Let a population consist of the values ​cigarettes, ​cigarettes, and cigarettes smoked in a day. Show that when samples of size 2 are randomly selected with​ replacement, the samples have mean absolute deviations that do not center about the value of the mean absolute deviation of the population. What does this indicate about a sample mean absolute deviation being used as an estimator of the mean absolute deviation of a​ population?.

when you subtract a negative number from any platitude number the equation changes to addition so you would add the value of the negative number to 1.

To subtract a negative number from one you will need to set it up like this

1- (-x) x equals the negative number you're talking about

so we use the method KCC (keep change change)

So we KEEP the positive one, CHANGE the subtraction sign in to a plus sign "+" then CHANGE the negative number to a positive

lets say the negative number is 2

1-(-2)

1+ (+2)

1+2 = 3

Answer:

4

Step-by-step explanation:

the second column and the second row so, the answer is 4

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

"If the 2 is quantity use multiply it again"

NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

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[tex]\large\bold{SOLUTION} \\ [/tex]

GIVEN :-

FIND :-

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

[tex] \bold{Formula:}[/tex]

[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]

Now let's start solving :-

[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]

[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]

[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]

[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]

Therefore, the area of the space that needs to be covered is 100.80ft² .

[tex] \underline{ \rule{185pt}{3pt}}[/tex]

Answer:

[tex]\sf C) \ x = -1\dfrac{2}{5} , \ y = \ 1\dfrac{3}{5}[/tex]

Given equations:

Make x the subject in equation 1:

Substitute this into equation 2:

2(y - 3) - 7y = -14

2y - 7y = -14 + 6

-5y = -8

  y = -8/-5

  y = 1.6

Then x = y - 3

           = 1.6 - 3

           = -1.4

Solution: (x, y) ⇒ (-1.4, 1.6)

(a) The fraction of books that are fiction is 2/3.

(b) The fraction of books that are non-fiction is 1/3.

To find the fraction of fiction and non-fiction books on a bookshelf:

Given: A bookshelf has 96 books. 64 of the books are fiction and the rest are non-fiction books. (a)Fraction of fiction books =?

(b)Fraction of non-fiction books =?

Now,

As given, we have,

The total number of books on a bookshelf = 96

Out of 96, the total number of fiction books = 64

So,

The remaining number of books = non-fiction books = 96-64 = 32

(a) Fraction of fiction books = fiction books/total books

= 64/96

On simplification,

= 2/3

(b) Fraction of non-fiction books = non-fiction books/total books

= 32/96

= 1/3

Therefore, the fraction of fiction and non-fiction books is 2/3 and 1/3 respectively.

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By defining and solving systems of equations, we will see that:

a) the fraction is 40/56

d) the fraction is 15/21.

We have the fraction 5/7 and we want to write it in different ways.

a) First we want to find a number a/b such that:

a/b = 5/7

a + b = 96

This is a little system of equations, to solve this, first we can rewrite the first equation as:

7a = 5b

Now we can isolate a on the second equation:

a = 96 - b

And replace that on the other equation:

7*(96 - b) = 5b

And now we can solve this for b.

672 - 7b = 5b

672 = 5b + 7b = 12b

672/12 = b = 56

And we know that:

a = 96 - b = 96 - 56 = 40

Then the fraction is 40/56

d) This time we want the denominator to be 9 less than twice the numerator.

in a/b, a is the numerator and b is the denominator.

So this time we have:

a/b = 5/7

b = 2a - 9

We can rewrite the first equation again:

7a = 5b

And then replace the other equation in the right side:

7a = 5*(2a - 9)

And now solve this for a.

7a = 10a - 45

45 = 10a - 7a = 3a

45/3 = a = 15.

And:

b = 2a - 9 = 2*15 - 9 = 21

Then the fraction is 15/21.

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Answer:

(-6)

Step-by-step explanation:

Integer subtraction:

If two numbers have different sign, subtract and the result will have the sign of the bigger number.

 8 - 14 = (-6)

Subtract 8 from 14 and the bigger number is 14 and sign of 14 is (-).

So, the answer is  (-6)

An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is C.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Juanita’s salary once she completes 10 years, her salary will be increased to 3 times what she makes now plus $2,000. Now, if her salary is represented by s, then the expression that would represent her salary after 10 years is,

Salary after 10 years = 3s + 2000

Hence, the correct option is C.

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Answer:

C

Step-by-step explanation:

Answer:

The graph of G(x) is the graph of F(x) stretched vertically and shifted 8 units up.

Answer:

{-3, 2, -5, 1, 6}

Step-by-step explanation:

The domain is the set of input values.

Answer:

534

Step-by-step explanation:

The solution is in the image

One complete period of a non-transformed cotangent function is π.

The period of the function is defined as the interval after which the function value repeats itself.

For example, f(T+x)=f(x)

where T is the period of the function.

Here given that there is a non-transformed function cotangent function.

We have to find the period of the function in which interval the value of the function will repeat.

So for the function y=f(x)=cot x

the period of the function is π. means after π the value of the cotangent repeats.

cot(π+x)=cot x

Then one cycle of the cotangent graph lies between 0 and π.

Therefore One complete period of a non-transformed cotangent function is π.

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Answer:

b = 2

Step-by-step explanation:

using the tangent ratio in the right triangle and the exact value

tan30° = [tex]\frac{1}{\sqrt{3} }[/tex] , then

tan30° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{b}{a}[/tex] = [tex]\frac{b}{2\sqrt{3} }[/tex] = [tex]\frac{1}{\sqrt{3} }[/tex] ( cross- multiply )

b × [tex]\sqrt{3}[/tex] = 2[tex]\sqrt{3}[/tex] ( divide both sides by [tex]\sqrt{3}[/tex] )

b = 2

Answer:

Given that a = 2√3.

Let's find value of b...

[tex]\textsf {21 cm}[/tex]

[tex]\textsf {If it is correct to the nearest centimeter, then the least side length}\\\textsf {would be 8 - 1 = 7 cm. }[/tex]

[tex]\textsf {Then, the least possible perimeter would be :}[/tex]

[tex]\mathsf {7 \times 3}[/tex]

[tex]\textsf {21 cm}[/tex]

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Answer:  [tex]\textsf{y = -1/4x - 4}[/tex]

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Given: [tex]\textsf{Slope = -1/4, Point through = (4, -5)}[/tex]

Find:  [tex]\textsf{Equation for the line that passes through the given point}[/tex]

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

Plug in the values

Simplify and solve for y

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.

The arithmetic operations above can be evaluated and simplified as follows;

(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.

(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.

(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.

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Answer:

5. 8π 6. 18π 7. 8.6π 8. 11/4π

Step-by-step explanation:

8. 2 3/4

2*4+3 = 11/4

First blank: Side-Angle-Side similarity postulate

Second blank: proportional

A function assigns the value of each element of one set to the other specific element of another set. The zeroes of the functions are -2, 1, and 3.

A function assigns the value of each element of one set to the other specific element of another set.

Given f(x) = (x - 1)(x + 2)(x − 3), therefore, the zeroes of the functions are -2, 1, and 3. The end behavior of the function is that if x approaches ∞ then f(x) approaches ∞, while if x approaches -∞ then f(x) approaches -∞, as can be observed from the given graph.

Hence, the zeroes of the functions are -2, 1, and 3.

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Answer:

−1, 2, −3; continues downward to the left and upward to the right

Step-by-step explanation:

Step-by-step explanation:

1. let n=2, then, n+2= 2+2=4 so 2^2= 4 and 4^2=16 then 16-4=12 which is an even number

2. let n=4, the. n+3=4+3=7, and 4^2=16 and 7^2=49 then 49-16 =33 which is an odd number

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1.  m³

2. cm³

3. s³

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

1. Volume is measure in m³

2.  volume of a rectangular pencil case in cm³

3. V = s x s x s or s³

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The distributive property of multiplication over addition for rational numbers is (a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

Which of the following is an example of distributive property of multiplication over addition for rational numbers

(a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

(b) -3/4 × {2/3 + (-5/6)} = [3/4 × 2/3] - (-5/6)

(c) -3/4 × {2/3 + (-5/6)} = 2/3 + (-3/4) × -5/6

(d) -3/4 × {2/3 + (-5/6)} = {2/3 + (-5/6)} - 3/4

The distributive property of multiplication states that:

a * (b + c) = (a * b) + (a * c)

From the given question, we have:

-3/4 × {2/3 + (-5/6)}

This means that:

a = -3/4

b = 2/3

c = -5/6

Recall that a * (b + c) = (a * b) + (a * c)

So, we have:

-3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

Hence, the distributive property of multiplication over addition for rational numbers is (a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

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Answer:

75 mm

Step-by-step explanation:

 To find the hypotenuse, use Pythagorean theorem

Hypotenuse² = base² + altitude²

                  c² = 21² + 72²

                      = 441 + 5184

                      = 5625

                 [tex]\sf c = \sqrt{5625}[/tex]

                    [tex]= \sqrt{75*75}\\\\\boxed{\bf c = 75 \ mm}[/tex]

Answer:

HI i no  answer of this quetion but what grade are in school

the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

To do this, we can think on the situation as a right triangle, where the hypotenuse is 4 miles, the angle that we look at measures 10.5°, and the change in elevation (let's call it x) will be the opposite cathetus to that angle.

Then we can use the relation:

Sin(a) = (opposite cathetus)/(hypotenuse)

Replacing what we know, we get:

sin(10.5°) = x/4mi

x = sin(10.5°)*4mi = 0.73mi

So the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

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Answer:  [tex]\textsf{x}^2\textsf{ - 14x + 24}[/tex]

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Given:  [tex]\textsf{x = 12 and x = 2}[/tex]

Find: [tex]\textsf{Determine the quadratic equation}[/tex]

Solution:  In order to determine the quadratic equation we need to move the integers onto the side where x is and then distribute.

Move the integers

Create and expression and distribute

Therefore, after completing the steps we were able to determine that the quadratic equation that will have solutions of x = 12 and x = 2 is x^2 - 14x + 24.