The net force on q₂ will be 1.07 x 10⁻² N, pointing to the left.
To find the net force on particle q₂, we need to calculate the force due to q₁ and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:
F = k × (q₁ × q₂) / r²
where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.
The force due to q₁ on q₂ can be calculated as:
F₁ = k × (q₁ × q₂) / r₁²
where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).
Similarly, the force due to q₃ on q₂ can be calculated as:
F₂ = k × (q₃ × q₂) / r₃²
where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).
The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.
To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:
Fnet = F₁ - F₃
Substituting the values we get:
Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²
Plugging in the values we get:
Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]
Fnet = 1.07 x 10⁻² N
Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.
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the temperature of an ideal gas in a sealed 0.60m^3 container is reduced from 440 k to 270 k. the final pressure did the gas is 40kpa. the molar heat capacity at constant volume of the gas is 28.0j/mol•k. what is the work done by the gas?
Analyze the data on the plot below. Determine the speed of the hawksbill sea turtle during each interval listed below.
HELP PLEASE!!!
Answer:
Day 0 to day 2: 5km/day
Day 2 to day 3: 2km/day
Explanation:
Day 0 to day 2: 10/2 = 5
Day 2 to day 3: 12 - 10 = 2
To Calculate:
The x-axis, or the days from 0 to 6, line up with the y-axis, or the distance from 0 to 24. The point in the graph means that on that day, the turtle traveled that much distance. For example, on the third point (2, 10), the day is 2 and the distance is 10. To find the distance over multiple days, catalog the days in your mind and look for the points. Then, find the difference. For example, from day 2 (2, 10) to day 5 (5, 18), this would look like: 5 - 2 = 3, and 18 - 10 = 8, so this means that over 3 days, the turtle traveled 8 km.
