PLEASE HELP, I NEED THIS TO BE DONE BY TODAY

The point estimate for the mean is 12.1 and the margin of error is 1.95.

For an interval estimate for the mean with a lower bound of 8.2 and an upper bound of 16, the midpoint of the interval is the point estimate for the mean.

Point estimate for the mean = (Lower bound + Upper bound) / 2 = (8.2 + 16) / 2 = 12.1

The margin of error is the difference between the point estimate for the mean and either the lower or upper bound of the interval. Since the interval estimate given is a two-sided interval, we can take the difference between the point estimate and the lower bound (or the upper bound) and divide by 2 to get the margin of error.

Margin of error = (Upper bound - Point estimate for the mean) / 2 = (16 - 12.1) / 2 = 1.95

Therefore, the point estimate for the mean is 12.1 and the margin of error is 1.95.

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According to the given information, the series Σ(sin(1/n)) diverges.

What is the convergence and divergence of the sequence?

Convergence: A sequence approaches a fixed number as the number of terms increases.

Divergence: A sequence does not approach a fixed number as the number of terms increases.

We have:

aₙ = sin(1/n)

bₙ = 1/n

Note that both aₙ and bₙ are positive for n > 0.

We will use the limit comparison test to determine if the series converges or diverges. To do this, we will compare the given series to a known series whose convergence or divergence is already known. We will choose the series Σ(1/n) as our comparison series since it is a p-series with p = 1, which is known to diverge.

Taking the limit as n approaches infinity of aₙ/bₙ, we get:

lim n→∞ (sin(1/n)/(1/n))

We can evaluate this limit using L'Hopital's rule:

lim n→∞ (cos(1/n) * (-1/n²)) / (-1/n²)

= lim n→∞ cos(1/n)

Since the cosine function is continuous, we can substitute the limit as m = 1/n:

lim m→0 cos(m)

cos(m) is continuous at m=0, and cos(0) = 1, so

lim m→0 cos(m) = 1

Since the limit of aₙ/bₙ is a finite, positive value, we conclude that the series Σaₙ and the series Σbₙ have the same behavior; that is, either they both converge or they both diverge. Since the series Σbₙ diverges, the series Σaₙ also diverges.

Therefore, the series Σ(sin(1/n)) diverges.

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The measure of the largest angle (angle C) is approximately 87 degrees. So, correct option is A.

To find the value of x, we can use the Pythagorean theorem:

BC² = AB² + AC²

Substituting the given values, we get:

23² = 16² + AC²

529 = 256 + AC²

AC² = 273

AC = √273

Now, we can use the Law of Cosines to find the largest angle, which is opposite to the longest side (BC):

cos(C) = (a² + b² - c²) / 2ab

where a, b, and c are the lengths of the sides opposite to angles A, B, and C, respectively.

Substituting the given values, we get:

cos(C) = (16² + AC² - 23²) / 2(16)(AC)

cos(C) = (256 + 273 - 529) / (32√273)

cos(C) = 0.0838

C = cos⁻¹(0.0838)

C ≈ 87 degrees

Therefore, correct option is A.

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a) The perimeter of the shape is 10π.

b)  The expression for the perimeter of the shape in terms of x and π is  (5/2)πx.

The shape consists of a quarter circle with radius x, and two semicircles with radius x as well.

a) To find the perimeter of the shape when x = 4, we need to first find the length of each component of the shape.

The quarter circle has an arc length of one-fourth the circumference of a circle with radius x, which is:

arc length = (1/4) × 2πx = (1/2)πx

The two semicircles each have a circumference of half the circumference of a circle with radius x, which is:

circumference = πx

Therefore, the total perimeter of the shape is:

perimeter = arc length + 2 × circumference

= (1/2)πx + 2πx

= (5/2)πx

When x = 4, the perimeter of the shape is:

perimeter = (5/2)π(4) = 10π

b) To write an expression for the perimeter of the shape in terms of x and π, we use the same calculations as above:

arc length = (1/2)πx

circumference = πx

Therefore, the perimeter of the shape is:

perimeter = arc length + 2 × circumference

= (1/2)πx + 2πx

= (5/2)πx

So the expression for the perimeter of the shape in terms of x and π is:

perimeter = (5/2)πx

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The school has $6,375 left to buy supplies for next year's play.

Let's "a" represents the number of adults and "c" represents the number of children. We can then use these variables to represent the amount of money collected from their tickets.

The amount of money collected from adults is given as $8 for each adult's ticket. So, the total amount collected from adults can be represented as 8a. Similarly, the amount of money collected from children is given as $3 for each child's ticket. So, the total amount collected from children can be represented as 3c.

We are also given that there were 80 adults and 20 children at the school play. We can use these numbers to create two equations:

a + c = 100 (equation 1)

80a + 20c = total amount collected from tickets (equation 2)

By using substitution method to solve these equations. We can rearrange equation 1 to get c in terms of a:

c = 100 - a

We can then substitute this expression for c in equation 2:

80a + 20(100 - a)

Simplifying the above equation, we get:

60a + 2000 = total amount collected from tickets

We know that $125 was donated to the local theater program. So, the amount of money left to buy supplies for next year's play can be represented as:

total amount collected from tickets - $125

Substituting the value of total amount collected from tickets from the above equation, we get:

60a + 2000 - $125

Simplifying the above equation, we get:

60a + 1875 = amount left to buy supplies

By substituting the value of "a" from equation 1 to get:

60(80) + 1875 = amount left to buy supplies

Simplifying the above equation, we get:

$6,375 = amount left to buy supplies

Therefore, the school has $6,375 left to buy supplies for next year's play.

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Complete Question is There were 80 adults and 20 children at a school play. The school collected $8 for each adult's ticket and $3 for each child's ticket. The school donated $125 of the money from tickets to local theater program and used the remaining money to buy supplies for next year's school play. How much money does the school have to buy supplies for nest year's play?  

The number of degrees of freedom increases, the t-distribution becomes closer to the standard normal distribution, and the critical value of t approaches the value of 1.96, which is the critical value of z for a 95% confidence interval based on the standard normal distribution.

The critical value of t for a 95% confidence interval changes as the number of degrees of freedom increases in the following way:

As the number of degrees of freedom increases, the critical value of t decreases.

This is because the t-distribution becomes more concentrated around its mean of 0 as the number of degrees of freedom increases.

The t-distribution is a family of probability distributions that depend on the number of degrees of freedom.

The number of degrees of freedom is small, the t-distribution has more spread or variability, and the tails of the distribution are wider than the normal distribution.

The number of degrees of freedom increases, the t-distribution approaches the normal distribution, which has a fixed and known critical value for a given level of confidence.

If we consider a 95% confidence interval with 10 degrees of freedom, the critical value of t is approximately 2.228.

But if we increase the degrees of freedom to 50, the critical value of t decreases to approximately 2.009.

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The average gradient for the stream segment is calculated as the change in elevation divided by the horizontal distance:

gradient = (change in elevation) / (horizontal distance)

The change in elevation is the difference between the starting elevation (550 feet) and the ending elevation (100 feet):

change in elevation = 550 ft - 100 ft = 450 ft

The horizontal distance is given as 100 miles:

horizontal distance = 100 miles

Therefore, the average gradient is:

gradient = (450 ft) / (100 miles) = 4.5 ft/mile

So the answer is (c) 4.5 ft/mile.

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This results in a probability of approximately 0.044, or 4.4%.  the probability of any number of eagles surviving their first year can be calculated using the binomial probability formula.

The probability of a bald eagle surviving its first year of life is 62%. If 45 bald eagles are randomly selected, we can use the binomial probability formula to calculate the probability of a certain number of eagles surviving their first year.

P(x=k) = (n choose k) * p^k * (1-p)^(n-k)

Where n is the total number of trials (45), k is the number of successes (surviving eagles), p is the probability of success (0.62), and (n choose k) is the binomial coefficient.

To find the probability that exactly 20 eagles survive their first year, we plug in the values:

P(x=20) = (45 choose 20) * 0.62^20 * 0.38^25

This results in a probability of approximately 0.044, or 4.4%.

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To prove that line AB is equal to line CD and line BC is equal to line AD in parallelogram ABCD, we can use the properties of parallelograms.

1. Opposite sides of a parallelogram are parallel.

Since ABCD is a parallelogram, we know that AB is parallel to CD and BC is parallel to AD.

2. If two parallel lines are intersected by a transversal, then the alternate interior angles are congruent.

Using the fact that AB is parallel to CD, we can draw a transversal line, say line EF, intersecting these parallel lines at points E and F. This gives us alternate interior angles AEF and CFE, which are congruent. Similarly, using the fact that BC is parallel to AD, we can draw another transversal line, say line GH, intersecting these parallel lines at points G and H. This gives us alternate interior angles CBG and DAG, which are congruent.

3. If two angles of a parallelogram are congruent, then the other two angles are also congruent.

From step 2, we know that angle AEF is congruent to angle CFE and angle CBG is congruent to angle DAG. Using the fact that the opposite angles of a parallelogram are congruent, we can say that angle ABD is congruent to angle CDA and angle BCD is congruent to angle DAB.

4. If two angles of a quadrilateral are congruent, then the opposite sides of the quadrilateral are congruent.

Using step 3, we know that angle ABD is congruent to angle CDA and angle BCD is congruent to angle DAB. Therefore, we can say that AB is congruent to CD and BC is congruent to AD.

Therefore, we have proved that line AB is equal to line CD and line BC is equal to line AD in parallelogram ABCD.

To find Aliyaah's percentile, we first need to calculate her z-score: $z = \frac{x - \mu}{\sigma} = \frac{46.0 + 0.96(2.7)}{2.7} \approx 2.26$

Using a standard normal distribution table, we can find that the area to the left of $z = 2.26$ is approximately 0.988. This means that Aliyaah's height is at the 98.8th percentile.

To compare Aliyaah's height to Jayne's height, we need to find Jayne's z-score. We can use the standard normal distribution table again, this time to find the z-score that corresponds to the 93rd percentile. We find that $z \approx 1.48$.

This means that Jayne's height is 1.48 standard deviations above the mean. Since Aliyaah's height is only 0.96 standard deviations above the mean, we can conclude that Jayne is taller than Aliyaah.

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Based on the regression equation, we can predict the value of the dependent variable given a value of the independent variable.

The equation includes variables that represent the relationship between the dependent and independent variables, allowing us to estimate the dependent variable's value when provided with the independent variable's value. An equation is a mathematical expression that uses symbols and operations to represent a relationship between two or more variables.

Variables are factors that can change and affect the outcome of the equation. In a regression equation, one variable is considered the dependent variable, meaning that its value depends on the value of another variable, called the independent variable.

Regression analysis is a statistical method used to model the relationship between the dependent variable and one or more independent variables. The regression equation is the mathematical formula that represents this relationship. By inputting a specific value for the independent variable into the equation, we can predict the corresponding value of the dependent variable.

It is important to note that the regression equation only predicts the value of the dependent variable based on the values of the independent variable.

It does not necessarily imply causation between the two variables, nor does it measure the association between two variables directly. However, it can be a useful tool for analyzing data and making predictions based on that data.

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Answer: 7/40

Step-by-step explanation:

Systems (i) and (ii) are linear, while systems (iii) and (iv) are nonlinear.

A linear system satisfies the properties of superposition and homogeneity, meaning that if the input is scaled or if multiple inputs are added together, the output will also be scaled or added together accordingly. Systems (i) and (ii) are both linear since they both satisfy these properties. However, systems (iii) and (iv) are nonlinear since they do not satisfy the properties of superposition and homogeneity. System (iii) contains a non-linear term (y(t))^2 and system (iv) contains a non-linear term (u(t))^2.

The determination of whether a system is linear or nonlinear can have important implications for the analysis and control of the system. It is important to recognize the differences between these types of systems in order to effectively model and manipulate them.

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The standard parametric equations for the line passing through points P and Q is [tex]$\begin{cases} x = -6 + 2t \ y = 8 - 7t \ z = 1 + 2t \end{cases}$[/tex] .

To find the standard parametric equations for the line passing through points P(-6, 8, 1) and Q(-4, 1, 3), we first need to find the direction vector of the line. This can be done by subtracting the coordinates of point P from the coordinates of point Q:

[tex]$\vec{PQ} = \begin{pmatrix}-4 \ 1 \ 3\end{pmatrix} - \begin{pmatrix}-6 \ 8 \ 1\end{pmatrix} = \begin{pmatrix}2 \ -7 \ 2\end{pmatrix}$[/tex]

Now we can write the parametric equations in the form:

[tex]$\begin{cases} x = x_0 + at \ y = y_0 + bt \ z = z_0 + ct \end{cases}$[/tex]

where (x0, y0, z0) is a point on the line and (a, b, c) is the direction vector.

We can choose either point P or Q as the point on the line. Let's use point P. So we have:

[tex]$\begin{cases} x = -6 + 2t \ y = 8 - 7t \ z = 1 + 2t \end{cases}$[/tex]

These are the standard parametric equations for the line passing through points P and Q.

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The length of IKE is 2x - 12.

A condition on a variable that is true for just one value of the variable is called an equation.

Since KITE is a kite, we know that KT = IT and KE = IE. Let's call the length of these diagonals d. Then we have:

KT + TI = d

KE + EI = d

Substituting in the given values, we get:

x + 6 + 2x = d

2x + IE = d

Solving for d in the first equation, we get:

3x + 6 = d

Substituting this into the second equation, we get:

2x + IE = 3x + 6

Solving for IE, we get:

IE = x + 6

Therefore, IKE is equal to:

IKE = IT - IE

IKE = (d - KT) - (x + 6)

IKE = (3x + 6 - x - 6) - (x + 6)

IKE = 2x - 12

So, the length of IKE is 2x - 12.

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Answer: 0.648

Step-by-step explanation:

We can use the formula P(B|A) = P(A and B) / P(A) to find P(A and B), where P(A and B) is the probability of both A and B occurring and P(A) is the probability of A occurring.

Rearranging the formula, we get:

P(A and B) = P(B|A) * P(A)

Substituting the given values, we get:

P(A and B) = 0.8 * 0.81 = 0.648

Therefore, the value of P(A and B) is 0.648, rounded to the nearest thousandth.

Without the histograms, there's no specific region as an answer. However, you can follow these steps to determine the region with the least standard deviation in level of interest based on the provided data.

To determine the region with the least standard deviation in level of interest, we need to analyze the histograms for each region. Standard deviation is a measure of how spread out the data is. The region with the least standard deviation will have data points that are more closely clustered around the mean (average) level of interest.


1. Examine the histograms for each region.
2. Look for the region where the data points are more tightly grouped around the mean level of interest. This indicates less variability and a smaller standard deviation.
3. Identify the region with the least standard deviation in level of interest.

To determine the region with the least standard deviation in the level of interest, examine the histograms for each region and identify the one where data points are tightly clustered around the mean level. Calculate the standard deviation for each region and select the region with the smallest value, indicating a more concentrated and less variable distribution of the level of interest.

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This means that there are 10 different combinations of 3 items that we can choose from the set {A, B, C, D, E}. These combinations are:

{A, B, C}, {A, B, D}, {A, B, E}, {A, C, D}, {A, C, E}, {A, D, E}, {B, C, D}, {B, C, E}, {B, D, E}, and {C, D, E}.

The number of possible ways to select a subset of items of a given numerosity from a larger set is known as the binomial coefficient in combinatorics.

The binomial coefficient, denoted by ()(nk) or sometimes by (nk), gives the number of ways to choose k items from a set of n distinct items, without regard to their order.

The notation ()(nk) is read as "n choose k" or "the number of combinations of n things taken k at a time".

The formula for the binomial coefficient is given by the expression:

()(nk) = n! / (k!(n-k)!),

where n! (n factorial) is the product of all positive integers up to n, k! (k factorial) is the product of all positive integers up to k, and (n-k)! ((n-k) factorial) is the product of all positive integers from (n-k) up to n.

For example, if we have a set of 5 distinct items {A, B, C, D, E}, the number of ways to choose 3 items from this set, without regard to their order, is given by:

()(53) = 5! / (3!2!) = 10

This means that there are 10 different combinations of 3 items that we can choose from the set {A, B, C, D, E}. These combinations are:

{A, B, C}, {A, B, D}, {A, B, E}, {A, C, D}, {A, C, E}, {A, D, E}, {B, C, D}, {B, C, E}, {B, D, E}, and {C, D, E}.

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Answer:

77

Step-by-step explanation:

To show that every amount greater than 17 dollars can be made from a combination of 3-dollar and 10-dollar bills, we can use a technique called "proof by induction."

First, let's check the base case: can we make 18 dollars using only 3-dollar and 10-dollar bills? Yes, we can use two 3-dollar bills and one 10-dollar bill: 3 + 3 + 10 = 16.

Now, let's assume that we can make any amount greater than n dollars using only 3-dollar and 10-dollar bills. We want to prove that we can make any amount greater than n+1 dollars as well.

To do this, we can consider two cases:

1. The amount we want to make includes at least one 10-dollar bill. In this case, we can subtract 10 dollars from the amount and use our induction hypothesis to make the remaining amount using only 3-dollar and 10-dollar bills. Then we add the 10-dollar bill back in, and we have made the original amount.

2. The amount we want to make does not include any 10-dollar bills. In this case, we can use our induction hypothesis to make the amount n-7 using only 3-dollar and 10-dollar bills (since 10 - 3 = 7). Then we add a 10-dollar bill and a 3-dollar bill to get n+3, and we can add another 3-dollar bill to get n+6. Finally, we add one more 3-dollar bill to get n+9, which is greater than n+1.

Therefore, we have shown that any amount greater than 17 dollars can be made from a combination of 3-dollar and 10-dollar bills using proof by induction.

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Answer: The two numbers are x = 26 and y = 9.

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Answer:

64,339 = π(r^2)(20)

r^2 = 1,023.987

r = 32 ft

The critical value of F for a .05 significance level, with within-groups degrees of freedom of 15 and between-groups degrees of freedom of 5, is approximately 2.901.

To find the critical value of F, you need to consult an F-distribution table, which you can find in a statistics textbook or online. Using the table, locate the row corresponding to the between-groups degrees of freedom (5) and the column corresponding to the within-groups degrees of freedom (15). The intersection of this row and column will give you the critical value of F for a .05 significance level.

Remember that the critical value of F is used to determine whether there is a significant difference between group means in an analysis of variance (ANOVA) test. If your calculated F-value is greater than the critical value, you would reject the null hypothesis and conclude that there is a significant difference between the group means.

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To find all the spanning trees of a given graph, we can start by selecting any subset of its edges such that the resulting subgraph is still connected and contains all the vertices of the original graph.

We can repeat this process by removing an edge that is part of the chosen subset and adding a new edge that connects two different components of the subgraph until we have explored all possible subsets. In the case of the graph shown below, we can start by selecting any of its edges and checking if the resulting subgraph is still connected.

For example, we can choose the edge between vertices A and C and obtain the following subgraph:

    A---B
     \ /
      X
     / \
    C---D

This subgraph is a tree because it is connected and contains no cycles. We can continue the process by removing an edge and adding a new one until we have explored all possible trees. Note that some of the trees may have the same topology, i.e., they may have the same branching structure, but with different labels on the vertices or edges.

To count the number of different spanning trees, we can use the formula n^(n-2), where n is the number of vertices in the graph. In this case, n=4, so the total number of spanning trees is 4^(4-2) = 16. However, some of these trees may be isomorphic, which means they have the same topology, but with different labels on the vertices or edges.

To count the number of different spanning trees up to isomorphism, we can group them by their topology and count the number of groups. One way to do this is to label the vertices of the graph and count the number of trees that have the same branching structure, but with different vertex labels. Another way is to use the Prüfer sequence, which is a unique code that represents the topology of a tree as a sequence of integers.

Using the first method, we can label the vertices of the graph as follows:

    A---1---B
     \ /   / \
      X   2   Y
     / \ / \ /
    C---3---D

Then, we can enumerate all possible trees that have the same branching structure, but with different vertex labels:

    A---1---B      A---2---B      A---3---B      A---4---B
     \           \           \           \
      X           X           X           X
       \         / \         / \         / \
        3       1   3       2   3       3   1
       /         \ /         \ /         \ /
      C           C           C           D
                   \           \           \
                    Y           Y           Y
                     \         / \         / \
                      2       1   2       2   4

There are four different trees, one for each label of the vertex A. The other vertices can be permuted in six ways, but this does not change the topology of the tree. Therefore, there are 4 different trees up to isomorphism. Alternatively, we can use the Prüfer sequence to obtain the same result:

    A---B
     \ /
      X
     / \
    C---D

The Prüfer sequence of this tree is (2, 3, 3), which uniquely identifies its topology. We can obtain all other trees with the same Prüfer sequence by replacing the labels of the vertices as follows:

    A---C
     \ /
      X
     / \
    B---D

    A---D
     \ /
      X
     / \
    C---B

    A---B
     \ /
      X
     / \
    D---C

Therefore, there are 4 different trees up to isomorphism, as before.

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the experimental probability of the coin landing on tails is 1/3 or approximately 0.33 when expressed as a decimal when coin was flip 18 times and landed on heads 12times

In this case, the coin was flipped 18 times and landed on heads 12 times, so it landed on tails 6 times.

Therefore, the experimental probability of the coin landing on tails is 6/18, which simplifies to 1/3 or approximately 0.33.
. To calculate the experimental probability, follow these steps:

1. Determine the number of successful outcomes (times the coin landed on tails). In this case, the coin was tossed 18 times and landed on heads 12 times, so it must have landed on tails 6 times (18 - 12 = 6).

2. Determine the total number of trials (times the coin was tossed). In this case, it's 18.

3. Calculate the experimental probability by dividing the number of successful outcomes by the total number of trials:
Experimental probability of tails = (Number of tails) / (Total number of tosses) = 6 / 18

4. Simplify the fraction to get the experimental probability:
6 / 18 = 1 / 3

So, the experimental probability of the coin landing on tails is 1/3 or approximately 0.33 when expressed as a decimal.

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Noah needs 195 cups of cinnamon and 130 cups of nutmeg to make 130 pounds of spiced pecans.

Noah is not correct in claiming that he has enough spices to make 130 pounds of spiced pecans.

To begin with, let's look at the recipe Noah uses. He mixes 1/2 cup of cinnamon and 1/3 cup of nutmeg to make 1/6 cup of the spice mixture.

=>  1/3 + 1/6 = (2 +1)/ 6 = 3/6 = 1/2

So, the amount of cinnamon required would be

=> 130*(1/2) = 195 cups or 15 3/4 quarts.

Similarly, the amount of nutmeg required would be

=> 130 * 1 = 130 cups or 10 1/4 quarts.

Now, let's see if Noah has enough spices to make 130 pounds of spiced pecans. We can add the amount of cinnamon and nutmeg required, which is

=> 195 cups + 130 cups = 325 cups (or 26 quarts).

This is more than the amount of spices Noah has, which is only 2 quarts.

Therefore, Noah is not correct in claiming that he has enough spices to make 130 pounds of spiced pecans. He would need more than 12 times the amount of spices he currently has in order to make that amount.

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Convert [tex]\frac{11\pi }{12}[/tex] radians = 165 degree.

Radians and degrees are units used to measure angles in mathematics. As with any two units that are used to measure the same thing, we can convert between radians and degrees. We do this by using the fact that π radians is equal to 180°.

Now, Convert [tex]\frac{11\pi }{12}[/tex] radians to degrees.

To convert radians to degrees, multiply by [tex]\frac{180}{\pi }[/tex], since a full circle is 360° or [tex]2\pi[/tex] radians.

=> [tex](\frac{11\pi }{12}).\frac{180}{\pi }[/tex]

Cancel the common factor of 12

[tex]\frac{11}{12}.{12(15)}[/tex]

Combine 11 and 15 we get

= > 165°

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There are 2401 ways for the pirate to steal 7 items if there are at least 7 of each type of item available in the shop.

Since the pirate needs to steal 7 items and there are only 4 types of items available, he cannot just choose one type of item to steal. Instead, he needs to steal at least one item from each type of item available in the shop.

Let's consider the number of ways he can steal items from each type:

Eye patches: He needs to choose at least one eye patch, and he can choose up to 6 more, for a total of 7 possibilities.

Wooden legs: He needs to choose at least one wooden leg, and he can choose up to 6 more, for a total of 7 possibilities.

Hook hands: He needs to choose at least one hook hand, and he can choose up to 6 more, for a total of 7 possibilities.

Parrots: He needs to choose at least one parrot, and he can choose up to 6 more, for a total of 7 possibilities.

To find the total number of ways he can steal 7 items, we can multiply the number of possibilities for each type of item:

7 x 7 x 7 x 7 = 2401

Therefore, there are 2401 ways for the pirate to steal 7 items if there are at least 7 of each type of item available in the shop.

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The dimension of rectangles  with  the smallest perimeter are 2 units 2 by 5 units

The area of Rectangle is the product of its length to its width

i.e., Area of rectangle = length x width

Given:

Area of rectangle = 20 square feet

Now, Area of rectangle = length x width

length x width = 20

Now, factorize 20 as

=2 × 2 × 5

=4× 5

=20 units

So, the dimension of rectangles are 2 units 2 by 5 units.

A closed path that covers, encircles, or outlines a one-dimensional length or a two-dimensional shape is called a perimeter. A circle's or an ellipse's circumference is referred to as its perimeter. There are numerous uses in real life for perimeter calculations.

The length of a shape's outline is its perimeter. must add the lengths of all four sides of a rectangle or square to determine its perimeter. In this instance, x represents the rectangle's length and y its width.

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Answer:

Step-by-step explanation:

11 x (5 + 4x) = 55

55 + 44x = 55

44x = 55 - 55

44x = 0

x = 0

----------------

check

11 x (5 + 4 x 0) = 55

11 x 5 + 0 = 55

55 = 55

Answer / Step-by-step explanation:

So when it comes to solving equations there are cases where you can take any many different steps first. Fortunately, in this case there's only one way to approach the problem easily, and it is by applying the distributive property of multiplication in order to solve the parenthesis. Check out the attached image.

Then, using the property, we can rewrite the equation as follows:

[tex]\sf (11)(5)+(11)(4x)=55\\ \\\rightarrow55+44x=55[/tex]

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