To break all the bonds in one mole of molecules with a bond dissociation energy of 1 eV, we would require around 5.80 x [tex]10^{26}[/tex] kJ of energy.
The bond dissociation energy of 1 eV is roughly 96.485 kJ/mol. To break all the bonds in one mole of molecules (6.023 x [tex]10^{23}[/tex] molecules), we would need to multiply the bond dissociation energy by Avogadro's number:
96.485 kJ/mol x 6.023 x [tex]10^{23}[/tex] molecules/mol = 5.80 x [tex]10^{26}[/tex] kJ/mol
Bond dissociation energy is the amount of energy necessary to break a chemical connection between two atoms. It is also known as bond energy or bond enthalpy. This energy is measured in kilojoules per mole (kJ/mol) and is released when the bond forms. The energies of bond dissociation can vary greatly depending on the type of bond being broken.
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Balance this equation
C₂H₁6 + 02 -> CO ₂ (g) + H₂O(g)
The balanced form of the chemical equation given above is as follows: C₂H₁₆ + 60₂ -> 6CO₂ (g) + 6H₂O(g).
What is a balanced chemical equation?A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.
A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation is the same.
According to this question, the equation for photosynthesis is given. The balanced form is as follows:
C₂H₁₆ + 60₂ -> 6CO₂ (g) + 6H₂O(g)
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An aqueous solution of glucose (mm = 180. 2 g/mol) has a molality of 5. 21 m and a density of 1. 20 g/ml. What is the molarity of glucose in the solution?.
The molality and density of an aqueous solution of glucose (mm = 180. 2 g/mol) are 5. 21 and 1. 20 g/ml, respectively. Therefore, the molarity of glucose in the solution is 0.0355 M.
Molality is the number of moles of solute per kilogram of solvent, while molarity is the number of moles of solute per liter of solution.
molarity (M) = molality (m) * (density of solvent in g/mL) / (molar mass of solute in g/mol)
molality (m) = 5.21 m
the density of solvent (g/mL) = 1.20 g/mL
molar mass of solute (g/mol) = 180.2 g/mol
So, molarity (M) = 5.21 m * (1.20 g/mL) / (180.2 g/mol)
molarity (M) = 5.21 m * 0.0067 g/mL/g mol
molarity (M) = 0.0355 M
Therefore, the molarity of glucose in the solution is 0.0355 M.
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Solid iron (III) hydroxide decomposes to produce iron (III) oxide and water vapor. Write a balanced equation. If 0.75 L of water vapor are produced at STP,
Fe(OH)3 --> Fe2O3 + H2O (YOU MUST BALANCE THIS BEFORE STARTING)
a. How many grams of iron (III) hydroxide were used? grams of iron (III) hydroxide (3 sig figs)
b. How many grams of iron (III) oxide were produced? grams of iron (III) oxide (3 sig figs)
The balanced equation for the reaction between iron (III) hydroxide and water vapor to produce iron (III) oxide is Fe(OH)₃ -> Fe₂O₃ + 3H₂O
a. 26.5 grams of Fe(OH)₃ used.
b. 40 grams of Fe2O3 produced
How to calculate grams used and produced?Determine the number of moles of water produced: 0.75 L of water at STP (standard temperature and pressure) is equal to 0.75 moles.
Find the number of moles of Fe(OH)3: The reaction produces 3 moles of water for every 1 mole of Fe(OH)3, so 0.75 moles / 3 = 0.25 moles of Fe(OH)3.
Find the mass of Fe(OH)3: Fe(OH)3 has a molar mass of 106 g/mol, so 0.25 moles * 106 g/mol = 26.5 grams of Fe(OH)3.
So the answer to part a is 26.5 grams of Fe(OH)3 were used.
Determine the number of moles of Fe2O3: 0.25 moles of Fe(OH)3 produced 0.25 moles of Fe2O3.
Find the mass of Fe2O3: Fe2O3 has a molar mass of 160 g/mol, so 0.25 moles * 160 g/mol = 40 grams of Fe2O3.
So the answer to part b is 40 grams of Fe2O3 were produced.
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Radioactive iodine-123 has an effective half-life of 12 hours.
Part A
If a dose with an activity of 2.45 mCi of 1231 is given to a patient for a thyroid test, how much of the 123 I will still be active 60 hours later?
Express your answer with the appropriate units.
The amount of iodine-123 that will still be active 60 hours later is 0.0766 mCi.
How did we get the value?The effective half-life of iodine-123 is 12 hours, which means that after each 12-hour period, the activity of the sample will be reduced by half. After 60 hours, or 5 half-lives, the activity will be reduced to:
(1/2)^5 = 1/32
So only 1/32 of the original activity will remain. To find the activity that remains, we can multiply the initial activity by the fraction of the original activity that remains:
Remaining activity = (1/32) x 2.45 mCi = 0.0766 mCi
Therefore, the amount of iodine-123 that will still be active 60 hours later is 0.0766 mCi.
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About 0.153125 mCi of iodine-123 will still be active 60 hours later.
What is effective half-life of a radioactive substance ?Effective half-life of a radioactive substance is the amount of time it takes for the activity of the substance to decrease to half of its initial value, taking into account both the physical half-life of the substance and any biological processes that may affect its decay rate.
In this case, the effective half-life of iodine-123 is 12 hours. This means that after 12 hours, the activity of the substance will be reduced to half its initial value, and after another 12 hours (i.e., 24 hours after the initial dose), it will be reduced to one-quarter of its initial value, and so on.
To calculate the amount of iodine-123 that will still be active 60 hours later, we can use the following formula:
activity = initial activity x (1/2)^(t / t1/2)
where
"initial activity" is the initial amount of iodine-123 given to the patient (2.45 mCi) "t" is the time that has elapsed since the initial dose (60 hours) "t1/2" is the effective half-life of iodine-123 (12 hours)Plugging in the values, we get:
activity = 2.45 mCi x (1/2)^(60 hours / 12 hours)
activity = 2.45 mCi x 0.0625
activity = 0.153125 mCi
Therefore, about 0.153125 mCi of iodine-123 will still be active 60 hours later.
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Amino acids are represented in Fischer projections and described by D/L or R/S system. To denote amino acids as D or L, firstly they have to be written in Fischer projection, following the given steps:
1. The Fischer projection is denoted by a plus sign in which the acid group is placed on the top.
2. The carbon chain is the backbone of the Fischer projection, thus the side chain groups are placed at the bottom of the plus sign.
3. The vertical lines represent the bonds facing away from you (these are the carbon chain) and they are depicted by dashed wedges.
4. The horizontal lines represent the bonds coming towards you and they are depicted by solid wedges.
5. The position of the amino group determines the configuration of amino acid: If the amino group is on right side then it is D-amino acid, if the amino group is on left side then it is L-amino acid.
That's a good summary of how to represent amino acids in Fischer projections and determine their D/L configuration.
Just to clarify, the orientation of the amino group is actually determined by looking at the lowest chiral center of the molecule, which is usually the alpha carbon (the carbon next to the carboxyl group). If the amino group is on the right side of this carbon in the Fischer projection, it is an L-amino acid; if it's on the left side, it's a D-amino acid. This may seem counterintuitive, but it's because the Fischer projection is actually a 2D representation of a 3D molecule, and the labels "D" and "L" were historically assigned based on the orientation of the molecule in space rather than the orientation on paper.
Additionally, the R/S system is a different method of assigning absolute configuration (not D/L) to chiral centers in molecules, including amino acids. In this system, the orientation of the groups around the chiral center are ranked by priority (based on atomic number), and the molecule is oriented so that the lowest priority group is pointing away from the viewer. The remaining three groups are then prioritized in a clockwise or counterclockwise direction, and the molecule is assigned an R or S configuration based on the direction of the priority sequence.
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Write an equation that shows the formation of a copper (ii) ion from a neutral copper atom
An equation that shows the formation of a copper (ii) ion from a neutral copper atom is Cu ⇒ Cu⁺² + 2e⁻.
What is oxidation ?Oxidation occurs when a reactant loses electrons during a reaction. Reduction occurs when a reactant accumulates electrons during a reaction. When metals react with acid, this is a common occurrence. Oxidation occurs when a reactant loses electrons during a reaction.
When an atom looses an electron to form positive ion, this process is called as an oxidation reaction.
Copper will lose 2 electron to form +2 ion. The equation for the formation of copper (II) ion from neutral copper atom follows:
Cu ⇒ Cu⁺² + 2e⁻
Thus, Cu ⇒ Cu⁺² + 2e⁻ is an equation that shows the formation of a copper (ii) ion.
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Count the number of atoms in the formula: 2Ca(OH)2
Ca atoms
There are
type your answer...
There are
type your answer...
There are type your answer...
O atoms
Hatoms
The total number of atoms is type your answer...
The total number of atoms in the formula is 2 + 4 + 4 = 10 atoms.
What are atoms?
An atom is the basic unit of matter and the defining structure of elements. The term "atom" comes from the Greek word for indivisible, because it was once thought that atoms were the smallest things in the universe and could not be divided.
Atoms are composed of a nucleus, which contains positively charged protons and uncharged neutrons, surrounded by a cloud of negatively charged electrons. The number of protons in an atom's nucleus determines what element the atom is, as each element has a unique number of protons.
To count the number of atoms in the formula 2Ca(OH)2, we need to determine the number of each type of atom present.
In this formula, there are:
2 calcium atoms (Ca)4 oxygen atoms (O)4 hydrogen atoms (H)So, the total number of atoms in the formula is 2 + 4 + 4 = 10 atoms.
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If the reaction yield is 95.7% how many grams of lead oxide will be produced by the decomposition of 2.50g of lead carbonate
If the reaction yield is 95.7%, then 2.37 grams of lead (II) oxide will be produced by the decomposition of 2.50 grams of lead (II) carbonate.
Answer:
2.54g
Explanation:
Lead carbonate (PbCO3) can be decomposed to produce lead oxide (PbO) and carbon dioxide (CO2). The equation for this reaction is as follows:
PbCO3(s) -> PbO(s) + CO2(g)
Let's assume that the reaction yield is 95.7%, meaning that 95.7% of the theoretical amount of lead oxide produced in the reaction is actually obtained. To find the actual amount of lead oxide produced, we first need to find the theoretical amount of lead oxide produced by the reaction.
The theoretical amount of lead oxide can be calculated using the stoichiometry of the reaction, where the number of moles of reactants is balanced with the number of moles of products. If we assume that 2.50g of lead carbonate is decomposed, the number of moles of lead carbonate can be calculated as follows:
n = m/M
where n is the number of moles, m is the mass of the substance, and M is the molar mass of the substance. For lead carbonate, the molar mass is:
M = 207.19 g/mol
So, the number of moles of lead carbonate is:
n = 2.50 g / 207.19 g/mol = 0.01202 mol
Since the reaction is balanced, the number of moles of lead oxide produced should be equal to the number of moles of lead carbonate. The mass of lead oxide produced can be calculated using the number of moles and the molar mass of lead oxide:
m = n x M
where M = 223.20 g/mol is the molar mass of lead oxide. So, the mass of lead oxide produced is:
m = 0.01202 mol x 223.20 g/mol = 2.68 g
Since the reaction yield is 95.7%, the actual amount of lead oxide produced is:
actual_mass = 0.957 x 2.68 g = 2.54 g
So, approximately 2.54g of lead oxide will be produced by the decomposition of 2.50g of lead carbonate.
A new element with three naturally occurring isotopes has an average atomic mass determined to be 81.5529
amu. The first two isotopes have relative abundances of 76.12% and 10.27% and masses of 81.6643 amu and
81.1239 amu respectively. What is the mass of the third isotope?
- report your answer in six significant figures
- do not include units
The average atomic mass for the new element is given 81.5529 amu. The percentage abundance for the third isotope is 13.6 %. Then its atomic mass is 83.9 amu.
What are isotopes?Isotopes are atoms of same element with different atomic mass numbers. Almost all elements have two or more isotopes but not all of them are stable in nature.
The average atomic mass can be calculated from the isotopic mass and and percentage abundance as follows:
atomic mass = ∑ (isotopic mass × %abundance /100 )
Apply the isotopic mass and abundance of all isotopes given as follows:
atomic mass of the element = (76.12/100 ×81.6643 amu) + (10.27/100 × 81.1239 amu) + (13.6 /100 × X amu) =81.5529 amu.
Then,
(13.6 /100 × X amu) = 70.41 amu.
X = 83.9 amu.
Therefore, the atomic mass of the third isotope is 83.9 amu.
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Zinc metal and aqueous copper (II) chloride react to produce aqueous zinc chloride and
copper metal.
O Combustion
O Synthesis
O Single Replacement
O Decomposition
O Double Replacement
O Acid/Base Neutralization
Answer: Single Replacement
Explanation:
This reaction is single replacement because the Zinc pushes out the Copper from the CuCl2 to form ZnCl. This happens because Zinc is above Copper in the activity series.
Can someone elaborate why Fatty acids methyl esters (FAME) is suitable to by analysed using gc? based on their smoking point aspect
Answer:
Fatty acids methyl esters (FAMEs) are a class of biofuels derived from vegetable oils or animal fats and are commonly used as a diesel fuel substitute. FAMEs are suitable for analysis using gas chromatography (GC) because of their relatively high boiling points, which allow for efficient separation and detection of individual components.
Answer:
Fatty acids methyl esters (FAME) are suitable for analysis using gas chromatography (GC) due to their high volatility and thermal stability. These characteristics make FAMEs ideal for GC analysis because they can be vaporized and separated easily into their individual components. This is because the esterification of fatty acids to form FAMEs results in the introduction of a methyl group, which reduces the molecular weight and increases the volatility of the fatty acids. Additionally, the methyl ester functional group has a high smoking point, meaning that it can withstand high temperatures without breaking down, making it suitable for GC analysis where high temperature conditions are used to vaporize and separate the components. The use of GC in the analysis of FAMEs provides accurate and precise information on the composition of fatty acids in various samples, which is useful in applications such as the analysis of edible oils, biodiesel, and other lipid-containing materials.
Explanation:
1. There are 3 main types of chemical formulas: empirical, molecular and structural.
Structural formulas identify the location of chemical bonds between the atoms of a
molecule. Consider the following molecular structure below:
(a) Redraw the structure in the form of expanded and condensed structures.
(b) Classify the carbons labelled a and b as primary, secondary or tertiary.
[4 marks]
(a) Expanded structure:
CH3–CH2–CH–CH3
Condensed structure:
CH3CH2CHCH3
(b) Carbon a is a primary carbon and Carbon b is a secondary carbon.
What are chemical formulas?Generally, Chemical formulas are symbols used to represent elements and molecules.
They usually consist of the symbols for the elements in the molecule, with subscripts indicating the number of each atom.
For example, the chemical formula for water is H2O, indicating two hydrogen atoms and one oxygen atom.
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Please help! Will give brainly, attached photo.
The mass of the HgO is 434 g.
What is the stoichiometry?Stoichiometry allows us to calculate the amount of each reactant and product involved in a reaction based on its chemical formula. This is done by using the balanced chemical equation for the reaction, which shows the ratio of moles of each reactant and product involved in the reaction.
The reaction equation is; 2HgO(s)→Hg(l)+O2(g).
The number of moles of the oxygen is; 32.1g/ 32 g/mol
= 1 mole
We have to know form the reaction equation that;
2 moles of the HgO produces 1 mole of oxygen
x moles of HgO would produce 1 moles of oxygen
x = 2 moles
Mass of the compound = 2 moles * 217 g/mol
= 434 g
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When 6.50 moles of Calcium oxide
decomposes, how many moles of oxygen
gas are produced.
2 Cal --) 2 Ca + O2
A) 6.50 moles 0₂
B) 13.0 moles 0₂
C) 3.25 moles 0₂
Answer:
A) 6.50 moles 0₂
Explanation:
In the reaction, 2 moles of Calcium oxide decomposes to produce 2 moles of Calcium and 1 mole of Oxygen gas.
So, when 6.50 moles of Calcium oxide decomposes, 6.50 x (1 mole O₂ / 2 moles Calcium oxide) = 6.50 x 0.5 = 3.25 moles of Oxygen gas will be produced.
And as 3.25 x 2 = moles O₂,
Type the correct answer in the box. Express your answer to three significant figures.
The half-life of carbon-14 is 5,730 years. Dating organic material by looking for C-14 can't be accurately done after
50,000 years.
Suppose a fossilized tree branch originally contained 4.30 grams of C-14. How much C-14 would be left after 50,000 years?
Use the formula N = No (+)*
A tree branch that originally had 4.3 grams of carbon-14 will have
grams after 50,000 years.
Answer:
0.041 grams of carbon-14 remaining.
Explanation:
The half-life of carbon-14 is the time it takes for half of the original amount of carbon-14 to decay. In this case, the half-life of carbon-14 is 5,730 years. This means that after 5,730 years, half of the original amount of carbon-14 will remain, and half will have decayed.
In this problem, we are given that a fossilized tree branch originally contained 4.30 grams of C-14, and we are asked how much C-14 would be left after 50,000 years. To find this, we need to calculate how many half-lives have occurred over this time period, and then find the resulting amount of C-14.
We can use the formula N = N0 * (1/2)^(t/t1/2) to calculate the amount of C-14 after a given number of half-lives, where N0 is the initial amount of C-14, t is the total time elapsed, and t1/2 is the half-life of the substance.
Plugging in the given values, we get N = 4.30 g * (1/2)^(50000 years / 5730 years/half-life) = 0.041 g.
So, after 50,000 years, the tree branch will have 0.041 grams of carbon-14 remaining.
ALLEN
One of the main terms used in physics to describe the radioactive decay of a specific sample or element over a predetermined amount of time is half-life, also known as half-life period. After 50,000 years, the tree branch will have 0.041 grams of carbon-14 remaining.
What is half-life?A radioactive material's half-life is typically described as the amount of time it takes for one half of its atoms to decay or change into another substance. Ernest Rutherford made the first discovery of the theory in 1907. It is typically denoted by the letters Ug or t1/2.
Understanding half-lives is crucial because they allow you to determine if a sample of radioactive material is safe to handle. A sample is deemed safe when its radioactivity is below detection thresholds. Ten half-lives later, something occurs.
We can use the formula N = N0 * (1/2)^(t/t1/2)
N = 4.30 g * (1/2)^(50000 years / 5730 years/half-life) = 0.041 g.
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how many molecules are represented 11.5 g of C2H5OH
According to the question the molar mass of C2H5OH is 46.07 g/mol.
What is molar mass?Molar mass is the mass of a given substance (expressed in grams) divided by the amount of substance (expressed in moles). It is also known as the molecular weight of a substance, and is the sum of the atomic masses of all the atoms in a molecule. Molar mass is used to calculate the mass of a compound in a given volume, and is commonly used in the fields of chemistry, physics, and biology to identify, quantify, and measure substances. It is also used to determine the density of a given substance, and is an important part of formulas used to calculate the concentration of a particular substance in solution.
To calculate the number of molecules, we must divide the given mass of 11.5 g by the molar mass of C2H5OH. This gives us a result of 250.03 molecules of C2H5OH.
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946.36 water * 1 mol water/ 236.59 g water * 4 mol lemonade/ 2 mol water * 225.285 g lemonade/1 mole lemonade = ? g lemonade.
According to the recipe, to make 4 moles of lemonade, you use 2 moles of water, one mole of sugar and one mole of lemon juice, expressed in grams:
2 water + sugar + lemon juice = 4 lemonade
2*(236.59) + 225g + 257.83g = 4*(719.42)g
473.18g + 225g + 257.83g = 2877.68g
So for every 2877.68g of lemonade made, they use 473.18g of water, 225g of sugar, and 257.83g of lemon juice.
You know that they made a batch of 2050.25g, so to detect the limiting reactant, first, you have to calculate, in theory, how much of each ingredient you need to make the given amount of lemonade:
Use cross multiplication
Water:
2877.68g lemonade → 473.18g water
2050.25g lemonade → X= (2050.25*473.18)/2877.68= 337.12g water
Following the recipe, to elaborate 2050.25g of lemonade, you need to use 337.12g of water.
Sugar:
2877.68g lemonade → 225g sugar
2050.25g lemonade → X= (2050.25*225)/2877.68= 160.30g sugar.
To elaborate 2050.25f of lemonade you need to use 160.30g of sugar.
Lemon juice:
2877.68g lemonade → 257.83g lemon juice
2050.25g lemonade → X= (2050.25*257.83)/2877.68= 183.69g lemon juice.
To elaborate 2050.25f of lemonade you need to use 183.69g lemon juice.
Available ingredients vs. theoretical yields for 2050.25g of lemonade:
Water 946.36 g → 337.12g
Sugar 196.86 g → 160.30g
Lemon Juice 193.37 g → 183.69g
The lemon juice will be the first ingredient to be used up, there will be a surplus of water and sugar.
What is lemonade?
In Egypt around the 13th and 14th centuries, people drank a concoction of lemon juice, dates, and honey called qatarmizat.Lemonade was sold to Parisians in cups by vendors who carried tanks of the soft drink on their backs.To know more about lemonade, click the link given below:
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3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O
In the above equation how many moles of water can be made when 41 moles of HNO3 are consumed?
Answer:
5.125 moles of water
Explanation:
Given the reaction:
Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O
When 41 moles of HNO3 are consumed, we can calculate the number of moles of water produced using the stoichiometric coefficients in the balanced chemical equation.
According to the coefficients, 1 mole of Cu reacts with 8 moles of HNO3 to produce 4 moles of H2O. Therefore, when 41 moles of HNO3 are consumed, we can calculate the number of moles of water produced as follows:
41 moles HNO3 / 8 moles HNO3 per mole H2O = 5.125 moles H2O
So, 5.125 moles of water can be made when 41 moles of HNO3 are consumed.
define Qc, and how Qc is used (in comparison to Kc) to determine the direction in which the equilibrium will shift, resulting in changes to the concentrations of reactants and products
Answer:
Explanation:
"Qc" stands for "Reaction Quotient Concentration" and represents the ratio of the concentrations of products raised to their stoichiometric coefficients, divided by the ratio of the concentrations of reactants raised to their stoichiometric coefficients at a given point in a chemical reaction.
Qc is used in comparison to "Kc," the "Equilibrium Constant Concentration," to determine the direction in which a chemical reaction at equilibrium will shift. If Qc is less than Kc, the reaction will shift in the direction that increases the concentration of products, so as to reach a new state of equilibrium with Kc. Conversely, if Qc is greater than Kc, the reaction will shift in the direction that increases the concentration of reactants, so as to reach a new state of equilibrium with Kc.
In other words, if Qc is equal to Kc, the reaction is at its state of equilibrium, and any changes to the concentrations of reactants or products will cause the reaction to shift until a new state of equilibrium is reached with the updated Kc value. If Qc is not equal to Kc, the reaction will shift until it reaches a state of equilibrium with the updated Kc value.
S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O
In the above equation how many moles of water can be made when 66 moles of HNO3 are consumed?
Answer:
792 moles.
Explanation:
When 66 moles of HNO3 are consumed, 6 x 66 = 396 moles of NO2 are produced.
Since the equation shows a 1:2 mole ratio between HNO3 and H2O, the number of moles of H2O produced is 2 x 396 = 792 moles.
An anion X-3 has 31 nucleons and has atomic numbe equal to 15. The number of electron having m = 0 i it, is:-
Answer: 23
Explanation:
because it is been multiplyed by 3 has s 31 nucleons and has atomic numbe equal to 15. The number of electron having m = 0 i
Answer:
The number of electrons with magnetic quantum number m = 0 can be calculated from the atomic number of the element. The atomic number gives the number of protons, and thus the number of electrons in a neutral atom. For the anion X-3, we have 15 - 3 = 12 electrons. The magnetic quantum number m can have integer values from -j to +j, where j is a half-integer representing the total angular momentum quantum number of the electron. In this case, j can be equal to 1/2, 3/2, 5/2, and so on. For the lowest value of j, which is 1/2, the magnetic quantum number m can have two values, +1/2 and -1/2. Thus, there are two electrons with m = 0. The number of electrons with m = 0 is equal to the number of electrons in the lowest energy level, which is the 1s orbital. In this case, two electrons occupy the 1s orbital, and both have m = 0.
Explanation:
A cylinder, with a piston pressing down with a constant pressure, is filled with 1.90 moles of a gas (n1), and its volume is 49.0 L (V1). If 0.500 mole of gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder? Express your answer with the appropriate unit
Answer:
the final volume of the gas inside the cylinder after 0.500 mole has leaked out is 37.0 L.
Explanation:
The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Since the pressure and temperature are constant, we can assume that they remain constant during the process of the gas leaking out. So, the initial state (1) and the final state (2) of the gas can be described as follows:
(1) PV1 = n1RT
(2) PV2 = (n1 - 0.500)RT
Now, we can find the final volume of the gas by substituting the known values into the equation and solving for V2:
V2 = (n1RT)/P = (1.90 * 8.31 * T)/P
V2 = (1.90 * 8.31 * T)/P = (1.90 * 8.31 * T)/P = 49.0
V2 = 49.0 L * (1.90 - 0.500) / 1.90
V2 = 37.0 L
For parts of the free-response question that require calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your wo
your answer. Examples and equations may be included in your answers where appropriate.
Н
H:O:H
H:C:H
Н
:CI:
:CI:C:CI:
:CI:
Answer the following questions about CH, and CC14. The Lewis electron-dot diagrams for molecules of the compounds are shown above.
(a) Which compound has the higher boiling point? Justify your answer. The type(s) of intermolecular force(s) in both substances should be included in your answer.
The CCl4 molecule is larger and has more electrons hence it is more polarizable and has a larger boiling point
Does higher molar mass imply a higher boiling point?A higher molar mass does imply a higher boiling point for a substance, assuming that the other conditions (pressure, temperature, etc.) are constant.
This is because the boiling point is a measure of the temperature at which a substance changes from a liquid to a gas at a given pressure. As the molar mass of a substance increases, the intermolecular forces between the molecules tend to be stronger, which makes it more difficult to separate the molecules and vaporize the substance. As a result, the boiling point generally increases with increasing molar mass.
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Ni(NO3)2(aq)+Na2S(aq)→NiS(s)+NaNO3(aq) Express your answer as a chemical equation including phases.
Answer:
Ni(NO3)2 (aq) + Na2S (aq) -> NiS (s) + 2NaNO3 (aq)
Explanation:
How many molecules (or formula units) are in each sample? Express your answer in molecules to three significant figures.
Part A: 60.1 g H2O
N = ______ molecules H20
Part B: 127 mg Na3PO4
N = ______ molecules Na3PO4
Part C: 29.6 kg C6H12O6
N = _______ molecules C6H12O6
Part D: 46.9 g N2
N = _______ molecules N2
The Avogadro constant, which is 6.022 x 10²³ molecules/mol, must be utilized in order to determine the number of formula units or molecules present in a sample.
The Avogadro constant is what?The number of entities (such as atoms, molecules, or ions) that make up one mole of a substance is represented by the Avogadro constant, a fundamental physical constant. The letter "NA" stands for the Avogadro constant value, which is approximately 6.022 x 10²³ entities per mole. This indicates that a substance has exactly 6.022 x 10²³ entities in a single mole.
Part A:
Molar mass of H₂O = 18.015 g/mol
Number of moles of H₂O = 60.1 g / 18.015 g/mol
= 3.33 mol
Number of molecules of H₂O = 3.33 mol x 6.022 x 10²³ molecules/mol
= 2.00 x 10²⁴ molecules
N = 2.00 x 10²⁴ molecules H₂O
Part B:
Molar mass of Na₃PO₄ = 163.94 g/mol
Number of moles of Na₃PO₄ = 127 mg / 1000 mg/g / 163.94 g/mol
= 7.73 x 10⁻⁴ mol
Number of formula units of Na₃PO₄ = 7.73 x 10⁻⁴ mol x 6.022 x 10²³ formula units/mol = 4.65 x 10²⁰ formula units
N = 4.65 x 10²⁰ formula units Na₃PO₄
Part C:
Molar mass of C₆H₁₂O₆ = 180.16 g/mol
Number of moles of C₆H₁₂O₆ = 29.6 kg / 1000 g/kg / 180.16 g/mol
= 0.164 mol
Number of molecules of C₆H₁₂O₆ = 0.164 mol x 6.022 x 10²³ molecules/mol = 9.88 x 10²² molecules
N = 9.88 x 10²² molecules C₆H₁₂O₆
Part D:
Molar mass of N₂ = 28.02 g/mol
Number of moles of N₂ = 46.9 g / 28.02 g/mol
= 1.67 mol
Number of molecules of N₂ = 1.67 mol x 6.022 x 10²³ molecules/mol
= 1.00 x 10²⁴ molecules
N = 1.00 x 10²⁴ molecules N₂
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Calculate the percent yield of Cl2(g) in the electrolytic decomposition of hydrogen chloride if 25.8 g of HCl produces 13.6 g of chlorine gas: 2 HCl (aq) → Cl2 (g) + H2 (g)
The percent yield of Cl2 in the electrolytic decomposition of HCl is 54.18%.
What is electrolytic decomposition?Electrolytic decomposition is a type of chemical reaction that uses electricity to break down a compound into its component elements or ions. This process involves passing an electric current through an electrolyte, which is a substance that conducts electricity when dissolved in a solvent or melted.
To calculate the percent yield of Cl2 in the electrolytic decomposition of HCl, we need to compare the actual yield of Cl2 obtained in the experiment to the theoretical yield of Cl2 that could be obtained if all the HCl reacted completely.
After balancing,
2 HCl (aq) → Cl2 (g) + H2 (g)
The molar mass of HCl is 36.46 g/mol, so 25.8 g of HCl is equal to 25.8 g / 36.46 g/mol = 0.708 mol of HCl.
According to the balanced equation, 2 moles of HCl should produce 1 mole of Cl2, so the theoretical yield of Cl2 can be calculated as:
Theoretical yield of Cl2 = 0.5 × 0.708 mol = 0.354 mol
The molar mass of Cl2 is 70.90 g/mol, so the theoretical yield of Cl2 in grams is:
Theoretical yield of Cl2 = 0.354 mol × 70.90 g/mol = 25.1 g
The actual yield of Cl2 obtained in the experiment is 13.6 g.
The percent yield of Cl2 can be calculated as:
Percent yield = (Actual yield / Theoretical yield) × 100%
Percent yield = (13.6 g / 25.1 g) × 100%
Percent yield = 54.18%
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Platinum is a transition metal and forms two different ions, Pt2+ and Pt4+. Write the formulas for the compounds for each platinum ion with bromide ions.
The formulas for the compounds formed between platinum ions and bromide ions are Platinum (II) bromide (PtBr2) and Platinum (IV) bromide (PtBr4)
In both of these compounds, the bonding between the platinum ion and the bromide ions is primarily ionic in nature.
In platinum (II) bromide (PtBr2), each platinum ion is surrounded by two bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +2 charge, and the two bromide ions have a -1 charge each, so the overall charge of the compound is neutral.
In platinum (IV) bromide (PtBr4), each platinum ion is surrounded by four bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +4 charge, and the four bromide ions have a -1 charge each, so the overall charge of the compound is neutral.
The bond between the platinum ion and the bromide ions is a result of the attraction between their opposite charges.
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In the 1920s, western powers began to expand their influence in the middle east primarily due to __________. A. The discovery of oil in the regionb. The rising number of terrorist attacks against the westc. European desires to create a jewish homelandd. Rising fundamentalist movements in iran and saudi arabia please select the best answer from the choices provided. Abcd.
In the 1920s, western powers began to expand their influence in the middle east primarily due to A. The discovery of oil in the region.
The Role of Oil in the Expansion of Western Powers in the Middle East during the 1920sIn the 1920s, the Western powers, such as Britain and France, began to expand their influence in the Middle East primarily due to the discovery of oil in the region. The discovery of oil brought enormous economic and strategic importance to the region, and the Western powers sought to secure their access to this valuable resource. The discovery of oil also helped to modernize the region, as the Western powers invested in infrastructure development, such as pipelines, ports, and railways, which facilitated the transportation of oil and other goods. The Western powers also sought to protect their interests in the region by establishing protectorates, such as Kuwait and Bahrain, and by dividing up the former Ottoman Empire into new nation-states that would be more amenable to Western influence. This led to a backlash from some in the region, who saw the Western powers as meddling in their affairs, and who called for greater independence and self-determination. Nonetheless, the discovery of oil in the region had a profound impact on the political and economic development of the Middle East and continues to shape the region's geopolitics today.
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2.How might the structure of molecules help scientists determine how they interact with other molecules?
According to the molecular geometry, with the help of structure of molecules which provide information on site of attachment with other molecules, one can determine their mode of reaction.
What is molecular geometry?Molecular geometry can be defined as a three -dimensional arrangement of atoms which constitute the molecule.It includes parameters like bond length,bond angle and torsional angles.
It influences many properties of molecules like reactivity,polarity color,magnetism .The molecular geometry can be determined by various spectroscopic methods and diffraction methods , some of which are infrared,microwave and Raman spectroscopy.
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Answer: The shape of a molecule helps to determine its properties, which affect how a molecule interacts with other molecules, such as polarity and bonding.
Calculate the mass of iron(III) oxide that contains a trillion oxygen atoms.
Answer:
7,3g
Explanation:
8.336x10^-13 moles x 88 g/mol =7,3 g
Answer:
0.13 grams.
Explanation:
To calculate the mass of iron(III) oxide that contains a trillion oxygen atoms, we first need to determine the molar mass of iron(III) oxide, also known as ferric oxide or Fe2O3. The molar mass of Fe2O3 is approximately 159.69 g/mol.
Next, we need to convert the number of oxygen atoms to moles using Avogadro's number, which is 6.022 x 10^23 atoms/mol. One mole of Fe2O3 contains two moles of oxygen, so the number of moles of Fe2O3 can be calculated as:
(1 trillion oxygen atoms) / (2 * 6.022 x 10^23 atoms/mol) = 8.37 x 10^-12 moles
Finally, we can calculate the mass of iron(III) oxide as:
(8.37 x 10^-12 moles) * (159.69 g/mol) = approximately 0.13 g
So, the mass of iron(III) oxide that contains a trillion oxygen atoms is approximately 0.13 grams.
Allen i little forget about this Sorry
