In Macy’s, a coat has a regular price of x dollars. During a sale, the price of the coat is discounted by 20%. The expression 0.8x describes the discounted price, in dollars, of the coat. Which expression also describes the discounted price, in dollars, of the coat?

plz help me

y=895•1.07^x Y is the population of quails and X is the amount of years that have passed.

Answer:

(√10 +2√8)(√10 -2√8)=

(10 -8√5 + 8√5 -32)

10+0-32

10-32

= -22

Hope this helps.

Answer:

The other person is right, A. -22

Step-by-step explanation:

Answer:

Make N alone

There is an 8 so we subtract 8 from both sides so the equation is still equal

-4 - 8 = -12

Because we are subtracting N it is positive

N = 12

8 - 12 = -4

Hope this helps

Step-by-step explanation:

Answer:

x=-3

Step-by-step explanation:

\left(5^3\right)^2\cdot 5^{x+4}=5^7

Apply\:exponent\:rule

x+10=7

x=-3

Answer:

x = -3

Step-by-step explanation:

(5^3)^2 · 5^(x+4) = 5^7

First of all, we simplify (5^3)^2. When you have an exponent in parentheses that is raised to another exponent that is outside the parentheses, you multiply the exponents.

(5^3)^2 = 5^(3·2) = 5^6

We cannot simplify 5^(x+4) or 5^7 any further, so our equation is now:

5^6 · 5^(x+4) = 5^7

We can divide 5^6 from both sides to get:

5^(x+4) = (5^7)/(5^6)

When exponents of like terms are divided we can subtract the exponents.

5^(x+4) = 5^(7-6)

5^(x+4) = 5^1

This last part is a bit trickier. When exponents of like terms are multiplied we add the exponents. We can use this knowledge to determine that 5^(x+4) is made up of 5^x · 5^4. Now we have:

5^x · 5^4 = 5^1

We can divide both sides by 5^4.

5^x = (5^1)/(5^4)

We simplify the right side by the same way we did earlier when we divided exponents:

5^x = 5^(1-4)

5^x = 5^-3

We can see that x = -3, but using logarithms, we can finish isolating x. Taking the log base 5 of both sides, we get:

x = log₅(5^-3)

If you don't already know, log₅(5^-3) means what exponent do you raise 5 to in order to get 5^-3. After stating it like this, we can clearly see that log₅(5^-3) equals -3.

So x = -3

Another way we could have solved the logarithm is by using one of the laws of exponents. In this case, we would use logₐ(x^y) = y(logₐm). This would give us:

x = -3(log₅5)

x = -3(1)

x = -3

Either way works.

Answer: Subtituting CD =5 in AB + CD = JK

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

• AB + CD = JK (equation 1 )

• CD = 5 (equation 2)

So, we simply have to combine the equations.

Substituting CD =5 in equation 1:

AB + CD = JK

AB+(5) =JK

Feel free to ask for more if needed or if you did not understand something.  

The steps that you need is to add subtract and divide all the slopes to get your answer

Answer:

Sample Answer:   Start by choosing two data points. Calculate the difference between the second y value and the first y value. Then divide that by the difference between the second x value and the first x value.

Answer:

[tex]\displaystyle y' = -4(4x - 1)(4 - x^5)^3(22x^5 - 5x^4 - 8)[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Distributive Property

Algebra I

Terms/CoefficientsFactoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

y = (4x - 1)²(4 - x⁵)⁴

Step 2: Differentiate

Product Rule:                                                                                                 [tex]\displaystyle y' = \frac{d}{dx}[(4x - 1)^2](4 - x^5)^4 + (4x - 1)^2\frac{d}{dx}[(4 - x^5)^4][/tex]Chain Rule [Basic Power Rule]:                                                                       [tex]\displaystyle y' = [2(4x - 1)^{2 - 1} \cdot \frac{d}{dx}[(4x - 1)]](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^{4 - 1} \cdot \frac{d}{dx}[(4 - x^5)]][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(4x - 1) \cdot \frac{d}{dx}[(4x - 1)]](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot \frac{d}{dx}[(4 - x^5)]][/tex]Basic Power Rule:                                                                                         [tex]\displaystyle y' = [2(4x - 1) \cdot 4x^{1 - 1}](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot -5x^{5 - 1}][/tex]Simplify:                                                                                                          [tex]\displaystyle y' = [2(4x - 1) \cdot 4](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot -5x^4][/tex]Multiply:                                                                                                         [tex]\displaystyle y' = 8(4x - 1)(4 - x^5)^4 - 20x^4(4x - 1)^2(4 - x^5)^3[/tex]Factor:                                                                                                           [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 2(4 - x^5) - 5x^4(4x - 1) \bigg][/tex][Distributive Property] Distribute 2:                                                             [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 8 - 2x^5 - 5x^4(4x - 1) \bigg][/tex][Distributive Property] Distribute -5x⁴:                                                         [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 8 - 2x^5 - 20x^5 + 5x^4 \bigg][/tex][Brackets] Combine like terms:                                                                     [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3(-22x^5 + 5x^4 + 8)[/tex]Factor:                                                                                                           [tex]\displaystyle y' = -4(4x - 1)(4 - x^5)^3(22x^5 - 5x^4 - 8)[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

Answer:

3x+6y =0

-6y

3x=-6y

x=-2y

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

(x^3)(x^4) = (xxx)(xxxx) = x^7 when multiplying you add the exponents

(x^5)÷(x^2) = (xxxxx)÷(xx) = xxx or x^3 because two of the x's reduce therefore when dividing you subtract the exponents

(x^2)^3 = (x^2)(x^2)(x^2) = (xx)(xx)(xx) = x^6 when raising a power to a power you multiply the exponents

Answer:

Look at the attachment

The equation is an illustration of a linear function.

The equation for the number of pages left in the book is [tex]b =p- rd[/tex]

The total number of pages is:

[tex]Total = p[/tex]

The daily rate is:

[tex]Rate = r[/tex]

So, the number of pages read in d days is:

[tex]Pages = Rate \times Days[/tex]

This gives

[tex]Pages = r \times d[/tex]

Multiply

[tex]Pages = rd[/tex]

The number of pages left (b) is then calculated as:

[tex]b =Total - Pages[/tex]

So, we have:

[tex]b =p- rd[/tex]

Hence, the equation for the number of pages left in the book is [tex]b =p- rd[/tex]

Read more about linear equations at:

https://brainly.com/question/14323743

Answer:

x = 45°

Step-by-step explanation:

Look at the picture*