if the distance between two electrons is doubles, what would happen to the electric force between them? group of answer choices the electric force would be weaker depending on the angle between the charges. the electric force would be half as strong. the electric force would be 1/4 as strong. the electric force would be 1/16 as strong.

Answers

Answer 1

If the distance between two electrons is doubled, the electric force between them would be 1/4 as strong. This is because Coulomb's Law states that the electric force between two point charges is inversely proportional to the square of the distance between them.

The electric force between two point charges is inversely proportional to the square of the distance between them, according to Coulomb's Law. Doubling the distance between the charges would result in the force being reduced by a factor of 2² = 4.

Therefore, the electric force between the two electrons would be 1/4 as strong if the distance between them is doubled. It's important to note that this assumes that there are no other charges present that could influence the force.

Additionally, the angle between the charges does not affect the strength of the electric force since Coulomb's Law is a scalar equation that only depends on the distance between the charges.

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Related Questions

The intensity of electromagnetic radiation from the sun reaching the earth's upper atmosphere is 1.37kW/m2
Assuming an average wavelength of 680nm for this radiation, find the number of photons per second that strike a 1.30m2 solar panel directly facing the sun on an orbiting satellite.

Answers

The number of photons per second striking a solar panel facing the sun on an orbiting satellite is approximately 6.65 x 10^21.

How many photons per second strike a solar panel facing the sun on an orbiting satellite?

To find the number of photons per second that strike a 1.30m2 solar panel directly facing the sun on an orbiting satellite, we can use the formula:

Number of photons per second = (power per unit area) / (energy per photon)

The power per unit area of the electromagnetic radiation from the sun reaching the earth's upper atmosphere is given as 1.37 kW/m2.

We can use the following formula to compute the energy per photon:

Energy per photon =

(Planck's constant x speed of light) / (wavelength)

Where Planck's constant (h) is 6.626 x 10^-34 Joule-seconds and the speed of light (c) is 2.998 x 10^8 meters per second.

Substituting the given values, we get:

Energy per photon = (6.626 x 10^-34 Joule-seconds x 2.998 x 10^8 meters per second) / (680 x 10^-9 meters)

= 3.097 x 10^-19 Joules

Now, substituting these values in the formula for the number of photons per second, we get:

Number of photons per second = (1.37 x 10^3 Watts/m2) / (3.097 x 10^-19 Joules/photon) x (1.30 m2)

= 6.65 x 10^21 photons/second

Therefore, approximately 6.65 x 10^21 photons per second strike a 1.30m2 solar panel directly facing the sun on an orbiting satellite.

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given what causes seasons, which of the following planets would have the most drastic temperature and hours of daylight difference between summer season and winter season? group of answer choices mars earth mercury venus uranus

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Uranus would have the most drastic temperature and hours of daylight difference between summer season and winter season.

The seasons on Uranus are caused by its extreme tilt, which is at an angle of 98 degrees compared to its orbit around the sun. This means that one pole of the planet is constantly facing the sun while the other pole is in complete darkness. As Uranus orbits the sun, each pole alternates between facing the sun and facing away from it, causing extreme temperature and daylight differences between the summer and winter seasons. In addition, Uranus has a very long orbital period of 84 Earth years, so each season lasts for approximately 21 Earth years, making the temperature and daylight differences even more extreme. Therefore, Uranus would have the most drastic temperature and hours of daylight difference between summer season and winter season compared to Mars, Earth, Mercury, and Venus.

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A random sample of 30 companies on the Forbes 500 list was selected and the relationship between sales (in hundreds of thousands of dollars) and profits (in hundreds of thousands of dollars) was investigated using regression. A least-squares regression line was fitted to the data using statistical software, with sales as the explanatory variable and profits as the response variable. Assume that the conditions for inference are met. Here is the output from the software: Dependent variable is Profits R-squared - 66.2% 3 - 466.2 with 30 - 2 - 28 degrees of freedom Variable Coefficient s.e. of Coefficient Constant -176.644 61.16 Sales 0.092498 0.0106 P-value 0.0050 50.0001 Which of the following expressions best represents the margin of error of a 95% confidence interval for the slope of the population regression line? 1.701 (0.0106) 0.0106 B 1.96 V30 1.96 (0.0106) 2.048 (0.0106) 2.048 0.0106 30

Answers

The expression that best represents the margin of error of a 95% confidence interval for the slope of the population regression line is 0.0217.

The margin of error of a confidence interval for the slope of the population regression line measures the precision of the estimate and quantifies the uncertainty associated with it. A 95% confidence interval is an interval that, if we were to take many random samples and compute a confidence interval for each sample, approximately 95% of the intervals would contain the true population slope.

The formula for the margin of error of a 95% confidence interval for the slope is:

margin of error = t* (standard error of the slope)

where t* is the critical value from the t-distribution with n-2 degrees of freedom for a 95% confidence interval, and the standard error of the slope is the estimated standard deviation of the sampling distribution of the slope.

From the output of the software, we can see that the standard error of the slope is 0.0106. The critical value t* for a 95% confidence interval with 28 degrees of freedom is approximately 2.048. Therefore, the margin of error is:

margin of error = 2.048 * 0.0106 = 0.0217

So, the expression that best represents the margin of error of a 95% confidence interval for the slope of the population regression line is 0.0217.

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if she hadn't tucked at all, how many revolutions would she have made in the 1.7 s from board to water? express your answer using two significant figures.

Answers

If the diver hadn't tucked at all, she would have made about 1.47 revolutions in the 1.7 seconds from the board to the water.

Without tucking, the diver would have maintained the same initial angular velocity throughout the dive.

We can use the equation:

θ = ω_i[tex]*t + 0.5α*t^2[/tex]

where θ is the angle rotated,

ω_i is the initial angular velocity,

α is the angular acceleration, and

t is the time interval.

Since the diver is not tucking, there is no angular acceleration, so α = 0. We can rearrange the equation to solve for the number of revolutions:

θ = ω_i*t

θ is given as 1.5 revolutions or 3π radians. We can convert the time interval to seconds:

t = 1.7 s

The initial angular velocity can be found using the equation:

ω_i = ω_f - α*t

where ω_f is the final angular velocity, which we assume is zero since the diver enters the water with zero angular velocity.

Thus, ω_i = -α*t.

The angular acceleration can be found using the kinematic equation:

θ = 0.5*(ω_i + ω_f)*t

Substituting in ω_f = 0 and solving for α:

α = 2*θ/[tex]t^2[/tex]

Plugging in the given values, we get:

α =[tex]2*(3\pi )/(1.7 s)^2[/tex]

  = 3.2 rad/[tex]s^2[/tex]

Now we can solve for ω_i:

ω_i = -αt

      = [tex]-(3.2 rad/s^2)(1.7 s)[/tex]

      = -5.44 rad/s

The negative sign indicates that the diver was rotating in the opposite direction to the desired direction (clockwise instead of counterclockwise).

Finally, we can use the equation θ = ω_i*t to find the number of revolutions:

θ = (5.44 rad/s)*(1.7 s)

= 9.25 radians

Number of revolutions = 9.25 radians / (2π radians/revolution) ≈ 1.47 revolutions

Therefore, if the diver hadn't tucked at all, she would have made about 1.47 revolutions in the 1.7 seconds from the board to the water.

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85) What is the net power that a person with surface area of 1.20 m2 radiates if his emissivity is 0.895, his skin temperature is 27°C, and he is in a room that is at a temperature of 17°C? (σ = 5.67 × 10-8 W/m2 ∙ K4)
A) 60.3 W
B) 62.6 W
C) 65.7 W
D) 68.4 W
E) 64.8 W

Answers

The person radiates heat at a rate of 62.6 W.

The net power that a person radiates can be calculated using the formula P = εσA(T_p^4 - T_r^4), where P is the power, ε is the emissivity, σ is the Stefan-Boltzmann constant, A is the surface area, T_p is the temperature of the person's skin, and T_r is the temperature of the room.

Substituting the given values into the formula, we get P = (0.895)(5.67 × 10^-8 W/m^2∙K^4)(1.20 m^2)[(300 K)^4 - (290 K)^4] = 62.6 W. Therefore, the person radiates heat at a rate of 62.6 W. Answer B is correct.

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Identify the three controls on an automobile that allow the car to be accelerated. (Circular Motion and Satellite Motion: Acceleration)

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The three controls on an automobile that allow the car to be accelerated are the gas pedal, the transmission, and the engine.

The gas pedal controls the amount of fuel and air that enters the engine, which increases the power output of the engine. The transmission controls the gear ratio of the car, allowing it to maintain an appropriate speed based on the engine's power output.

The engine converts the fuel and air into mechanical energy, which is transmitted to the wheels through the transmission, resulting in the car's acceleration.

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When air is inhaled into the respiratory system, o2 first enters the.

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When air is inhaled into the respiratory system, it first travels through the nose or mouth and down the trachea, which is also known as the windpipe.

From there, the air passes through the bronchi and into the bronchioles, which are smaller airways that lead to the alveoli, the tiny air sacs within the lungs.

The alveoli are responsible for exchanging gases, which means that they allow oxygen to enter the bloodstream and remove carbon dioxide from it.



Once the air reaches the alveoli, oxygen molecules diffuse through their thin walls and into the surrounding capillaries, which are small blood vessels.

This process is known as gas exchange and is crucial for delivering oxygen to the body's tissues and organs.

The oxygen molecules bind to hemoglobin in the red blood cells and are transported throughout the body, while carbon dioxide is carried back to the lungs to be exhaled.



In summary, when air is inhaled into the respiratory system, oxygen first enters the alveoli in the lungs where it undergoes gas exchange before being transported throughout the body via the bloodstream.

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If the mass of the Earth were doubled (while keeping its size the same), how much more would you weigh at the surface?
You would weigh half as much.
You would weigh the same.
You would weigh four times as much.
You would weigh twice as much.

Answers

You would weigh twice as much. Doubling the mass of the Earth would double your weight since your weight is related to the gravitational force between you and the Earth.

What is gravitational force?

Gravitational force is an attractive force that exists between two objects that have mass. It is the force of attraction between any two objects with mass, and is typically described by Isaac Newton's law of universal gravitation. Newton's law states that the force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. This force is responsible for the attraction of all matter, and is what binds the planets and stars in our universe. It is also responsible for the formation of galaxies, and the movement of the planets in our solar system.

The gravitational force is proportional to the masses of both objects and inversely proportional to the square of the distance between them. Since the distance is the same, doubling the mass of the Earth would double your weight.

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during a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from the wall. if the time the ball was in contact with the wall was 160 ms, what was the magnitude of the average force applied to the ball? question 13 options:

Answers

The magnitude of the average force applied to the ball can be calculated using the equation for impulse, which is equal to the change in momentum. l is 1.6 kgm/s / 0.160 s = 10.0 N. This equation is given by:

What is momentum?

Momentum is a concept in physics that describes the tendency of a body in motion to stay in motion. It is the product of an object’s mass and velocity, and is often represented as a vector quantity. Momentum is conserved in closed systems, meaning that an object’s momentum cannot be created or destroyed, only changed by an outside force.

Impulse = Δp = m * Δv

where m is the mass of the ball and Δv is the change in velocity.

In this case, m = 0.200 kg and Δv = 20.0 m/s - 12.0 m/s = 8.0 m/s.

Therefore, the impulse is equal to 0.200 kg * 8.0 m/s = 1.6 kgm/s.

The average force is equal to the impulse divided by the duration of the collision, which is 160 ms.

Therefore, the magnitude of the average force applied to the ball is 1.6 kgm/s / 0.160 s = 10.0 N.

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Each member of a family of six owns a computer rated at 500 watts in a 120 V circuit. If all computers are plugged into a single circuit protected by a 20 ampere fuse, what is the maximum number of the computers can be operating at the same time?
A) 2
B) 3
C) 4
D) 5 or more

Answers

First, we need to calculate the total power being used by the computers:
6 computers x 500 watts/computer = 3000 watts

Next, we need to calculate the current (in amperes) that this amount of power would draw:
P = VI
3000 watts = 120V x I
I = 25 amperes

Since the circuit is protected by a 20 ampere fuse, we cannot have all 6 computers operating at the same time. To determine the maximum number of computers that can be operating at the same time, we need to divide the total current draw by the maximum current allowed:
20 amps ÷ 25 amps/computer = 0.8 computers

Since we cannot have a fraction of a computer operating, the maximum number of computers that can be operating at the same time is 0. Therefore, the answer is A) 2.

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when light of wavelength 450 nm is incident on potassium, photoelectrons with stopping potential of 0.52 v are emitted. If the wavelength of the incident light is changed to 300 nm, the stopping potential is 1.90 V. Using only these numbers together with the values of the speed of light and the electron charge, find the work function of potassium and compute a value for Planck's constant.

Answers

The average of these two values is 6.12 x 10-34 Js, which is the value of Planck's constant.

What is average?

Average is a term used to describe a value or set of values that is typical or representative of a group of values. It is a measure of central tendency and is calculated by adding all the values in a set and then dividing by the number of values in the set. Average values can provide an overall picture of a data set, helping to identify trends and outliers.

For 450 nm: Work Function (W) = 0.52 V x 1.602 x 10-19 C = 8.25 x 10-19 J
For 300 nm: Work Function (W) = 1.90 V x 1.602 x 10-19 C = 3.02 x 10-18 J
f = c/λ
Using these equations, we can calculate a value for Planck's constant for each wavelength of light:
For 450 nm: h = E/f = 8.25 x 10-19 J/(3.00 x 108 m/s/0.45 x 10-9 m) = 6.17 x 10-34 Js
For 300 nm: h = E/f = 3.02 x 10-18 J/(3.00 x 108 m/s/0.30 x 10-9 m) = 6.07 x 10-34 Js
The average of these two values is 6.12 x 10-34 Js, which is the value of Planck's constant.

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which of the following ionic compounds has the largest lattice energy (i.e., the lattice energy most favorable to a stable lattice)? question 8 options: 1) bao 2) beo 3) csi 4) nabr 5) bas

Answers

The compound with the largest lattice energy is the one that has the greatest charge on its constituent ions and the smallest ionic radius. Among the given options, BaO has the largest lattice energy as it has a 2+ cation (Ba) and a 2- anion (O) with small ionic radii, resulting in a strong electrostatic attraction between the ions in the lattice. Thus, the correct answer is option 1) BaO.

To determine which of the following ionic compounds has the largest lattice energy, we need to consider their ionic charges and sizes. The options are:

1) BaO
2) BeO
3) CsI
4) NaBr
5) BaS

Lattice energy is directly proportional to the product of the charges and inversely proportional to the distance between ions. Larger charges and smaller distances result in more favorable lattice energy.

1) BaO: Ba²⁺ and O²⁻ - Higher charges, but Ba is larger in size
2) BeO: Be²⁺ and O²⁻ - Higher charges, and Be is smaller in size
3) CsI: Cs⁺ and I⁻ - Lower charges, and both Cs and I are larger in size
4) NaBr: Na⁺ and Br⁻ - Lower charges, and both Na and Br are smaller in size compared to CsI
5) BaS: Ba²⁺ and S²⁻ - Higher charges, but Ba is larger in size

Comparing the options, BeO (option 2) has the largest lattice energy due to its higher ionic charges and smaller ionic size compared to the other compounds.

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Laser Surgery Each pulse produced by an argon-fluoride excimer laser used in PRK and LASIK ophthalmic surgery lasts only 10. 0 ns but delivers an energy of 2. 50 mJ.

part a: What is the power produced during each pulse?

part b: If the beam has a diameter of 0. 850 mm, what is the average intensity of the beam during each pulse?

part c: If the laser emits 55 pulses per second, what is the average power it generates?

Answers

Laser Surgery Each pulse produced by an argon-fluoride excimer laser used in PRK and LASIK ophthalmic surgery lasts only 10. 0 ns but delivers an energy of 2. 50 mJ.

Part a The power produced during each pulse is 0.25 W.

Part b The average intensity of the beam during each pulse is 441 kW/ [tex]mm^{2}[/tex].

Part c The average power generated by the laser is 13.75 W.

Part a

Power = Energy / Time

Power = 2.50 mJ / (10.0 ns) = 0.25 W

Therefore, the power produced during each pulse is 0.25 W.

Part b

Average Intensity = Power / Area

Area = π[tex](d/2)^{2}[/tex] = 0.566 [tex]mm^{2}[/tex]

Average Intensity = 0.25 W / 0.566 mm^2 = 441 kW/ [tex]mm^{2}[/tex]

Therefore, the average intensity of the beam during each pulse is 441 kW/ [tex]mm^{2}[/tex].

Part c

Average Power = Power per Pulse x Frequency

Power per Pulse = 0.25 W

Frequency = 55 pulses/s

Average Power = 0.25 W x 55 pulses/s = 13.75 W

Therefore, the average power generated by the laser is 13.75 W.

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FILL IN THE BLANK. A wave is transporting energy from left to right. The particles of the medium are moving back and forth in a leftward and rightward direction. This type of wave is known as a ____.
a. mechanical
b. electromagnetic
c. transverse
d. longitudinal

Answers

The correct answer is option c  transverse

A wave is transporting energy from left to right. The particles of the medium are moving back and forth in a leftward and rightward direction.

Energy transport means moving energy from one location to another. Energy transfer means moving energy out of something (solid, liquid or gas) thereby reducing its energy, into something else (another solid, liquid or gas) thereby increasing its energy. The two mechanisms of energy transfer are heat and work.

Active transport requires energy for the process by transporting molecules against a concentration or electrochemical gradient

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suppose a 2.2 t field is applied across a 10-gauge copper wire (2.588 mm in diameter) carrying a 18 a current.

Answers

The 2.2 t field applied across a 10-gauge copper wire carrying an 18 A current would result in a force of approximately 400 N.

This is because the magnetic field interacts with the electric current in the wire, creating a force known as the Lorentz force. The force is perpendicular to both the direction of the current and the direction of the magnetic field.

The Lorentz force is a fundamental concept in electromagnetism and is used in many applications, including electric motors and generators. It is also important in understanding the behavior of charged particles in magnetic fields, such as in the study of plasma physics.

The size of the force depends on the strength of the magnetic field, the amount of current in the wire, and the geometry of the wire. In this case, the 2.588 mm diameter of the copper wire is an important factor in determining the force experienced by the wire.

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a 3 kg wooden block slides 5m down a wooden incline at constant velocity .calculate increase in system thermal energy g

Answers

To calculate the increase in system thermal energy for a 3 kg wooden block sliding 5m down a wooden incline at constant velocity, follow these steps:

1. Determine the angle of the incline:

Unfortunately, the angle of the incline is not provided in the question. Let's assume the angle is θ.

2. Calculate the gravitational force acting on the block:

The gravitational force (Fg) can be calculated using the formula

Fg = m * g,

where

m is the mass of the block (3 kg) and

g is the acceleration due to gravity (9.8 m/s²).

So, Fg = 3 kg * 9.8 m/s²

           = 29.4 N.

3. Calculate the component of the gravitational force acting parallel to the incline:

The parallel component of the gravitational force (F_parallel) can be calculated using the formula F_parallel = Fg * sin(θ).



4. Determine the work done by the parallel component of the gravitational force:

The work done (W) can be calculated using the formula

W = F_parallel * d,

where

d is the distance the block slides down the incline (5m).



5. Calculate the increase in system thermal energy:

Since the block is sliding at constant velocity, the work done by the parallel component of the gravitational force is equal to the increase in system thermal energy. So, ΔE_thermal = W.



To find the exact value for the increase in system thermal energy, the angle of the incline (θ) is needed.

However, based on the information provided and the steps outlined above, you can calculate the increase in system thermal energy once the angle is known.

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a 1.60 m-long steel piano wire has a diameter of 0.20 cm. how great is the tension in the wire if it stretches 0.25 cm when tightened

Answers

To calculate the tension in the steel piano wire, we can use the formula: Tension = (Force / Area)
First, we need to calculate the cross-sectional area of the wire: Area = πr^ Area = π(0.1 cm)^ Area = 0.0314 cm^2
Next, we can calculate the force exerted on the wire when it stretches by 0.25 cm:

Force = kx where k is the spring constant and x is the displacement from the equilibrium position. For a steel wire, the spring constant is approximately 2 x 10^11 N/m. Displacement (x) = 0.25 cm = 0.0025 m Force = (2 x 10^11 N/m) x (0.0025 m) Force = 5 x 10^8 N Finally, we can substitute these values into the tension formula: Tension = (Force / Area Tension = (5 x 10^8 N) / (0.0314 cm^2) Tension = 1.59 x 10^11 N/m^2 Therefore, the tension in the steel piano wire is approximately 1.59 x 10^11 N/m^2. 1. Calculate the cross-sectional area (A) of the wire using the formula A = π * (d/2)^2, where d is the diameter. In this case, d = 0.20 cm.


A = π * (0.20/2)^2 ≈ 0.0314 cm²  Convert the wire length (L) and stretch (ΔL) to meters. L = 1.60 m, ΔL = 0.25 cm = 0.0025 m Calculate the strain (ε) using the formula ε = ΔL / L. ε = 0.0025 / 1.60 ≈ 0.001562  Use the Young's modulus (Y) for steel, which is approximately 200 GPa (200 × 10^9 Pa) Calculate the stress (σ) using the formula σ = Y * ε.
σ = (200 × 10^9) * 0.0015625 ≈ 312500000 Pa . Finally, calculate the tension (T) in the wire using the formula T = σ *
Convert A to square meters: A = 0.0314 cm² = 3.14 × 10^(-6) m² T = 312500000 * (3.14 × 10^(-6)) ≈ 981.25  The tension in the 1.60 m-long steel piano wire with a diameter of 0.20 cm, which stretches 0.25 cm when tightened, is approximately 981.25 N.

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Therefore, the tension in the piano wire is 1.23 x 10⁻⁸ N.

The tension in the piano wire can be calculated using Hooke's law, which states that the force exerted by a spring or elastic material is proportional to the amount of deformation it undergoes. The equation for Hooke's law is:

F = kx

where F is the force, k is the spring constant, and x is the amount of deformation.

For the piano wire, the deformation is given as 0.25 cm, or 0.0025 m. We can calculate the spring constant using the equation:

k = (πd²/4) / L

where d is the diameter of the wire, and L is the length of the wire. Substituting the given values, we get:

k = (π x 0.002²/4) / 1.6

k = 4.91 x 10⁻⁶ N/m

Now, we can calculate the tension in the wire using Hooke's law:

F = kx

F = (4.91 x 10⁻⁶ N/m) x 0.0025 m

F = 1.23 x 10⁻⁸ N

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as a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. calculate the pressure exerted on the floor by the heel if it has an area of 1.50 cm2 and the woman's mass is 65.0 kg. express the pressure in kpa.

Answers

The pressure exerted on the floor by the heel of the woman's high-heeled shoe is approximately 4251 kPa.

To calculate the pressure exerted on the floor by the heel of the woman's high-heeled shoe, we can use the formula:

pressure = force / area

First, we need to calculate the force exerted by the woman's heel on the floor. We know that her mass is 65.0 kg and that her entire weight is momentarily placed on one heel, so we can calculate the force as:

force = mass x acceleration due to gravity
force = 65.0 kg x 9.81 m/s
force = 637.65 N

Now that we have the force, we can calculate the pressure by dividing the force by the area of the heel:

pressure = force / area
pressure = 637.65 N / 1.50 cm²

We need to convert the area from cm² to m²:

1 cm² = 0.0001 m²
1.50 cm² = 0.00015 m²

pressure = 637.65 N / 0.00015 m²
pressure = 4,251,000 Pa

Finally, we can convert the pressure from Pa to kPa:

1 kPa = 1000 Pa

pressure = 4,251,000 Pa / 1000
pressure = 4251 kPa

Therefore, the pressure exerted on the floor by the heel of the woman's high-heeled shoe is approximately 4251 kPa.

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When there is a steady current in the circuit, the amount of charge passing a point per unit of time is:
A) The same everywhere in the circuit
B) Greater in the 1 ohm resistor than the 2 ohm resistor
C) Greater at point X than at point Y
D) Greater in the 2 ohm resistor than in the 3 ohm resistor

Answers

When there is a steady current in the circuit, the amount of charge passing a point per unit of time is the same everywhere in the circuit.

According to Ohm's law, the current flowing through a conductor is directly proportional to the potential difference (voltage) applied across it and inversely proportional to its resistance. In a series circuit, the current is constant throughout because the resistance is the same everywhere. Therefore, the amount of charge passing a point per unit of time is also constant and it is not affected by the value of the resistance..

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the expansion of the universe means that a. as time goes by, space itself expands carrying the galaxies along with it. b. galaxies that is further away is moving faster away from the earth, since earth is at the center. c. as time goes by, galaxies move away from each other through empty space. d. each object in the universe expands its size.

Answers

The expansion of the universe means that as time goes by, space itself expands carrying the galaxies along with it.

The expansion of the universe refers to the phenomenon where the distances between galaxies are increasing over time. This means that the universe is expanding, and the galaxies are moving away from each other. It is important to note that it is not the galaxies themselves that are moving, but the space between them that is expanding. This is known as the metric expansion of space.

Therefore, the correct answer to the question is option A: as time goes by, space itself expands carrying the galaxies along with it.

Option B is incorrect because the Earth is not at the centre of the universe, and option C is partially correct but does not fully capture the nature of the expansion. Option D is also incorrect as objects in the universe do not expand in size due to the expansion of the universe.

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14) The absolute temperature of a gas is T. In order to double the rms speed of its molecules, what should be the new absolute temperature?
A) 4T
B) 2T
C) T
D) 8T
E) 16T

Answers

In order to double the RMS speed of its molecules, the new absolute temperature is: 4T. The correct option is (E).

What is Absolute temperature?

Absolute temperature is a measure of the average kinetic energy of the particles in a system, usually a gas. It is measured in kelvin (K) and is based on the theoretical concept of absolute zero, which is the temperature at which all thermal motion ceases.

The new absolute temperature to double the RMS speed of molecules can be calculated using the root-mean-square speed formula: v_rms = √(3kT/m)

where v_rms is the root-mean-square speed, k is the Boltzmann constant, T is the absolute temperature, and m is the mass of a molecule.

If we want to double the RMS speed, we need to multiply it by 2. Therefore, the new root-mean-square speed becomes: 2v_rms = √(3kT₂/m)

Squaring both sides, we get:

(2v_rms)² = 3kT₂/m

4(v_rms)² = 3kT₂/m

Substituting v_rms² = 3kT/m, we get:

4(3kT/m) = 3kT₂/m

12kT/m = 3kT₂/m

T₂ = 4T

Therefore, the new absolute temperature required to double the RMS speed of molecules is 4T, which is option (E).

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Complete question:

The absolute temperature of a gas is T. In order to double the rms speed of its molecules, what should

be the new absolute temperature?

(A) 16T

(B) 8T

(C) 2T

(D) √2T

(E) 4T

23) If you add 700 kJ of heat to 700 g of water originally at 70.0°C, how much water is left in the container? The latent heat of vaporization of water is 22.6 × J/kg, and its specific heat capacity is 4186 J/kg ∙ K.
A) 429 g
B) 258 g
C) 340 g
D) 600 g
E) none

Answers

The mass of water remaining in the container is 669.03 g, so the mass of water that has evaporated is 30.97 g. Therefore, the answer is A) 429 g.

First, we need to calculate the initial energy (Q) of the water:

Q = m * c * ΔT

Where m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Q = (700 g) * (4186 J/kg ∙ K) * (70.0°C - 25.0°C)

Q = 166.22 kJ

The heat added to the water (q) is 700 kJ. Since the heat added is greater than the initial energy of the water, some of the water will evaporate. We can calculate the amount of water that has evaporated using the following equation:

q = m * Lv

Where Lv is the latent heat of the vaporization of water.

m = q / Lv

m = (700 kJ) / (22.6 × 10^3 J/kg)

m = 30.97 g

Therefore, the mass of water that has evaporated is 30.97 g. The mass of water remaining in the container is:

m = m_initial - m_evaporated

m = 700 g - 30.97 g

m = 669.03 g

So, the answer is A) 429 g.

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Which describes the amplitude of a wave when it carries more energy?.

Answers

The amplitude of a wave increases when it carries more energy.

The amplitude of a wave when it carries more energy can be described as "larger" or "higher."

A larger or higher amplitude means that the wave has more energy. In simple terms, amplitude refers to the maximum displacement of a wave from its equilibrium position, and higher amplitude waves have a greater intensity or power. This can be observed in various types of waves such as sound waves, electromagnetic waves, or mechanical waves. When the amplitude increases, the energy of the wave also increases, which is directly related to the amount of work done to produce the wave.

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19) A 200-L electric water heater uses 2.0 kW. Assuming no heat loss, how many hours would it take to heat the water in this tank from 23°C to 75°C? The specific heat of water is 4186 J/kg ∙ K and its density is 1000 kg/m3.
A) 5.0. hours
B) 6.0 hours
C) 7.0 hours
D) 8.0 hours

Answers

B) The water tank contains 200 kg of water. It requires 4.35 x 10^7 J of energy to heat the water from 23°C to 75°C. With a 2 kW electric water heater, it will take approximately 6.0 hours to heat the water.

First, we need to calculate the mass of water in the tank:

mass = volume * density

[tex]mass = 200 L * 1000 kg/m^3[/tex]

mass = 200 kg

Next, we can calculate the energy required to heat the water:

[tex]Q = m * c * ΔT[/tex]

Where m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

ΔT = 75°C - 23°C

ΔT = 52°C

Q = (200 kg) * (4186 J/kg ∙ K) * (52°C)

[tex]Q = 4.348 × 10^7 J[/tex]

We can now calculate the time required to heat the water using the power of the electric water heater:

P = Q / t

Where P is the power, Q is the energy required to heat the water, and t is the time.

t = Q / P

[tex]t = (4.348 × 10^7 J) / (2.0 × 10^3 W)[/tex]

t = 21740 s

t = 6.04 hours (rounded to two decimal places)

Therefore, the answer is B) 6.0 hours.

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calculate the pressure in pascals exerted on a tabletop by a cube of iron that is 1.50 centimeters on each side and has a mass of 26.6 grams.

Answers

The pressure in pascals exerted on a tabletop by a cube of iron that is 1.50 centimeters on each side and has a mass of 26.6 grams then the pressure exerted on the tabletop by the iron cube is 1,159,555.56 pascals.

To calculate the pressure in pascals exerted on a tabletop by the iron cube, we need to use the formula: Pressure = Force/Area. The force is equal to the weight of the cube, which can be calculated as mass times gravitational acceleration (9.8 m/s^2).
First, we need to convert the dimensions of the cube from centimeters to meters, so each side is 0.015 meters. The volume of the cube is then 0.015^3 = 3.375 x 10^-6 cubic meters.
Next, we can calculate the density of iron, which is 7,870 kg/m^3. Using the formula density = mass/volume, we can convert the mass of the cube from grams to kilograms: 26.6 grams = 0.0266 kilograms.
The weight of the cube is then: weight = mass x gravity = 0.0266 x 9.8 = 0.26068 newtons.
Finally, we can calculate the pressure exerted on the tabletop by the cube: Pressure = Force/Area. The area of the bottom of the cube is equal to the length times width, which is (0.015 m)^2 = 2.25 x 10^-4 square meters.
Therefore, Pressure = 0.26068/2.25 x 10^-4 = 1,159,555.56 pascals.
So the pressure exerted on the tabletop by the iron cube is 1,159,555.56 pascals.

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antenna area with effective waevlength of 10^4 earth radii. what is the frequency of teh radiations emitted?

Answers

The frequency of the radiations emitted is approximately 3 kHz. To determine the frequency of the radiations emitted by an antenna with an effective wavelength of 10^4 Earth radii, we can use the formula:

Frequency (f) = Speed of Light (c) / Wavelength (λ)

The Earth's radius is approximately 6,371 kilometers. So, the effective wavelength (λ) is:

λ = 10^4 Earth radii * 6,371 km = 63,710,000 km

To find the frequency, we will need to convert the wavelength to meters:

λ = 63,710,000 km * 1,000 m/km = 63,710,000,000 m

Now, we can find the frequency:

f = c / λ
f = 299,792,458 m/s / 63,710,000,000 m = 0.004708 Hz ≈ 3 kHz

Therefore, the antenna's effective wavelength is given as 10^4 Earth radii, which translates to 63,710,000 km. By using the formula f = c/λ, we can calculate the frequency of the radiations emitted by the antenna to be approximately 3 kHz.

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Air is saturated when
A ) Its relative humidity is 100% B ) It contains minimum amount of moisture possible at that temperature C ) Its relative humidity is 0%

Answers

A) Its relative humidity is 100% - This is the correct option. When air is saturated, its relative humidity is at 100%, which means that it contains the maximum amount of moisture possible at that temperature.

What is humidity?

Humidity is the amount of water vapor in the air. It is an important physical property of the atmosphere and is related to the temperature and pressure of the air. It is typically expressed as a percentage of the maximum amount of water vapor that can be held in the air at a given temperature. High humidity can cause discomfort, making it difficult to cool off, while low humidity can cause dry skin and other health issues. Humidity also affects the rate of evaporation and can affect weather patterns.

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Complete Question:
Air is saturated when  _______________

A ) Its relative humidity is 100%

B ) It contains minimum amount of moisture possible at that temperature

C ) Its relative humidity is 0%

D) None of these

83) How much power does a sphere with a radius of 10 cm radiate into empty space if is has an emissivity of 1.0 and is kept at a temperature of 400 K? (σ = 5.67 × 10-8 W/m2 ∙ K4)
A) 60 W
B) 70 W
C) 180 W
D) 210 W
E) 360 W

Answers

The power radiated by a sphere into empty space can be calculated using the Stefan-Boltzmann law, which states that the power radiated is proportional to the fourth power of the temperature and the surface area of the object and is given by:

Power = emissivity x Stefan-Boltzmann constant x surface area x temperature^4

Here, the sphere has a radius of 10 cm, so its surface area can be calculated as:

Surface area = 4 x π x radius^2 = 4 x π x (0.1 m)^2 = 0.04π m^2

Substituting the given values into the equation and solving for power, we get:

Power = 1.0 x 5.67 x 10^-8 x 0.04π x (400 K)^4 = 69.98 W

Therefore, the power radiated by the sphere is approximately 70 W, which is option B.

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Sunlight is used in a double-slit interference experiment. The fourth-order maximum for a wavelength of 500 nm occurs at an angle of ? = 90°. Thus, it is on the verge of being eliminated from the pattern because ? cannot exceed 90° in Eq. 35-14. (a) What least wavelength in the visible range (400 nm to 700 nm) are not present in the third-order maxima? To eliminate all of the visible light in the fourth-order maximum, (b) should the slit separation be increased (show 1) or decreased (show 0) and (c) what least change in separation is needed?

Answers

The least wavelength in the visible range that are not present in the third-order maxima is 400 nm. The slit separation be Decreased. Least change in separation needed is 0.001 mm

The answer for a . The least wavelength in the visible range that are not present in the third-order maxima is 400 nm. This is because the fourth-order maximum occurs at an angle of 90°, and so the third-order maximum will be eliminated at 400 nm.

The answer for B. To eliminate all of the visible light in the fourth-order maximum, the slit separation should be decreased (show 0).

The answer for C. A decrease in the slit separation of 0.001 mm would result in an increase in the angle of the fourth-order maximum to 90.1°, eliminating all visible light.. This is because the angular separation of the diffraction maxima is equal to the wavelength divided by the slit separation. Thus, a decrease in the slit separation of 0.1 mm would result in an increase in the angle of the fourth-order maximum to 90.1°, eliminating all visible light.

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a merry-go-round starts from rest and accelerates at a constant rate of 0.4 rev/s2.note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.what is its rotational velocity after 6 s?the rotational velocity of the merry-go-round is 7.2 numeric responseedit unavailable. 7.2 incorrect.rev/s.

Answers

Answer: The angular acceleration of the merry-go-round is 0.4 rev/s^2. We can use the following equation to find the final angular velocity:

ω_f = ω_i + αt

where ω_f is the final angular velocity, ω_i is the initial angular velocity (which is zero in this case), α is the angular acceleration, and t is the time.

Substituting the given values, we get:

ω_f = 0 + (0.4 rev/s^2)(6 s)

ω_f = 2.4 rev/s

Therefore, the rotational velocity of the merry-go-round after 6 s is 2.4 rev/s.

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