In infrared satellite images, land appears _________ and clouds appear _________. A. red, yellow B. white, black C. black, white D. yellow, red

The magnitude of the force exerted by the left cube on the right cube is 17.64N.

When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.

Two identical 3.0-kg cubes are placed on a horizontal surface in contact with one another. The cubes are lined up from left to right and a force F₁ is applied to the left side of the left cube causing both cubes to move at a constant speed v. The coefficient of kinetic friction between the cubes and the surface is 0.3.

From the equilibrium of forces in vertical direction

Normal force N= 2m x g

friction force f = μN =μ(2m)g

From the equilibrium of forces in horizontal direction

F₁ =ma =0

using Newton's third law of motion, we get

F₁  - f =0

F₁  =f = μ(2m)g

Put the values, we get

F₁  = 17.64N

Thus, magnitude of the force exerted by the left cube on the right cube is 17.64N.

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The angle at which it should be banked for a traffic speed of 100 km/h is

14.57°.

To find the angle of banking following formula can be used,

[tex]tan \alpha = v^{2} /rg[/tex]

Given v = 100km/h or

          = 100  x 1000 / 3600

          = 27.7 m/s

Hence,

[tex]tan \alpha = (27.7)^{2} / 300 * 9.81[/tex]

[tex]tan\alpha = 0.26[/tex]

[tex]\alpha = tan^{-1} 0.26[/tex]

[tex]\alpha = 14.57[/tex]°

Hence, the angle of banking of the road will be 14.57°

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The cutoff frequency for magnesium is 8.93 x 10¹⁴ Hz.

The work function is related to the frequency as

W0 = h x fo

where, fo = cutoff frequency and h is the Planck's constant

Given is the work function for magnesium is  3.70 eV.

fo = 3.7 x 1.6 x 10⁻¹⁹ / 6.626 x 10⁻³⁴

fo = 8.93 x 10¹⁴ Hz.

Thus, the cut off frequency is 8.93 x 10¹⁴ Hz.

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The average velocity is 4i m/sec

The average acceleration is 4i

Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs. T

According to the question,

x=at²i + btj ( t is in second and x is in meter).

Average velocity =  [tex]\frac{dx}{dt}[/tex]

[tex]\frac{dx}{dt} = 2at i + b j\\\\\frac{dx}{dt} = 2 * 2 * t i +1 j\\\\\frac{dx}{dt} = 4t i +j[/tex]

[tex]\frac{dx}{dt}[/tex] in the time interval of 2 to 3 sec is

at 2 sec,

[tex]\frac{dx}{dt} = 4 * 2 i +j = 8i +j[/tex]

at 3 sec ,

[tex]\frac{dx}{dt}[/tex] = 4 * 3 i + j = 12i+j

Therefore the average velocity is

[tex]\frac{(12i +j - 8i -j)}{(3-2)} = 4i[/tex]

The velocity at any given time is   [tex]\frac{dx}{dt} = 4t i +j[/tex]

The acceleration at any given time is [tex]\frac{dx^2}{dt^2}[/tex]

[tex]\frac{dx^2}{dt^2} = 4 i[/tex]

The average acceleration in the time interval  t₁=2sec and t₂=3sec

Average Acceleration =  4i

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Answer:

C probably

Explanation:

think c because when you first start the car the first thing you hear electrical sound.

Answer:

  19.6 m/s

Explanation:

The velocity is the product of acceleration and time.

__

Here, the acceleration is due to gravity.

  v = at

  v = (9.8 m/s²)(2 s) = 19.6 m/s

The stone hits the ground with a speed of 19.6 m/s.

A stone is dropped from the top of a tower which touches the ground after 2 seconds.

Hence, The stone hit the ground with the velocity speed of 19m/s².

- When you're solving velocity, you're determining how fast an object moves from its original position, with respect to a frame of reference, and a function of time.

- That means an object's velocity will be equal to the object's speed and direction of motion.

"Problem has been solve"

(ノ^_^)ノ

Answer:

Tolerate

Explanation:

The electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C

Given an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.

Solve for the electric flux through the cylinder due to this infinte line:

As below equation mentions, the electric flux for a uniform electric filed is given by:

Фₓ = EA cosΦ

Φₓ = λLcosΦ)/ε

Φₓ = (3 x 10^(-6) x 0.4 x cos0)/(8.854 x 10^(-12))

Φₓ = 1.355 x 10^(5) Nm²/C

Hence the electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C

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The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

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Answer:

26.85

Explanation: I got it right on Acellus.

Answer:

Joes displacement is 54m

Explanation:

The light is bent away from the normal

The average velocity of the particle from rest to 9 seconds would be 2 meters/sec.

This average velocity can be calculated with the following equation:

v = dx / dt

where:

dx = displacement = 18 meters

dt = interval of time = 9 seconds

Substitute;

v = dx / dt

v = 18 / 9

v = 2 meters/sec

Hence, the average velocity of the particle from rest to 9 seconds would be 2 meters/sec.

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Answer:

1cm

Explanation:

The amplitude of a wave is the distance from the center line (in this case the 1 cm marker on the vertical ruler) to the highest or lowest point. For this image the highest point is 2 cm, 2cm-1cm=1cm. The lowest point is 0cm, 1cm-0cm=1cm.

The amplitude of the wave is 1 cm. So, the correct option is a.

A point on a vibrating body or wave can move up to its maximum distance or displacement when measured from its equilibrium position, which is known as the amplitude. It is equivalent to the length of the vibration path divided in half.

Here,

The crests and trough of a wave is given. Amplitude can also be defined as the peak distance of the crest or trough of the wave.

From the given diagram, we can say that the sum of heights of the crest and trough is given as 2 cm. So, that will be the total vibration path. So, half of its length will give the amplitude of the wave.

Therefore, the amplitude of the wave,

A = 2/2 = 1 cm

Hence,

The amplitude of the wave is 1 cm. So, the correct option is a.

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You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, the average force on the jet is due to the catapult is mathematically given as

What is the average force on the jet is due to the catapult?

Generally, the equation for acceleration is mathematically given as

[tex]a=\frac{vf^2-vi^2}{2s}\\\\\Therefore\\\\a=\frac{69.29^2-0^2}{2(90}\\\\a=26.673m/s^2[/tex]

In conclusion, The force

F=m*a

F=15100*26.673

F=40272.3N

F 402 KN

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Explanation:

this is the answer 276 volts

Answer:

Explanation:

Wow, I said 'beets'..... I must be weird.

Answer:

if you pick it up the heat will flow to the hand until the Temperature of both evens out

Answer:

Approximately [tex]53^{\circ}[/tex], assuming that the upper and lower surfaces of the glass on this boat are parallel.

Explanation:

Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.

The following angles would be alternate interior angles between the two normals:

Since the two normals are parallel to each other, these two angles would have the same value. Let [tex]\theta_{\text{glass}}[/tex] denote the value of both of these angles.

Let [tex]\theta_{\text{src}}[/tex] denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let [tex]\theta_{\text{dst}}[/tex] denote the angle at which this beam of light enters the new medium.

Let [tex]n_\text{src}[/tex] and [tex]n_\text{dst}[/tex] denote the refractive indices of the original and the new medium, respectively. By Snell's Law:

[tex]\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}[/tex].

Let [tex]\theta_{\text{water}}[/tex] denote the angle at which the beam of light in this question leaves the water. Let [tex]\theta_{\text{air}}[/tex] denote the angle at which this beam of light enters the air. It is given that [tex]\theta_{\text{water}} = 37^{\circ}[/tex], while [tex]\theta_{\text{air}}[/tex] is the value that needs to be found.

Let [tex]n_{\text{air}}[/tex], [tex]n_{\text{water}}[/tex], and [tex]n_{\text{glass}}[/tex] denote the refractive index of air, water, and glass, respectively. By Snell's Law:

[tex]\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}[/tex].

[tex]\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}[/tex].

Thus:

[tex]\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}[/tex].

Since [tex]\theta_{\text{water}} = 37^{\circ}[/tex]:

[tex]\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}[/tex].

In other words, this beam of light would leave the glass at approximately [tex]53^{\cic}[/tex] from the normal.

HIV can be contracted from contact with bloodborne pathogens.

Other bloodborne diseases are HBV, malaria, syphilis and brucellosis

Bloodborne pathogens can be defined as those microorganisms or pathogenic organisms that cause disease and are present in human blood.

Blood borne pathogens can also be contacted through the following means

In conclusion; HIV can be contracted from contact with bloodborne pathogens.

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Answer:

4.2 A

Explanation:

V=IR

V= voltage

I= Current

R= resistance

so you will find the resistance in the circuit so

R= V/I

R=2V/0.70A

R=2.857 ohms ( TO THE NEAREST THOUSANDTH)

then you will find the current of the 12V battery using the resistance in the circuit

I=V/R

I=12/2.857

I=4.2A (TO THE NEAREST TENTH)

The strength of the electric field on the point charge at this distance will be 4000 V/m.

The strength of the electric field is the ratio of electric force per unit charge.

The given data in the problem is;

Qis the unit charge = 4.0 × 10⁻⁶ C

E is the strength of the electric field

R is the distance from point charge = 3 m

The strength of the electric field is;

[tex]\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m[/tex]

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.

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Answer:

0.159

Explanation:

the formula to find its is 1÷2*gt^2

Answer:

D

Explanation:

v= a t

 = 5.1 * .25 = 1.275 m/s

Answer:

Explanation:

Comment

You could calculate it out by assuming the same starting temperature for each substance. (You have to assume that the substances do start at the same temperature anyway).

That's like shooting 12 with 2 dice. It can be done, but aiming for a more common number is a better idea.

Same with this question.

You should just develop a rule.  The rule will look like this

The greater the heat capacity the (higher or lower) the change in temperature.

The greater the heat capacity the lower the change in temperature

That's not your question. You want to know which substance will have the greatest temperature change given their heat capacities.

Answer

lead. It has the smallest heat capacity and therefore it's temperature change will be the greatest.

Find the relationship

[tex]\\ \rm\Rrightarrow Q=mc\Delta T[/tex]

[tex]\\ \rm\Rrightarrow 100=10c\Delta T[/tex]

[tex]\\ \rm\Rrightarrow 10=c\Delta T[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{10}{c}=\Delta T[/tex]

[tex]\\ \rm\Rrightarrow \Delta T\propto \dfrac{1}{c}[/tex]

So lower the c higher ∆T

Lead has the largest change in T as it has least capacity

Answer:

liquid turns into vapor when the liquid molecules achieves the energy to break down the form or when gets highly excited. The temp required for this is called latent heat of vaporization. As the liquid molecules attain this energy through heat it suddenly changes form into vapor , and when the heat is continued , molecule after molecule receives this energy and changes to vapor .So if you continue heating the liquid all the liquid will change form to vapor state leaving residue , ie the dissolved particles .

liquid turns into vapor when the liquid molecules achieves the energy to break down the form or when gets highly excited. The temp required for this is called latent heat of vaporization. As the liquid molecules attain this energy through heat it suddenly changes form into vapor , and when the heat is continued , molecule after molecule receives this energy and changes to vapor .So if you continue heating the liquid all the liquid will change form to vapor state leaving residue , ie the dissolved particles .I’m no expert but this is what i think happens …

Hello!

We can use Faraday's Law of Electromagnetic Induction to solve.

[tex]\epsilon = -N \frac{d\Phi_B}{dt}[/tex]

ε = Induced emf (4.08 V)
N = Number of loops (?)

[tex]\Phi_B[/tex] = Magnetic Flux (Wb)
t = time (s)

**Note: The negative sign can be disregarded for this situation. The sign simply shows how the induced emf OPPOSES the current.

Now, we know that [tex]\frac{d\Phi_B}{dt}[/tex] is analogous to the change in magnetic flux over change in time, or [tex]\frac{\Delta \Phi_B}{\Delta t}[/tex], so:
[tex]\epsilon = N \frac{\Delta \Phi_B}{\Delta t}\\\\\epsilon = N \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}[/tex]

Rearrange the equation to solve for 'N'.

[tex]N = \frac{\epsilon}{ \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}}[/tex]

Plug in the given values to solve.

[tex]N = \frac{4.08}{ \frac{9.44*10^{-5} - 2.57*10^{-5}}{0.0154}} = 914.585 = \boxed{915 \text{ coils}}[/tex]

**Rounding up because we cannot have a part of a loop.

The field exerts 6.5 x 10⁸ Newton of force on EACH COULOMB of charge in the field.

We're putting 1.6 x 10⁻¹⁹ Coulomb of charge into the field.

The force on it will be

      (1.6 x 10⁻¹⁹ Coulomb) x  (6.5 x 10⁻⁸ Newton/Coulomb).

That's 1.04 x 10⁻¹⁰ Newton.

Answer:

it will float

Explanation:

according to Archimedes' principle, if the buoyant force is equal to the weight of the mass of the object, the object will float

Answer:

Since 1 cal = 4.19 J     the heat Q received by the metal is

Q = 13,500 J * 1 C / 4.19 J = 3,222 calories

S = ΔQ / (ΔT * ΔM)  = 3222 cal / (45 deg C / 750 gm)

S = .095 cal / gm deg C

Note that specific heat capacity for Cu is .093 cal / gm deg C

It is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.

The associations among variables have a fundamental value in science because they can determine how such variables behave in hypothetical situations.

Moreover, correlation only indicates a type of association between variables and therefore it is less informative.

In conclusion, it is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.

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