It is 6 kilometers from Linda's house to the nearest mailbox. How far is it in meters?

The union consists of all of the elements that are contained in each interval.

Inequality Form:

x<6

Interval Notation:

(−∞,6)

The answer will be Rs. 4330.

Step-by-step explanation:

Because if you subtract 340 from 4670, you will get the answer which is 4330.

Answer:

a=1.66

b=8368.12

Step-by-step explanation:

hope it helps

The logical conclusion from the statement is that

B. The opposite sides of a rhombus are congruent.

From the information given, if shape is a parallelogram, then opposite angles are congruent.

In this case, since the rhombus is a parallelogram, then the opposite sides of a rhombus are congruent.

In conclusion, the correct option is B.

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The domain of the linear function is (1.5, ∞) and the range of the linear function will be (40, ∞).

The domain means all the possible values of x and the range means all the possible values of y.

A carpet installer charges a flat rate of $40 and $1.50 per square foot for labor.

So the total cost for the labor depends on the amount of carpet installed, the relationship between the total cost for labor and the amount of corporate installed.

Then the domain of the relation is the range of the relation will be

Let y be the total amount and x be the number of square foot.

y = 1.5x + 40

Then the domain of the linear function is (1.5, ∞) and the range of the linear function will be (40, ∞).

The graph is given below.

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Answer:

3/2+1/2+17/2=21/2

Answer: 21/2 hours or 10 1/2 hours

Step-by-step explanation:

To find out the total number of hours needed for all activities scheduled for the day, simply add the needed hours for each activity.

You just need to add them because they have the same denominator.

3/2 for homework

1/2 for home chores

17/2 for sleep

[tex]\frac{3}{2} + \frac{1}{2} + \frac{17}{2} = \frac{21}{2}[/tex] hours

The length of the actual tree will be 72 inches.

Fraction is the portion of a total amount where the above part of the fraction is the denominator and the bottom part of the fraction is called the numerator.

The equation whose highest degree of the variable is 1 is called a linear equation.

Here given that the length of a painting of the tree is 2/9 of the actual length of the tree.

So mathematically the length of a painting= (2/9)*the length of actual tree

Let the length of the actual tree is x

then from above it is clear that the length of a painting of the tree= (2/9)x

Given the length of the painting is 16 inches.

So the linear equation will be (2/9)x= 16

⇒ x= 16/(2/9)

⇒x= 16*9/2

⇒x=72 inches

Therefore the length of the actual tree will be 72 inches.

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Question 24 :

P594.65 : 35 days

P594.65/7 : 35/7 days

P84.95 : 5 days

⇒ A. P84.95

Question 25 :

88.75 + 85.5 + 90.5 + 87.25 / 4

352/4

88

⇒ B. 88

Question 26 :

I = P × r × t

I = 580.00 × 0.065 × 1

I = P37.70

⇒ B. P37.70

Answer:

f(1)= 3×1 + 2 = 5

....

.....

....

f(5)= 3×5 + 2 = 17

Answer:

f(5) = 17

Step-by-step explanation:

Given: f(x) = 3x + 2

We are asked to find the value of the function when the value of x is 5

Substitute 5 as the value of x in the function:

⇒ f(x) = 3x + 2

⇒ f(5) = 3(5) + 2 [multiply]

⇒ f(5) = 15 + 2 [add]

⇒ f(5) = 17

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Answer:

37.5 m

Step-by-step explanation:

Since the trapezoid area formula is ((base 1+base 2)/2)*height, we can plug in the values.

((8+7)/2)*5

(15/2)*5

7.5*5=37.5

Now we add the unit, "m" to get 37.5 m!

Answer:

12 minutes

Step-by-step explanation:

added in the picture

Answer:

Step-by-step explanation:

You want the domain and range of the function y = √(x -7) +1.

The domain is the horizontal extent of the graph. The graph of the given function extends to the right from x=7, which is included in the solution set.

The domain is x ≥ 7.

The range is the vertical extent of the graph. The graph of the given function extends upward from y=1, which is included in the solution set.

The range is y ≥ 1.

Answer: domain: 7

range: 1

Step-by-step explanation:

Answer: 1.25

Step-by-step explanation:

The explicit formula for the sequence is [tex]a_{n}=10(0.5)^{n-1}[/tex]

Substituting in n=4,

[tex]a_{4}=10(0.5)^{4-1}=\boxed{1.25}[/tex]

Answer:

Step-by-step explanation:

Answer:

-4(-2)+2(3)-(-4)

8+6+4

16 is the answers

Step-by-step explanation:

please mark me as brainlest

Answer:

Step-by-step explanation:

Two points ( -8,-1) and ( -1,0) are the solutions and the other points are not the solution to the inequality.

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than.

Given inequality is:-

We will check all the points for the inequality:-

(−8,−1) →  x + 5y  <  2.  →  -8 +(5 x -1) < 2  →  -13 < 2 It is inequality

(−1,0)   → x + 5y  <  2   →   -1 < 2 It is inequality

(4,2)    → x + 5y  <  2   →    14 < 2  wrong

(9,6)    → x + 5y  <  2   →    39 < 2 wrong

(0,10)  →  x + 5y  <  2  →    50 < 2 wrong

Therefore the two points ( -8,-1) and ( -1,0) are the solutions and the other points are not the solution to the inequality.

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Answer:

C

Step-by-step explanation:

 0 ≤ h ≤ 40, h ∈ R

Hope this helps :)

Answer:

390/1000

This is the answer and hope it helps

Answer:

40

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\sf 14\ ft}[/tex]

Step-by-step explanation:

Yard sticks = 4

12-inch rulers = 2

All are placed end to end.

We know that,

1 yard = 3 feet

4 yards = 3 × 4 feet

4 yards = 12 feet

We know that:

1 inch = 0.083 feet

24 inch = 0.083 × 24 feet

24 inch = 2 feet

= 4 yardsticks + 2 12-inch rules

= 12 ft + 2 ft

= 14 ft

[tex]\rule[225]{225}{2}[/tex]

Answer:

Step-by-step explanation:

The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.

Given a company has 200 machines. Each machine has a 12% probability of not working.

If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.

So

1) probability that 5 would not be working

C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵

                                ≈ 0.18665

2)  probability that at least one machine would be working

0.88⁴⁰ ≈ 0.00602

3) probability that all would be working

1 - 0.12⁴⁰ ≈ 1.0000

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Answer:

[tex]sec(\theta)=\frac{2}{\sqrt3}[/tex]

Step-by-step explanation:

Given [tex]sin(\theta)=\frac{1}{2}[/tex] , to find [tex]sec(\theta)[/tex], it will be helpful to visualize a right triangle (triangle with a 90 degree angle) associated with that particular θ.  There are a few ways to go about this:

All of the basic trigonometric functions, applied to an angle) are a ratio of two specific sides of any right triangle that holds that angle.

Remember that the Sine of an angle is defined specifically, the ratio of the opposite side (the side across from the angle in the Sine function), and the hypotenuse (the side across from the right angle).  You might remember this through SohCahToa

[tex]sin(\theta)=\frac{opp}{hyp}[/tex]

In our case, since [tex]sin(\theta)=\frac{1}{2}[/tex] , so  [tex]\frac{opp}{hyp}=\frac{1}{2}[/tex] .  While there are an infinite number of triangles that have that ratio of those sides, they are all "similar" triangles (corresponding angles congruent, and corresponding sides are proportional, yielding common ratios of sides), and for ease, we can consider simply the triangle where the value of the numerator is the length of the opposite side, and the value of the denominator is equal to the hypotenuse.  So, [tex]opp=1[/tex], and [tex]hyp=2[/tex].

While we haven't actually talked about θ yet, we can still set up the triangle that has these sides so that we can visualize what the triangle looks like. (see image)

This triangle represents the triangle for the unknown θ in the original sine function.  We're tasked with finding the secant of that particular unknown θ.

Working toward Secant

Here, it will be helpful to remember either the reciprocal identities for[tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex], or the definition of the secant function [tex]sec(\theta)=\frac{hyp}{adj}[/tex].

I find that most people remember the reciprocal identities more easily than keeping track of the definitions, so, since secant is related to cosine, it will be important to remember that [tex]cos(\theta)=\frac{adj}{hyp}[/tex].  From there, take the reciprocal of the cosine-value to get the secant-value (which matches the definition of the secant function).

Either way, it comes down to knowing the lengths of the side adjacent to theta, and the hypotenuse.  We already know the length of the hypotenuse, so we just need the length of the adjacent side.

Applying the Pythagorean Theorem

Fortunately, because it is a right triangle, the Pythagorean Theorem applies: [tex]a^{2} +b^{2} =c^{2}[/tex]  (where c is the length of the hypotenuse, and a & b are the lengths of the legs)

Substituting the known values for the sides we do know...[tex](adj)^{2} +(1)^{2} =(2)^{2}\\(adj)^{2} +1 =4[/tex]

...isolating "adj" by subtraction...

[tex](adj)^2=4-1\\(adj)^2=3[/tex]

...applying the square root property...

[tex]adj=\sqrt{3}[/tex]  or  [tex]adj=-\sqrt{3}[/tex]

Identifying which Quadrant the triangle is in

Since we were given that [tex]0^o < \theta < 90^o[/tex], our triangle is an acute triangle (as drawn in the diagram), and is in quadrant I (indicating that both legs will be measured with a positive value.

Thus, we discard the negative solution and conclude that [tex]adj=\sqrt{3}[/tex].

Finding the final solution

From there, [tex]cos(\theta)=\frac{adj}{hyp}[/tex] implies [tex]cos(\theta)=\frac{\sqrt3}{2}[/tex], and through the reciprocal relationship (or simply the definition of secant, whichever is easier for you to remember), [tex]sec(\theta)=\frac{2}{\sqrt3}[/tex]

Note:  This method did not require knowing what the angle θ was.

If you know well the values of special triangles in the unit circle, you may have identified that [tex]sin(\theta)=\frac{1}{2}[/tex]  is associated with [tex]\theta=30^o[/tex].  If so, if you also recall that the ordered pair associated with that point on the unit circle is [tex](\frac{\sqrt3}{2} ,\frac{1}{2} )[/tex], and that the [tex]cos(\theta)=x\text{-coordinate on the unit circle}[/tex], then you can quickly identify that  [tex]cos(\theta)=\frac{\sqrt3}{2}[/tex].

This method still ends the same: recalling the reciprocal relationship between cosine and secant, giving [tex]sec(\theta)=\frac{2}{\sqrt3}[/tex].

Answer:

20 L

Step-by-step explanation:

I am guessing that you meant should instead of shouldn't.

To solve this we can set the amount of 10% solution needed equal to x. This means that the 60% solution will be the remaining amount needed, so 50 L - x.

We can do 10%*x+60%*(50-x)=50*40%. Solving for x we get:

0.1*x+0.6*50-0.6*x=50*0.4

0.1*x+30-0.6*x=20

-0.5*x=-10

x=20

The first step is replacing the given trigonometric functions by simpler ones and then taking the product of the denominators.

Here we have the expression:

[tex]\frac{tan(x)}{1 + sec(x)}[/tex]

Remember that:

[tex]tan(x) = \frac{sin(x)}{cos(x)}\\ \\sec(x) = \frac{1}{cos(x)}[/tex]

Replacing that would be the "step zero", we can write:

[tex]\frac{tan(x)}{1 + sec(x)} = tan(x)*\frac{1}{1 + sec(x)} = \frac{sin(x)}{cos(x)} \frac{1}{1 + \frac{1}{cos(x)} }[/tex]

The first step to simplify this, is taking the product between the denominators:

[tex]\frac{sin(x)}{cos(x)} \frac{1}{1 + \frac{1}{cos(x)} } = sin(x)*\frac{1}{cos(x) + \frac{cos(x)} {cos(x)} } = \frac{sin(x)}{cos(x) + 1}[/tex]

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Answer:

tanx(1-secx)/(1+secx)(1-secx)

Step-by-step explanation:

aP E

Answer:

-28x^3-28x^2+16x+15

Step-by-step explanation:-28x^3-28x^2+16x+15

Using the binomial distribution, it is found that the probabilities are:

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

Exercise 1:

The parameters are:

n = 15, p = 0.4, x = 4.

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{15,4}.(0.4)^{4}.(0.6)^{11} = 0.1228[/tex]

Exercise 2:

The parameters are:

n = 12, p = 0.2, x = 2.

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{12,2}.(0.2)^{2}.(0.8)^{10} = 0.2835[/tex]

Exercise 3:

The parameters are:

n = 20, p = 0.05.

The probability is:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

Using the binomial formula for each value and adding them:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3585 + 0.3774 + 0.1887 + 0.0596 = 0.9841[/tex]

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