Please help it’s geometry :(

Answer:

1/8

Step-by-step explanation:

[tex]\frac{1}{2}^3 = \frac{1^3}{2^3} = \frac{1}{8}[/tex]

Answer:

PV/nR = T

Step-by-step explanation:

PV = nRT

Divide each side by nR

PV/nR = nRT/ nR

PV/nR = T

Answer:

So we know that P*V = n*R*T im guessing

So that means that we divide it by how much we are multiplying by T aka n*R

so PV/nR = T

I am guessing that this is no physics fomula or math formula with things I dont know but if these are just random vars this is the answer.

Step-by-step explanation:

Answer:

tan 41 = 0.87

sin 63 = 0.89

cos 14 = 0.97

Step-by-step explanation:

No explanation since the question states to use the ALEKS calculator so you just make sure the calculator is in degrees then simply press tan 41 etc.

Let's start with part a, finding the maximum and minimum.

Answer a: Max temp is -5 C on day 200.  Min temp is -79 C on day 500.

Sine model.

We're looking for a model

T(n) = A sin( ωn - p ) + o

where T(n) is the estimated temperature on day n, A the amplitude of the variation, omega the radial frequency of variation, p a phase shift and o an offset, the average temperature.

Averaging min and max gives -42 C; that's the offset, what we get when the sine is zero.  o = -42 C.

That's pretty close to the value on day 0 so we'll just use a sine function without any phase shift, p = 0.

Subtracting min from max gives a total span of 74 C degrees, so a sinusoidal amplitude that's half that, A = 37 C.

From max to min is a half period, or about a half period since we're only seeing every 100 days.  That's 300 days, so a full cycle about every 600 days.

We want the argument to sine to go from 0 to 2pi as we complete a single period, 600 days,  So when n=600 this term must be 2π, so it's of the form

ωn = 2 π n / 600.

Putting it all together we get our model:

Answer b: T(n) = 37 sin(2 π n / 600) - 42

We already estimated the period at 600 days.  That's a full year.

Answer c: 600 days

We can see a full period is closer to 700 days (compare day 500 and day 1200, and also day 600 and day 1300) and the phase shift might need adjusting, but I think we pretty much did as they asked so I'll stop here.

Answer:

A, B, D, E, F

Step-by-step explanation:

No because to be a function, each dot on the graph would need to be located at its own x value. Looking at the graph you see two dots located at x = 5 so it is not a function.

Answer:d

Step-by-step explanation on ed

Answer:

771

Step-by-step explanation:

Answer:

771

Step-by-step explanation:

Answer:

(5,6), (3, 6) and (3, 5).

Step-by-step explanation:

If we imagine the line y = x to be a mirror , the image of each point is the same perpendicular distance to the mirror has the original point.

So the image of (6,5) = (5,6)

(6, 3) ---> ( 3, 6)

(5,3) ---> (3, 5).

Note that the coordinates are reversed in each case.

In this case the general rule for the reflection is  (x, y)  ---> (y, x).

Answer: $7.58/2=$3.79

Step-by-step explanation:

Answer:

Step-by-step explanation:

The discriminant is what's under the square root sign in the quadratic equation.  The equation for the discriminant is [tex]b^{2}-4ac[/tex], where b is the coefficient of x, a is the coefficient of [tex]x^{2}[/tex], and c is the number with no variable attatched to it.  If we plug in the numbers ([tex]17^{2} -4*4*3[/tex]) it gives you 241, which is the discriminant.  Since 241 is more than zero, it has 2 zeros.  If the discriminant was 0, there'd be 1 zero, and less then zero there would be zero zeros.

Answer:

[tex] \sqrt{2^{2} } * \sqrt{2^{2} } * \sqrt{2} * \sqrt{5} * \sqrt{7} * \sqrt{y^{2} } * \sqrt{y} [/tex]

[tex] 2*2*y\sqrt{2*5*7*y} [/tex]

[tex] 4y\sqrt{70y} [/tex]

Step-by-step Explanation:

To find the expressions that are equivalent to

[tex] \sqrt{1,120y^{3} } [/tex]

let's simplify each of the options given to know if we would arrive at

[tex] \sqrt{1,120y^{3} } [/tex]

Option 1:

[tex] \sqrt{2*2*2*2*5*7*y*y} [/tex]

[tex] \sqrt{(2*2*2)*(2*5)*(7)*(y*y)} [/tex]

[tex] \sqrt{8*10*7*y^{2} } [/tex]

[tex] \sqrt{560y^{2} } [/tex]

Not equivalent to the given expression.

Option 2:

[tex] \sqrt{2^{2} } * \sqrt{2^{2} } * \sqrt{2^{2} } * \sqrt{5^{2} } * \sqrt{7^{2} } * \sqrt{y^{2} } * \sqrt{y^{2} } [/tex]

[tex] 2 * 2 * 2 * 5 * 7 * y * y [/tex]

[tex] 8*5*7*y*y [/tex]

[tex] 280y^{2} [/tex]

Not equivalent to the given expression.

Option 3:

[tex] \sqrt{2^{2} } * \sqrt{2^{2} } * \sqrt{2} * \sqrt{5} * \sqrt{7} * \sqrt{y^{2} } * \sqrt{y} [/tex]

[tex] 2 * 2 * \sqrt{2} * \sqrt{5} * \sqrt{7} * y * \sqrt{y} [/tex]

[tex] 2 * 2 * y * \sqrt{2} * \sqrt{5} * \sqrt{7} * \sqrt{y} [/tex]

[tex] 4y * \sqrt{2 * 5 * 7 * y} [/tex]

[tex] \sqrt{16y^{2} } * \sqrt{70y} [/tex]

[tex] \sqrt{16 * y^{2} * 70 * y } [/tex]

[tex] \sqrt{16 * 70 * y^{2} * y } [/tex]

[tex] \sqrt{1,120y^{3} } [/tex]

This option is equivalent.

Option 4:

[tex] 2*2*y\sqrt{2*5*7*y} [/tex]

[tex] 4y\sqrt{70y} [/tex]

[tex] \sqrt{16y^{2} } * \sqrt{70y} [/tex]

[tex] \sqrt{16 * y^{2} * 70 * y } [/tex]

[tex] \sqrt{1,120y^{3} } [/tex]

This option is equivalent to the given expression.

Option 5:

[tex] 4y\sqrt{70y} [/tex]

[tex] \sqrt{16y^{2} } * \sqrt{70y} [/tex]

[tex] \sqrt{16y^{2} * 70 * y} [/tex]

[tex] \sqrt{16 * 70 * y^{2} * y} [/tex]

[tex] \sqrt{1,120y^{3} } [/tex]

Equivalent!

Options 3, 4 and 5 are the 3 expressions equivalent to

[tex] \sqrt{1,120y^{3} } [/tex]

Answer:C D E

Step-by-step explanation:

Just did the test

Answer:

2x + y^2

Step-by-step explanation:

We group the like terms, so:

x + x = 2x

y * y = y^2

_______________________________

Hey!!

Solution,

X+X+y*y

= 2x+y^2

The answer is 2x+y^2

hope it helps

Good luck on your assignment

____________________________

Answer:

13

Step-by-step explanation:

To solve this, lets first find the number of footballs he still needs:

75-24 = 51

Now to find the number of packages, divide by 4, since there are 4 balls per package:

51/4 = 12 Remainder 3

Since there is a remainder, and the Coach MUST have at least 75, then we need to add a package to include the remainder:

12 + 1 = 13 Packages

Answer:

(-2,0) and (2,0)

Step-by-step explanation:

To find the x intercepts of a graph, you need to set the y to 0. This is because a graph only intersects the x axis at the line y=0. Hence:

[tex]4x^2-16=0[/tex]

Factor:

[tex]4(x^2-4)=0 \\\\4(x-2)(x+2)=0 \\\\x=2,-2[/tex]

The x intercepts are at (-2,0) and (2,0). Hope this helps!

Answer:

The x intercepts are -2 and 2

Step-by-step explanation:

y=4x^2-16

Set equal to zero to find the x intercepts

0 =4x^2-16

Factor

0 = 4(x^2 -4)

Factor again, noticing the difference of squares ( a^2 - b^2) = (a-b)(a+b)

0 = 4(x-2) (x+2)

Using the zero product property

0 = x-2   0 = x+2

x =2          x = -2

The x intercepts are -2 and 2

Answer:

9x^2 +12x

Step-by-step explanation:

To find the area of a rectangle you need to multiply the length by the width. So,

3 by 3x^2 = 9x^2

3 by 4x = 12x

So the area of the entire rectangle is: 9x^2 + 12x

Answer:7678

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

H * 2g/w² = R² - r²

r² = R² - H * 2g/w²

r = √(R² - H * 2g/w²)

Answer:

I guess the answer is c.... I guess it must be c

Answer:

y=10x-15

Step-by-step explanation:

with the points given you know x=2 and y=5

make a new point called (x,y)

now use the formula (y-5)/(x-2)=10 (10 being the gradient)

y-5 = 10(x-2)

y-5=10x-20

add 5 to both sides

y-5+5=10x-20+5

y=10x-15

Since we're given a point and a slope, we can write

the equation of this line using the point-slope formula.

The point-slope formula is shown at the top of the image below.

The given point, (2,5), represents (x1,y1).

Now plug in the information to get the equation below.

Now you can distribute the 10.

Then add 5 to both sides.

You will end up with the equation y = 10x - 15 as your answer.

Answer: Brainliess plsssssss

The answer in this question is Alternate interior angles are congruent.

Step-by-step explanation:

Alternate interior angles are defined as when the two lines are crossed by another line which is called transversal, the pairs of angles on opposite sides of the transversal but inside the two lines are known as alternate interior angles.

Answer:

9n-5

Step-by-step explanation:

Let n=the number:

9n-5

Answer:

x = -7

Step-by-step explanation:

-5(x-1) = 40

Divide each side by -5

-5(x-1)/-5 = 40/-5

x-1 = -8

Add 1 to each side

x-1+1 = -8+1

x = -7

Answer:

x = -7

Step-by-step explanation:

-5(x-1) = 40

-5x + 5 = 40

5x - 5 = - 40

5x = 5 - 40

5x = - 35

x = -35/5

x = -7

Answer: A (3, -4)

Step-by-step explanation:

A minimum is at the lowest point on the parabola. The minimum and maximum can be seen by looking at the vertex.

If you go right 3 spaces on the x-axis horizontally, then down 4 spaces vertically on the y-axis you get (3, -4).

4 is negative because you are going down below the x-axis.

Answer:

(C) ¹/₂

Step-by-step explanation:

Given;

A standard number cube with the numbers 1 through 6 = 1, 2, 3, 4, 5, 6

The probability of rolling a number less than 4 = 3, 2, 1

The probability of rolling 3, P(3) = ¹/₆

The probability of rolling 2, P(2) = ¹/₆

The probability of rolling 1, P(1) = ¹/₆

Probability of rolling a number less than = P(3) or P(2) or P(1)

                                                                   = ¹/₆ + ¹/₆ + ¹/₆

                                                                   = ³/₆

                                                                   = ¹/₂

Therefore, the probability of rolling a number less than 4 is ¹/₂

Option (C) ¹/₂

Answer:

X=20°

Step-by-step explanation:

SinX+16°+Cos2X+14°=90

3x+30=90

3x=60

x=20°

Answer:

10 sqrt 3.

Step-by-step explanation:

sqrt30 = sqrt10 * sqrt 3

so sqrt30 * sqrt10

= sqrt10 * sqrt10 * sqrt3

= 10 sqrt 3.

Answer:d

Step-by-step explanation:

Answer:

To solve this problem, we need to write each number in two different ways, we could use percetanges or fractions.

This number can be written in scientific notation like [tex]4 \times 10^{7}[/tex], where the exponent depends on the amount of zeros the quantity has.

A second way to write this number would be as a product [tex]2 \times 20,000,000.00[/tex].

Similarly, this number can be written in scientific notation [tex]2 \times 10^{-2}[/tex], also, we can write it as a fraction [tex]\frac{2}{100}[/tex].

This number in scientific notation would be [tex]1.05 \times 10^{8}[/tex]. As a product would be

[tex]1050 \times 100000[/tex].

In scientific notation would be [tex]7 \times 10^{-9}[/tex]. As a fraction would be [tex]\frac{7}{1000000000}[/tex].

In scientific notation would be [tex]4.56983 \times 10^{5}[/tex]. Also, we can write it as a sum

[tex]450,000 + 6,983[/tex]

In scientific notation would be [tex]6.73 \times 10^{-7}[/tex]. As a fraction would be [tex]\frac{673}{1000000000}[/tex]