Answer:
Closer to 30.
Step-by-step explanation:
To answer this first find 40% of 90.
90*0.4=36
0.4 is the same as 40%
Hope this helps!
If not, I am sorry.
Consider the equation below. n2 3h2 right arrow. 2nh3 what is the mole ratio of hydrogen to ammonia?
The mole ratio of hydrogen to ammonia will be 3:2.
What is the chemical equation?A depiction of a chemical reaction using elements' indicators to determine how much of each source and result is present-typically in moles.
The chemical equation is given below.
N₂ + 3H₂ = 2NH₃
Then the mole ratio of hydrogen to ammonia will be 3:2.
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Select the correct answer. The function g(x) = x2 is transformed to obtain function h: h(x) = g(x) − 5. Which statement describes how the graph of h is different from the graph of g? A. The graph of h is the graph of g vertically shifted up 5 units. B. The graph of h is the graph of g horizontally shifted left 5 units. C. The graph of h is the graph of g vertically shifted down 5 units. D. The graph of h is the graph of g horizontally shifted right 5 units.
The graph of h(x) is the graph of g vertically shifted down 5 units. Then the correct option is C.
What is a function?Functions are found all across mathematics and are required for the creation of complex relationships.
The function g(x) = x² is transformed to obtain function h:
h(x) = g(x) − 5
h(x) = x² − 5
The graph h(x) get shifted downward by 5 units.
Then the correct option is C.
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6 numbers that have a median of 8 a mean of 9 and a range of 13?
Answer:
5,6,8,8,9,18
Step-by-step explanation:
...................
2. The smallest number from the given numbers 6895, 4875 and 5689 will have its smallest digits at place. (A)
The smallest digit of the smallest number is at the thousands place.
What is Number System ?The system of representing numbers is called Number System.
The given numbers are 6895 , 4875 , 5689
The smallest number among these is 4875
The smallest digit in this number is 4
4 is at thousands place
Therefore , The smallest digit of the smallest number is at the thousands place.
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q(t)= Q_0 e^-kt where Q represents the quantity remaining after t years and k is the decay constant 0.00043. How long will it take for 500g of radium to decay to 5g?
It takes 16,064 years for the 500g of radium to decay to 5g.
How long will it take for 500g of radium to decay to 5g?
Here we have the decay equation:
[tex]Q(t) = Q_0*e^{-k*t}[/tex]
Where Q₀ is the initial amount, and k is the decay constant.
We know that:
Q₀ = 500g
k = 0.00043
And we want to find the value of t such that Q(t) = 5g, so we need to solve:
[tex]5 = 500*e^{-0.00043*t}\\\\5/500 = e^{-0.00043*t}\\\\0.001 = e^{-0.00043*t}[/tex]
Now we can apply the natural logarithm in both sides:
[tex]ln(0.001) = ln(e^{-0.00043*t})\\\\ln(0.001) = -0.00043*t\\\\\frac{ln(0.001)}{-0.00043} = t = 16,064.5[/tex]
So it takes 16,064 years for the 500g of radium to decay to 5g.
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What is the length of the hypotenuse? If necessary, round to the nearest tenth.
By the Pythagorean theorem,
[tex]a^{2}+12^{2}=13^{2}\\\\a^{2}+144=169\\\\a^{2}=25\\ \\ a=\boxed{5}[/tex]
If f(x) = 2x² + 3x and g(x) = x - 2, what is (f+ g)(2) ?
[tex](f+g)(x)=f(x)+g(x)\\\\f(x)=2x^2+3x\\g(x)=x-2\\\\(f+g)(2)=2\cdot2^2+3\cdot2+2-2=8+6=14[/tex]
In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then do the calculation.
How many ways are there to distribute 8 different books among 21 children if no child gets more than one book?
a.) Combination; Subscript 13 Baseline C Subscript 8 Baseline = 1287
b.) Combination; Subscript 21 Baseline C Subscript 8 Baseline = 203,490
c.) Permutation; Subscript 21 Baseline P Subscript 8 Baseline = 8,204,716,800
d.) Permutation; Subscript 13 Baseline P Subscript 8 Baseline = 51,891,840
Using the permutation formula, it is found that the number of ways to distribute the books is given by:
c. 8,204,716,800
The order is important, as the books are different, hence the permutation formula is used to solve this question.
What is the permutation formula?The number of possible permutations of x elements from a set of n elements is given by:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this problem, 8 books are distributed among 21 children, hence the number of ways is given by:
[tex]P_{21,8} = \frac{21!}{13!} = 8,204,716,800[/tex]
Which means that option c is correct.
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A graph is shown below
what is the equation of the line in slope intercept form HELP ASAP
Answer:
y = -2x + 16
the y intercept is the y value at x = 0. On the graph there is a dot at 16 on x= 0, so the y intercept would be 16.
the only answer choice adding 16 sis y = -2x + 16
can someone please help me with this problem?
If lies in the quadrant IV what can be the value of cos
When Ф lies in quadrant IV the value of cos Ф lies in [0, 1].
What is quadrant?One fourth of the part of a circle is said to be the quadrant of the circle.
Given the angle Ф lies in quadrant IV.
As we know, cos Ф is positive only in first and fourth quadrant i.e when Ф lies in 0<Ф<90 and 270<Ф<360.
cosФ range from [-1,1]
So, cos Ф is positive when Ф lies in 1st and 4th quadrant.
& cos Ф is negative when Ф lies in 2nd and 3rd quadrant.
If cos ∅ lies in the quadrant IV, anything between [0, 1] can be the value of cos ∅.
Hence, when Ф lies in quadrant IV the value of cos Ф lies in [0, 1].
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Write the equation of the line in slope-intercept form Slope=5/3 Y-Intercept=4
Answer:
y=5/3x+4
Step-by-step explanation:
Slope intercept formula: y=mx+b
m=slope
b=Y-Intercept
Answer:
[tex]\sf y=\dfrac{5}{3}x+4[/tex]
Step-by-step explanation:
Given:
[tex]\textsf{slope of $\dfrac{5}{3}$, and a y-intercept of $4$}[/tex]
⇒ Slope-Intercept Form: y = mx + b
where:
m is the slopeb is the y-intercept (when x = 0)Substitute the given values:
[tex]\sf\\ \implies y=mx+b\\\\\implies y=\dfrac{5}{3}x+4[/tex]
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Line / has a slope of. The line through which of the following pair of points is
perpendicular to /?
A. (4, 6), (2, 2) B. (8,8), (2, 4)
C. (8,2), (2,4)
D. (6,2), (2, 4)
Let [tex]A(x_A,\ y_A),\ B(x_B,\ y_B)[/tex]. Then a slope of the line AB represent the formula:
[tex]m=\dfrac{y_B-y_A}{x_B-x_A}[/tex]
Substitute the coordinate od the points to the formula of a slope.
[tex]A.\\(4,\ 6),\ (2,\ 2)\\\\m=\dfrac{2-6}{2-4}=\dfrac{-4}{-2}\\\\\huge\boxed{m=2}[/tex]
[tex]B.\\(8,\ 8),\ (2,\ 4)\\\\m=\dfrac{4-8}{2-8}=\dfrac{-4}{-6}\\\\\huge\boxed{m=\dfrac{2}{3}}[/tex]
[tex]C.\\(8,\ 2),\ (2,\ 4)\\\\m=\dfrac{4-2}{2-8}=\dfrac{2}{-6}\\\\\huge\boxed{m=-\dfrac{1}{3}}[/tex]
[tex]D.\\(6,\ 2),\ (2,\ 4)\\\\m=\dfrac{4-2}{2-6}=\dfrac{2}{-4}\\\\\huge\boxed{m=-\dfrac{1}{2}}[/tex]
Which expression is equivalent to √48x5, if x>0?
OA. 12x³√3x
OB. 4x³√3
OC. 4x²√3x
D. 12x²√x
Answer: C
Step-by-step explanation:
[tex]\sqrt{48x^{5}}=\sqrt{16x^{4}}\sqrt{3x}=\boxed{4x^{2}\sqrt{3x}}[/tex]
A river flows at 2m/s. Juan’s boat can travel twice as fast down the river as it can go up the river. How fast can the boat go in still water?
Answer: 2m/s
Step-by-step explanation:
The boat goes twice as fast down the river, which means it goes twice as slow up the river.
Because the river flows at 2m/s, I think the answer is 2m/s
Let (-7, 2) be a point on the terminal side of 0.
Find the exact values of sin0, sec 0, and tan 0.
By applying the definitions of trigonometric functions, the exact values of the sine, secant and tangent of the point on the terminal side are [tex]\sin \theta = \frac{2}{\sqrt{53}}[/tex], [tex]\sec \theta = -\frac{\sqrt{53}}{7}[/tex] and [tex]\tan \theta = -\frac{2}{7}[/tex].
How to determine the exact values
In this question we need to find the exact values of three trigonometric functions associated with the terminal side of an angle. The following definitions are used:
Sine
[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (1)
Secant
[tex]\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}[/tex] (2)
Tangent
[tex]\tan \theta = \frac{y}{x}[/tex] (3)
If we know that x = - 7 and y = 2, then the exact values of the three trigonometric functions:
Sine
[tex]\sin \theta = \frac{2}{\sqrt{53}}[/tex]
Secant
[tex]\sec \theta = -\frac{\sqrt{53}}{7}[/tex]
Tangent
[tex]\tan \theta = -\frac{2}{7}[/tex]
By applying the definitions of trigonometric functions, the exact values of the sine, secant and tangent of the point on the terminal side are [tex]\sin \theta = \frac{2}{\sqrt{53}}[/tex], [tex]\sec \theta = -\frac{\sqrt{53}}{7}[/tex] and [tex]\tan \theta = -\frac{2}{7}[/tex].
Remark
The statement reports typing errors, correct form is shown below:
Let (x, y) = (- 7, 2) be a point on the terminal side of θ. Find the exact value of sin θ, sec θ and tan θ.
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What are the domain and range of the function represented by the set of
ordered pairs?
{(-7, 1), (-3, 2), (0, -2), (5,5)}
Answer:
see explanation
Step-by-step explanation:
the domain is the set of x- coordinates from the ordered pairs , that is
domain : { - 7, - 3, 0, 5 }
the range is the set of y- coordinates from the ordered pairs, that is
range : { - 2, 1, 2, 5 }
HELP HELP HELP HELP
HELP HELP HELP HELP
HELP HELP HELP HELP
HELP HELP HELP HELP
Step-by-step explanation:
just breathe and read it carefully. no need for panic. all you need is common sense, nothing fancy.
the tools and definitions to use are given in the description. we only need to use them.
the height of the point of view is 44 + 6 = 50 ft (because the eyes are again 6 ft above the top of the hill, and we are dealing with what the eyes can see).
so, the seeable distance D in miles is then
D = sqrt(2×50) = sqrt(100) = 10 miles
she will be able to see approximately 10 miles to the horizon.
How many cubes are needed to build this figure?
4
6
5
3
Answer:
3
Step-by-step explanation:
because I sense three and You need
Which of the following could be the equation of the function below?
y = -3 sin (2 (x + pi)) + 2
y = -3 sine (x + pi) + 2
y = 3 sin (4 (x - pi)) + 4
y = 3 sin (2 (x + pi)) + 2
The equation of the sine function will be y = -3 sin [2(x + π)] + 2. Then the correct option is A.
What is a sinusoidal Function?It is a function that repeats itself in a particular time interval.
The equation is given as
y = A sin (ωx + Ф) + C
Where A is the amplitude, ω is the frequency, Ф is the phase difference, and C is the constant.
From the graph, we have
A = -3
ω = 2
Ф = 2π
C = 2
Then we have the equation will be
y = -3 sin [2(x + π)] + 2
Then the correct option is A.
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Friends can you please explain me what is given in this picture, and tell me how to solve this please!..
Thank you
Step-by-step explanation:
the picture and its text explain it actually already.
each block (or square) on each side represents a fraction.
the whole block is 1. the colored parts are the fraction of that whole (1).
we see the example 2/3 × 3/4
the left block with 2 out of 3 strips marked in pink shows us 2/3 (2/3 of the block is pink).
the right block with 3 out of 4 strips marked in purple shows us 3/4 (3/4 of the block is purple).
it is essential for this method to orient the strips in one block to be at a right angle with the strips of the other block.
now, to do the multiplication you overlay the strips of both blocks.
you see this creates a chess board pattern. the total number of little squares or rectangles is the denominator (bottom part) of the result. in this case 12.
the number of little squares or rectangles that are in both original strips is the numerator (the top part) of the result. in this case 6.
so, yes, 2/3 × 3/4 = 6/12, which can then be refined to 1/2.
now, you have to do the same thing with the actual examples (I cannot draw here, sorry) :
1/4 × 3/5 = 3/20
the left block with 4 strips (one in pink, or whatever color you want), the right block with 5 strips (and 3 marked in e.g. purple).
and then the result block with 4 columns and 5 rows creating 20 little squares or rectangles, and 3 of them are in all original strips.
and the same
3/5 × 2/3 = 6/15 = 2/5
1/2 × 2/5 = 2/10 = 1/5
AD and CD are tangents to the circle below
Calculate the size of angle 0
Answer: [tex]59^{\circ}[/tex]
Step-by-step explanation:
In triangle ABC, we know that [tex]\angle ABC=130^{\circ}-\theta[/tex]. So, by the inscribed angle theorem, minor arc AC is equal to [tex]260^{\circ}-2\theta[/tex].
Thus, major arc AC is equal to [tex]100^{\circ}+2\theta[/tex].
Using the fact that the angle formed by the two tangents is 38 degrees,
[tex]\frac{(100^{\circ}+2\theta)-(260^{\circ}-2\theta)}{2}=38^{\circ}\\\\100^{\circ}+2\theta-260^{\circ}+2\theta=76^{\circ}\\\\4\theta-160^{\circ}=76^{\circ}\\\\4\theta=236^{\circ}\\\\\theta=\boxed{59^{\circ}}[/tex]
A quilt is designed using a square pattern. Each square contains two rectangles. Each rectangle contains a shaded rhombus.
Each rectangle contains a shaded rhombus. The left angle is 50 degrees and the top angle is (2 x + 20) degrees.
What is the value of x?
50
55
125
145
According to the computations, this rhombus's value of x is equal to 55°.
How can we calculate x's value?The total of all the angles in a rhombus should be 360 ° because the opposing angles in a rhombus are always identical.
We may infer the preceding information from the rhombus's picture:
Neighboring angles= 2x+ 20 & 50°
Opposite angles=2x+ 20 & 50°
Combining the angles results in:
2x+20+50+2x+20+50=360
⇒4x+140= 360
⇒4x=360-140
⇒4x=220
⇒x=220/4
⇒x=55°
Hence, it is concluded that the value of x is (b) 55°.
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Round the number to the nearest ten-thousands:
388,725
a. 400,000
b.390,000
c. 388,800
d. 389,000
Answer:
B is the correct answer
Step-by-Step:
Weiming receives a weekly pocket money of $28. If he decides to save 20% of it, find his saving in a year and spendings in a year
Welming's spending is $1164.8 and his savings is $291.2
How to determine the savings and the spending?The given parameters are:
Weekly pocket = $28
Save = 20%
There are 52 weeks in a year.
So, the yearly pocket is:
Yearly pocket = $28 * 52
Evaluate
Yearly pocket = $1456
He saves 20%.
So, we have:
Savings = 20% * $1456
Evaluate
Savings = $291.2
His spending is then calculated as:
Spending = $1456 - $291.2
Evaluate
Spending = $1164.8
Hence, Welming's spending is $1164.8 and his savings is $291.2
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What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12
Answer:
x≥20
Step-by-step explanation:
-3(6-2x)≥4x+12
or, -18+6x≥4x+12
or, -18-12≥4x-6x
or, -40≥-2x
or, -40/2≥-x
or, -20≥-x
or, 20≥x
= x≥20
Match the function with the graph.
a. y = |x+ 5|
b. y= |x-5| + 2
c. y= |x-5|
d. y=|x| -5
i did a and it was wrong. i don’t understand lol please help
C. y= |x-5|
you have the right idea, it's being shifted horizontally so the shift would be shown inside of the brackets. However, it would be |x-5| not |x+5| because the graph is shifting to the right.
Tawny wrote an expression to represent “the quotient of 82 and a number, decreased by 26.” She then evaluated the expression when n = 2. Which statements are true about the expression and its value? Check all that apply.
The correct expression is 82 minus StartFraction 24 Over n EndFraction.
To evaluate the expression, subtract 26 from the quotient.
To evaluate the expression, subtract the quotient from 82.
The correct expression is StartFraction 82 Over n EndFraction minus 26.
The operations include division and subtraction.
To evaluate, substitute 24 for the variable in the equation.
The value of the expression is 15.
The correct expression is (82/n) - 26 ,The operations include division and subtraction , To evaluate, substitute 2 for the variable in the equation , the value of the expression is 15 , Option D, E and F is the answer.
What is an Expression ?An expression is the mathematical statement consisting of variables , constant and mathematical operators .
It is given that the expression has to be formed from the data
the quotient of 82 and a number, decreased by 26
Let the number from which it is divided is n then
quotient * divisor = 82
quotient = 82 /n
(82/n) - 26 is the expression formed from the data
When n =2
the expression value is
41 -26
15
The correct expression is StartFraction 82 Over n EndFraction minus 26.
The operations include division and subtraction.
To evaluate, substitute 2 for the variable in the equation , the value of the expression is 15.
Therefore Option D, E and F is the answer.
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Answer:D.E.F
Step-by-step explanation:
Triangle is reflected across the y-axis and then dilated by a factor of centered at the origin. Which statement correctly describes the resulting image, triangle ? Image of right triangle ABC in a graph with vertices A (minus 4, minus 2), B (4, minus 2), and C (4, 4) A. Both the reflection and dilation preserve the side lengths and angles of triangle . B. The reflection preserves the side lengths and angles of triangle . The dilation preserves angles but not side lengths. C. The dilation preserves the side lengths and angles of triangle . The reflection does not preserve side lengths and angles. D. Neither the reflection nor the dilation preserves the side lengths and angles of triangle .
Answer: B. The reflection preserves the side lengths and angles of the triangle. The dilation preserves angles but not side lengths.
Step-by-step explanation:
Reflections are congruency transformations, but dilations are similarity transformations.
In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point (-2, 2, 0)?
The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m
How to calculate the electric field?Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,
The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k
Since V = 2x − 5x²y + 3yz²
dV/dx = d(2x − 5x²y + 3yz²)/dx
= d2x/dx - d5x²y/dx + d3yz²/dx
= 2 - 10xy + 0
= 2 - 10xy
dV/dy = d(2x − 5x²y + 3yz²)/dy
= d2x/dy - d5x²y/dy + d3yz²/dy
= 0 - 5x² + 3z²
= - 5x² + 3z²
dV/dz = d(2x − 5x²y + 3yz²)/dz
= d2x/dz - d5x²y/dz + d3yz²/dz
= 0 - 0 + 6z
= 6z
The electric field
So, E = -grad(V)
= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]
= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]
So, the electric field at (-2, 2, 0) is
E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]
E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]
E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]
E = -[42i + (-20 + 0)j + (0)k]
E = -[42i - 20j + 0k]
E = -42i + 20j - 0k
The magnitude of the electric field
So, the magnitude of E at (-2, 2, 0) is
|E| = √[(-42)² + 20² + 0²]
= √[1764 + 400 + 0]
= √2164
= 46.52 V/m
So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m
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