N'(-10,-15) is the image of N after a dilation with a scale factor of 5/4, centered at the origin. What are the coordinates of N?

When the point N is dilated, the coordinate of N changes to N'

The coordinate of point N is (8,12)

The given parameters are:

N' = (10,15)

k = 5/4

To calculate the coordinate of N, we make use of:

N * k = N'

So, we have:

N * 5/4 = (10,15)

Multiply both sides by 4

N * 5 = (40,60)

Divide both sides by 5

N = (8,12)

Hence, the coordinate of point N is (8,12)

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Hector's Flower Arrangements
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