If the line segment AB is on a number line, and point A is at 6 and Point B is at 13, then the length of AB is ____.

The standard deviation is a measure of a collection of values' variance or dispersion. The correct option is B.

The standard deviation is a measure of a collection of values' variance or dispersion. A low standard deviation implies that the values are close to the set's mean, whereas a high standard deviation shows that the values are spread out over a larger range.

For the last summer,

Mean = (140 + 220 + 190 + 180 + 190) / 5 = 920/5 = 184

[tex]\sigma={\sqrt {\dfrac{(140-184)^2+ (220-184)^2+(190-184)^2+(180-184)^2+(190-184)^2}{5}}}\\\\\sigma = 25.7682[/tex]

For this summer,

Mean = (150 + 170 + 150 + 190 + 180) / 5 = 840/5 = 168

[tex]\sigma={\sqrt {\dfrac{(150-168)^2+ (170-168)^2+(150-168)^2+(190-168)^2+(180-168)^2}{5}}}\\\\\sigma = 16[/tex]

Hence, The number of pages in each book varied more last summer than this summer. Thus, the correct option is B.

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Answer:

y=-x^2-4x-1

Step-by-step explanation:

when it is an arch like an upside down U then its

-x^2

it passes through the y axis at -1

its vertex or high point is -2,3 so its

-4x

Answer:

See below

Step-by-step explanation:

Dome shaped parabola      so   'a'  is negative

'c' is determined where x = 0

    this value is -1

Axis of symmetry is the x value of the vertex (which is the high point of the dome)

   x = -2

Answer:

6 and 4

Step-by-step explanation:

Let one number be x.

Then another will be : 4x - 20

In accordance with the question;

x + 4x - 20 = 10

5x = 10 + 20

x = 30/5

= 6

x = 6

4x - 20 = 4×6 - 20 = 4

So, the numbers are 6 and 4.

Were you not given a diagram?

Answer:

please help me find em ah and I will be able to do what I can

Another way to write the equation is 7x + 54 = 0

Given the equation;

[tex]\frac{7}{8}x + \frac{3}{4} = -6[/tex]

Find the LCM on the left side, which is 8

[tex]\frac{7x + 6}{8} = -6[/tex]

Cross multiply

[tex]7x + 6 = -6[/tex] × [tex]8[/tex]

[tex]7x + 6 = -48[/tex]

Collect like terms

[tex]7x = -48 - 6[/tex]

[tex]7x = -54[/tex]

Take all to one side

[tex]7x + 54 = 0[/tex]

Thus, another way to write the equation is 7x + 54 = 0

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Answer:

please mark me brainlist

Step-by-step explanation:

i need it

Answer:

3^1 multiplied by 3^2 = 3^(1 + 2) = 3^3

162

Simplify ——————

(2•3^3)

Canceling out 2 as it appears on both sides of the fraction line

3^4 divided by 3^3 = 3^(4 - 3) = 3^1 = 3

Step-by-step explanation:

hope this helps you ♡

Answer:  Choice D)  All rhombuses are squares

=============================================================

Explanation:

Let's go through the answer choices to see which are true and which are false.

Check out the venn diagram below showing the connection between the geometric shapes mentioned. The large outer rectangle represents the set of all quadrilaterals. Inside this is the oval representing all parallelograms. Then inside the oval is the set of rectangles and the set of rhombuses. The overlapping region of the rectangles and rhombuses is the set of squares, marked in blue.

As you can see, picking any square will get us a rhombus and a rectangle automatically. However, picking any rhombus will not guarantee it's a square.

Answer:

[tex]31[/tex]

Step-by-step explanation:

It's 31 degrees, I hope it is the right answer

Step-by-step explanation:

(4²-x²)³/²

or,(4+X) (4-X)

Substitute [tex]x = 4 \sin(y)[/tex], so that [tex]dx = 4\cos(y)\,dy[/tex]. Part of the integrand reduces to

[tex]16 - x^2 = 16 - (4\sin(y))^2 = 16 - 16 \sin^2(y) = 16 (1 - \sin^2(y)) = 16 \cos^2(y)[/tex]

Note that we want this substitution to be reversible, so we tacitly assume [tex]-\frac\pi2\le y\le \frac\pi2[/tex]. Then [tex]\cos(y)\ge0[/tex], and

[tex](16-x^2)^{3/2} = 16^{3/2} \left(\cos^2(y)\right)^{3/2} = 64 |\cos(y)|^3 = 64 \cos^3(y)[/tex]

(since [tex]\sqrt{x^2} = |x|[/tex] for all real [tex]x[/tex])

So, the integral we want transforms to

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 64 \int \cos^3(y) \times 4\cos(y) \, dy = 256 \int \cos^4(y) \, dy[/tex]

Expand the integrand using the identity

[tex]\cos^2(x) = \dfrac{1+\cos(2x)}2[/tex]

to write

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 256 \int \left(\frac{1 + \cos(2y)}2\right)^2 \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \cos^2(2y)) \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \frac{1 + \cos(4y)}2\right) \, dy \\\\ = 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy[/tex]

Now integrate to get

[tex]\displaystyle 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy = 32 \left(3y + 2 \sin(2y) + \frac14 \sin(4y)\right) + C \\\\ = 96 y + 64 \sin(2y) + 8 \sin(4y) + C[/tex]

Recall the double angle identity,

[tex]\sin(2y) = 2 \sin(y) \cos(y)[/tex]

[tex]\implies \sin(4y) = 2 \sin(2y) \cos(2y) = 4 \sin(y) \cos(y) (\cos^2(y) - \sin^2(y))[/tex]

By the Pythagorean identity,

[tex]\cos(y) = \sqrt{1 - \sin^2(y)} = \sqrt{1 - \dfrac{x^2}{16}} = \dfrac{\sqrt{16-x^2}}4[/tex]

Finally, put the result back in terms of [tex]x[/tex].

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 128 \frac x4 \frac{\sqrt{16-x^2}}4 + 32 \frac x4 \frac{\sqrt{16-x^2}}4 \left(\frac{16-x^2}{16} - \frac{x^2}{16}\right) + C \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 8 x \sqrt{16 - x^2} + \frac14 x \sqrt{16 - x^2} (8 - x^2) + C \\\\ = \boxed{96 \sin^{-1}\left(\frac x4\right) + \frac14 x \sqrt{16 - x^2} \left(40 - x^2\right) + C}[/tex]

Answer:

Step-by-step explanation:

a cuboid has length 18.5 cm, width 9.4 cm a height 6.2 cm. Work out the area of the cuboid​

assuming you are looking for thr surface area

Surface Area of a Cuboid ·

TSA = 2 (lw + wh + hl)

2*( 18.5 * 9.4 + 9.4 * 6.2 + 6.2 * 18.5) =         (remember PEMDAS)

2 * 346.88 =

693.76 cm²

Answer:

-10 and -2

Step-by-step explanation:

First, divide both sides by 4 to get |x+6| = 4
Then, Take the absolute vaule on both sides
x+6= 4 or -4
So, x could be 2 vaules
Your welcome!

4 | x + 6 | = 16

Divide both sides by 4.

[tex]\bf{\dfrac{4|x+6|}{4}=\dfrac{16}{4} }[/tex]

[tex]\bf{|x+6|=4 }[/tex]

Absolute value is solved.

[tex]\bf{|x+6|=4 }[/tex]

We know either x + 6 = 4 or x + 6 = -4.

x + 6 = 4 (Possibility 1)

x + 6 - 6 = 4 - 6 (Subtract 6 from both sides)

x=−2

x + 6 = -4 (Possibility 2)

x + 6 - 6 = -4 - 6 (Subtract 6 from both sides)

x=-10

Solution:

x=−2 or x=−10

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Step-by-step explanation:

all the details see in the attachment.

Using conditional probability, it is found that there is a 0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

In this problem, we have that the probabilities are given as follows:

[tex]P(A) = 0.433, P(A \cap B) = 0.29 \times 0.50 = 0.145[/tex]

Hence the conditional probability is:

[tex]P(B|A) = \frac{0.145}{0.433} = 0.3349[/tex]

0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

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The length of the missing sides of triangles A and B are 9.43 cm and 12.04 cm respectively.

Triangle A:

Hypotenuse² = height ² + base²

x² = 8² + 5²

= 64 + 25

x² = 89

x = √89

x = 9.43 cm

Triangle B:

Hypotenuse² = height ² + base²

17² = 12² + x²

17² - 12² = x²

289 - 144 = x²

145 = x²

x = √145

x = 12.04 cm

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The trip to the lake took  4 hours.

The first step is to determine the distance of the trip.

Distance = average speed x time

24 km/h x 5 = 120 km

Time = distance / average speed

120 / 30 = 4 hours

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Answer:

Slope-intercept form: y = 3x - 1

Step-by-step explanation:

We are given that a line passes through the point (-5, -16) and has a slope of 3

We want to write the equation in point-slope form, and simplify it to slope-intercept form (if it is possible to do so).

First, point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point

We have both the slope and a point, but let's label the values of everything to avoid confusion + mistakes:

m = 3

[tex]x_1=-5\\y_1=-16[/tex]

Now substitute into the formula (remember: we have NEGATIVE numbers, and the formula uses SUBTRACTION):

[tex]y--16=3(x--5)[/tex]

The equation can be simplified

[tex]y+16=3(x+5)[/tex]

We can also write this in slope-intercept form

Start by distributing 3 to both x and 5 (multiply both x and 5 by 3)

[tex]y+16=3x + 15[/tex]

Subtract 16 from both sides

y = 3x - 1

Answer:

200 cans.

Step-by-step explanation:

f(c)=10r + 120

Put t=8 into it

T(c) = 10 x 8 + 120

=200 cans

(Use substitution method)

Answer:

Step-by-step explanation:

Comment

This can be done as a proportion. A proportion is 2 equal ratios. If you know three parts of the proportion then you can solve for the 4th.

Proportion

31 wrecks/1085 cars = 7 wrecks / x cars

Solution

31 wrecks/1085 cars = 7 wrecks / x cars        Cross Multiply

31 * x = 1085 * 7                                                Simplify the right

31 * x = 7595                                                     Divide both sides by 31

31 * x/31 = 7595/31

x = 245

Answer 7 wrecks means 245 cars have passed the intersection

THE ANSWER IS -> b. x > 1

hope it helps

thanks

Answer: c. x>0

Step-by-step explanation:

Answer:

let the no. be X

82% of X = 94.3

82/100 *X = 94.2

X = 94.2 *100/82

X = 94.2/0.82

X = 114.8

Answer:

115

Step-by-step explanation:

82% = 82/10 = 0.82

94.3 / 0.82 = 115

Hope this helps

The estimated cost of the ending inventory, assuming the gross profit rate is 35% is; $11250

Let us first calculate the gross profit;

Gross Profit = Sales * Profit%

Gross Profit = 395000 * 35%

Gross Profit = $138250

Cost of goods sold = Sales - Gross Profit

Cost of goods sold = 395000 - 138250

Cost of goods sold = $256750

Cost of ending inventory = Cost of goods available for sale - Cost of goods sold

Cost of ending inventory = 268000 - 256750

Cost of ending inventory = $11250

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The solution for the system of equations is: (99/13, 150/13)

Given the two expression 2/3x+3/5y=12 and 5/2y-3x=6

We have to find solution of two given expression.

To find the value of x, we have to eliminate y by making y the subject of formula in any of the equations.

Multiply equation A by 5/3 t.o get,

5/3(2/3x) + 5/3(3/5y) = 5/3(12)

10/9x + y = 20

y = 20 - 10/9x

substituting for y into equation b, we have:

5/2(20 - 10/9x) - 3x = 6

50 - 25/9x - 3x = 6

52/9x = 44

52x = 396

The expression that gives the value of x is: 52x = 396

Hence, x = 396/52 = 99/13

y = 20 - 10/9(99/13) = 20 - 110/13 = 150/13

Hence The solution for the system of equations is: (99/13, 150/13)

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Answer:

The formula is: y = y•e^(-k•x)

In this specific case the function is: 512•e^(-x/1.44)

The number of players in the round 7 is 4

Answer:

They could make at most 5 teams and its not possible to make everyone on team.

Step-by-step explanation:

If there are 4 players on a team, then we use 23 ÷ 4 = 5.75, 0.75 is not enough for 1, so there are 3 players remaining after making 5 teams.

The only problem is you may also go bankrupt before you're able to double your bet enough times.

If the game's events are independent,  similar to flipping a coin,  then the probability never changes, it's still a 1 out of 5 chance of winning each time.

The coin has no memory,  so it will always have the same probability on each flip.

If the games' events are like that,  a losing streak doesn't mean a win is now more likely.

But if the events are not independent,  it may make sense to increase the bet.  

for example,  a bag has 10 coins and 2 are worth 100.  You reach in and pull out 5 coins, all worth only a penny each.

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true.

Your odds of getting one of the 2 $100 coins is now much greater than the original 1 out of 5 chance.

 You originally had a 2 out of 10 chance on the first draw.  But now it's up to 2 out of the remaining 5 or 40% chance of winning.  

There is another reason someone may wish to double their bet.  If you doubled your bet each time you lost,  you would eventually recoup all your losses.  It can work.

The only problem is you may also go bankrupt before you're able to double your bet enough times.

That risk is usually considered too great to double your bets on independent events.

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Answer:

Step-by-step explanation: