On a coordinate plane, an image has points (negative 2, 2), (0, 2), (2, 0), (0, negative 2), (negative 2, negative 2).
Use the image shown and a scale factor of 1/2 to find the pre-image. Which is the pre-image of A’?

The multiplication is 120*[tex]a^{3/2}[/tex].

Power defines a base number raised to the exponent, where base number is the factor which is multiplied by itself and exponent denotes the number of times the same base number is multiplied.

Given:

3√(5a) * 8 √(35a²)

= 3√(5a)* 8* a *√7* √5

= 3*8*5*a *√(7a)

= 120 [tex]a^{1/2+1}[/tex]

=120*[tex]a^{3/2}[/tex]

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Answer:

[tex]120a\sqrt{7a}[/tex]

Step-by-step explanation:

It's right on khan academy

An axiom is a statement that is assumed to be true without proof.

In logic, a statement could be shown to be valid or true by the use of premises that lead to a sound conclusion.

The following terms can be used to describe the statements;

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Answer:

The answer is axiom, theorem, and then conjecture

Step-by-step explanation:

Explanation:

A function is a relationship where any one x-value/input only has one corresponding y-value/output. (note: a y-value can have multiple x-values).

> This can be called "assigning one y-value to every x element".

The vertical line test places a line that would connect all y-values of an x-value (that is, if it were to have multiple y-values). If multiple points can be found along the vertical line, it is, therefore, by the definition of a function, not a function. (Because an x-value will have more than one y-value).

So, a graph that fails the vertical-line test does not represent a function because an x-value will correspond with more than one y-value.

hope this helps!!

Step-by-step explanation:

Answer:

it's 5 degrees celsius I think you must have entered a 4-32 instead of a 41-32 is what threw you off

Step-by-step explanation:

The graph of this model would be a straight line that increases only option third is correct.

A line graph is a graph made up of segments of straight lines that connect the depicted data points.

We have:

An auto mechanic charges (C) an initial fee of $50 and then $40 per hour.

Let T be the total fee and h is the number of hours

T = 50 + 40h

The above equation represents a graph of a straight line as the slope of the line is positive.

m = 50

Thus, the graph of this model would be a straight line that increases only option third is correct.

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Answer:

A exponential equation is usually of the form f(x)=a (1±r)ˣ.

Our limitation: Initial Vale is 500.

Let's look at our options:

#1- Initial Value of 1000  --- WRONG!

#2- Initial Value of 1000  --- WRONG!

#3- Initial Value of 500 ---- Maybe

#4- Initial Value of 500 ---- Maybe

Let's look at 3 and 4:

#3- Fits Our Form of f(x)=a (1±r)ˣ ---- CORRECT!

#4- Does not fit Our Form of f(x)=a (1±r)ˣ, It's to the 2nd power, not the x power! ---- WRONG!

Hence, #3 Is correct!

Step-by-step explanation:

Well, I hope you understood, and I'd gladly explain anything that didn't make sense. A brainliest would be appreciated, thank you!

-Zylynn Jade Ardenne

Answer:

[tex]\textsf{C.} \quad \left(3,\dfrac{5}{2}\right)[/tex]

Step-by-step explanation:

Midpoint between two points

[tex]\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)[/tex]

Define the endpoints of the line segment:

[tex]\textsf{Let }(x_1,y_1)=(-1,2)[/tex]

[tex]\textsf{Let }(x_2,y_2)=(7,3)[/tex]

Substitute the defined endpoints into the midpoint formula and solve:

[tex]\implies \textsf{Midpoint}=\left(\dfrac{7+(-1)}{2},\dfrac{3+2}{2}\right)[/tex]

[tex]\implies \textsf{Midpoint}=\left(3,\dfrac{5}{2}\right)[/tex]

Midpoint

If she puts 0 in the box she would have a direct variation.

Lydia writes the equation y = 5x - __ with a missing value.

She puts a value in the box and says that the equation represents a direct variation.

We have to choose the correct option from the given options that explain that the equation could represent a direct variation.

When two variables are such that one is a constant multiple of the other, we said they are in Direct variation.

In form of y = ax, where y and x are in direct variation.

Consider the given equation y = 5x  - __

For the equation to be in direct variation the value of the missing term has to be 0.

then the equation becomes,

y = 5x

Thus, If she puts 0 in the box she would have a direct variation.

Option (a) is correct.

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Answer:

a

Step-by-step explanation:

Answer:

[tex]m \leqslant 10 \: or \: m > 4[/tex]

Step-by-step explanation:

[tex] \frac{m - 2}{3} \leqslant - 4 \\ \frac{m - 2}{3} \times 3 \leqslant - 4 \times 3 \\ m - 2 \leqslant - 12 \\ m - 2 + 2 \leqslant - 12 + 2 \\ m \leqslant 10[/tex]

OR

[tex]3m - 8 > 4 \\ 3m - 8 + 8 > 4 + 8 \\ 3m > 12 \\ \frac{3m}{3} > \frac{12}{3} \\ m > 4 [/tex]

The expression 6x¹⁰ - 96x² can be written by factoring out the greatest common factor is 6x²(x⁸ - 16) and for a part, B expression can be simplified by applying identity.

It is defined as the combination of constants and variables with mathematical operators.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have an expression:

Part A)

= 6x¹⁰ - 96x²

= 6x²(x⁸ - 16)

Part B)

[tex]\rm =6x^2(\left(x^4\right)^2-4^2)[/tex]

[tex]\rm =6x^2(\left(x^4+4\right)\left(x^4-4\right))[/tex]

[tex]\rm =6x^2\left(x^2+2x+2\right)\left(x^2-2x+2\right)\left(x^2+2\right)\left(x^2-2\right)[/tex]

Thus, the expression 6x¹⁰ - 96x² can be written by factoring out the greatest common factor is 6x²(x⁸ - 16) and for a part, the B expression can be simplified by applying identity.

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Answer: QN=19

Step-by-step explanation:

Diagonals of an isosceles trapezoid are congruent, so NQ=PM.

By the segment addition postulate, NQ=QR+RN=3x+7.

So,

[tex]6x-5=3x+7\\\\3x-5=7\\3x=12\\\\x=4[/tex]

So, [tex]QN=3(4)+7=\boxed{19}[/tex]

Answer:

0.462

Step-by-step explanation:

1km=1000m

so to get from metres to kilometres you divide by 1000

so 462÷1000=0.462

The vertex of the absolute value function is (-7,-2)

The function is given as:

f(x) = 3|x + 7| - 2

The above function is an absolute value function.

An absolute value function is represented as:

f(x) = a|x - h| + k

Where:

Vertex = (h,k)

By comparison, we have:

(h,k) = (-7,-2)

Hence, the vertex of the absolute value function is (-7,-2)

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Answer:

1/2 cup of chocolate chips

Step-by-step explanation:

Given ratio:

Let x be the unknown amount of chocolate chips:

[tex]\implies \sf \dfrac{1}{3}:2=x:3[/tex]

[tex]\implies \sf \dfrac{\frac{1}{3}}{2}=\dfrac{x}{3}[/tex]

Cross multiply:

[tex]\implies \sf 3 \cdot \dfrac{1}{3}=2 \cdot x[/tex]

[tex]\implies \sf 1=2x[/tex]

[tex]\implies \sf x=\dfrac{1}{2}[/tex]

Therefore, 1/2 a cup of chocolate chips will be needed for 3 cups of flour.

Let that be x

Answer:

LM

Step-by-step explanation:

Perpendicular slope would be   - 1 / m   =   - 1/(-5/6)   = 6/5

slope m = rise / run       line   LM   rises 6    for a run of 5      

Answer:

it's 1,1 is the correct ans

Step-by-step explanation:

Because my teacher told its absolutely correct answer I got the same question in exam

Answer:

the answer should be the 2 one

Step-by-step explanation:

I got it right just had it.

Answer:

  168π cm²

Step-by-step explanation:

The total surface area is the sum of the areas of the parts: a hemisphere and a cone.

__

The area of a hemisphere is half the area of a sphere, so the total area is ...

  total area = hemisphere area + cone area

  = 2πr² +πrl

  total area = πr(2r +l)

__

For the given dimensions, r = 6 cm, l = 16 cm, the total surface area is ...

  total area = π(6 cm)(2(6 cm) +16 cm) = π(6)(28) cm²

  total area = 168π cm²

The equation fourth represents the ellipse that has vertices at (1, 0) and (11, 0), and an eccentricity of 3/5 option fourth is correct.

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have:

The vertices of the ellipse = (1, 0) and (11, 0)

Eccentricity of ellipse = 3/5

We have equations:

[tex]\rm \dfrac{\left(x-6\right)^{2}}{100}+\dfrac{y^{2}}{64}=1[/tex]

[tex]\rm \dfrac{\left(x+6\right)^{2}}{64}+\dfrac{y^{2}}{100}=1[/tex]
[tex]\rm \dfrac{\left(x+6\right)^{2}}{16}+\dfrac{y^{2}}{25}=1[/tex]

[tex]\rm \dfrac{\left(x-6\right)^{2}}{25}+\dfrac{y^{2}}{16}=1[/tex]

From the fourth equation:

The vertices of the ellipse:

(1, 0) and (11, 0)

The eccentricity:

c²  = a² - b²

c² = 25-16

c = 3

e = c/a = 3/5

Thus, the equation fourth represents the ellipse that has vertices at (1, 0) and (11, 0), and an eccentricity of 3/5 option fourth is correct.

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Answer: I don’t understand

Step-by-step explanation:

After factorizing the given equation, we can find the three iterations by putting the consecutive values of x.

The given equation is 3∧x = 2∧(-x) + 4. We can modify it as shown below:

Take logarithm on both the sides

log(3∧x) = log[2∧(-x) + 4]

xlog3 = log[2∧(-x) + 4]

x = log[2∧(-x) + 4] / log3

For the first iteration, put x = 1

x = log[2∧(-1) + 4] / log3

x = log4.5 / log3

x = 0.477

For the second iteration, put x = 2

x = log[2∧(-2) + 4] / log3

x = log4.25 / log3

x = 0.477

For the third iteration, put x = 3

x = log[2∧(-3) + 4] / log3

x = log4.125 / log3

x = 0.477

So, this is how we can find three iterations.

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The value of this irrational Expression is 40.77 .

An expression is a mathematical statement consisting of variables , constants and mathematical operators.

The expression given is

7√22 +3√7

√22 = 4.69

√7 = 2.65

32.83 + 7.94

40.77

The value of this irrational Expression is 40.77 .

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Answer:

is B

Step-by-step explanation:

this is the best possible answer

Answer:

B

Step-by-step explanation:

Answer: 2[tex]x^{2}[/tex]+7x-4

Step-by-step explanation:

Product implies multiplication so just multiply it out.

(2x-1) (x+4)

2x^2+8x-1x-4  (Combine like terms)

2x^2+7x-4

Answer:

see the attachment photo!

i hope this can help you! :)