Answer:
Because Physics is mainly composited of math
Explanation:
If you really think about it the only way any science works is off maths, whether that be measuring the amount of NaOH to put into a solution or determening the amount of sugar you want in a cake it all relys on maths
15. If friction was completely removed from the track, what affect would this have on the roller coaster ride?
A. Without friction, the roller coaster ride would last forever!
B. The coaster would eventually stop because the coaster would still lose energy.
C. The coaster would use hills and flat sections to stop instead.
WILL MARK BRAINIEST DO QUICKKKK ISTGG PLS
Answer:
the answer is up the bird will go up
Explanation:
What new details are you able to see on the slide when the magnification is increased to 10x that you could not see at 4x
Answer: A more detailed information like the nucleus of cells on the slide is seen as the magnification Increases.
Explanation:
The microscope is an instrument used in a laboratory to view magnified image of an object ( cells on a slide). There are two types:
--> Simple microscope and
--> Compound microscope.
Simple microscope is used to view an object using JUST ONE convex lens, and the image formed is usually erect and magnified.
Compound microscope has a higher magnification compared to a simple microscope. It is produced by using TWO CONVERGING LENS of short focal length. Here, the two lenses used are classified according to their positions. The lens near the object is called the objective lens while the one nearer to the eye is called the eyepiece lens.
The objective lens of the compound lens used in the laboratory has ×4, ×10, ×40, ×100 magnifications. As the magnification of the objective lens is increased from ×4 to ×10 a more detailed information of the image is seen as the diameter of field of view decreases. For example the constituents of a cell like the nucleus can be viewed using a higher magnification.
state and explain five practical applications or uses of eddy current in everyday activities
Answer:
They are applied in electromagnetic braking.Used in separation of metals such as Aluminum from other metals.Used in identifying metals in vending machines.Testing of structure of aircrafts apply eddy currents through procedures of Non destructive examination.They are used in defect detecting and safety hazards application.Explanation:
Eddy current are loops of electric currents which are induced within conductors when there is a change in magnetic field in the conductor through Faraday's Law of induction.
They are applied in electromagnetic braking. This is where the eddy current acts as brakes to stop moving objects. However, they are used along side mechanical braking systems.
Used in separation of metals such as Aluminum from other metals. Using the eddy current separator, ferrous elements are attracted to the magnet while aluminum being non-ferrous ,is left separated.
Used in identifying metals in vending machines. These machines use eddy currents to detect fake coins where the fake coins will slow at a certain speed to be identified.
Testing of structure of aircrafts apply eddy currents through procedures of Non destructive examination.
They are used in defect detecting and safety hazards application. Defects in heat exchanger tubes can be detected by eddy currents.
3.) A family travels by car cross country 6,200 km in 80 hours. In meters per 1 point
second, how fast did the family travel? (3600 seconds = 1 hour) (Show ALL
work!) *
Answer:
v = 21.52 m/s
Explanation:
Given that,
The distance covered by the car, d = 6200 km
Time taken by the car, t = 80 hours
We need to find the speed of the car. The speed of an object is given by total distance dividing total time.
[tex]v=\dfrac{6200\times 10^3\ m}{80\times 3600}\\\\v=21.52\ m/s[/tex]
So, the speed of the car is 21.52 m/s.
Which of the following is not a true statement?
v=at
O art
Answer:
t = Δa / v
Explanation:
To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:
Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:
Acceleration = change in velocity / time
a = Δv / t ..... (1)
But
Δv = v₂ – v₁
Substitute the value of Δv into equation (1)
a = Δv / t
a = v₂ – v₁ / t ....... (2)
From equation (1), make Δv the subject of the equation.
a = Δv / t
Cross multiply
Δv = at .... (3)
From equation (1), make t the subject of the equation.
a = Δv / t
Cross multiply
at = Δv
Divide both side by a
t = Δv /a ...... (4)
From circular motion, centripetal's force is given by:
F = mv²/r
F = ma꜀
Therefore,
ma꜀ = mv²/r
Cancel out m
a꜀ = v²/r
SUMMARY:
a = Δv / t
a = v₂ – v₁ / t
Δv = at
t = Δv /a
a꜀ = v²/r
Considering the options given in question above, t = Δa / v is not a true statement.
Answer:
Option 4
Explanation:
What is the daily use of the deltoid?
Answer:
In our everyday life, the deltoids take on most of the work in rotating our arms, but besides that the deltoid muscle also allows us to carry objects at a safe distance from the body. It is also responsible from stopping a dislocation or injury to the humerus when we carry something heavy.
Answer:
Lifting, pushing and pulling
Explanation:
it uses it
QUESTION 7
How much force is required to bring a car of mass 1,126 kg, initially traveling at 20.4 m/s, to rest in 7.4 s?
Answer:
The force required is 3,104 N
Explanation:
Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = ma
Where a is the acceleration of the object.
On the other hand, the equations of the Kinematics describe the motion of the object by the equation:
[tex]v_f=v_o+at[/tex]
Where:
vf is the final speed
vo is the initial speed
a is the acceleration
t is the time
Solving for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:
[tex]\displaystyle a=\frac{0-20.4}{7.4}[/tex]
[tex]a=-2.757\ m/s^2[/tex]
The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:
[tex]F = 1,126\ kg * 2.757\ m/s^2[/tex]
F= 3,104 N
The force required is 3,104 N
A 1100 kg car strikes a wall with a force of 4000 N in 0.35 seconds. What is the change in the
velocity of the car?
Answer:
(v-u) = 1.27 m/s
Explanation:
Given that,
Mass of a car, m = 1100 kg
Force with which the wall strikes, F = 4000 N
Time, t = 0.35 s
We need to find the change in velocity of the car.
The net force acting on the car is given by :
F = ma
a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\(v-u)=\dfrac{Ft}{m}\\\\(v-u)=\dfrac{4000\times 0.35}{1100}\\\\(v-u)=1.27\ m/s[/tex]
(v-u) is the change in velocity. Hence, the change in the velocity of the car is 1.27 /s.
Suppose that you cut a sugar cube into smaller and smaller parts. If you
could separate out one molecule, which of these describes what you have?
A. a carbon atom.
B. a molecule without atoms.
C. a molecule with no mass.
D. a molecule of sugar.
Answer:
c
Explanation:
jsjdkksddssddddddmekekwkkwkekeke
The graph below shows the force required to stretch a spring various distances. Review the graph below.
What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 3.0 meters?
Explanation:
Elastic string constant (k)
= Slope of the graph F/x
= 15.0N/10.0m = 1.50N/m
Hence,
EPE = 0.5kx² = 0.5(1.50N/m)(3.0m)² = 6.75J.
Answer:
6.8
Explanation:
A ship's boiler steam comes out at 112 C and pushes through the system, exiting into the condenser,
which is kept at 20 C by circulating seawater. What is the ideal efficiency of the ship's boiler? Round to
the nearest thousandth.
O 0.643
O 0.523
O 0.703
O 0.239
Answer:
D: 0.239
Explanation:
Equation for ideal efficiency is;
η = 1 - (T_c/T_h)
We are told that;
steam comes out at 112° C. Thus, T_h = 112°C. Converting to Kelvin gives; T_h = 112 + 273 = 385 K
The one exiting into the condenser is kept at 20°C. Thus; T_c = 20 + 273 = 293 K
Thus;
η = 1 - (293/385)
η = 0.239
A badminton shuttlecock leaves the racquet traveling 30 m/s. It goes over the net 0.5
seconds later with a speed of 10 m/s. Calculate its average acceleration.
Given :
A badminton shuttlecock leaves the racquet traveling 30 m/s.
It goes over the net 0.5 seconds later with a speed of 10 m/s.
To Find :
The average acceleration of the shuttlecock.
Solution :
We know, average acceleration(a) is given by :
[tex]a = \dfrac{\text{Change in speed}}{\text{Time taken }}\\\\a = \dfrac{10-30}{0.5 }\ m/s^2\\\\a = -40\ m/s^2[/tex]
Therefore, the average acceleration is -40 m/s².
a bug is flying with a velocity of 10m/s into a wind at 3m/s what is the resultant velocity of the bug?
please I really need help, I will mark you brainliest
A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.
1. Calculate the impulse delivered to the ball.
2. What was the change in momentum of the ball?
3. What was the velocity of the ball as it left the tennis racket?
4. What would happen to the ball's velocity if it remained on the tennis racket longer than .05 s?
Explanation:
I am not sure about this question sry but u can try asking a tutor u don't need to use any points
What happens to make electrical current flow in a generator?
find the potential energy of an aircraft weighing 10000 bs at 5000 ft true altitude and 125 kts true air speed
Answer:
[tex]U=5*10^7ft.Ib[/tex]
Explanation:
From the question we are told that
Weight [tex]W= 10000bs[/tex]
Altitude [tex]H=5000ft[/tex]
Speed [tex]V=125kts\\1kts=0.514m/s\\V=125*0.514=>64.25m/s[/tex]
Generally the equation for Potential energy ids mathematically given as
[tex]Potential\ Energy\ U=mgh[/tex]
[tex]U=Wh[/tex]
[tex]U=10000*5000[/tex]
[tex]U=5*10^7ft.Ib[/tex]
PLEASE HELP!! URGENT!!
IDENTIFY WHAT IS BEING DESCRIBED IN EACH SENTENCE AND WRITE YOUR ANSWER ON THE BLANKS
_______1. Allows ingestion and breaks down food so that nutrients can be absorbed.
_______2. Provides mechanical support; stores minerals and produces red blood cells.
_______3. Protects the body's internal environment and stores fat.
_______4. Enables the transport of nutrients, glasses and wastes to and from cells.
_______5. Secretes hormones into the bloodstream for regulation of cellular activities.
The correct answers for the given paragraph are as follow:
Digestive Enzymes allows ingestion and breaks down food.Skeletal system provides mechanical support and also stores minerals.Integumentary system protects the body's internal environment and stores fat.Cardiovascular system enables the transport of nutrients, glasses and wastes to and from cells.Endocrine glands secretes hormones into the bloodstream for regulation of cellular activities.1.
The digestive enzymes are the proteins that tends to break down the larger molecules like fats, proteins and carbs into smaller molecules.
Thus, the correct answer is Digestive Enzyme.
2.
The skeletal system is the framework of body, consisting of bones and various connective tissues. It provides the mechanical support and produces red blood cells.
Thus, the correct answer is skeletal system.
3. The organ system that protects the body's internal environment and stores the fat is known as Integumentary system.
Thus, the correct answer is integumentary system.
4.
The cardiovascular system enables the transport of nutrients, glasses and wastes to and from cells. Also, it is used for the transportation of nutrients and oxygen-rich blood to all parts of the body and to carry deoxygenated blood back to the lungs.
Thus, the correct answer is cardiovascular system.
5.
Endocrine glands are responsible for the secretion of hormones into the bloodstream to regulate the cellular activities.
Thus, the correct answer is Endocrine glands.
Learn more about the human organs and digestive system here:
https://brainly.com/question/16347243
A roller coaster car starts at 6 m/s at the top of the hill at the 3 seconds latter at the bottom of the hill the roller coaster car is going 72 m/s, what was the cars acceleration?
Answer:
22m/s
Explanation:
Step one:
Given data
Initial velocity of roller coster u= 6 m/s
Final velocity v= 72m/s
time t= 3 seconds
Required
We want to solve for the acceleration of the roller coster
Step two:
From the formula
acceleration= v-u/t
substitute
a= 72-6/3
a=66 /3
a= 22 m/s
The cars acceleration 22m/s
Please help meeeeeeeeeee
Answer:
C
Explanation:
But I’m not quite sure
Find the speed (in m/s) needed to escape from the solar system starting from the surface of Neptune. Assume there are no other bodies involved, and do not account for the fact that Neptune is moving in its orbit.
Answer:
The speed needed to escape from the solar system starting from the surface of Neptune is approximately 23557.615 meters per second.
Explanation:
The escape speed needed to escape from the gravitational influence of a planet ([tex]v_{e}[/tex]), measured in meters per second, is derived from Newton's Law of Gravitation and Principle of Energy Conservation and defined by the following formula:
[tex]v_{e} = \sqrt{\frac{2\cdot G\cdot M}{R} }[/tex] (1)
Where:
[tex]G[/tex] - Gravitational constant, measured in cubic meters per kilogram-square second.
[tex]M[/tex] - Mass of Neptune, measured in kilograms.
[tex]R[/tex] - Radius from the center to surface, measured in kilograms.
If we know that [tex]G = 6.672\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 1.024\times 10^{26}\,kg[/tex] and [tex]R = 24.622\times 10^{6}\,m[/tex], then the escape speed needed is:
[tex]v_{e} =\sqrt{\frac{2\cdot \left(6.672\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (1.024\times 10^{26}\,kg)}{24.622\times 10^{6}\,m} }[/tex]
[tex]v_{e} \approx 23557.615\,\frac{m}{s}[/tex]
The speed needed to escape from the solar system starting from the surface of Neptune is approximately 23557.615 meters per second.
A force does 128-J of work on a 4-kg cart. What mus be the velocity of the cart?
Answer:
v = 8[m/s]
Explanation:
In this case, the work that is exerted on the cart is the kinetic energy that allows the movement, so we can use the following equation of kinetic energy.
[tex]E_{kin}=Work\\E_{kin}=\frac{1}{2} *m*v^{2}[/tex]
Now replacing:
[tex]128=0.5*4*v^{2} \\v=\sqrt{64} \\v=8[m/s][/tex]
an object is moving with constant velocity downwards on a frictionless inclined plane that makes an angle of
An object is moving with constant velocity downwards on a frictionless inclined plane that makes an angle of θ with the horizontal.
1. Which direction does the force of gravity act on the object?
2. Which direction does the normal force act on the object?
Which force is responsible for the object moving down the incline?
Answer:
The answer is below
Explanation:
1. When an object is moving with a constant velocity, the direction the force of gravity act on the object is DIRECTLY DOWN.
2. When an object is moving with a constant velocity, the direction the normal force act on the object "perpendicular to the surface of the plane."
3. When an object is moving with a constant velocity, the force that is responsible for the object moving down the incline is "the component of the gravitational force parallel to the surface of the inclined plane."
What is the target heart rate for a 24 year old?
Answer:
196
Explanation:
subtract 24 from 220 to get your answer.
Answer:
100 beats for minute
Explanation:
Adults ( age 18 and over) 60 - 100 beats per minute
the reading on a mercury barometer at mombasa is 760mms.calculate the pressure at mombasa(density of mercury=1.36x10 power 4kg/m3
Answer:
The pressure at Mombasa is 101.396 KPascal.
Explanation:
Given: Reading on barometer = 760 mm
= 0.76 m
Density of mercury = 1.36 x [tex]10^{4}[/tex] kg/[tex]m^{3}[/tex]
In this case, the pressure can be expressed as:
P = σhg
Where: σ is the density of mercury, h is height of mercury in the barometer, and g is the acceleration due of gravity.
But, g = 9.81 m/[tex]s^{2}[/tex]
So that,
P = 1.36 x [tex]10^{4}[/tex] x 0.76 x 9.81
= 101396.16 Pascal
P = 101.395 KPascal
The pressure at Mombasa is 101.396 KPascal.
Can water and alcohol be purified by distillation
PLS Help
1. Define "sport" in your own words. Define what a "hobby" is.
2. Do some research and find a definition of sport that makes sense to you. In what ways is this definition similar to yours and in what ways is it different? How do the "experts" define the difference between a sport and a hobby?
3. Select 4 of the following and state whether you think it is a sport, or hobby and, of course, why. Of course you can research and see what others think. If you believe something is not a sport, what could make it a sport.
Competitive cheerleading, race car driving, horse racing, darts, fishing, trampoline, WWE wrestling, swimming, rodeo.
Answer:
sport is an activity that involves movement and teamwork.
hobby is a personal interest that you enjoy doing often.
Explanation:
:)
an astronaut must journey to a distant planet, which is 300 light years from earth. what speed will be necessary if the austronaut wishes to age only 12 years during the round trip
Answer:
First, if you are inside a spaceship that travels with a relativistic speed, your inner time does not change. So your cells and DNA feel the time exactly as how they would feel it on Earth. This means that if you spend 12 years travelling on your spaceship, you will age those 12 years, while the ones that are still in Earth may be experienced time in a different way (The ones on Earth may measure the time between your departure and your arrival as 15 years, for example, so they feel the time in a different way).
Then we only need to solve the equation:
Distance/time = speed
Distance = 300 Light years.
Time = 12 years:
300 light-years/12 years = speed = 25*C
where C is the speed of light:
C = 3*10^8 m/s
From this, we can conclude that you would need to travel a lot faster than the speed of light.
Then the speed is:
speed = 25*3*10^8 m/s= 7.5*10^9 m/s.
Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. Through what angle will it have turned after time 2t?
Answer:
After time 2t, the wheel will turn through an angle of 100 rad.
Explanation:
Given;
initial velocity of the wheel, [tex]\omega_i = 0[/tex]
time of motion, t = t
angular distance, θ = 25 rad
The constant angular acceleration is calculated as;
[tex]\theta = ut + \frac{1}{2}at^2\\\\\theta = 0 + \frac{1}{2}at^2\\\\2\theta = at^2\\\\a = \frac{2\theta }{t^2} \\\\a = \frac{2\ \times \ 25 }{t^2}\\\\a = \frac{50}{t^2} \\\\when \ t = 2t\\\\\theta = \frac{1}{2}at^2\\\\\theta = \frac{1}{2}(\frac{50}{t^2})(2t)^2\\\\\theta =\frac{1}{2}(\frac{50}{t^2})(4t^2)\\\\\theta = 100 \ rad[/tex]
Therefore, after time 2t, the wheel will turn through an angle of 100 rad.
The angle of the wheel would have turned after time 2t is equal to 100 rad.
Given the following data:
Initial angular velocity = 0 rad/s (since the wheel starts from rest).Time = t secondsAngle = 25 radTo determine the angle of the wheel would have turned after time 2t:
First of all, we would determine the angular acceleration of the wheel by using the second equation of rotational motion.
[tex]\theta = ut + \frac{1}{2} at^2\\\\25 =0(t) + \frac{1}{2} at^2\\\\25=\frac{1}{2} at^2\\\\50=at^2\\\\a=\frac{50}{t^2} \;rad/s^2[/tex]
Next, we would determine the angle the wheel would have turned after time 2t:
[tex]\theta = ut + \frac{1}{2} at^2\\\\\theta = 0(2t) + \frac{1}{2} (\frac{50}{t^2} )(2t)^2\\\\\theta = \frac{25}{t^2} \times 4t^2\\\\\theta = 25\times 4\\\\\theta = 100\;rads[/tex]
Read more: https://brainly.com/question/8898885
