We will apply the Pythagoras theorem to find the measure of the unknown leg in a triangle when one leg and the hypotenuse are provided dimensions.
What is the definition of a right-angle triangle?It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometric function.
According to Pythagoras, the sum of the squares of two sides equals the square of the longest side.
[tex]\rm h^2 = p^2+ b^2[/tex]
Where,
h is the hypotenuse
p is the perpendicular
b is the base
If any of the two is given the third side will be obtained using the Pythagoras theorem.
In a triangle with given measurements for one leg and the hypotenuse, we will determine the measure of the unknown leg by the Pythagoras theorem.
Hence we willl apply the pythogorous theorem for finding the unknown side.
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HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELP
Answer:
C.
Step-by-step explanation:
Adding 2 fractions results in a fraction.
Answer:
B: The sum is a non-terminating and a non-reapeating decimal
Step-by-step explanation:
-11/4 +5/g
There is 15 steps you have to do after (look in the picture)
but this is what you get:
[tex]-\frac{11g-20}{4g}[/tex]
What are the solutions of 2x² - 6x+5=0?
Answer:
no solutions
Step-by-step explanation:
we use the quadratic formula.
for an equation ax²+bx+c=0, the solutions for x are:
x = (-b±sqrt(b²-4ac))/2a
in our case, a=2, b=-6 and c=5, so:
x= (6±sqrt(36-40))/4
we see that we get a negative number inside the sqrt, so we have no real solutions
Answer:
No solution
Step-by-step explanation:
1) Use the quadratic formula
[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
[tex]2x^2-6x+5=0[/tex]
[tex]a=2\\b=-6\\c=5[/tex]
[tex]x=\frac{-(-6)\pm\sqrt{(-6)^2-4*2*5} }{2*2}[/tex]
2) Simplify
Evaluate the exponent:
[tex]x=\frac{6\pm\sqrt{(-6)^2-4*2*5} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{36-4*2*5} }{2*2}[/tex]
Multiply the numbers:
[tex]x=\frac{6\pm\sqrt{36-4*2*5} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{36-40} }{2*2}[/tex]
Subtract the numbers:
[tex]x=\frac{6\pm\sqrt{36-40} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{-4} }{2*2}[/tex]
Multiply the numbers
[tex]x=\frac{6\pm\sqrt{-4} }{2*2}[/tex]
[tex]x=\frac{6\pm\sqrt{-4} }{4}[/tex]
3) No real solutions because the discriminant is negative
The square root of a negative number is not a real number
[tex]d=-4[/tex]
Result
No solution
Which rule describes a composition of transformations the maps pre-image PQRSto image P”Q”R”S”
The rule that describes the composition of transformations that maps figure PQRS to figure P"Q"R"S"is r y-axis • RO, 90° (x, y)
How to determine the transformation?See attachment for complete question
From the image, we have:
P = (1,1)
Q = (1,5)
R = (3,5)
S = (3,1)
Start by reflecting PQRS across the y-axis. i.e. r y-axis
This is done by
(x, y) -> (-x,y)
So, we have:
P' = (-1,1)
Q' = (-1,5)
R' = (-3,5)
S' = (-3,1)
Next, we rotate by 90 degrees counterclockwise i.e. RO, 90° (x, y)
This is done by
(x, y) -> (-y, x)
So, we have:
P'' = (-1,-1)
Q'' = (-5,-1)
R'' = (-5,-3)
S'' = (-1,-3)
Hence, the rule that describes the composition of transformations that maps figure PQRS to figure P"Q"R"S"is r y-axis • RO, 90° (x, y)
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2/6+5/6 as a whole number
Answer: 2/6+5/6 + 1.167
Answer:
1.16
Step-by-step explanation:
Solve for h in A = ½ ah - ½ bh. Solve for h in A = ½ ah - ½ bh .
Answer:
h = A / ( 1/2 a - 1/2 b)
Step-by-step explanation:
A = ½ ah - ½ bh
Factor out an h
A = h( 1/2 a - 1/2 b)
Divide each side by ( 1/2 a - 1/2 b)
A / ( 1/2 a - 1/2 b) = h ( 1/2 a - 1/2 b)/ ( 1/2 a - 1/2 b)
A / ( 1/2 a - 1/2 b) = h
h = A / ( 1/2 a - 1/2 b)
A table of data is given.
x: -2, -1, 0, 1, 2
f(x): 128, 27, 5, 1, 0.1
Which exponential model best represents the data?
A. f(x) = 5(1.2)^x
B. f(x) = 5(0.2)^x
C. f(x) = 2(5)^x
D. f(x) = 2(0.5)^x
The exponential model best represents the data is B. f(x) = 5(0.2)^x
How to determine the exponential model?From the table of values, we have the following points:
(x, y) = (0,5) and (1,1)
An exponential model is represented as:
y = ab^x
Substitute (x, y) = (0,5)
5 = ab^0
5 = a
This gives
a = 5
So, we have:
y = 5b^x
Substitute (x, y) = (1,1)
1 = 5b^1
This gives
5b = 1
Divide by 5
b = 0.2
Substitute b = 0.2 in y = 5b^x
y = 5(0.2)^x
Hence, the exponential model best represents the data is B. f(x) = 5(0.2)^x
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Just a question about the problem, dont need the answer if you dont want to solve it, but would 15 be negative? Thats all, Thanks!
[tex]f(x)=x^{2} +15x+3[/tex]
Answer:
[tex]x = -\frac{15}{2}[/tex]
Step-by-step explanation:
Hello!
The formula for the AOS is given to you, and you simply have to plug in the information given by the equation.
Equation of a Parabola (Standard): [tex]y = ax^2 + bx + c[/tex]
Comparing it to our equation:
a = 1b = 15c = 3Plug it in to the AOS formula:
[tex]x = \frac{-b}{2a}[/tex][tex]x = \frac{-15}{2(1)}[/tex][tex]x = -\frac{15}{2}[/tex]You only have to input 15 in to the correct box since the negative sign is already placed for you.
solve for 2.5w+12 on a graph
x-intercept -4.8
y-intercept 12
slope 2.5
plot points
x y
-2, 7
-1, 9.5
0, 12
1, 14.5
2 ,17
Match each data set with its standard deviation.
Round your answer to the nearest tenth, if necessary.
Click on the link to use the GeoGebra graphing calculator to assist you.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
{74,76,77,77,78,82,130}
{8,74,76,77,77,78,82}
{74,74,76,77,77,78,82}
Answer:
don't know but please keep trying up
Figure it out..............................................
4. Minnie bought 6 postcards during 3 days of vacation. After 8 days of vacation, how many total postcards will Minnie have bought?
A. 4
B. 5
C. 16
D. 12
whats is 452 divided by2
Answer:
452/2 = 226
Step-by-step explanation:
45 divided by 2 is 22 and the remainder would be 12, which could be divided by 2 again to get 6. Add this to the total and you get 226.
Hope this helps! :D
Help! Will mark the big B for correct answer!
Answer:
The answer is A
Step-by-step explanation:
They both have a maximum of 5!
Which foundation drawing matches this orthographic drawing?
The figure second represents the foundation drawing of a provided front, right, and top view option second is correct.
What is orthographic drawing?Three-dimensional objects can be represented in two dimensions via an orthographic projection.
As we have given orthographic drawings.
The front, right, and the top view is shown in the picture of the cuboid if merge all the view we will find the three-dimensional figure is a cuboid.
We can represent the cuboid by 2×3 grids as shown in the picture second.
Thus, the figure second represents the foundation drawing of a provided front, right, and top view option second is correct.
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Solve the simultaneous equations below.
7x-6y = 30
2x+6y= 24
Answer:
(x,y)—>(6,2)
Step-by-step explanation:
Add both equations to eliminate y
9x=54
x=6
plug x=6 into either equation
2(6)+6y=24
6y=24-12
y=12/6=2
The diagram below shows a square inside a regular octagon. The apothem of the octagon is 15.69 units. To the nearest square unit, what is the area of the shaded region? 13 U 13 U Apothem length: 15.69 O A. 1463 square units B. 816 square units C. 647 square units OD. 764 square units
perimeter of octagon
8(13)104unitsNow area
perimeter×apothem /2104(15.69)/252(15.69)815.88units²Area of square
13²169units²Area of shaded region
815.88-169646.88units²647units²Answer:
C. 647 square units
Step-by-step explanation:
To find the shaded area, subtract the area of the unshaded square from the area of the octagon.
Area of the octagon
[tex]\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}[/tex]
where:
n = number of sidesl = length of one sidea = apothemGiven:
n = 8l = 13a = 15.69Substitute the given values into the formula and solve for A:
[tex]\implies \textsf{Area}=\sf \dfrac{8 \cdot 13 \cdot 15.69}{2}[/tex]
[tex]\implies \textsf{Area}=\sf \dfrac{1631.76}{2}[/tex]
[tex]\implies \textsf{Area}=\sf 815.88\:\:square \:units[/tex]
Area of the square
[tex]\implies \textsf{Area}=\sf 13^2=169 \:\:square \:units[/tex]
Area of the shaded region
= area of the octagon - area of the square
= 815.88 - 169
= 646.88
= 647 square units (nearest square unit)
Find the range of values of x for which
[tex]2{x}^{2} \geqslant 9x + 5[/tex]
See attached images for work.
whats the polynomial of (7x+7)(x+2)
Answer:
okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
will you be my friend
Step-by-step explanation:
.......... okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
y = 2x² - 9x + 10
solve the following quadratic function by factoring
Which expression has a value of 16 when n = 5?
StartFraction 25 Over n EndFraction + 7
30 minus 3 n
7 + StartFraction 45 Over n EndFraction
n cubed minus 114
Answer:
7+45/n or 5
Step-by-step explanation:
45 divided by n or technically 5 is 9 plus 7 is 16 :)
Answer:7+45/n or 5
Step-by-step explanation:
If it is already 110F degrees below zero, and the temperature drops another 40 F degrees, how cold is it now?
Answer:
-150
or 150 degrees below 0
Step-by-step explanation:
The temp is -110. Dropping another 40 degrees means subtracting 40.
-110 - 40 = -150
The set of life spans of an appliance is normally distributed with a mean mu = 48 months and a standard deviation sigma = 8 months. what is the z-score of an appliance that stopped working at 64 months?
The z-score of an appliance that stopped working at 64 months is 2.
What is mean?The mean of observations is equal to the ratio of sum of all the observations and the number of observations.
Given, the set of life spans of an appliance is normally distributed with a mean mu = 48 months and a standard deviation sigma = 8 months
The z-score is then calculated as
z = x - μ /σ
For an appliance that stopped working at 64 months, we have
x = 64
On substituting the values, we get
z = 64-48/8
z = 2
Hence, the z-score of an appliance that stopped working at 64 months is 2
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Answer:
D on edge
Step-by-step explanation:
2
Help please asap points an brainlist
The function h(x) is a transformation of the square root parent function,
f(x)=√x. What function is h(x)?
-5
5
-5-
h(x)
f(x)
K
I
5
Answer: [tex]h(x)=\sqrt{x+4}[/tex]
Step-by-step explanation:
The graph of h(x) is the graph of f(x) shifted 4 units left.
if cospheta =3/5 and pheta is located in the fourth quadrant, then sin2pheta=_____
-8/25
24/5
-24/25
8/25
Step-by-step explanation:
if cospheta =3/5 and pheta is located in the fourth quadrant, then sin2pheta=_____
-8/25
24/5
-24/25
8/25
The correct answer for this question is 8/25
can someone please help mee i need the exact answer(30 points will give brainliest!!!)
The domain of the given graph is [−3, ∞) and the range is (−∞, 4].
We need to find the domain and range of the given graph.
What are the domain and range of the function?The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values that it can take.
We can observe that the graph extends horizontally from −3 to the right without a bound, so the domain is [−3, ∞). The vertical extent of the graph is all range values 4 and below, so the range is (−∞, 4].
Therefore, the domain of the given graph is [−3, ∞) and the range is (−∞, 4].
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Work out the area of this triangle
Step-by-step explanation:
the area of a triangle is
baseline × height / 2
baseline and height must be at a right angle with each other.
so, in our case
6 × 11 / 2 = 3 × 11 = 33 cm²
Answer:
Area = 33 cm²
Step-by-step explanation:
[tex]\textsf{Area of a triangle}=\sf \dfrac{1}{2}bh[/tex]
where:
b is the baseh is the height (perpendicular to the base)If we turn the triangle counterclockwise, so that the side that measures 6 cm is the base, we will see that the length that measures 11 cm is the height of the triangle (see attached).
Therefore:
b = 6 cmh = 11 cmSubstitute the found values into the formula and solve for A:
[tex]\implies \sf A=\dfrac{1}{2}(6)(11)[/tex]
[tex]\implies \sf A=\dfrac{1}{2}(66)[/tex]
[tex]\implies \sf A=33[/tex]
Therefore, the area of the triangle is 33 cm²
Determine the linear function for a graph that is a line with a slope of 1/7
and contains the point
(−4, 1).
The linear equation is y = (1/7)*x + 11/7.
How to get the linear equation?
The general linear equation is:
y = a*x + b
Where a is the slope.
Here we know that a = (1/7), then the line is:
y = (1/7)*x + b
We also know that the line contains the point (-4, 1), this means that when x = -4, we must have y = 1.
Replacing that, we get:
1 = (1/7)*(-4) + b
1 + 4/7 = b
7/7 + 4/7 = b
11/7 = b
So the linear equation is:
y = (1/7)*x + 11/7.
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The equation of the linear function of the line is: y = 1/7x + 11/7.
What is a Linear Function Equation?A linear function equation is modelled as, y = mx + b, where m is the slope and b is the y-intercept.
Slope (m) = 1/7, and the line passes through (-4, 1), therefore, substitute (x, y) = (-4, 1) and m = 1/7 into y = mx + b:
1 = 1/7(-4) + b
1 = -4/7 + b
1 + 4/7 = b
11/7 = b
b = 11/7
Plug in the values of m and b into y = mx + b:
y = 1/7x + 11/7
The equation of the linear function is: y = 1/7x + 11/7
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The Volume of a cube depends on the length of its sides.This can be written in function notation as v(s).What is the best interpretation of V(3)=27
Answer and Step-by-step explanation:
There is a cube with side length 3. The volume of this cube is 27.
Find the distance between the point (3, 5) and a line with the equation 5 x - 3 y + 10 = 0
The distance between the point (3, 5) and a line with the equation 5x – 3y + 10 = 0 will be 10 / √(34) units.
What is the distance between a point and a line?Let (x₁, y₁) be the point and ax + by + c = 0 be the line.
Then the distance between a point and a line will be
[tex]\rm d = \dfrac{|ax_1 + by_1 + c|}{\sqrt{a^2 + b^2}}[/tex]
The point (3, 5) and a line with the equation 5x – 3y + 10 = 0.
Then the distance between them will be
[tex]\rm d = \dfrac{|5 *3 - 3 *5 + 10|}{\sqrt{5^2 + (-3)^2}}\\d = \dfrac{10 }{\sqrt{34}} \ units[/tex]
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The star shape is made from a regular hexagon and six congruent equilateral triangles The area of the star shape is 96cm squared Work out the area of the regular hexagon.
Answer:
48 Square Centimeters
Step-by-step explanation:
The red triangular exterior pieces are all equilateral triangles with some side length.
We don't need to know what that side length is. It doesn't matter.
The area of one red equilateral triangle is some area A.
There are 6 of these red triangles, so the red exterior triangular parts combine to a total area of 6*A.
The hexagon is composed of equilateral triangles as well.
Each of these blue equilateral triangles is congruent to any outer red triangle because the side length is the same.
Therefore, the 6 blue equilateral triangles composing this hexagon combine to get a total area of 6*A
The area of the star overall is 12*A because we have 6 blue triangles combining with the 6 red triangles.
There is a total of 12 triangles.
