Multiply (−7)(2)(−2). −28 −14 28 14

Answer:

4/6

Step-by-step explanation:

there are three even numbers (3/6) and 3 odd numbers but you are only looking for 5 (1/6) so the answer is 4/6

hopefully this helps you :)

pls mark my answer brainlest I need it ;)

Answer:

[tex]x=3[/tex]

Step-by-step explanation:

So we have the equation:

[tex]2x+7+2x=19[/tex]

First, let's combine like terms on the left:

[tex](2x+2x)+7=19[/tex]

Add:

[tex]4x+7=19[/tex]

Subtract 7 from both sides:

[tex](4x+7)-7=(19)-7[/tex]

The left side cancels. Subtract on the right:

[tex]4x=12[/tex]

Now, divide both sides by 4:

[tex]\frac{4x}{4}=\frac{12}{4}[/tex]

The left cancels. Divide on the right:

[tex]x=3[/tex]

So, the value of x is 3.

Answer:

X=3

Step-by-step explanation:

2x+2x(=4x)=19-7

4x=12

X=12\4(divide)

x=3

Answer:

Step-by-step explanation:

y - 3 = 0(x - 1)

y - 3 = 0

y = 3

Answer:

275

Step-by-step explanation:

110 x 2.5 = 275

If 110 km is one gallon, you would multiply 110 by 2.5, and that's what i did above.

Answer:

20,000

Step-by-step explanation:

Scince 4, (a number lower than 5) is in front of the 3 (which is in the 10,000's place), 20,000 should be the answer.

Answer:

The answer is x-6

Step-by-step explanation:

x=(whatever number)

less means subtract

So the answer is x-6

Answer:

B is correct!!!!!!!!!   x-6

Step-by-step explanation:

this is correct because when it says 'than' that means the whole answer flips around

Answer:

The perimeter of a square is 128, the area when perimeter 84 is 441

Step-by-step explanation:

When the length of a square arm is l,

the area of a square is A = l^2.

So in your case, A = \sqrt{1024} = l^2

So l is simply, l = 32.

The perimeter of a square is, P = 4.l = 32*4 = 128

Again when the perimeter is, P = 84

l = 84/4 = 21

So then the area is, A = 21^2 = 441

Answer:

Number of chaperones = 9

Step-by-step explanation:

Given:

Total number of teacher = 2

Total people attend = 54

Find:

Number of chaperones

Computation:

Assume;

Number of chaperones = x

So,

x = [54-x] / 5

5x = 54 - x

6x = 54

x = 9

Number of chaperones = 9

Answer:

g(h(6)) = 36

h(g(6)) = 36

Explanation:

There is no difference in this because we're just basically using the commutative property. For g(h(6)), you just plug in 6 for x² which will give you 36. And since g(x) = x, the value of x is 36. In the same way for h(g(6)), g(6) = 6 and h(6) = (6)² therefore getting you 36. For both equations though, you will get the same answer.

Answer:

g(h(6)) = 36

h(g(6)) = 36

Step-by-step explanation:

There is no difference in this because we're just basically using the commutative property. For g(h(6)), you just plug in 6 for x² which will give you 36. And since g(x) = x, the value of x is 36. In the same way for h(g(6)), g(6) = 6 and h(6) = (6)² therefore getting you 36. For both equations though, you will get the same answer.

Answer:

9m=49 is the answer of the product of 9 and m is 49

Answer:

I think C

Step-by-step explanation:

It has a whole number as numerator and denominator so it is rational and it is a real number, but it is not an integer because it is a fraction.

Answer:

Rational, and Real numbers.

Step-by-step explanation:

There's a certain overlapping sequence of categorizing:

Whole #, Integers, Rational, Real.

Fractions and decimals belong in Rational, so you could say they are real as well.

Hope this helps! (sorry about it being brief)

Answer: 0

Step-by-step explanation: Natural numbers are your

counting numbers and they're always positive.

Since 0 is not a positive number,

it's not include within the set of natural numbers.

Answer: 0

Step-by-step explanation:

Answer:

7. C. 6

8. H. √34

9. A. (1, 3.5)

10. J. 10

Step-by-step explanation:

7. AB = 2y, BC = 6y, AC = 48

AB + BC = AC (segment addition theorem)

Substitute the above values into the equation

2y + 6y = 48

Solve for y

8y = 48

Divide both sides by 8

8y/8 = 48/8

y = 6

8. Distance between P(2, 8) and Q(5, 3):

[tex] PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] P(2, 8) = (x_1, y_1) [/tex]

[tex] Q(5, 3) = (x_2, y_2) [/tex]

[tex] PQ = \sqrt{(5 - 2)^2 + (3 - 8)^2} [/tex]

[tex] PQ = \sqrt{(3)^2 + (-5)^2} [/tex]

[tex] PQ = \sqrt{9 + 25} [/tex]

[tex] PQ = \sqrt{34} [/tex]

9. Midpoint (M) of segment LB, for L(8, 5) and B(-6, 2) is given as:

[tex] M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}) [/tex]

Let [tex] L(8, 5) = (x_1, y_1) [/tex]

[tex] B(-6, 2) = (x_2, y_2) [/tex]

Thus:

[tex] M(\frac{8 + (-6)}{2}, \frac{5 + 2}{2}) [/tex]

[tex] M(\frac{2}{2}, \frac{7}{2}) [/tex]

[tex] M(1, 3.5) [/tex]

10. M = -10, N = -20

Distance between M and N, MN = |-20 - (-10)|

= |-20 + 10| = |-10|

MN = 10

Answer:

530

Step-by-step explanation:

200+6(55)

6x55=330

200+330=530

Answer:

I would choose A

Step-by-step explanation:

I chose A because it's an hypotenuse because of the different sides

11=5(x-2)+2x

11-2x=5(x-2)

(11-2x) / 5 = x-2

11/5=2.2

2.2-0.4x = x-2

4.2-0.4x=x

4.2=1.4x

x=3

Answer: x = 3

Step-by-step explanation:

5x -10 +2x = 11

7x = 21

x=3

Hope that helps!

Steps to solve:

6x + 6 = 6(x - 1)

~Distribute left side

6x + 6 = 6x - 6

~Subtract 6 to both sides

6x = 6x - 12

~Subtract 6x to both sides

0 = -12

No solutions.

Best of Luck!

Hey there!☺

[tex]Answer:\boxed{\text{There are no solutions.}}[/tex]

[tex]Explanation:[/tex]

[tex]6x+6=6(x-1)[/tex]

6x + 6 = (6)(x) + (6)(-1) Distribute

6x + 6 - 6x = 6x - 6 - 6x Subtract 6x from both sides

6 = -6

6 - 6 = -6 - 6 Subtract 6 from both sides

0 = -12

No solutions.

Hope this helps!

Answer:

3.4 lessons per week

Step-by-step explanation:

If the teacher has to teach 6 chapter in 15 weeks, and each chapter has around 8.5 lessons. it means that the teacher has to teach in 15 weeks a total amount of lessons of 6*8.5= 51.

so 15 weeks---51 lessons

    1 week------x

From the above relation we have= 51/15= 3,4 lessons per week

Answer:

28

Step-by-step explanation:

Answer:

The points are "(2,2)".

Step-by-step explanation:

Given value:

[tex]f(x,y)=x^3-6xy+y^3+7[/tex]

Finding the first partial derivation which is equal to 0.

[tex]\to f_x(x,y)=3x^2-6y...............(a)\\\\ \to f_y(x,y)=-6x+3y^2...................(b)[/tex]

solve both the above equation by equal to 0.

For equation (a)

[tex]\to 3x^2-6y=0\\\\\to 3x^2=6y\\\\\to x^2=2y\\\\\to y=\frac{x^2}{2}\\\\[/tex]

For equation (b)

[tex]\to -6x+3y^2 =0 \\\\\to 3y^2 =6x\\\\\text{put the value of y in equation b}\\\\\to 3(\frac{x^2}{2})^2 -6x=0\\\\\to \frac{3}{4} x^4 -6x=0\\\\[/tex]

by solving the above value in the form of x we get:

[tex]\to x=0\\ \to x=2\\ \to x= -1 +\sqrt{3} i\\ \to x= -1 -\sqrt{3} i\\[/tex]

by solving the above value in the form of y we get:

[tex]\to y=0\\ \to y=2\\ \to y= -1 +\sqrt{3} i\\ \to y= -1 -\sqrt{3} i\\[/tex]

Solve the value by applying the second derivation method:

[tex]\to f_{xx}(x,y)=6x...............(a1)\\\\ \to f_{yy}(x,y)=6y...................(b2)\\\\\to f_{xy}(x,y)=-6...................(c2)[/tex]

calculating the value of discriminate:

[tex]d=f_{xx}(x,y) f_{yy}(x,y)-[f_{xy}(x,y)]^2[/tex]

The critical point of the given equation will be (2,2)

[tex]d=f_{xx}(2,2) f_{yy}(2,2)-[f_{xy}(2,2)]^2\\\\[/tex]

  [tex]= (6 \times 2) (6 \times 2) -[(-6)^2]\\\\= (12) (12) -[36]\\\\= 144 -36\\\\= 108\\\\[/tex]

Answer:

[tex](2,2)[/tex] is a minimum point of the function [tex]f(x,y).[/tex]

Step-by-step explanation:

[tex]f(x,y)=x^3-6xy+y^3+7[/tex]

Find the partial differentiation w.r.t. [tex]x[/tex] and [tex]y[/tex].

[tex]\frac {\partial f}{\partial x}=3x^2-6y[/tex]

[tex]\frac {\partial f}{\partial y}=-6x+3y^2[/tex]

[tex]\frac {\partial^2 f}{\partial x^2}=6x[/tex]

[tex]\frac {\partial^2 f}{\partial y^2}=6y[/tex]

[tex]\frac{\partial f}{\partial xy}=-6[/tex]

Find the critical points.

[tex]\frac {\partial f}{\partial x}=\frac {\partial f}{\partial y}=0[/tex]

[tex]\Rightarrow 3x^2-6y=0 \;\text{and}\; -6x+3y^2=0[/tex]

[tex]\Rightarrow 6y=3x^2\Rightarrow y=\frac{x^2}2[/tex]

[tex]\Rightarrow -6x+\frac 34 x^4=0\Rightarrow \frac {x^3}4=2[/tex]

[tex]\Rightarrow x^3=8\Rightarrow x=2,y=2[/tex]

Therefore, [tex](2,2)[/tex] is a critical point.

Now, [tex]\frac {\partial^2 f}{\partial x^2}\frac {\partial^2 f}{\partial y^2}-{\frac {\partial f}{\partial xy}}^2[/tex]

[tex]=6x6y-36=36xy-36>0 \;\text{at critical point }\; (2,2)[/tex]

Thus, [tex](2,2)[/tex] is not a saddle point.

[tex]\because \frac{\partial^2 f}{\partial x^2}>0 \; \text{and}\; \frac {\partial^2 f}{\partial x^2}\frac {\partial^2 f}{\partial y^2}-{\frac {\partial f}{\partial xy}}^2>0 \;\text{at point}\; (2,2)[/tex]

Hence, [tex](2,2)[/tex] is a local minimum of a given function.

Answer:

32/9

Step-by-step explanation:

Answer: 7/2 or 3  1/2

Step-by-step explanation:

Answer:

One fraction = [tex]\frac{23}{12}[/tex]

Mixed Number = [tex]1\frac{11}{12}[/tex]

Step-by-step explanation:

Since each circle represents one unit,

Sum of all segments of a circle = Circle having 12 segments

If one segment of the circle is removed from one circle,

Remaining parts of the given circles = 12 + 11

Now one  fraction representing the shaded sectors = [tex]\frac{12}{12}+\frac{11}{12}[/tex]

                                                                                       = [tex]\frac{23}{12}[/tex]

Mixed number = [tex]\frac{12}{12}+\frac{11}{12}[/tex]

                        = 1 + [tex]\frac{11}{12}[/tex]

                        = [tex]1\frac{11}{12}[/tex]

Answer:

7/9

Step-by-step explanation:

x = .7

10x = 7.7

10x - x = 7.7 repeating

9x = 7

x = 7/9

Bam

Answer:

A man walking away from a lamppost with a light source h=8 m above the ground. The man is m= 2 m tall. How long is the man’s shadow when he is d=15 m from the lamppost?

Step-by-step explanation:

2/x=6/(10+x) cross multiply.

6x=2(10+x)

6x=20+2x

6x-2x=20

4x=20

x=20/4

x=5 m. is the length of the man's shadow.

Answer: 3

Step-by-step explanation:

Answer:6

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

f(x) when x=2 is just a fancy way of saying substitute the x in this equation with 2.

so the equation becomes..

3(2)^3-5    ... remeber PEMDAS

3(8)-5

24 -5 =19