Is 937.5 as the same as 937.50 Answer the question.​

Answer:

b

Step-by-step explanation:

when u plug in -6 u get the equation equal to 0 which means x+6 is a factor of that function.

A ratio shows us the number of times a number contains another number. The correct option is C.

A ratio shows us the number of times a number contains another number.

For winning less than $10, a person needs to take out a green ticket or a yellow ticket. Therefore, the odds against winning less than $10 are,

(Number of blue tickets) : (Number of green and yellow tickets)

5: 30

1: 6

Hence, the correct option is C.

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Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

[tex]ax^2+bx+c=0[/tex]

Let's find a, b, c:

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}[/tex]

[tex]x=\frac{5\pm\sqrt{121} }{4}[/tex]

[tex]x=4[/tex] or [tex]x=\frac{-3}{2}[/tex]

Answer:

x = 4 or x = -3/2

Answer:The end of immigration quotas in the 1960s led to

a significant decrease in safe places for refugee immigrants.

a significant increase in discrimination against immigrants.

a significant increase in the number of Asian immigrants.

a significant decrease in the number of Asian immigrants.

Step-by-step explanation:

Answer:

380.1

Step-by-step explanation:

A=[tex]\pi[/tex]r^2

A=[tex]\pi[/tex]*11*11

A~ 380.13 m^2

nearest tenth: 380.1

Maximum total 8 points in which the sides of the quadrilateral can intersect the sides of the hexagon.

A regular hexagon is a closed shape polygon which has six equal sides and six equal angles. In case of any regular polygon, all its sides and angles are equal.

A convex quadrilateral is a four-sided polygon that has interior angles that measure less than 180 degrees each. The diagonals are contained entirely inside of these quadrilaterals

Take a look at just one side of the quadrilateral—a straight line. Since we are told that no side of the quadrilateral lies on the same line as a side of the hexagon, the maximum number of times a side of the quadrilateral could intersect the hexagon is 2. We can use a ruler to test this on the image of the hexagon. There is no way to pass a straight line through the hexagon and have it intersect the shape more than 2 times. Therefore, the maximum number of points at which the quadrilateral could intersect the hexagon would be

at 2 points per side, at 2 × 4 = 8 points.

Hence, Maximum total 8 points in which the sides of the quadrilateral can intersect the sides of the hexagon.

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Answer:

t= 31/175 ≈ 5.64516129

​

Step-by-step explanation:

Refer Pic For Steps....

Hope it Helps!!!

Answer:

so y represents her age right now so if we go back we are subtracting so he age would be y-5

a

Hope This Helps!!!

½×½ which will be ¼

Step-by-step explanation:

because

Probability that the starting player wins:

[tex]P_{n} =[/tex]  m /n + m + n(n-1) /(n + m)(n+m -1) × [tex]P_{n-2}[/tex]

Let us say that the probability that the first player wins is [tex]P_{n}[/tex]. Then this can be happen in two ways:

If the first player wins in the first move which has a probability: m /n + m

If the first player wins after the second move which has a probability :

n(n-1) /(n + m)(n+m -1) × [tex]P_{n-2}[/tex]

Therefore by the law of probability,

[tex]P_{n} =[/tex]  m /n + m + n(n-1) /(n + m)(n+m -1) × [tex]P_{n-2}[/tex]

This will allow us to find out the probability of first player winning the game recursively.

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Answer:

[tex]\large\boxed{\sf n^2 \ log \ x }[/tex]

Step-by-step explanation:

Given that ,

[tex]\longrightarrow \log \ x + \log\ x^3 + \log \ x^5\ \dots + \log x^{2n-1} [/tex]

As we know that , [tex] \log x^n = n \log x [/tex] , therefore ;

[tex]\longrightarrow \log x + 3\log x + 5\log_x +\dots + (2n-1)\log x [/tex]

Take out log x as common ;

[tex]\longrightarrow \log x ( 1 + 3+5+...+(2n-1))[/tex]

The terms inside the brackets are the sum of first n odd numbers . And we know that the sum of first n odd numbers in n² . Therefore ;

[tex]\longrightarrow \log x (n^2) \\[/tex]

[tex]\longrightarrow \underline{\underline{\red{{ n^2\log x }}}}[/tex]

Option c is correct!

The value of each algebraic expressions are:

1. 16

2. 156

3. 87

4. 3

5. 300

6. 4

7. 68

An algebraic expression is a mathematical statement involving variables and digits. It is evaluated by plugging in the value of the variables.

1. Product of y and 12 is 12y

100 - 12y

Plug in the value of y

100 - 12(7) = 16

2. b(15 + 37) = b(52) = 3(52)

= 156

3. Product of z and 12 is 12z

12z + 27 = 12(5) + 27

= 87

4. 135 ÷ 5c = 135/5(9)

= 3

5. w²(12/4) = 3w²

= 3(10²)

= 300

6. 12d ÷ (25 - 19)

12d/6 = 12(2)/6

= 4

7. 13 + 5x

13 + 5(11)

= 68

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Answer:

2 days 21 hours and 50 minutes

Step-by-step explanation:

There are a couple of ways to solve this. Here is my approach

Convert everything to the lowest unit ie minutes, find the difference and then find the equivalent days, hours and minutes

Note

1 hour = 60 minutes

1 day = 24 hours * 60 minutes/hour = 1440 minutes

So,

7 days, 8 hours, 20 minutes = 7 * 24 * 60 + 8 * 60 + 20 = 10580 minutes
4 days, 10 hours, 30 minutes = 4 * 24 * 60 + 10 * 60 + 30 = 6390 minutes

Difference(elapsed time) = 10580 - 6390 = 4190 minutes

Convert 4190 to days, minutes and hours. This is a process of using whole division to find the quotient and remainder successively

For days, divide by 1440 which is the number of minutes in a day:
4190 minutes ÷ 1440 minutes = 2 whole days  with remainder of 1390 minutes

For hours divide by 60 which is the number of minutes in an hour:
the remainder 1390 minutes ÷ 60 minutes = 21 whole hours with remainder of 50 minutes

So 4190 minutes == 2 days, 21 hours and 50 minutes

Considering the formulas for the area and the perimeter of the rectangle, the one with the desired measures is given as follows:

a length of 3 units and a width of 4 units.

Considering a rectangle of length l and width w, we have that:

For a rectangle with a length of 3 units and a width of 4 units, we have that:

Hence it is the correct option.

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Answer:

A

Step-by-step explanation:

.......STP=90°........

The value of composite function (koh)(x) is 1/(5+x) after plugging h(x)  = 5+x in the k(x) option (B) is correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The question is:

if h(x)=5+x and k(x)=1/x which expression is equivalent to (koh)(x)

Answer options are:

We have:

h(x) = 5 + x

k(x) = 1/x

To find the composite function:

(koh)(x):

= k(h(x))

= 1/(5+x)

Thus, the value of composite function (koh)(x) is 1/(5+x) after plugging h(x)  = 5+x in the k(x) option (B) is correct.

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Answer:

https://www.khanacademy.org/

Step-by-step explanation:

I am not entirely sure what you mean however if you sign up for this website and go to whichever grade level you need you can practice all you want

Answer:

Online customers buy an average of 4 packs compared with walk-in customers, who buy an average of 2 packs.

Step-by-step explanation:

Create the dot plots (see attached diagrams)

Online customers: blue dots

Walk-in customers: red dots

To calculate the average packs both groups of customers buy, sum all data values and divide by the total number of data values.

[tex]\textsf{Average of Online customers}=\dfrac{ 1 \times 3+ 4 \times 4+ 5\times 5}{10}=4.4[/tex]

[tex]\textsf{Average of Walk-in customers}=\dfrac{ 3 \times 1+ 6\times 2+ 1\times 3}{10}=1.8[/tex]

Online:  4.4 rounds down to 4

Walk-in:  1.8 rounds up to 2

Therefore, online customers buy an average of 4 packs compared with walk-in customers, who buy an average of 2 packs.

Find average of both customers

Online :-

Offline

option C

Answer:

$ 63

Step-by-step explanation:

Let the new price ( price after the discount ) be x.

Old price                    Discount                     New price

 100                              30                                  70

  90                               30                                   x

Now we can make an expression like this to solve this

100  ⇒  70

90  ⇒ x

Use cross multiplication to solve for x.

100x = 70 × 90

100x = 6300

Divide both sides by 100.

x = $ 63

Answer:

Discount: $27.00

Final Price: $63.00

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 90 × 30/100

Discount = 90 x 0.3

You save = $27.00

Final Price = Original Price - Discount

Final Price = 90 - 27

Final Price = $63.00

[tex]\text{First I'd recommend replacing the number with just n.}\\\text{Now, multiply this number by 2:: 2n}\\\text{Multiply 10 by it:: 2n*10}[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\text{6 is subtracted from (2n*10):: (2n*10)-6}[/tex]

[tex]\text{This gives a total of 20}[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\text{(2n*10)-6=20}[/tex]

A quadrilateral in which opposite sides are parallel is called a parallelogram. The measure of the ∠GFH is 16°.

A quadrilateral in which opposite sides are parallel is called a parallelogram. Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.

For a parallelogram and a rhombus opposite sides are parallel, therefore, the sides that are parallel are,

AB║DC║ED║FG

Since the sides are parallel,

∠ABC = ∠FGH = 126°

Also, ∠AHC and ∠GHF lie on the same line, therefore,

∠AHC + ∠GHF = 180°

∠GHF = 180° - 142° = 38°

Now, in ΔGHF

∠GHF + ∠HFG + ∠GFH = 180°

∠GFH = 180° - 126° - 38°

∠GFH = 16°

Hence, the measure of the ∠GFH is 16°.

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Answer:

The diameter is 10 cm. the radius is 5 cm. the area is πr² = π x 5² = 78.5 cm².

1 m² = 10,000 cm².

78.5/10,000 = 3,300/n n is the cost per square meter.

78.5n = 10,000 x 3300

n = 420,382.1656

The cost per square meter is $420,382.17.

The equivalent expression to 7^13/7^7 would be 7^6.

Those expressions that might look different but their simplified forms are the same expressions are called equivalent expressions.

To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

We have given an expression as  7^13/7^7

The equivalent expression;

[tex]\dfrac{7^{13}}{7^7} \\\\7^{13-7}\\\\7^6[/tex]

Hence, The equivalent expression to 7^13/7^7 would be 7^6.

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The second data set represents the boxplot because in the box plot the measure of statistics is the same as the data set option second is correct.

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

We have given a data set and a box plot shown in the picture.

From the boxplot we can see:

Minimum value = 2

Q1 = (2+4)/2 = 3

Median = (4+6)/2 = 5

Q3 = (8+10)/2 = 9

Maximum value = 10

The second data set:

{2, 3, 3, 4, 5, 5, 8, 10, 10}

Minimum value = 2

Q1 = (2+4)/2 = 3

Median = (4+6)/2 = 5

Q3 = (8+10)/2 = 9

Maximum value = 10

Thus, the second data set represents the boxplot because in the box plot the measure of statistics is the same as the data set option second is correct.

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Reason:

sorry but here is no options so I am giving you a example so that you can understand by your own!

Answer;

5r+3

2x-6

X4+10

4y-1

Step by step answer;

So the method of identifying the Monomail is if you see a variable in a constant so it is a Monomail !

The value of the sin theta will be equal to [tex]Sin\theta =\sqrt{\dfrac{2}{3}}[/tex]

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle termed trigonometry.

Given that:-

The value of Sin will be calculated as:-

[tex]Sin^2\theta +Cos^2\theta = 1\\\\Sin^2\theta + \dfrac{\sqrt{3}}{2}=1\\\\Sin^2\theta = 1 -\dfrac{1}{3}\\\\Sin\theta = \sqrt{\dfrac{2}{3}}[/tex]

We can see that the value of sin is less than zero therefore

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The volume of the second parallelepiped will be 1 cm³. According to the given conditions, α is 50% of a, β is 20% of b and γ is 10% of c.

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

Given condition;

α is 50% of a, β is 20% of b and γ is 10% of c

α =  a/2

β = b/5

γ = c/10

The volume of the first parallelepiped:

V = abc

100cm³=abc

The volume of the second parallelepiped:

[tex]\rm V'= \alpha \times \beta \times \gamma \\\\ \rm V'= \frac{a}{2} \times \frac{b}{5} \times \frac{c}{10} \\\\ V' = \frac{abc}{100} \\\\ V'=\frac{100}{100} \\\\ V' = 1 cm^3[/tex]

Hence, the volume of the second parallelepiped willl be 1 cubic meter.

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Answer: 2

Step-by-step explanation:

[tex]{12x+2}=\frac{18+34}{2}\\\\12x+2=26\\\\12x=24\\\\x=\boxed{2}[/tex]