Solve the system of equations by substitution.
x + y = A system of equations. StartFraction 3 over 8 EndFraction x plus StartFraction one-third EndFraction y equals StartFractions 17 over 24 EndFraction.
x + 7y = 8
(, )

Answer:

a. y-intercept:(0,  -6), x-intercepts: (3, 0) and (-2, 0). vertex: (0.5, -6.25)

b. y-intercept: (0, 6), x-intercepts(3, 0) and (-2, 0). vertex: (0.5, 6.25)

Step-by-step explanation:

a:

 So finding the y-intercept is really easy and is simply when x=0. If you plug in 0 as x it makes [tex]y=(0)^2-0-6[/tex] which simplifies to -6, which is the y-intercept. As for the x-intercepts you can calculate that by using the quadratic equation [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\[/tex]. In this case a=1, b=-1, c=-6. So plugging those values in you get [tex]x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(-6)}}{2(1)}[/tex], which simplifies to [tex]x=\frac{1\pm5}{2}[/tex]. This gives you the x-intercepts 6/2 and -4/2 which are 3 and -2. The vertex can be calculated by manipulating the equation so it's in the form of [tex]y=(x-h)^2+k[/tex] where (h, k) is the vertex of the parabola. This is done by moving c to the other side and then completing the square and the isolating y. So the first step will be

Move c to the other side

[tex]y+6=x^2-x[/tex]

Complete the square by adding (b/2)^2

[tex]y+6+0.25 = x^2-x+0.25[/tex]

Rewrite as square binomial

[tex]y+6.25 = (x-0.5)^2[/tex]

Isolate y

[tex]y=(x-0.50)^2-6.25[/tex]

(h, k) = 0.50, -6.25 which is the vertex

b: To identify the y-intercept you plug in 0 as x which will only leave c which in this case is 6 which is the y-intercept. (0, 6). To identify the x-intercepts you can simplify plug in the values a, b, c into the quadratic equation which was stated in the previous answer. In this case a, b, c = -1, 1, 6. Plugging these values in gives the equation [tex]y=\frac{-(1)\pm\sqrt{1^2-4(-1)(6)}}{2(-1)}[/tex]. which simplifies to [tex]x=\frac{-1\pm5}{-2}[/tex] which gives the values -2 and 3. To find the vertex it's the same process as before

Factor out -1

[tex]y=-(x^2-x-6)[/tex]

Add 6 to both sides (on the left side add -6 since -1 was factored out).

[tex]y-6=-(x^2-x)[/tex]

Complete the square by adding (b/2)^2 to both sides (add -(b/2)^2 to left side since -1 was factored out)

[tex]y-6-0.25 = -(x^2-x+0.25)[/tex]

Rewrite as square binomial

[tex]y-6.25=-(x-0.5)^2[/tex]

Add 6.25 to both sides

[tex]y=(x-0.50)^2+6.25[/tex]

(h, k) = (0.50, 6.25)

When you graph the parabolas you'll notice there just flipped relative to the x-axis. This can be deduced by simply looking at the two equations, since the two equations have the same absolute value coefficients, the signs are just different, and more specifically they're all opposite. If you took the first equation and multiplied the entire right side by -1 you would get the same equation. And since that equation really represents the value of y (since it's equal to y) you're reflecting it across the x-axis.

Answer:

a) y-intercept (0,  -6); x-intercepts (3, 0) and (-2, 0); vertex (0.5, -6.25)

b) y-intercept (0, 6); x-intercepts (3, 0) and (-2, 0); vertex (0.5, 6.25)

Step-by-step explanation:

Answer:

63

Step-by-step explanation:

A circle is 360 degrees

So, subtracting 297 from 360, we'd get 63 degrees

The true statements about ∠MJK and ∠MJL are

The statement is given as:

∠MJK and ∠MJL are a linear pair of angles and the angles are also supplementary

As a general rule, linear pair angles are adjacent angles that add up to 180 degrees. This means that:

The above means that, the following options are true:

(e), (f) and (h)

Also, the converse of the statement is:

∠MJK and ∠MJL are supplementary angles and the angles are also  linear pair of angles

This is false because not all supplementary angles are  linear pair angles

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Answer:

18.1cm

Step-by-step explanation:

Please refer to the attached photo for a better understanding. Apologies for the terrible drawing.

First we will find the length of BE by using pythagoras' Theorem.

[tex]c^{2} =a^{2} +b^{2} \\AB^{2} =BE^{2} +EA^{2} \\16^{2} =BE^{2} +7^{2} \\256=BE^{2} +49\\BE^{2} =256-49\\BE=\sqrt{207} cm[/tex]

We will leave BE as it is as it is not the final answer.

Since we know CD = BE,

CD = [tex]\sqrt{207} cm[/tex]

Now from the photo, draw a line from C to A or A to C, you will see another triangle.

Now we will use Pythagora's Theorem again to find AC.

[tex]AC^{2} =AD^{2} +DC^{2} \\AC^{2} =11^{2} +(\sqrt{207}) ^{2} \\AC^{2} = 121+207\\AC^{2} =328\\AC=\sqrt{328} \\=18.1cm (1dp)[/tex]

Answer:

440cm²

Step-by-step explanation:

*Area= (a+b)/2×h

(19+25)/2*20

= _ * 440cm². *_

Answer:

440cm²

Step-by-step explanation:

I believe its right

In the triangle ABC, the length of the line segment SA=3 ft ( 3rd option).

In triangle ABC,

According to the triangle proportionality theory, we know that if a triangle has a line segment parallel to one of its sides, the line segment splits the other sides correspondingly.

Hence,

SA/SB=CT/BT

⇒SA/10=2.7/9

⇒SA=(2.7*10)/9

⇒SA=3

So, the length of SA is 3 ft.

Therefore the 3rd option is correct.

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Answer:

x = 45 degrees

Step-by-step explanation:

Using the alternate exterior angle theorem, the angles are equal. You can set the expressions equal to each other:

3x = x + 90
2x = 90
x = 45

Answer: The answer is

x=   -3

y=    3

Answer:

2x³ + 2x

Step-by-step explanation:

(x² + x³ + x² + x) - (x² - x³ + x² - x)

= x² + x³ + x² + x - x² + x³ - x² + x

Gathering like terms...

x³ + x³ +x² + x² -x² - x² + x + x

= 2x³ + 2x

The difference of the polynomials is 2(x³+x).

A polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables.

Given are two polynomials (x² + x³ + x² + x) and (x²-x³+x²-x), we need to find the difference,

So,

(x² + x³ + x² + x) - (x²-x³+x²-x)

= x² + x³ + x² + x - x²+x³-x²+x

= 2x²-2x²+x³+x³+x+x

= 2x³+2x

= 2(x³+x)

Hence the difference of the polynomials is 2(x³+x).

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Answer:

By splitting the line segments into equal parts, we find that the length of the line segment formed by joining the mid-points is 5.5 units.

Step-by-step explanation:

Given lengths show that the length of JK is 5 units, KL is 4 units and LM is 6 units. Let the midpoint of JK be A. This means JK is splited into two equal parts JA and AK. Since the lengths of both the segments are same, it will be 5/2 = 2.5 units.

Now, let the midpoint of LM be B. So, we have two equal line segments LB and BM of length 6/2 = 3 units.

So, the length of the line segment formed by joining A and B will be 2.5 + 3 = 5.5 units

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Answer:

4 pi     ( = 12.566  in^2 )

Step-by-step explanation:

TOTAL area =   pi r^2    =    pi (6)^2 = 36 pi   in^2

  divide into 9 pieces    36 pi  / 9 = 4 pi   in ^2

Answer:

s = 6 cm

Step-by-step explanation:

the area (A) of a square is calculated as

A = s² ( s is the side length )

given A = 36 , then

s² = 36 ( take square root of both sides )

s = [tex]\sqrt{36}[/tex] = 6

Answer:

0.32

Step-by-step explanation:

2^3 = 2*2*2 = 8

5^2 = 5*5 = 25

------------------------------

8/25 = 0.32

Answer: 63

Step-by-step explanation:

I assume you meant (x+3)/5 = 12.

Answer:

See below

Step-by-step explanation:

If you can't tell just by looking at them, you will need to convert them all to fractions of a common denominator .....in this case (the smallest) common denominator would be 18

1/2 = 9/18  

1/3 = 6/18

1/6 = 3/18

4/9 = 8/ 18             so now you can see least to greatest is

                                    1/6    1/3    1/2   4/9

Answer:

Answer:

Inequality is the answer

Answer: Inequality ✅

Step-by-step explanation:

Hii, do you need to know the answer to your question? No problem!

The answer to your question is "inequality".

An inequality is a number sentence that shows how two or more expressions are not equal.

An example of that is [tex]\sf 4x+4\geqslant3x-5[/tex].

So 4x+4 is greater than or equal to 3x-5, but they're not 100% equal (such is the case in equations).

--

Hope that this helped! Best wishes.

--

Answer:

(10/3)π units

Step-by-step explanation:Mark if it is correct

Answer:

[tex]\frac{10\pi }{3}[/tex] inches

≈ 10.5 inches

Step-by-step explanation:

The formula for arc length is as follows:
Arc length = [tex]\frac{\theta}{360} * 2\pi[/tex]

[tex]\frac{120}{360} * 10\pi \\= \frac{1}{3} * 10\pi \\= \frac{10\pi}{3}[/tex]

Hope this helps and feel free to mark this as brainliest!

Answer:

-1/2

Step-by-step explanation:

sin(30 degrees) = sin (pi/6) = 1/2

cos(30 degrees) = cos (pi/6) = [sqrt(3)]/2]

sin (60 degrees) = sin(pi/3) = [sqrt(3)]/2]

1/2 - [sqrt(3)/2] / [sqrt(3)/2] = -1/2

Answer:

Roots of the equation are  (−3−√7) , (−3+√7)

Step-by-step explanation:

For solving a quadratic equation using completing the square method:

given equation:

y = x^2 - 6x +2

0 = x^2 - 6x + 2

0 = x^2 - 3^2 + 3^2 -6x +2

0 = (x-3)^2 -7

7 =  (x-3)^2

±[tex]\sqrt{7}[/tex] = x-3

±[tex]\sqrt{7}[/tex] + 3 = x

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5b+a-2c when a=2,b=1&c=3

5(1) + 2 - 2(3)

5 + 2 - 6

7-6

Answer: 1

The linear measure of arc vw as described in the task content is; 46.89in.

It follows from the task content that the radius of the circle with center p is given as pv = 32in. and the angle subtended by the arc is; 84.

On this note, the measure of arc vw is;

= (84/360) × 2 × 3.14 × 32

= 46.89 inches.

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Answer:

The algebraic expression which represents the phrase “two times the quantity of a number minus 12” is : 2x- 12

Step-by-step explanation:

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.

for example :-

3x + 4y – 7,  4x – 10, etc.

These expressions are represented with the help of unknown variables, constants and coefficients. The combination of these three (as terms) is said to be an expression. It is to be noted that, unlike the algebraic equation, an algebraic expression has no sides or equal to sign

let the quantity mentioned in the question be 'x'

therefore according to the statement the algebraic expression which represents the phrase “two times the quantity of a number minus 12” is : 2x- 12 is

⇒2x - 12 (answer)

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By using trigonometric rules and expressions we find that the expression [tex]x = \sqrt{\frac{1-\cos 170^{\circ}}{2} }[/tex] is equivalent to single trigonometric expression x = sin 85°.

In this question we must apply trigonometric rules to simplify a given number, in which case we can take advantage of this expression:

[tex]\sin \frac{\theta}{2} = \sqrt{\frac{1 - \cos \theta}{2} }[/tex]

If we know that [tex]x = \sqrt{\frac{1-\cos 170^{\circ}}{2} }[/tex], then the rewritten expression is:

x = sin 85°

By using trigonometric rules and expressions we find that the expression [tex]x = \sqrt{\frac{1-\cos 170^{\circ}}{2} }[/tex] is equivalent to single trigonometric expression x = sin 85°.

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Answer:

B

Step-by-step explanation:

look at the graph, it is really easy with such basic numbers involved :

the red dotted line is

y = 2

since the line is dotted (= the points on the line are not included in the solution), the colored area is below the line is

y < 2

the blue line is clearly just a 45° basic line through the origin (0,0), and that means for every point in that line x is equal to y.

y = x

and the line is solid, so the points are included in the solution. the shaded area is above the line, so, we need to use the ">" relation :

y >= x

the required solution is the combination of both, and therefore, B is correct.

Answer:

10

Step-by-step explanation:

use PEMDAS

PEMDAS order is Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

2[32 — (4 − 1)³] =

2[32 — (3)³] =

2[32 — 27] =

2[5] =

10

khanacademy

We have:

For a parabola like:

[tex]y = a*x^2 + b*x + c[/tex]

The vertex is at:

[tex]x = -b/2a[/tex]

In this case, we have:

[tex]y = -2x^2 -4x + 14[/tex]

So the vertex is at:

[tex]x = 4/2*(-2) = -1[/tex]

To get the y-value, we need to evaluate in x = -1.

[tex]y = -2*(-1)^2 - 4*(-1) + 14 = -2 + 4 + 14 = 16[/tex]

So the vertex is (-1, 16)

To do that we just evaluate in x = 0.

[tex]y = -2*0^2 -4*0 + 14 = 14[/tex]

The vertical intercept is (0, 14).

Using Bhaskara's formula we get:

[tex]x = \frac{4 \pm \sqrt{(-4)^2 - 4*(-2)*14} }{2*-2} \\\\x = \frac{4 \pm 11.31 }{-4}[/tex]

So the two roots are:

x = (4 + 11.31)/(-4) = -3.83

x = (4 - 11.31)/(-4) = 1.83

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Answer:

D

Hope this helps!