Empirical formula of the Cyclopropane = C[tex]H_{2}[/tex]
Molecular formula of the Cyclopropane = [tex]C_{3} H_{6}[/tex]
Cyclopropane is a cyclic compound having 3 carbon atoms in a ring.
As we know carbon is having 4 valency, that means it can form 4 bonds with other atoms.
In case of cyclopropane each carbon atom is attached with 2 carbon atoms in a ring, so 2 valency of each carbon atom is used in a ring formation.
The remaining 2 valency are satisfied by hydrogen atoms.
Here, 3 carbons are there so 6 hydrogens are used to satisfy their valency.
An empirical formula is a simple representation of ratio of the atoms present, while a molecular formula is a detailed representation of the total number of atom.
So here, carbon and hydrogen ratio is 1:2 , from this the Empirical formula of the Cyclopropane became C[tex]H_{2}[/tex]
And the molecular formula of the Cyclopropane is [tex]C_{3} H_{6}[/tex].
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In the laboratory you dissolve 12.2 g of iron(II) iodide in a volumetric flask and add water to a total volume of 500 mL.
What is the molarity of the solution?
M.
What is the concentration of the iron(II) cation?
M.
What is the concentration of the iodide anion?
M.
In the laboratory you dissolve 16.8 g of iron(III) sulfate in a volumetric flask and add water to a total volume of 250 mL.
What is the molarity of the solution?
M.
What is the concentration of the iron(III) cation?
M.
What is the concentration of the sulfate anion?
M.
You wish to make a 0.271 M hydrobromic acid solution from a stock solution of 12.0 M hydrobromic acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution?
mL
Question 1
1) The formula of iron(II) iodide is [tex]\text{FeI}_{2}[/tex] and has a formula mass of 309.654 g/mol. This means that in 12.2 grams, there are
12.2/309.654 = 0.039398812868557 mol.So, the molarity is (0.039398812868557)/(0.5) = 0.0788 M (to 3 sf)
2) In 0.039398812868557 mol of iron(II) iodide, there are 0.039398812868557 moles of iron(II) iodide cations, and thus the molarity is still 0.0788 M (to 3 sf)
3) In 0.039398812868557 mol of iron(II) iodide, there are
2(0.039398812868557) = 0.078797625737114 moles of iodide anionsThus, the molarity is (0.078797625737114)/(0.5) = 0.158 M (to 3 sf)
Question 2
1) The formula of iron(III) sulfate is [tex]\text{Fe}_{2}\text{(SO}_{4})_{3}[/tex] and has a formula mass of 399.9 g/mol. This means that in 16.8 grams, there are
16.8/399.9 = 0.042010502625656 molSo, the molarity is (0.042010502625656)/(0.25) = 0.168 M (to 3 sf)
2) In 0.042010502625656 moles of iron(III) sulfate, there are 2(0.042010502625656)=0.084021005251312 moles of iron(III) cations, so the molarity is:
0.084021005251312/0.25 = 0.336 M (to 3 sf)3) In 0.042010502625656 moles of iron(III) sulfate, there are 3(0.042010502625656)=0.12603150787697 moles of sulfate anions, so the molarity is:
0.12603150787697/0.25 = 0.504 M (to 3 sf)Question 3
Since we need 50.0 mL of solution at 0.271 M,
0.271 = (moles of HBr)/(0.05) moles of HBr = 0.01355 molSo, we need this from 12.0 M HBr so, meaning that:
12.0 = (0.01355)/(liters of 12.0 M HBr stock solution)liters of 12.0 M HBr stock solution = 0.0011291666666667 L = 1.13 M (to 3 sf)An unknown gas effuses at a rate of 2.0 times the rate of Cl₂. What is the molar mass of the unknown gas?
The molar mass of the unknown gas is determined as 17.75 g.
Rate of gas diffusionThe rate of gas diffusion is given by Graham's law.
R₁√M₁ = R₂√M₂
where;
R₁ is the rate of diffusion of the unknown gasM₁ is the molecular mass of the unknown gasR₂ is rate of diffusion of chlorine gasM₂ is the molecular mass of chlorine gas[tex]\frac{R_1}{R_2} = \sqrt{\frac{M_2}{M_1} } \\\\\frac{2R_2}{R_2} = \sqrt{\frac{71}{M_1} }\\\\2 = \sqrt{\frac{71}{M_1} }\\\\2^2 = \frac{71}{M_1} \\\\M_1 = \frac{71}{4} \\\\M_1 = 17.75 \ g[/tex]
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Calculate the standard enthalpy change associated with this reaction at 25 °C using the
following enthalpies of formation:
CH4 ∆Hf = -62.7 kJ·mol–1, CO2 ∆Hf = -393.5 kJ·mol–1, H2O ∆Hf = -285.8 kJ·mol–1.
The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ
What is Standard Enhalpy change ?The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions, and with everything in its standard state.
According to the balanced chemical equation ;
CH₄(g) + 2O₂(g) ⟶ CO₂(g) + 2H₂O(l)
Now,
ΔH⁰ = ΔH⁰f(products) − ΔH⁰f(reactants)
= [ΔH⁰(CO₂) +ΔH⁰(H₂O)] − [ΔH⁰(CH₄) + 2ΔH⁰(O₂)]
= [−393.5 + 2 x (−285.8)] − [−62.7 + 2 x 0]
= − 902.4 kJ
Hence, The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ
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Which of the following is the best example of an isolated system?
OA. A bus at a bus station
B. An astronaut in a spaceship
OC. A car on the freeway
D. A motorcycle in a garage
Answer:
B. An astronaut in a spaceship
Isolated system :-
In an isolated system, there is no transfer of energy or matter between the system and the environment.
Hope it helps!
Sunspot populations quickly rise and more slowly fall on an irregular cycle about every 11 years. Significant variations of the 11-year period are known over longer spans of time. For example, from 1900 to the 1960s the solar maxima (the period of greatest activity in the solar cycle of the sun) trend of sunspot count has been upward; from the 1960s to the present, it has diminished somewhat. The Sun is presently at a markedly heightened level of sunspot activity and was last similarly active over 8,000 years ago.
The number of sunspots correlates with the intensity of solar radiation over the period (since 1979) when satellite measurements of absolute radiative flux were available. Since sunspots are darker than the surrounding photosphere it might be expected that more sunspots would lead to less solar radiation and a decreased solar constant. However, the surrounding margins of sunspots are hotter than the average, and so are brighter; overall, more sunspots increase the sun's solar constant or brightness. During the Maunder Minimum in the 17th Century there were hardly any sunspots at all. The Maunder Minimum is the name given to the period roughly from 1645 to 1715, when sunspots became exceedingly rare, as noted by solar observers of the time. It is named after the solar astronomer Edward W. Maunder (1851-1928) who discovered the dearth of sunspots during that period by studying records from those years. During one 30-year period within the Maunder Minimum, for example, astronomers observed only about 50 sunspots, as opposed to a more typical 40,000-50,000 spots. This coincides with a period of cooling known as the Little Ice Age.
1) Which of the following is a true statement?:
A. There were more sunspots in 1965 than in 1701
B. The Little Ice Age had nothing to do with sunspots
C. The Sun is presently at a low level of sunspot activity
D. No one is counting sunspot activity any more
The Sun is presently at a low level of sunspot activity. Hence, option C is correct.
What is solar radiation?Solar radiation is often called the solar resource for the electromagnetic radiation emitted by the sun.
The Sun is presently at a low level of sunspot activity is the correct answer.
Hence, option C is correct.
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How many xenon atoms are contained in 1.00 moles of xenon?
Answer:
6.022 x 10²³
Explanation:
The number of atoms = the number of moles x with the Avogadro's number.
(The Avogadro's number is 6.022 x 10²³ atoms / moles)
number of atoms = 1.00 moles x 6.022 x 10²³ atoms / mole
number of atoms = 6.022 x 10²³ atoms
(There is no need to simplify?) = 6.022 x 10²³
(ps. This is my first time doing this question so im sorry if i got it wrong
(つ﹏⊂)
Hybridization of bromine in SF4 and arsenic in SF2
Answer:
The answer is C
Need ASAP please and thank you
The empirical formula would be [tex]C_2H_3O_2[/tex] and the molecular formula would be [tex]C_4 H_6 O_4[/tex]
Empirical and molecular formulaFrom the illustration:
C = 40.6 g H = 5.1 g O = 54.2 g
Divide each element by its molar weight:
C = 40.6/12 = 3.4 H = 5.1/1 = 5.1 O = 54.2/16 = 3.4
Divide by the smallest:
C = 3.4/3.4 = 1 H = 5.1/3.4 = 1.5 O = 3.4/3.4 = 1
Thus, the empirical formula is [tex]C_2H_3O_2[/tex]
To find the molecular formula:
[ [tex]C_2H_3O_2[/tex]]n = molecular formula
where n = molar mass/empirical formula mass
Empirical formula mass = 24 + 3 + 32 = 59
n = 118.084/59 = 2
Thus, the molecular formula is [tex]C_4 H_6 O_4[/tex] which is more or less the same as the empirical formula.
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The Empirical formula will be C₂H₃O₂ and the Molecular formula would be C₄H₆O₄
What is Empirical and Molecular Formula ?Empirical formula is a formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.
Molecular formula is a chemical formula that gives the total number of atoms of each element in each molecule of a substance.
Given ;
C = 40.6 gH = 5.1 gO = 54.2 gDivide each element by its molar weight:
C = 40.6 / 12 = 3.4H = 5.1 / 1 = 5.1 O = 54.2 / 16 = 3.4Divide by the smallest Value:
C = 3.4/3.4 = 1H = 5.1/3.4 = 1.5 O = 3.4/3.4 = 1Thus, the Empirical formula is C₂H₃O₂
Now, to find the molecular formula ;
[C₂H₃O₂ ]n = molecular formula
where n = molar mass / empirical formula mass
Empirical formula mass = 24 + 3 + 32 = 59
n = 118.084 / 59 = 2
[C₂H₃O₂ ]n = molecular formula
[C₂H₃O₂ ]2 = C₄H₆O₄
Thus, the Molecular formula is C₂H₃O₂
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Which are the product(s) of this chemical reaction? FeCl 3 + 3NH 4OH ->
a. 3NH4Fe + Cl3OH
b. 3FeCl3NH4OH
c. 3NH4Cl + 3FeOH
d. Fe(OH)3 + 3NH4Cl
Which hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine?
Correct Answer is B
Answer:
C.) Csp² - Nsp³
Explanation:
Because the carbon has only 3 unique bonds, the conformation of the carbon should be Csp² (s + p + p). While the nitrogen also has only 3 bonds, making up 3 orbitals, it also has a lone pair of electrons. These electrons also take up one orbital. Therefore, the conformation of nitrogen is Nsp³ (s + p + p + p).
The hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.
What is hybridization?Hybridization is defined as the concept of the mixing of the atomic orbitals for the formation of new hybrid orbitals which are suitable for the pairing of electrons in forming chemical bonds in valence bond theory. And the orbital formed by the hybridization are termed as hybrid orbitals.
Since the carbon atom form one single bond with hydrogen atom and one pi bond with nitrogen bond, so the conformation of carbon atom is Csp2. On the other hand, nitrogen also form one single bond and a pi bond, so it also contribute three hybrid orbital. Since it have one lone pair of nitrogen so they take one orbitals. Therefore, the conformation of nitrogen atom is Nsp3.
Thus, we concluded that the hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.
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Pure water boils at 100°C.
What happens to the water particles when water
boils?
A They gain energy and move further apart.
B They gain energy and stay close together.
C They lose energy and move further apart.
D They lose energy and stay close together.
Answer:
A
Explanation:
What information does a net ionic equation give that the complete ionic equation does not show?
A complete ionic equation shows ions formed from each of the species. It also show the charge on each of the ions.It also shows all reactants as compounds or elements. The ions formed and their charges can only be inferred from this equation.
What is a Net Ionic equation ?The net ionic equation shows the chemical species involve in chemical reaction while the complete ionic equation also involve the spectator ions.
What are Spectator ions ?These ions are same in both side of chemical reaction and thus cancels out each other.
Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
The net ionic equation state that whether precipitation is occur or not.
If the chemical reaction have no net ionic equation it means all are in aqueous from not precipitation occur.
Consider the following example:Balanced Chemical equation:
HClO₂(aq) + NaOH(aq) → H₂O(l) + NaClO₂ (aq)
Ionic equation:
H⁺(aq) + ClO₂⁻(aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + ClO₂⁻ (aq)
Net ionic equation:
H⁺(aq) + OH⁻(aq) → H₂O(l)
The ClO₂⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation.
The water can not be splitted into ions because it is present in liquid form.
Hence, The net ionic equation shows the chemical species involve in chemical reaction while the complete ionic equation also involve the spectator ions.
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We do not want all staff being able to access all records that we hold. How can you ensure traceability and accessibility to the data stored?
To ensure data traceability and accessibility is to complete a study beginning-to-end on a closed system or platform.
How can you ensure traceability and accessibility to the data stored ? Lean On Self-Service Business Intelligence. Embed Dashboards Into Your Teams' Tools. Facilitate Data Literacy Throughout the Company. Embrace Your Changing Role.Learn more about Data accessibility here ;
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The average speed of a diatomic fluorine molecule at 25 ∘C is 442.4 m⋅s−1 . What is the average wavelength of a fluorine molecule at this temperature? Assume that the molecule acts as a single particle
The average wavelength of the fluorine molecule will be 2.36 × 10⁻¹¹ metres.
Fluorine Molecule's Speed = 442.4 m/s
The Molar Mass of the F₂ = 38 g/mol
Now as we know that any molecule's
1 mole contain = 6.022 × 10²³ Molecule
So, 1 Fluorine molecule mass =
Fluorine's Molar mass / Number of Fluorine molecule in 1 mole
So, 1 Fluorine molecule mass = 38 / ( 6.022 × 10²³ )
1 Fluorine molecule mass = 6.31 × 10⁻²³ g
1 Fluorine molecule mass = 6.31 × 10⁻²⁶ Kg
So molecule's momentum = Molecule's mass × Molecule's Velocity
So molecule's momentum = ( 6.31 × 10⁻²⁶ ) × 442.4
So molecule's momentum = 2.8 × 10⁻²³ Kg.m/s
Now wavelength of Fluorine molecule = λ = planks constant / momentum
wavelength of Fluorine molecule = λ = ( 6.626 × 10⁻³⁴ ) / ( 2.8 × 10⁻²³ )
wavelength of Fluorine molecule = λ = 2.36 × 10⁻¹¹ metre
So the wavelength of the diatomic fluorine molecule came out to be 2.36 × 10⁻¹¹ metres after applying all the concepts and formulas.
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In the reaction of 675.9 grams of barium chloride and excess silver(I) nitrate, how many grams of silver(I) chloride should get formed?
i dont understand, show work pls ty
Taking into account the reaction stoichiometry, the mass of silver(I) chloride formed is 930.37 grams.
Reaction stoichiometryIn first place, the balanced reaction is:
2 AgNO₃ + BaCl₂ → 2 AgCl + Ba(NO₃)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
AgNO₃: 2 moles BaCl₂: 1 moleAgCl: 2 molesBa(NO₃)₂: 1 moleThe molar mass of the compounds is:
AgNO₃: 169.87 g/moleBaCl₂: 208.24 g/moleAgCl: 143.32 g/moleBa(NO₃)₂: 261.34 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
AgNO₃: 2 moles ×169.87 g/mole= 339.74 grams
BaCl₂: 1 mole ×208.24 g/mole= 208.24 grams
AgCl: 2 moles ×143.32 g/mole= 286.64 grams
Ba(NO₃)₂: 1 mole×261.34 g/mole= 261.34 grams
Mass of silver(I) chloride formedThe following rule of three can be applied: if by reaction stoichiometry 208.24 grams of barium chloride form 286.64 grams of silver(I) chloride, 675.9 grams of barium chloride form how much mass of silver(I) chloride?
[tex]mass of silver(I) chloride=\frac{675.9 grams of barium chloride x286.64 grams of silver(I) chloride }{208.24 grams of barium chloride}[/tex]
mass of silver(I) chloride= 930.37 grams
Finally, the mass of silver(I) chloride formed is 930.37 grams.
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AICI3 + Pb(NO3)2
I need the answer please
Answer:
2 AlCl₃ + 3 Pb(NO₃)₂ ---> 2 Al(NO₃)₃ + 3 PbCl₂
Explanation:
This is a double-displacement reaction. The general structure of these reactions are:
AB + CD ----> AD + BC
In these reactions, the cation of one molecule is swapped with the cation of another molecule. To find the products, you first need identify the charge on each ion. This is important to know so that you can balance the new molecule via subscripts.
AlCl₃ = Al³⁺ and Cl⁻
Pb(NO₃)₂ = Pb²⁺ and NO₃⁻
Therefore, one of the new products should be a combination of Al³⁺ and NO₃⁻ and the other should be Pb²⁺ and Cl⁻. An easy way to balance the charges in the new molecules is to the make the charge on the cation the subscript of the anion (and vice versa). For instance, since Pb has a +2 charge, the chlorine should have a 2 subscript.
The unbalanced equation:
AlCl₃ + Pb(NO₃)₂ ---> Al(NO₃)₃ + PbCl₂
Reactants: 1 aluminum, 3 chlorine, 1 lead, 2 nitrate
Products: 1 aluminum, 2 chlorine, 1 lead, 3 nitrate
The balanced equation:
2 AlCl₃ + 3 Pb(NO₃)₂ ---> 2 Al(NO₃)₃ + 3 PbCl₂
Reactants: 2 aluminum, 6 chlorine, 3 lead, 6 nitrate
Products: 2 aluminum, 6 chlorine, 3 lead, 6 nitrate
Na2 C6H6O7 (sodium hydrogen citrate)
Express the mass of sodium to three significant figures.
mNa =
The exact mass of one Na - atom is 22.98977 amu and thus, the weight of two sodium atoms in present in Na₂C₆H₆O₇ is 45.979539 g/mol.
What is Molar mass ?The molar mass of a substance is the mass in grams of 1 mole of the substance.
We can obtain a substance's molar mass by summing the molar masses of its component atoms.
Mass of one Na atom = 22.98977
Mass of two Na atom = 22.98977 x 2
= 45.97954
= 45.9 (up to 3 Significant figures)
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|
Dilution
A chemist makes 620. ml. of zinc nitrate • (Zn(NO3)₂) working solution by adding distilled water to 210. mL of a 4.93 M stock solution of zinc nitrate in water.
Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.
1.66 M is the concentration of the chemist's working solution.
What is molarity?Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
In this case, we have a solution of Zn(NO₃)₂.
The chemist wants to prepare a dilute solution of this reactant.
The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.
We want to know the concentration of this diluted solution.
As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:
[tex]n_1[/tex]= [tex]n_2[/tex] (1)
and we also know that:
n = M x [tex]V_2[/tex]
If we replace this expression in (1) we have:
[tex]M_1[/tex] x [tex]V_1[/tex]= [tex]M_2[/tex] x [tex]V_2[/tex]
Where 1, would be the stock solution and 2, the solution we want to prepare.
So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is [tex]M_2[/tex]:
4.93 x 210 = 620 x[tex]M_2[/tex]
[tex]M_2[/tex] = 1.66 M
This is the concentration of the solution prepared.
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I need help with this one bad
Explanation:
it applies to pressure laws
How much heat (in joules) does it take to heat 180 g of water from 24 °C to 66 °C? The heat capacity of water is 4.184 J/(g · °C). You may round your answer to the nearest 100 J
Answer:31,631.04
Explanation: multiply final temp with initial temp = 42 then multiplied by grams = 7,560 then multiplied by J = 31,631.04
Calculate the mass of pure sodium chloride will yield enough hydrogen chloride gas to tralize 25 cm² of 0.5 M potassium trioxo- bonate(IV) solution. NACI=58.5, HC1 = 36.5, K,CO, = 138)
D...
W...
m...
A student runs two experiments with a constant-volume "bomb" calorimeter
containing 1400. g of water (see sketch at right).
sam....
First, a 5.000 g tablet of benzoic acid (C6H5CO₂H) is put into the "bomb" and
burned completely in an excess of oxygen. (Benzoic acid is known to have a heat of
combustion of 26.454 kJ/g.) The temperature of the water is observed to rise from
13.00 °C to 32.28 °C over a time of 10.7 minutes.
ry Sy...
an Am...
Next, 4.900 g of ethane (C₂H6) are put into the "bomb" and similarly completely
burned in an excess of oxygen. This time the temperature of the water rises from
13.00 °C to 44.56 °C.
Use this information, and any other information you need from the ALEKS Data
resource, to answer the questions below about this reaction:
-
stirrer
Is this reaction exothermic, endothermic, or neither?
ก
thermometer
chemical reaction
"bomb"
A "bomb" calorimeter.
If you said the reaction was exothermic or endothermic, calculate the amount of heat that was
released or absorbed by the reaction in the second experiment.
2C₂H,(g) + 70₂(g) 4CO₂(g) + 6H₂O(g)
Be sure any of your answers that are calculated from measured data are rounded to the correct number of significant digits.
Note for advanced students: it's possible the student did not do these experiments sufficiently carefully, and the values you
calculate may not exactly match published values for this reaction.
exothermic
Oendothermic
neither
water
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Answer:
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a 20.0mL sample of 0.15M hydrochloric acid (HCI) is needed to neutralize a 10.0mL sample of potassium hydroxide (KOH). what is the molarity of KOH solution?
Answer: .75 M
Explanation:
How does temperature affect Keq of a reaction
In an endothermic reaction, Keq increases as the temperature increases and vice versa.
In an exothermic reaction, Keq decreases as the temperature increases and vice versa.
Keq is the equilibrium constant of a reaction. The equilibrium constant is independent of the concentrations of the reactants and productsThe only factor that the equilibrium constant depends on is the temperature of the system of reactionIn an endothermic reaction, energy is gainedSo a higher temperature is more favourable in an endothermic reactionAs a result, more products are formed at a higher temperature, leading to a higher value of KeqIn an exothermic reaction, energy is releasedSo a lower temperature is more favourable in an exothermic reactionAs a result, fewer products are formed at a higher temperature, leading to a lower value of KeqTherefore, the temperature is the only factor that affects the equilibrium constant of a reaction.
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What are the rows of the periodic table called?
A. Periods
B. Elements
C. Atoms
D. Groups
Answer:
i believe its called A. periods
M1 = 3M M2 = 1.25M V1 = V1=.125L unkown What is V2?
0.3 L is the final volume when M₁ = 3 M, V₁ = 0.125L, M₂ = 1.25M.
What is volume?The amount of space occupied by a three-dimensional figure as measured in cubic units.
Given data:
M₁ = 3 M
V₁ = 0.125L
M₂ = 1.25M
V₂ = ?
Solution:
M₁V₁ = M₂V₂
3 M × 0.125L = 1.25M × V₂
V₂ = 0.3 L
Hence, 0.3 L is the final volume.
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If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of KCI in the resulting solution?
1.199 M is the concentration of KCI in the resulting solution.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
No.of moles of KCI
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]
= 0.599 moles
Vol.of the solution,V= 500 ml
= 0.5 liter
Molarity
[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]
[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]
= 1.199 M
Hence, 1.199 M is the concentration of KCI in the resulting solution.
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1. Write the reaction rate expressions for the following reactions in terms of the disappearance of the reactants and the appearance of products: 1-(aq)+ OCI-(aq)-CI-(aq)+OI-(aq)
In terms of the disappearance of the reactants, the rate equations are R= -kd[I-]/dt and -kd[OCl-]/dt.
What is an ionic reaction?The term ionic reaction refers to the reaction that takes place between two ions. In this case, the ionic reaction is; I-(aq) + OCl-(aq) -------> Cl-(aq) + OI-(aq).
The rate equations in terms of the disappearance of the reactants is;
R= -kd[I-]/dt
And
R = -kd[OCl-]/dt
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Sort the length measurements in increasing order of magnitude from smallest to largest.
The length measurements in increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.
What is Measurement ?Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events.
Measurement is a process of determining how large or small a physical quantity is as compared to a basic reference quantity of the same kind.
Hence, Among the given length measurements, The increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.
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How many grams of hydrogen gas are produced from 2.50 mol of water?
__Ca(s) + __H2O(l) → __Ca(OH)2(aq) + __H2(g)
Answer:
2.52 g H₂
Explanation:
To find the mass of hydrogen gas, you need to (1) convert moles H₂O to moles H₂ (via mole-to-mole ratio from reaction coefficient) and then (2) convert moles H₂ to grams H₂ (via molar mass from periodic table values). When multiplying the given value by the mole-to-mole ratio, you need to use the coefficients of the balanced equation. An reaction is balanced once there is an equal amount of each element on both sides.
(Step 1)
The unbalanced equation:
Ca(s) + H₂O(l) ----> Ca(OH)₂(aq) + H₂(g)
Reactants: 1 calcium, 2 hydrogen, 1 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
The balanced equation:
1 Ca(s) + 2 H₂O(l) ----> 1 Ca(OH)₂(aq) + 1 H₂(g)
Reactants: 1 calcium, 4 hydrogen, 2 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
(Step 2)
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
(Step 3)
2.50 moles H₂O 1 mole H₂ 2.016 g
--------------------------- x ------------------------- x ---------------------- = 2.52 g H₂
2 moles H₂O 1 mole
