Practice using angle relationships.
Assignment
J
What is the measure of JKL?
* 60°
96°
O 80°
O 110°
O 120°
240
H
K L

Answer:

$3

Step-by-step explanation:

7 rands for $1

7×3=21

21 rands for $3

Answer:

$3

Step-by-step explanation:

7 rand = 1 dollar

Divide both sides by 7 rand.

1 = (1 dollar)/(7 rand)

Notice that the fraction (1 dollar)/(7 rand) equals 1, so multiplying by it will not change the amount, just the units.

21 rand * (1 dollar)/(7 rand) =

= 21/7 dollar

= 3 dollar = $3

Answer:

9.425 or 3π

Step-by-step explanation:

arc length = 2πr(θ/360)

The angle is 90˚ as indicated by the square symbol.

ABC = 2π6(90/360) = 9.425 or 3π

Answer:

No, binomial distribution cannot be applied.

Step-by-step explanation:

We known that a Binomial Distribution depends on provided experiment , a binomial distribution have only 2 outcomes. For example, when we flip a coin in the air, then the possible outcomes are Head and Tail.

But in the context, an American roulette wheel has [tex]37[/tex] outcomes. It means when we spin the American Roulette wheel, ball may lend on any of the numbers between 0 to 36. So there are more than [tex]2[/tex] outcomes.

Therefore, binomial distribution can not be applied here.

Answer:

Answer:

The probability that the average score of the 49 golfers exceeded 62 is 0.3897

Step-by-step explanation:

Answer:

99

Step-by-step explanation:

99

Given:

The five number summary of two data sets are given as:

a) 0, 4, 12, 14, 20

b) 2, 8, 14, 18, 20

To find:

The range for the outliers.

Solution:

We know that,

An observation is considered an outlier if it is below [tex]Q_1-1.5(IQR)[/tex]

An observation is considered an outlier if it is above [tex]Q_3+1.5(IQR)[/tex]

Where, IQR is the interquartile range and [tex]IQR=Q_3-Q_1[/tex].

The five number summary of two data sets are given as:

0, 4, 12, 14, 20

Here, [tex]Q_1=4[/tex] and [tex]Q_3=14[/tex].

Now,

[tex]IQR=14-4[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-1.5(10),14+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-15,14+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-11,29][/tex]

An observation is considered an outlier if it is below -11.

An observation is considered an outlier if it is above 29.

The five number summary of two data sets are given as:

2, 8, 14, 18, 20

Here, [tex]Q_1=8[/tex] and [tex]Q_3=18[/tex].

Now,

[tex]IQR=18-8[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-1.5(10),18+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-15,18+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-7,33][/tex]

An observation is considered an outlier if it is below -7.

An observation is considered an outlier if it is above 33.

Answer:

D = 120 Degrees ,  E : x = 14 , F: <JHK = 21, G: Summplementary Angle is 96 Degrees

Step-by-step explanation:

4X+2X = 180

6X=180

X=30

<ABD = 4X = 4(30) = 120

Answer:

6

Step-by-step explanation:

Therefore, the number 6.4 rounded to the nearest whole number is 6. * If the number you are rounding off is followed by 0,1,2,3,4, round the number down. To find 6.4 rounded to the nearest whole number.

Please Mark me brainliest

Answer:

Step-by-step explanation:

Answer:

C.

Step-by-step explanation:

Science questions are T/F. That's .5 or [tex]\frac{1}{2}[/tex] chance to get it right.

7 questions. Each with a [tex]\frac{1}{2}[/tex].

That's [tex](\frac{1}{2})^{7}[/tex]  

[tex](\frac{1}{2})^{7}[/tex] = [tex]\frac{1}{128}[/tex] = .0078 = .008 rounded

English questions are multiple choice. 4 choices. That's .25 or [tex]\frac{1}{4}[/tex]

3 questions. Each [tex]\frac{1}{4}[/tex]

That's [tex](\frac{1}{4})^{3}[/tex]

[tex](\frac{1}{4})^{3}[/tex] = [tex]\frac{1}{64}[/tex] = .0156 = .016 rounded

The probability of getting all questions correct is 0.004 which is lower than for science (0.016).

Science questions are said to have a 6 out of 6 correct answer range and a 0.5 chance of being answered properly.

So, P(6) = 0.5⁶

P(6) = 0.016

We are informed that there are 4 out of 4 correct answers for English, with a 0.25 chance of getting it right.

Thus; P(4) = 0.25⁴ = 0.004

Thus, we conclude that they will have to study English.

Learn more about Probability here:

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Answer:

The administrator should sample 968 students.

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.88}{2} = 0.06[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.06 = 0.94[/tex], so Z = 1.555.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation of 300.

This means that [tex]n = 300[/tex]

If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?

This is n for which M = 15. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]15 = 1.555\frac{300}{\sqrt{n}}[/tex]

[tex]15\sqrt{n} = 300*1.555[/tex]

Dividing both sides by 15

[tex]\sqrt{n} = 20*1.555[/tex]

[tex](\sqrt{n})^2 = (20*1.555)^2[/tex]

[tex]n = 967.2[/tex]

Rounding up:

The administrator should sample 968 students.

Answer:

geometric

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Given that the cones are similar then corresponding dimensions are in proportion, that is

[tex]\frac{12}{2}[/tex] = [tex]\frac{3}{x}[/tex] ( cross- multiply )

12x = 6 ( divide both sides by 12 )

x = 0.5 → A

Answer:

x=57/2

Step-by-step explanation:

2x+3=60

<=> 2x=57

=> x=57/2

Answer:

x = 960

Step-by-step explanation:

x=√{576×(576+1024)}

or, x = √(576×1600)

or, x = √576×√1600

or, x = 24×40

or, x = 960

Answered by GAUTHMATH

Answer:

Step-by-step explanation:

Answer:

Poggers

Step-by-step explanation:

Answer:

P=2pi×r

P=2×12pi=24pi

24pi÷4=6pi

6pi÷2=3pi

p=2×6×pi

p=12pi

12pi÷2=6pi

permiter=3pi+6pi+12=40.27

that is for part a

9514 1404 393

Answer:

  55 units

Step-by-step explanation:

If two angles have the same measure, the triangle is isosceles. That means two sides have the same measure. Since the two given sides are different measures, the remaining side must be one of those. The perimeter will be greatest if the congruent sides are the longest. The greatest perimeter is ...

  15 + 20 + 20 = 55 . . . units

Answer:

c

Step-by-step explanation:

The residual for the point line (10,80) is option A 75. at the given line which best fits y = 6.2x + 13.

The graph follows a straight line equation shows a straight line graph.

            slope(m)=tan∅=y axis/x axis.

Straight line graphs show a linear relationship between the x and y values.

solving the equation:-

y = 6.2x + 13

putting value of X = 10

Y = 6.2 * 10 + 13

Y = 62 + 13

Y = 75

Hence the line best fit = 75.

Learn more about equation of a line here:-https://brainly.com/question/18831322

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Answer:

The graph of y = f(x) will shift down 11 units

Step-by-step explanation:

Answer:

the answer is 3.162

Step-by-step explanation:

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

Fleet of 18 means that [tex]N = 18[/tex]

9 are carrying nuclear weapons, which means that [tex]k = 9[/tex]

9 are destroyed, which means that [tex]n = 9[/tex]

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

In which

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021[/tex]

[tex]P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687[/tex]

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Answer:

a) someone will steal her stuff in any other situation even if a stranger watches it

Answer:

Kindly check explanation

Step-by-step explanation:

The data table :

Use of SM _UK _China _ Russia _US _ col total

Yes ______480 __215 ___343 __640 _ 1678

No _______320 _ 285 ___357__ 360 _ 1322

Row Total__ 800 _500 __ 700_ 1000_ 3000

H0 : p1 = p2 = p3 = p4

H1 : p1 ≠ p2 ≠ p3 ≠ p4

Test statistic :

χ² = Σ(observed - Expected)² / Expected

Expected value of each cell = (Row total * column total) / N

N = grand total

Expected Values:

447.467 _279.667 _ 391.533 _ 559.333

352.533 _ 220.333 _ 308.467 _ 440.667

χ²=(2.36536+14.9527+6.01605+11.6337+3.00232 18.9793+7.63611+14.7665) = 79.352

Degree of freedom, df = (row-1)*(column-1) = (2 - 1) * (4 - 1) = 1 * 3 = 3

Using the Pvalue from Chisquare calculator :

Pvalue(79.352, 3) = 0.00000000001

Decision region :

Reject H0 ; If Pvalue < α

α = 0.05

Since 0.000000001 < 0.05 ; Reject H0 and conclude that not all population proportion are equal.

Sample proportion :

Phat = number of yes, x / total

For UK, Phat = 480/800 = 0.6

For China , Phat = 215/500 = 0.43

For Russia , Phat = 343/700 = 0.49

For US, Phat = 640/1000 = 0.64

Answer:

[tex]T=812[/tex]

Step-by-step explanation:

From the question we are told that:

No. Committee Members [tex]n=6[/tex]

Pool of : 5 students and 7 faculty members

At least 2 student members and at least 1 faculty member

Generally the committee is mathematically given by

The Total Events are

[tex]T=(^5C_2*^7C_4)+(^5C_3)*(^7C_3)+(^5C_4)*(^7C_2)+(^5C_5)*(^7C_1)[/tex]

[tex]T=350+350+105+7[/tex]

[tex]T=812[/tex]

Answer: 0.38

Step-by-step explanation:

Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:

P(x > 0.3)

Then, we will use a standard normal table

P(z > 0.3)

= 1 - p(z < 0.3)

= 1 - 0.62

= 0.38

Therefore, p(x > 0.3) = 0.38

The probability of x > 0.3 is 0.38.

Answer:

The right answer is:

(a) 0.1456

(b) 18.125, 69.1202, 8.3139

Step-by-step explanation:

Given:

N = 24

n = 5

r = 7

The improperly drilled gearboxes "X".

then,

⇒ [tex]P(X) = \frac{\binom{7}{x} \binom {17}{5-x}}{\binom{24}{5}}[/tex]

(a)

P (all gearboxes fit properly) = [tex]P(x=0)[/tex]

                                               = [tex]\frac{\binom{7}{0} \binom{17}{5}}{\binom{24}{5}}[/tex]

                                               = [tex]0.1456[/tex]

(b)

According to the question,

[tex]X = 91+5[/tex]

Mean will be:

⇒ [tex]\mu = E(x)[/tex]

       [tex]=E(91+5)[/tex]

       [tex]=9E(1)+5[/tex]

       [tex]=9.\frac{nr}{N}+5[/tex]

       [tex]=9.\frac{5.7}{24} +5[/tex]

       [tex]=18.125[/tex]

Variance will be:

⇒ [tex]\sigma^2=Var(X)[/tex]

         [tex]=V(9Y+5)[/tex]

         [tex]=81.V(Y)[/tex]

         [tex]=81.n.\frac{r}{N}.\frac{N-r}{N}.\frac{N-n}{N-1}[/tex]

         [tex]=81.5.\frac{7}{24}.\frac{24-7}{24}.\frac{24-5}{24-1}[/tex]

         [tex]=69.1202[/tex]

Standard deviation will be:

⇒ [tex]\sigma = \sqrt{69.1202}[/tex]

       [tex]=8.3139[/tex]