In the equation y/6 = 156, what is the next step in the equation solving sequence

Step-by-step explanation:

all the details You can find in the attachment.

Answer:

2x+3+9

because plyer scored 9 points and throw 2point shotand same number 3

Answer:

C

Step-by-step explanation:

The correct statement is option C.

A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively. Additionally, i = √-1 and both a and b are real numbers.

Since we know that

Complex number is of the form a+ib

Where,

a is real number belongs to real axis

And b is also a real number belongs to imaginary axis.

And the value of i = √-1

Thus,

The set of all numbers of the form a+bi, where a and b are any

real numbers and i equals √-1 is the correct statement.

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Answer:

easy = 391 items

hard = there are 8 more girls than there are boys

Answer:

360

Step-by-step explanation:

using the definition

n [tex]P_{r}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]

where n! = n(n - 1)(n - 2)..... × 3 × 2 × 1

then

6[tex]P_{4}[/tex]

= [tex]\frac{6!}{(6-4)!}[/tex]

= [tex]\frac{6!}{2!}[/tex]

= [tex]\frac{6(5)(4)(3(2)(1)}{2(1)}[/tex] ← cancel 2(1) on numerator / denominator

=  6 × 5 × 4 × 3

= 360

Answer: 1/2

Step-by-step explanation:

Dividing the numerator and denominator by x, we get the limit is equal to:

[tex]\lim_{x \to -\infty} \frac{-\sqrt{1+\frac{5}{x}+\frac{1}{x^2}}+3}{4+\frac{7}{x}}\\\\=\frac{\lim_{x \to -\infty} \left(-\sqrt{1+\frac{5}{x}+\frac{1}{x^2}}+3 \right)}{\lim_{x \to -\infty} \left(4+\frac{7}{x} \right)}\\\\=\frac{2}{4}=\boxed{1/2}[/tex]

The expression (a²b¹c)² × (6a³b) × (2c³)³ × (4ab¹) × (2c³) is equivalent to the expression 384a⁸b⁴c¹⁴.

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

⇒ (a²b¹c)² × (6a³b) × (2c³)³ × (4ab¹) × (2c³)

By simplifying, we have

⇒ a⁴b²c² × 6a³b × 8c⁹ × 4ab¹ × 2c³

⇒ 384a⁸b⁴c¹⁴

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Answer:

the answer will be similar, because if you divide 2, 3, 2.25 by 3 you will get the answer.

Answer:

Linear Equations In One Variable =

[6(x-1)6] / 7 = 12

[(6x - 6)6] = 84

[36x - 36] = 84

36x = 84 + 36

36x = 120

x = 120/36

x = 10/3

equation solved (Answer : 10/3)

The fraction of the total number of marbles is left in the bag after removing and giving part to her friend is 3/8

let

Remaining marbles = x - 1/2x

= (2x-x) / 2

= x/2

= 1/2x

Number of marbles given to her friend = 1/4 of 1/2x

= 1/4 × 1/2x

= 1/8x

Number of marbles left in the bag = Remaining marbles - Number of marbles given to her friend

= 1/2x - 1/8x

= (4x-x) / 8

= 3x/8

= 3/8x

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Answer:

Breyer

Step-by-step explanation:

1gallon=128oz half gallon=64oz

We can make both of their unit to 224oz: 14x16=224oz 64x3.5=224oz

Haagen Dazs:3.67x16=58.72/224oz

Breyer: 4.69x3.5=16.415/224oz

Breyer’s way cheaper

Applying the negative exponent, the equivalent expression  [tex]3^{-3}[/tex]  is 1/27.

The exponents of a number are defined as the representation of a number that shows how many times a number is multiplied by itself.

When we have a negative exponent, we use a fraction, with the term with the exponent going to the denominator.

Hence, the equivalent expression is:

[tex]3^{-3} = \dfrac{1}{3^3} = \dfrac{1}{27}[/tex]

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The range of the function g(x) will be (–∞, –4] ∪ [2, ∞). Option C is correct.

The domain denotes all potential x values, while the range denotes all possible y values.

When we plot the graph of the given function we will get the maximum and the minimum value till we get the function plot. The difference in the value of those coordinates is the range of the function.

The range of the function g(x) will be (–∞, –4] ∪ [2, ∞).

Hence option C is correct.

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How much more he has to credit to be worth what it was at at the start of 2010 is: 3,657,000.

Firsts step

Total amount debited=8,000+207,000

Total amount debited=215,000

Total amount credited=116,000+12,000

Total amount credited=128,000

Second step

Additional amount to credit:

40 Lakhs is 4,000,000

Hence:

Additional amount to credit=4,000,000- (215,000+128,000)

Additional amount to credit=4,000,000-343,000

Additional amount to credit=

Therefore how much more he has to credit to be worth what it was at at the start of 2010 is: 3,657,000.

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The correct answer is option A which is the operating profit will be $73000.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that:-

We will consider the following notations and will make the expression for operating profit.

P = profit

S = sales = $900000

F = Fixed cost = $197000

V = 07S = variable cost

So the expression will be given as:-

P = S - F - V

P = S - F - 0.7S

P = 9000000 - 1797000 - ( 0.7 x 9000000)

P = 703000 - 630000

P = $73000

Therefore the correct answer is option A which is the operating profit will be $73000.

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Answer:

need more info

Step-by-step explanation:

what I can tell you is that when you change all the x's in the equation to 6s, both sides of the equation will equal eachother.

Answer:

i think, bond rating agencies giving CDOs very low ratings, discouraging investors to invest

Step-by-step explanation:

Answer:

4mm

Step-by-step explanation:

you have to add both sides after substituting each of the 4 sides by 1mm

which gives you the total of 4

Answer:

defectionist forme solb ifv

Statement 1

Twice the sum of the odd numbers would be:

[tex]2(1+3+5+\cdots+99)=2+6+10+\cdots+198[/tex], which is not equal to the sum of all the even numbers from 1 to 100.

Statement 2

The sum of all the odd numbers from 1 to 100 can be thought of as an arithmetic sequence containing 50 terms, with first term 1 and common difference 2. This means the sum of the series would be:

[tex]\frac{50}{2}[2(1)+(50-1)(2)]=2500[/tex]

which is not equal to 1002.

The statement 1 and the statement 2 are incorrect.

The sum of the arithmetic series of first term a₁ and common difference d will be s= n/2{2a₁+(n-1)d

Statement 1:

Given in statement 1, Twice the sum of the odd numbers would be:

2(1+3+5+7.......+99)=2+6+10+14+.....198

which is not equal to the sum of all the even numbers from 1 to 100.

Statement 2:

The sum of all the odd numbers from 1 to 100 can be calculated as follows where this is an arithmetic sequence of 50 terms, where the first term is 1 and the common difference is 2. This means the sum of the arithmetic series would be:

s= n/2{2a₁+(n-1)d}

putting the above formula

a₁=1

n=50

d=2

s= 50/2{2(1)+(50-1)2} = 25{2+98} =2500 ≠1002

which is not equal to 1002.

Therefore statement 1 and 2 are incorrect.

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The base case of [tex]n=1[/tex] is trivially true, since

[tex]\displaystyle P\left(\bigcup_{i=1}^1 E_i\right) = P(E_1) = \sum_{i=1}^1 P(E_i)[/tex]

but I think the case of [tex]n=2[/tex] may be a bit more convincing in this role. We have by the inclusion/exclusion principle

[tex]\displaystyle P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1 \cup E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1) + P(E_2) - P(E_1 \cap E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le P(E_1) + P(E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le \sum_{i=1}^2 P(E_i)[/tex]

with equality if [tex]E_1\cap E_2=\emptyset[/tex].

Now assume the case of [tex]n=k[/tex] is true, that

[tex]\displaystyle P\left(\bigcup_{i=1}^k E_i\right) \le \sum_{i=1}^k P(E_i)[/tex]

We want to use this to prove the claim for [tex]n=k+1[/tex], that

[tex]\displaystyle P\left(\bigcup_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)[/tex]

The I/EP tells us

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cup E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right)[/tex]

and by the same argument as in the [tex]n=2[/tex] case, this leads to

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1})[/tex]

By the induction hypothesis, we have an upper bound for the probability of the union of the [tex]E_1[/tex] through [tex]E_k[/tex]. The result follows.

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^k P(E_i) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)[/tex]

Using the normal approximation to the binomial, it is found that the probabilities are given as follows:

a) 0.0055 = 0.55%.

b) 0.2296 = 22.96%.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The parameters of the binomial distribution are given as follows:

n = 150, p = 0.889.

Hence the mean and the standard deviation of the approximation are:

Item a:

Using continuity correction, the probability is P(123.5 < X < 124.5), which is the p-value of Z when X = 124.5 subtracted by the p-value of Z when X = 123.5, hence:

X = 124.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{124.5 - 133.35}{3.8473}[/tex]

Z = -2.3

Z = -2.3 has a p-value of 0.0107.

X = 123.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{123.5 - 133.35}{3.8473}[/tex]

Z = -2.56

Z = -2.56 has a p-value of 0.0052.

Hence the probability is 0.0107 - 0.0052 = 0.0055 = 0.55%.

Item b:

The probability is P(112.5 < X < 130.5), which is the p-value of Z when X = 130.5 subtracted by the p-value of Z when X = 112.5, hence:

X = 130.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{130.5 - 133.35}{3.8473}[/tex]

Z = -0.74

Z = -0.74 has a p-value of 0.2296.

X = 112.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{112.5 - 133.35}{3.8473}[/tex]

Z = -5.42

Z = -5.42 has a p-value of 0.

Hence the probability is 0.2296 - 0 = 0.2296 = 22.96%.

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The correct answer is option 4 which is f(x) = 2.9|x| is narrower than the parent function f(x) = |x|

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

Given parent function is f(x)=|x|

Now we have to find which function from given choices will be narrower than the parent function.

Notice that adding or subtracting some number from the parent function only shifts the graph up, down, and left of the right side.

But that will not make the function narrower or broader.

So f(x) = |x – 2| and f(x) = |x| + 3, can't be the answer.

Multiplying by some positive real number which is more than 1, makes the function narrower.

Only f(x) = 2.9|x| from remaining choices fits that case.

Hence correct answer is option 4 which is f(x) = 2.9|x| is narrower than the parent function f(x) = |x|

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Answer:

D,E

Step-by-step explanation:

Answer: [tex]\frac{\sqrt{113}}{7}[/tex]

Step-by-step explanation:

As X is an acute angle, all 6 trigonometric functions with an argument of X are positive.

Using the identity [tex]1+\tan^{2} X=\sec^{2} X[/tex],

[tex]1+\left(\frac{8}{7} \right)^{2}=\sec^{2} X\\\\\sec^{2} X=\frac{113}{49}\\\\\therefore \sec X=\boxed{\frac{\sqrt{113}}{7}}[/tex]

Answer: C, 5, 5√3

Step-by-step explanation:

The short leg of a 30-60-90 triangle equal half the hypotenuse, 10/2 = 5. The long leg equals √3 times the short leg, 5*√3 = 5√3.

Answer:

side ≈ 4.24= [tex]\frac{6}{\sqrt{2} }[/tex]

Step-by-step explanation:

sides a = b

[tex]6^{2} =a^{2} +a^{2}[/tex]

[tex]6^{2} =2a^{2}[/tex]

[tex]a^{2}= \frac{6^{2} }{2} =\frac{36}{2} =18[/tex]

[tex]a=\sqrt{18} =4.24=\sqrt{(9)(2)} =\frac{6}{\sqrt{2} }[/tex]

Hope this helps

Answer: Length = 9 cm, Width = 6 cm

Step-by-step explanation:

L - 3 + L - 3 + L + L = 30

2L - 6 + 2L = 30

4L - 6 = 30

4L = 36

L = 9

Length = 9 cm

Width = 9-3 = 6 cm

Explanation:

Equation: x + 1 = 9

Solving Steps:

x + 1 = 9                 (subtract both sides by 1)

x + 1 - 1 = 9 - 1        (simplify the following)

x = 8

Then check for solution:

x + 1 = 9

                         [insert x = 8]

8 + 1 = 9

9  =  9

As both sides are equal, the statement is true.

[tex]\large\underline{ \cal{SOLUTION:}}[/tex]

[tex] \large \bold{x + 1 = 9}[/tex]

[tex] \large \bold{x = 9 - 1}[/tex]

[tex] \large \bold{x = \red{8}}[/tex]

[tex] \: [/tex]

[tex]\large\underline{ \cal{CHECKING:}}[/tex]

[tex] \large{ \bold{ \underline{ \red{8} }+ 1 = 9}}[/tex]

[tex] \large \bold{-N} \frak{unx-}[/tex]