Review the graph. Given z = , which letter represents z3?

A
B
C
D

Answer:

540,000 cubic centimeters

Step-by-step explanation:

1 meter and 20 centimeters is equal to 120 centimeters.

[tex]120 \times 90 \times 50 = 540000[/tex]

The leading coefficient of the quadratic equation f(x)= x² – 8x – 4 will be 1.

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2.

The quadratic function, of vertex (h, k), is given by:

y = a(x – h)² + k

where a is the leading coefficient.

Then we have the quadratic equation given below.

f(x)= x² – 8x – 4

f(x)= x² – 8x + 16 – 16 – 4

f(x)= (x – 4)² – 20

Then the leading coefficient will be 1.

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The options are not mentioned , but the correct graph is plotted and attached with the answer.

A function is a mathematical statement that relates a dependent variable with an independent variable .

It is given to find among the options which is the correct graph for

y = log₃ (x-1)

The options are not mentioned , but the correct graph is plotted and attached with the answer.

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Answer:

3(4)² - 2(4) + 1 = 48 - 8 +1 = 41

x = 4

[tex] {3x}^{2} - 2x + 1 \\ \\ 3 \times {4}^{2} - 2 \times 4 + 1 \\ \\ 3 \times 16 -8 + 1 \\ \\ 48 - 8 + 1 \\ \\ 41.[/tex]

Answer:

The commutative property of addition says that changing the order of addends does not change the sum.

(a+b)+c = a+ (b+c)

( -8 + -7) + 6 = -8 + ( -7 + 6)

-15 + 6          =   -8 + -1

-9                  =  -9

Answer:

Hence, proved (a+b) + c = a + (b+c)."

Step-by-step explanation:

first take left hand side and insert the values of a, b, and c and similarly than take right hand side.

L.H.S

(a+b)+c

(-8+(-7))+6

(-8-7)+6

-15+6

-9

R.H.S

a+(b+c)

-8+(-7+6)

-8+(-1)

-8-1

-9

hence, proved (a+b) + c = a + (b+c)."

The distance of the first truck from the fire is 0.578 mile and the distance of the second truck from fire is 0.722 mile.

Using sine rule, we find the length of AB and BC as shown in the image.

a/sin A = b/sin B = c/sin C

Angle C = 180 - (58 + 52) = 70⁰

1.3/(sin 70) = b/(sin 52)

b = (1.3sin 52) / (sin 70)

b = 1.09 mile

c = (1.3sin 58) / (sin 70)

c = 1.1732 miles

Bisect angle C, and use sine rule again to find the lengths of bisected line AB.

1.09/(sin 90) = x/[sin (90 - 58)]

1.09/(sin 90) = x/(sin 32)

x = (1.09 sin 32)/(sin 90)

x = 0.578 mile

Truck B's position from the fire = 1.3 miles - 0.578 mile = 0.722 mile

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Step-by-step explanation:

I'm going to assume you mean

[tex]log(5^{125})[/tex] which can be rewritten as [tex]125 log(5)[/tex] since if you start with [tex]log(a) = x = > 10^x=a\\(10^x)^c=a^c\\c *log(a^c)[/tex]since when you do (10^x)^c you're just multiplying the exponent which is represented by the x but is equal to the log you just multiply the log which is why you can bring it in front.

You can then approximate the value of log(5) using a calculator and multiply by 125 to get around 87.371

Answer: 4/9

Step-by-step explanation:

Parallel lines have equivalent slopes.

As line 'l' and line 'm' are parallel to each other ,then the slope of line 'm' is also 4/9.

Parallel lines have the same slope. The slope of line segments is identical because they are all similarly inclined with respect to the positive x-axis. If 'l', and 'm' are the slopes of two parallel lines,

then l = m

Slope-intercept notation for lines may be expressed as y=mx+b.

In this notation, b denotes the location of the line's y-axis intercept, and slope(m) indicates the slope of the line.

The slope of 'l'=4/9

The slope of the two parallel lines is the same.

Therefore, the slope of the parallel line "m" = 4/9.

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Answer:

70%

$571.41

Step-by-step explanation:

100% means 1, or a whole thing.

Since the discount is 30% of the original price, and the original price is 100% of the original price, then

100% - 30% = 70%

With a 30% discount, you actually pay 70% of the original price.

$399.99 is 70% of the original price.

399.99 / 70% = x / 100%

70x = 100 × 399.99

x = 571.41

The original price was $571.41.

The value of x in the segment is 3

Using the secant and segment theorem, we have:

x * (x + 21) = (x + 1) * (x + 1 + 14)

Evaluate the sum

x * (x + 21) = (x + 1) * (x + 15)

Expand

x^2 + 21x = x^2 + 15x + x + 15

Subtract x^2 from both sides

21x = 15x + x + 15

Evaluate the like terms

5x = 15

Divide both sides by 5

x = 3

Hence, the value of x is 3

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Answer:

D

Step-by-step explanation:

A. The domain is not all real numbers since the domain of the inverse is the range of the square root function which is not all real numbers.

B and C. The domain is not x >= -4, that's the range since the domain and range are swapped relative to the original square root function which had a domain x >= 4 and a range x >= 0

D. This is true since the range of the square root function is x >= 0 which is now the range of the inverse.

Answer:

Option C.  [tex]g(x)=(\frac{1}{3}x)^2[/tex]

Step-by-step explanation:

Given a function to start with, extra operations that are done outside of the given function, cause vertical transformations, whereas operations that are done inside of the function cause horizontal transformations.

Transformations on the outside

Ex. [tex]g(x)=(x^2)-3[/tex]  is subtracting 3 outside, so its transformation is vertical.

Transformations on the inside

Ex. [tex]g(x)=(x-7)^2[/tex] is subtracting 7 inside, so its transformation is horizontal.

For any function, stretches or compressions occur by multiplying by positive numbers larger or smaller than 1.

Multiplying by numbers larger than one, quantities get larger, and multiplying by a positive number less than one, quantities get smaller.

For example, [tex]\$10*2 = \$20[/tex], but [tex]\$10*\frac{1}{2} = \$5[/tex]

For transformations, this intuition needs a small modification:

Multiplying on the outside

When multiplying outside of the function, things outside happen normally, and since it is happening outside, it is in a vertical direction.

Ex. Multiplying outside by 3, things get larger (stretch) vertically to 3 times as much as (300% of) normal (away from a height of zero).

Multiplying outside by [tex]\frac{1}{2}[/tex] , things get smaller (compress) vertically down to [tex]\frac{1}{2}[/tex] as much as (50% of) normal (toward a height of zero).

"g" is lower than "f", so it may have been compressed vertically (see alternative solution at end).

Looking at the only options with multiplication outside (A & B), option B multiplies by 3 (greater than 1), so it would stretch "f" even taller.

Option A, does compress "f" vertically (by 1/3), but doesn't compress it enough to arrive at the point (3,1) defined on function "g". Note ordered pair (3,1) on "g", meaning when you input "3", you get out "1".  

Putting 3 into the "f" function, f(3)=9.  Since one-third (the transformation in Option A) of 9 is 3, not 1, Option A doesn't compress "f" enough.

Multiplying on the inside

When multiplying inside, transformations happen horizontally, and inside things happen "backwards".

So, if multiplying inside by 4, (...normally things get bigger...) things actually get smaller (compressed) horizontally, reduced to 1/4 (the reciprocal of 4) the size (toward a horizontal distance of zero).

If multiplying by a number less than one (but positive), like [tex]\frac{1}{3}[/tex] , (...things normally get smaller...) things will actually get larger (stretch) in the horizontal direction out to triple (the reciprocal of [tex]\frac{1}{3}[/tex]) as much as normal.

Looking options C & D (where multiplication happens inside), both have multiplication by a positive number less than one (... normally would make things smaller...), which will stretch "f" out horizontally.

Looking at the red point (3,1), the blue function does have a height-matched point at (1,1).

Measuring horizontal distances, (3,1) is 3-units from the y-axis, whereas (1,1) is only 1-unit away.  Thus, the "g" is 3 times as far as "f", meaning a horizontal stretch outward by 3.

Answer C multiplies inside by [tex]\frac{1}{3}[/tex], so it actually makes things 3 times bigger horizontally.

The correct answer is option C.

To verify, from (3,1), put 3 into the option C g(x) --  it gives "1" as an output.

[tex]g(x)=(\frac{1}{3}x)^2\\g(3)=(\frac{1}{3}(3))^2\\g(3)=(1)^2\\g(3)=1\\[/tex]

This function could have been compressed vertically to obtain the red graph.

Note that f(3)=9.

The point (3,1), on the red function, is only at a height of 1 ... 1/9th the height of the blue function.  We could compress the "f" vertically by 1/9th to transform the blue function into the red function.

Vertical transformations come from operations outside, and outside things behave "normally", so to vertically compress by 1/9th, just multiply on the outside by 1/9th.

Thus, an alternative answer to transform f(x) to g(x) is [tex]g(x)=\frac{1}{9}(x^2)[/tex]

Two last things:

Simplifying this function we just obtained we get [tex]g(x)=\frac{1}{9}x^2[/tex]

Returning to the function that we chose for our answer in option C, [tex]g(x)=(\frac{1}{3}x)^2[/tex]

[tex]g(x)=(\frac{1}{3}x)(\frac{1}{3}x)[/tex]

[tex]g(x)=\frac{1}{9}x^2[/tex]

Note that the transformation answer for this problem (Option C) and our alternative solution both simplify and match perfectly, so they both represent the same end result.

Answer: [tex]\frac{1}{7^{2}}[/tex]

Step-by-step explanation:

Using the exponent rule [tex]a^{b} \cdot a^{c}=a^{b+c}[/tex], we get that

[tex]7^{3} \cdot 7^{-5}=7^{-2}[/tex]

Then, using the exponent rule [tex]a^{-b}=\frac{1}{a^b}[/tex], we get that

[tex]7^{-2}=\boxed{\frac{1}{7^{2}}}[/tex]

the correct options are:

Here we have the function:

[tex]F(x) = -\sqrt[3]{x}[/tex]

First, this is a cubic root, so its domain is the set of all real numbers (same for the range). And we know that the cubic root is an increasing function, so if we put a negative sign before it, we will have a decreasing function.

Then the correct options are:

The fourth option is incomplete, so we can't conclude if it is true or not, it would be true if it said:

"The function is a reflection over the x-axis of y = ∛x"

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Answer:

b, c, d

Step-by-step explanation:

Answer: A

Step-by-step explanation:

We can rewrite [tex]8^x[/tex] as follows:

[tex]8^{x}=\left(8^{9} \right)^{x/9}=\left(\frac{1}{8^{9}} \right)^{-x/9}[/tex]

Hence, [tex]A=\frac{1}{8^{9}}=\boxed{8^{-9}}[/tex]

Answer:

  f(x) = 2(x -3)² +5   or   f(x) = 2x² -12x +23

Step-by-step explanation:

The equation of a quadratic is easily written in vertex form when the coordinates of the vertex are given. Here, the point one horizontal unit from the vertex is 2 vertical units higher, indicating the vertical scale factor is +2.

__

The vertex form equation for a parabola is ...

  f(x) = a(x -h)² +k . . . . . . vertex (h, k); vertical scale factor 'a'

For vertex (h, k) = (3, 5) and vertical scale factor a=2, the vertex form equation of the parabola is ...

  f(x) = 2(x -3)² +5 . . . . . vertex form equation

Expanded to standard form, this is ...

  f(x) = 2(x² -6x +9) +5

  f(x) = 2x² -12x +23 . . . . . standard form equation

Answer: 3/4

Step-by-step explanation:

The difference in price between the two companies is $81-$79.56 = $1.44

Fire side Shop

Price of Chimney cap =$120

First Discount = 25% of(120)=$30

Price after 1st Discount = $120-$30=$90

Second Discount = 10% of 90=$9

Price after 2nd Discount = $90-$9=$81

Builders' Supply

Price of Chimney Cap= $111

First Discount= 25% of 111 = $27.75

Price after 1st Discount = $111 - $27.75 = $83.75

Second Discount = 5% of $83.75 = $ 4.1875

Price after 2nd Discount = $83.75 - $4.1875 = $79.5625 ≈ $79.56

Therefore,

a) Builders supply offers the lower price.

b) Difference in price = $81-$79.56 = $1.44

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The option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7], and the range is R: [–5, 1]

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have an ellipse equation:

[tex]\rm x^{2}+4y^{2}-2x+16y-19=0[/tex]

We can write the above equation as:

[tex]\rm \dfrac{\left(x-1\right)^{2}}{36}+\dfrac{\left(y+2\right)^{2}}{9}=1[/tex]

The domain will be:

D: [–5, 7]

The range will be:

R: [–5, 1]

Thus, the option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7] and the range is R: [–5, 1]

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Answer:

see the attachment photo!

12a - 8 -5a + 12

arranging like terms

12a - 5a - 8 + 12

a ( 12-5) - 8 - 12

a(7) - 4(2 - 3)

a(7) -4(-1)

a(7) + 4

7a + 4

simplifing the expressions

Answer:

12a-5a-8+12

=(12-5)a+4

=7a+4

The product of (√3x + √5)(√15x+2√30) assuming x ≥ 0 is 3√5x² + 6√10x + 5√3x + 10√6

It follows from the task content that the expression given whose product is to be evaluated is;

(√3x + √5)(√15x+2√30)

Hence, by multiplying the terms with each other accordingly; we have;

= (√45x² + 2√90x + √75x + 2√150)

= 3√5x² + 2√90x + √75x + 2√150

= 3√5x² + 2×3√10x + √75x + 2√150

= 3√5x² + 2×3√10x + 5√3x + 2√150

= 3√5x² + 2×3√10x + 5√3x + 10√6

= 3√5x² + 6√10x + 5√3x + 10√6

Ultimately, the product of the expression is; 3√5x² + 6√10x + 5√3x + 10√6

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The correct representations of this solution is {n | n > 3} an open circle appears at positive 3.

Inequalities are expressions not separated by an equal sign. Given the inequality

6 + 2n > 12

Subtract 6 from both sides

2n > 12 - 6

2n >6

Divide both sides by 2

2n/2 >6/2

n >3

Hence the correct representations of this solution is {n | n > 3} an open circle appears at positive 3.

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Answer:

The range of the function f(x) :  is y > 0.

The correct option is (A)

Step-by-step explanation:

The definition of range is the set of all possible values that the function will give when we give in the domain as input.

Given function is :

If we draw the graph for this, then we can see that the horizontal asymptote is 0.

So,  the range is real numbers higher than 0.

Hence, the range should be y > 0.

Answer:

177

Step-by-step explanation:

2/3 are women.

that means the remainder, 1/3, are men.

59 = 1/3 of all kindergarten teachers (3/3 = 1 representing the "whole").

so,

59×3 = 177

is the number of all kindergarten teachers employed by the school district.

A pattern is a recurring arrangement of numbers, forms, colours, and so on.

In mathematics, a pattern is a recurring arrangement of numbers, forms, colours, and so on. The Pattern may be applied to any form of event or object. A pattern is defined as a group of integers that are connected to each other in a specified way.

As per the pattern, Each figure has 3 more squares than the one before it.

Hence, the correct option is C.

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Answer:

All the possible zeroes of the polynomial: f(x) = [tex]3x^{6} + 4x^{3} - 2x^{2} +4[/tex] are  ±1 , ±2 ,  ±4 ,  ±[tex]\frac{1}{3}[/tex] , ±[tex]\frac{2}{3}[/tex]  , ±[tex]\frac{4}{3}[/tex] by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = [tex]3x^{6} + 4x^{3} - 2x^{2} +4[/tex]

Find all factors (p) of the constant term.

Here we are looking for the factors of 4, which are:

±1 , ±2 and ±4

Now find all factors (q) of the coefficient of the leading term

we are looking for the factors of 3, which are:

±1 and ±3

List all possible combinations of ± [tex]\frac{p}{q}[/tex]  as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 ,  ±4 ,  ±[tex]\frac{1}{3}[/tex] , ±[tex]\frac{2}{3}[/tex]  , ±[tex]\frac{4}{3}[/tex] as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = [tex]3x^{6} + 4x^{3} - 2x^{2} +4[/tex] are  ±1 , ±2 ,  ±4 ,  ±[tex]\frac{1}{3}[/tex] , ±[tex]\frac{2}{3}[/tex]  , ±[tex]\frac{4}{3}[/tex]

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The equation of line is y = 3x + 3 that passes throgh the provided points option (C) y = 3x + 3 is correct.

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

The options are missing.

The options are:

A) y = 3x - 3

B) y = -3x + 3

C) y = 3x + 3

D) y = -3x - 3

From the points [tex]\left(-2,3\right)[/tex] and [tex]\left(-1,0\right)[/tex]:

[tex]\rm y\ =\ \dfrac{3}{-1+2}\left(x+1\right)[/tex]

y = 3(x + 1)

y = 3x + 3

Thus, the equation of line is y = 3x + 3 that passes throgh the provided points option (C) y = 3x + 3 is correct.

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