Answer :
8 units⠀
Step-by-step explanation :
⠀
Here,
Area of the parallelogram is 104 sq. unitsBase length of the parallelogram is 13 units.⠀
We know that,
[tex]{\longrightarrow \qquad{ \mathfrak{ \pmb{Base \times Height = Area_{(Parallelogram)}}}}}[/tex]
⠀
Now, Substituting the values in the formula :
⠀
[tex]{\longrightarrow \qquad{ \sf{ {13 \times Height = 104}}}}[/tex]
⠀
[tex]{\longrightarrow \qquad{ \sf{ {Height = \dfrac{104}{13} }}}}
[/tex]
⠀
[tex]{\longrightarrow \qquad{ \pmb { \frak{Height \: \: {= 8}}}}}[/tex]
⠀
Therefore,
The Height of the parallelogram is 8 units.Question :-
The Area of Parallelogram is 104 units² . Its Base is 13 units . What is the Height of the Parallelogram ?Answer :-
Height of Parallelogram is 8 units .Explanation :-
As per the provided information in the given question, we have been given that the Area of Parallelogram is 104 units² . Its Base is given as 13 units . And, we have been asked to calculate the Height of the Parallelogram .
For calculating the Height , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Parallelogram} \: = \: Base \: \times \: Height \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf { Area \: _{Parallelogram} \: = \: Base \: \times \: Height } [/tex]
[tex] \longmapsto \: \: \: \sf { 104 \: = \: 13 \: \times \: Height } [/tex]
[tex] \longmapsto \: \: \: \sf { \dfrac {104}{13} \: = \: Height} [/tex]
[tex] \longmapsto \: \: \: \sf { 8 \: = \: Height} [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Height \: = \: 8 }} [/tex]
Hence :-
Height of Parallelogram = 8 units .[tex] \underline {\rule {204pt} {4pt}} [/tex]
Additional Information :-
[tex] \begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered} [/tex]
What equation has the solution x=8?
Answer:
X/4 = 2
X=8
8 divided by 4 is 2 and 4x2 is 8
The volume of the right circular cylinder is 144 pi cubic yards. of h, the height of the cylinder is 4 yards, what is r, the radius of the base?
How many unique triangles can be draw waith side lengths id 12 cm and 16 cm, and a 50 degree included angle?
Answer:
the answer for this question is 1
Convert equation to standard form
18) y+1=4/5(x-5)
Answer:
4x - 5y = 25
Step-by-step explanation:
PLS HELP ME ASAP I WILL MARK THE BRAINLIEST
Answer:
Unfortunately I was only able to solve the second question
Step-by-step explanation:
So sorry if I'm wrong but this is what I got:
Volume of a cylinder
V=πr^2h
V=π(4^2)(19)
V=955.04
Lateral S.A.
S.A.=2πrh
S.A.=2π(4)(19)
S.A.=477.52
Total S.A.
S.A.=2πrh+2πr^2
S.A.=2π(4)(19)+2π(4^2)
S.A.=578.05
What is the area of a sector of a circle with a radius of 8 inches and formed by a central angle that measures 80 degrees?
[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=8\\ \theta =80 \end{cases}\implies \begin{array}{llll} A=\cfrac{(80)\pi (8)^2}{360}\implies A=\cfrac{128\pi }{9} \\\\\\ A\approx 44.68~in^2 \end{array}[/tex]
HELP HELP HELPPPPP
thanks lol
Answer:
257mm^2
Step-by-step explanation:
18*(3+15)/2 = 162
4*(15+5) =80
3+5 = 15
total = 257 mm^2
Answer:
Step-by-step explanation:
Area of composite figure:
Shape I:
Shape I is an triangle
base= 3 + 15 + 5 = 23 mm
height = 18 mm
[tex]\boxed{\text{Area of traingle = $\dfrac{1}{2}base*height$}}[/tex]
[tex]= \dfrac{1}{2}*18*23\\\\= 9*23\\\\= 207 \ mm^{2}[/tex]
Shape 2:
Shape 2 is an rectangle.
length = 15 + 5 = 20 mm
width = 4 mm
[tex]\boxed{\text{Area of rectangle = length * width}}[/tex]
= 20 *4
= 80 mm²
Shape 3:
length = 5 mm
widht = 3 mm
Area of shape 3 = 5 * 3 = 15 mm²
Area of the composite shape = 207 + 80 + 15
= 302 mm²
Express 34m,5cm,6mm in millimeters
Answer:
1- 34,000 Millimeters in 34 meters
2- 50 Millimeters in 5 Cm
3- 6mm is already in milimeter form
Step-by-step explanation:
1000 Millimeters are in 1 meter so 34,000 millimeters are in 34 meters
10 millimeters are in 1 CM, so 50 millimeters make up 5 cm
Answer:
34m=34x10³mm=34000mm
5cm=5x10mm=50mm
6mm=6mm
10x - 8y = 4
-5x + 3y = -9
(please explain step by step I don't understand)
Answer:
x = 6
y = 7
Step-by-step explanation:
10x - 8y = 4 ⇒ ( 1 )
-5x + 3y = -9 ⇒ ( 2 )
( 2 ) × 2
2 × ( -5x + 3y = -9 )
-10x + 6y = - 18 ⇒ ( 3 )
( 1 ) + ( 3 )
10x - 8y -10x + 6y = 4 - 18
-2y = - 14
Divide both sides by ( - 2 )
y = 7
Now let us replace y with 7 to find the value of x.
For that, let us use equation ( 1 ).
10x - 8y = 4
10x - 8 × 7 = 4
10x - 56 = 4
10x = 56 + 4
10x = 60
Divide both sides by 10.
x = 6
Answer:
[tex]\boxed{\sf{x=6 \quad y=7}}[/tex]Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
10x-8y=4 and -5+3y=-910x-8y=4
x=2(2y+1)/5
Substitute.
[tex]\sf{-5*\dfrac{2(2y+1)}{5}+3y=-9}[/tex]
Solve.
-y-2=-9
Add by 2 from both sides.
-y-2+2=-9+2
Solve.
-y=-7
Divide by -1 from both sides.
-y/-1=-7/-1
Solve.
Divide the numbers from left to right.
-7/-1=7
y=7
Substitute of y=7.
x=2(2*7+1)/5
PEMDAS stands for:
ParenthesisExponentsMultiplyDivideAddSubtract2(2*7+1)/5
Do parenthesis first.
2*7=14
14+1=15
2(15)/5
Multiply.
2*15=30
Divide.
30/5=6
x=6
Therefore, the correct answer is x=6 and y=7.I hope this helps you! Let me know if my answer is wrong or not.
Help please!!! :')
Given a diameter of a circle at endpoints (8,-7) and (4,5), algebraically find the equation of the circle.
thank you smm <3
Answer:
(x-6)^2 + (y+1)^2=40
Step-by-step explanation:
see image. Use Midpoint Formula to find the center. Then use Distance Formula to find the diameter. Cut the diameter in half to find the radius. Use the circle formula to insert (h,k) the center and r, the radius to find the equation. See image.
Answer: [tex](x - 6)^2 + (y + 1)^2 = 40[/tex]
=========================================================
Explanation:
The x coordinates of the given endpoints are x = 8 and x = 4. Apply the midpoint to them to get [tex]\frac{x_1+x_2}{2} = \frac{8+4}{2} = \frac{12}{2} = 6[/tex] which is the x coordinate of the midpoint. I added them up and divided by 2.
Similar steps will have the y coordinate of the midpoint be
[tex]\frac{y_1+y_2}{2} = \frac{-7+5}{2} = \frac{-2}{2} = -1[/tex]
Overall, the midpoint of those given points is (6, -1)
This is the center of the circle because the two endpoints are part of a diameter.
-------------------------------------------------
Now turn to the template
[tex](x - h)^2 + (y -k )^2 = r^2[/tex]
We will plug in the center (h,k) = (6, -1) and one of the endpoints for (x,y). Let's say we go for (x,y) = (4,5)
This leads us to the following:
[tex](x - h)^2 + (y -k )^2 = r^2\\\\(4 - 6)^2 + (5 - (-1) )^2 = r^2\\\\(4 - 6)^2 + (5 + 1 )^2 = r^2\\\\(-2)^2 + (6 )^2 = r^2\\\\4 + 36 = r^2\\\\r^2 = 40\\\\[/tex]
We don't need to isolate r itself. If you wanted, you could take the square root of both sides to see that the radius is [tex]r = \sqrt{40} \approx 6.3246[/tex]. However, again we don't need to solve for r entirely when forming the circle's equation.
With that [tex]r^2[/tex] value in mind, and the h & k values as well, we go from this template
[tex](x - h)^2 + (y -k )^2 = r^2[/tex]
to this final answer
[tex](x - 6)^2 + (y + 1)^2 = 40[/tex]
Please help, super confused :(
Answer:
Below.
Step-by-step explanation:
The graph shown is f(x).
3. The graph 3 is the same shaped graph as drawn but moved 3 units to the left.
4. The graph 4 is the same shaped graph as drawn but moved 5 units to the right.
Hope this helps.
marty's dog eats about 5 pounds of dog food every four days. what is the rate the dog eats his food in pounds per day?
Answer:
5/4 pounds
Step-by-step explanation:
Using unitary method:
4 days-------5 pounds
1 day---------5/4 pounds
What is (3.14)(87.5)²=____?
Answer:
24040.625
Hope this helped! I'm not good at explaining the steps, but this is the answer.
CAN SOMEONE HELP ME PLSSSSSS I ASKED THIS LIKE 3 TIMES BUT NO ONE ANSWERED.THABKYOU!
Determine the area of the park that is not covered by the wading pool.
Answer:
19.63 m^2
Step-by-step explanation:
This is an Area=pi r^2 equation so it would be 3.14*2.5^2
can someone help me with this queston
Step-by-step explanation:
1) option A OR B AS THEY ARE THE SAME
2) option a
Answer: question 1 is b
Question 2 is a
Step-by-step explanation: hope it helps
in question 1 a and b are the same so choose this or this
What is the best estimate of the area of the figure on the grid if each square has a side length of 1 inch?
12 square inches
O 20 square inches
25 square inches
O 33 square inches
Answer:12 i think
Step-by-step explanation:
Find the following measures and angle measures.
Answer:
Step-by-step explanation:
A sharper buys cat food and bags of 3 pounds her cat eats 3/4 pounds each week how many weeks does one bag last right in multiplication or division problem to represent this  situation
Answer:
Thus, the total food can be eaten by the cat in 4 weeks.Total weight of a bag of cat food = 3 lbs.The number of lbs the cat eats the food = 3/4 lbs each week.We need to find the number of weeks does one bag that is 3 lbs last.Now, the total food we have is 3 and cats eat 1/4th of total food each week.Thus, the total food can be eaten by the cat in 4 weeks.To know more about it, please refer to the link:brainly.com/question/12457996
Step-by-step explanation:
Two pens and one eraser cost $35 and three pens and four erasers cost $65. Find the cost of the pencil and eraser separately.
Answer:
Pencil is $15 and erasers are $5
Ben used 130. 2 pounds of gravel in his front yard and 110. 4 pounds in his back yard. How many more pounds of gravel does Ben use in his front yard than his back yard?
Answer:
19.8
Step-by-step explanation:
Subtract 130.2 by 110.4
A right prism is shown below.
What is the surface area of the right prism?
Question options:
290 in2
420 in2
520 in2
2940 in2
Answer:
290 8s the answer because 15 mutiplyed by 8 plus 17 multiplyed by 10 give you 290
[tex]\fbox{Surface \: area \: of \: prism = 520 \: sq.in.} [/tex]
Step by step explanation:Given:
height of prism h = 10 in
length of base of triangle b = 8 in
height of triangle h' = 15in
side A of triangle = 17 in
To find:
Surface area of prism = ?
Solution:
[tex]\begin{gathered}Area \: of \: base \: triangle = \: \frac{1}{2}\cdot{b}{h'} \\ Area \: of \: base \: triangle = \frac{1} {\not2}\cdot{15} \times \not{8} \\ Area \: of \: base \: triangle = 60 \: {in}^{2} \end{gathered}[/tex]\\[tex]\fbox{Area \: of \: base \: triangle \: (B) = 60 \: sq.in. }\\\begin{gathered}Perimeter \: of \: base \: triangle = Side A + Height \: h' + base \: b \\ Perimeter \: of \: base \: triangle = 15 + 17 + 8 \: in\\ Perimeter \: of \: base \: triangle = 40 \: in\end{gathered}
[/tex]
[tex]\fbox{Perimeter \: of \: base \: triangle (p) \: = 40 \: in} [/tex]
[tex]\begin{gathered}Surface \: area \: of \: prism = 2B+ \: ph \\ Surface \: area \: of \: prism = 2 \times 60+ \: 40 \times 10 \\ Surface \: area \: of \: prism = 120 + 400\\ Surface \: area \: of \: prism = 520 \: {in}^{2} \end{gathered} [/tex]
[tex]\fbox{Surface \: area \: of \: prism = 520 \: sq.in.} [/tex]
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find the domain of the function (f•g)(x) where f(x)2x^2+c, g(x)=5x-1
Step-by-step explanation:
Notice the domain for both function is all real numbers.
So if we either add, subtract, multiply, or compose the functions, the domain will be all real numbers.
Find the area of the shape below
11 ft
7 ft
10 ft
8 ft
2 ft
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Let's solve ~
Area of whole shape = Area of greater rectangle - area of smaller rectangle
Area of greater rectangle :
[tex]\qquad \sf \dashrightarrow \:11 \times 10[/tex]
[tex]\qquad \sf \dashrightarrow \:110 \: \: ft {}^{2} [/tex]
Area of smaller rectangle :
[tex]\qquad \sf \dashrightarrow \:7 \times 8[/tex]
[tex]\qquad \sf \dashrightarrow \:56 \: \: ft {}^{2} [/tex]
Area of composite figure :
[tex]\qquad \sf \dashrightarrow \:110 \: ft {}^{2} - 56 \: ft {}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:54 \: {ft}^{2} [/tex]
Match each statement with its equivalent statement:
(match the ABC`s with the XYZ`s) Thank you!
A. sin^2 θ
B. sin(-θ)
C. tanθ
X. -sinθ
Y. sinθ/cosθ
Z. 1-cos^2θ
The ABC and XYZ statements are trigonometric statements
The equivalent of A is ZThe equivalent of B is XThe equivalent of C is YHow to match the statements?A. sin^2 θ
To do this, we apply the following trigonometric ratio
sin^2 θ + cos^2 θ = 1
Subtract cos^2 θ from both sides
sin^2 θ = 1 - cos^2 θ
Hence, the equivalent of A is Z
B. sin(-θ)
Assume that θ is an acute angle, then we have:
sin(-θ) = -sinθ
Hence, the equivalent of B is X
C. tanθ
Using the trigonometry formula, we have:
tanθ = sinθ/cosθ
Hence, the equivalent of C is Y
Read more about trigonometry ratios at:
https://brainly.com/question/11967894
This question has two parts. First, answer Part A. Then, answer Part B.
Part A
Fill in the blank question.
Complete the following to show that the expressions (5+1)(5−1) and 52−12 are equivalent.
What number is not part of the solution set to the inequality below?
x - 2 > or equal to 12
A 10
B 14
C 16
D 18
Answer:
B. 14
Step-by-step explanation:
Add 2 to both sides:)
Mrs. Chase hired a landscaping service to plant a row of bushes around her triangular backyard. If the bushes
must be planted 3 feet apart, approximately how many bushes are needed for the backyard? (4 points work,
1-point final answer)
12
30
The number of bushes that is approximately needed for Mrs. Chase's backyard is 23 bushes
How many bushes are needed?The number of bushes needed = perimeter of the backyard / 3 feet
The perimeter of the backyard is the sum of the three sides of the right triangle that is the shape of the backyard. The length of the third side would be detemined using Phythagors theorem.
Length of the third side : √30² - 12² = 27.50 feet
Perimeter of the backyard = 27.50 + 12 + 30 = 69.50 feet
The number of bushes needed =69.50 / 3 = 23.17 = 23 bushes
To learn more about triangles, please check: https://brainly.com/question/22949981
what is the area of the parallelogram below if b=6.1? Round your answer to the nearest tenth.
The scale drawing is 2 cm:5m. What is the length,width,and area of the actual room. 8cm & 12 cm
Answer:
Length= 20m, width=30m Area= 600m²
Step-by-step explanation:
The length becomes 8/2 × 5m=20m
the width becomes 12/2 × 5m=30m
Area = length × width
= 20m × 30m
=600m²
A fruit punch is made with 32 ounces of ginger ale for every 12 ounces of frozen orange juice
concentrate. How much ginger ale should you use for 30 ounces of orange juice concentrate?
Answer:
80
Step-by-step explanation:
if you make a ratio table
32ginger ale = 12orange juice
now we now 6x5=20 so we can divide 12 by 2 which would give us 6 and the same with 32 which would give us 16 now you have
16ginger ale = 6 orange juice
and we need 30 orange juice so 6x5= 30 and we multiply 16 by 5 too so 16x5=80 t
therefore
80 ginger ale = 30 orange juice