P(A)=0.34, P(B)=0.61, P(A and B)=0.05
P(BIA)

Answers

Answer 1

Answer:

0.147

Explanation:

P(B | A) = P( A and B) / P(A)

            = 0.05 / 0.34

            = 0.147


Related Questions

What is the probability that a randomly selected person said data analysis was a critical skill?
A..050
B.0.33
C.0.15
D.0.79

Answers

The probability that a randomly selected person said data analysis was a critical skill will be A. 0.50.

How to calculate the probability?

The number of critical skilled person will be:

= 253 + 105

= 358

The total number of employees will be:

= 253 + 110 + 105 + 250

= 718

Therefore, the probability will be:

= 358/718 × 100

= 50%

= 0.50

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consider the following hypothesis test, H0, U greater than or equal to 20, Ha less than 20, a sample of 50, provided a mean of 19.4 population standard deviation is 2, compute the value of of the test static, what is the p-value,

Answers

Based on the calculations, the value of the test statistic and p-value are equal to -2.1213 and 0.0169 respectively.

Given the following data:

Standard deviation = 2.Sample mean = 19.4.Number of sample = 50.Hypothesized mean = 20.

How to compute the test static?

Mathematically, the value of the test statistic can be computed by using this formula:

[tex]Z=\frac{\bar{x}\;-\;\mu}{ \frac{\sigma}{\sqrt{n} } }\\\\Z=\frac{19.4\;-\;20}{\frac{2}{\sqrt{50}}}\\\\Z=\frac{-0.6}{0.282842 }[/tex]

zₓ = -2.1213.

From the z-table, the p-value is given by:

P(Z < zₓ) = P(Z < -2.1213)

P(Z < -2.1213) = 0.0169.

Since the p-value is equal to 0.0169 less than α = 0.05, we would reject H₀ : µ equal to 20. Thus, we would conclude that µ < 20.

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ASAP HURRY Drag the descriptions of each investment in order from which will earn the least simple interest to which will earn the most simple interest.
from least to greatest please help: investment of 1,200 at a 12% interest rate for 5 years, investment of 1,200 at a 12% interest rate for 9 years, and a investment of 1,200 at a 6% interest rate for 9 years.

Answers

The descriptions of each investment from  least to greatest are:

An investment of 1,200 at a 6% interest rate for 9 years- A = $1,848.00.An investment of 1,200 at a 12% interest rate for 5 years- A = $1,920.00.An investment of 1,200 at a 12% interest rate for 9 years - A = $2,496.00.

What is the investment about?

An investment of 1,200 at a 12% interest rate for 5 years will be:

I = A - P = $720.00

Note that:

A = P(1 + rt)

Therefore,

r = R/100 = 12%/100 = 0.12 per year.

So:

A = 1200(1 + (0.12 × 5)) = 1920

A = $1,920.00

So, The total amount accrued, principal plus interest, from simple interest on a principal of $1,200.00 at a rate of 12% per year for 5 years is $1,920.00.

At an investment of 1,200 at a 12% interest rate for 9 years:

A = $2,496.00

I = A - P = $1,296.00

Note that

A = P(1 + rt)

Therefore:

r = R/100 = 12%/100 = 0.12 per year.

So:

A = 1200(1 + (0.12 × 9)) = 2496

A = $2,496.00

Therefore, the total amount accrued, principal plus interest, from simple interest on a principal of $1,200.00 at a rate of 12% per year for 9 years is $2,496.00.

At an investment of 1,200 at a 6% interest rate for 9 years.

Note that:

I = A - P = $648.00

The Equation is:

A = P(1 + rt)

Therefore,

r = R/100 = 6%/100 = 0.06 per year.

So

A = 1200(1 + (0.06 × 9)) = 1848

A = $1,848.00

So, The total amount accrued, principal plus interest, from simple interest on a principal of $1,200.00 at a rate of 6% per year for 9 years is $1,848.00.

So, the descriptions of each investment from  least to greatest are:

An investment of 1,200 at a 6% interest rate for 9 years- A = $1,848.00.An investment of 1,200 at a 12% interest rate for 5 years- A = $1,920.00.An investment of 1,200 at a 12% interest rate for 9 years - A = $2,496.00.

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