The total cost of a tie and a pair of pants was $87.18. If the price of the tie was $2.12 less than the pair of pants, what was the price of the tie? Express your answer as a simplified fraction or a decimal rounded to two places.
find the slope for the given equation: - 3x-5y=11
Answer:
K=-3/5
Step-by-step explanation:
y= -3x/5 - 11/5
In your job with the heating contractor you photograph houses with infrared film and use the pictures to determine where to place additional installation you need to buy 18 rolls of film a local camera shop sells to film for $9.95 parole plus 5% sale tax mail order company sells to film for $975 parole and charges $15 to ship the whole order but no charges on sales tax if you choose the better of the two prices how much will you pay for 18 rolls of film
Answer:
$188.06
Step-by-step explanation:
The total cost for the film will be the sum of film cost, applicable sales tax, and applicable shipping charges. The film cost will be the product of the number of rolls and the cost per roll.
__
camera shopfilm cost = (18 rolls) × ($9.95 /roll) = $179.10
sales tax = 0.05 × $179.10 = $8.96
There is no shipping charge associated with the camera shop purchase, so the total cost is ...
camera shop cost = film cost + sales tax = $179.10 +8.96 = $188.06
__
mail orderfilm cost = (18 rolls) × ($9.76 /roll) = $175.50
shipping charge = $15.00
There is no sales tax associated with the mail order, so the total cost is ...
mail order cost = film cost + shipping charge = $175.50 +$15.00 = $190.50
__
The price from the camera shop is the better of the two prices. The purchase there would cost you $188.06 for 18 rolls of film.
_____
Additional comment
The after-tax charge per roll of film at the camera shop is 9.95×1.05 = 10.4475. This is $0.6975 more than the basic charge per roll from the mail order company. In order to get the shipping charge of $15 to be less than $0.6975 per roll, the number of rolls ordered must be more than 15/0.6975 = 21.5.
An order of 22 rolls of film from the mail order company would cost less than from the camera shop. ($229.50 vs. $229.85)
pls i need to pass this class i wna graduate
Answer:
[tex]\boxed{\sf x= -29.5}[/tex]
Step-by-step explanation:
[tex]\sf \sqrt{-2x+5}-3=5[/tex]
[tex]\sf \sqrt{-2x+5}=8[/tex]
[tex]\sf -2x+5=64[/tex]
[tex]\sf -2x=59[/tex]
[tex]\sf \cfrac{-2x}{-2}=\cfrac{59}{-2}[/tex]
Therefore, x = -29.5.
Question is attached………
Answer:
D
Step-by-step explanation:
the cordinate is at (-3,2)
Each salesperson at an insurance agency is rated either below average, average, or above
average with respect to sales ability. Each salesperson is also rated with respect to his or her
potential for advancement either fair, good, or excellent. These traits for the 500 sales people
were cross-classified into the following table.
Potential for Advancement
Sales Ability Fair Good Excellent Total
Below Average 16 12 22 50
Average 45 60 45 150
Above Average 93 72 135 300
Total 154 144 202 500
If a salesperson is selected at random what is the probability:
A. The salesperson has “Fair” potential for advancement.
B. The salesperson has “Fair” potential or has Above Average Sales ability
C. The salesperson has “Fair” potential given they have Above Average Sales ability.
D. Of selecting 2 salespersons and finding they both have Fair potential for advancement.
Probability that the salesperson has “Fair” potential or has Above Average Sales ability is; 90.8%
How to find the probability?A) Probability that the salesperson has “Fair” potential for advancement = (16 + 45 + 93)/500 = 154/500 = 30.8%
B) Probability that the salesperson has “Fair” potential or has Above Average Sales ability = 30.8% + (300/500)% = 90.8%
C) Probability that the salesperson has “Fair” potential given they have Above Average Sales ability = P(A|B) = P(A ∩ B)/P(B) = (93/500)/0.6 = 0.31 = 31%
D) P(selecting 2 salespersons and finding they both have Fair potential for advancement) = (154/500) * (153/499) = 9.44%
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Which of the following is a root of the polynomial function below?
In consecuence, the conjugate complex number x₂ = (- 5 + i √3)/2 is one of the three roots of the cubic equation f(x) = x³ + 6 · x² + 12 · x + 7. (Correct choice: D)
How to determine the roots of a cubic equation
In this case we have a cubic equation, that is, a third order polynomial. There are two strategies to determine the roots of cubic equations: (i) Cardano's formula, (ii) Numerical methods.
The quickest though most effective way consists in determining the roots by numerical methods (i.e. Newton-Raphson method). By using numerical methods we conclude that the cubic equation f(x) = x³ + 6 · x² + 12 · x + 7
x₁ = - 1, x₂ = (- 5 + i √3)/2, x₃ = (- 5 - i √3)/2
In consecuence, the conjugate complex number x₂ = (- 5 + i √3)/2 is one of the three roots of the cubic equation f(x) = x³ + 6 · x² + 12 · x + 7. (Correct choice: D)
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A car has a maximum speed of 355.7 feet/second. Convert this speed to miles/hour.
Answer:
242.5226626 mphStep-by-step explanation:
1 ft/s = 0.681818 mph
355.7 * 0.681818 = 242.5226626
355.7 ft/s = 242.5226626 mph
What is the range of the function y=3√x+8?
O-∞
O-8
O 0≤y<∞
O 2≤y<∞
Answer: 0 ≤ y < ∞
Step-by-step explanation:
First, let us graph the function. See attached.
-> If I graphed the formatting of the square root sign incorrectly, please let me know so I can fix the answer.
The range of the function is all of the function's output values. In this case, all of the y values.
0 ≤ y < ∞
a² + b² + ab = 7
b² + c² + bc = 21
a² + c² + ac = 28 ab + bc + ac = ?
Answer:
ab+bc+ac = 7+21 + 28 =56
so the answer is 56
Observe that
[tex]a^2 + b^2 + ab = 7 \iff a^2 + b^2 - 2\cos(120^\circ) = \left(\sqrt 7\right)^2[/tex]
[tex]b^2 + c^2 + bc = 21 \iff b^2 + c^2 - 2\cos(120^\circ) = \left(\sqrt{21}\right)^2[/tex]
[tex]a^2 + c^2 + ac = 28 \iff a^2 + c^2 - 2\cos(120^\circ) = \left(\sqrt{28}\right)^2[/tex]
Drawing a comparison to the law of cosines, we see the first equation defines a triangle with sides [tex]a[/tex], [tex]b[/tex], and [tex]\sqrt 7[/tex]; the second equation defines one with sides [tex]b[/tex], [tex]c[/tex], and [tex]\sqrt{21}[/tex]; and the third equation defines another one with sides [tex]a[/tex], [tex]c[/tex], and [tex]\sqrt{28}[/tex]. We can then join these triangles at a point D to form a new triangle ABC with sides [tex]\sqrt7,\sqrt{21},\sqrt{28}[/tex]. (See attached sketch)
Now, the area of ABC is the sum of the areas of ABD, BCD, and ACD. The area of any of these triangles is equal to half the area of a parallelogram spanned by the sides involving the vertex D. The area of a parallelogram with adjacent sides [tex]x[/tex] and [tex]y[/tex] and with angle [tex]\theta[/tex] between them is [tex]ab\sin(\theta)[/tex].
For example, triangle ABD has area
[tex]\mathrm{area}_{\Delta ABD} = \dfrac12 \times ab \sin(120^\circ)[/tex]
Then the total area of triangle ABC is
[tex]\mathrm{area}_{\Delta ABC} = \dfrac12 \sin(120^\circ) (ab + ac + bc)[/tex]
We use Heron's formula to find the area of ABC. If [tex]s[/tex] is its semiperimeter, i.e.
[tex]s = \dfrac{\sqrt7 +\sqrt{21} + \sqrt{28}}2[/tex]
then, with a lot of algebraic simplification,
[tex]\mathrm{area}_{\Delta ABC} = \sqrt{s (s-\sqrt7) (s - \sqrt{21}) (s - \sqrt{28})} = \dfrac{7\sqrt3}2[/tex]
Finally, we find
[tex]\dfrac{7\sqrt3}2 = \dfrac12 \sin(120^\circ) (ab + ac + bc) \implies ab + ac + bc = \dfrac{\frac{7\sqrt3}2}{\frac12\times\frac{\sqrt3}2} = \boxed{14}[/tex]
Pre-Test Active
2 3
5 6
7
9 10
Which formula should be used to find the circumference of a circle?
O C-nd
O C-2nd
0 С-яг
OC-4
Save and Exit
Mark this and return
Next
TIME REMAINING
45:32
Submit
Answer:
C = 2√(πA) units
Step-by-step explanation:
Classify each of the following variables as quantitative or qualitative. For those which are quantitative, classify them further as continuous or discrete.
a) Weight of adult females
b) Street addresses in Addis Ababa
c) Years of professional experience of employees
d) Number of courses offered to students in AAU in this semester.
Answer:
a) quantitative - continuous
b) qualitative
c) quantitative - discrete
d) quantitative - discrete
Explanation:
A qualitative variable describes an object or its property without counting or measuring. Therefore it does not include any numbers.
A quantitative variable is one which results from counting or measuring a property of an object or situation. If the variable arises from counting, it is called discrete, and if it arises from any measurement, it is called continuous.
OLLEGE
>
For the given functions, find (fog)(x) and (gof)(x) and the domain of each.
f(x) = 4x + 1, g(x)=√x
(fog)(x) =
(gof)(x) =
The domain of fog is ☐.
(Type your answer in interval notation.)
The domain of g of is.
(Type your answer in interval notation. Use integers or fractions for any numbe
Part 1
[tex](f\circ g)(x)=f(\sqrt{x})=4\sqrt{x}+1[/tex]
We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is [tex]\boxed{[0, \infty)}[/tex]
Part 2
[tex](g \circ f)(x)=g(4x+1)=\sqrt{4x+1}[/tex]
We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,
[tex]4x+1 \geq 0\\\\4x \geq -1\\\\x \geq -\frac{1}{4}[/tex]
Thus, the domain in interval notation is [tex]\boxed{\left[-\frac{1}{4}, \infty)}[/tex]
What is the simplified form of this expression? 3x + (8x − 16)
Design a real life activity for the Intermediate Phase in which learners will be required to apply the associative property of multiplication over addition.
The associative property of adding or multiplying can be represented by (a + b) + c = a + (b + c) and a * (b * c) = (a * b) * c
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The associative property states that when adding or multiplying it can be represented by:
(a + b) + c = a + (b + c)
For multiplication:
a * (b * c) = (a * b) * c
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Which expression is the simplest form of - (4x³ + x²) + 2 (x³ − 3x²)?
OA. -2³ - 7x²
OB.
B. -2x³-5x2
O C.-6x³ - 2x²
OD. -6x³6x²
The expression which is the simplest form of; - (4x³ + x²) + 2 (x³ − 3x²) is; -2x³ -7x².
What is the simplest form of the expression?The expression given in the task content whose simplest form is to be determined is;
- (4x³ + x²) + 2 (x³ − 3x²)
Hence, upon opening up the parentheses, it follows that;
-4x³ - x² +2x³ -6x²
Upon collection and summing up of like terms; -2x³ -7x².
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Vlad spent 20 minutes on his history homework and then completely solved x math problems that each took 2 minutes to complete. What is the equation that can be used to find the value of y, the total time that Vlad spent on his homework, and what are the constraints on the values of x and y?
y=2x+20; x is any integer greater than or equal to 0, and y is an integer greater than or equal to 20.
y=2x+20; x is any real number greater than or equal to 0, and y is any real number greater than or equal to 20.
y=20x+2; x is any integer greater than or equal to 0, and y is an integer greater than or equal to 20.
y=20x +2; x is any real number greater than or equal to 0, and y is any real number greater than or equal to 20
Answer:
y=2x+20
Step-by-step explanation:
x is any real number greater than or equal to 0, and y is any real number greater than or equal to 20
Hope this helps :)
multiplicity of F(x)= 4x^3+19x^2-41x+9
The multiplicity of the function is 1 for each term after factorization.
What is polynomial?Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.
[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]
We have a polynomial function:
[tex]\rm F(x)= 4x^3+19x^2-41x+9[/tex]
After factorization:
[tex]\rm F(x) = \left(4x-1\right)\left(x^2+5x-9\right)=0[/tex]
[tex]\rm F(x) =(4x-1)^1(\:x-\frac{-5+\sqrt{61}}{2})^1(\:x+\frac{-5-\sqrt{61}}{2})^1[/tex]
The multiplicity of the function is 1 for each term.
Thus, the multiplicity of the function is 1 for each term after factorization.
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PLEASE HELP AND SHOW WORK PLEASE.
How is this a no solution answer? I came out with the answer x < -2 and x ≥ 5
5 - x > 7 and 2x + 3 ≥ 13
Inequalities help us to compare two unequal expressions. There exists no solution to the given set of inequalities.
What are inequalities?Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.
The given Inequalities can be solved as,
5 - x > 7
-x > 7 - 5
-x > 2
x < -2
2x + 3 ≥ 13
2x ≥ 10
x ≥ 5
As per the solution of the two inequalities, the value of x should be less than -2 but at the same time, it should be more than or equal to 5, which is impossible. Thus, there is no solution for the given inequalities.
This can be confirmed by graphing the two inequalities, as shown below. Since there is no area in common between the two inequalities, there exists no solution to the given set of inequalities.
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Given f ( x ) = 1 x + 10 , find the average rate of change of f ( x ) on the interval [ 8 , 8 + h ] . Your answer will be an expression involving h .
Answer: 1
Step-by-step explanation:
[tex]f(8+h)=8+h+10=18+h\\\\f(8)=8+10=18[/tex]
So, the average rate of change is:
[tex]\frac{(18+h)-18}{(8+h)-8}=\frac{h}{h}=\boxed{1}[/tex]
The question is wrong, the expression will not be in terms of h since it is a linear function.
Find the value of x.
Answer:
Step-by-step explanation:
plug in x try numbers
x = 14.2
The function below has at least one rational zero.
Use this fact to find all zeros of the function.
f(x)=7x³ +9x²-12x-4
Answer:
Using the rational root theorem, we know to divide the function by (x - 1).
(7x³ + 9x² - 12x - 4) / (x - 1) = 7x^2 + 16x + 4
Now we can further factorize 7x^2 + 16x + 4 into (7x + 2) and (x + 2).
Therefore, the original function can be rewritten as (x - 1) (7x + 2) (x + 2).
Using the factorized form above, the zeros of the function are 1, -2/7, and -2.
Please help me with this problem below!
Part 1
[tex](g\circ h)(x)=g(x-4)=(x-4)^2 + 1=x^2 - 8x+16+1=\boxed{x^2 - 8x+17}[/tex]
Part 2
[tex](-\infty, \infty)[/tex]
The answers in the box are:
First box: [tex]\mathbf{x^2-8x+17}[/tex]Second box: [tex]\mathbf{(-\infty,\infty)}[/tex].Given that the functions are
[tex]g(x)=x^2+1[/tex]
[tex]h(x)=x-4[/tex]
Since clearly g(x) and h(x) exist for all real values of x so the domain of g(x) and h(x) both are all real numbers.
Now the composition of function is given by,
[tex](g\circ h)(x)=g(h(x))[/tex]
[tex]=g(x-4)[/tex]
[tex]=(x-4)^2+1[/tex]
[tex]=x^2-8x+16+1[/tex], since we know that [tex](a-b)^2=a^2-2ab+b^2[/tex]
[tex]=x^2-8x+17[/tex]
So, [tex](g\circ h)(x)=x^2-8x+17[/tex]
It is a polynomial function so it is defined for all real values of x.
Hence the domain of composition is all real numbers, that is [tex](-\infty,\infty)[/tex]
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Determine the next three terms in the following sequence: Negative 1, one-half, negative one-fourth, StartFraction 1 Over 8 EndFraction,____, ____, ____,... a. StartFraction 1 Over 12 EndFraction, StartFraction 1 Over 24 EndFraction, StartFraction 1 Over 48 EndFraction b. StartFraction 1 Over 16 EndFraction, StartFraction 1 Over 32 EndFraction, StartFraction 1 Over 64 EndFraction c. Negative StartFraction 1 Over 12 EndFraction, StartFraction 1 Over 24 EndFraction, Negative StartFraction 1 Over 48 EndFraction d. Negative StartFraction 1 Over 12 EndFraction, StartFraction 1 Over 24 EndFraction, Negative StartFraction 1 Over 48 EndFraction
The next three terms will be -1/16, 1/32, and -1/64. Then the correct option is B.
What is the geometric sequences?Let a be term and r be the common ratio. Then the geometric sequences will be
[tex]\rm a_n = a_{n -1} \cdot r[/tex]
The sequence is given below.
-1, 1/2, -1/4, 1/8,....
The common ratio will be -1/2.
Then the next three terms will be
a₅ = a₄ x (-1/2)
a₅ = (1/8) x (-1/2)
a₅ = -1/16
a₆ = a₅ x (-1/2)
a₆ = (-1/16) x (-1/2)
a₆ = 1/32
a₇ = a₆ x (-1/2)
a₇ = (1/32) x (-1/2)
a₇ = -1/64
Then the next three terms will be -1/16, 1/32, and -1/64.
Then the correct option is B.
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Answer:
C
Step-by-step explanation:
2015-{2015÷5(x-5)÷5}=2014
Answer:
x=80.8
Step-by-step explanation:
follow BODMAS
2015-(2015÷5(x-5)÷5)=2014
2015-(2015÷5x-25÷5)=2014
2015-(405/x-5)=2014
2015-(405-5x)=2014
2015-405+5x=2014
1610+5x=2014
5x=2014-1610
(5x=404)1/5
x=80.8
please i need it so badl please
The sum of the ages of Damien and Keyanna is 100 years. 10 years ago, Damien's age was 4 times Keyanna's age. How old is Damien now?
Answer:
Damien is 74 years old now
Step-by-step explanation:
Define the variables:
Let d = age of DamienLet k = age of KeyannaGiven information:
The sum of the ages of Damien and Keyanna is 100 years. 10 years ago, Damien's age was 4 times Keyanna's age.From the given information, create 2 equations:
Equation 1: d + k = 100
Equation 2: d - 10 = 4(k - 10)
Rewrite Equation 1 to make k the subject:
⇒ k = 100 - d
Substitute this into Equation 2 and solve for d:
⇒ d - 10 = 4(100 - d - 10)
⇒ d - 10 = 400 - 4d - 40
⇒ d - 10 = 360 - 4d
⇒ d - 10 + 10 = 360 - 4d + 10
⇒ d = 370 - 4d
⇒ d + 4d = 370 - 4d + 4d
⇒ 5d = 370
⇒ 5d ÷ 5 = 370 ÷ 5
⇒ d = 74
Therefore, Damien is 74 years old now.
As a nurse, part of your daily duties is to mix medications in the proper proportions for your patients. For one of your regular patients, you always mix Medication A with Medication B in the same proportion. Last week, your patient's doctor indicated that you should mix 90 milligrams of Medication A with 72 milligrams of Medication B. However this week, the doctor said to only use 8 milligrams of Medication B. How many milligrams of Medication A should be mixed this week?
The Medication A mixed this week should be 10 milligrams.
We have,
Medications to be mixed in the proper proportions.
Last week's proportions as the doctor indicated ;
Medication A = 90 milligrams
Medication B = 72 milligrams
This week's proportions as doctor indicated;
Medication B = 8 milligrams
Let, Medication A = x milligrams
As we are instructed to mix the Medication in the proper proportions,
So,
According to the question,
90/72 = x/8
10/8 = x/8
⇒ x = 10 milligrams
Here, the Medication A mixed is 10 milligrams.
Therefore, the Medication A mixed this week should be 10 milligrams.
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Suppose a jar contains 12 red marbles and 12 blue marbles. If you reach in the jar and pull out 2 marbles at random, find the probability that both are red
The probability that both are red marbles is 0.2391
How to determine the probability?The given parameters are:
Red =12
Blue = 12
Total = 24
The probability of selecting the first red marble :
P(Red) = 12/24
Now, there are 11 red marbles and 23 marbles in all
The probability of selecting the second red marble :
P(Red) = 11/23
The required probability is:
P = 12/24 * 11/23
Evaluate
P = 0.2391
Hence, the probability that both are red marbles is 0.2391
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A comedy club's nightly revenue from the sale of x tickets is given by R = 15x and its
nightly costs are given by C= 1.25x + 495. How many tickets need to be sold each night
to break even? In other words, when will revenue equal costs?
Considering the given equations for the revenue and the cost, it is found that 36 tickets have to be sold each night to break even.
What is the break-even point?The break-even point is when the revenue and the costs are equal.
In this problem, the equations are given as follows:
R(x) = 15x.C(x) = 1.25x + 495.At the break-even point:
R(x) = C(x)
15x = 1.25x + 495
13.75x = 495
x = 495/13.75
x = 36.
36 tickets have to be sold each night to break even.
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Which numbers are irrational???
Answer:
√2/4, √3/4, and √5/4.
Step-by-step explanation:
A rational number is any integer, fraction, terminating decimal, or repeating decimal.
