The value of R is 2.5 or (5/2) . We can find the answer by using concepts of slope of line.
What is the slope of a line?
Slope of a line measures its steepness . Mathematically, its calculated as "rise over run".
When two points are given,
Slope of a line = (y2 - y1)/(x2 - x1)
Here, y2 = R
y1 = 1
x2 = 7
x1 = 9
Slope of a line = (R-1)/(7-9)
In the que, its given slope = -3/4
So, (R-1)/(-2) = -3/4
R = 5/2 or 2.5
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what is 6845.86 rounded to the nearest cent?
Answer: 6,845.9, or to whole number 6,846
Step-by-step explanation:
which option describes a situation in which reduction occurs
The option which describes a situation in which reduction occurs Cl2 becoming Cl–. (Option B)
Reduction refers to the type of chemical reactions in which the number of electrons in an atom, or a group of atoms increases. The electrons taken up by the substance reduced are supplied by another substance, which is thereby oxidized. Hence, oxidation is the loss of electrons or an increase in the oxidation state, while reduction is the gain of electrons or a decrease in the oxidation state. In the given situation, Cl2 becoming Cl- represents reduction as the oxidation state is decreased from 0 to -1.
Note: The question is incomplete. The complete question probably is: Which option describes a situation in which reduction occurs? A) S2– becoming S. B) Cl2 becoming Cl–. C) Al becoming Al3+. D) Xe2+ becoming Xe6+.
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Match each of the following planar vector fields with the corresponding plot. Note that the vectors are scaled to avoid overlap. A
nswer Bank F(x, y)=(8,8) F(x, y)=(8,0) F(x, y)=(0,8) F(x, y)=(-8,0)
The vector are quantity that has both magnitude and direction. they are normally visualized in graph.
A vector - values function F : R² ---> R² can be visualized as a vector field. At a point (x,y) , we plot a value of F(x,y) as a vector with the tail anchored as (x,y)
If we visualize the vector field it will look like an explosion emanating from the origin.
At each point (x,y) , the vector F(x,y) points precisely away from the origin.
If you drew the arrows to scale they would be as long as the distance to the origin but again the drawn arrows are shorter than the actual values of the vector field
The graph of a vector field is created by pointing arrows one at a time of substituting points into the plane to determine what error to draw at the point
The question is incomplete so, I have answered in general
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help meeeeeeeeeeeeee pleaseeeeeeeeeeeeeeeeeeeeeeeeee
Factor: 5x2 – 15x – 20.
Answer:
=5x2-(20-5)x-20
=5x2-20x+5x-20
=5x(x-4)+5(x-4)
=(x-4)(5x+5)
Answer:-5(2+3x)
Step-by-step explanation:
answer the question posed in part (c) for a confidence level of 74%. (round your answer to two decimal places.)
The Z-value posted in part(c) for a confidence level of 74% is 1.150
The Confidence level in statistics denotes the likelihood that an estimate of the location of a statistical parameter (such as an arithmetic mean) in a sample survey will also hold true for the population.
Confidence levels must be determined before conducting a survey since they affect the poll's margin of error and necessary coverage. 90, 95, and 99% confidence intervals are widely employed in surveys.
A calculated statistic that was based on a sample would also be true for the entire population, within the established confidence level, with a 95% likelihood, if the confidence level were set at 95%.
Every confidence level has different z-value
In the question, We have to write the Z-value of 74% which is 1.15
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A group of campers and one group leader left a campsite in a canoe. They traveled at an average rate of 10 km/h. Two hours later, the other group leader left the campsite in a motorboat. He traveled at an average rate of 22 km/h.A. How long after the canoe left the campsite did the motorboat catch up with it?B. How long did the motorboat travel?
A .The canoe left the campsite did the motorboat catch up with it 3 hrs and 40 minutes
B . The motorboat travel at 1 hr 40 minutes
A group of campers and one group leader left a campsite in a canoe.
They traveled at an average rate of 10 km/h.
1st Group DATA:
rate = 10 km/h ; distance = x km ; time = d/r = x/10 hrs
Two hours later, the other group leader left the campsite in a motorboat.
He traveled at an average rate of 22 km/h.
Group Leader DATA:
rate = 22 km/h ; distance = x km ; time = d/r = x/22 hrs
A. How long after the canoe left the campsite did the motorboat catch up with it?
Group time - Leader time = 2 hr
x/10 - x/22 = 2
Multiply thru by 110 to get:
11x - 5x = 220
6x = 220
x = 110/3 = km
canoe total time = x/10 = (110/3)/(10) = 11/3 = 3 hrs and 40 minutes
B. How long did the motorboat travel?
motorboat time = x/22 = (110/3)/22 = 1 hr 40 minutes
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Bruce says that if a number is a product of 6, then it is not a product of 3. What would you say to Bruce?
Bruce can be advised to correct his reasoning as the number divisible by six will also remain divisible to 3.
How to find the factors of a number?The factor of a number is any number that divides it completely.
In order to find the factors of a number keep dividing it with the known factors.
Given that,
A number is product of 6.
Then, 6 is the factor of that number.
But the factors of 6 are 2 and 3 which implies that 3 is also a factor of that number.
It implies that Bruce has not applied the correct reasoning to reach the conclusion.
Hence, a number which is a product of 6 can also be a product of 3.
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1. Select all expressions that are equivalent to 8 +16i.
(A.) 2(4 + 8)
(B.) 2i(8-4)
4(21-4)
4i(4-21)
(E.) -2i(-8-4i)
The equivalent expression for the given expression is -2i(-8+4i).
What is an equivalent expression?Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.
The given expression is 8 +16i.
The given expression can be written as 8(1+2i)
-2i(-8+4i)
= -2i×(-8)-(-2i)×4i
= 16i-8i²
= 16i-8(-1)
= 8+16i
Therefore, the equivalent expression is -2i(-8+4i).
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Evaluate the integral ∫∫∫Dxyz dV, where D is the region bounded below by xy-plane and above by the hemisphere z=√9−x2−y2.
Refer to the photos taken.
Find the slope of the question below
A police officer claims that the proportion of accidents that occur in the daytime (versus nighttime) at a certain intersection
is not 35% To test this claim, a random sample of 500 accidents at this intersection was examined from police records it is
determined that 156 accidents occurred in the daytime.
The following is the setup for this hypothesis test:
HOD=0.35
Hkpl 0.35
।
Find the p-value for this hypothesis test for a proportion and round your answer to 3 decimal places.
The following table can be utilized which provides areas under the Standard Normal Curve
-1.6
1.S
0.036
0.045
0.055
0.01
9900
0.034
0.081 0.079 0.078
0.042
0.04
0.026 0.026
0.033
0.041
1500
0.063 0.062
0.075
1900
90'0
0.031
0.039
0.048
0.059
0.07
0.08
0.024
0.024
0.031
0.030
0.038 0.038
0.046
0.057
0.069
0.058
0.071
0.09
0.023
0.029
0.037
0.046
0.056
E
The p-value of the hypothesis test in this problem is given as follows:
0.075.
How to calculate the p-value of the test?The first step in calculating the p-value of the test is obtaining the test statistic, which is given by the equation presented as follows:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which the parameters are defined as follows:
[tex]\overline{p}[/tex] is the sample proportion.p is the proportion tested at the null hypothesis.n is the sample size.The values of these parameters in this problem are given as follows:
[tex]p = 0.35, n = 500, \overline{p} = \frac{156}{500} = 0.312[/tex]
Hence the test statistic is of:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.312 - 0.35}{\sqrt{\frac{0.35(0.65)}{500}}}[/tex]
z = -1.78.
Now we have to consider that we have a two-tailed test, as we are testing if the mean is different of a value.
Using a z-distribution calculator, with a two-tailed test and z = -1.78, the p-value of the test is given as follows:
0.075.
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FILL IN THE BLANK. before employing inferential statistics, alberto selects the probability level required for statistical significance. this level is referred to as the___\of the test.
Alberto chooses the probability threshold needed for statistical significance and then use inferential statistics. This level layer is described known as the test's significance level.
The significance level refers to the threshold at which one may agree that an event was statistically significant.
To evaluate statistical significance, researchers utilize a measurement called the p-value: whereas if the p-value was lower than the significance level, the result is considered statistically significant. The implies as well as standard deviations of both the data samples determine the p-value.
The confidence level would be the inverse of the significance level and is computed as 1 minus the significance level.
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4. Are these two functions inverses of each other?
g(x)=1/4 x
f(x)= 4x
Answer:
Yes
Step-by-step explanation:
g(x) = 1/4 x
g(x) = x/4
f(x) = 4x
If you plugin f(x) in g(x) and g(x) into f(x), you should get x:
f(g(x))=
4(g(x)= => plugin g(x) for x in f(x)
4(x/4)=
4*x/4=x √
g(f(x))=
f(x)/4= ==> plugin f(x) for x in g(x)
4x/4 = x√
Hence, f(x) and g(x) are inverse of each other.
Which equation is represented by the graph below?
Answer:
(4,2) may be the answer
I guess!!
The article also reported that for a sample of 36 individuals who had taken quetiapine, the sample mean cholesterol level change and estimated standard error were 9.06 and 4.256, respectively. Make any necessary assumptions about the distribution of change in cholesterol level, test the hypothesis that the true average cholesterol level increases. Givens: State the appropriate hypotheses. (Use μD = μafter − μbefore.) H0: μD = 0 Ha: μD > 0 t value= 2.1 or 2.128759398 unrounded p value=? Identify the significance levels at which there is sufficient evidence to reject H0. (Choose all that apply.) ? = 0.1 ? = 0.05 ? = 0.01 ? = 0.001 For the sample of 45 individuals who had taken olanzapine, the article reported (7.520, 9.830) as a 95% CI for true average weight gain (kg). What is a 99% CI? (Round your answers to three decimal places.
P-value is equal to 0.0206 and the significance levels at which there is sufficient evidence to reject H0 are at = 0.05 and [tex]\alpha[/tex]=0.1 and value of 99% CI = 7.132, 10.218.
Here we have,
n= 36
e= 9.06
S.E. = 4.256
Hypothesis
H0: μD = 0
Ha: μD > 0
This a right-tailed test
Test statistics,
t = 2.12
P-value at t= 2.12 and degree of freedom(df) = n-1 =36-1 = 35
P-value = t-dist(t, df, tails)
= t-dist(2.12, 35, L)
= 0.020585
= 0.0206 Round to 4 decimals
If pvalue>[tex]\alpha[/tex], then we reject the null hypothesis.
So, [tex]\alpha[/tex]= 0.05 and [tex]\alpha[/tex]=0.1 we reject the H0.
For sample of n=45 df will be= 45 -1 =44
t0.025 = 2.015
Mean weight = (7.520 + 9.830)/2 = 8.675
Margin of error = 9.830 - 8.675 = 1.155
SE = 1.155/2.015 = 0.573
99%tc = 2.692
Margin of error = 2.692 x 0.573 = 1.543
99% CI = 8.675 ± 1.543
= 7.132, 10.218
99% CI = 7.132, 10.218.
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Tommy made s sandwiches for them to eat when they get hungry. Tommy put 3 slices of turkey and 3 slices of ham on each sandwich.
Pick all the expressions that represent how many slices of meat Tommy used on the sandwiches.
Answer:
Step-by-step explanation:het
The owner of a football team claims that the average attendance for games is 67,800, he therefore justified in moving the team to a city with a larger stadium.
express the null hypothesis in symbolic form- use the correct symbol for indicated parameter
The null hypothesis is H0: μ ≤ 68,800 for the given case of The owner of a football team claiming that the average attendance for games is 67,800.
Since we know that a null hypothesis (H0) shows that no significant variation exists between variables in other words it can be said that a single variable is much not different than its mean. since from the above case we were given the information that The owner of a football team claims that the average attendance for games is 67,800. So, the null hypothesis the that the average attendance at games is less than or equal to 68,800.
H0: μ ≤ 68,800
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the function relates the length of a skid mark measured in feet at an accident scene to the speed of the car in miles per hour. that means an accident reconstructionist can measure the length of a skid mark and find the speed the car was traveling. if a skid mark with a length of 82.5 ft was found, find the speed of the car. round your answer to the nearest tenth.
If a skid mark with a length of 82.5 feet was found, then the speed of the car is 13.59 miles per hour
The function is
l(s) = 0.46s^2 - 0.199s + 0.264
Where l is the length of a skid mark measured in feet at an accident scene
s is the speed of the car in miles per hour
Given that the skid mark length = 82.5 feet
Then the equation will be
0.46s^2 - 0.199s + 0.264 = 82.5
Rearrange the terms
0.46s^2 - 0.199s + 0.264 - 82.5 = 0
0.46s^2 - 0.199s - 82.236 = 0
Use the quadratic equation
= [tex]\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]
Substitute the values in the equation
= [tex]\frac{0.199+/-\sqrt{(-0.199)^2-4(0.46)(-82.236)} }{2(0.46)}[/tex]
= (0.199 ± 12.30) / 0.92
Then
(0.199 + 12.30) / 0.92 = 13.59
(0.199 - 12.30) / 0.92 = -13.15
Therefore, the speed of the car is 13.59 miles per hour
The complete question is:
The function l(s) = 0.46s^2 - 0.199s + 0.264 relates the length of a skid mark measured in feet at an accident scene to the speed of the car in miles per hour. that means an accident reconstructionist can measure the length of a skid mark and find the speed the car was traveling. if a skid mark with a length of 82.5 ft was found, find the speed of the car. round your answer to the nearest tenth.
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The temperature cooled by 4° on the first day of the year together on the 1st 2 days of the year the temperature heated up 7°
Answer:
Hi, are you missing part of this question?
The temperature on the second day is 11°.
How to calculate the temperature?Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both.
Let the temperature on the second day be x.
Based on the information, temperature cooled by 4° on the first day of the year together on the 1st 2 days of the year the temperature heated up.
-4 + x = 7
Collect the like terms
x = 7 + 4..
x = 11
The temperature is 11°
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The temperature cooled by 4° on the first day of the year together on the 1st 2 days of the year the temperature heated up 7°. What is the Temperature on tue second day?
On January 1, a nasty species of algae is mistakenly introduced into Lake Skinner. It grows in such a way that it doubles every day. If it continues to grow like this, the lake will be totally covered and the fish in the lake will suffocate. At the rate it is growing, this will happen on January 30.
1). When will Lake Skinner be covered halfway?
2). On January 26, you convince your friend that the lake will be completely covered soon. Your friend laughs. Why is your friend skeptical?
3). One January 29 a cleanup crew arrives and is able to remove most of the algae. When they are done on February 1, only 1 % of the surface is covered. How well does this solve the problem in Lake Skinner?
Answer: If the algae in Lake Skinner doubles every day, then on the 15th day (halfway between the 1st and 30th) the lake will be covered halfway.
If the algae doubles every day, then on January 26 it would have only doubled six times, meaning it would only cover 1/64 of the lake's surface. This is why your friend may be skeptical that the lake will be completely covered soon.
The cleanup crew's efforts on January 29 were able to remove most of the algae, but by February 1 only 1% of the lake's surface was still covered. This means that while the problem has been greatly reduced, it is not completely solved and there may still be some risks to the fish in the lake. Continued monitoring and efforts to prevent future algae blooms may be necessary to fully protect Lake Skinner.
Step-by-step explanation:
If the translation T maps point A(-3,1) onto point A'(5,5), what is he translation T?
Answer: Translation T = (x + 8, y + 4)
Step-by-step explanation:
The x coordinate moved to the right by 8 and the y coordinate moved up by 4.
Find the probability that when a couple has six children, at least one of them is a boy. (Assume that boys and girls are equally likely.)
The probability of having a boy when a couple has six children is 63 / 64.
What is probability?The ratio of good outcomes to all possible outcomes of an event is known as probability. A lot of successful results for an experimental with 'n' results can be represented by the symbol x.
Given:
A couple has six children, n = 6
The wanted event, p = 1 / 2
Calculate the probability of having a boy given by the following formula,
[tex]P(X) = nC_x px (1-p)n-x[/tex]
Here, [tex]X[/tex] = number of boys,
So,
P(X >= x) = 1 - P(X = 0)
P (X) = 1 - 6C₀ × (1 / 2) 0 × (1/2) 6
P (X) = 63 / 64
Therefore, the probability of having a boy when a couple has six children is 63 / 64.
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How do you figure out the slope of a line
Answer:
m = [tex]\frac{rise}{run}[/tex]
Step-by-step explanation:
1. take any two points on the line
2. figure out the vertical change between both points, known as the rise
3. figure out the horizontal change between both points, known as the run
4. slope is defined as the variable m and is the [tex]\frac{rise}{run}[/tex]
HELPPPPP IM ON MY QUIZ
Answer:
10mph
keeping it short so you can ace your quiz :D
if this helps you, it would help me a lot if you could mark this as brainliest :)
The median size of a new single-family house built in the United States between 1987 and 2001 can be modeled by the equation H(x) = 0.359x3 − 15.198x2 + 221.738x + 862.514 square feet where x is the number of years after 1980. † (a) Determine the time between 1987 and 2001 when the median house size was increasing least rapidly. (Round your answer to the nearest year.) Find the corresponding house size. (Round your answer to the nearest whole number.) square ft Find the corresponding rate of change in house size. (Round your answer to one decimal place.) square feet per year (c) Determine the time between 1987 and 2001 when the median house size was increasing most rapidly.
PLEASE SHOW WORK!
As per the given question the median size of a new house and the values of different parts of the question will be as follows:
(a) We must locate the period when the rate of change is the smallest in order to establish the period during which the median house size increased the least quickly. Finding the derivative of the following equation will provide us with the rate of change of the house size with respect to time, which we can utilize to do this.
derivative of the function H(x) = 0.359x3 - 15.198x2 + 221.738x + 862.514 given by the equation for the rate of change of the house size with respect to time as
H'(x) = 3 (0.359) x2 - 2 (15.198) x + 221.738
(b) By setting the derivative to 0 and figuring out x, we may determine the moment at which the rate of change is the least. We have x = 3.904 as a result. The time where the rate of change is the smallest is 3.904 years after 1980, or 1984.904, because x denotes the number of years after 1980. This roughly corresponds to 1984, making 1984 the year in which the median house size increased at the slowest rate.
We may enter the value of x into the previous equation to obtain H(1984) = 0.359 x [tex](1984)^{3}[/tex] - 15.198 x [tex](1984)^{2}[/tex] + 221.738 ( 984) + 862.514
= 2,532,358 sq ft. as the comparable house size at this time. In 1984, this was the size of the typical home.
We may enter the value of x into the derivative equation to obtain H'(1984) = 3 (0.359) x [tex](1984)^{2}[/tex] - 2 (15.198 x 1984 + 221.738) = 606.696 sq ft per year, which corresponds to the rate of growth in house size. This represents the median house size's rate of change during the slowest period of growth.
(c) The biggest rate of change must be found in order to pinpoint the period in which the median house size increased most quickly. Finding the derivative equation's greatest value will help us do this. To accomplish this, one can solve for x while setting the derivative equal to 0, then determine the values of x that are either more or less than the answers we obtained. The derivative equation can then be used to solve for the maximum value using these x values.
Using the quadratic formula to solve for x. The quadratic formula is given by x = [tex]\frac{(-b ± √(b^2 - 4ac))}{2a}[/tex], where a, b, and c are the coefficients of the quadratic equation. Here, a = 3 (0.359) = 1.077, b = -2 (15.198) = -30.396, and c = 221.738. Putting these values into the quadratic formula gives us x = [tex]\frac{(30.396 ± √(30.396^2 - 4 (1.077 X 221.738))}{2 (1.077)}[/tex]
= [tex]\frac{(30.396 ± √(928.822 - 948.512))}{2.154}[/tex]
= [tex]\frac{(30.396 ± √(-19.690))}{2.154}[/tex]
= [tex]\frac{15.198}{2.154}[/tex]
= 7.096.
The derivative equation will have a maximum or lowest value at the value of x that we just discovered because it is a quadratic. We can enter this value of x into the derivative equation to obtain H'(7.096) = 3 x 0 and use this result to determine the derivative equation's maximum value.
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A mining company owns two mines. These mines produce an ore that can be graded into two classes: regular grade and low grade. The company must produce at least 350 tons of regular-grade and 610 tons of low-grade ore per week. The first mine produces 5 tons of regular-grade and 17 tons of low-grade ore per hour. The second mine produces 20 tons of regular-grade and 10 tons of low-grade ore per hour. The operating cost of the first mine is $7000 per hour, and the operating cost of the second mine is $29,000 per hour. The first mine can be operated no more than 54 hours a week, and the second mine can be operated no more than 27 hours a week. How many hours per week should each mine be operated to minimize the cost?
The number of hours to operate the mines to minimize cost are Mine 1 hour = 30 hours and Mine 2 hour = 10 hours
How to determine the number of hours?The given parameters can be represented using the following table of values
Mine 1 (x) Mine 2 (y) Available
Regular grade 5 20 350
Low grade 17 10 610
Operating cost 7000 29000
Time 54 27
From the table, we understand that we are to minimize cost
This means that:
Objective function: C = 7000x + 29000y
Subject to:
5x + 20y ≥ 350
17x + 10y ≥ 610
Next, we plot the constraints on a graph (see attachment)
From the graph, we have
(x, y) = (30, 10)
This means that
Mine 1 hour = 30 hours
Mine 2 hour = 10 hours
Hence, the number of hours are 30 and 10 hours
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Raquel is playing a game where she throws a ball that paper called a trash ball into her trashcan the diameter of the top of the trashcan is 20 inches Raquel once the trash ball to have a diameter that is 1/4 the diameter of the top of the trashcan what should the timing of Raquel trash Be?
The diameter of the top of the trash ball is 5 inch.
What is a diameter?The diameter is the distance along the circle's center that must travel in order to touch two points on its periphery.
solution:
Given that the diameter of top of the trash can is 20 inch.
And the diameter of trash ball is 1/4th of the diameter of trash can.
The diameter of trash ball = 1/4 ( the diameter of trash can )
The diameter of trash ball = 1/4 (20 inch)
The diameter of trash ball = 20/4
The diameter of trash ball = 5 inch.
Therefore, the diameter of the top of the trash ball is 5 inch.
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Which of the following terms appear in the expansion of (x + y)10? The letter a in each term represents a real constant. ax3y7, ay5, ax5, ax5y
In the binomial expression (x + y)^10, the term that will appear in the expansion of expression is ax^3y^7.
Binomial expression refers to the algebraic expression which contains two terms. These expressions are expanded using binomial theorem. According to the theorem, it is possible to expand the binomial (x + y)^n into a sum involving terms of the form ax^by^c, where the exponents b and c are nonnegative integers with b + c = n, and the coefficient a of each term is a specific positive integer depending on n and b. Hence, for the given expression, the term which will appear in the expansion of binomial would have variables whose sum of power would be equal to the power of the expression i.e., the sum of the power would be 10. Hence, ax3y7 would appear in the expansion as the sum 3+7=10.
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Write the expressions in standard form 1/6(r-6)
Answer:
1/6 r-1
Step-by-Step Explanation:
1/6(r-6)
1/6 * (r-6) - distribute 1/6
1/6 r - 1/6 * 6 - simplify the expression
SOLUTION 1/6 r-1
