Answer:
Positive charge is attracted to the neutral object.
Explanation:
Recall ; Like charges repel, unlike charges attract. This phrase simply means (positive (+) is attracted to negative (-ve) and vuc versa while both positive, positive and negative, negative charge repel.
For a neutral object. The quantity of positive charge equals the quantity of negative charges. This simply means a neutral object contains charges as well, which are usually scattered or randomly aligned.
Therefore, when a positive charge is brought near a neutral body, the order of alignment of the charges change, with the negative charge all moving towards the direction of the positively charged body and the positive charges in the neutral body aligning in the opposite direction.
The charge will be attracted.
Understanding the force between charges.
As you may know, opposite charges attract (and equal charges repel).
So, when you put a positive charge near a neutral material, all the negative charges in the material will move towards the surface of the material closer to the positive charge (and the positive charges in the material will move away).
Now the charge in the material is not homogeneous, so the positive charge will see a negatively charged surface near it, and it will be attracted to that surface.
Thus we can conclude that as a positive charge is brought near a neutral, insulating piece of material, the charge will be attracted towards it.
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A ball rolls across a smooth surface at a steady 0.5 m/s. What is its acceleration? m/s^2?
Answer:
0m/s²
Explanation:
The acceleration of the given body whose motion has been described will be zero.
This is because the body moves with a constant velocity.
Acceleration is defined as the rate of change of velocity with time.
Since in this problem, the velocity is not changing per time, then the acceleration would be zero.
A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.
which two types of potentional energies would be types of mechancial energies
Answer:
Gravitation Potential Energy and Elastic Potential Energy
Explanation:
PE=abbreviation for potential energy
PE is a mechanical energy like KE is. There are two types of PE in high school physics (do not talk about other PE's like chemical PE).
Elastic PE is like the stored energy for example in a pole vault competition, the Elastic PE is stored in the pole before the vaulter goes over the desired height. (Energy stored in ELASTIC object ONLY) (commonly on the 11th grade regents springs are used to represent elastic PE)
Gravitational PE can be calculated through the formula PE=mgh although some people substitute the PE with a U. (ENERGY STORED IN OBJECT'S HEIGHT)
What forces are related to a person pushing a large crate accross the floor?
Answer:
98
Explanation:
Answer:
friction, air resistance
Explanation:
Modern psychology traces its roots back
Answer:
Psychology traces its roots back through recorded history to India, China, the Middle East, and Europe. Buddha and Confucius focused on the powers and origin of ideas. ... The ideas of Bacon and Locke contributed to the development of modern empiricism.
Explanation:
A 0.5 m3 container is filled with a fluid whose specific volume is 0.001 m3/kg. At standard gravitational acceleration, the contents of this container weigh:
Answer: the contents of this container weighs 4905 kg.m/s²
Explanation:
Given that;
volume of a container V = 0.5 m³
we know that standard gravitational acceleration g = 9.81 m/s²
specific volume of liquid filled in the container v = 0.001 m³/kg
now we express the equation for weight of the container.
W = mg
W = (pV)g
W = Vg / ν
so we substitute
W = (0.5 m³)(9.81 m/s ) / 0.001 m³/kg
W = 4.905 / 0.001
W = 4905 kg.m/s²
Therefore, the contents of this container weighs 4905 kg.m/s²
2. A rock is shot straight up into the air with a slingshot that had been stretched 0.30 m. Assume
no air resistance.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
m= 500 g
A
• Y=0
Position A
Position
System/Flow
O
k=100N
- 100
a 옝
&x=0.30m
Om
KE PE, PE
KE PE, PEe Ethermal
Initial
Final
b. Quantitative Energy Conservation Equation
C
Determine the greatest height the rock could reach.
Answer:
e
Explanation:
Which option is an example of a good blackbody radiator?
A. A mirror that reflects the light that strikes it
B. A classroom full of students in a school
C. A stove burner that glows red when it is turned on
D. Water that bends the light that enters it
Answer: C. A stove burner that glows red when it is turned on
Explanation:
I did the quiz
Which common characteristic of planets do Saturn and Earth share?
They have rings.
They have moons.
They are made of rock.
They have thick atmospheres.
The common characteristics of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.
What is moons of planets?Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.
The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.
Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.
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glucose+oxygen--->carbon dioxide+water+energy= What reaction??
Fill in the answers to describe this chemical equation.
Name the reactants in this reaction.
Name the products in this reaction.
How many oxygen atoms are involved in this reaction?
Is this equation balanced, and how can you tell?
Is this reaction endothermic or exothermic, and how can you tell?
I REALLY NEED HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
combustion reaction
glucose,oxygen
carbon dioxide,water,energy
8
no. required balanced equation is:
C6H12O6+6O2--->6CO2+6H2O+energy
endothermic as it needs heat in the form of sunlight.
Two 10-cm-diameter charged rings face each other, 23.0 cm apart. Both rings are charged to 40.0 nC . What is the electric field strength You may want to review (Pages 641 - 643) . For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Charge on a Van De Graaff.
The strength of the electric field is 1.10×10^4 N/C.
The data is sent to us.
r = d/2 = 0.1/2 = 0.05 m, d = 10 cm = 0.1 m, and z = 17 cm = 0.17 m
Q = 40 nC = 40×10^-9 C
A) in the middle of the two circles
Since the electric fields created by the two rings are directed in opposite directions, there is no electric strength.
B) midway down the left ring
Electric strength is equal to the sum of the electric fields created by the left and right rings.
Electric strength is equal to E leftring + E rightring, which equals 0 plus kQz/(r2 + z2).
Electric strength = k×Q×z/(r^2 + z^2)^
Electric strength = 9×10^9×40×10^-9×0.17/(0.05^2 + 0.17^2)
Electric strength= 1.10×10^4 N/C
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Two marbles, one twice as massive as the other, are dropped from the same height. When they strike the ground, how does the kinetic energy of the more massive marble compare to that of the other marble
Answer: The more massive one will have larger kinetic energy.
Explanation:
We know that when we drop an object, the acceleration of the object will be equal to the gravitational acceleration.
a(t) = -9.8m/s^2
And to get the velocity, we need to integrate over time, to get:
v(t) = (-9.8m/s^)*t + v0
Where v0 is the initial speed of the object.
You can see that the mass of the object does not affect the velocity of it.
Then when we drop two marbles of different masses from the same height, we know that the final velocity of them will be equal.
Now, we also know that the kinetic energy can be written as:
K = (m/2)*v^2
where m is the mass, and v is the velocity.
Then the kinetic energy of the marble with less mass can be written as:
k = (m/2)*v^2
And the kinetic energy for the more massive one is:
K = (M/2)*v^2
And we know that both of them have the same velocity, and M is larger than m, then we can conclude that the marble with larger mass will have larger kinetic energy.
A 110 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be done on the hoop to stop it
Answer:
the work that must be done to stop the hoop is 2.662 J
Explanation:
Given;
mass of the hoop, m = 110 kg
speed of the center mass, v = 0.22 m/s
The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;
W = ΔK.E
W = ¹/₂mv²
W = ¹/₂ x 110 x 0.22²
W = 2.662 J
Therefore, the work that must be done to stop the hoop is 2.662 J
The amount of work that must be done to stop a hoop of mass 110 kg moving with s speed of 0.220 m/s is 2.662 J
Work can be defined as the ability or the capacity to perform work. Work is also the measure of energy of a body. The S.I unit of work is Joules (J)
From the question, The kinetic energy of the hoop = The energy required to stop the hoop.Formular for kinetic energy of the hoop is
EK = mv²/2.................... Equation 1
Where EK = Kinetic energy of the hoop, m = mass of the hoop, v = velocity of the hoop.
Given: m = 110kg, v = 0.220 m/s.
Substitute these values into equation 1
EK = 110(0.22)²/2
Ek = 2.662 J.
Therefore, The amount of work that must be done on the hoop to stop it is
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When scientists want to determine the actual age of a fossil, they use_____________
Answer:
Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages. Absolute dating is used to determine a precise age of a fossil by using radiometric dating to measure the decay of isotopes, either within the fossil or more often the rocks associated with it.
A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an amplitude of 0.143 mm and a frequency of 76.9 Hz and is traveling in the negative direction of an x axis. If the wave equation is of the form y(x,t) = ym sin(kx + ωt), what are (a) ym, (b) k, and (c) ω, and (d) the correct choice of sign in front of ω?
Answer:
a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s d. +1
Explanation:
a. ym
Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm
b. k
We know k = wave number = 2π/λ where λ = wavelength.
Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.
So, λ = v/f = √(T/μ)/f
substituting the values of the variables into the equation, we have
λ = √(T/μ)/f
= √(19.6 N/0.512 kg/m)/76.9 Hz
= √(38.28 Nkg/m)/76.9 Hz
= 6.187 m/s ÷ 76.9 Hz
= 0.081 m
= 81 mm
So, k = 2π/λ
= 2π/0.081 m
= 77.6 rad/m
c. ω
ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz
So, ω = 2πf
= 2π × 76.9 Hz
= 483.18 rad/s
d. The correct choice of sign in front of ω?
Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.
rank in terms of momentum
A. A 10,000 kg train car at rest
B. A 100 kg person running at 5 m/s
C. A 1200 kg car going 15 m/s
D. A 15 kg meteor going at a speed of 1000 m/s
Answer:
See the explanation below,
Explanation:
Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.
[tex]P=m*v[/tex]
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
A)
[tex]P = 10000*0\\P=0[/tex]
B)
[tex]P=100*5\\P=500[kg*m/s][/tex]
C)
[tex]P=1200*15\\P=18000[kg*m/s][/tex]
D)
[tex]P=15*1000\\P=15000[kg*m/s][/tex]
From higher to lower momentum
C,D,B,A
At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 300 N/C. At a distance r2 from the charge, the field has a magnitude of 160 N/C. Find the ratio r2/r1.
Answer:
the ratio of r₂/r₁ is 1.37.
Explanation:
Given;
magnitude of electric field strength at a distance r₁, E₁ = 300 N/C
magnitude of electric field strength at a distance r₂, E₂ = 160 N/C
Electric field strength is given as;
[tex]E = \frac{kQ}{r^2} \\\\E_1r_1^2 = E_2r_2 ^2\\\\\frac{E_1}{E_2} = \frac{r_2^2}{r_1^2} \\\\\frac{E_1}{E_2} =( \frac{r_2}{r_1})^2\\\\\sqrt{\frac{E_1}{E_2} } = \frac{r_2}{r_1}\\\\\frac{r_2}{r_1} = \sqrt{\frac{300}{160} }\\\\\frac{r_2}{r_1} =1.37[/tex]
Therefore, the ratio of r₂/r₁ is 1.37.
What happens to the amplitude of the resultant wave when two sound waves with equal amplitude constructively interfere?
Answer:
For two waves of equal amplitude interfering constructively, the resulting amplitude is twice as large as the amplitude of an individual wave. For 100 waves of the same amplitude interfering constructively, the resulting amplitude is 100 times larger than the amplitude of an individual wave.
PLEASE HELP (100)
A block M, with mass of 4 kg, is released from rest and slides down a ramp that is angled at 28° above the horizontal (from the bottom of the ramp). The length of the ramp, d, is 3 meters. How much work is done by the gravitational force as the block slides down the ramp?
Answer:
The work done will be [tex]W=55.27\: J[/tex]
Explanation:
The work equation is given by:
[tex]W=F\cdot x[/tex]
Where:
F is the force due to gravity (weight = mg)
x is the length of the ramp (3 m)
Now, the force acting here is the component of weight in the ramp direction, so it will be:
[tex]F_{x-direction}=mgsin(28)[/tex]
Therefore, the work done will be:
[tex]W=mgsin(28)*3[/tex]
[tex]W=4*9.81*sin(28)*3[/tex]
[tex]W=55.27\: J[/tex]
I hope it helps you!
please genuinely help. 15 pts
:(
A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?
Answer:
Δp = 620 N.s
Explanation:
Newton's second law, was originally conceived as follows:[tex]F = \frac{\Delta p}{\Delta t} (1)[/tex]
In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.for m= constant, it reduces to F= m*a.
Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:[tex]\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)[/tex]
What needs to happen to make electrical current flow in a generator?
Fill in the chart with the correct values of F for each change in the system described in questions
Answer:
We know that the gravitational force F between two masses P and Q, that are separated by a distance R is:
[tex]F = G*\frac{P*Q}{R^2}[/tex]
Where G is the gravitational constant.
a) Mass P is doubled, then we have 2*P instead of P, the new force is:
[tex]F' = G*\frac{(2*P)*Q}{R^2} = 2*(G*\frac{P*Q}{R^2} ) = 2*F[/tex]
b) Now R is doubled, then instead of R, we have 2*R:
[tex]F' = G*\frac{P*Q}{(2*R)^2} = G*\frac{P*Q}{4*R^2} = G*\frac{P*Q}{R^2}*(1/4) = F/4[/tex]
c) Now we replace P by 2*P, and Q by 3*Q
[tex]F' = G*\frac{(2*P)*(3*Q)}{R^2} = 2*3*(G*\frac{P*Q}{R^2} ) = 6*F[/tex]
d) The entire mass of the system is increased by a factor of 4, then both of the individual masses are increased by a factor of 4.
Then we need to replace P by 4*P, and Q by 4*Q.
[tex]F' = G*\frac{(4*P)*(4*Q)}{R^2} = 4*4(G*\frac{P*Q}{R^2} ) = 16*F[/tex]
e) Now we replace R by R/2.
[tex]F' = G*\frac{P*Q}{(R/2)^2} = G*\frac{P*Q}{R^2/4}= 4*G\frac{P*Q}{R^2} = 4*F[/tex]
Two surfaces in contact are moving slowly past each other. As the relative speed between the two surfaces in contact increases, what happens to the magnitude of their coefficient of kinetic friction
Answer:
It begins to increase
Explanation:
As the surfaces move slowly and then increase their relative speeds, the coefficient of kinetic friction begins to increase until it reaches it terminal value in which, it can no longer increase.
Suppose you have a string of length LaTeX: LL clamped down on both sides. Is it possible for the wavelength of a standing wave on this string to equal LaTeX: L/3L / 3
Answer:
Explanation:
For a string of length L clamped down on both ends , for fundamental mode of vibration
2 . λ / 4 = L
= λ / 2 = L
λ = 2 L
For other modes , the formula is
n . λ/2 = L where n is an integer .
λ = 2L / n
if n = 6
λ = 2L / 6
= L/3
So wavelength = L/3 is possible .
How does water move from the surfaces of lakes, rivers, and the ocean directly back into the atmosphere?
A.precipitation
B.evaporation
C.condensation
Answer:
B. Evaporation
Explanation:
Because I am absolutely positive
Please give Brainlyest
1. How many atoms are needed to form a molecule?
Answer:
Answer: 20
Explanation: cause
Explanation:
When two or more atoms link up, they create a molecule. e.g, A molecule of water is made of two atoms of hydrogen (H) and one atom of oxygen (O).
What does a negative velocity indicate about an object's motion? Plz help
Answer:
The sign of the velocity depends on the coordinate system chosen to define the position. A positive velocity simply means that the object is moving in the positive direction, as defined by the coordinate system, while a negative velocity means the object is traveling in the other direction.
- Hope this helps!
Why don't we use x-ray to communicate information?
Answer: The difficulty comes in the modulation, and in the fact that X-rays can't be transmitted via wires or fiber.
Explanation: Mark me as brainlisti
a projectile is fired so that when it reaches the maximum height h it has speed vtop when the projectile is at h/2 the speed is 2vtop at what angle is the projectile fired
Answer:
Explanation:
Let the velocity of firing be u at angle θ
At maximum height velocity will be equal to horizontal component of initial velocity or vcosθ
So , vtop = v cosθ
At height h/2
vertical component of velocity v₂
v₂² = (usinθ)² - 2 g . h/2
v₂² = u²sin²θ - gh
horizontal component of velocity at height h/2 = u cosθ
velocity at height h / 2
= √ ( u²sin²θ - gh + u² cos²θ)
Given
√ ( u²sin²θ - gh + u² cos²θ) = 2 vtop
u²sin²θ - gh + u² cos²θ = 4 v²top = 4 u² cos²θ
u²sin²θ - gh = 3 u² cos²θ
At height h , vertical component of velocity is zero
0 = u²sin²θ - 2gh
gh = u²sin²θ / 2
u²sin²θ - u²sin²θ / 2 = 3 u² cos²θ
u²sin²θ / 2 = 3 u² cos²θ
Tan²θ = 6
Tanθ = 2.45
θ = 68⁰ .
6.A nurse pushes a woman in a wheelchair at a constant acceleration up a ramp for a period of 17.5 s. At the base of the ramp, the wheel chair is at rest, and at the top of the ramp, the
wheelchair has a velocity of 0.50 m/s. The woman and her wheelchair have a combined
mass of 65.0 kg. What is the magnitude of the net force on the woman and her wheelchair
as they acceferate up the ramp?
(A) 0.27 N
(B) 1.9 N
(C) 2.3 N
Answer:
The answer is :(B) 1.9 N
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