the bolt goes into the roof along the n-axis. any force perpendicular to the n-axis (that is, any force along the line of the roof n) tends to shear off the bolt. p is 150 lbs. using vector methods, find the component of p perpendicular to the roof (along the n axis).

The percentage at which the transferred electrons change the mass of the penny is [- (n x 9.1 x 10⁻³¹)/m] x 100 .

The deficiency  or excess  of electrons in an atom leads to the development of charge.

The total mass of coin after loosing electrons is calculated as follows;

= m - (n x 9.1 × 10⁻³¹ ) Kg

where;

There will be decrease in the mass of the penny.  So the amount of decrease in mass will be;

= final mass - initial mass

= m - (n x 9.1 × 10⁻³¹ ) - m

= - (n x 9.1 ×10⁻³¹ )

This negative sign indicates that the mass has decreased.

The percentage decrease in the amount of mass transferring the electrons is calculated as;

[- (n x 9.1 x 10⁻³¹)/m] x 100    

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The statements that are correct and relevant to solving this problem are:

-The information contains the conversion factor 45s/135mm²

-The starting point for the calculation is 7903 mm².

-The problem assumes that the conversion between seconds and hours is known.

Calculation is both a process and a movement. Calculation's ultimate result is also a consequence of calculated action.

The calculator is a machine which thus calculates the average numbers and displays the results on a screen. It has a numerical keypad.

starting point is 7903 mm²

whit will be

A sec, min or her. (Here hour)

hour.

Assumes that the conversion between second and

hour is known.

Conversion factor.4513545-X 7903 = 2634.33 sec135

or 2634.33

0.732 hour

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Complete question:

(a) The specific volume of air in the cylinder is heated without changing its temperature until its volume doubles is 0.861 m³/kg.

(b) Specific volume of air in the cylinder increases.

(c) The pressure of air in the cylinder decrease.

The amount of cubic metres that one kilogramme of matter takes up is known as the specific volume. It is the reciprocal of density and the ratio of a substance's volume to mass. In other words, specific volume is inversely related to density. Any state of matter may be measured or calculated for specific volume, but calculations involving gases are where it is most frequently applied.

Though it can also be expressed in terms of millilitres per gramme (mL/g) or cubic feet per pound (ft³/lb), the standard unit for specific volume is cubic metres per kilogramme (m³/kg).

(a) Specific volume =

[tex]$ \mathrm{ \hat V = \frac{V}{m} = \frac{RT}{P} }[/tex]

[tex]$ \mathrm{ =\frac{\overline RT}{mP} }[/tex]

[tex]$ \mathrm{ = \frac{8.314 \times 300}{28.97 \times 100} }[/tex]

[tex]$ \mathrm{ \hat V = 0.861 \ m^3/kg }[/tex]

(b) Mass will remain constant so on doubling the volume, specific volume will also be doubled i.e.

[tex]$ \mathrm{ \hat V_2 = 2\hat V_1 }[/tex]

Thus, specific volume increases.

(c) Since, T = constant

[tex]$ \mathrm{ P\hat V_1 = P\hat V_2}[/tex]

[tex]$ \mathrm{ \frac{P_2}{P_1} = \frac{\hat V_1 }{\hat V_2 } }[/tex]

[tex]$ \mathrm{ \frac{P_2}{P_1} = \frac{\hat V_1 }{2\hat V_1 } }[/tex]

[tex]$ \mathrm{ \frac{P_2}{P_1} = \frac{1 }{2 } }[/tex]

[tex]$ \mathrm{ P_2= \frac{1}{2} \times 100}[/tex]

[tex]$ \mathrm{ P_2=50}[/tex]

Thus pressure decrease in this case.

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Complete question:

The stiffness is 0.21 N/m and frequency is 2.84 Hz.

The effective spring constant k of the web can be determined as follows:

Stiffness is defined as the resistance to forces that bend a component. Firmness is very important to the end-use performance of many papers.

[tex]F= \frac{1}{2pi} \sqrt{\frac{k}{m} }[/tex]

k= 4 pi²f²m

= 0.21875 N/m

The frequency of the web's oscillations can be determined as follows: The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. The unit of frequency is hertz (Hz), or one occurrence per second.

[tex]F= \frac{1}{2pi} \sqrt{\frac{0.21}{0.56 g} }[/tex]

= 2.84 Hz

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It takes 5.0 s for a wave to travel 3.0 m along the spring.

The time it takes for a wave to travel 3.0 m along the spring is 5.0 s. This can be calculated by dividing the distance (3.0 m) by the wave speed, which is equal to the frequency (2.5 Hz) multiplied by the distance between successive peaks (0.60 m).

3.0 m / (2.5 Hz x 0.60 m) = 5.0 s

What is frequency?

Frequency is a measure of the number of times a particular event or phenomenon occurs within a given period of time. It is usually expressed as an oscillations per second (Hertz). Frequency is an important measure in many fields, including physics, engineering, electronics, and music.

Therefore, It takes 5.0 s for a wave to travel 3.0 m along the spring.

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Instantaneous power output of a 3-phase 60 Hz generator will not be constant under following condition when the load is balanced.

Instantaneous power output of a single phase 60 hz generator will be constant under reactive power.

Responsive power is otherwise called: ghost power. One more method for making sense of this is that responsive power is the resultant power in watts of an air conditioner circuit when the ongoing waveform is out of stage with the waveform of the voltage, normally by 90 degrees assuming the heap is simply receptive and is the consequence of either capacitive or inductive burdens. A model is fueling a brilliant light, in a responsive burden energy stream toward the heap a fraction of the time, though in the other half power streams from it, which gives the deception that the heap isn't dispersing or consuming power. Receptive power is one of the three kinds of force present in stacked circuits.

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8.3 m/s is the terminal velocity of the squirrel can be calculated using the equation for terminal velocity and 10.8 m/s is the velocity of a 50.0 kg person hitting the ground.

What is velocity?
Velocity is a measure of the speed of an object's motion in a particular direction. It is a vector quantity, meaning it has both magnitude and direction. Velocity is usually measured in meters per second (m/s).

The terminal velocity of the squirrel can be calculated using the equation for terminal velocity of an object in a fluid, which is given by Vt = (2×m×g)/(ρ×Cd×A). Here, m is the mass of the object, g is the acceleration due to gravity, ρ is the density of the fluid, Cd is the drag coefficient, and A is the reference area of the object. The drag coefficient for a horizontal skydiver is 0.8, and the density of air is 1.225 kg/m^3. Therefore, the terminal velocity of the squirrel can be calculated as Vt = (2×500×9.8)/(1.225×0.8×895) = 8.3 m/s.

The velocity of a 50.0 kg person hitting the ground can be calculated using the equation for the velocity at the end of a fall, which is given by Vf = sqrt(2×g×h). Here, g is the acceleration due to gravity and h is the height of the fall. Therefore, the velocity of the person hitting the ground can be calculated as Vf = sqrt(2×9.8×5.6) = 10.8 m/s.

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A unit vector perpendicular to a given vector is a vector of the same length but with a direction that is 90 degrees to the given vector. Geometrically, the collection of all such vectors forms a circle.

What is vector?
Vector is a mathematical object used to represent magnitude and direction. It is composed of a magnitude and a direction that can be represented in Euclidean space by an ordered pair of numbers. A vector can also be represented by a directed line segment to indicate the direction of the vector and its magnitude. Vectors can be used to represent many physical quantities such as velocity, force, acceleration, and electric and magnetic fields. Vectors are also used in calculus to represent derivatives of functions, enabling us to calculate the rate of change of the function.

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When joists do not completely span the distance from one wall to the other, you must offset the markings on the second wall by 1 1/2 inches. This is known as a "joist hanger offset."

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The power of the hot rod of mass 2000 kg is 580645.16 W.

Power is the rate at which work is done.

To caculate the power output of the hot rod, we use the formula below.

Formula:

Where:

Substitute these values into equation 1

Hence, the power is 580645.16 W.

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1) The ratio of density of A to density of B is 3/2.
2) The ratio of volume of A to the volume of B is 1/3.

How closely a material is packed together is determined by its density. As the mass per unit volume, it is referred to. D or is the symbol for density. Formula for Density = m/V, where is the density, m is the object's mass, and V is its volume.

Given:

Weight of A block = 12 N

Apparent weight of A block = 8 N

Weight of B block = 20 N

Apparent weight of B block  = 12 N

Given is a relationship between apparent weight and original weight.

W' = W -B --- (1)

B = W dis liq - ρ liq V obj ---(2)

For block-A :

From equations (1) and (2),

W' = W  - ρt V

Substitute the given values,

8 = 12 - ρt V

ρt V = 4 ---(3)

For block-B :

From equations (1) and (2),

W' = W  - ρt V

12 = 24 - ρt V

ρt V = 12 ---(4)

From equations (3) and (4)

ρt VA/ρt VB = 4/12

ρt VA/ρt VB = 1/3

As a result, the ratio of volume of A to the volume of B is 1/3.

From given weights of A block  and B block,

[tex]W_A}[/tex]/[tex]W_{B}[/tex] = 12/24 ---(5)

weight of an object in terms of volume and density can be written as,

W = ρ Vg

So, equation (5) written as,

ρA [tex]V_{A}[/tex]g/ρB [tex]V_{B}[/tex]g = 12/24

ρA/ρB × [tex]V_{A}[/tex]/[tex]V_{B}[/tex] = 1/2

Substitute  [tex]V_{A}[/tex]/[tex]V_{B}[/tex] = 1/3

ρA/ρB ×1/3 = 1/2

ρA/ρB = 3/2

So, the ratio of density of A to density of B is 3/2.

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The relationship between speed, distance, and time is described using the formula speed distance time. An object traveling 10 miles in 5 minutes averages 120 miles per hour.

10 miles were covered in total.

It took five minutes in total.

The formula can be used to determine the speed.

s = d/t

s being the speed

D stands for distance.

The amount of time used

Let's change the known variables in the equation above to get

s = 10/5

= 2 miles/minute

However, we must convert the speed to miles per hour in order to use it.

s=2 x 60 miles per hour

120 miles per hour.

An object traveling 10 miles in 5 minutes averages 120 miles per hour.

Consequently, the typical speed is 120 miles per hour.

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A correct equation for the quantities represented in this scenario is

tan Θ=[tex]\frac{d_{n} }{d_{e} }[/tex].

Now, according to the question,

tanΘ=[tex]\frac{opp.\: side}{adj.\: side}[/tex]

Now, by the figure mention,

The side opposite to the angle Θ is [tex]d_{n}[/tex] and the adjacent sides is [tex]d_{e}[/tex].

The three primary trigonometric functions—Sine, Cosine, and Tangent—are based on a right-angled triangle.

Triangle with the opposite side, adjacent side, and hypotenuse can be declared by:

The terms "opposite" and "adjacent" refer to the angle's opposing and adjacent, respectively.

The long one is "Hypotenuse."

Now, put these values in the formula,

which gives the equation,

tanΘ=[tex]\frac{d_{n} }{d_{e} }[/tex]

Now, from the options given it is clearly seen that option-1 is correct.

Question: in the town of centralburg (figure 1), which is laid out in a uniform block grid, the grocery store is three blocks east and four blocks north of the post office. which of the following is a correct equation for the quantities represented in this scenario

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Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

What  is linearly decreasing force?

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Answer: v = 11149.3 m/s

Explanation:

Assuming that the values in your question were supposed to have exponents.

v = minimum speed

r = distance from center of earth

= radius of earth + height above the surface

= (6.371 * 10^6 m) + (0.40 * 10^5 m)

= 6.411 x 10^6 m

M = mass of earth = 5.974 x 10^24 kg

m = mass of meteor

Using conservation of energy

GMm/r = (0.5) m v^2

GM/r = (0.5) v^2

(6.67 * 10^-11)(5.974 * 10^24)/(6.411 * 10^6) = (0.5) v^2

62153455 = (0.5)v^2

Divide both sides by 0.5

124306910 = v^2

Square root both sides

v = 11149.3 m/s

Value of electric field at x=1m is

electric field E= [tex]\frac{-dV}{dx} =[/tex]  [tex]- \frac{-d(5x^{2} -10x - 9)}{dx}[/tex]

electric field E= -(10x-10)

electric field E= 0

An electric field is a physical phenomenon that surrounds electrically charged particles and exerts force on any other charged particles nearby, either attracting or repelling them. It can also refer to the physical field surrounding a system of charged particles.Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.Electrical technology makes use of electric fields, which are significant in many branches of physics. For instance, in atomic physics and chemistry, the electric field acts as an attracting force to hold atoms' atomic nuclei and electrons together.

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The velocity 'v' of the cube as it leaves the block would be, v=[tex]\sqrt{\frac{2gR}{1+m/M} }[/tex].

Conservation of mechanical energy is a principle that states that the total mechanical energy of a closed system remains constant as long as no energy is added or removed from the system. In this case, the system consists of the two blocks and the table on which they rest. Since there is no friction and no external force acting on the system, the total mechanical energy (potential energy + kinetic energy) remains constant as the cube slides down the track. This allows us to use the initial potential energy of the cube to calculate its final kinetic energy, and thus its velocity as it leaves the block.

The magnitude of velocity of the cube as it leaves the block can be found using Conservation of mechanical energy.

Initially, the cube is at rest at the top of the track and has only potential energy, given by m₁gh, where g is the acceleration due to gravity and h is the height of the track. As the cube slides down the track, it loses potential energy and gains kinetic energy.

we have

mu=mv−−(1)

wall=Δk

mgR = [tex]\frac{1}{2} mv^{2} + \frac{1}{2} mu^{2}[/tex]

mgR = [tex]\frac{1}{2} mvH_{2}[/tex] + [tex]\frac{1}{2} (\frac{mv}{M} ) ^{2}[/tex] × M

mgR= [tex]\frac{1}{2} mv^{2} + \frac{1}{2} \frac{m^{2} v^{2}}{M}[/tex]

So, v²=[tex]\frac{2gR}{1+m/M}[/tex]

So, v= [tex]\sqrt{\s{\frac{2gR}{1+m/M} }}[/tex].

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False. Removing fault current within seconds or minutes may not be enough to prevent damage to the conductor or equipment.

What is meant by a short circuit?

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A bar rotates horizontally about its center, reaching a maximum angular velocity in 6 complete rotations from rest and has a constant angular acceleration of 0.110 radians.

What is angular acceleration?

The angular acceleration is the rate at which the angular velocity of an object is changing.

Therefore, since the angular acceleration of the bar is constant, this means that the angular velocity of the bar is increasing at a constant rate.

To find the angular velocity at any given time, we can use the equation: angular velocity = angular acceleration x time.

To find the final angular velocity, we can use the equation: final angular velocity = initial angular velocity + angular acceleration x time.

Therefore, the final angular velocity of the bar after 6 complete rotations is: 0 + 0.110 radians/s x (6 x 2π) = 6.832 radians/s.

To find the angle that the bar has rotated through, we can use the equation: angle = angular velocity x time

Therefore, the angle that the bar has rotated through after 6 complete rotations is: 6.832 radians/s x (6 x 2π) = 42.5 radians.

It's worth noting that angular velocity is a vector quantity, it's magnitude is given in radians/s and its direction is given by the right hand rule.

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Complete question is:

A bar rotates horizontally about its center, reaching a maximum angular velocity in 6 complete rotations from rest and has a constant angular acceleration of 0.110 radians. The movement of the interia of the bar about the raxis of the rotation is about 0.0216kgm^.

a. Show the final angular velocity of the bar is 3 radians.

b. Draw the variation with time t of the angular displacement 0 of the bar during the acceleration .

c. Calculate the torque acting on the bar while it is accelerating.

d. The torque is removed. The bar comes to rest in 30 complete rotations with constant angular deceleration. Determine the time taken for the bar to come to rest.

The ball of mass 200g reaches a height of 17.2m when it is thrown up at 25 m/s at 40 degrees, the time taken to reach peak height is 1.86s and the total time taken to fall back is 3.72s.

Given mass of the ball (m) = 200g

Initial speed of ball (u) = 25m/s

The angle at which ball is thrown = θ = 40 degrees

The horizontal velocity of ball = uxsinθ = 25 x sin 40 = 18.6m/s

The vertical velocity of ball = uycosθ = 25 x cos 40 = -16.6m/s

(a) Maximum height reached (h) = ux^2sin^2θ/2g where g is the gravitational acceleration.

Then h = (18.6)^2/2 x 10 = 17.2m

(b) The final velocity at maximum height (Vfy) = 0

We know that from Newtons laws of motion v = u + at then

Vy = uxsinθ + (-gt)

then t = uxsinθ/g = 18.6/10 = 1.86s

(c) The amount of time required for an upward and downward route is equal. So,  total time taken by the ball to return to the ground = 1.86+1.86 = 3.72s.

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When the activation energies of the forward and backward processes are equal, the energy of the reactant and product becomes equal.

Therefore, E=EAEB=0. The reaction has reached equilibrium when the forward and reverse reaction rates are equal to one another. When the rate of the forward reaction equals the rate of the reverse reaction, a system is said to be in chemical equilibrium. The activation energy () of the reverse reaction is the SUM of the activation energy of the forward reaction AND the energy released from the forward reaction, according to the information provided.

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1.496E+11 metres, 1.4960E+13 centimetres, and 1.4960E+8 kilometres are all equivalent to one astronomical unit (au). The average distance between the sun and the earth serves as the basis for this peculiar unit.

The distance between any two places in space is equal to the length of the straight line connecting them, which is also the shortest path. This is the usual conception of distance in classical physics, especially in Newtonian mechanics. The straight-line distance is mathematically known as the Euclidean distance in two- and three-dimensional space. The physical concept of distance is employed in physics to explain how far an object has moved. Distance is a scalar quantity. SI units for distance A metre is the unit of distance according to the International System of Units.

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In a vacuum, both the feather and the rock would fall at the same rate due to the absence of air resistance.

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The kinetic energy of an object at a given instant is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

In this scenario, the net force acting on the object decreases linearly throughout the displacement, as shown on the graph, and reaches zero at the end of the displacement. Therefore, the object's velocity at the instant the net force is zero is equal to its final velocity, which is the velocity of the object when it comes to rest.

Since the net force acting on the object is zero at this point, the work done by the net force is also zero. Therefore, the initial kinetic energy of the object is equal to its final kinetic energy, which is the kinetic energy of the object when it comes to rest.

Therefore, we can use the formula for kinetic energy to find the kinetic energy of the object at the instant the net force is zero:

KE = 1/2 * m * v^2

KE = 1/2 * (3.0 kg) * (0 m/s)^2

KE = 0 J

The kinetic energy of the object at the instant the net force is zero is 0 J. This means that the object has come to rest and all its kinetic energy has been transformed into other forms of energy like heat or sound.

Answer:

B. Vector c

Explanation:

You have to look for these two points (4,0) and (1,-3) on your graph (x, y) , and then you have to find which vector connects them together and that must be vector c

There are two prominent stars in the sky that are spatially separated by about two meters.

Which constellation has two of the brightest stars in the universe?

Second brightest and the brightest star in the night sky is Sirius, which is in the constellation Canis Major. With an apparent magnitude of -1.46, Sirius, the second brightest star, can be seen from anywhere. The Canis Major constellation contains the bright star in question. It is the Alpha star of this constellation.

Which of the two shining stars is it in the sky?

The Sun is the brightest star that can be seen from Earth and has a magnitude of 26.74. Sirius comes in second with a magnitude of 1.46 mag.

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Now the force equation at point A is given as f (n)= 0.05N

h < (1/2)R.This means that the ball must start at a height that is at least half a radius above the top of the loop, or 2.5 radii above the ground, in order to travel around the entire circle.

v = 12.45m/s

Part B)

F(n) = 0.05N

As we know that the point A lies on the top of the loop

so we will have by energy conservation

so the speed at point A is given as

mg (H-2R) = 1/2 mv ²

v = √2 g (H-2R)

V= 12.45 m/s

Now the force equation at point A is given as

F (n)= 0.05N

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These energy between the various temperature units are accurately represented by formulae in Degrees Celsius = (9/5 x Degrees Fahrenheit) + 32

The Formula for Converting Temperature We employ the same conversion formulas found in the majority of textbooks. To convert temperatures from degrees Fahrenheit to degrees Celsius, multiply the result by.5556 (or 5/9) after subtracting 32. When converting from celsius to Degrees, multiply the result by 1.8 (about 9/5) then by 32.

The formula for converting degrees Celsius to degree Fahrenheit, which would be given by the equation F=95(C)+32, must be used in this situation. Therefore, we must divide the stated temperature by nine, multiply it.

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The sum of all the kinetic and potential energies of a system's constituent pieces is the total energy of the system.

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