if cp=rs 400, loss=10% find sp
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Answer:

Step-by-step explanation:

You want the domain and range of the function y = √(x -7) +1.

The domain is the horizontal extent of the graph. The graph of the given function extends to the right from x=7, which is included in the solution set.

The domain is x ≥ 7.

The range is the vertical extent of the graph. The graph of the given function extends upward from y=1, which is included in the solution set.

The range is y ≥ 1.

Answer: domain: 7

range: 1

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\sf 14\ ft}[/tex]

Step-by-step explanation:

Yard sticks = 4

12-inch rulers = 2

All are placed end to end.

We know that,

1 yard = 3 feet

4 yards = 3 × 4 feet

4 yards = 12 feet

We know that:

1 inch = 0.083 feet

24 inch = 0.083 × 24 feet

24 inch = 2 feet

= 4 yardsticks + 2 12-inch rules

= 12 ft + 2 ft

= 14 ft

[tex]\rule[225]{225}{2}[/tex]

Answer:

72

Step-by-step explanation:

I got it right .......

Answer:

390/1000

This is the answer and hope it helps

Answer:

-38,994

Step-by-step explanation:

-291*134

=-38,994

Answer:

-38,994

Step-by-step explanation:

(-291) × 134

Apply PEMDAS.

Remember,

Solution:

Evaluating,we obtain

Answer:

Step-by-step explanation:

The initial vale is when x = 0

-  That is 75,

The growth factor is 2%.

Answer:

20 L

Step-by-step explanation:

I am guessing that you meant should instead of shouldn't.

To solve this we can set the amount of 10% solution needed equal to x. This means that the 60% solution will be the remaining amount needed, so 50 L - x.

We can do 10%*x+60%*(50-x)=50*40%. Solving for x we get:

0.1*x+0.6*50-0.6*x=50*0.4

0.1*x+30-0.6*x=20

-0.5*x=-10

x=20

The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.

Given a company has 200 machines. Each machine has a 12% probability of not working.

If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.

So

1) probability that 5 would not be working

C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵

                                ≈ 0.18665

2)  probability that at least one machine would be working

0.88⁴⁰ ≈ 0.00602

3) probability that all would be working

1 - 0.12⁴⁰ ≈ 1.0000

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The function in this graph is increasing in the interval   –2 ≤ x ≤ 3 , Option D is the right answer.

A function is a mathematical statement used to relate a dependent and an independent variable.

From the graph it can be seen that the graph is increasing in the interval

–2 ≤ x ≤ 3

The graph is said to be increasing when the value of y is getting more and more positive

As  –2 ≤ x ≤ 3 , y varies from -3 to +3

Therefore Option D is the right answer.

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Answer:

–2 ≤ x ≤ 3

Step-by-step explanation:

The logical conclusion from the statement is that

B. The opposite sides of a rhombus are congruent.

From the information given, if shape is a parallelogram, then opposite angles are congruent.

In this case, since the rhombus is a parallelogram, then the opposite sides of a rhombus are congruent.

In conclusion, the correct option is B.

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Answer:

  (b)  median

Step-by-step explanation:

A box-plot is a graphical representation of the 5-number summary of a data set. It includes the minimum, maximum, median, and 1st and 3rd quartiles.

__

The measure of center shown in a box plot is the median.

The answer will be Rs. 4330.

Step-by-step explanation:

Because if you subtract 340 from 4670, you will get the answer which is 4330.

The slope of the linear function is 3 and the y-intercept is -3 if the linear function contains the following points: (0,-3) and (6,15)

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have:

A linear function contains the following points: (0,-3) and (6,15)

The slope:

[tex]\rm m =\dfrac{15-(-3)}{6-0}[/tex]

m = 18/6

m = 3

The equation of a line:

y = mx + c

Plug x = 0, y = -3

-3 = c

Thus, the slope of the linear function is 3 and the y-intercept is -3 if the linear function contains the following points: (0,-3) and (6,15)

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Answer:

Step-by-step explanation:

the answer should be 5 inches I guess

[tex]\huge\underline\red{Answer -}[/tex]

[tex]\bold{8 \frac{2}{5} }\: \\\\ \implies \: \frac{5 × 8 + 2}{5} \: \\ \\ \implies \: \frac{ 40 + 2}{5} \\\\ \implies \frac{42}{5} \\\\ \rightarrow \:\boxed {reciprocal \: = \frac{5}{42} } \\ \\[/tex]

hope helpful ~

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{8 \dfrac{2}{5}}\\\\\mathsf{= \dfrac{8\times5+2}{5}}\\\\\mathsf{= \dfrac{40 + 2}{5}}\\\\\mathsf{= \dfrac{42}{5}}\\\\\mathsf{=\dfrac{5}{42}}\\\\\huge\text{Therefore, the answer should be: \boxed{\mathsf{\dfrac{5}{42}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

37.5 m

Step-by-step explanation:

Since the trapezoid area formula is ((base 1+base 2)/2)*height, we can plug in the values.

((8+7)/2)*5

(15/2)*5

7.5*5=37.5

Now we add the unit, "m" to get 37.5 m!

Press the Linear Regression button to generate the regression line.

We have given that, regression line using a regression calculator

We have to determine how to graph a scatterplot and its regression line using a regression calculator.

Before entering data into the regression calculator, it is important to determine which variable should be associated with the x-axis and which with the y-axis.

Regression analysis is a set of statistical processes for estimating the relationships between a dependent variable and one or more independent variables.

Enter the data pairs.

Press the Linear Regression button to generate the regression line.

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Answer:

x = 1, -5

Step-by-step explanation:

4(x^2 + 4x - 5) = 0

4(x - 1)(x + 5) = 0

x = 1, -5

The true statements are

-one zero with multiplicity 3

-one zero with multiplicity 4

-one zero with multiplicity 5

-one zero with multiplicity 1 and one zero with multiplicity 2

-one zero with multiplicity 1 and one zero with multiplicity 3

-one zero with multiplicity 2 and two zeros with multiplicity 1

-one zero with multiplicity 2 and three zeros with multiplicity 1

-Two zeros with multiplicity 2

-Two zero with multiplicity 2 and two zeros with multiplicity 1

-Two zero with multiplicity 2 and three zeros with multiplicity 1

-Two zero with multiplicity 1

-Three zeros with multiplicity 1

-Four zeros with multiplicity 1

-Five zeros with multiplicity 1

The function is given as:

f(x)

And it has a degree of 3

This means that

Using the above highlight as a guide, the true statements are (a), (d),and (l)

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Answer:

[tex]sec(\theta)=\frac{2}{\sqrt3}[/tex]

Step-by-step explanation:

Given [tex]sin(\theta)=\frac{1}{2}[/tex] , to find [tex]sec(\theta)[/tex], it will be helpful to visualize a right triangle (triangle with a 90 degree angle) associated with that particular θ.  There are a few ways to go about this:

All of the basic trigonometric functions, applied to an angle) are a ratio of two specific sides of any right triangle that holds that angle.

Remember that the Sine of an angle is defined specifically, the ratio of the opposite side (the side across from the angle in the Sine function), and the hypotenuse (the side across from the right angle).  You might remember this through SohCahToa

[tex]sin(\theta)=\frac{opp}{hyp}[/tex]

In our case, since [tex]sin(\theta)=\frac{1}{2}[/tex] , so  [tex]\frac{opp}{hyp}=\frac{1}{2}[/tex] .  While there are an infinite number of triangles that have that ratio of those sides, they are all "similar" triangles (corresponding angles congruent, and corresponding sides are proportional, yielding common ratios of sides), and for ease, we can consider simply the triangle where the value of the numerator is the length of the opposite side, and the value of the denominator is equal to the hypotenuse.  So, [tex]opp=1[/tex], and [tex]hyp=2[/tex].

While we haven't actually talked about θ yet, we can still set up the triangle that has these sides so that we can visualize what the triangle looks like. (see image)

This triangle represents the triangle for the unknown θ in the original sine function.  We're tasked with finding the secant of that particular unknown θ.

Working toward Secant

Here, it will be helpful to remember either the reciprocal identities for[tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex], or the definition of the secant function [tex]sec(\theta)=\frac{hyp}{adj}[/tex].

I find that most people remember the reciprocal identities more easily than keeping track of the definitions, so, since secant is related to cosine, it will be important to remember that [tex]cos(\theta)=\frac{adj}{hyp}[/tex].  From there, take the reciprocal of the cosine-value to get the secant-value (which matches the definition of the secant function).

Either way, it comes down to knowing the lengths of the side adjacent to theta, and the hypotenuse.  We already know the length of the hypotenuse, so we just need the length of the adjacent side.

Applying the Pythagorean Theorem

Fortunately, because it is a right triangle, the Pythagorean Theorem applies: [tex]a^{2} +b^{2} =c^{2}[/tex]  (where c is the length of the hypotenuse, and a & b are the lengths of the legs)

Substituting the known values for the sides we do know...[tex](adj)^{2} +(1)^{2} =(2)^{2}\\(adj)^{2} +1 =4[/tex]

...isolating "adj" by subtraction...

[tex](adj)^2=4-1\\(adj)^2=3[/tex]

...applying the square root property...

[tex]adj=\sqrt{3}[/tex]  or  [tex]adj=-\sqrt{3}[/tex]

Identifying which Quadrant the triangle is in

Since we were given that [tex]0^o < \theta < 90^o[/tex], our triangle is an acute triangle (as drawn in the diagram), and is in quadrant I (indicating that both legs will be measured with a positive value.

Thus, we discard the negative solution and conclude that [tex]adj=\sqrt{3}[/tex].

Finding the final solution

From there, [tex]cos(\theta)=\frac{adj}{hyp}[/tex] implies [tex]cos(\theta)=\frac{\sqrt3}{2}[/tex], and through the reciprocal relationship (or simply the definition of secant, whichever is easier for you to remember), [tex]sec(\theta)=\frac{2}{\sqrt3}[/tex]

Note:  This method did not require knowing what the angle θ was.

If you know well the values of special triangles in the unit circle, you may have identified that [tex]sin(\theta)=\frac{1}{2}[/tex]  is associated with [tex]\theta=30^o[/tex].  If so, if you also recall that the ordered pair associated with that point on the unit circle is [tex](\frac{\sqrt3}{2} ,\frac{1}{2} )[/tex], and that the [tex]cos(\theta)=x\text{-coordinate on the unit circle}[/tex], then you can quickly identify that  [tex]cos(\theta)=\frac{\sqrt3}{2}[/tex].

This method still ends the same: recalling the reciprocal relationship between cosine and secant, giving [tex]sec(\theta)=\frac{2}{\sqrt3}[/tex].

The union consists of all of the elements that are contained in each interval.

Inequality Form:

x<6

Interval Notation:

(−∞,6)

Using the binomial distribution, it is found that the probabilities are:

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

Exercise 1:

The parameters are:

n = 15, p = 0.4, x = 4.

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{15,4}.(0.4)^{4}.(0.6)^{11} = 0.1228[/tex]

Exercise 2:

The parameters are:

n = 12, p = 0.2, x = 2.

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{12,2}.(0.2)^{2}.(0.8)^{10} = 0.2835[/tex]

Exercise 3:

The parameters are:

n = 20, p = 0.05.

The probability is:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

Using the binomial formula for each value and adding them:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3585 + 0.3774 + 0.1887 + 0.0596 = 0.9841[/tex]

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Answer: 1.25

Step-by-step explanation:

The explicit formula for the sequence is [tex]a_{n}=10(0.5)^{n-1}[/tex]

Substituting in n=4,

[tex]a_{4}=10(0.5)^{4-1}=\boxed{1.25}[/tex]

Answer:

f(1)= 3×1 + 2 = 5

....

.....

....

f(5)= 3×5 + 2 = 17

Answer:

f(5) = 17

Step-by-step explanation:

Given: f(x) = 3x + 2

We are asked to find the value of the function when the value of x is 5

Substitute 5 as the value of x in the function:

⇒ f(x) = 3x + 2

⇒ f(5) = 3(5) + 2 [multiply]

⇒ f(5) = 15 + 2 [add]

⇒ f(5) = 17

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Answer:

125

Step-by-step explanation:

All the work is in picture attat

Answer:

-28x^3-28x^2+16x+15

Step-by-step explanation:-28x^3-28x^2+16x+15