanation:

The VOLUME of the ring is   4.2 - 4.0 = .2 ml  = .2 cm^3

the MASS of the ring is this times the density

.2 cm^3  *  21 g/cm^3 = 4.2 g

Answer:

the answer is c

Explanation:

density is mass/volume

so mass=density × volume

but we take the change is volume that is v2-v2=4.2-4=0.2ml

but the density is in gm/cm^3 so we should convert ml into cm^3. eventually they are equal so mass=21×0.2=4.2

Answer:

The si unit used to measure weight is kilogram /kg

Answer:

15 oxygens

Explanation:

Given the partially balanced reaction: [tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \text{5C} \text{O}_{2}}+\text{5H}_\text{2}\text{O}[/tex]

The subscripts (small number to the right of each element symbol) are the number of atoms of the element within each compound/molecule, and the coefficients (numbers in front of each compound) represent the number of that molecule involved in one full reaction (if the equation were balanced).

The product side of the reaction is on the right of the arrow.

To determine the total number of Oxygens on the product side, we need to identify how many Oxygens are in each molecule (the subscript on the Oxygen), and then multiply times the number of that molecule that would be involved (Coefficient of the compound containing Oxygen).  There are multiple compounds on the right side of the equation that contain Oxygen, so we'll need to add together the number of Oxygens each part contributes.

[tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}[/tex]

[tex]\text{\# reactant-side Oxygens}=\bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}\\=5 \text{ CO}_{\text{2}}\text{ molecules} *\frac{\text{2 Oxygens}}{\text{1 CO}_{\text{2}}\text{ molecule}}+5 \text{ H}_{\text{2}}\text{O molecules} *\frac{1\text{ Oxygen}}{\text{1 H}_{\text{2}}\text{O molecule}}\\=10\text{ Oxygens}+5\text{ Oxygens}\\=15\text{ Oxygens}[/tex]

The entropy of a mixture is 96.44J K-1 mol -1

The formula for calculating the entropy of a mixture-

Δ[tex]S_{mix} =[/tex][tex]-nR(X_{O2} ln_{XO2} +X_{N2} lnX_{N2})[/tex]

X=mole fraction

total no. of moles(t)=m + n

                             =2.4+9.2

                             =11.6 moles

now substituting the values-

entropy of mix=-11.6R(2.4/11.6 + 9.2/11.6)

                       =11.6R

( R=8.314 )        =11.6×8.314

                          =96.44J K-1 mol -1

hence, The entropy of a mixture is 96.44J K-1 mol -1

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Answer:

I am a small palm-sized pointing device

From the calculations, the concentration of the acid is 0.24 M.

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA =  50 mL

VB = 20 mL

NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

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7.66g of ethyl butyrate is produced.

The reaction is

CH₃CH₂CH₂COOH + CH₃CH₂OH ----> CH₃CH₂CH₂COOCH₂CH₃

From 0.0845 mol of butanoic acid we get 0.78 x 0.0845 = 0.66 mol of ethyl butyrate.

The molar mass of ethyl butyrate is 116.16g/mol

So 0.66 x 116.16 = 7.66g

7.66g of ethyl butyrate is produced.

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This is because fall has more weather patterns which are repetitive than summer.

This is defined as the atmospheric condition of a particular place at a given period of time.

The repetitive weather patterns have various effects on the stars which is why they were studied.

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Answer:

69.6 g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.

Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (LiOH): 23.947 g/mol

2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

75.8 g LiOH          1 mole             1 mole CO₂               44.007 g
------------------  x  ----------------  x  -----------------------  x  -------------------  =
                            23.947 g         2 moles LiOH              1 mole

= 69.6 g CO₂

The mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of LiOH = 75.8g

Moles of LiOH = mass / molar mass

                       = 75.8 / 24 = 3.15 moles

From the reaction,

2 moles of LiOH react with 1 mole of CO₂

1 mole of LiOH needs 0.5 moles of CO₂

thus, 3.15 moles will need 0.5 × 3.15 moles = 1.575 moles of CO₂

Mass of Carbon dioxide = 1.575 × 44

                                       = 69.3g of carbon dioxide

Therefore, the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g

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Answer:

1.57

Explanation:

moles = mass / molar mass

moles = 69 / 44.013

moles = 1.57

moles N₂O = 69 : 44 g/mol = 1.568

N₂O : 2 moles N, 1 mole O

moles N = 1.568 x 2 = 3.136

The pressure has no effect on the equilibrium constant.

Equilibrium is a state when the forward reaction rate is equal to the backward reaction rate .

The equation given is

H₂ + I₂ ⇄ 2HI

The Equilibrium constant depends only upon temperature and nature of reaction ,

It is independent of  catalyst presence , initial concentration of reactants,and pressure.

The pressure has no effect on the equilibrium constant.

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