Suppose you are starting your own company selling chocolate covered strawberries. You decide to sell the milk chocolate covered strawberries for a profit of $2.25/box and the white chocolate covered strawberries at $2.50/box. Market tests and available resources, however, have given you the following constraints. The combined production level should not exceed 800 boxes per month. The demand for the white chocolate is no more than half the demand for milk chocolate strawberries. The production level for white chocolate should be less than or equal to 200 boxes.

Using the information in the problem, write the constraints. Let x represent number of milk chocolate boxes produced, and y represent number of white chocolate boxes produced.

Total number of chocolate boxes that can be produced: x+y Answer
≤
Answer
800

Restrictions based on demand of each: y Answer
Answer
200
x

Maximum amount of white chocolate production: y Answer
≤
Answer
200

Minimum amount of milk chocolate production: x Answer
Answer

Minimum amount of white chocolate production: y Answer
Answer

Vertices of the feasible region: (0,0)(400, Answer
)( Answer
, Answer
)( Answer
,0)

Optimization equation: Profit = Answer
x+ Answer
y

Your maximum profit is $ Answer
. You should produce Answer
boxes of milk chocolate and Answer
boxes of white chocolate.

Answer:

8 units^2

Step-by-step explanation:

The area of a tringle is 1/2 bh. The base, LK, measures 4 while the height is also 4(you can get these values by counting the squares). This means the area is:

1/2 * (4)(4) = 1/2 * 16 = 8 units^2

Answer:

Should be (B).

8.5

ED2021

Answer: B

Step-by-step explanation:

Answer:

9/25

Step-by-step explanation:

3 novels , 1 bio , 1 poetry = 5 books

P( novel) = novels / books

               = 3/5

Book is returned

3 novels , 1 bio , 1 poetry = 5 books

P( novel) = novels / books

               = 3/5

P(novel, return, novel) = 3/5 * 3/5 = 9/25

=======================================================

Explanation:

Let's solve the given equation for the variable 'a'

a(2+1) = 36

a*(3) = 36

3a = 36

a = 36/3

a = 12

There are 12 students in the class. This must mean there are 12 lemonades, because each person gets 1 lemonade.

Since there are 24 cookies, each student gets 24/12 = 2 cookies

Since each student gets 2 cookies and 1 lemonade, this is where the "2+1" comes from in the original equation. Each student gets 3 items total, which explains the notation 3a.

The value of 'a' from the given expression would be 13.

Given that;

At snack time, Ms. Rivera passes out 24 cookies to her class. She also passes out 1 glass of lemonade to each student.

Here, the equation is,

a(2+1)=36

Solve for a;

a × 3 = 36

3a = 36

Divide both sides by 3;

a = 36/3

a = 13

Thus, the value of a is 13.

Learn more about the equation visit:

brainly.com/question/28871326

#SPJ3

Answer:

6 97/100 bags

Step-by-step explanation:

4 1/10 ⋅ 1 7/10 = ?

41/10 ⋅ 17/10 = 697/100

697/100 = 6 97/100

6 97/100 bags

Answer:

697/100 bags

or

6 97/100 bags

Step-by-step explanation:

it is fractions. just plain and simple.

when you eat a pizza slice, it is usually one of 8 slices that make the whole pizza. 1/8 or one 8th. meaning that the whole thing is 8/8 or eight 8ths.

the same for 10ths or any other fractions.

4 1/10 bags = 41/10 bags

1 7/10 times = 17/10 times

and now we multiply fractions, as 17/10 times is similar to 2 times or 3 times something - we multiply by this factor.

41/10 × 17/10

as we learned in early elementary school : numerators (top part of the fraction) are multiplied with each other, and denominators (bottom part) are multiplied with each other. and then we simplify the result as much as possible.

41/10 × 17/10 = (41×17) / (10×10) = 697/100

no simplification is possible, sadly.

but that means he used almost 7 bags of hot dog buns.

exactly 6 full bags and 97/100 of the 7th bag.

so, either

697/100 bags

or

6 97/100 bags

or as alternative (not wanted here in this example but just FYI)

6.97 bags

Answer:

Im pretty sure its 1,000 miles (dont forget the unit)

Step-by-step explanation:

Determine if this problem is a inverse variation or direct variation problem! This means that:

equation would be:

1=40

25=x

cross multiply*

x=25*40

x=1,000 miles apart! (dont forget the unit)

If this doesnt work then try this equation!

1=40

25=x

Multiply 1*40 and 25 *x

40=25x......    

40/25= 1.6

x=1.6! (Extra step)

Cheers!

Answer: 100 Miles

Step-by-step explanation: took the miles and got it correct.

(Also it's 2.5 inches apart, not 25.)

Answer:

✔ a strong positive

✔ weaken

✔ decrease

ED2021

Answer:

The scatterplot including only the blue data points shows  

✔ a strong positive

association. Including the orange data point at (86, 0.4) would  

✔ weaken

the correlation and  

✔ decrease

the value of r.

Step-by-step explanation:

Answer:

y = -x + 5

Step-by-step explanation:

The point is in quadrant 2, so the line must pass through points that look like (a, 0) and (0, a) where a is a positive number.  The slope of such a line is -1.

If (x, y) is a point on the line, then the slope between points (x, y) and (-5, 10) is 1, and you can write

[tex]\frac{y-10}{x-(-5)}=-1\\y-10 = -1(x+5)\\y-10=-x-5\\y=-x+5[/tex]

Answer:

0.2725

0.0431

Step-by-step explanation:

The distribution here is a poisson distribution :

λ = 1.3

The poisson distribution :

p(x) = [(e^-λ * λ^x)] ÷ x!

Expected probability of finding male with 0 accident ; x = 0

p(0) = [(e^-1.3 * 1.3^0)] ÷ 0!

p(0) = [0.2725317 * 1] ÷ 1

p(0) = 0.2725317

= 0.2725

2.)

P(x ≥ 4) = 1 - P(x < 4)

P(x < 4) = p(x = 0) + p(x. = 1) + p(x = 2) + p(x = 3)

p(x = 0) =  p(0) = [(e^-1.3 * 1.3^0)] ÷ 0! = 0.2725

p(x = 1) = p(1) = [(e^-1.3 * 1.3^1)] ÷ 1! = 0.35429

p(x = 2) = p(2) = [(e^-1.3 * 1.3^2)] ÷ 2! = 0.23029 p(x = 3) = p(3) = [(e^-1.3 * 1.3^3)] ÷ 0! = 0.09979

P(x < 4) = 0.2725 + 0.35429 + 0.23029 + 0.09979 = 0.95687

P(x ≥ 4) = 1 - 0.95687 = 0.0431

Answer:

rt3/2

Step-by-step explanation:

first off cosine is the x coordinate

now if you do't want to use a calculator, you can use use the unit circle.

360 - 330 = 30 (360 degrees is a whole circle)

a 30 60 90 triangle is made, then use the law for 30 60 90 triangles:

if the shortest leg is x, the other leg is x*rt3 and the hypotenuse is 2x.

Answer:

D

Step-by-step explanation:

cos 330 = cos (360-330)

= cos 30

= √3 /2

Answer:

option 2

Step-by-step explanation:

Answer:

20 students

Step-by-step explanation:

Step 1:

Calculate the percentage of students who brought oranges by taking away the percentage of students who brought bananas and apples from the total percentage of students.

100-(20+35)

=45

Step 2:

Equate the percentage of students who brought oranges to the number of students who brought oranges

45%=9

100%

(100×9)/45

=20 students

Answer:

0

Step-by-step explanation:

We have two points so we can use the sloe formula

m = (y2-y1)/(x2-x1)

   = ( 10-10)/(1-4)

  = 0/ -3

  = 0

Answer:

Slope is 0

explanation:

Slope is the same as gradient.

Formular:

[tex]{ \boxed{ \bf{slope = \frac{y _{2} - y _{1}}{x _{2} - x _{1} } }}}[/tex]

Substitute the variables:

[tex]{ \tt{slope = \frac{10 - 10}{1 - 4} }} \\ \\ = { \tt{ \frac{0}{ - 3} }} \\ = 0[/tex]

Answer:

0.475: Z = -0.062706778

0.525: Z = 0.062706778

Step-by-step explanation:

Answer:

34

Step-by-step explanation:

let the missing value is x

(25+x) /2 = 29.5

25+x = 29.5(2)

25+x = 59

x = 59-25

x = 34

Answer:

a) P(79 <= P <= 81) = 0.9968

b) P( X >  81 ) = 0.0002

Step-by-step explanation:

mean value = 75 GPa

standard deviation = 1.7 GPa

a) Determine P(79 <= P <= 81)

given that : n = 25

attached below is the detailed solution

P(79 <= P <= 81) = 0.9968

b) Determine how likely the sample mean diameter will exceed 81

given that n = 36

mean diameter = 81

P( X >  81 ) = 0.0002

Answer:

m=[tex]7\sqrt3[/tex]

n=7

Step-by-step explanation:

Hi there!

We are given a right triangle (notice the 90°) angle, the measure of one of the acute angles as 60°, and the measure of the hypotenuse (the side OPPOSITE from the 90 degree angle) as 14

We need to find the lengths of m and n

Firstly, let's find the measure of the other acute angle

The acute angles in a right triangle are complementary, meaning they add up to 90 degrees

Let's make the measure of the unknown acute angle x

So x+60°=90°

Subtract 60 from both sides

x=30°

So the measure of the other acute angle is 30 degrees

This makes the right triangle a special kind of right triangle, a 30°-60°-90°  triangle

In a 30°-60°-90° triangle, if the length of the hypotenuse is a, then the length of the leg (the side that makes up the right angle) opposite from the 30 degree angle is [tex]\frac{a}{2}[/tex], and the leg opposite from the 60 degree angle is [tex]\frac{a\sqrt3}{2}[/tex]

In this case, a=14, n=[tex]\frac{a}{2}[/tex], and m=[tex]\frac{a\sqrt3}{2}[/tex]

Now substitute the value of a into the formulas to find n and m to find the lengths of those sides

So that means that n=[tex]\frac{14}{2}[/tex], which is equal to 7

And m=[tex]\frac{14\sqrt3}{2}[/tex], which simplified, is equal to [tex]7\sqrt3[/tex]

Hope this helps!

Step-by-step explanation:

f(x)=log(x)

     =d(log(x)/dx)

=>y=1/x

The answer is A and D

good luck

Answer:

A) m∠A ≅ m∠C, m∠B ≅ m∠D

Step-by-step explanation:

If both pairs of opposite angles are congruent, then the figure is a parallelogram.

Answer:

1 + 7n

Step-by-step explanation:

7-(3n+6)+10n​

7 - 3n - 6 + 10 n

1 - 7n

Answered by Gauthmath

Answer:

(3/2,10)

Step-by-step explanation:

Mid point is ((10-7)/2,(13+7)/2)=(1.5,10)

0.08 cm/min

Step-by-step explanation:

Given:

[tex]\dfrac{dV}{dt}=5\:\text{cm}^3\text{/min}[/tex]

Find [tex]\frac{dr}{dt}[/tex] when diameter D = 20 cm.

We know that the volume of a sphere is given by

[tex]V = \dfrac{4\pi}{3}r^3[/tex]

Taking the time derivative of V, we get

[tex]\dfrac{dV}{dt} = 4\pi r^2\dfrac{dr}{dt} = 4\pi\left(\dfrac{D}{2}\right)^2\dfrac{dr}{dt} = \pi D^2\dfrac{dr}{dt}[/tex]

Solving for [tex]\frac{dr}{dt}[/tex], we get

[tex]\dfrac{dr}{dt} = \left(\dfrac{1}{\pi D^2}\right)\dfrac{dV}{dt} = \dfrac{1}{\pi(20\:\text{cm}^2)}(5\:\text{cm}^3\text{/min})[/tex]

[tex]\:\:\:\:\:\:\:= 0.08\:\text{cm/min}[/tex]

Answer:

(x-1)^2 + (y+4)^2 = 4

Step-by-step explanation:

The equation for a circle is given by

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-1)^2 + (y- -4)^2 = 2^2

(x-1)^2 + (y+4)^2 = 4

First, write out the equation in slope intercept form.

-3y= -2x+6

y= 2/3x -2

The slope of the equation is 2/3, m.

Substitute the slope and coordinate into y=mx+b. Since it’s parallel, the slope remains the same.

6= 2/3(2)+b

6= 4/3+b

14/3=b

y= 2/3x + 14/3

Answer:

I think its 2 hours 30 minutes

Step-by-step explanation:

Answer:

1:3

Step-by-step explanation:

27 : 81

Divide each side by 27

27/27 : 81/27

1:3

Answer:

The number of hits would follow a binomial distribution with [tex]n =10,\!000[/tex] and [tex]p \approx 4.59 \times 10^{-6}[/tex].

The probability of finding [tex]0[/tex] hits is approximately [tex]0.955[/tex] (or equivalently, approximately [tex]95.5\%[/tex].)

The mean of the number of hits is approximately [tex]0.0459[/tex]. The variance of the number of hits is approximately [tex]0.0459\![/tex] (not the same number as the mean.)

Step-by-step explanation:

There are [tex](26 + 10)^{6} \approx 2.18 \times 10^{9}[/tex] possible passwords in this set. (Approximately two billion possible passwords.)

Each one of the [tex]10^{9}[/tex] randomly-selected passwords would have an approximately [tex]\displaystyle \frac{10,\!000}{2.18 \times 10^{9}}[/tex] chance of matching one of the users' password.

Denote that probability as [tex]p[/tex]:

[tex]p := \displaystyle \frac{10,\!000}{2.18 \times 10^{9}} \approx 4.59 \times 10^{-6}[/tex].

For any one of the [tex]10^{9}[/tex] randomly-selected passwords, let [tex]1[/tex] denote a hit and [tex]0[/tex] denote no hits. Using that notation, whether a selected password hits would follow a bernoulli distribution with [tex]p \approx 4.59 \times 10^{-6}[/tex] as the likelihood of success.

Sum these [tex]0[/tex]'s and [tex]1[/tex]'s over the set of the [tex]10^{9}[/tex] randomly-selected passwords, and the result would represent the total number of hits.

Assume that these [tex]10^{9}[/tex] randomly-selected passwords are sampled independently with repetition. Whether each selected password hits would be independent from one another.

Hence, the total number of hits would follow a binomial distribution with [tex]n = 10^{9}[/tex] trials (a billion trials) and [tex]p \approx 4.59 \times 10^{-6}[/tex] as the chance of success on any given trial.

The probability of getting no hit would be:

[tex](1 - p)^{n} \approx 7 \times 10^{-1996} \approx 0[/tex].

(Since [tex](1 - p)[/tex] is between [tex]0[/tex] and [tex]1[/tex], the value of [tex](1 - p)^{n}[/tex] would approach [tex]0\![/tex] as the value of [tex]n[/tex] approaches infinity.)

The mean of this binomial distribution would be:[tex]n\cdot p \approx (10^{9}) \times (4.59 \times 10^{-6}) \approx 0.0459[/tex].

The variance of this binomial distribution would be:

[tex]\begin{aligned}& n \cdot p \cdot (1 - p)\\ & \approx(10^{9}) \times (4.59 \times 10^{-6}) \times (1- 4.59 \times 10^{-6})\\ &\approx 4.59 \times 10^{-6}\end{aligned}[/tex].

It looks like the limit you want to find is

[tex]\displaystyle \lim_{x\to\infty} \left(\frac{x+4}{x-1}\right)^{x+4}[/tex]

One way to compute this limit relies only on the definition of the constant e and some basic properties of limits. In particular,

[tex]e = \displaystyle\lim_{x\to\infty}\left(1+\frac1x\right)^x[/tex]

The idea is to recast the given limit to make it resemble this definition. The definition contains a fraction with x as its denominator. If we expand the fraction in the given limand, we have a denominator of x - 1. So we rewrite everything in terms of x - 1 :

[tex]\left(\dfrac{x+4}{x-1}\right)^{x+4} = \left(\dfrac{x-1+5}{x-1}\right)^{x-1+5} \\\\ = \left(1+\dfrac5{x-1}\right)^{x-1+5} \\\\ =\left(1+\dfrac5{x-1}\right)^{x-1} \times \left(1+\dfrac5{x-1}\right)^5[/tex]

Now in the first term of this product, we substitute y = (x - 1)/5 :

[tex]\left(\dfrac{x+4}{x-1}\right)^{x+4} = \left(1+\dfrac1y\right)^{5y} \times \left(1+\dfrac5{x-1}\right)^5[/tex]

Then use a property of exponentiation to write this as

[tex]\left(\dfrac{x+4}{x-1}\right)^{x+4} = \left(\left(1+\dfrac1y\right)^y\right)^5 \times \left(1+\dfrac5{x-1}\right)^5[/tex]

In terms of end behavior, (x - 1)/5 and x behave the same way because they both approach ∞ at a proportional rate, so we can essentially y with x. Then by applying some limit properties, we have

[tex]\displaystyle \lim_{x\to\infty} \left(\frac{x+4}{x-1}\right)^{x+4} = \lim_{x\to\infty} \left(\left(1+\dfrac1x\right)^x\right)^5 \times \left(1+\dfrac5{x-1}\right)^5 \\\\ = \lim_{x\to\infty}\left(\left(1+\dfrac1x\right)^x\right)^5 \times \lim_{x\to\infty}\left(1+\dfrac5{x-1}\right)^5 \\\\ =\left(\lim_{x\to\infty}\left(1+\dfrac1x\right)^x\right)^5 \times \left(\lim_{x\to\infty}\left(1+\dfrac5{x-1}\right)\right)^5[/tex]

By definition, the first limit is e and the second limit is 1, so that

[tex]\displaystyle \lim_{x\to\infty} \left(\frac{x+4}{x-1}\right)^{x+4} = e^5\times1^5 = \boxed{e^5}[/tex]

You can also use L'Hopital's rule to compute it. Evaluating the limit "directly" at infinity results in the indeterminate form [tex]1^\infty[/tex].

Rewrite

[tex]\left(\dfrac{x+4}{x-1}\right)^{x+4} = \exp\left((x+4)\ln\dfrac{x+4}{x-1}\right)[/tex]

so that

[tex]\displaystyle \lim_{x\to\infty} \left(\frac{x+4}{x-1}\right)^{x+4} = \lim_{x\to\infty}\exp\left((x+4)\ln\dfrac{x+4}{x-1}\right) \\\\ = \exp\left(\lim_{x\to\infty}(x+4)\ln\dfrac{x+4}{x-1}\right) \\\\ =\exp\left(\lim_{x\to\infty}\frac{\ln\dfrac{x+4}{x-1}}{\dfrac1{x+4}}\right)[/tex]

and now evaluating "directly" at infinity gives the indeterminate form 0/0, making the limit ready for L'Hopital's rule.

We have

[tex]\dfrac{\mathrm d}{\mathrm dx}\left[\ln\dfrac{x+4}{x-1}\right] = -\dfrac5{(x-1)^2}\times\dfrac{1}{\frac{x+4}{x-1}} = -\dfrac5{(x-1)(x+4)}[/tex]

[tex]\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{x+4}\right]=-\dfrac1{(x+4)^2}[/tex]

and so

[tex]\displaystyle \exp\left(\lim_{x\to\infty}\frac{\ln\dfrac{x+4}{x-1}}{\dfrac1{x+4}}\right) = \exp\left(\lim_{x\to\infty}\frac{-\dfrac5{(x-1)(x+4)}}{-\dfrac1{(x+4)^2}}\right) \\\\ = \exp\left(5\lim_{x\to\infty}\frac{x+4}{x-1}\right) \\\\ = \exp(5) = \boxed{e^5}[/tex]