Answer:
r = 50[m]
Explanation:
Since the instrument has an operating or range radius, we must calculate this working distance or radius. We can determine the working area with the values that were given to us.
[tex]A=\frac{70W}{0.0089\frac{w}{m^{2} } } \\\\A=7865.16[m^{2} ][/tex]
Now using the area of the circle we can find the radius.
[tex]A=\pi *r^{2} \\7865.16=\pi *r^{2} \\\\r=\sqrt{\frac{7865.16}{\pi } } \\r=50[m][/tex]
A 1600 kg car is moving north with a speed of 25 m/s. An impulse of 10,000 N-s south is applied to the car. After the impulse is applied, the speed of the car is:
Answer:
The speed of the car is 18.75 m/s
Explanation:
Impulse-Momentum Change Equation
The impulse received by an object is equal to the change in momentum:
Impulse = Change in momentum
The change in momentum is:
[tex]\Delta p=m\Delta v=m(v_2-v_1)[/tex]
Where m is the mass of the object, v2 is the final speed, and v1 is the initial speed. This means the impulse J is:
[tex]J=m(v_2-v_1)[/tex]
It's given an m=1,600 kg car is moving at v1=25 m/s North and then an impulse of J=-10,000 N.s is applied South. The minus sign indicates the impulse is opposite to the original direction of the velocity.
Solving for v2:
[tex]\displaystyle v_2=\frac{J}{m}+v_1[/tex]
Substituting:
[tex]\displaystyle v_2=\frac{-10,000}{1,600}+25[/tex]
[tex]\displaystyle v_2=-6.25+25=18.75[/tex]
[tex]v_2=18.75\ m/s[/tex]
The speed of the car is 18.75 m/s
A body with a mass of 10.0kg is assumed to be in earth's gravitational field with g=9.80m/s2. What is the acceleration?
Answer:
a = F/m
a = 9.80÷ 10.0
a 0.98 m/s²
Question 7 (1 point)
An air mass exists off the Pacific coast of California. What type of air mass is this and
what are its main characteristics?
Choose ALL that apply
Lesson 1.07
Maritime
Polar
Continental
Polar
Maritime
Polar
Maritime
Tropical
Maritime
Tropical
Continental
Tropical
Maritime
Tropical
forms over warm water
warm, humid air mass
its a polar air mass
brings rainy or muggy weather
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)
What is your average resting heart rate?
Answer:
from 60 to 100.
Explanation:
Normal heart rates at rest: Children ages 6 - 15 70 – 100
Adults (age 18 and over) 60 – 100
A force is 10 and is used to move a box. It is moved a distance of 3 m. What is the work involved in moving the box?
Answer:
Workdone = 30Nm
Explanation:
Given the following data;
Force = 10N
Distance = 3m
To find the workdone;
Workdone = force * distance
Substituting into the equation, we have
Workdone = 10 * 3
Workdone = 30Nm.
Therefore, the work involved in moving the box is 30 Newton-meter.
How Could The movements of objects across the sky have led people to the conclusion that earth is the center of the universe
Answer:
What we see in the sky
Where are they in the general context of the overview of the Universe?
With the naked eye, the main astronomical objects we can see are the Sun, the Moon, the stars, and some of the planets
All of the stars we see are in the Milky Way galaxy, most of them relatively close to the Sun.
The stars we see in the sky come in a range of brightnesses, partly because stars come in different intrinsic brightnesses, and partly because some are closer than others.
When we look at an astronomical object ``by eye'', we can't tell just by looking how far away it is (because not all objects have the same intrinsic brightness). All we can see is what direction it is in.
As a result, when looking ``by eye'', the positions of stars on the sky are described by their direction only; you can imagine that the sky is a big sphere with astronomical objects located at different positions on it. This is called the celestial sphere
The positions of the stars can be described with a sort of astronomical longitude and latitude, called right ascension and declination.
Constellations are patterns of stars seen in the sky. However, although the stars in any constellation are all in the same general direction in the sky, the different stars in a constellation may be at very different distances from Earth, hence constellations may not be real associations of stars in space, just stars in the same general direction as seen from Earth.
Only the nearest galaxies are visible to the naked eye, as relatively faint smudges of light, although two of the very nearest galaxies, the Magellanic Clouds, are visible are moderately large clouds from the Southern hemisphere.
Motions in the sky
Hope this helps! :)
A 20 Kg box is sliding across a horizontal table at 10m/s. If the coefficient of Friction is 0.5, what is the acceleration of the box?
By Newton's second law,
• the net vertical force on the box is
∑ F = n - mg = 0
where n = magnitude of the normal force, m = mass of the box, and g = acceleration due to gravity; then
n = mg = (20 kg) (9.8 m/s²) = 196 N
• the net horizontal force on the box is
∑ F = -f = -ma
where f = mag. of kinetic friction and a = acceleration of the box. Since
f = µn
where m is the coefficient of kinetic friction, so that
f = 0.5 (196 N) = 98 N
Then the box's acceleration is
-98 N = - (20 kg) a → a = (98 N)/(20 kg) = 4.9 m/s²
Does which object have the compacity that is the best measured in pints?
option 1: water bottle
option 2: swimming pool
option 3: trash barrel
option 4: soup spoon
:)
Answer:
1 or 2
Explanation:
DO NOT ANSWER IF YOU DONT KNOW What is the medium for a wave:
i. At the beach?
ii. In a football stadium?
iii. Of sound?
How much work is required to pull a sled 5 meters if you use 60N of force?
Answer:
300Nm
Explanation:
work = force x distance = 60x5=300
The work required to pull a sled by 5 meters using 60 N of force is 300 joules.
What is Work done in physics?Work done in physics is defined as the dot product of force and displacement caused by it. Mathematically -
W = F.x
W = |F| |x| cos Ф
where Ф is the angle between force and displacement
Given is to calculate the work required to pull a sled by 5 meters by using 60 N of force.
We can write the following data -
Applied Force [F] = 60 Newtons
Displacement needed [x] = 5 meters
Angle between force and displacement [Ф] = 0°
Using the formula for work done, we can write -
W = |F| |x| cos Ф
W = 60 x 5 x cos(0)
W = 300 x 1
W = 300 Joules
Therefore, the work required to pull a sled by 5 meters using 60 N of force is 300 joules.
To solve more questions on Work, energy and power, visit the link below-
brainly.com/question/3893991
#SPJ6
Explain the principles of work in physics.
If you pay children in kindergarten to make things from modeling clay, and then stop, you may find that they are less willing to do it for nothing than they were before you ever started paying them. This is an example of?
Answer: overjustification
Explanation:
The overjustification effect is a situation that occurs when an incentive like prizes or money or prizes leads to the reduction in an individual's intrinsic motivation that is necessary in performing a task.
In this case, because the children are motivated by money, when the take doesn't involve money anymore, they may not be willing to do it.
In the image below, which region is showing an abnormally high sea level?
Color-coded map showing the height of the world's ocean surfaces at a particular time. Black areas correspond to 35 to 50 centimeters below normal. Blue areas correspond to 5 to 25 centimeters below normal. Gray areas correspond to 0 centimeters above or below normal. Yellow areas correspond to 5 to 15 centimeters above normal. Red areas correspond to 25 to 35 centimeters above normal. In this map, area A is colored blue, area B is colored yellow, area C is colored red, and area D is colored gray.
A
B
C
D
According to the information provided, the area showing abnormally high sea level is area C.
How to identify the area the highest sea level?To identify the area of the sea with the highest level, we must take as a reference the colors of each region and to what parameters each one corresponds.
In this case we have a map with areas painted in blue, yellow, red and gray, that is, there are areas with the following characteristics.
Area A (blue) has levels 5 to 25 centimeters below normal.Area D (grey) has levels 0 centimeters above or below normal.Area B (yellow) has levels 5 to 15 centimeters above normal.Area C (red) has levels 25 to 35 centimeters above normal.Learn more about maps in: https://brainly.com/question/1670085
Answer:c
Explanation:test
How is the brightness of the star related to how quickly it pulses?
Answer:
The greater the luminosity of a star, the longer its period of oscillation.
What is the formula of the Ca^2+and F^1- ions when they come together?
Answer:
CaF₂
Explanation:
When calcium ions combine with fluoride ions calcium fluoride is formed.
The formula is ;
Ca²⁺+2 F¹→CaF₂
In this formula, Calcium ion has a charge of 2+ and the fluoride ion has a charge of 1-. Two fluoride ions are required to make the overall charge zero.
The center of mass of a cow and the center of mass of a tractor are 208 meters apart. The magnitude of the gravitational force of attraction between these two objects is calculated to be 1.8 × 10-9 newtons.
What would the magnitude of the gravitational force of attraction be between these two objects if they were 416 meters apart?
A.
1.62 × 10-9 newtons
B.
3.6 × 10-10 newtons
C.
9 × 10-10 newtons
D.
4.5 × 10-10 newtons
Answer:
The magnitude of the gravitational force of attraction between the two objects when they are 416 meters apart is;
D. 4.5 × 10⁻¹⁰ Newtons
Explanation:
The given parameters are;
The distance between the center of mass of the cow and the tractor, r = 208 m
The gravitational attraction between the cow and the tractor = 1.8 × 10⁻⁹ N
The formula for finding the gravitational force, 'F', between the cow and the tractor is given as follows;
[tex]F =G\cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}[/tex]
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹m³·kg⁻¹·s⁻²
m₁·m₂ = The product of the mass of the cow and the tractor
Therefore, we have;
[tex]F = 1.8 \times 10^{-9} =G\cdot \dfrac{m_{1} \cdot m_{2}}{208^{2}}[/tex]
1.8 × 10⁻⁹ × 208² ≈ 7.78752 × 10⁻⁵ = G × m₁ × m₂
Therefore, when the distance between the two objects are 416 meters apart, we have;
[tex]F = \dfrac{G \cdot m_{1} \cdot m_{2}}{r^{2}} = \dfrac{7.78752 \times 10^{-5}}{416^2} = 4.5 \times 10^{-10}[/tex]
The magnitude of the gravitational force of attraction between the cow and the tractor when they are 416 meters apart, F = 4.5 × 10⁻¹⁰ N.
Which shows zero as significant digits? Check all that apply.
0.02
7.560
O 430
0 604
O 70,230
Answer:
Explanation:
0.02
0.604
70,230
becuase if you take away the 0 then it would change the value of the number
A race car accelerates from 50 m/s to 75 m/s over a distance of 400 m. What is the race car's acceleration?
Answer:
[tex]a=3.90\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = 50 m/s
Final velocity, v = 75 m/s
DIstance, d = 400 m
We need to find the acceleration of the car. Let the acceleration of the car be a. We can use the third equation of motion to find it as follows :
[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(75)^2-(50)^2}{2(400)}\\\\=\dfrac{3125}{2(400)}\\\\=3.90\ m/s^2[/tex]
So, the acceleration of the car is [tex]3.90\ m/s^2[/tex].
External forces such as extreme weather pose a constant threat to the structural reliability of structures
Answer:
True
Explanation:
External forces such as extreme weather pose a constant threat to the structural reliability of structures.
Extreme weather conditions such as a high temperature or rainfall have an effect on structures due to the constant exposure of the structures to this factors. The materials used in building these structures have different properties which are usually affected by environmental factors.
it is easier to see clothes with pointed needle than a blunt one
Answer:
Explanation:
It is easier to see clothes with pointed needle than a blunt one because pressure exerted is more in a pointed needle as it occupies less space compared to blunt needle, A blunt has more surface area so the pressure exerted will less as compared to a pointed needle.
IF YOU FOUND MY ANSWER USEFUL THEN PLEASE MARK ME BRAINLIEST.
why has SI system been developed?? give reason
plzz help i have exam tmr
Answer:
It allows people in different places and different countries to use the same units, avoid mistakes and understand each other more easily.
PHYSICS QUESTION BRAINLIEST
Ball A with a mass of 5 kg is moving at 20 m/s, collides with ball B of unknown
mass moving at 10 m/s in the same direction. After the collision, ball
A moves at 10 m/s and ball B at 15 m/s, both still in the same
direction. What is the mass of ball B?
M = mass of the ball A = 5.0 kg
m = mass of the ball B = ?
V = initial velocity of the ball A before collision = 20 m/s
v = initial velocity of the ball B before collision = 10 m/s
V' = final velocity of the ball A after collision = 10 m/s
v' = final velocity of the ball B after collision = 15 m/s
using conservation of momentum
M V + m v = M V' + m v'
(5.0) (20) + m (10) = (5.0) (10) + m (15)
100 + 10 m= 50 + 15 m
5 m = 50
m= 10 m/s
Answer: 5
Explanation:
cat walks 100 m  East, then turns around and walks 25 m west. What is the cats displacement?
a) 75 m
b) 100 m
c) 25 m
d) 125 m
Answer:
75mExplanation:
If a cat walk 100m East, this means that it is walking in the positive x direction, the distance will therefore be +100m
If it turns around and walks 25 m west, the direction of movement is in the negative x direction i.e -25m
Taking the sum;
Displacement = +100m - 25m
Displacement of the cat = 75m
hence the cats displacement is 75m
Can anybody helppp me with this
Which is an example of a physical change?
cake baking
gasoline combusting
salt dissolving
iron rusting
Answer:
Salt dissolving
Explanation:
Dis solving salt in water doesn't change it's chemical composition
Answer:
Iron Rusting
6th grade stuff or 5th i think
Explanation:
Please help with this question!!!!
describe how an electromagnet can be switched on and off.
Answer:The magnetic field around an electromagnet is just the same as the one around a bar magnet. It can, however, be reversed by turning the battery around. Unlike bar magnets, which are permanent magnets, the magnetism of electromagnets can be turned on and off just by closing or opening the switch.
I WILL GIVE BRAINLIEST PLEASE HURRY
Evan examines a diagram of the rock cycle in his science textbook. He wonders how he can connect what he has learned about matter and energy to the rock cycle. Which statement explains what happens to material as it moves through the stages of the rock cycle?
Group of answer choices
A) New matter is being created all of the time.
B) The same matter is recycled over and over.
C) Eventually the broken-down matter disappears.
D) Old matter is destroyed and new matter takes its place.
Answer:
Hiii
The answer should be B)The same matter is recycled over and over.
How do geologists construct the geologic column?
Answer:
They do this by joining pieces of different Rock sequences together from different places in the whole world.
Explanation:
Geologic columns are basically an arrangement of rock layers whereby the newest rocks are at the top while the oldest rocks will be at the bottom. Thus, it is like a timescale that's used to find the age of rock formation on the earth around the world.
A student climbs to the top of the gym and drops a baseball to the ground below. A physics student standing nearby has a motion sensor and determines that the baseball hit the ground with a velocity of 17 m/s. if you ignore air resistance, how long was the baseball falling through the air?
Answer:
The baseball was falling during 1.733 seconds.
Explanation:
The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground ([tex]t[/tex]), measured in seconds, which is determined by the following kinematic formula:
[tex]t = \frac{v-v_{o}}{g}[/tex] (1)
Where:
[tex]v_{o}[/tex], [tex]v[/tex] - Initial and final speeds of the baseball, measured in meters per second.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v = 17\,\frac{m}{s}[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the time spent by the baseball is:
[tex]t = \frac{17\,\frac{m}{s}-0\,\frac{m}{s} }{9.807\,\frac{m}{s^{2}} }[/tex]
[tex]t = 1.733\,s[/tex]
The baseball was falling during 1.733 seconds.
What is polarization. How can we remove it?
