It is known that the variance of a population equals 1,936. A random sample of 121 has been selected from the population. There is a .95 probability that the sample mean will provide a margin of error of _____. Group of answer choices 31.36 or less 1,936 or less 344.96 or less 7.84 or less

Answer:

13/9l  or 1  4/9 l

Step-by-step explanation:

Answer:

quantity of alcohol = l liters

we need to make a solution of having 45% alcohol by adding water.

45% alcohol means whatever id the total quantity of solution there is 45% alcohol.

Let the total quantity of solution be x.(

then

quantity of alcohol in terms of x = 45% of x = 45/100 x

but we know that quantity of alcohol = l liters

45/100 x = l

x = 100/45 l

Thus, total quantity of solution is 100/45 l,

but in it, there are l liters of alcohol.

to find the quantity of water we need to subtract the quantity of alcohol from the total quantity of solution

quantity of water in the solution = 100l/45  - l = (100l - 45l)/45 = 65l/45

quantity of water in the solution = 13/9l = 1 4/9 l -------->answer.

Thus, 1 4/9 liters of water needs to be added to l liters of alcohol to make a solution of 45% alcohol.

PLEASE MARK THIS AS BRAINLIST

Answer:

W=7 and L=11

Step-by-step explanation:

We have two unknowns so we must create two equations.

First the problem states that  length of a rectangle is 10 yd less than three times the width so: L= 3w-10

Next we are given the area so: L X W = 77

Then solve for the variable algebraically. It is just a system of equations.

3W^2 - 10W - 77 = 0

(3W + 11)(W - 7) = 0

W = -11/3 and/or W=7

Discard the negative solution as the width of the rectangle cannot be less then 0.

So W=7

Plug that into the first equation.

3(7)-10= 11 so L=11

Answer:

your answer will be Option D

Step-by-step explanation:

log 10

Answer:

155 women must be randomly selected.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.645.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

The population standard deviation is known to be 28 lbs.

This means that [tex]\sigma = 28[/tex]

We want 90% confidence that the sample mean is within 3.7 lbs of the populations mean. How many women must be sampled?

This is n for which M = 3.7. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]3.7 = 1.645\frac{28}{\sqrt{n}}[/tex]

[tex]3.7\sqrt{n} = 1.645*28[/tex]

[tex]\sqrt{n} = \frac{1.645*28}{3.7}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645*28}{3.7})^2[/tex]

[tex]n = 154.97[/tex]

Rounding up:

155 women must be randomly selected.

9514 1404 393

Answer:

  1.56×10^10 cL

Step-by-step explanation:

There are 1000 liters in a cubic meter, so 10^5 centiliters in a cubic meter. The 1.56×10^5 cubic meters will then have ...

  (1.56×10^5 m^3)×(10^5 cL/m^3) = 1.56×10^10 cL

_____

That's 15,600,000,000 cL.

"Centi-" is a prefix meaning 1/100.

Answer:

1

Step-by-step explanation:

Cosine is a trigonometric function that is represented by adjacent divided by the hypotenuse. The side adjacent to angle A is AC and the hypotenuse is AB, so we can say cos(A) = [tex]\frac{AC}{AB}[/tex]. We can do the same for angle B. The side adjacent to it is BC, and the hypotenuse is again AB. So, we can say

cos(B) = [tex]\frac{BC}{AB}[/tex]. We are solving for [tex]\frac{cosA}{cosB}[/tex], so we can substitute the value of those two and solve:

[tex]\frac{\frac{AC}{AB}}{\frac{BC}{AB} }[/tex]

[tex]\frac{AC}{AB} * \frac{AB}{BC} = \frac{AC}{BC}[/tex]

AC is given to be 3 and BC is also 3, so [tex]\frac{AC}{BC}[/tex] is [tex]\frac{3}{3}[/tex] which is just 1.

Answer:

3.6 hours

Step-by-step explanation:

The formula is

1/a+1/b = 1/c  where a and b are the times working along and c is the time working together

1/6 + 1/9 = 1/c

Multiply by 36c to clear the fractions

36c (1/6 + 1/9 = 1/c)

6c +4c = 36

10c = 36

Divide by 10

10c/10 = 36/10

c = 3.6 hours working together

Answer:

Step-by-step explanation:

The next term is going to be simply 38*19 = 722

The series is geometric which means that you multiply from one term to get to the next.

The ratio of 19, and the current term is 38. So to get to the next term, multiply 38 * 19

Answer:

3/4

Step-by-step explanation:

add the no. of red marbles and blue marbles

2+4 = 6

Probability so divide 6/8 simplified to 3/4

Answer:(

fx).(gx)=D. -40x^3+25x^2+45

Step-by-step explanation:

Answer:

The ratio of the perimeters of the first nonagon to the second is 3.6 to 1.

Step-by-step explanation:

Given that a regular nonagon has an area of 90 square feet, and a similar nonagon has an area of 25 square feet, to determine what is the ratio of the perimeters of the first nonagon to the second, the following calculation must be performed:

25 = 1

90 = X

90/25 = X

3.6 = X

Therefore, the ratio of the perimeters of the first nonagon to the second is 3.6 to 1.

Answer:

x = 7 and

y = 4[tex]\sqrt{2}[/tex]

Step-by-step explanation:

as you can see from the image we need to draw a line and when we do so we get a special right triangle with angle measures 90-45-45 and side lengths represented by a-a-a[tex]\sqrt{2}[/tex]

since the line we drew is parallel to the rectangle's length it's = 4 and so the number represented with a is also = 4

from there on we see x = 7 and y = 4[tex]\sqrt{2}[/tex]

Answer:

I can confirm, it is B! x=7 and y=4sqrt2

Step-by-step explanation:

edge

Assuming the car's speed [tex]\frac{630}{14}=45\mathrm{mph}[/tex] does not change, the car will travel [tex]45\cdot42=\boxed{1890}[/tex] miles.

Hope this helps :)

Answer:

The proportion of bottles that will have more than 30 ounces dispensed into them is 0.9772 = 97.72%.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The amount dispensed has been observed to be approximately normally distributed with mean 32 ounces and standard deviation 1 ounce.

This means that [tex]\mu = 32, \sigma = 1[/tex]

Determine the proportion of bottles that will have more than 30 ounces dispensed into them.

This is 1 subtracted by the p-value of Z when X = 30, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{30 - 32}{1}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.0228.

1 - 0.0228 = 0.9772

The proportion of bottles that will have more than 30 ounces dispensed into them is 0.9772 = 97.72%.

2=4x+y

y=2-4x

Александр Мазепов

Step-by-step explanation:

Step 1:  Solve for y

[tex]2 = 4x + y[/tex]

[tex]2 - 4x = 4x + y - 4x[/tex]

[tex]y = 2 - 4x[/tex]

Step 2:  Solve for x

[tex]2 - 2 - 4x = 0 - 2[/tex]

[tex]-4x / -4 = -2 / -4[/tex]

[tex]x = 1/2[/tex]

Step 3:  Solve for y

[tex]y = 2 - 4(0)[/tex]

[tex]y = 2[/tex]

Step 4:  Graph the equation

Graph the x-intercept, (1/2, 0), the y-intercept, (0, 2) and draw a line between them.  Look at the attached picture for the graph:

Answer:

Option B, 1

Step-by-step explanation:

tan 45° = 1/1 = 1

Answer:

[tex]\approx 0.482659[/tex]

Step-by-step explanation:

The experimental probability is the chance of an event happening based on data, or rather the experiment results, and not on a theoretical calculation. In essence, a theoretical calculation can be described by the following formula:

[tex]\frac{desired}{total}[/tex]

However, the experimental probability can be described with the following formula:

[tex]\frac{number\ of\ desired\ outcomes}{number\ of \ trials}[/tex]

The number of trials is the sum of the number of outcomes. In this case, the desired outcome is tails. Therefore, the experimental probability can be described using the following formula:

[tex]\frac{tails}{total}[/tex]

One can also rewrite the formula as the following. This is because the total is the sum of the number of the two outcomes:

[tex]\frac{tails}{heads+tails}[/tex]

Substitute,

[tex]\frac{167}{167+179}[/tex]

Simplify,

[tex]\frac{167}{346}[/tex]

Rewrite as a decimal:

[tex]\approx 0.482659[/tex]

Answer:

let 2 no. be x and y

x+y=31 ..... (1)

x-y=11 .........(2)

from (1)

x=31-y ..........(3)

putting (3) in (2)

31-y-y=11

-2y=11-31

-2y=-20

2y=20

y=10

Answer:

45

Step-by-step explanation:

The length of the arc is equal to the central angle it sees.

Answer:

All have exactly one solution

Step-by-step explanation:

a) -13x + 12 = 13x - 13

   +13x         +13x

-------------------------------

          12 = 26x - 13

         +13           +13

         -------------------

           25 = 26x

          -----   ------

           26     26

          25/26 = x

b) 12x + 12 = 13x - 12

   -12x          -12x

  -----------------------

          12 = x - 12

        +12       +12

        -----------------

            24 = x

c) 12x + 12 = 13x + 12

  -12x          -12x

 -----------------------------

           12 = x + 12

           0 = x

d) -13x + 12 = 13x + 13

   +13x           +13x

 -----------------------------

         12 = 26x + 13

        -13             -13

      -----------------------

          -1  = 26x

          ---      -----

          26       26

          -1/26 = x

Answer:

(0.7044 ; 3.0956)

Step-by-step explanation:

Given:

GROUP A:

n1 = 25

x1 = 12.7

s1 = 2.2

GROUP B :

n2 = 25

x2 = 10.8

s2= 2.0

The obtain the confidence interval assuming unequal population variance :

(x1 - x2) ± tα/2[√(s1²/n1 + s2²/n2)]

The degree of freedom :

df = (s1²/n1 + s2²/n2)² ÷ (s1²/n1)²/n1-1 + (s2²/n2)²/n2-1

The degree of freedom :

(2.2²/25 + 2²/25)² ÷ (2.2²/25)²/24 + (2²/25)²/24

df = 0.12503296 ÷ (0.0015617 + 0.0010666)

df = 47.57 ;

df = 48

Tcritical value ; α = 95% ; df = 48

Tcritical = 2.0106

C.I = (12.7 - 10.8) ± 2.0106[√(2.2²/25 + 2²/25)]

C.I = 1.9 ± (2.0106 * 0.5946427)

C.I = 1.9 ± 1.1955887

C. I = (0.7044 ; 3.0956)

First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.

Let's apply the first derivative of this f(x) function.

[tex]f(x) = \sin(px)+\cos(px)\\\\f'(x) = \frac{d}{dx}[f(x)]\\\\f'(x) = \frac{d}{dx}[\sin(px)+\cos(px)]\\\\f'(x) = \frac{d}{dx}[\sin(px)]+\frac{d}{dx}[\cos(px)]\\\\f'(x) = p\cos(px)-p\sin(px)\\\\ f'(x) = p(\cos(px)-\sin(px))\\\\[/tex]

Now apply the derivative to that to get the second derivative

[tex]f''(x) = \frac{d}{dx}[f'(x)]\\\\f''(x) = \frac{d}{dx}[p(\cos(px)-\sin(px))]\\\\ f''(x) = p*\left(\frac{d}{dx}[\cos(px)]-\frac{d}{dx}[\sin(px)]\right)\\\\ f''(x) = p*\left(-p\sin(px)-p\cos(px)\right)\\\\ f''(x) = -p^2*\left(\sin(px)+\cos(px)\right)\\\\ f''(x) = -p^2*f(x)\\\\[/tex]

We can see that f '' (x) is just a scalar multiple of f(x). That multiple of course being -p^2.

Keep in mind that we haven't actually found dy/dx yet, or its second derivative counterpart either.

-----------------------------------

Let's compute dy/dx. We'll use f(x) as defined earlier.

[tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\y = \ln\left(f(x)\right)\\\\\frac{dy}{dx} = \frac{d}{dx}\left[y\right]\\\\\frac{dy}{dx} = \frac{d}{dx}\left[\ln\left(f(x)\right)\right]\\\\\frac{dy}{dx} = \frac{1}{f(x)}*\frac{d}{dx}\left[f(x)\right]\\\\\frac{dy}{dx} = \frac{f'(x)}{f(x)}\\\\[/tex]

Use the chain rule here.

There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.

Now use the quotient rule to find the second derivative of y

[tex]\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\[/tex]

If you need a refresher on the quotient rule, then

[tex]\frac{d}{dx}\left[\frac{P}{Q}\right] = \frac{P'*Q - P*Q'}{Q^2}\\\\[/tex]

where P and Q are functions of x.

-----------------------------------

This then means

[tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} + \left(\frac{f'(x)}{f(x)}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} +\frac{(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2+(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\[/tex]

Note the cancellation of -(f ' (x))^2 with (f ' (x))^2

------------------------------------

Let's then replace f '' (x) with -p^2*f(x)

This allows us to form  ( f(x) )^2 in the numerator to cancel out with the denominator.

[tex]\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*f(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*(f(x))^2}{(f(x))^2} + p^2\\\\-p^2 + p^2\\\\0\\\\[/tex]

So this concludes the proof that [tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2 = 0\\\\[/tex] when [tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\[/tex]

Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.

Answer:

A. Combination.

B. 17020

Step-by-step explanation:

A. Determination whether it is permutation or combination.

From the question given above, we were told that the student body of 185 students wants to elect two (2) representatives.

This is clearly combination because it involves a selecting process (i.e selecting 2 out of 185).

NOTE: Combination involves selecting while permutation involves arranging.

B. Determination of the combination.

Total number of people (n) = 185

Number of chosen people (r) = 2

Number of combination (ₙCᵣ) =?

ₙCᵣ = n! / (n – r)! r !

₁₈₅C₂ = 185! / (185 – 2)! 2!

₁₈₅C₂ = 185! / 183! 2!

₁₈₅C₂ = 185 × 184 × 183! / 183! 2!

₁₈₅C₂ = 185 × 184 / 2!

₁₈₅C₂ = 185 × 184 / 2 × 1

₁₈₅C₂ = 34040 / 2

₁₈₅C₂ = 17020

Answer:

$1.25x

Step-by-step explanation:

Given :

Cost per pound = $1.25

Number of pounds of apple = x

The total cost of apple = (cost per pound * number of apple in pounds)

Hence,

Total cost of x pounds of apple is :

($1.25 * x)

= $1.25x

Step-by-step explanation:

here's the answer to your question

Answer:

0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The production manager claims they have a mean life of 83 months with a variance of 81.

This means that [tex]\mu = 83, \sigma = \sqrt{81} = 9[/tex]

Sample of 146:

This means that [tex]n = 146, s = \frac{9}{\sqrt{146}}[/tex]

What is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors?

This is 1 subtracted by the p-value of Z when X = 81.2. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{81.2 - 83}{\frac{9}{\sqrt{146}}}[/tex]

[tex]Z = -2.42[/tex]

[tex]Z = -2.42[/tex] has a p-value of 0.0078.

1 - 0.0078 = 0.9922.

0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.

Answer:

Step-by-step explanation:

192

Answer:

Step-by-step explanation:

Answer:

4 ft

Step-by-step explanation:

I guess, the meaning is the largest marbles, so that we can pave the whole floor without cutting any marbles and leaving empty spots.

so, 20×16 ft²

we can have marbles 1/2 ft long. and it all fits well : 40×32 marbles.

we can have them 1 ft long, and it all fits well : 20×16 marbles.

we can have them 2ft long, and it still fits well : 10×8 marbles.

and so on.

so, actually, we are looking for the greatest common divisor (GCD) of 20 and 16. and that gives us the maximum length of a single marble to fulfill the requirement.

let's go for the prime factors starting with 2

20/2 = 10

10/2 = 5

5/3 fits not work

5/5 = 1 done

so, 20 = 2²×3⁰×5¹

16/2 = 8

8/2 = 4

4/2 = 2

2/2 = 1 done

16 = 2⁴

so, for the GCD I can only use powers of 2 (the only prime factors both numbers have in common).

and we have to use the smaller power of 2, which is 2, so, the GCD is 2² = 4

=>

the maximum length of the squared marbles is 4 ft.

that would pave the floor with 5×4 marbles completely.