The shopping cart moves a distance of 4.57 meters in 3.00 seconds.
Using Newton's second law, which relates force, mass, and acceleration we can solve this problem
F = ma
where F is the net force acting on the object, m is its mass, and a is its acceleration.
In the given problem, the net force acting on the shopping cart is 14.0 N, and its mass is 15.5 kg. We can rearrange the equation above to solve for the acceleration of the cart:
a = F/m
a = 14.0 N / 15.5 kg
a = 0.9032 [tex]m/s^2[/tex]
Now we can use the kinematic equation that relates distance, acceleration, and time:
d = 1/2 * a * [tex]t^2[/tex]
where d is the distance traveled, a is the acceleration, and t is the time.
Plugging in the values we have:
d = 1/2 * 0.9032 [tex]m/s^2[/tex] * [tex](3.00 s)^2[/tex]
d = 4.57 meters
Therefore, the shopping cart moves a distance of 4.57 meters in 3.00 seconds.
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A balloon is inflated with helium at a constant pressure that is 4.3 × 105 Pa in excess of atmospheric pressure. If the balloon inflates from a volume of 1.8 × 10−4 m3 to 9.5 × 10−4 m3, how much work is done on the surrounding air by the helium-filled balloon during this expansion?
Answer: W = 331.1 J
Explanation:
W = pdv
= (4.3 x 10^5 Pa) (9.5 × 10−4 m3 - 1.8 × 10−4 m3)
W = 331.1 J or 3.3 x 10^2 J
The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.
What is meant by pressure-volume work?Pressure-volume work is defined as the work that a fluid does when it is compressed or expanded by an external force factor.
Here,
Pressure of the helium gas, P = 4.3 x 10⁵Pa
Initial volume of the helium gas, V₁ = 1.8 x 10⁻⁴m³
Final volume of the helium gas, V₂ = 9.5 x 10⁻⁴m³
The expression for the pressure-volume work is given by,
Work done, W = PΔV
where ΔV is the change in volume of the helium gas.
Therefore,
W = P(V₂ - V₁)
W = 4.3 x 10⁵(9.5 x 10⁻⁴- 1.8 x 10⁻⁴)
W = 4.3 x 10⁵x 7.7 x 10⁻⁴
W = 331.1 J
Hence,
The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.
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I need help in this please
The net force acting on the charge Q is in the direction D. The net force is the sum of forces from the two point charges Q+ each.
What is Coulomb's law ?According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:
Fq = k q1 q2 /r²
where, k is a constant.
As per this equation, the electrostatic force between two charges will increase as the magnitude of charge increases and the force decreases as the distance between them increases.
Here, the forces acting on the point charge Q- are the forces from the two Q+ charges. They are of different distances from the charges. The force in the direction E will be greater here. The net force on -Q is acting in the direction D.
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if you see the moon directly above a tree from your bedroom window one day, will the moon appear in the same position earlier or later the next day? explain.
The moon will not appear in the same position at the same time the next day, due to the Earth's rotation and the moon's motion in its orbit around the Earth.
The position of the moon in the sky changes due to the rotation of the Earth on its axis, as well as the moon's own motion in its orbit around the Earth. Therefore, if you see the moon directly above a tree from your bedroom window one day, the moon will not appear in the same position at the same time the next day. The time it takes for the moon to return to the same position in the sky is approximately 24 hours and 50 minutes, which is known as a lunar day. This is longer than a solar day (which is 24 hours), because the moon is also moving in its orbit around the Earth, and therefore has to move slightly further in the sky to return to the same position relative to the Sun. So, the moon will appear in a slightly different position in the sky relative to the tree each day, and it will also rise and set at slightly different times each day. The exact amount of change will depend on factors such as the time of year and the location of the observer.
In summary, the moon will not appear in the same position at the same time the next day, due to the Earth's rotation and the moon's motion in its orbit around the Earth.
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four different pairs of transverse wave pulses are shown below. in each case the pulses are moving towards each other. at some point in time the pulses meet and interact (interfere) with each other. for which pair will the height of the combined (resultant) pulse be greatest at the center of the combined pulses, at the point where the centers of the pulses coincide?
The resultant pulse's amplitude is the sum of the amplitudes of the two original pulses. This might be two crests or two troughs colliding.
When two waves superimpose in opposite phase, the amplitude of the consequent is equal to the difference in amplitude of the component waves, resulting in the least amount of light intensity; this is known as destructive interference.
When two pulses travelling in opposite directions along a stretched string collide. Because both pulses cause the string to move higher as they travel, the net displacement of the string at that location is equal to the total of the pulse amplitudes. Because the two waves are travelling through the same medium, they have the same speed. The superposition total wave travels in the same direction and at the same speed as the two component waves, but its local amplitude is determined by whether the two individual waves have the same or opposite phase.
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which structural fragment would give rise to a characteristic triplet-quartet pattern in the 1h nmr spectrum?
A split signal in NMR spectroscopy is made up of three lines that are near together. The line height will be close to a 1:2:1 ratio. The CH3 group causes a triplet at 1.2 ppm in the simulated 1H-NMR spectra of 2-ethylphenol.
The amount of signals in 1H NMR spectroscopy tells you about the numerous sorts of chemically equivalent protons in the molecule. In NMR spectroscopy, chemically comparable H atoms in a molecule give a single signal. A triplet of doublets (tdd) happens when the two biggest coupling constants are the same. A triplet of triplets (tt) arises when the two greatest coupling constants and the two lowest coupling constants are the same.
A quarter note triplet is made up of three quarter notes played at the same time as two quarter notes or a single half note. In the United Kingdom, quarter note triplets are known as crotchet triplets. Tetra methy lsilane was chosen as the internal reference compound for 1H NMR because it exhibits a strong, crisp resonance line from its 12 protons, as well as a chemical shift at low resonance frequency compared to practically all other 1H resonances.
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Suppose you have two metal cubes, one made of iron and one made of aluminum. You transfer the same amount of heat Q to each of them. Which cube will have the higher final temperature, given they have the same masses and initialtemperatures? a. Iron Cube b. Aluminum Cube
If the same amount of heat Q is applied to each cube, the aluminum cube will have a greater end temperature than the iron cube.
The average thermal energy of the particles in a system is measured by temperature. It is a scalar number that represents the amount of heat energy present in a substance and is usually expressed in degrees Celsius (°C), Kelvin (K), or Fahrenheit (°F). The kinetic energy of the particles in a system, which is the energy associated with their motion, is proportional to temperature. When a system's temperature rises, so does the kinetic energy of its particles, resulting in quicker and more chaotic motion. In contrast, when the temperature drops, the The particles' kinetic energy reduces, resulting in slower and less chaotic motion.
Here, The eventual temperature of the two cubes will be determined by their respective heat capacities. The quantity of heat energy required to raise the temperature of a unit of mass of a material by one degree Celsius is defined as its specific heat capacity.
Aluminum has a greater specific heat capacity than iron, which means it takes more heat energy to increase its temperature by the same amount.
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if the distance between two isolated parallel plates that are oppositely charged is doubled, the electric field between the plates is essentially unchanged. however, the:
The charged density of the parallel plates affects the electric field between them. The field between plates is 0 if they are neutral or 0 if they carry charges, depending on which way they are charged. While there is no field inside the sphere.
What is the electric field between the plates?The capacitor's two oppositely charged plates are separated by an electric field that is constant throughout, except the plate edges.
The electric field does not change since the space between the plates is smaller than their combined surface area.
Because the two parallel charged plates are kept apart from one another, a homogenous electric field is created there.
Therefore, Potentially, there will be a double differential between the plates.
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HELP ME PLEASE!!!!!!!
Fluffy the Cat falls out of a tree that is 15 meters tall.
How long does it take the cat to land?
Need to show work!!!!!!
Answer:
it would take approximately 1.7 seconds for Fluffy the Cat to fall from a 15 meter tall tree.
Explanation:
To calculate the time it takes for an object to fall, you can use the following formula:
t = sqrt(2d / g)
where:
t is the time in seconds
d is the distance fallen in meters
g is the acceleration due to gravity (approximately 9.8 m/s^2 on the surface of the Earth)
So, substituting in the values for d (15 meters) and g (9.8 m/s^2), we get:
t = sqrt(2 * 15 / 9.8)
t = sqrt(30 / 9.8)
t = sqrt(3.06122448979591836734693877551)
t ≈ 1.744823934831724823036837018032 seconds
If you apply is 400 N pushing 20 - KG sled what is the acceleration ? solve the following problems
If you apply is 400 N pushing 20 - KG sled. The acceleration is 20 m/s².
What is acceleration?Acceleration is a vehicle's capacity to gain speed within a short time. The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion.
When an item's mass and the net force acting on it are known, the acceleration of that object can be calculated using this equation for acceleration.
Acceleration = force/mass
Force = 400 N
Mass = 20 kg
400 / 20 = 20 m/s²
Therefore, the acceleration is 20 m/s².
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A current of 0.33 A is following through a circuit .If the potential difference across two points of wire is 5V ,Claculate the resistance
Answer:
The value of resistance is
[tex]15.15ohm[/tex]
Explanation:
Greetings!!!
Given values:-current(I)= 0.33A
potential difference(V)= 5V
Required values:-resistance (R)= ?
Solution:-Firstly, recall the ohm's law
V= RISubstitute known variables into the equation
(5)= R(0.33)Solve for Resistance
R= 15.15 ΩIf you have any questions tag me on comments
Hope it helps!!!
Answer:
15 Ω.
Explanation:
The resistance of a circuit can be calculated using Ohm's law, which states that the potential difference (V) across a conductor between two points is directly proportional to the current (I) flowing through it, given by the equation V = IR.
To find the resistance, we can rearrange the equation to R = V/I, where R is the resistance. Substituting the values we have, we get:
R = 5V / 0.33A = 15 Ω
So, the resistance of the circuit is 15 Ω.
(hrwc9p104) an old chrysler with mass 2650 kg is moving along a straight stretch of road at 81 km/h. it is followed by a ford with mass 1550 kg moving at 52 km/h. how fast is the center of mass of the two cars moving?
The two automobiles center's of mass are moving at a 19.79 m/s speed. Calculate the system's total mass and canter of mass velocity to get the velocity of the system's center of mass for the two automobiles.
The weighted average of the velocities of each individual object, multiplied by their mass, equals the velocity of the canter of mass.
Let's refer to the center of mass's velocity as V cm. Then:
V cm is equal to (mass of Chrysler times its velocity plus mass of Ford times its velocity) / (total mass of system)
The speeds must first be changed from km/h to m/s:
Chrysler's speed is 81 km/h, or 81 * 1000 / 3600 m/s, or 20.83 m/s.
Ford's speed of 52 km/h is equal to 52 * 1000 / 3600 m/s, or 18.06 m/s.
Then, we may determine the system's overall mass and center-of-mass velocity:
Overall mass equals the sum of the masses of Chrysler and Ford, or 2650 kg plus 1550 kg, totaling 4200 kg.
V cm is equal to (mass of Chrysler times its velocity plus mass of Ford times its velocity) / total mass.
V cm is calculated as (2650 kg at 20.83 m/s and 1550 kg at 18.06 m/s) / 4050 kg.
V cm is equal to 4200 kg / (55,051.5 kg m/s + 25,244 kg m/s).
V cm = 4200 kg / 80,295.5 kg / 19.79 m/s
Hence, the two automobiles center's of mass are moving at a velocity of 19.79 m/s.
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Mallory pushes her water bottle of 1.70 kg to the side. She applies a force of 108.20 N to the right. If the bottle accelerates at 8.79 m/s2, what is the coefficient of friction?
According to the question, the coefficient of friction is found to be 0.138. It is the ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together.
What is the coefficient of friction?The coefficient of friction may be defined as a measure of the amount of friction that is significantly existing between two surfaces. When you find a coefficient of friction, you're calculating the resistance to motion at the interface of two surfaces of similar or dissimilar materials.
According to the question,
The force, F = m × a = 1.70 kg × 8.79 = 14.94 N.
The formula for calculating the coefficient of friction is as follows:
μ = F/N = 14.94/108.20 = 0.138.Therefore, the coefficient of friction is found to be 0.138.
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This is an AP physics problem on the subject of Conservation of Momentum
The Momentum is the product of mass and velocity.
What is the momentum?Momentum is a measure of an object's motion. It is defined as the product of an object's mass and its velocity. In physics, momentum is a conserved quantity, which means that the total momentum of a closed system remains constant unless acted upon by an external force.
Final momentum of Ax = 1 * 2 * cos 30 = 1.73 Kgm/s
Final momentum of Ay = 1 * 2 * sin 30 =1 Kg m/s
Final momentum of Bx = 1 * Vs * cos 30
Final momentum of By = 1 * Vy * sin 30
The velocity is then;
1 * 5 + 0 = (1 * 2) + (1 * vs)
5 = 2 + vs
Vs = 3 m/s
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at the instant the traffic light turns green, an automobile starts with a constant acceleration of 2.70 m/s2. at the same instant a truck, traveling with a constant speed of 11.30 m/s, overtakes and passes the automobile. (a) how far beyond the traffic signal will the automobile overtake the truck?
The traffic signal will the automobile overtake the truck far away beyond the traffic signal is 2.7 m.
The difference between haste and relative haste is that haste is measured with respect to a reference point which is relative to a different point. While relative haste is measured in a frame where an object is either at rest or moving with respect to the absolute frame.
The relative haste is defined as the haste of an object with respect to another bystander.
It's the time rate of change of relative position of one object with respect to another object.
W.r.t automobile,
u = ut - ua at t=0
= 11.3 - 0
= 11.3 m/s
d = dt - da
= 0 - 2.7 = -2.7m/s²
So, s = ut + 1/2at²
= 11.3(t) - 2.7/2 at²
0 = 11.3t - 2.7/2 t²
= 11.3t - 1.35 t²
11.3t = 1.35t²
t = 11.3/1.35
t = 8.37 sec
They will overtake again at 8.37 s
v = 11.3 m/s and st = vx1 = 11.3 m
both truck and car would travelled 11.3 m
Speed of automobile,
v = u + at
= 0 + 2.7(1)
= 2.7 m/s
Speed of the automobile is : 2.7 m/s
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An object has 10 J of GPR.What would be its GPE if its mass was halved?
If the mass of the object is halved, its new GPE would be 5 J. The gravitational potential energy (GPE) of an object near the surface of the Earth is given by the formula:
GPE = mgh
where:
m is the mass of the object
g is the acceleration due to gravity (9.81 m/s² near the surface of the Earth)
h is the height of the object above some reference level (usually taken to be the ground level)
The given information of the object having 10 J of gravitational potential energy (GPE) is insufficient to calculate its mass or height. As a result, we cannot use the above formula to calculate the object's GPE if its mass is halved.
However, we can take advantage of the fact that an object's GPE is directly proportional to its mass. That is, if we cut the object's mass in half, its GPE will be cut in half as well. This is mathematically expressed as:
GPE2 = (1/2) GPE1
where:
GPE1 is the object's first GPE.
GPE2 is the object's new GPE after its mass has been halved.
As a result, if the object's GPR is considered its initial GPE and its mass is halved, its new GPE is:
GPE2 = (1/2) GPR
Substituting the given value of GPR = 10 J, we get:
GPE2 = (1/2) x 10 J = 5 J
So, if the mass of the object is halved, its new GPE would be 5 J.
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PLS ANSWERRR What are the main differences between the carbon flows 300 years ago and today?
The main differences between the carbon flow 300 years ago and today are the amount of carbon dioxide released into the atmosphere and the sources of those emissions.
300 years ago, the majority of carbon emissions came from natural sources, such as volcanic eruptions and forest fires. However, today, the majority of carbon emissions come from human activities, such as burning fossil fuels for energy and deforestation for agriculture and urbanization. Additionally, the amount of carbon dioxide released into the atmosphere has greatly increased in the past 300 years due to the industrialization of society and the increase in the human population. This has led to an increase in greenhouse gases in the atmosphere and has contributed to climate change.
In summary, the main differences between the carbon flow 300 years ago and today are the sources of emissions and the amount of carbon dioxide released into the atmosphere.
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An airplane flies 1400 miles in 2 1/2 hours.
4 What is its average speed in miles per hour?
Answer:
the average speed of the airplane is 560 miles per hour.
Explanation:
To calculate the average speed of an airplane, you need to divide the total distance it travels by the total time it takes to travel that distance.
In this case, the total distance is 1400 miles and the total time is 2 and a half hours, so we can calculate the average speed as follows:
Average Speed = Total Distance / Total Time
Average Speed = 1400 miles / 2.5 hours
Average Speed = 560 miles per hour
Two stars are of equal luminosity. Star A is 3 times as far from you as star B. Star A appears _________ star B.A. 3 times brighter than
B. 9 times brighter than
C. one-third as bright as
D. the same brightness as
E. one-ninth as bright as
The answer is E. One-ninth as bright as star B if two star are of equal luminosity.
The apparent brightness of a star depends on its distance from the observer. According to the inverse square law, the apparent brightness of a star decreases as the square of the distance from the observer increases. In this case, star A is three times farther away from the observer than star B. Therefore, the apparent brightness of star A will be nine times less than that of star B.
Since the two stars are of equal luminosity, we can conclude that star A appears one-ninth as bright as star B. This is because the apparent brightness of a star is proportional to its luminosity divided by the square of the distance from the observer. Since the two stars have the same luminosity, the ratio of their apparent brightness is equal to the inverse square of the ratio of their distances from the observer.
In summary, the answer is E. One-ninth as bright as star B
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An object 0.1 m tall is placed 0.4 m from a convex mirror with a focal length of 0.3 m. What is the height of the image?
Answer: no exact answer
=
Explanation:
you measured the length, diameter and mass of two different cylinders. in both cases, you found that the length had 3 significant figures and that length was the measurement with the fewest number of significant digits. if you found the weight densities to be 38123 n/m3 and 38091 n/m3 and you round these values to the correct number of significant figures, can you conclude the two cylinders are made of the same material (do they have the same weight density)?
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38107 N/m³
The formula for volume of cylinder is:
V = πr²l
where,
V = Volume
r = radius
l = length of cylinder
So, if length has the 3 significant figures which is least in all values, Then the volume must also be in 3 significant figures. The formula for weight density is:
Weight Density = Weight/Volume
Here, the volume has the least significant figures of 3, therefore, the weight densities must also have 3 significant figures:
Weight Density 1 = 38123 N/m³
Weight Density 1 = 38124 N/m³
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38123 N/m³
Weight Density 2 = 38124 N/m³
Weight Density 2 = 38107 N/m³
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What happens to the number of valence electrons as you move from element 1 to element 18 on the Periodic Table?
When we move from element 1 to element 18 on the periodic table the number of Valence Electrons as we move increases.
The elements 1 to element 18 are located in the group 1-2 and group 13-18 of the periodic table.
Now when we move from element 1 to element 18 we are basically moving from left to right in the periodic table and as we move from left to right we see that the number of valence electrons in the group increases by one from the one element to the next in the periodic table.
This is due to the increasing atomic number of the elements.
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HELP ME ASPPP THANKYOU
A window pane would gain heat the fastest
Why does a window pane gain heat fast?
We have to note that the heat capacity of the material would be very important to know the object that would be able to gain the heat fast. If the object is gaining the heat fast, it means that it has a low specific heat capacity.
Again the window pane does have a low specific heat capacity and is able to absorb heat and the temperature would rise faster causing the object to gain heat the fastest as we can see from the explanation here.
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what is the range of distance before and behind the main focus distance? the character or object remains in focus if they remain in this range
The range of distance before and behind the main focus distance is referred to as the depth of field.
The depth of field is determined by several factors, including aperture size, focal length, and distance to the subject. Generally, the depth of field is greater behind the main focus distance than in front of it. The distance before the main focus distance is referred to as the near focus limit, and the distance behind it is referred to as the far focus limit. The depth of field is an important consideration in photography and videography as it affects the sharpness and clarity of the final image or video. It can be adjusted by changing the aperture size, focal length, or distance to the subject. The range of distance before and behind the main focus distance is referred to as the depth of field.
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Problems 9 and 10 are related to the following situation: It's a dirty little Menlo
secret that every time the floors in Stent Hall are waxed, Mr. Colb likes to slide
down the hallway in his socks. Mr. Colb weighs 950 N and the force of friction
acting on him is 100 N.
●
Calculate Mr. Colb's acceleration down the hall.
Oh no! There's an open door leading nowhere at the end of the second floor
hallway! Mr. Colb is traveling at 2.8 m/s when he becomes a horizontally
launched projectile and plummets to the ground below (don't worry, he lands
on a pile of backpacks and only his pride is injured). If the window is 3.7 m
high, calculate how far from the base of the wall Mr. Colb lands.
Mr. Colb's acceleration down the hallway is 0.91 m/[tex]s^2[/tex] as per the given data.
What is acceleration?Acceleration is the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.
To calculate Mr. Colb's acceleration down the hallway, we can use the formula:
a = (F - f) / m
a = (F - f) / m
a = (950 N - 100 N) / (950 kg * 9.81 m/[tex]s^2[/tex])
a = 0.91 m/[tex]s^2[/tex]
To calculate how far from the base of the wall Mr. Colb lands, we can use the equations of motion for a projectile:
y = yo + voyt + 0.5a[tex]t^2[/tex]
x = xo + voxt
y = yo + voyt + 0.5a[tex]t^2[/tex]
3.7 m = 0 m + 0 m/s * t + 0.5 * 9.81 [tex]m/s^2[/tex] x [tex]t^2[/tex]
t = 0.89 s
Now we can use the horizontal equation of motion to calculate how far Mr. Colb travels horizontally in 0.89 s:
x = xo + vox x t
x = 0 m + 2.8 m/s x 0.89 s
x = 2.49 m
Thus, Mr. Colb lands 2.49 meters away from the base of the wall.
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an alpha particle (two protons and two neutrons) moves from a to c. what is the change in potential energy of the system (alpha source charges)? note: a neutron is electrically neutral (no net electrical charge).
The change in potential energy of the system depends on the charges and distances of the source particles, as well as the charge of the alpha particle and the distances between the alpha particle and the source particles.
To calculate the change in potential energy of the system, we need to know the electric potential at points A and C, and the charge of the particles involved.
If we assume that the alpha particle is moving in a vacuum and that the source charges are fixed, then we can use the formula for the potential energy of a point charge in an electric field:
U = qV
where U is the potential energy, q is the charge of the particle, and V is the electric potential at the point where the particle is located.
Since an alpha particle consists of two protons and two neutrons, its net charge is +2e, where e is the elementary charge. We also need to know the charges of the source particles.
Let's assume that the source charges are two positive point charges, located at points A and B, respectively. We can also assume that the alpha particle starts at point A and moves to point C, which is at a distance r from point A and a distance s from point B.
The electric potential at point A, VA, is given by:
VA = k(q1/r1 + q2/r2)
where k is the Coulomb constant, q1 and q2 are the charges of the source particles at point A and B, respectively, and r1 and r2 are the distances between the source particles and point A.
Similarly, the electric potential at point C, VC, is given by:
VC = k(q1/(r+s) + q2/s)
The change in potential energy of the alpha particle as it moves from point A to point C is:
ΔU = Uc - Ua = qVC - qVA
Substituting the values of VA and VC, we get:
ΔU = qk(q1/(r+s) + q2/s) - qk(q1/r1 + q2/r2)
Simplifying this expression, we get:
ΔU = qk(q1/r1 - q1/(r+s) + q2/s - q2/r2)
So, the change in potential energy of the system depends on the charges and distances of the source particles, as well as the charge of the alpha particle and the distances between the alpha particle and the source particles.
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metal rods of length 20cm each are laid end to end to form a bridge at 25°C. What gap will be provided between consecutive rails for the bridge to withstand 75°C?
Answer:
1 mm
Explanation:
To find the gap between the metal rods that would allow the bridge to withstand a temperature change from 25°C to 75°C, we need to calculate the increase in length of the metal rods due to thermal expansion.
The linear expansivity of most metals is around 10^-5 / K. So, the increase in length of each metal rod can be calculated as:
ΔL = α * L * ΔT
where α is the linear expansivity, L is the initial length of the rod (20 cm), and ΔT is the change in temperature (75°C - 25°C = 50°C).
Converting the units to SI units, the initial length of the rod becomes 0.2 m and the change in temperature becomes 50 K. So, the increase in length of the rod becomes:
ΔL = 10^-5 / K * 0.2 m * 50 K = 0.001 m = 1 mm
So, the gap between the metal rods should be at least 1 mm to allow for the thermal expansion of the metal rods and avoid buckling or breaking of the bridge under the temperature change from 25°C to 75°C.
What types of intermolecular forces are exhibited by each compound? 1. lon-lon 2.Hydrogen bonding 3.Dipole-Dipole 4.van der Waals forces OH N 'N
It's worth noting that most molecules can exhibit a variety of intermolecular forces. The types of intermolecular forces that exist are determined by the molecule's specific structure and composition.
OH: The OH molecule can exhibit hydrogen bonding, which is a type of intermolecular force that occurs when a hydrogen atom is bonded to a highly electronegative atom such as oxygen or nitrogen.
Nitrogen gas (N2) is a nonpolar molecule that does not form hydrogen bonds. It can, however, exhibit van der Waals forces, which are weak attractive forces that occur between all molecules, including nonpolar ones like N2.
'N': It is unclear what is meant by "'N," but assuming it refers to a nitrogen-containing molecule, the types of intermolecular forces it can exhibit vary depending on the molecule. Hydrogen bonding can occur when a hydrogen atom is bonded to a highly electronegative atom, such as oxygen or nitrogen. If the molecule is polar (has a separation of positive and negative charge across the molecule), dipole-dipole interactions can occur. Van der Waals forces can be observed in nonpolar molecules.
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how can the momentum of a speeding bullet be the same as the momentum of a supertanker moving toward a dock
Mass in motion is quantified by momentum, which is the measure of how much weight is moving. It typically has the sign math
What does motion mean in mathematics?
In mathematics, movement, distance, velocity, impulse, and speed are used to explain motion. By securing a reference point to the environment or the observer, a body's motion can be seen. A body's motion is quantified by tracking how its location changes in relation to the perspective it occupies.
What types of motion may an object make?
The force acting on a body determines how it moves. These are some examples of various motion types. Translational: When an item goes along a route across all 3 components, it is of this type. Rotational: This sort of movement involves an object moving in a circular motion around a fixed axis.
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An airplane flies with a constant speed of
540 miles per hour. How long will it take to travel a distance of 2160 miles?
Answer:
4 hours
Explanation:
2160 miles ÷ 540 miles/hr = 4
Help please. Urgently need answer
The final kinetic energy of the lead bullet after the impact is 50 J.
option A.
What is the final kinetic energy of the system?
The final velocity of the lead bullet system will be used to determine their final kinetic energy after the impact.
m1u1 + m2u2 = v ( m1 + m2 )
where;
u1 and u2 are the initial velocitiesm1 and m2 are the massesv is the final velocity of the lead bullet after the impact( 0.05 x 200) + 0.95(0) = v ( 0.05 + 0.95 )
10 m/s = v
K.E_final = ¹/₂mv²
= ¹/₂ ( 0.05 + 0.95 ) (10²)
= 50 J
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