The compound P4S3 is used in matches and reacts with oxygen through the chemical reaction shown below.
What mass of SO2 is produced from the combustion of 0.200 g P4S3?
P4S3 (s) + ------- O2 (g) ===> ------------ P4O10(s) + ----- SO2 (g)

Answer:

Explanation:

The structural formula provides more information which is often used to represent a particular organic substance. A structural formula indicates how the atoms are arranged within the molecule of a substance. From the information, the structure of  4-methyl-5-oxohexanal is represented by using a stick formula where the methyl group falls into position 4 and oxygen group falls into position 5 on the hexanal compound.

The structure is provided in the image attached below for better understanding.

Answer:

All of these are true.

Explanation:

Copper lies below iron in the activity series, this implies that copper is more easily reduced than iron as its electrode potential is positive.

Also, copper is extracted easily from its sulphide ore by oxidation with oxygen. Similarly, the reduction of iron in a blast furnace requires toxic CO, hence the answer above.

Answer:

2 mL

Explanation:

Step 1: Given data

Step 2: Calculate the volume of the 10 M solution

We want to prepare a diluted solution from a concentrated one. we can calculate the volume of the initial solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.1 M × 200 mL/10 M

V₁ = 2 mL

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

Answer:

The limiting reactant is CH₄

26.0g of CH₂Cl₂ is the maximum amount that can be formed

4.15g CCl₄ will remain

Explanation:

The reaction of methane, CH₄, with carbon tetrachloride, CCl₄ is:

CH₄ + CCl₄ → 2CH₂Cl₂

To find the maximum mass of dichloromethane that can be determined we need to find moles of methane and carbon tetrachloride:

Moles CH₄:

2.45g * (1mol / 16.04g) = 0.153 moles

Moles CCl₄:

27.7g * (1mol / 153.82g) = 0.180 moles

That means just 0.153 moles of CCl₄ will react until CH₄ is over.

The limiting reactant is CH₄

Assuming the whole 0.153 moles will react, the moles of CH₂Cl₂ will be:

0.153 moles CH₄ * (2 moles CH₂Cl₂ / 1 mole CH₄) = 0.306 moles of CH₂Cl₂

The mass is (Molar mass dichloromethane: 84.93g/mol):

0.306 moles of CH₂Cl₂  * (84.93g / mol) = 26.0g of CH₂Cl₂

The moles of CCl₄ that remain are:

0.180 moles - 0.153 moles = 0.027 moles

In grams:

0.027 moles * (153.82g / mol) = 4.15g CCl₄

Answer:

Option A. 0.330 atm.

Explanation:

To know the correct answer, we simply do the following:

1. Conversion of 251 torr to atm

760 torr = 1 atm

Therefore,

251 torr = 251 torr / 760 torr × 1 atm

251 torr = 0.330 atm

2. Conversion of 251 torr to psi

1 torr = 0.0193 psi

Therefore,

250 torr = 250 torr / 1 torr × 0.0193 psi

250 torr = 4.825 psi

From the above illustrations, 251 torr is equivalent to both 0.330 atm and 4.825 psi. Therefore, only option A is correct.

Answer:

0.31 mole

Explanation:

The following data were obtained from the question:

Mass of SF6 = 45.0 g

Number of mole of SF6 =..?

Next, we shall determine the molar mass of SF6.

This can be obtained as follow:

Molar mass of SF6 = 32 + (19×6)

Molar mass of SF6 = 32 + 114

Molar mass of SF6 = 146 g/mol

Finally, we shall determine the number of mole in 45 g of SF6 as follow:

Molar mass of SF6 = 146 g/mol

Mass of SF6 = 45.0 g

Number of mole of SF6 =..?

Number of mole = mass /Molar mass

Number of mole of SF6 = 45 /146

Number of mole of SF6 = 0.31 mol

Therefore, 0.31 mol is present in 45 g of SF6.

Answer:

obtain something from (a specified source).

Explanation:

Answer:

It is like the orgins of something

Explanation:

A number can be written in the form of scientific notation as follows :

[tex]N=x\times 10^y[/tex]

x is any real number and y is integer

(a) The distance between Pluto and the Sun is 5,913,000 km.

There are 6 digits after 5. In scientific form is given by :

[tex]N=5.91\times 10^6\ km[/tex]

(b) The density of nitrogen gas is 0.0012506 g/cm³.

There are 2 digits before 1. In scientific notation,

[tex]d=1.25\times 10^{-3}\ g/cm^3[/tex]

Answer:

A. When a liquid is first placed in a closed container, the evaporation rate is higher than it is in an open container under the same conditions.

Explanation:

Evaporation refers to the process by which a liquid changes to gas or vapor. It usually occurs at the surface of a liquid.

Factors that affects evaporation include; nature of the liquid, surface area of liquid exposed, temperature and wind.

Considering the options given:

A. When a liquid is first placed in a closed container, the evaporation rate is higher than it is in an open container under the same conditions. = False

This is false because, the more the surface of the liquid exposed, the higher the rate of evaporation.

B. When a liquid is first placed in a closed container, the evaporation rate is higher than the condensation rate. = True

This is true because when a liquid is first placed in a container, the equilibrium position favors evaporation initially than condensation as saturation of the space above the liquid with vapor has not been achieved.

C. When the rates of evaporation and condensation are equal, the system has reached dynamic equilibrium.= True

Dynamic equilibrium is achieved when the rate of forward and backward reaction, in this case, evaporation and condensation are equal.

D. Vapor pressure refers to the pressure of a gas at a given temperature in equilibrium with its liquid phase. = True

E. Stronger intermolecular forces within the liquid typically result in a lower vapor pressure under a given set of conditions.  = True

Strong intermolecular forces between the molecules of the liquid causes the liquid to remain in the liquid state rather than turning to vapor, thereby lowering vapor pressure

Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

[tex]C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)[/tex]

Generally [tex]\Delta H = \Delta U + \Delta N* RT[/tex]

Here [tex]\Delta H[/tex] is the change in enthalpy

[tex]\Delta U [/tex] is the change in the internal energy

              [tex] \Delta N[/tex]  is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is [tex] O_2[/tex] and  [tex]CO_2[/tex] and this are both gases so the change would occur in the number of moles

So  

[tex]\Delta H = \Delta U + [16 -23]* RT[/tex]

[tex]\Delta H = \Delta U -7RT[/tex]

The  negative sign in the equation tell us that the enthalpy[tex]\Delta_r H[/tex] would be less than the Internal energy [tex]\Delta_r U[/tex]

Answer:

The answer is

Explanation:

To find the number of moles in a substance when given the molar mass and mass we use the formula

[tex]n = \frac{m}{M } [/tex]

where

n is the number of moles

M is the molar mass

m is the mass of the substance

Mr( Na) = 23 , Mr( CL ) = 35.5

Molar mass ( NaCl ) = 23 + 35.5

= 58.5 g/mol

Mass = 1.005 kg

It's equivalent in grams is

1.005 × 1000 = 1005 g NaCl

So the number of moles in NaCl is

[tex]n = \frac{1005}{58.5} \\ = 17.179487...[/tex]

We have the final answer as

17.2 mol to the nearest tenth

Hope this helps you

Given :

2.5 mole of Sulfuric acid [tex]( H_2SO_4 )[/tex] .

To Find :

Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid

Solution :

Let us assume volume of water be 1 L .

Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .

So , for 2.5 mole sulfuric acid required 5 mole of NaOH .

Moles of NaOH ,

[tex]n=M\times Volume \\\\n=5\times 1=5\ moles[/tex]  

Molecular mass of NaOH , M.M = 58.44 g/mol .

Mass of 5 moles of NaOH :

[tex]m=5\times 58.44\ g\\\\m=292.2\ g[/tex]

Hence , this is the required solution .

Answer:

HEPES.

Explanation:

Hello,

In this case, considering the given options, and the pH requirement of 7.5, considering the Henderson-Hasselbach equation:

[tex]pH=pKa+log(\frac{[base]}{[acid]})[/tex]

The best buffer is that having the closest pKa to the required pH, thus, for the given Ka, we obtain:

[tex]pKa_{MES}=-log(Ka_{MES})=-log(7.9x10^{-7})=6.10\\\\pKa_{HEPES}=-log(Ka_{HEPES})=-log(3.2x10^{-8})=7.49\\\\pKa_{Formic \ acid}=-log(Ka_{Formic \ acid})=-log(1.8x10^{-4})=3.74\\\\pKa_{Acetic\ acid}=-log(Ka_{Acetic\ acid})=-log(1.8x10^{-5})=4.74\\\\pKa_{Tris}=-log(Ka_{Tris})=-log(6.3x10^{-9})=8.2[/tex]

Therefore, the best buffer is the HEPES since its pKa is almost the required pH.

Regards-

The answer is 30.

Explanation:

The total number of protons and neutrons in a nucleus is called mass number. So 14 proton plus 16 neutron is = 30 mass number.

Answer: Some examples are color, density, volume and mass

Explanation:

Physical properties are anything you can smell, touch, or hear. They can be observed without changing.

Answer:

it’s electron configuration is 1s^2 2s^2 2p^4. To determine valence electrons, add the outermost s and p orbitals. In an oxygen atom, 8 electrons are present. Electron present in the first shell (n=1) 2n^2=2 (1)^2=2 (1)=2.

an experiment should be replicated for one: it my give more reason to people who did not do it them selves two: during the experiment one variable could have been wrong like a gust of wind or a draft that's why you should conduct the experiment 3 to 4 times then get the medium or the average of your results giving you a more accurate answer.

Answer:

The mass of the acetic acid is 13.5 g

Explanation:

Given;

weight percent of the acetic acid (ratio of solute to total solution), w/w = 98 %

volume of acetic acid, v = 12.83 mL

density of acetic acid, ρ = 1.05 g/mL

density is given by;

density = mass / volume

mass = density x volume

mass of the acetic acid in 12.83 mL =  1.05 g/mL x 12.83 mL

mass of the acetic acid in 12.83 mL = 13.5 g

Therefore, the mass of the acetic acid is 13.5 g

≈ 0,27 g/cm³

36.5 l = 36.5 dm³ = 36500 cm³

10 kg = 10000 g

d = m/V

= 10000g/36500cm³

≈ 0,27 g/cm³

Answer:

A good experimental design should always: include more than one independent variable. have predictable outcomes. be repeatable.

Explanation:

Hope this helps :D

Answer:

Explanation: Mendeleev arranged the elements on the basis of their atomic mass. Melting and boiling point were used as the physical characteristics in deciding the position of elements. He arranged the elements and wrote the formula of their oxides and hydrides which seemed to possess same chemical formula.

Explanation:

Answer:

7. Why is the d-block one energy level behind the s-block? Also, why would the f-block be so far behind?

me to

Explanation:

Answer:

element

Explanation:

it is use full for you thanks

Answer:

See explanation

Explanation:

The slope of a graph in which mass was plotted against volume is the density of the object. Density of objects have been measured and recorded in standard handbooks for the purpose of reference. If the density of an unknown substance is measured, it can now be compared with the density of known substances recorded in standard handbooks such as the handbook of physics and chemistry. By so doing, the unknown substance can be identified.

According to standard handbooks, the density of copper is 8.96 g/ml while that of nickel is 8.908 g/ml. If the average slope obtained is around 8.96 g/ml, then the metal is copper and not nickel.

An alternative to this method is to measure the refractive index of the piece of metal and compare the average values observed with the contents of standard handbooks in order to identify the unknown metal.

Answer:

Density =M/V

1500/7600

5.0666666667=Ans...