If this person's far-point distance with her contacts is 8.5 m, what is her uncorrected for point distance?

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Answer 1

If a person's far-point distance with their contacts is 8.5 m, what is their uncorrected far-point distance?The far point of the human eye is the farthest point to which it can focus without straining. For a normal eye, this distance is usually infinity.

When the image formed on the retina is not clear, the distance from the eye to the farthest point to which the eye can focus is called the far-point distance. The ability of an eye to focus on distant objects is its capacity.

If the person's far-point distance with her contacts is 8.5 meters, her uncorrected for point distance can be calculated by using the following formula: Diopter = 100 cm / focal length in meters Using the above formula we have:Focal length = 100 cm / Diopter Focal length = 100 cm / 8.5 meters = 11.76 cm

Uncorrected for point distance = 1 / (focal length) Uncorrected for point distance = 1 / 0.1176 metersUncorrected for point distance = 8.49 meters

Therefore, the uncorrected for point distance of the person's eye is 8.49 meters.

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a 4700 kg railcar hits a bumper (a spring) at 1.9 m/s, and the spring compresses by 0.06 m. assume no damping.

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Given that a railcar of mass 4700 kg hits a bumper at 1.9 m/s and the spring compresses by 0.06 m, we are required to determine the force exerted by the spring on the railcar.

Using the formula for the force exerted by a spring, we get:F = kxwhereF = force exerted by the springk = spring constantx = compression of the springWe need to determine the spring constant k.To find the spring constant k, we use the formula,k = F / xWhere F is the force exerted by the spring and x is the distance by which the spring is compressed. In this case,x = 0.06 m, and the force exerted by the spring can be found as follows:The initial kinetic energy of the railcar is converted into elastic potential energy of the spring.

The total energy of the system is conserved, hence:1/2 mv² = 1/2 kx²wherev = 1.9 m/s (initial velocity)m = 4700 kg (mass of the railcar)x = 0.06 m (compression of the spring)k = spring constantRearranging the above formula, we can find k as,k = m v² / x²k = 4700 × 1.9² / 0.06²k = 5.872 × 10⁷ N/mNow that we have found the spring constant, we can use it to determine the force exerted by the spring:F = kx = 5.872 × 10⁷ × 0.06 = 3.523 × 10⁴ NTherefore, the force exerted by the spring on the railcar is 3.523 × 10⁴ N. Hence, F = 3.523 × 10⁴ N ,Here, we have made use of the spring formula which states thatF = kxwhereF = force exerted by the springk = spring constantx = compression of the springWe have determined the spring constant k ask = m v² / x²and then used it to find the force exerted by the spring on the railcar.

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find f , the magnitude of the force applied to each side of the nutcracker required to crack the nut. express the force in terms of fn , d , and d .

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To find the magnitude of the force applied to each side of the nutcracker required to crack the nut, we need to use the formula: F = (2Fn*d) / D. where F is the required force, Fn is the force applied by each side of the nutcracker, d is the distance between the pivot point and the nut, and D is the distance between the pivot point and the point where the force is applied.

So, the magnitude of the force required to crack the nut can be expressed as F = (2Fn*d) / D. This formula shows that the magnitude of the force required to crack the nut is directly proportional to the force applied by each side of the nutcracker (Fn), and the distance between the pivot point and the nut (d), and inversely proportional to the distance between the pivot point and the point where the force is applied (D).

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