Plz help me find x and y on the triangle big thanks​

Answer:

Step-by-step explanation:

Everything is correct. But you forgot to add

x = 6 - square root of 26. The answer is

x = 6 + square root of 26 or

x = 6 - square root of 26

Answer:

The area is 19.63.

Step-by-step explanation:

Step-by-step explanation:

Area of a circle is

[tex]area = \pi \: r ^{2} [/tex]

area=3.14(2.5)²

19.63in²

Answer:

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

Step-by-step explanation:

Probability of a defective part:

0.04 of [tex]\frac{100}{180}[/tex], that is, coming from A.

0.05 of [tex]\frac{80}{180}[/tex], that is, coming from B. So

[tex]p = 0.04\frac{100}{180} + 0.05\frac{80}{180} = \frac{0.04*100 + 0.05*80}{180} = 0.0444[/tex]

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

Answer:

Step-by-step explanation:

A = (2)(3.14)(2)(4) + (2)(3.14)(2^2)

A = 75.36 in

Answer:

Where is the question?

Step-by-step explanation:

Python is an interpreted high-level general-purpose programming language. Python's design philosophy emphasizes code readability with its notable use of significant indentation.

Answer:

3b^2+2b-8

Step-by-step explanation:

(3b-4)(b+2)

FOIL

first:3b*b = 3b^2

outer:2*3b = 6b

inner: -4b

Last: -4*2 = -8

Add together

3b^2 +6b-4b-8

Combine like terms

3b^2+2b-8

Answer:

[tex]3b^2+2b-8[/tex]

Step-by-step explanation:

Again, we can use FOIL to expand this equation:

First: [tex]3b(b)=3b^2[/tex]

Outer: [tex]3b(2)=6b[/tex]

Inner: [tex]-4(b)=-4b[/tex]

Last: [tex]-4(2)=-8[/tex]

We can combine the b terms to get [tex]2b[/tex], and we have our answer as [tex]3b^2+2b-8[/tex]

Answer:

I think the answer is 39x, 13y

Step-by-step explanation:

point : extra points

1 : 3

y : 39

y= 39÷3

y= 13

Answer:

the answer is B ...Extreme Values

Answer:

✔ positive

✔ 1

✔ closely

✔ increases

ED2021

Im sorry I don't know the answer to the question

Answer:

85 rounded to the nearest dollar would be $1. 73 rounded to the nearest dollar would also be $1

Step-by-step explanation:

Answer:

5 and 6

Step-by-step explanation:

call them a and b, respectively

we have a*b=30 -> a=30/b

a+b=11 -> b+ 30/b=11

b=6 and a=5

Answer:

[tex]a_{n} = -64(-\frac{1}{4})^{n-1}[/tex]

it seems like the first term is -64, so lets write the formula accordingly:

a_n = a1(r)^(n-1)

where 'n' is the number of terms

a1 is the first term of the sequence

'r' is the ratio

the ratio is [tex]-\frac{1}{4}[/tex] because -64 * [tex]-\frac{1}{4}[/tex] = 16 and so on...

the explicit formula is :

[tex]a_{n}[/tex] = [tex]-64(-\frac{1}{4} )^{n-1}[/tex]

Answer:

Regular Polygons are never concave by definition.

Step-by-step explanation:

Answer:

3h33j333jj3

Step-by-step explanation:b3n3n3nn3n33

X1=-2 and x2=1

You would just need to plug the first y equation value into the 2nd equation to get what I got in the photo. Then solve for the x’s to get the coordinates.

Answer:

11

Step-by-step explanation:

Unknown number = x

If twice the difference of x and 8 is 6:

2(x-8) = 6

2x-16 = 6

2x = 6 + 16

2x = 22

x = 22/2

x = 11

Answer from Gauthmath

Answer:

50

Step-by-step explanation:

Sum Even numbers

n = 50

d = 2

a1 = 2

The last number is

an = a1 + (n-1)d

an = 2 + (50 - 1)*2

an = 2 + 49 * 2

an = 2 + 98

an = 100

Sum of the even numbers

Sum = (a1 + a50)*n/ 2

Sum = (2 + 100)*50/2

sum = 102 * 25

sum = 2550

Sum of the first 50 odd numbers

a1 = 1

n = 50

d = 2

l = ?

Find l

l = a1 + (n - 1)*2

l = 1 + 49*2

l = 99

Sum

Sum = (1 + 99)*50/2

Sum = 2500

The difference and answer is 2550 - 2500  = 50

Answer: 4 13/30 cups

Step-by-step explanation:

Since Lila used 1 2/5 times as much lemonade as Naomi did (3 1/6 cups), we have to multiply 1 2/5 by 3 1/6:

1 2/5 ⋅ 3 1/6 = ?

19/6 ⋅ 7/5 = 133/30

133/30 = 4 13/30

4 13/30 cups

Step 1: Solve for one variable

---I will be using the first equation and solving for a.

a + c = 405

a = 405 - c

Step 2: Substitute into the other equation

---Now that we have a value for a, we can substitute that value into the second equation. Then, we can solve for c.

12a + 5c = 3950

12(405 - c) + 5c = 3950

4860 - 12c + 5c = 3950

-12c + 5c = -910

-7c = -910

c = 130

Step 3: Plug back into the first equation

---We now know one variable, which means we can plug back into our first equation and solve for the other.

a = 405 - c

a = 405 - 130

a = 275

Answer: 275 adults, 130 children

Hope this helps!

Answer:

Range: {-1, 0, 5/7, 4/5, 1, 2}

Step-by-step explanation:

We know that:

f(x) = (x + 1)/(2x - 1)

And:

f: A ⇒ B

where:

A={-1,0,1,2,3,4}

B= {-1,0,4/5,5/7,1,2,3,}

We want to find the range of f(x).

The range of f(x) will be the set of the outputs of f(x) (and because f goes from A to B, we will only take the outputs that belong to B).

Then we only need to evaluate all the values of A in f(x), and see if the output belongs to B.

we have:

f(x) = (x + 1)/(2x - 1)

f(-1) = (-1 + 1)/(2*-1 - 1) = 0   (this does belong to B)

f(0) = (0 + 1)/(2*0 - 1) = -1  (this does belong to B)

f(1) = (1 + 1)/(2*1 - 1) = 2  (this does belong to B)

f(2) = (2 + 1)/(2*2 - 1) = 1 (this does belong to B)

f(3) = (3 + 1)/(2*3 - 1) = 4/5  (this does belong to B)

f(4) = (4 + 1)/(2*4 - 1) = 5/7  (this does belong to B)

So the range of f(x) is the set with all these outputs, which is:

Range: {-1, 0, 5/7, 4/5, 1, 2}

If y = x + 6√(x + 4), then

y' = 1 + 3/√(x + 4)

Substituting y and y' into the DE gives

(y - x) y' = (x + 6√(x + 4) - x) (1 + 3/√(x + 4))

… = 6√(x + 4) (1 + 3/√(x + 4))

… = 6√(x + 4) + 18

on the left side, while on the right you get

y - x + 18 = x + 6√(x + 4) - x + 18

… = 6√(x + 4) + 18

so both sides match and the given function is indeed a solution to the DE.

Answer:

Step-by-step explanation:

The position function for this is:

[tex]s(t)=-16t^2+88t+9[/tex]. We can use this equation to find the position (or height) of the rocket at ANY TIME during its flight. I could find out the height of the rocket at 3 seconds by plugging in a 3 for t and solving for s(t); I could find the height of the rocket at 12 seconds by plugging in a 12 for t and solving for s(t), etc.

The first derivative of position is velocity:

v(t) = -32t + 88.

If we are looking for the time the rocket reaches it max height, we need to remember from physics class that this happens when the velocity of the object is at 0. We set the velocity equation equal to 0 then and solve for t:

0 = -32t + 88 and

-88 = -32t so

t = 2.75 seconds. This means that 2.75 seconds after the rocket is launched, it reaches its max height. In order to find what that max height is we plug 2.75 into the position equation for t and solve:

[tex]s(2.75)=-16(2.75)^2+88(2.75)+9[/tex] to get that

s(2.75) = 130

The max height is 130 feet and it reaches this point at 2.75 seconds into its motion.

9514 1404 393

Answer:

  (1, -3)

Step-by-step explanation:

The point P that partitions AB into the ratio m:n is ...

  P = (mB +nA)/(m+n)

The point you're looking for is ...

  P = (3(3, -9) +2(-2, 6))/(3+2) = (9-4, -27+12)/5 = (5, -15)/5

  P = (1, -3)

Answer:

D. 3

Step-by-step explanation:

A triangle can be defined as a two-dimensional shape that comprises three (3) sides, three (3) vertices and three (3) angles.

Simply stated, any polygon with three (3) lengths of sides is a triangle.

In Geometry, a triangle is considered to be the most important shape.

Generally, there are three (3) main types of triangle based on the length of their sides and these include;

I. Equilateral triangle: it has all of its three (3) sides and interior angles equal.

II. Isosceles triangle: it has two (2) of its sides equal in length and two (2) equal angles.

III. Scalene triangle: it has all of its three (3) sides and interior angles different in length and size respectively.

In Geometry, an acute angle can be defined as any angle that has its size less than ninety (90) degrees.

Hence, we can deduce that the greatest number of acute angles that a triangle can contain is three (3) because the sum of all the interior angles of a triangle is 180 degrees.

The sine curve equation, y = 10·sin(x·π/24), that models the entrance of the

tunnel with a cross section that is the shape of half of a sine curve and the

height of the tunnel at the edge of the road, (approximately 7.07 ft.) are

found by applying the following steps

(a) The equation for the sine curve is y = 10·sin(x·π/24)

(b) The height of the tunnel at the edge of the road is approximately 7.07 feet

The reason for the above answers are presented as follows;

(a) From a similar question posted online, the missing part of the question

is, what is the height of the tunnel at the edge of the road

The known parameters;

The shape of the tunnel = One-half sine curve cycle

The height of the road at its highest point = 10 ft.

The opening of the tunnel at road level = 24 ft.

The unknown parameter;

The equation of the sine curve that fits the opening

Method;

Model the sine curve equation of the tunnel using the general equation of a sine curve;

The general equation of a sine curve is y = A·sin(B·(x - C) + D

Where;

y = The height at point x

A = The amplitude = The distance from the centerline of the sine wave to the top of a crest

Therefore;

The amplitude, A = The height of half the sine wave = The height of the tunnel = 10 ft.

D = 0, C = 0 (The origin, (0, 0) is on the left end, which is the central line)

The period is the distance between successive points where the curve passes through the center line while rising to a crest

Therefore

The period, T = 2·π/B = 2 × Opening at the road level = 2 × 24 ft. = 48 ft.

T = 48 ft.

We get;

48 = 2·π/B

B = 2·π/48 = π/24

By plugging in the values for A, B, C, and D, we get;

y = 10·sin((π/24)·(x - 0) + 0 = 10·sin(x·π/24)

The equation of the sine curve that fits the opening is y = 10·sin(x·π/24)

(b) The height of the tunnel at the edge of the road is given by substituting

the value of x at the edge of the road into the equation for the sine curve

as  follows;

The width of the shoulders = 6 feet

∴ At the edge of the road, x = 0 + 6ft = 6 ft., and 6 ft. + 12 ft. = 18 ft.

Therefore, we get;

y = 10 × sin(6·π/24) = 10 × sin(π/4) = 5×√2

y = 10 × sin(18·π/24) = 10 × sin(3·π/4) = 5×√2

The height of the, y, tunnel at the edge of the road where, x = 6, and 18 is y = 5·√2 feet ≈ 7.07 ft.

Learn more about the sine curve here;

https://brainly.com/question/3827606

If x = -1, you have

2(-1) + 3 cos(-1) + e ⁻¹ ≈ -0.0112136 < 0

and if x = 0, you have

2(0) + 3 cos(0) + e ⁰ = 4 > 0

The function f(x) = 2x + 3 cos(x) + eˣ is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < c < 0 such that f(c) = 0.

9514 1404 393

Explanation:

A cone is a 3-dimensional object created by revolving a line about an axis that intersects that line. This figure is a "double-napped" cone. The point where the revolved line and the axis meet is the a.pex, or vertex, of the cone. Typically, we're concerned with a finite portion of the cone, from the vertex to a base that is a circle in a plane perpendicular to the axis.

A "conic" is a 2-dimensional figure that results from the intersection of a plane and a cone. There are four general categories, named according to the angle the plane makes with the axis and/or the side of the cone. These are illustrated in the attachment.

Producing these at home can be an interesting project. A circle can be made using a compass.

An ellipse can be drawn using a pair of pins and a loop of string. The pins would be placed at the foci of the ellipse, and the string would constrain the drawing instrument (pen or pencil) to have a constant total distance to the two foci.

A parabola can be drawn on graph paper using coordinates derived from an equation for it. It can also be drawn using a compass and a set square by plotting points that are equidistant from the focus and a line that is called the directrix. If you have a physical cone-shaped object, you can cut it at an angle that will produce a parabola.

A hyperbola can be drawn on graph paper from an equation. It can also be drawn using a compass by plotting points that have a constant difference in their distance to the two foci, or by plotting points whose ratio of distance to focus and directrix is a constant. A physical cone-shaped object can be cut to produce a hyperbola.

__

The general form equation for a conic is ...

  Ax² +Bxy +Cy² +Dx +Ey +F = 0

Usually, we're concerned with conics that have axes parallel to the coordinate axes, so B=0. The equation of an ellipse has A and C with the same sign. The equation of a hyperbola has A and C with opposite signs,

In standard form, the equations for figures centered at the origin are ...

__

The vertex of a conic is an extreme point on the (major) axis of the conic. The focus is a point used in the definition of the conic. The focus is "inside" the curve, on the axis of symmetry. The directrix is a line used in the definition of the conic. The directrix is "outside" the curve, perpendicular to the axis. The second attachment shows these for a parabola.