Answer:
65.59 m /s
Explanation:
Initial velocity u = 4.73 m/s
Final velocity v = ?
time t = 6.21 s
acceleration = g = 9.8 m /s
v = u + gt
= 4.73 + 9.8 x 6.21
= 65.59 m /s .
An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance does the object move while accelerating?
A) 30 m
B) 3 m
C) 90 m
D) 600 m
Answer:
Distance s = 90 meter
Explanation:
Given:
Initial velocity u = 0 m/s
Final velocity v = 30 m/s
Acceleration a = 5 m/s²
Find:
Distance s
Computation:
v² = u² + 2as
30² = 0² + 2(5)(s)
Distance s = 90 meter
If the action force is the boy pushing the box, what is the reaction force?
A - the boy pushing against the box
B - the box pushing against the boy
C - friction pushing against the boy
D - friction slowing down the movement of the box
Answer:
B - the box pushing against the boy
Explanation:
Newton's third law of motion also known as the law of action and reaction states that for every action there is equal and opposite reaction.
The action force is the force acting in one direction while the reaction force is the force acting in the opposite direction. for example, when a person wants to jump, the person exerts a downward force on the ground known as action force and also, the ground exerts upward force on the person known as reaction force.
If the action force is the boy pushing the box, what is the reaction force is the box pushing against the boy.
A box of textbooks is on the middle shelf in the bookroom 1.3 m from the floor. If the janitor relocates the box to a shelf that is 2.6 m from the floor, how much work does he do
Answer:
Explanation:
Work done by janitor = increase in potential energy of book
Potential energy = mgh , m is mass , h is displacement in height and g is acceleration due to gravity .
here displacement in height of book = 2.6 - 1.3 = 1.3 m
so h = 1.3 m
m = mass of the box
increase in potential energy of box = m x 9.8 x 1.3
= 12.74 m
Work done by janitor = 12.74 m Joule .
How do you think the sock and underwear became charged?
According to force-field analysis, _____. change will occur when the sum of the opposing forces is zero equilibrium occurs when there are no forces acting for or against change change occurs when forces in one direction exceed forces in the opposing direction ignoring forces against change facilitates the change process
Answer: Change occurs when forces in one direction exceed forces in opposing direction
Explanation:
Force field analysis is the basic tool typically used in root cause analysis which enable an individual to take certain action after the identification of the root cause.
According to force-field analysis, there is a change when the forces in one direction exceed the forces in opposing direction.
In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 32.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe
Answer:
10.44 liters of gasoline.
Explanation:
First, we need to convert the units of the car from mi/gal to km/L as follows:
[tex] mileage = 32.0 \frac{mi}{gal}*\frac{1.609 km}{1 mi}*\frac{1 gal}{3.785 L} = 13.60 km/L [/tex]
That means that for every liter of gasoline the car travels 13.60 kilometers.
So, to complete a 142-km trip in Europe the volume of gasoline needed is:
[tex] V = \frac{1 L}{13.60 km}*142 km = 10.44 L [/tex]
Therefore, to complete a 142-km trip in Europe we need to buy 10.44 liters of gasoline.
I hope it helps you!
A sports car moving at constant velocity travels 130 m in 4.9 s . If it then brakes and comes to a stop in 3.8 s , what is the magnitude of its acceleration (assumed constant) in m/s2
Answer:
the magnitude of the constant acceleration is 6.98 m/s²
Explanation:
Given;
distance traveled at a constant velocity, d = 130 m
time of motion, t = 4.9 s
The constant velocity is calculated as;
[tex]v = \frac{d}{t} \\\\v = \frac{130}{4.9} \\\\v = 26.53 \ m/s[/tex]
The car comes to a stop in 3.8 s.
When the car comes to a complete stop, the final velocity of the car will be zero.
the constant acceleration is calculated as;
v = u + at
0 = u + at
at = -u
a = -u/t
a = (-26.53) / (3.8)
a = -6.98 m/s²
Therefore, the magnitude of the constant acceleration is 6.98 m/s²
If your mass is 68.05 kg,how much gravitational force would you experience on mars?
Given :
Mass, m = 68.05 kg.
To Find :
How much gravitational force would you experience on mars ?
Solution :
Acceleration due to gravity on mars is, g = 3.711 m/s²
( You can find it on internet )
Now, weight can be given as :
W = mg
W = 68.05 kg × 3.711 m/s²
W = 252.533 kg m/s² = 252.533 N
Hence, this is the required solution.
A square plate of copper with 50.0-cm sides has no net charge and is placed in a region of a uniform electric field of 80.0 kN/C directed perpendicularly to the plate. Find (a) the charge density of each face of the plate and (b) the total charge on each face.
Answer:
σ = ±708 nC/m²
Q = ±177 nC
Explanation:
given data
Side of copper plate L = 50 cm
Electric field, E = 80 kN/C
solution
we get here Charge density,σ that is express as
σ = E x ε₀ ....................1
here ε₀ is Permittivity of free space that is 8.85 x 10⁻¹² C²/Nm²
so put value in eq1we get
σ = 80 x 10³ x 8.85 x 10⁻¹²
σ = 708 x 10⁻⁹ C/m²
σ = 708 nC/m²
and
now we get here total change on each faces
Q = σ A ...............2
Q = 708 x 10⁻⁹ x (0.50)²
Q = 177 nC
A 16.9 kg monkey is swinging on a 5.32 m long vine. It starts at rest, with the vine at a 43.0° angle. How fast is the monkey moving at the bottom of its swing? (Unit = m/s)
Answer:
v = 5.7554 m/s
Explanation:
First of all we need to know if the angle of the vine is measured in the horizontal or vertical.
To do this easier, let's assume the angle is measured with the horizontal. In this case, the innitial height of the monkey will be:
h₀ = h sinα
h₀ = 5.32 sin43° = 3.6282 m
As the monkey is dropping from the innitial point which is the suspension point, is also dropping from 5.32. Then the actual height of the monkey will be:
Δh = 5.32 - 3.63 = 1.69 m
In order to calculate the speed of the monkey we need to understand that the monkey has a potential energy. This energy, because of the gravity, is converted in kinetic energy, and the value will be the same. Therefore we can say that:
Ep = Ek
From here, we can calculate the speed of the monkey.
Ep = mgΔH
Ek = 1/2 mv²
The potential energy is:
Ep = 16.9 * 9.8 * 1.69 = 279.9
Now with the kinetic energy:
1/2 * (16.9) * v² = 279.9
v² = (279.9) * 2 / 16.9
v² = 33.12
v = √33.12
v = 5.7554 m/sHope this helps
A car accelerates uniformly from rest to 23 m/s over a distance of 30 meters. What is the acceleration of the car?
Answer:
a= 17.69 m/s^2
Explanation:
Step one:
given data
A car accelerates uniformly from rest to 23 m/s
u= 0m/s
v= 23m/s
distance= 30m
Step two:
We know that
acceleration= velocity/time
also,
velocity= distance/time
23= 30/t
t= 30/23
t= 1.30 seconds
hence
acceleration= 23/1.30
accelaration= 17.69 m/s^2
Need help fast ! 10 points!
How is thermal energy different from heat?
A. Heat is a form of energy, while thermal energy is a form of energy transfer
B. Thermal energy is a form of energy, while heat is a form of energy transfer
A 1.25 m long string attached to a 60.0 Hz vibra
tor created a standing wave with 5 loops. What was the velocity of the waves in the string?
Unit= m/s
Answer:
The velocity of the waves in the string is 30 m/s.
Explanation:
Given;
frequency of the wave, F = 60.0 Hz
number of loops, n = 5
length of the string, L = 1.25 m
1 loop, L = λ/2
For 5 loops;
[tex]L = \frac{5\lambda}{2}[/tex]
where;
λ is the wavelength
[tex]L = \frac{5 \lambda}{2} \\\\5 \lambda = 2L\\\\\lambda = \frac{2L}{5} \\\\\lambda = \frac{2 \ \times \ 1.25}{5} \\\\\lambda = 0.5 \ m[/tex]
The velocity of the waves in the string is calculated as;
V = Fλ
V = (60)(0.5)
V = 30 m/s
Therefore, the velocity of the waves in the string is 30 m/s.
All of the following are changeable
risk factors EXCEPT:
A)Stress
B)Eating habits
C)Heredity
D)Drug use
Answer:
Heredity
Explanation:
Can't change the DNA you inherited the same way you can change eating habits+drug use or avoid stress
Answer:
[tex]\boxed {\boxed {\sf C. \ Heredity}}[/tex]
Explanation:
A risk factor is something that increases the chance of getting a disease. Some are controllable, but some are not.
Stress, eating habits, drug use, exercise, smoking, hygiene, and amount of sleep are all controllable or changeable risk factors. Anybody can change these things in their life.
On the other hand, uncontrollable risk factors, such as age, gender, ethnicity and heredity cannot be changed. Nobody has control over these factors.
So, heredity is the uncontrollable risk factor.
15. A travelling wave is described by the equation y(x,t)= 0.003 cos (20 x + 200t) where y and x are
measured in meters and t in seconds. What is the period of this wave?
Answer:
T = 3.14 10⁻² s
Explanation:
The general equation for a traveling transverse wave is
y = A sin (k x - wt +Ф)
where w is the angular velocity that is related to the period and Ф is the phase of the oscillation
w = 2π / T (1)
In this case they indicate that the expression of the wave
y = 0.003 cos (20 x + 200t)
if we use the relationship of the double angles
a = kx - wt
b = Ф
sin (a + b) = sin a cos b + sin b cos a
for the case Ф = 90 we have
sin (a + b) = cos b
we substitute
y = A cos (kx -wt)
with an initial phase of fi = 90º
if we compare the terms of the two expressions
A = 0.003 m
k = 20 m⁻¹
w = -200 rad/s
the negative sign indicates that the wave goes to the left
if we clear from equation 1
T = 2π / w
T = 2π / 200
T = 3.14 10⁻² s
In a chemical reaction atoms will do what?
Moving a ball up a hill
O A. increases its chemical energy
OB. decreases its chemical energy
O C. increases its potential energy
OD. decreases its potential energy
Answer:
C increase in potential energy
How will you know which dye diffuses the most quickly?
Answer:
If there is a large difference between the concentration of one fluid and the concentration of the other, then the particles will diffuse faster. In the experiment, the dye particles in the food coloring are very concentrated.
Explanation:
A force of 9 N acts on an object for 0.63 seconds.
Answer:
5.67
Explanation:
force is = m x a
which will give us
0.63
x 9
= 5.67
what
must always be
included on the
graph
A force of 22.04 N is applied tangentially to a wheel of radius 0.340 m and gives rise to an angular acceleration of 1.20 rad/s2. What is the moment of inertia of the wheel
Answer:
the moment of inertia of the wheel is is 6.245 kg.m²
Explanation:
Given;
applied force, f = 22.04 N
radius of the wheel, r = 0.34 m
angular acceleration, a = 1.2 rad/s²
The moment of inertia of the wheel is calculated as;
[tex]I = \frac{\tau}{\alpha } \\\\I = \frac{Fr}{\alpha } \\\\I = \frac{22.04 \ \times \ 0.34 }{1.2} \\\\I = 6.245 \ kg.m^2[/tex]
Therefore, the moment of inertia of the wheel is is 6.245 kg.m²
How does a tire of a car interact with the road
Answer:
friction
Explanation:
the road is the pathway for the vehicle so the tures create friction to stay sturdie
An air conditioner removes heat steadily from a house at a rate of 750 kJ/min while drawing electric power at a rate of 5.25 kW. Determine (a) the COP of this air conditioner and (b) the rate of heat transfer to the outside air.
Answer:
[tex]Q'_H=1065kJ/min[/tex]
Explanation:
From the question we are told that
Heat Remove rate Q_o= 750 kJ/min
Power Draw P=5.25
a)Generally the coefficient of performance (COP) of an air conditioner is mathematically given as
[tex]COP=\frac{Q_o}{P}[/tex]
[tex]COP=\frac{750kJ/min}{5.25kw}[/tex]
Where
[tex]750kJ/min=12.5kJ/sec[/tex]
[tex]COP=\frac{12.5kJ/sec}{5.25kw}[/tex]
[tex]COP=2.38[/tex]
b)Generally the equation for power is mathematically represented as
[tex]P=Q_H-Q_o[/tex]
[tex]P+Q_o=Q_H[/tex]
[tex]Q_H=P+Q_o[/tex]
[tex]Q_H=5.25+12.5[/tex]
[tex]Q_H=17.75kW[/tex]
Generally rate of heat transfer to the outside air is mathematically given as
[tex]Q'_H=17.75*60[/tex]
[tex]Q'_H=1065kJ/min[/tex]
The coefficients of friction between the load and the flatbed trailershown are μs = 0.40 and μk = 0.30. Knowing that the speed of the rigis 72 km/h, determine the shortest distance in which the rig can bebrought to a stop if the load is not to shift
Answer:
50.97 m
Explanation:
m = Mass of truck
[tex]\mu_s[/tex] = Coefficient of static friction = 0.4
v = Final velocity = 0
u = Initial velocity = 72 km/h = [tex]\dfrac{72}{3.6}=20\ \text{m/s}[/tex]
s = Displacement
Force applied
[tex]F=ma[/tex]
Frictional force
[tex]f=\mu_s mg[/tex]
Now these forces act opposite to each other so are equal. This is valid for the case when the load does not slide
[tex]ma=\mu_s mg\\\Rightarrow a=\mu_s g\\\Rightarrow a=0.4\times 9.81\\\Rightarrow a=3.924\ \text{m/s}^2[/tex]
Since the obect will be decelerating the acceleration will be [tex]-3.924\ \text{m/s}^2[/tex]
From the kinematic equations we have
[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-20^2}{2\times -3.924}\\\Rightarrow s=50.97\ \text{m}[/tex]
So, the minimum distance at which the car will stop without making the load shift is 50.97 m.
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with a frequency of 41.2 kHz. A car is approaching him at a speed of 33.0 m/s. The wave is reflected by the car and interferes with the emitted sound producing beats. What is the frequency of the beats
Answer:
the frequency of the beats is 8.7687 kHz
Explanation:
Given the data in the question;
The frequency for stationary source and moving observer is;
f' = f( 1 +( v_observer/v_sound))
we know that, speed of sound in dry air = 343 m/s
so we substitute
f' = 41.2 kHz( 1 + (33.0 m/s / 343 m/s) ) = 41.2kHz( 1 + 0.0962) = 41.2kHz(1.0962)
f' = 45.1634 kHz
Now the frequency for stationary observer and moving source with frequency f' will be
f" = f'( 1 / (1 - ( v_observer/v_sound)))
45.1634 kHz( 343 / 343 - 33)
we substitute
f" = 45.1634 kHz( 1 / (1 - (33.0 m/s / 343 m/s)))
f" = 45.1634 kHz( 1 / (1 - 0.0962))
f" = 45.1634 kHz( 1 / 0.9038 )
f" = 45.1634 kHz( 1.1064 )
f" = 49.9687 kHz
Now the beat frequency will be;
f_beat = f' - f
we substitute
f_beat = 49.9687 kHz - 41.2 kHz
f_beat = 8.7687 kHz
Therefore, the frequency of the beats is 8.7687 kHz
Identify the characteristics of an oppressor.
Oppressors have a(n)
attitude toward others. They have a need for
.
Answer:
Oppressors have a repressive attitude toward others. They have a need for power and dominance.
Explanation:
Oppression is the painful experience of deliberate arbitrariness, violence and abuse of power inflicted on an individual, society or group of people. The term repression is often used synonymously for this.
Oppression arises from the general, also unconscious, assumption that a certain group of people is inferior or without rights. Oppression is seldom limited to governmental activities. Individuals can also be victims of oppression if they lack the solidarity of a social group.
Oppressive individuals, in turn, are those who exert repression on others. They are generally narcissistic and megalomaniacal people, who have a wrong self-perception of their virtues and negatively weigh the virtues of other people.
explain how are frequency, wavelength, energy, and penetrating ability of the waves change and differ from one another PLEASE HELP YOU WILL GET 56 POINTS IT HAS TO BE CORRECT PLEASE HELP YOU WILL GET 56 POINT IT HAS TO BE CORRECT
If we compare the energy of visible light to the energy of X-rays, we find that X-rays have a much higher frequency. Usually, electromagnetic radiation with higher frequency (energy) have a higher degree of penetration than those with low frequency.
Consider a runner in lane 1 with a speed v1 and a runner in lane 4 with a speed v4 , where the ratio of the speeds v4/v1 is 2 . The radius of lane 4 is b times the radius of lane 1, and both runners have the same mass. Which of the following claims is correct about the net forces F1 and F4 exerted on the runners in lanes 1 and 4, respectively?
a. F4 is equal to 2/b F1.
b. F4 is equal to 4/b F1.
c. F4 is equal to 2/b^2 F1.
d. F4 is equal to 4/b^2 A F1.
Answer:
[tex]F_4=\frac{4}{b}F_1[/tex]
Explanation:
Centripetal force is the net force acting on a body which makes it move along a curved path. This force is always towards the center of curvature.
The centripetal force is given by:
F = mv² / r
where m is the mass of the body, v is the velocity of the body, r is the radius, F is the centripetal force and v²/r is the centripetal acceleration.
Given that:
[tex]\frac{v_4}{v_1}=2\\\\v_4=2v_1\\\\ Also, radius\ of\ lane\ 4(r_4)=2*radius\ of\ lane\ 1\\\\Let\ r_1\ be\ radius\ of\ lane\ 1,m=mass\ of\ runner\ in\ lane\ 1=mass\ of\ runner\ in\ lane\ 4\ \\and\ v_4=velocity\ of\ runner\ in\ lane\ 4.\ Hence:\\\\r_4=b*r_1=br_1\\\\The\ centripetal\ force\ for\ lane\ 4(F_4)\ is:\\\\F_4=\frac{mv_4^2}{r_4}\\\\ F_4=\frac{m(2v_1)^2}{br_1}\\\\F_4= \frac{4mv_1^2}{br_1} \\\\But\ F_1=\frac{mv_1^2}{r_1}\\\\Hence\ F_4=\frac{4}{b}F_1[/tex]
F4 is equal to 4/b F1. A further explanation is provided below.
According to the question,
[tex]\frac{v_4}{v_1} =2[/tex][tex]\frac{r_4}{r_1} = b[/tex]The net force of the object in uniform circular motion will be:
→ [tex]F = \frac{mv^2}{r}[/tex]
∴ [tex]F_1 = \frac{m_1 v_1^2}{r_1}[/tex]
[tex]F_4 = \frac{m_4 v_4^2}{r_4}[/tex]
Now,
→ [tex]\frac{F_1}{F_4} = \frac{m_1}{m_4}\times (\frac{v_1}{v_4} )^2\times \frac{r_4}{r_1}[/tex]
[tex]\frac{F_1}{F_4} = \frac{1}{4}\times b[/tex]
[tex]F_1 = \frac{b}{4} F_4[/tex]
[tex]F_4 = \frac{4}{b} F_1[/tex]
Thus the above response i.e., "option b" is correct.
Learn more:
https://brainly.com/question/4527006
. Suppose that a positive charge is brought near a neutral, insulating piece of material. Is the positive charge attracted, repelled, or indifferent to the neutral object
Answer:
Positive charge is attracted to the neutral object.
Explanation:
Recall ; Like charges repel, unlike charges attract. This phrase simply means (positive (+) is attracted to negative (-ve) and vuc versa while both positive, positive and negative, negative charge repel.
For a neutral object. The quantity of positive charge equals the quantity of negative charges. This simply means a neutral object contains charges as well, which are usually scattered or randomly aligned.
Therefore, when a positive charge is brought near a neutral body, the order of alignment of the charges change, with the negative charge all moving towards the direction of the positively charged body and the positive charges in the neutral body aligning in the opposite direction.
The charge will be attracted.
Understanding the force between charges.
As you may know, opposite charges attract (and equal charges repel).
So, when you put a positive charge near a neutral material, all the negative charges in the material will move towards the surface of the material closer to the positive charge (and the positive charges in the material will move away).
Now the charge in the material is not homogeneous, so the positive charge will see a negatively charged surface near it, and it will be attracted to that surface.
Thus we can conclude that as a positive charge is brought near a neutral, insulating piece of material, the charge will be attracted towards it.
If you want to learn more about electromagnetic forces, you can read:
https://brainly.com/question/24743340
A car moving at a speed of 36 km/h reaches the foot of a smooth
incline, when the engine is switched off. If the angle of inclination is 30
degrees, how much distance does the automobile travel up the ramp?
Answer:
d = 10.2 m
Explanation:
When the car travels up the inclined plane, its kinetic energy will be used to do the work in climbing up. So according to the law of conservation of energy, we can write that:
[tex]Kinetic\ Energy\ of\ the \ Car = Work\ Done\ while\ moving\ up\ the\ plane\\\frac{1}{2}mv^{2} = Fd[/tex]
where,
m = mass of car
v = speed of car at the start of plane = (36 km/h)(1000 m/1 km)(1 h/3600 s)
v = 10 m/s
F = force on the car in direction of inclination = W Sin θ
W = weight of car = mg
θ = Angle of inclinition = 30°
d = distance covered up the ramp = ?
Therefore,
[tex]\frac{1}{2}mv^{2} = mgdSin\theta\\\frac{1}{2}v^{2} = gdSin\theta\\\frac{1}{2}(10\ m/s)^{2} = d(9.81\ m/s^{2}) Sin\ 30^{0}[/tex]
d = 10.2 m
