If an object's velocity versus time graph is a horizontal line the object is travelling at constant velocity which means the object is not accelerating at all.
Claudia is performing an experiment, testing to see if decreasing the temperature in which pea plants are growing makes them flower sooner. In this experiment, what are some values that Claudia will want to hold constant. (Choose all that apply)
a.which day the plants begin to flower
b.the amount of light the plants get
c.the temperature the plants are grown in
d.the type and amount of fertilizer used
e.the amount of water the plants get
Claudia is performing an experiment, testing to see if decreasing the temperature in which pea plants are growing makes them flower sooner which means that some values that Claudia will want to hold constant include the following below:
b.the amount of light the plants get.
d.the type and amount of fertilizer used.
e.the amount of water the plants get.
What is an Experiment?This refers to a procedure which is carried out by scientists in other to support or refute a hypothesis and is usually done in the laboratory. It is also used to ascertain the authenticity of a claim and consists of two types of variables which are constant and control variables.
The constant variables doesn't change and is applied uniformly to all the specimens. In this scenario they include the amount of light, fertilizer and water the plants gets.
Controlled variables are the ones which are changed and its varied application on different specimens are used to measure the effect and in this case an example is the temperature the plants are grown in because the test involves this parameter.
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A car initially has a velocity of 29 m/s starts to increase its velocity at a constant rate of 2.4 m/s2, for a distance of 22 m. What is its final velocity?
Answer:
vf=43.55m/s
Explanation:
Data:
vi=29m/s
S=22m
a=2.4 m/s^2
vf=? we are supposed to find final velocity.
we will use following equation of motion:
Formula:
[tex]2as=vf^{2} -vi^{2}[/tex]
put values
[tex]2(2.4)(22)=vf^2-(29)^2\\[/tex]
solving for [tex]vf^2[/tex].
taking [tex](29)^2[/tex] on the other side .
[tex]vf^2=2(2.4)(22)+(29)^2[/tex]
solve square first.
[tex]vf^2=2(24)(22)+841[/tex]
multiply the terms.
[tex]vf^2=1056+841[/tex]
add the terms
[tex]vf^2=1897[/tex]
taking square root on both sides.
[tex]\sqrt{vf^2}=\sqrt{1897}[/tex]
square root of [tex]vf^2[/tex] will be cancelled out .
[tex]vf=43.55m/s[/tex]
You make a capacitor by cutting the 14.5-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.35 mm , and connecting them across a 6.00 V battery.
If you disconnect the battery and separate the plates to a distance of 3.50 cm without discharging them, what will be the potential difference between them?
Express your answer to three significant figures with the appropriate units.
From the definition of capacitance, the potential difference between them will be 6.24v
What is Capacitance of a capacitor ?The capacitance of a capacitor is the ratio of charge to the voltage supplied. It is measure in Farad.
If you make a capacitor by cutting the 14.5-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.35 mm , and connecting them across a 6.00 V battery, the cross sectional A = πr²
where r = 14.5/2 = 7.25 cm
r = 7.25/100 = 0.0725 m
The distance d = 3.35 mm = 3.35/1000 = 0.00335 m
A = πr²
A = 22/7 × 0.0725²
A = 0.0165 m²
Capacitance is proportional to the area of the plate and inversely proportional distance between them. That is,
C = ξA/d
where ξ = 8.5 × 10^-12 C²/Nm²
C = (8.5 × 10^-12 × 0.0165) / 0.00335
C = 4.19 × 10^-11 F
From Charge Q = CV
Q = 4.19 × 10^-11 × 6
Q = 2.5 × 10^-10 C
If you disconnect the battery and separate the plates to a distance of 3.50 cm without discharging them, the capacitance will be
C = ξA/d
C = (8.5 × 10^-12 × 0.0165) / 0.0035
C = 4.007 × 10^-11
From Q = CV
V = Q/C
V = 2.5 × 10^-10 / 4.007 × 10^-11
V = 6.24 v
Therefore, the potential difference between them will be 6.24v
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I need help in this…
Diffraction is the spreading out of waves past small openings and the bending of waves around small obstructions.
What is diffraction ?Diffraction is the process by which light spreads out after passing through a small space or bends around an obstruction. Diffraction can occur in waves of any kind, including sound, radio, and water.
What is diffraction in sound wave?When an object has dimensions that are close to or smaller than the sound wave's wavelength, it causes a sound wave to move around it.
Waves spread out as they move through an aperture or around objects, which is known as diffraction. It happens when the aperture's or obstacle's size is of the same order of magnitude as the wave's wavelength. Nearly all of the wave is blocked at very small aperture sizes.
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What does a coat do?
O Coats speed up heat transfer.
O Coats make people cooler.
O Coats slow heat transfer.
O Coats make people warmer.
Answer: Coats make people warmer.
Explanation: Coats help keep us warm due to the fillings inside the materials.
A vector has an x component of -25.5 units and a y component of 36.6 units. Find the magnitude and direction of this vector.
the magnitude and direction of this vector is cos −1√ (−5/ 89)
Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.
A constant quantity's magnitude is a numerical value for the quantity expressed in terms of a unit of measurement. For instance, the real number 2000 is the magnitude of the quantity 2 kilometers in the unit-of-measure meter.
Magnitude = (25) 2 + (40) 2 =5√89
Angle with the x-axis equals tan√ 1(y/x).
=tan −1 √ (40/−25)
=tan −1√ (−8/5)
=cos −1√ (−5/ 5 √2+6/2)
=cos −1√ (−5/ 89)
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A student performed a sphere drop experiment. The sphere was dropped from 1.50 m above the ground and the sphere has
a mass of 0.875 kg. Free fall times for the student's experiments are below.
a. Before the student calculates the acceleration due to gravity from the data, are there any trials that should be thrown
out? Justify your choice.
The experimental value of the expression due to gravity through the experiment will come out to be 7.8 u, the error in the value has Accord because of air friction.
What is Newton's law of motion?Newton gave three laws of motion which can be utilised to find the velocity, acceleration and displacement of a body. These laws are only applicable for constant acceleration.
What is free fall?When a body falls freely under only the force of gravitation due to the earth and no other force act on the body is known as free fall.
Given:
Mass of the sphere is 0.875 kg
Height of the free fall is 1.5 metre
Experiments are conducted in the following manner:
First the bob will be released and from the point that it is being released we will measure the distance using the inch tape we will also calculate the time it takes for the bob to hit the ground.Using the speedometer will measure the final velocity before it is the ground.Now using Newton's first law of motion we can derive the acceleration due to gravity we know the final velocity using the speedometer the distance it has covered and the time it has taken to complete that distance.Using Newton's first law of motion
i.e. v = u + a × t
Where,
u is initial velocity
v is final velocity
a is acceleration due to gravity
t is time taken to cover distance
From the data given v = 15.6 m/s
t is 2 seconds
Substituting value in Newton's first law of motion we get
Value of acceleration due to the gravity = 7.8u
Therefore, The experimental value of the expression due to gravity through the experiment will come out to be 7.8 u , the error in the value has Accord because of air friction.
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A CT scan uses a rotating X-ray source mounted on a circular ring to capture three dimensional images of a body (see Figure
43.2 on page 521 of the textbook). One rotation of the X-ray source produces one sliced image of the body.
A specific CT scan machine has a circular ring with radius 44 cm (diameter 88 cm), and the mass of the X-ray source mounted
on the circular ring is 26 kg. The ring rotates at a constant rate of 21 rad/s. Answer the following questions.
(a) What is the tangential speed of the X-ray source in m/s?
(b) How many degrees does the X-ray source turn in 100 milliseconds?
(c) What is the magnitude of the centripetal force on the X-ray source?
(d) How many seconds does it take to take one image?
(e) What is the frequency of the rotation of the X-ray source in the unit of Hz?
Answer:
rsgc
Explanation:
bsf xg
why does the acceleration due to gravity have to be measured in an airless tube?
It is measured in the airless tube because there is no air to offer resistance to the fall of the object.
What is the acceleration due to gravity?The acceleration due to gravity refers to the acceleration that is imparted to a body because of its movement in the earth's gravitational field. Irrespective of mass, all objects move with the same acceleration in the earth gravitational field.
If air is present, air resistance makes it appear as if different masses are accelerated to different amounts. Thus, the acceleration due to gravity is measured in an airless tube the where there is no air to offer resistance to the fall of the object.
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An electric field of 8.5x105 V/m is desired between two parallel
plates, each of area 45 cm7 and separated by 2.45mm of air. What
charge must be on each plate?
The charge that must be on each plate is 3.53 x 10⁻⁸ C.
Electric field between two parallel platesThe electric field between two parallel plates is given as;
C = εA/d
C = Q/V
V = Ed
C = Q/Ed
Q/Ed = εA/d
Q/E = εA
Q = εEA
where;
ε is permittivity of free spaceE is electric field strengthA is the area of the plateQ is the chargeQ = (8.85 x 10⁻¹² x 8.85 x 10⁵ x 45 x 10⁻⁴)
Q = 3.53 x 10⁻⁸ C
Thus, the charge that must be on each plate is 3.53 x 10⁻⁸ C.
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1. What if the acceleration of an object is equal to zero? Acceleration is still a constant, but it just happens to be zero. In this special case, what are the equations of motion?
Answer: zero acceleration is zero acceleration, not constant acceleration.
Explanation:
Galileo carried out his seminal free-fall experiment using an inclined plane. Why is such an approach feasible, and some-
times preferable to the simple drop method, for determining g?
For determining g (gravity), seminal free-fall experiment using inclined plane is preferable to the simple drop method because in simple drop method there is resistance caused by air on the falling object whereas on the seminal free-fall method using inclined plane air resistance has little to no effect.
Galileo was an Italian scientist who combined theory with experiment. He was very much interested in understanding the movement and falling of objects.
Objects when falling down would accelerate quickly i.e., let’s take an object falling at the speed of x, after time t it would travel at 2x, after 2t it would be 4x. Therefore, it is difficult to time with accuracy. Thus, inclined plane would help to dilute the effects of gravitational force and reduce the time.
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At t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT . At the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
1.) At what time does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
t=
2.) At what coordinate does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
x =
1. The truck overtakes the car at time t = 2vC/(aT - aC)
2. The coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
The question has to do with equation of motion
What are the equations of motion?The equations of motion are equations that are used to describe the motion of an object under constant acceleration.
1.) At what time does the truck pass the car?
Since at t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT.
We find the distance moved by the truck using the equation of motion d = ut + 1/2at² where
u = initial speed of truck = 0 m/s(since it starts at rest) a = acceleration of truck = aTSo, d = ut + 1/2at²
d = 0 × t + 1/2aTt²
d = 1/2aTt²
Also, at the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
We find the distance moved by the car using the equation of motion D = ut + 1/2at² where
u = initial speed of car = vC a = acceleration of car = -aCSo, D = ut + 1/2at²
D = vCt + 1/2(-aC)t²
D = vCt - 1/2aCt²
The truck over takes the car when d = D
So, 1/2aTt² = vCt - 1/2aCt²
1/2aTt² - 1/2aCt² - vCt = 0
[(aT - aC)t/2 - vC)]t = 0
⇒ t = 0 or (aT - aC)t/2 - vC = 0
⇒ t = 0 or (aT - aC)t/2 = vC
⇒ t = 0 or t = 2vC/(aT - aC)
So, the truck overtakes the car at time t = 2vC/(aT - aC)
2.) At what coordinate does the truck pass the car?Since the distance moved by the truck is d = x - 0
= 1/2aTt², where x = coordinate where truck passes car.
To find the coordinate where the truck passes the car, we susbstitute the time where the truck passes the car into d. So, t = 2vC/(aT - aC)
So, x - 0 = 1/2aTt²
x = 1/2aT[2vC/(aT - aC)]²
x = 2aT[vC/(aT - aC)]²
So, the coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
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There are numerous starting points that a composer could use when writing a piece of music.
A. True
B. False, dynamics and tempo are the only starting points
C. False, composers never us a starting point
D. False, structure is the only starting point
There are numerous starting points that a composer could use when writing a piece of music. True.
Composers write, direct, and create tunes for numerous genres. they will produce compositions, scores, and preparations for theatre, movies, television, and even video games. Composers have fantastic musical ears and frequently advocate for musicians.
A music style or subgenre may be described by using the musical techniques, the cultural context, and the content material and spirit of the themes. The geographical foundation is once in a while used to perceive a song style, even though a single geographical category will often encompass a wide style of subgenres.
Dynamics manner how quietly or loudly a bit of track ought to be performed. Dynamics are an essential way of conveying the mood of a bit and your use of dynamics is a marked detail of your performance. Composers use dynamics to trade the temper.
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please help:((( If you run 60 m in 7 seconds, then run 25 m in 4 seconds, what is your average speed for the entire run?
Answer:22m
Explanation:
gina wants to find out if the temperature of water affects the solubility of a material. here are the variables in her experiment. she get three containers of equal size and labelled them A, B and C. then pour 50ml of hot water in container A, 50ml of lukewarm water in container B, and 50ml of cold water in container C, she then pour 1 teaspoon of salt in each container and stir it fo three minutes. then observes the result
The temperature of water affects the solubility of material the ability of a material, the solute, to combine with another substance, the solvent, is known as solubility in chemistry.
The contrary is appropriate for insoluble except in extremely rare circumstances, a solid or liquid cannot be "dissolved" in gas without first becoming gaseous composition of the solute and solvent, including their pH and the presence of other dissolved substances, as well as temperature and pressure, are the key determinants of solubility. The dependence is frequently explicable in terms of interactions between the atoms, molecules, or ions of the two substances as well as in terms of thermodynamic notions like enthalpy and entropy.
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What are the internal resistance and voltage rating of a 420 Watt automatic washing machine that draws 1.75 Ampere?
The internal resistance of the washing machine is 137.14 Ω.
What is internal resistance?Internal resistance is the inherent resistance of a conductor.
To calculate the internal resistance of the washing machine, we use the formula below.
Formula:
P = I²R................... Equation 1Where:
P = Power of the washing machineI = CurrentR = Internal Resistance of the washing machine.Make R the subject of the equation
R = P/I²................ Equation 2From the question,
Given:
I = 420 WR = 1.75 ASubstitute the these values into equation 2
R = 420/1.75²R = 137.14 ΩHence, the internal resistance of the washing machine is 137.14 Ω.
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A student is running at her top speed of 5.5 m/s to catch a bus, which is stopped at the bus stop. When the student is still a distance 40.4 m from the bus, it starts to pull away, moving with a constant acceleration of 0.173 m/s^2.
(a) For how much time does the student have to run at 5.5 m/s before she overtakes the bus?
(b) For what distance does the student have to run at 5.5 m/s before she overtakes the bus?
(c) When she reaches the bus, how fast is the bus traveling?
(d) If the student's top speed is 2.70 m/s , will she catch the bus?
(a) The time taken before the student catches the bus is 11.52 seconds.
(b) The distance the student have to run before she overtakes the bus is 63.36 m.
(c) The speed of the bus is 2.0 m/s.
(d) If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.
Time elapsed before the student over takes the busApply the principle of relative velocity as follows;
(Vs - Vb)t = D
where;
Vs is the velocity of the studentVb is the velocity of the bust is the time in which the student catches the busD is the distance between them(Vs - at)t = D
where;
a is the acceleration of the bus(5.5 - 0.173t)t = 40.4
5.5t - 0.173t² = 40.4
0.173t² - 5.5t + 40.4 = 0
solve the quadratic equation using formula method;
a = 0.173, b = -5.5, c = 40.4
t = 11.52 seconds or 20.27 seconds
so the minimum time taken by the student to over take the bus is 11.52 seconds
Distance the student have to run to overtake the busd = vt
d = 5.5 m/s x 11.52 s = 63.36 m
Speed of the busv = at²
v = 0.173 x (11.52)
v = 2.0 m/s
If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.
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A pet store surveyed 625 people to see how many own a bird, how many own a dog, and how many own a cat.
The Venn diagram below shows the results. (Each number gives the number of people who fall into that Venn diagram category.)
All people in the survey-
Own a
bird
Own a
dog
115
103
49
138
61
33
34
Own a
cat
92
(a) How many of the people own exactly two of the three types of animals?
people
(b) How many of the people don't own a dog?
people
(c) How many of the people own neither a cat nor a bird, but do own a dog?
people.
The people who own all the three animals are 33 , (b) People who don't own a dog are 244 and (c) People who neither own a cat nor a bird but own a dog are 34 in number.
What is a Venn diagram?A Venn diagram is a representation of data in terms of figure. Where each circle represents a set of data, intersection of two or more circles shows that there is a common entity in both the sets.
What is a universal set in Venn diagram?A universal set contains all the possible elements. In Venn diagram a universal set is represented by a rectangle.
Given:
Total number of the people surveyed = 625
People who one a cat = 115
People who own a bird = 103
People who own a dog = 34
1) To find the number of people who own all the three animals we will have to find the intersection of C, B and D.
Where,
C represents set of cat
B represents set of bird
D represents set of dog
// Represents intersection
:: Represents union
From the given data
C//B//D = 33
i.e. people who own all the three animals = 33
2) People who don't own a dog.
Now carefully look at the given diagram you will notice:
34 own D only
138 own D and C
92 own D and B
33 own all the three
Now to find who doesn't own a dog we will find who owns a dog and then minus that from total people who owns animals.
Total people who own an animal= (115+103+34+138+61+92-2×33)
Total people who own an animal = 475
Now people who own a dog = 34+138+92-33
People who own a dog = 231
People who don't own a dog = 475-231
People who don't own a dog = 244
3) People who neither own a cat nor a bird but own a dog = 34
Therefore, the people who own all the three animals are 33 , People who don't own a dog are 244 and People who neither own a cat nor a bird but own a dog are 34 in number.
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The position-time equation of motion for a bunny hopping across
a yard is
x = 8.3 m+ (2.2 m/s)t
What is the initial position of the bunny?
Answer:
8.3 m
Explanation:
The initial position of the bunny is at time t = 0
x = 8.3 + 2.2 (0) = 8.3 m
The initial position of a bunny hopping across a yard is 8.3 meters.
What is the position?It is the location of the object in relation to time, when the object starts moving it is changing its position in relation to time. When the position of an object keeps changing then the displacement of an object can be calculated as the reference point is necessary to calculate the position, and it also shows the direction, therefore, it is a vector quantity. The graph of position and time gives us the velocity of the object.
Given: The position time equation of the object;
x = 8.3 + 2.2 t (x is the distance / position, t is time in seconds)
so for the initial position, time will be zero (t = 0);
Therefore, at t = 0 the position will be;
x = 8.3 + 2.2 ×0
x = 8.3 meters
Hence, the initial position of the bunny hopping across a yard is 8.3 meters.
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what is kineamatics (60 words)
Kinematics is the study of motion of an object without considering the forces that caused the object to move.
Kinematics is a branch of mechanics, which is used to study about mechanical bodies or mechanical systems without the reference of the body's/system's physical properties or the forces acting on it.
Kinematics models different motion mathematically with the help of algebra. Therefore, it is referred as geometry of motion. The modelling is done to calculate the various factors of motion such as speed, acceleration etc.
Therefore, Kinematics is the study of motion of an object without considering the forces that caused the object to move.
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A police radar's effective range is 0.90 km , and your radar detector's range is 1.9 km . You're going 110 km/h in a 70 km/h zone when the radar detector beeps. At what rate must you negatively accelerate to avoid a speeding ticket?
Negative acceleration of 0.2 m/s^2 is needed to avoid a speeding ticket.
Negative acceleration occurs when a force causes a body's velocity to decrease. Positive acceleration occurs when the speed of something rises.
The acceleration of a slowing object is in the direction opposite from the velocity. As a result, this item is said to have negative acceleration.
Given:
Initial velocity, u = 110km/h
Final velocity, v = 70km/h
Police radar's effective range, S1 = 0.90km
Radar detector's range, S2 = 1.9km
To find:
Negative acceleration, a = ?
Formula:
v^2 = u^2 + 2aS
Calculation:
a = (v^2 – u^2) / 2(S1 - S2)
a = 70^2 – 110^2/ 2 x (0.9 – 1.9)
a = [(4900 – 12100) / (2 x -1)] / 3600^2
a = 0.2 m/s^2
Result:
0.2m/s^2 negative acceleration is required to avoid a speeding ticket.
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Question) A convex mirror has a radius of curvature of 28.4 cm. If you hold a 16-cm-long pencil 23.5 cm in front of the mirror, what will the image position and image height be?
I know the answer but I need the steps could anyone please help me asap?
Answer
di = -8.85 cm; hi = 6.0 cm
The distance of the image formed is -8.85 cm and the height of the image is 6.02 cm.
Image distanceThe position of the image formed is calculated as follows;
-1/f = 1/v + 1/u
where;
f is the focal length = r/2 = 28.4 cm /2 = 14.2 cmu is object distance = 23.5 cmv is the image distance1/v = -1/f - 1/u
1/v = -/14.2 - 1/23.5
1/v = -0.112975
v = -1/0.112975
v = -8.85 cm
Height of image formedThe height of the image formed is calculated as follows.
Use magnification equation;
image distance/object distance = image height / object height
v/u = hi/h0
8.85/23.5 = hi/16
hi = (8.85/23.5) x 16
hi = 6.02 cm
Thus, the distance of the image formed is -8.85 cm and the height of the image is 6.02 cm.
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If a small motor does 200 J of work to move a toy car 40 m, what force does it exert?
The force exerted during a work of 200 J done to move a toy car 40 m is 5 N
W = F * d
W = Work done
F = Force
d = Distance
W = 200 J
d = 40 m
F = W / d
F = 200 / 40
F = 5 N
The force exerted to move an object is work done. It is denoted as W. Its unit is Joules.
Therefore, the force exerted is 5 N
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12. (a)
(i) What is meant by the term artificial radioactivity?
A car crash gives out great force. These are reasons for the great force EXCEPT:
A- high car speed
B- a long time to stop
C huge car weight
D- huge deceleration
In school, Jarrett learned that salt lowers the freezing point of water. He wants to test this in a home experiment. He combines 1.0 grams of salt and 500 milliliters of water in a container. In an identical container, he pours 500 milliliters of water and does not add salt to it.
What should Jarrett do next?
A.
Place the salt water in a freezer and the pure water in a refrigerator.
B.
Mix the two samples of water together in a 1.0-liter container, and bring them to a boil on a stove.
C.
Place both containers in a freezer, and record the temperatures at which they begin to freeze.
D.
Place the pure water in a freezer and the salt water in a refrigerator.
Answer:
I think it's C but I'm not 100% sure
A cheetah can accelerate from rest to a speed of 30m/s in 7.0s . What is its acceleration?
The acceleration of the cheetah is 4.29 m/s².
What is acceleration?Acceleration can be defined as the rate of change of velocity.
To calculate the acceleration of theb cheetah, we use the formula below.
Formula:
a = (v-u)/t........... Equation 1Where:
a = Acceleration of the cheetahv = Final velocity of the cheetahu = Initial velocity of the cheetaht = time.From the question,
Given:
v = 30 m/su = 0 m/s (from rest)t = 7.0 sSubstitute these values into equation 1
a = (30-0)/7a = 4.29 m/s²Hence, the acceleration of the cheetah is 4.29 m/s².
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a bus is about to leave in exactly 5 seconds. you are 20 meters away. how fast do you need to run to get to the bus? give your answer in m/s. round 2 significant figures
A bus is about to leave in exactly 5 seconds. You are 20 meters away. With a speed of 4 m/sec you will be able to catch the bus on time.
What do you understand by the term Distance, Speed and Time?By dividing the distance traveled by the time required to complete that distance, speed is calculated. For a specific distance, it provides the travel time / distance.
Speed and distance are tightly related, whereas time and distance have an inverse relationship. Speed times the passing of time equals distance.
Distance divided by speed is how time is calculated; as speed rises, time slows down, and vice versa.
What is the calculation for the above problem?Given
Time = 5 secs
Distance = 20 m
On putting the values in the given formula we get,
Speed = Distance / Time
Speed = 20 m / 5 secs
Speed = 4 m/secs
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A car going initially with a velocity 13.5 m/s accelerates at a rate of 1.9 m/s2 for 6.2 s. It then accelerates at a rate of minus2.5 m/s2 until it stops. What is the total time from the start of the first acceleration until the car is stopped? (Write your answer to two decimal places and do not write unit)
The total time from the start of the first acceleration until the car is stopped is 16.31 s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the final velocity in the first 6.2 s Initial velocity (u) = 13.5 m/sAcceleration (a) = 1.9 m/s²Time (t) = 6.2 s Final velocity (v) = ?a = (v – u) / t
1.9 = (v – 13.5) / 6.2
Cross multiply
v – 13.5 = 1.9 × 6.2
v – 13.5 = 11.78
Collect like terms
v = 11.78 + 13.5
v = 25.28 m/s
How to determine the time to stop the car Initial velocity (u) = 25.28 m/sFinal velocity (v) = 0 m/sAcceleration (a) = -2.5 m/s² Time (t) =?a = (v – u) / t
Thus,
t = (v – u) / a
t = (0 – 25.28) / –2.5
t = 10.112 s
How to determine the total timeTime for the the first acceleration = 6.2 sTime to stop the car = 10.112 sTotal time =?Total time = 6.2 + 10.112
Total time = 16.31 s
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