i need this answer a.s.a.p!!!
Answer:
Should have ended with "at most -15, not "at least -15."
Step-by-step explanation:
[tex]\leq[/tex] -15 means less than or equal to -15
So it can be -15, but also anything less than -15. The phrase "at most -15, not "at least -15" says exactly that.
3. Find the measure of angle TOS in the figure below.
∠ROQ and ∠TOS are vertically opposite angles, so must be equal, which means they are 122°
∠TOS = 122°image Which of the following statements is true for ∠a and ∠b in the diagram?
Answer:
You have not added a picture soi can not help answer this question.
Step-by-step explanation:
Add the picture by either taking a photo or screenshot of the question then upload it.
The scale on a map is 1 : 25000
How many kilometres on the ground is represented by 7 cm on the map?
Answer:
175000 km
Step-by-step explanation:
the 1:25000 essentially means that every centimeter represents 25000 kilometers. so the answer is 175000 by multiplying 7 and 25000
1
A circle is defined by the equation given below.
x² + y²
2y -
What are the coordinates for the center of the circle and the length of the radius?
X
= 0
ig Algebr
OA. (1, 1), 2 units
OB. (-1,-1), 2 units
OC. (,1), 4 units
OD. (-1,-1), 4 units
Reset
Next
The coordinates for the center and length of the radius of this circle are equal to (½, 1), 2 units.
How to determine the coordinates?Mathematically, the standard form of the equation of a circle is given by;
(x - h)² + (y - k)² = r²
Where:
h and k represent the coordinates at the center.r is the radius of a circle.In order to determine the coordinates for the center and the length of the radius of this circle, we would use completing the square method:
x² + y² - x - 2y - 11/4 = 0
x² - x + ¼ + y² - 2y = 11/4 + ¼
(x - ½)² + y² - 2y + 1 = 12/4 + 1
(x - ½)² + (y - 1)² = 4
Comparing with the standard form, we have:
h = ½k = 1r = √4 = 2 units.Read more on circle here: https://brainly.com/question/14078280
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Complete Question:
A circle is defined by the equation given below.
x^2 + y^2 − x − 2y − 11/4 = 0
What are the coordinates for the center of the circle and the length of the radius?
please place the dot for me(20 points will give brainliest!!!)
Answer:
Domain & Range are both all real numbers.
Step-by-step explanation:
i
If this was a traditional parabola, the range would be y<=4. However, the arrow on the left going back up means eventually y will go to both positive & negative infinity.
There are 12 ducks and 11 geese in a certain park. Find the ratio of geese to ducks.
Please answer!!
-3 + 4/7 - 1/5
Step-by-step explanation:
please mark me as brainlest
Answer:
-92/35
Step-by-step explanation:
-3 + 4/7 - 1/5 =
-21/7 + 4/7 - 1/5 =
-(21*5) / (7*5) + (4*5)/(7*5) - (1*7)/(5*7) =
-105/35 + 20/35 - 7/35 =
-105+20-7 / 35 = -92/35
What is the product? Assume x>0.
(√3x + √5)√15x+2√30
O 3x√√5+3√165x+10-√√6
O 3x√5 +6√10x +5√3x +10√/6
O 3x√5+10√6
0 6√3x+10√6
Step-by-step explanation:
well you can distribute the sqrt(15x) to the (√3x + √5) and then combine the radicals using the product property of radicals: [tex]\sqrt[n]{a} * \sqrt[n]{b} = \sqrt[n]{ab}[/tex].
[tex](\sqrt{3x} + \sqrt{5})\sqrt{15x} + 2\sqrt{30}\\(\sqrt{3x} * \sqrt{15x}) + (\sqrt{5} * \sqrt{15x}) + 2\sqrt{30}\\\sqrt{45x^2} + \sqrt{75x} + 2\sqrt{30}\\[/tex]
Now we can simplify the radicals using the same property we used to combine them but instead of combining into one radical we'll separate them into two radicals where one of the radicals simplifies into a number without a radical
[tex](\sqrt{9} * \sqrt{x^2} * \sqrt{5}) + (\sqrt{25} * \sqrt{3x}) + 2\sqrt{30}\\3x\sqrt{5} + 5\sqrt{3x} + 2\sqrt{30}[/tex]
Alison has three times as many dimes as quarters in her purse. She has $9.35 altogether. How many coins of each type does she have?
========================================================
Work Shown:
x = number of quarters
3x = number of dimes
0.25x = value of just the quarters, in dollars
0.10(3x) = 0.30x = value of just the dimes, in dollars
0.25x+0.30x = 0.55x = total value in dollars
0.55x = 9.35
x = (9.35)/(0.55)
x = 17
Alison has 17 quarters and 3x = 3*17 = 51 dimes
17 quarters = 17*0.25 = $4.25
51 dimes = 51*0.10 = $5.10
17 quarters + 51 dimes = $4.25 + $5.10 = $9.35
The answers are confirmed.
can you help me solve this question
Answer: Coordinates: (1,3) length RS: 3 length RT: 2 ST: 3.6
Step-by-step explanation:
a^2+b^2=c^2
3^2+2^2=c^2
9+4=c^2
13=c^2
3.6=c
Estimate the sum
6 13/28 + 8 3/32
Answer:
14 will be the answer...
Step-by-step explanation:
6 13/28 = 6
8 3/32 = 8
6 + 8 = 14
what is 10.465 - (-25.21)
Answer: 35.675
Step-by-step explanation:
10.465−(−25.21)
The opposite of −25.21 is 25.21.
10.465+25.21
Add 10.465 and 25.21 to get 35.675.
35.675
I’m confused nd stuck
Answer:
B. (4,2)
Step-by-step explanation:
The answer is where the lines intersect.
Hope this helps!
If not, I am sorry.
Answer:
(4,2)
Step-by-step explanation:
the solution is where both lines intersect. We would write the point as (x,y). That’s why the answer is (4,2) not (2,4)
help pls i’ll do anything D:
Answer:
search it up ok that's all you can do
Tried every app none have the answer please help
Answer:
opotion has not correct answer
answer is 15.
Answer:
[tex]3^\frac{7}{10}[/tex] or [tex]\sqrt[10]{3^7}[/tex]
Step-by-step explanation:
[tex]\left(\sqrt{3}\right)\left(\sqrt[5]{3}\right)=\sqrt[10]{3^7}\quad[/tex]
(√3)([tex]\sqrt[5]{3}[/tex]) = √3 · [tex]\sqrt[5]{3}[/tex]
{√3 = [tex]3^{\frac{1}{2}}[/tex]} {radical rule: [tex]\sqrt{x}=x^1^/^2[/tex]}
[tex]\sqrt3[/tex][tex]\sqrt[5]{3}[/tex] = [tex]3^{\frac{1}{2}}[/tex] · [tex]\sqrt[5]{3}[/tex]
{[tex]\sqrt[5]{3}[/tex] = [tex]3^{\frac{1}{5}}[/tex]} {radical rule: [tex]\sqrt[n]{x} = x^1^/^n[/tex]}
[tex]3^{\frac{1}{2}}[/tex] · [tex]\sqrt[5]{3}[/tex] = [tex]3^{\frac{1}{2}}[/tex] · [tex]3^{\frac{1}{5}}[/tex] {exponent rule: [tex]a^x*a^y=a^x^+^y[/tex]}
(1/2 + 1/5 = 5/10 + 2/10 = 7/10)
[tex]=3^\frac{7}{10}[/tex] {opposite of radical rule: [tex]\sqrt[n]{x} = x^1^/^n[/tex] ; [tex]x^\frac{a}{b}=\sqrt[b]{x^a}[/tex]}
= [tex]\sqrt[10]{3^7}[/tex]
so, the simplified version of this equation can either be written as:
[tex]3^\frac{7}{10}[/tex] or [tex]\sqrt[10]{3^7}[/tex]
hope this helps!!
(I can't clearly see the last option, but if it's either of these, then it's correct)
cos2pi/7+cos4pi/7+cos8pi/7=1/8
An equation is formed of two equal expressions. The given equation is not true.
What is an equation?An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The complete question is: Check whether the given equation is true or not?cos2pi/7+cos4pi/7+cos8pi/7=1/8.
To know if the given equation, [tex]cos\dfrac{2\pi}{7}+cos\dfrac{4\pi}{7}+cos\dfrac{8\pi}{7}=\dfrac18[/tex] is true or not, both the sides of the equation are needed to be solved separately.
The value of [tex]cos\dfrac{2\pi}{7}+cos\dfrac{4\pi}{7}+cos\dfrac{8\pi}{7}[/tex] when simplified is equal to -0.5, or the value can be written as -(1/2).
Since the right side of the equation is equal to -1/2, while the right side of the equation is 1/8. Thus, the given equation is not true.
Hence, the given equation is not true.
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Peter uses the equation y = StartFraction 13 over 4 EndFraction x to model the number of miles that he has walked in x hours. Which statement is true about the proportional relationship that is modeled by Peter’s equation?
The true statement is Peter walks at a rate of 13 over 4 miles per hour.
What is the true statement?Direct variation is when two variables move in the same direction. If one variable increases, the other variable increases. When the hour Peter walks increases, the distance he walks also increases.
Here are the options:
Peter walks at a rate of StartFraction 4 over 13 EndFraction miles per hour.
Peter walks at a rate of 4 miles per hour.
Peter walks at a rate of StartFraction 13 over 4 EndFraction miles per hour.
Peter walks at a rate of 13 miles per hour.
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tan A + sin A/tan A-sin A
= sec A +1/sec A-1
We need to prove
[tex]\frac{\tan A+\sin A}{\tan A-\sin A}=\frac{\sec A+1}{\sec A-1}[/tex]
[tex]\text{LHS}=\frac{\tan A+\sin A}{\tan A-\sin A}\\\\=\frac{\frac{\sin A}{\cos A}+\sin A}{\frac{\sin A}{\cos A}-\sin A}\\\\=\frac{\sin A+\sin A \cos A}{\sin A-\sin A \cos A}\\\\=\frac{\sin A(1+\cos A)}{\sin A(1-\cos A)}\\\\=\frac{1+\cos A}{1-\cos A}\\\\=\frac{1+\frac{1}{\sec A}}{1-\frac{1}{\sec A}}\\\\=\frac{\sec A+1}{\sec A-1}\\\\ =\text{RHS}[/tex]
What is the missing reason in the proof?
A.) Segment addition
B.) Congruent Segments Theorem
C.) Transitive Property of Equality
D.) Subtraction Property of Equality
Answer:
I think it's C. transitive property of equality
Please help!!!
Consider the segment UV.
Type the correct answer in each box. Use numerals instead of words.
A number is less than 20 units away from 7 on the number line. what numbers are within these parameters? choose the inequality that represents the situation. solve the inequality.
The inequality which represents the situation is; |x - 7| < 20 and the solution is; 27 > x > -13.
What is the inequality that represents the situation?Since the number is less than 20 units away from.the number 7 on the number line, it follows.from interpretation that the inequality is;
|x - 7| < 20
Hence; x-7 < 20; x < 27
Or
-x + 7 < 20
-x < 13
x > -13
Hence, the solution of the inequality is; 27 > x > -13.
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Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?
The function g(x) = ∛(x -3) is positive at the interval x > 3
Complete questionGiven g(x) = ∛(x -3), on what interval is the function positive?
How to determine the positive interval?The function is given as:
g(x) = ∛(x -3)
Set the radicand to positive
x - 3 > 0
Add 3 to both sides
x > 3
Hence, the function is positive at the interval x > 3
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What is the value of y?
Enter your answer in the box
Y=_
Answer:
the angles of a triangle always equal 180 so
34+x-5+4y=180
simplify
29+x+4y=180
-29
x+4y=151
-4y
x=-4y+151
then put this into the original equation
29-4y+151+4y=180
simplify
29+151=180
so this proves that this works
-1/4x-151=y
Hope This Helps!!!
Use the multiplication law for logarithm to expand the following expression:[tex]log_{8} (21)[/tex]
- worth 20pt
Answer:
[tex]\log_8{(3)} + \log_8{(7)}[/tex]
Step-by-step explanation:
Product Rule for Logarithms
[tex]\log_b{(mn)} = \log_b{(m)} + \log_b{(n)}[/tex]
Instead of 21 you can write 3 · 7, because 21 = 3 · 7.
[tex]\log_8{(21)} = \\= \log_8{(3 \cdot 7)} =\\= \log_8{(3)} + \log_8{(7)}[/tex]
What is the midpoint of the class interval 80-89?
The midpoint of the class interval 80-89 is 84.5.
What is mid point of a class interval?The mid point of a class interval is also called the class mark of the class interval.
The midpoint is defined as the average of the upper and lower class limits.
Therefore, the midpoint of the class interval 80-89 can be calculated as follows:
mid point = 80 + 89 / 2
mid point = 169 / 2
mid point = 84.5
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2(2x – 1) + 7 < 13 or –2x + 5≤-10
Answer:
x<2 or x ≥ 15/2
Step-by-step explanation:
HELP ASAP PLS ILL MARK YOU BRAINLIEST
Answer:
c is the answer.
This should be easy. Answer it please :D
Answer:
is it 1 ques or 4 different questions?
Given the function, f(x)=√x-2 +3, choose the correct transformation.
right 2, up 3
Right2, down 3
left 2, up 3
left 2, down 3