So, the complete sentence is If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.
When the mass of the sun is larger, Earth moves around the sun at a faster pace and When the mass of the sun is smaller, Earth moves around the sun at a slower pace.
When Earth is closer to the sun, its orbit becomes faster and When Earth is farther from the sun, its orbit becomes slower.
When Earth is closer to the sun, there will be a hotter climate. A little movement that takes one closer to the sun could lead to a huge impact, as the sun is very hot.
So, it can be concluded that If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.
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a. The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J. Find by how much is the spring is compressed.
b. A 0.010 kg dart is fired straight up. Find the vertical distance the dart travels from its position when the spring is compressed to its highest position.
c. The same dart is now fired horizontally from a height of 4.70 m. The dart remains in contact until the spring reaches its equilibrium position. Find the horizontal velocity of the dart at that time.
d. Find the horizontal distance from the equilibrium position at which the dart hits the ground.
a. The spring is compressed by 0.174 m.
b. The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.
c. The horizontal velocity of the dart at that time is 13.74 m/s.
d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.
What is potential energy?The energy by virtue of its position is called the potential energy.
a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.
PE of spring = 1/2 kx²
Put the values, we get
P.E = 0.940 = 1/2 x 62 x²
x = 0.174 m
Thus, the spring is compressed by 0.174 m.
b. Given is a 0.010 kg dart is fired straight up.
The vertical height is find out by
0.940 J = (0.010 kg) (9.8 m/s²) h
h = 9.6 m
Thus, the vertical distance the dart travels from its position is 9.6 m
c. From the conservation of energy principle, total mechanical energy is conserved.
1/2 mv² =mgh
v = √2gh
Plug the values, we get
v = √2 x 9.8x 9.6
v = 13.74 m/s
Thus, the horizontal velocity is 13.74 m/s.
d. Time that dart spends in air, t = √2h/g
t = √(2x9.6)/9.81
t = 1.4 s
The horizontal distance from the equilibrium position at which the dart hits the ground.
Horizontal distance = (Velocity on x direction) x time
Horizontal distance = 13.74 m/s x 1.4s
Horizontal distance = 19.236 m
Thus, the horizontal distance is 19.236 m.
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1) 40 coloumbs of charge flow in 10 seconds. What is the current?
[tex]\large\boxed{Formula: I= \frac{Q}{t}}[/tex]
Note that:I: CurrentQ: Charge t: TimeSolution:Current is the flow of electrons around a circuit.SI unit of current is Amperes or Amps Symbol is ( A )Let's solve!
The formula is given above.
Let's substitute the values according to the formula.
We'll have to divide the measure of charge by the given time.
[tex]I= \frac{40}{10}[/tex]
Final answer:
[tex]\large\boxed{= 4 \: Amps \: (A)}[/tex]
Hence, the current is 4 amps.
a car is traveling along a straight road at a velocity of 30m/s when its engine cuts off. For the next ten seconds, the car slows down, and its average acceleration is a1. For the next five seconds, the car slows down further at a velocity of 24m/s, and its average acceleration is a2. The ratio of the average acceleration values is a1/a2=1.5. Find the velocity of the car at the end of the initial ten-second interval.
Answer:
See below....the question is unclear....pick the answer you think they want
Explanation:
Car goes from 30 m/s to 24 m/s in 10 seconds
acceleration = change in velocity/change in time
= -6 m/s / 10 s = - 3/5 m/s^2
The wording of the question is not very good.....perhaps they meant to say that after the 5 seconds the velocity is now 24 m/s ?
a1 *10 + a2 *5 = -6 m/s
( 6 m/s is the change in velocity from 30 to 24 m/s)
a1/a2 = 1.5 so a2 = a1/1.5 (substitute this in)
10 a1 + 5 ( a1/1.5) =-6
15 a1 + 5 a1 = -9
a1 = - .45 m/s^2
The velocity of the car at the end of the initial ten-second interval, given that the car further slows down for the next five seconds, is 25.5 m/s
How to determine the velocity of the car at the end of the 10 s interval?From the first statement, we have:
Initial velocity (u₁) = 30 m/sTime (t₁) = 10 secondsVelocity at the end of 10 s (v₁) = ?v₁ = u₁ + a₁t₁
v₁ = 30 + (a₁ × 10)
v₁ = 30 + 10a₁ ......(1)
From the second statement, we have:
Time (t₂) = 5 sFinal velocity (v₂) = 24 m/sRation of acceleration (a₁/a₂) = 1.5Initial velocity (u₂) = Velocity at the end of 10 sv₂ = u₂ + a₂t₂
24 = u₂ + (a₂ × 5)
24 = u₂ + 5a₂ .......(2)
But,
u₂ = v₁ = 30 + 10a₁
Thus, we have:
24 = 30 + 10a₁ + 5a₂
But,
a₁/a₂ = 1.5
a₁ = 1.5a₂ ..... (3)
Thus, we have:
24 = 30 + 10a₁ + 5a₂
24 = 30 + 10(1.5a₂) + 5a₂
24 = 30 + 15a₂ + 5a₂
24 = 30 + 20a₂
Collect like terms
24 - 30 = 20a₂
-6 = 20a₂
Divide both sides by 20
a₂ = -6 / 20
= -0.3 m/s²
Substituting the value of a₂ into equation 3, we have
a₁ = 1.5a₂
= 1.5 × -0.3
= -0.45 m/s²
Substitute the value of a₁ into equation 1 to obtain the velocity, v₁ at the end of the initial to 10 s
v₁ = 30 + 10a₁
= 30 + (10 × -0.45)
= 30 - 4.5
= 25.5 m/s
Thus, velocity of the car at the end of the initial ten-second interval is 25.5 m/s
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what is the radius of the 5th orbital in hydrogen?
Answer: 1.32 x 10^-9 m
Explanation:
The formula for the radius of nth orbital is:
[tex]r_{n}=\frac{n^{2}}{Z} \times 0.528 \text { Angstorms }[/tex]
For hydrogen, Z= 1, so we have:
[tex]$$\begin{aligned}r_{n} &=5^{2} \times 0.528 \text { Angstorm } \\&=13.2 \text { Angstorms } \\&=13.2 \times 10^{-10} \mathrm{~m} \\&=1.32 \times 10^{-9} \mathrm{~m}\end{aligned}$$[/tex]
Answer: 1.32*10^-9
Explanation: I had the same question and here's what I got:
rn = n2(r1)
n = 5
r = 5.29*10^-11
rn = n^2(r1)
= 5^2(5.29*10^-11)
r = 1.32*10^-9
In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is .......... a) 300 J c) 600 J (b) 450 J d) 750 J F=100 N CamScanner Wa 3m In the opposite figure , the work done by the force F to push the box upwards from the ground to the top of the inclined plane is .......... a ) 300 J c ) 600 J ( b ) 450 J d ) 750 J F = 100 N CamScanner Wa 3m
In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is 600 J.Option c is correct.
What is work done?Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
The displacement value from the triangle is;
[tex]\rm sin 30^0 = \frac{P}{H} \\\\ H=S =\frac{3 \ m}{sin 30^0} \\\\ S = 6\ m[/tex]
The work done is found as ;
[tex]\rm W= Fd \\\\ W = 100 \ N \times 6 \\\\ W= 600 \ J[/tex]
The force F in the opposing figure does 600 J of effort to lift the box from the ground to the top of the inclined plane.
Hence option c is correct.
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A local municipality placed an advert in the local newspaper for a competition of local high schools to participate to build a security system in the community hall to avoid vandalism and break ins
We will use the design process to meet the requirements of the competition by the given explained in the main answer.
What is the competition?The initiative was taken by two or more parties operating independently to win the business of a third party by competing to hire contractors on the best terms possible.
The complete question is
"A local businessperson placed an advert in the local newspaper for a competition for girls only from different schools to participate in the competition. The competition is about drawing ideas for a shopping complex for the local community. Girls from the different schools are excited about the competition. you are a group of boys in the local schools who saw the advert and feel it is unfair for you to be excluded from the competition.
consider yourself as one of the learners in the local schools.
Explain why the project should be given to boys also who have better skills for this project than the girls do.
1.2 think about the design process skills, investigates, design, make, evaluate and communicate."
Explain how you will use the design process to meet the requirements of the competition.
[ 1.1 ]Boys should also be given the project because some of them have more artistic talent than girls do when it comes to sketching designs for local shopping centers.
Boys can also present a clear picture of how local communities can expand their shopping options.
For instance, they can encourage local merchants to offer seasonal items because doing so will benefit their businesses.
They can also suggest that retailers encourage customers to bring a friend to participate in competitions, which will be highly regarded.
[1.2] In order to fulfill the needs of the competition, I would make sure to explore how a shopping center for the neighborhood functions, for instance, by making sure I am aware of the strategies one may use to enhance his or her firm in the neighborhood.
In order to win the competition, I would make sure that I was confident in what I was saying and that I was audible enough to be heard during the competition.
Finally, I would make sure I met the competition's conditions by staying on-topic and solely addressing the issues raised in the advertisement
Hence will use the design process to meet the requirements of the competition.
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Lesson 1, What is Physical Science.
Write an expository essay explain the difference between scientific knowledge and other kinds of science, include ideas regarding:
1) the scientific method.
2) true science versus false science.
3) examples of what scientists study and do not study.
4) what is required for a scientist to consider an idea to be true.
Physical science explains the physical world and not supernatural events and an idea is considered true by science if it can be observed, explained and reproduced by others.
What is physical science?
Physical science is a systematic study of the of the physical world and phenomena based on observation and experiments.
The scientific method involves:
observation and questionshypothesisexperimentsresults and further experimentstheories and lawsScience explains the physical world and not supernatural events.
Science studies physical phenomena such as the stars, the planets, living things, etc.
Science do not study about angels or demons or supernatural events.
An idea is considered true by science if it can be observed, explained and reproduced by others.
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5.00 μF, 10.0 μF, and 50.0 μF capacitors are connected in series across a 12.0-V battery.
(a) How much charge is stored in the 5.00-μF capacitor?
(b) What is the potential difference across the 10.0-μF capacitor?
(a) The charge stored in the 5.00-μF capacitor is 37.2 μC.
(b) The potential difference across the 10.0-μF capacitor is 3.72 V.
What is capacitor?The capacitance of a capacitor is defined as the ratio of the charge stored and the potential difference between the capacitor.
The capacitance of a capacitor is denoted by C and expressed as
C = Q/V
Given, 5.00 μF, 10.0 μF, and 50.0 μF capacitors are connected in series across a 12.0-V battery.
(a) The equivalent capacitance is
1 / Ceq = 1 / C₁ +1 / C₂ + 1/ C₃
Substitute the values, we get
Ceq = 3.1 μF
The charge stored in 5.00-μF capacitor is
Q = Ceq x V
Q = 3.1 μF x 12 V
Q = 37.2 μC
Thus, the charge stored in the 5.00-μF capacitor is 37.2 μC
(b) The potential difference across the 10.0-μF capacitor is given by
V = Q/C₂
Put the values, we get
V = 37.2 / 10
V = 3.72 V
Thus, the potential difference across the 10.0-μF capacitor is 3.72 V.
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A resistor has a resistance of 8.2 kΩ. If a voltage of 15.9 V were placed across it, what would be the current, in mA? Give the answer to two decimal places; don't worry if the computer adds zeroes.
The value of the electric current for the given conditions willl be 1939.02 A.
What is ohm’s law?Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
Ohm's law claims that the voltage across a conductor is direct to the current flowing through it. This current-voltage connection may be expressed mathematically as,
V=IR
15.9 V = I × 8.2 × 10³ Ω
I = 1939.02 A
Hence, the value of the electric current for the given conditions willl be 1939.02 A.
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Kim is ice-skating going 4.6 m/s. What is her velocity after 10 seconds ?
This is a uniform rectilinear motion (MRU) exercise.
To start solving this exercise, we obtain the following data:
Data:v = 4.6 m/sd = ¿?t = 10 secTo calculate distance, speed is multiplied by time.
We apply the following formula: d = v * t.
We substitute the data in the formula: the speed is equal to 4.6 m/s, the time is equal to 10 s, which is left as follows:
[tex]\bf{d=4.6\dfrac{m}{\not{s}}*10\not{s} }[/tex]
[tex]\bf{d=46 \ m}[/tex]
Therefore, the speed at 10 seconds is 46 meters.
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a generator uses loops of area 0.239 m^2, rotating 373 rad/s in a 0.0639 t magnetic field. how many loops must the coil have to generate a maximum emf of 2500 v?
The loops must the coil have to generate a maximum emf of 2500 will be 439.
What is the faraday law of electromagnetic induction?According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.
Given data;
Area,A = 0.239 m²
Angular velocity,ω=373 rad/sec
Magnetic field,B=0.0639 T
Maximum emf,E= 2500V
The formula for the maximum induced voltage is;
E{max} = N × B × A × ω
2500 = N × 0.639 × 0.0239 × 373
N = 438.66
N = 439 \ turns
Hence, loops must the coil have to generate a maximum emf of 2500 will be 439.
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Answer: 11392.99
Explanation: I had the same problem and here are the steps:
Values:
N (Number of loops) = 2000
A (area) = 0.239
ω (angular velocity) = 373
B (magnitude) = 0.0639
ε = NABω
= (2000)(0.239)(373)(0.0639)
ε = 11392.99 (FINAL ANSWER)
Metals are used in many products because of the characteristic properties that most metals have.
Which product
requires the high luster of metals in order to work?
O mirrors
O pots and pans
O food wrap
O circuit boards
a) Mirrors
Mirror requires the high luster of metals in order to work.
What causes the highest luster of a metal?When light shine on to the surface of a metal, its electrons absorb small amounts of energy and become excited into one of its many empty orbitals.
The electrons immediately fall back down to lower energy levels and emit light.
This process is responsible for the high luster of metals.
Here,
Mirrors have metal coating on its back side, because of high reflective property , high lustrous mirror is preferred . When metal is more lustrous, the less light reflect into it and bounces back.
Coating one side of a piece of glass with shiny metals can turn it into a mirror, reflecting light coming toward it.
Window glass can reflect only eight percent of light hitting it, while mirrors can reflect 95 percent of light hitting them.
The glass in a mirror is usually coated with a layer of silver or aluminum.
Mirrors are shiny because when photons (rays of light) coming from an object , it strike the smooth surface of a mirror, then they bounce back at the same angle. Our eyes see these reflected photons as a mirror image.
Therefore,
Mirror requires the high luster of metals in order to work.
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Answer:A) mirrors
Explanation:
How many seconds are in 28 hours?
Answer:
1680 seconds
Explanation:
[tex]28 hrs * \frac{60 s}{1 hr} =1680s[/tex]
Aude slipped on ice going 7.6 m/s .What was her velocity before she hit the wal?
Answer:
Define universal gravitational constant. Why is newton's law of gravitation called universal law?
two rods one aluminum and one brass are is clamped at one end. At zero degrees celsius, the roads are each 50 cm long and separated by 0.024 CM at their unfastened ends. At what temperature will the rod just come into contact.
At 11.3°C the rod will just come into contact
Coefficient of linear expansion of aluminium [tex]\alpha_{Al}[/tex] = [tex]23*10^-^6[/tex] °[tex]C[/tex]
Coefficient of linear expansion of Brass [tex]\alpha_{B} =19*10^-^6[/tex] °[tex]C[/tex]
[tex]\alpha = \Delta{L}/Lo(T2-T1)[/tex]
For aluminium
[tex]\alpha_{Al} = \Delta{L}/Lo(T-0)[/tex]
[tex]\Delta{L_{1}} = (23*10^-^6*50*T)[/tex]
For Brass
[tex]\alphaB = \Delta{L_{2}/Lo(T-0)[/tex]
[tex]\Delta{L_{1} +\Delta{L_{2} =0.024cm(23*10^-^6*50*T)+(19*10-6*50*T) =0.024[/tex]
T =11.43 °C
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the temprerture of an object is 40°c.what is this tempreture in farhenhite scale?
This is an exercise of thermal scales.
Data:T = 40 °C
T = °F ¿?
To convert degrees Celsius to degrees Fahrenheit, we have the formula:
[tex]\bf{^{\circ}F=\dfrac{9}{5} \ ^{\circ}C+32 \ \ \to \ \ \ Formula }[/tex]
We substitute our data into the formula.
[tex]\bf{^{\circ}F=\dfrac{9}{5} \times 40+32}[/tex]
First we divide 9/5 multiplied by 40.
[tex]\bf{=75+32}[/tex]
Add 75 plus 32
[tex]\bf{=104 \ ^{\circ}F}[/tex]
Therefore, the temperature change of 40 °C on the °F scale is equal to 104.
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A hollow cast-iron cylinder 4m long, 300mm outer diameter, and thickness of metal 50mm is subjected to a central load on the top when standing straight. The stress produced is 75000kN/m2. Assume Young's modulus for cast iron as 1.5x 108 kN/m^2 and find (i) magnitude of the load, (ii) longitudinal strain produced, and (iii) total decrease in length.
Here, the calculated Magnitude of the load P is 2945.2 kN, the Longitudinal strain produced is 0.0005 and the decrease in length is 2 mm.
Given,
Length, L = 4 m
Outer diameter, D = 300mm, D= 0.3 m
Thickness, t = 50 mm, t = 0.05 m
Stress produced, σ = 75000 kN/m²
Young's modulus for cast iron, E = 1.5 x 10⁸ kN/m²
Calculating the diameter of the cylinder,
Diameter of cylinder, d = (D) – (2t) = 0.3 –( 2 × 0.05)
d= 0.2 m
(i) Magnitude of the load P:
Using the relation, σ =P/A
P = σ × A = 75000 × π /4 (D² – d² )
P= 75000 × π/4 (0.3² – 0.2²)
P= 75000 × π/4 (0.09 – 0.04)
P = 2945.2 kN
Hence, Magnitude of the load P is 2945.2 kN.
(ii) Longitudinal strain produced, e :
Using the relation, Strain, (e) = stress/E
e= 75000/(1.5 x 10⁸)= 0.0005
Hence, the Longitudinal strain produced is 0.0005.
(iii)Total decrease in length, dL:
The total decrease in length can be calculated using the strain as the ratio of change in length to the original length is known as Strain.
Strain = change in length/original length
e= dL/L
0.0005 = dL/4
dL = 0.0005 × 4m = 0.002m=2mm
Hence,the decrease in length is 2 mm.
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What does the first law of thermodynamics state about energy?
The first law states that the internal energy change of that system is given by Q − W . Since added heat increases the internal energy of a system, Q is positive when added to the system and negative when removed from the system.
Estimate the gravitational force of attraction between two people sitting side by side on a park bench. How does this force compare with the gravitational force exerted on each of them by the Earth
Weight is compared with the gravitational force exerted on each of them by the Earth.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
The gravitational force is balanced by weight;
[tex]\rm F = W \\\\ G\frac{mM}{r^2} =mg[/tex]
Hence, weight is compared with the gravitational force exerted on each of them by the Earth.
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the 3kg object in figure is released from rest at height of 5m on curved frictionless ramp.at the foot of the ramp is a spring of force constant 400N/m.the object slide down the ramp and into the spring, compressing it a distance x before coming momentarily to rest. a) find x
b)describe the motion of the object (if any) after the block momentarily comes to rest?
The value of x given the data from the question is 0.86 m
How to determine the energyFrom the data given above, we can s determine the energy as follow:
Mass (m) = 3 KgHeight (h) = 5 mAcceleration due to gravity (g) = 9.8 m/s² Energy (E) = ?E = mgh
E = 3 × 9.8 × 5
E = 147 J
How to determine the value of xSpring constant (K) = 400 N/mEnergy (E) = 147 JExtention (e) = x = ?E = ½Ke²
147 = ½ × 400 × x²
147 = 200 × x²
Divide both side by 200
x² = 147 / 200
Take the square root of both sides
x = √( 147 / 200)
x = 0.86 m
Since the block came to rest, there is no motion
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an object is held 33.5 cm from a convex mirror. it creates a virtual image of magnification 0.253. what is the focal length of the mirror?
Answer:
Magnification= -image distance/object distance
.253=image distance/33.5
image distance= 8.48 cm
What is the estimated density of the golf ball? Record your answer to the nearest hundreth.
g/cm3
The estimated density of the golf ball is 170 kg/m³
What is density?
Density is the ratio as Mass per unit Volume.
In displacement method,
First , we measuring the volume of water displaced by an object which tell us the volume of the object then we will use the physical balance to determine its mass.
Then calculate the density by dividing the mass by the volume.
Here, D = m/V
By displacement method , the estimated volume of golf ball is 100 cm³ and estimated mass is 600 g
Then ,
Density = 100 cm³ / 600 g = 0. 17 g/ cm³ = 170 kg/m³
So the estimated density of golf ball is 170 kg/m³
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The following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t₁=2sec and t₂=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
will give brilliance
A. The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 4 i m/s.
B. The velocity and acceleration at any time t is 4t i +1 j and 4i.
C. The average acceleration in the time interval given in part (a) is 4
What is acceleration?Acceleration can be defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
Given the following equation shows the position of a particle in time t, x=at² i + bt j
where t is in second and x is in meter. a=2m/s², b=1m/s.
A. Velocity is time rate of change of displacement.
V = dx/dt
V = d/dt (2t² i + 1t j)
V = 4t i +1 j
Velocity in time interval,
At t₁=2sec , V₂= 4x2 i + 1 j = 8 i + 1 j
At t₂=3sec, V₃ = 4x3 i + 1 j = 12 i + 1 j
Average velocity in time interval t₁=2sec and t₂=3sec is
, V₃ - V₂ = (12 i + 1 j) - ( 8 i + 1 j )
Average velocity = 4 i
B. Velocity at time t, is
V(t) = V = 4t i +1 j
Acceleration a = dV/dt
a(t) = d/dt (4t i +1 j)
a(t) = 4 i +0 j
C. Average acceleration in time interval t₁=2sec and t₂=3sec is
a = 4 m/s²
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Two force of 20N and 40N act at a
Point and the angle between them is 50 degrees.
Find the resultant force
Find the direction using sine rule
R=√20²+40²+2.20.40 cos 50
R=55 N
R/sin β = F/sin α
55/sin 50 = 40/sin α
α = 33°
A piece of steel expands 10 cm when ur is heated from 20 to 50 degrees Celsius. How much would it expand if it was heated from 20 to 60 degrees Celsius
The steel would expand by 4. 8 * 10^-3 cm
How to determine the linear expansionThe change in length ΔL is proportional to length L. It is dependent on the temperature, substance, and length.
Using the formula:
ΔL= α LΔT
where ΔL is the change in length L = 10cm
ΔT is the change in temperature = 60° - 20° = 40° C
α is the coefficient of linear expansion = 1.2 x 10^-5 °C
Substitute into the formula
ΔL = [tex]1.2 * 10^-5 * 10 * 40[/tex]
ΔL = [tex]4.8 * 10 ^-3[/tex] cm
Therefore, the steel would expand by 4. 8 * 10^-3 cm
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What is temperature?
A. A type of heat transfer
ANUN
B. The measure of an object's "hotness"
APATIN
HERRE
C. Electromagnetic waves
Digita
D. The energy transferred between objects
H
The term temperature has to do with the measure of an object's "hotness".
What is temperature?The term temperature has to do with how hot or cold a body is. In other words, the word temperature brings us to call to mind the degree of hotness or coldness of a body.
Succinctly put, the term temperature has to do with the measure of an object's "hotness".
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When a cold alcohol thermometer is placed in a hot liquid, the column of alcohol goes down slightly before going up. Explain why.
Answer:
See below
Explanation:
When a cold alcohol thermometer is placed in a hot liquid, the following takes place.The glass of thermometer expands because of the heat so the column of alcohol goes down.After some time, the heat travels to alcohol and then alcohol expands.So, Reason why alcohol goes down first:Alcohol first goes slightly down because of the expansion of the glass of thermometer before doing up.
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In a hydraulic lift whose input line has a cross-sectional area of 1.00 cm² and whose output line has
a cross-sectional area of 22.0 cm², what is the largest mass (kg) that can be lifted by an input force
of 200. N?
By using Newton's Second law of motion, the largest mass that can be lifted by this input force is equal to 2,244 kg.
How to calculate the largest mass?Based on the information provided, we can logically deduce that the output to input force ratio is equal to 22:1. This ultimately implies that, the input force is equal to 1000 N, which would result in an output force of 22,000 N.
Next, we would calculate the largest mass by using Newton's Second law of motion:
Mass = Force/Acceleration
Mass = 22,000/9.8
Mass = 2,244 kg.
Note: Acceleration due to gravity is equal to 9.8 m/s².
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A 808 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 632 kg. The two cars lock up and slide together with a speed of 15.0 km/h. What was the speed of the first car just before the collision?
The speed of the first car just before the collision is 26.73 km/h.
What is conservation of momentum principle?When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.
The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.
m₁u₁ +m₂u₂ =(m₁ +m₂) v
Given a 808 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 632 kg. The two cars lock up and slide together with a speed of 15.0 km/h.
Second car is parked, so its velocity will be zero.
808 x u +632 x 0 = (808 +632 ) x 15
u = 26.73 km/h
Thus, the speed of the first car just before the collision is 26.73 km/h
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a. Recent studies have raised concern about 'heading' in youth soccer (i.e., hitting the ball with the head). A soccer player 'heads' a size 3 ball deflecting it by 40.0°, and keeps its speed of 13.20 m/s constant. A size 3 ball has a mass of approximately 2.000 kg. What is the magnitude of the impulse which the player must impart to the ball?
b. If the player's head has a mass of 2.90 kg, what is the magnitude of the average acceleration of the player's head during the impact. Assume that over the brief time of the impact, 30.40 ms, the player's head can be treated separately from the player's body.
a. The magnitude of the impulse which the player must impart to the ball is 17.25 kg.m/s.
b. The magnitude of average acceleration of the player's head during the impact is 195.66 m/s².
What is impulse?The change in momentum is equal to the product of impact force applied while colliding and time for that impact.
Impulse F. t = m (Vf -Vi)
where, Vf is the final velocity and Vi is the initial velocity.
Given, a soccer player 'heads' a size 3 ball deflecting it by 40.0°, and keeps its speed of 13.20 m/s constant. A size 3 ball has a mass of approximately 2.000 kg.
a. Substitute the values into the expression, we get
Impulse (x) = 2 x (13.20 - 13.20cos40°)
Impulse (x) = 3.088 kg.m/s
Impulse in y direction, is
Impulse (y) = 2 x 13.20sin40°
Impulse (y) = 16.97 kg.m/s
so, the magnitude of impulse is
I = sq rt(Ix² + Iy²)
Put the values, we get
I = 17.25 kg.m/s
Thus, the magnitude of the impulse which the player must impart to the ball is 17.25 kg.m/s
b. The player's head has a mass of 2.90 kg. The brief time of the impact, 30.40 ms,
F.t = I
Put the given values, we have
F = 17.25 / 30.40 x 10⁻³
F = 567.434 N
From the Newtons second law of motion,
F = ma
Plug the values from the question, we have
567.434 N = 2.90 x a
a = 195.66 m/s²
Thus the magnitude of average acceleration of the player's head during the impact is 195.66 m/s².
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